Cooler

L3.5 Rancang E-101 Heater

Fungsi : Memanaskankan margarin ke suhu ruangan

Alat : Shell and Tube Heat Exchanger

Langkah - langkah perancangan:1. mendefinisikan laju energi antara fluida panas dan fluida dingin (laju masa dan temperatur)2. menentukan jenis fluida yang masuk di shell dan di tube3. mementukan physical properti masing- masing fluida (densitas, viskositas, heat capacity dan konduktivity)4. mengasumsi nilai U5. menentukan dimensi tube dan shell, jumlah tube dan jenis pitch6. menghitung U dan A (luas area) koreksi7. menghitung koefisien perpindahan panas inside dan outside8. menghitung penurunan tekanan

Kecepatan pemanas = 3468.8465944622 Kg/jamQ = 1308617.174491 kj/jam

192.7136996923 Kmol/jam1243186.3157664 btu/jam

Ud= 5 BTU/jam.ft2.F [Kern tabel 8 hal 840]T reff= 25 oC 77 F

Hot fluid=Data shell (steam) Cold fluid=t1 (in)= 30 86 Ft2 (out)= 40 104 FT average= 35 95 F

Data tubeT1 (in)= 270 518 FT2 (out)= 70 158 FT average= 170 338 F

oCoCoC

oCoCoC

Menghitung TFluida Panas Fluida Dingin Selisih

518 T. tinggi 104 414.0158 T. rendah 86 72.0360 18.0 342.0

LMTD = 195.5180R = (T1-T2)/(t2-t1) = 20.00000S = (t2-t1)/(T1-T2) = 0.0416666667Dari figure 18 Kern, diperoleh faktor koreksiFt = 0.975 4 shellT = LMTD x Ft = 190.6 FTabel 10, Kern 843OD = 3/4 in 0.0625 ftID = 0.652 in 0.0543333333 ftBWG = 18A inside = 0.1707 ft2/ftA outside = 0.1968 ft2/ftAtube = 0.334 in2L = 12 ft 144tebal = 0.049 ft

1304.29229152

552.291790109

tabel 9 kern 841:tubeOD = 3/4 inpitch = square 1 pass = 4jmlh tube (Nt) = 688 tubeL/ID = 220.858895706shell ID = 33 in 2.7499720599 ft

Koreksi:

At= ft2

Nt=

LMTDUQA

dt .

0.ALA

N tt

LMTDUQA

dt .

0.ALA

N tt

LNALMTDQU

toutsided ...

1

2

12

ttln

ttLMTD

LNALMTDQU

toutsided ...

1

2

12

ttln

ttLMTD

Ud= 4.0137484746 BTU/jam.ft2.F

At= 1624.7808 ft2

Physical PropertiesTube: Densitas () = 53.6511

Viskositas ( ) = 3.70E-011.68E-01

konduktifitas thermal (kf) = 5.13E-01heat capacity = 4.50E-01

shell: Densitas () = 61.8169098879water Viskositas ( ) = 1.03E+00

konduktifitas thermal (kf) = 1.28E-02heat capacity = 0.4493486993

Tube Side

t= 0.3989444444 in2 = 0.0027704475 ft2

Gt= 1252088.89749 Kg/jam.ft2

Re= 4.06E+05jH= 1000 [fig 24 kern 834]

hi= 542.937838738 BTU/jam.ft2.F

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

33,0...k

CpIDkjHhi

ODIDhh iio .

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

33,0...k

CpIDkjHhi

ODIDhh iio .

471.993961143

SHELL SIDE (cold fluid) jarak baffle = B = 6.6 in

0.55 ft

De= 1.48 in0.1233333333 ft

As= 0.378125 in2 0.0315104167 ft

Gs= 110085.710105 Kg/ft2.jam50038.9591387 lb/ft2.jam

Re= 5.99E+03

jH= 45

1.52E+01 BTU/jam.ft2.F

471.993961143 BTU/jm.ft2.F

Uc= 1.48E+01 BTU/jam.ft2.F

0.007347509

Pressure dropTube side Re= 4.06E+05

f= 0.00012 [fig 26 kern 836]Densitas= 53.6510934 lb/ft3

859.4100396279 kg/m3Gt= 1252088.89748585 Kg/jam.ft2

569131.317039023 lb/jam.ft2

hio=

ho=

hio=

Rd=

5ID

5ID

pitchBODtubepitchIDAs .144

)..(

ss A

mG

es DG .Re

33,0...k

CpDkjHh

eo

00

00.hh

hhUi

iC

dc

dcd UU

UUR.


)..(

ss A

mG

es DG .Re

00

00.hh

hhUi

iC

dc

dcd UU

UUR.

Pt= 1.1314595833 Psi0.0769700397 atm

0.01 [fig 27 kern 837]

Pr= 0.16 psi0.0108843537 atm

0.0878543934 atm

Shell sideRe= 5991.37740564

f= 0.002 [fig 26 kern 839]

densitas= 61.8169098879 lb/ft3990.214171039 Kg/m3

N + 1 = 261.818181818

0.5600459255 psi0.0380983623 atm

0.1259527557 atm1.8510016978 psi

V2/2g =

PT=

IDnLGfP tt .10.22,5...

10

2


10

2

gVnPr 2.4 2

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

gVnPr 2.4 2

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

bhn bkupmnas

[Kern tabel 8 hal 840]

steamlight organic

1

2

12

ttln

ttLMTD

1

2

12

ttln

ttLMTD

lb/ft3lb/ft.jam h2Kg/ft.jam h20

densityh20

lb/ft3 viscositylb/ft.jam h20

h2cph20

Btu/jam.ft.oFBTU/lb.oF


33,0...k

CpDkjHh

eo

dc

dcd UU

UUR.

dc

dcd UU

UUR.

gVnPr 2.4 2

gVnPr 2.4 2

A B C0.03951 4.59E-04 -6.49E-06 -6.49E-010.00053 4.71E-05 4.96E-08 2.25E-02

n0.3471 0.274 0.28571 0.985366624

-36.826 4.29E-01 -1.62E-05 108.415086227.758 2.12E-01 -3.28E-05 100.3919768

33.933 -8.42E-03 2.99E-05 -1.78E-08 3.69E-12 33.8956495594

W/m K -3.75E-01W/m K 1.30E-02

gr/ml 61.5164383374

mcp 0.0002622669mcp 0.0002428582

j/mol k 1.8830916422 j/gr K 0.44976871





Kecepatan pemanas = 3468.8465944622 Kg/jamQ = 1308617.174491 kj/jam

192.7136996923 Kmol/jam1243186.3157664 btu/jam

Ud= 5 BTU/jam.ft2.F [Kern tabel 8 hal 840]T reff= 25 oC 77 F

Hot fluid=Data shell (steam) Cold fluid=t1 (in)= 30 86 Ft2 (out)= 100 212 FT average= 65 149 F

Data tubeT1 (in)= 190 374 FT2 (out)= 70 158 FT average= 130 266 F

oCoCoC

oCoCoC

Menghitung TFluida Panas Fluida Dingin Selisih

374 T. tinggi 212 162.0158 T. rendah 86 72.0216 126.0 90.0

LMTD = 110.9837R = (T1-T2)/(t2-t1) = 1.71429S = (t2-t1)/(T1-T2) = 0.4375Dari figure 18 Kern, diperoleh faktor koreksiFt = 0.975 4 shellT = LMTD x Ft = 108.2 FTabel 10, Kern 843OD = 3/4 in 0.0625 ftID = 0.652 in 0.0543333333 ftBWG = 18A inside = 0.1707 ft2/ftA outside = 0.1968 ft2/ftAtube = 0.334 in2L = 12 ft 144tebal = 0.049 ft

2297.74894095

972.962796811

tabel 9 kern 841:tubeOD = 3/4 inpitch = square 1 pass = 4jmlh tube (Nt) = 1012 tubeL/ID = 220.858895706shell ID = 37 in 3.0833020066 ft

Koreksi:

At= ft2

Nt=

LMTDUQA

dt .

0.ALA

N tt

LMTDUQA

dt .

0.ALA

N tt

LNALMTDQU

toutsided ...

1

2

12

ttln

ttLMTD

LNALMTDQU

toutsided ...

1

2

12

ttln

ttLMTD

Ud= 4.8071284427 BTU/jam.ft2.F

At= 2389.9392 ft2

Physical PropertiesTube: Densitas () = 53.6511

Viskositas ( ) = 3.70E-011.68E-01

konduktifitas thermal (kf) = 5.13E-01heat capacity = 4.50E-01

shell: Densitas () = 61.8169098879water Viskositas ( ) = 1.03E+00

konduktifitas thermal (kf) = 1.28E-02heat capacity = 0.4493486993

Tube Side

t= 0.5868194444 in2 = 0.004075135 ft2

Gt= 851222.491571 Kg/jam.ft2

Re= 2.76E+05jH= 450 [fig 24 kern 834]

hi= 244.322027432 BTU/jam.ft2.F

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

33,0...k

CpIDkjHhi

ODIDhh iio .

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

33,0...k

CpIDkjHhi

ODIDhh iio .

212.397282514

SHELL SIDE (cold fluid) jarak baffle = B = 7.4 in

0.6166666667 ft

De= 1.48 in0.1233333333 ft

As= 0.4753472222 in2 0.0396122685 ft


Re= 4.77E+03

jH= 45


212.397282514 BTU/jm.ft2.F


0.007074429


f= 0.00015 [fig 26 kern 836]Densitas= 53.6510934 lb/ft3

859.4100396279 kg/m3Gt= 851222.491571408 Kg/jam.ft2

386919.31435064 lb/jam.ft2

hio=

ho=

hio=

Rd=

5ID

5ID


)..(

ss A

mG

es DG .Re

33,0...k

CpDkjHh

eo

00

00.hh

hhUi

iC

dc

dcd UU

UUR.


)..(

ss A

mG

es DG .Re

00

00.hh

hhUi

iC

dc

dcd UU

UUR.

Pt= 0.9615170372 Psi0.0654093223 atm

0.02 [fig 27 kern 837]

Pr= 0.32 psi0.0217687075 atm

0.0871780297 atm


f= 0.002 [fig 26 kern 839]


N + 1 = 233.513513514

0.3543826939 psi0.0241076663 atm

0.111285696 atm1.6354545883 psi

V2/2g =

PT=


10

2


10

2

gVnPr 2.4 2

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

gVnPr 2.4 2

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

bhn bkupmnas

[Kern tabel 8 hal 840]

steamlight organic

1

2

12

ttln

ttLMTD

1

2

12

ttln

ttLMTD

lb/ft3lb/ft.jam h2Kg/ft.jam h20

densityh20

lb/ft3 viscositylb/ft.jam h20

h2cph20



33,0...k

CpDkjHh

eo

dc

dcd UU

UUR.

dc

dcd UU

UUR.

gVnPr 2.4 2

gVnPr 2.4 2

A B C0.03951 4.59E-04 -6.49E-06 -6.49E-010.00053 4.71E-05 4.96E-08 2.25E-02

n0.3471 0.274 0.28571 0.985366624

-36.826 4.29E-01 -1.62E-05 108.415086227.758 2.12E-01 -3.28E-05 100.3919768

33.933 -8.42E-03 2.99E-05 -1.78E-08 3.69E-12 33.8956495594

W/m K -3.75E-01W/m K 1.30E-02

gr/ml 61.5164383374

mcp 0.0002622669mcp 0.0002428582

j/mol k 1.8830916422 j/gr K 0.44976871





Kecepatan pemanas =Q =

Ud= 2 BTU/jam.ft2.FT reff= 25 oC

Data shell (steam)t1 (in)= 28t2 (out)= 50T average= 39

Data tubeT1 (in)= 70

oCoCoC

oC

T2 (out)= 30T average= 50

Menghitung TFluida Panas

158 T. tinggi86 T. rendah72

LMTD = 14.0711R = (T1-T2)/(t2-t1) = 1.81818S = (t2-t1)/(T1-T2) = 0.5238095238Dari figure 18 Kern, diperoleh faktor koreksiFt = 0.975 4 shellT = LMTD x Ft = 13.7 FTabel 10, Kern 843OD = 1 1/2 inID = 1.15 inBWG = 18A inside = 0.367 ft2/ftA outside = 0.3925 ft2/ftAtube = 1.54 in2L = 12 ft tebal = 0.049 ft

41.0494819551

8.7153889501

tabel 9 kern 841:tubeOD = 1 1/2 inpitch = square 1 7/ 8pass = 4jmlh tube (Nt) = 12 tube

oCoC

At= ft2

Nt=

LMTDUQA

dt .

0.ALAN tt

LMTDUQA

dt .

0.ALAN tt

LMTDUQA

dt .

0.ALAN tt

L/ID = 125.217391304shell ID = 39 in

Koreksi:

Ud= 1.452564825 BTU/jam.ft2.F

At= 56.52 ft2

Physical PropertiesTube: Densitas ()

Viskositas ( )

konduktifitas thermal (kf)heat capacity

shell: Densitas ()water Viskositas ( )


Tube Side

t= 0.0320833333 in2 =

Gt= 12695402.8474 Kg/jam.ft2

Re= 1.19E+10jH= 1000 [fig 24 kern 834]

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

hi= 420.88290242 BTU/jam.ft2.F

322.676891855

SHELL SIDE (cold fluid) jarak baffle = B = 7.8

0.65

De= 1.48 in0.1233333333 ft

As= 0.4225 in2


Re= 1.95E+07

jH= 700


322.676891855 BTU/jm.ft2.F

Uc= 13.2784946712 BTU/jam.ft2.F

13.2031849298

hio=

ho=

hio=

Rd=

5ID

5ID

5ID

33,0...k

CpIDkjHhi

ODIDhh iio .


)..(

33,0...k

CpIDkjHhi

ODIDhh iio .


)..(

33,0...k

CpIDkjHhi

ODIDhh iio .


)..(


f= 0.00012Densitas= 5.6125

89.90383125Gt= 12695402.8473737

5770637.65789712

Pt= 115.02818094017.8250463225

1

Pr= 161.0884353741

8.9134816966


f= 0.002 [fig 26 kern 839]


N + 1 = 221.538461538

8.9337716211131.2907077443

V2/2g =

PT=


10

2


10

2


10

2

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

2828.5475093975 Kg/jam1185.6268019048 kj/jam157.1415282999 Kmol/jam bhn bku

1126.3454618095 btu/jam pmnas

[Kern tabel 8 hal 840]77 F

Hot fluid= steamCold fluid= light organic

82.4 F122 F

102.2 F

158 F

86 F122 F

Fluida Dingin Selisih122 36.082.4 3.639.6 32.4

0.125 ft0.0958333333 ft

144

1

2

12

ttln

ttLMTD

1

2

12

ttln

ttLMTD

1

2

12

ttln

ttLMTD

3.2499669799 ft

= 5.6125 lb/ft3= 2.25E-04 lb/ft.jam

1.02E-04 Kg/ft.jam= 0.2828947067= 3.44E+00

= 63.3481004801 lb/ft3= 0.0002308911 lb/ft.jam= 0.0115826897= 0.447321153

0.0002228009 ft2



inft

0.0352083333 ft

ODIDhh iio .


)..(

ss A

mG

es DG .Re

33,0...k

CpDkjHh

eo

00

00.hh

hhUi

iC

dc

dcd UU

UUR.


)..(

es DG .Re

33,0...k

CpDkjHh

eo

00

00.hh

hhUi

iC

dc

dcd UU

UUR.


)..(

es DG .Re

00

00.hh

hhUi

iC

dc

dcd UU

UUR.

[fig 26 kern 836]lb/ft3kg/m3Kg/jam.ft2lb/jam.ft2

Psiatm[fig 27 kern 837]

psiatm

atm

0.2982618907 psi0.0202899245 atm

atmpsi

dc

dcd UU

UUR.

gVnPr 2.4 2

rtT PPP

dc

dcd UU

UUR.

gVnPr 2.4 2

rtT PPP

dc

dcd UU

UUR.

gVnPr 2.4 2

rtT PPP

A Bh2 0.03951 4.59E-04h20 0.00053 4.71E-05

densityh20 0.3471 0.274viscosityh20 -36.826 4.29E-01h2 27.758 2.12E-01cph20 33.933 -8.42E-03h2 25.399 2.02E-02

312

C-6.49E-06 -4.90E-01 W/m K4.96E-08 2.00E-02 W/m K

n0.28571 1.0147060785 gr/ml

-1.62E-05 95.4450272 mcp-3.28E-05 92.8120088 mcp

2.99E-05 -1.78E-08 3.69E-12 33.7111956628 j/mol k-3.85E-05 3.19E-08 -8.76E-12 28.8272658104 j/mol k

-2.83E-011.16E-02

63.3481004801

0.00023089110.0002245215

1.8728442035 j/gr K 0.4473211514.4136329052 j/gr K 3.44263707

3x2 inSTEAMLaju alir = 2828.547509397 kg/jam 6235.816 lbm/jamt1 (in)= 25 77 Ft2 (out)= 50 122 F 1 kg =T average= 37.5 99.5 F 1 m3 =

1 m =UmpanLaju alir = 2.0758631643 kg/jam 4.576448 lbm/jamT1 (in)= 70 158 FT2 (out)= 30 86 FT average= 50 122 F

Q = 1185.6268 kj/jam65.8681557 Kmol/jam bhn bku1126.34546 btu/jam pmnas

umpan steam delta158 tinggi 122 36

86 rendah 77 9

LMTD = 19.476383052

TC = 122 ftc = 99.5 f

Fluida dingin (steam)D2 = 3.068 in = 0.255667 ft (tabel 11 kern)D1 = 2.38 in = 0.198333 ft (tabel 11 kern)

aa= 0.0204330267 ft2

De = 0.1312403361 ft

oCoCoC

oCoCoC

Ga = 223.97308078 lb/ ft2 jamviscosity = 0.2308910653 lbm / ft jam

Re = 1.27E+02Jh = 6Cp = 0.447321153k = 0.0115826897

ho/s = 1.5739438132 Btu/jam ft2 F

UC = 1.5002120257 Btu/jam ft2 F

Faktor PengotorRd = 0.01

Ud = 2 (kern, tabel 8)

= 28.915673377 ft2

A outside = 0.622 ft2/ft

Panjang yang dibutuhkan = 46.48822 ft

Berarti dapat digunakan 5 x 15 ft hairpin dengan panjang total = 75

A sebenar'y46.65 ft2 4.334032

Ud = 1.2396858897

Rd = -0.140083504

BTU/lb.oFBtu/jam.ft.oF

LMTDUQA

dt .

De' = 0.0573333333

Nre' = 55.615505438

f= 0.0523226843density = 63.3481004801

delta p = 1.78839E-006

V= 0.0009821091

delta pn = 7.48865E-008

delta pan 8.19687E-007 psi

DELTA P TOTAL =

2.2046 lbm35.313 ft3 = 61023.37795 in33.2808 ft = 39.37 in

Fluida panasD = 2.067 in = 0.255667 ft

ap = 0.051358563 ft2

gp = 121417.2558 lb/ft2 jamviscosity = 2.25E-01 lbm/ft jam

Re = 1.38E+05

jh = 300Cp = 0.282894707k = 0.011 Btu/jam.ft.oF

ho/s = 24.84326695

Ho = 32.02485001 Btu/jam ft2 Fs = 1Hio = 32.02485001 Btu/jam ft2 F

ft

BTU/lb.oF

f = 5.33E-03density = 5.6125

3.50136106 psi

3.501362 PSI





Kecepatan pemanas =Q =

Ud= 5 BTU/jam.ft2.FT reff= 25 oC

Data shell (steam)t1 (in)= 0t2 (out)= 15T average= 7.5

Data tubeT1 (in)= 70

oCoCoC

oC

T2 (out)= 6T average= 38

Menghitung TFluida Panas

158 T. tinggi42.8 T. rendah

115.2

LMTD = 39.8091R = (T1-T2)/(t2-t1) = 4.26667S = (t2-t1)/(T1-T2) = 0.2142857143Dari figure 18 Kern, diperoleh faktor koreksiFt = 0.92 4 shellT = LMTD x Ft = 36.6 FTabel 10, Kern 843OD = 1 1/2 inID = 1.4 inBWG = 18A inside = 0.367 ft2/ftA outside = 0.3925 ft2/ftAtube = 1.54 in2L = 12 ft tebal = 0.049 ft

731.830482431

155.378021748

tabel 9 kern 841:tubeOD = 1 1/2 inpitch = square 1 7/ 8pass = 4jmlh tube (Nt) = 237 tube

oCoC

At= ft2

Nt=

LMTDUQA

dt .

0.ALAN tt

LMTDUQA

dt .

0.ALAN tt

LMTDUQA

dt .

0.ALAN tt

L/ID = 102.857142857shell ID = 39 in

Koreksi:

Ud= 3.2780173364 BTU/jam.ft2.F

At= 1116.27 ft2

Physical PropertiesTube: Densitas ()

Viskositas ( )


shell: Densitas ()ammonia Viskositas ( )


Tube Side

t= 0.6336458333 in2 =

Gt= 249735.032883 Kg/jam.ft2

Re= 1.74E+05jH= 500 [fig 24 kern 834]

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

LNALMTDQU

toutsided ...

naN

a tubett .144.

tawGt

/Re IDxGt

hi= 218.514519078 BTU/jam.ft2.F

203.946884472

SHELL SIDE (cold fluid) jarak baffle = B = 7.8

0.65

De= 1.48 in0.1233333333 ft

As= 0.4225 in2


Re= 1.92E+03

jH= 22


203.946884472 BTU/jm.ft2.F


0.0092906368

hio=

ho=

hio=

Rd=

5ID

5ID

5ID

33,0...k

CpIDkjHhi

ODIDhh iio .


)..(

33,0...k

CpIDkjHhi

ODIDhh iio .


)..(

33,0...k

CpIDkjHhi

ODIDhh iio .


)..(


f= 0.00015Densitas= 59.9

959.50815Gt= 249735.0328827

113515.924037591

Pt= 0.90264532240.0614044437

0.0011

Pr= 0.01760.0011972789

0.0626017226


f= 0.002 [fig 26 kern 839]


N + 1 = 221.538461538

0.06566425430.9650018819

V2/2g =

PT=


10

2


10

2


10

2

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

rtT PPP

..10.22,5)1.(..

10

2

e

sss D

NIDGfP

Ts PPP

1098.9136321075 Kg/jam141067.54295365 kj/jam

61.0507573393 Kmol/jam bhn bku134014.16580596 btu/jam pmnas

[Kern tabel 8 hal 840]77 F

Hot fluid= steamCold fluid= light organic

32 F59 F

45.5 F

158 F

42.8 F100.4 F

Fluida Dingin Selisih59 99.032 10.8

27.0 88.2

0.125 ft0.1166666667 ft

144

1

2

12

ttln

ttLMTD

1

2

12

ttln

ttLMTD

1

2

12

ttln

ttLMTD

3.2499669799 ft

= 59.9 lb/ft3= 0.369854 lb/ft.jam

0.1677646739 Kg/ft.jam= 0.0267685751= 0.51

= 38.4971795 lb/ft3= 0.9107550495 lb/ft.jam= 0.290517874= 0.5020947829

0.0044003183 ft2



inft

0.0352083333 ft

ODIDhh iio .


)..(

ss A

mG

es DG .Re

33,0...k

CpDkjHh

eo

00

00.hh

hhUi

iC

dc

dcd UU

UUR.


)..(

ss A

mG

es DG .Re

33,0...k

CpDkjHh

eo

00

00.hh

hhUi

iC

dc

dcd UU

UUR.


)..(

ss A

mG

es DG .Re

00

00.hh

hhUi

iC

dc

dcd UU

UUR.

[fig 26 kern 836]lb/ft3kg/m3Kg/jam.ft2lb/jam.ft2

Psiatm[fig 27 kern 837]

psiatm

atm

0.0450192166 psi0.0030625317 atm

atmpsi

dc

dcd UU

UUR.

gVnPr 2.4 2

rtT PPP

dc

dcd UU

UUR.

gVnPr 2.4 2

rtT PPP

dc

dcd UU

UUR.

gVnPr 2.4 2

rtT PPP

A Bh2 0.03951 4.59E-04h20 1.1606 -2.28E-03

densityh20 0.3471 0.274nh3 0.23689 0.25471viscosityh20 -36.826 4.29E-01nh3 -8.591 8.76E+02cph20 33.933 -8.42E-03nh3 33.573 -1.26E-02

C-6.49E-06 -6.49E-01 W/m K3.12E-18 5.03E-01 W/m K

n0.28571 0.985366624 gr/ml0.2887 0.616645515 gr/ml

-1.62E-05 108.4150862 mcp2.68E-02 -3.61E-05 1355.3507589156 cp

2.99E-05 -1.78E-08 3.69E-12 33.8956495594 j/mol k8.89E-05 -7.18E-08 1.86E-11 35.73689743 j/mol k

-3.75E-012.91E-01

61.516438337438.4971795

0.00026226690.9107550495

1.8830916422 j/gr K 0.449768712.1021704371 j/gr K 0.50209478

cooler keluaran reaktorSheet2cooler hidrogenSheet1cooler margarin

Cooler

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