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Create Index Cards On-Line: Create an account on quizlet.com Create a study set. Give the study set the name: Chapter 18 Solutions Create the study set.
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Create Index Cards On-Line:Create an account on quizlet.com Create a study set.Give the study set the name: Chapter 18 SolutionsCreate the study set with the following vocab
“Stock solution” is the same as the original solution.
Example
A stock solution of HCl has a concentration of 12M. How much of the stock solution would be required to make 325 mL of a 6M solution?
Monday, April 21st, 2014
Daily Log: Molality Notes Practice Problems Chapter 18 Test on
Friday
Molality
Molality is another way to represent the concentration of a solution.
It is represented by a lower case m. Molality = moles of solute/kg of solvent
Example: A 4.9m solution of NaCl is dissolved in 1000 grams of water. How many grams of NaCl is this?
Tuesday, April 22nd, 2014
PDN: Determine the molality of a NaCl solution in which 17.3 moles of solute are dissolved in 1400 grams.
Daily Log: Practice Problems Test on Friday!
18.3 Colligative Properties of Solutions
Properties that depend on the number of particles dissolved in a given mass of solvent Boiling Point Elevation Freezing Point Depression
Boiling-Point Elevation
∆Tb = Kb x m x im is the molaityi is the number of ions in solution
Kb is the molal boiling point elevation constantIt is dependent on the solvent
Freezing Point Depression
∆Tf = Kf x m x im is the molaityi is the number of ions in solution Kf is the molal freezing point constantIt is also dependent on the solvent
Example:
Determine the boiling point and freezing point of a solution in which 600 grams of MgCl2 is dissolved in 2400 grams of water. (Kb = 0.512 and Kf = 1.86)