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Contoh Soal Analisa Matriks (Portal Hal.172)

Feb 24, 2018

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    CONTOH 4.2

    Properties penampang

    Batang 1 (KOLOM) :

    b1 = 0.35 m

    h1 = 0.35 m

    A1 = 0.1225 m2

    I1 = 0.0012505208 m4

    L1 = 3.5 m

    Batang 2 (BALOK) :

    b2 = 0.20 m

    h2 = 0.45 m

    A2 = 0.09 m2

    I2 = 0.00151875 m4

    L2 = 5 mBahan / mate!a" :

    # = 21000000 $%/m2

    &!t'ng mat!$ $e$a$'an batang 1 (M1)

    A$!bat *!+"a,ement aah 1 -- 1 (tan"a! aah b "$a" 1)

    M 1.1 = #.A / L = 735000

    M 2.1 = 0 = 0

    M 3.1 = 0 = 0

    A$!bat *!+"a,ement aah 2 -- 2 (tan"a! aah b "$a" 2)

    M 1.2 = 0 = 0

    M 2.2 = 12.#I/L3 = 7350

    M 3.2 = .#I / L2 = 1282.5

    A$!bat *!+"a,ement aah 3 -- 3 (ta! aah b "$a" 3)

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    M 1.3 = 0 = 0

    M 2.3 = .#I / L2 = 1282.5

    M 3.3 = 4 #I / L = 30012.5

    A$!bat *!+"a,ement aah 4 -- 4 (tan"a! aah b "$a" 4)

    M 1.4 = - #.A / L = -735000

    M 2.4 = 0 = 0

    M 3.4 = 0 = 0

    A$!bat *!+"a,ement aah 5 -- 5 (tan"a! aah b "$a" 5)

    M 1.5 = 0 = 0

    M 2.5 = -12.#I/L3 = -7350

    M 3.5 = -.#I / L2 = -1282.5

    A$!bat *!+"a,ement aah -- (ta! aah b "$a" )

    M 1. = 0 = 0

    M 2. = .#I / L2 = 1282.5

    M 3. = 2 #I / L = 1500.25

    ''nan mat!$ $e$a$'an batang 1 (M1) :

    M11 M12 M13 M14

    M21 M22 M23 M24

    M1 = M31 M32 M33 M34

    M41 M42 M43 M44

    M51 M52 M53 M54

    M1 M2 M3 M4

    '*'t batang 1 : = 90

    Mat!$ tanma! ta! :

    0 0

    = 0 0

    0 0 1 0

    0 0 0

    0 0 0

    0 0 0 0

    1

    , 1

    !n 1

    - !n 1

    , 1

    , 1

    - !n 1

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    an+e mat!$ ta! 6

    0.00 -1 0 0

    = 1 0.00 0 0

    0 0 1 0

    0 0 0 0.000 0 0 1

    0 0 0 0

    Mat!$ $e$a$'an t'$t' mena*! :

    0.00 -1.00 0.00 0.00

    1.00 0.00 0.00 0.00

    0.00 0.00 1.00 0.00M 1 = 0.00 0.00 0.00 0.00

    0.00 0.00 0.00 1.00

    0.00 0.00 0.00 0.00

    4.50242#-011 -7350 -1282.5 -4.502#-011

    735000 4.502#-013 7.8792#-013 -735000

    0 1282.5 30012.5 0

    -4.5024#-011 7350 1282.5 4.502#-011

    -735000 -4.502#-013 -7.879#-013 735000

    0 1282.5 1500.25 0

    &!t'ng mat!$ $e$a$'an batang 2 (M2)

    A$!bat *!+"a,ement aah 1 -- 1 (tan"a! aah b "$a" 1)

    M 1.1 = #.A / L = 378000

    M 2.1 = 0 = 0

    M 3.1 = 0 = 0

    A$!bat *!+"a,ement aah 2 -- 2 (tan"a! aah b "$a" 2)

    M 1.2 = 0 = 0

    M 2.2 = 12.#I/L3 = 301.8

    M 3.2 = .#I / L2 = 754.5

    A$!bat *!+"a,ement aah 3 -- 3 (ta! aah b "$a" 3)

    M 1.3 = 0 = 0

    M = . M .

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    M 2.3 = .#I / L2 = 754.5

    M 3.3 = 4 #I / L = 25515

    A$!bat *!+"a,ement aah 4 -- 4 (tan"a! aah b "$a" 4)

    M 1.4 = - #.A / L = -378000

    M 2.4 = 0 = 0

    M 3.4 = 0 = 0

    A$!bat *!+"a,ement aah 5 -- 5 (tan"a! aah b "$a" 5)

    M 1.5 = 0 = 0

    M 2.5 = -12.#I/L3 = -301.8

    M 3.5 = -.#I / L2 = -754.5

    A$!bat *!+"a,ement aah -- (ta! aah b "$a" )

    M 1. = 0 = 0

    M 2. = .#I / L2 = 754.5

    M 3. = 2 #I / L = 12757.5

    ''nan mat!$ $e$a$'an batang 2 (M2) :

    M11 M12 M13 M14

    M21 M22 M23 M24

    M2 = M31 M32 M33 M34

    M41 M42 M43 M44

    M51 M52 M53 M54

    M1 M2 M3 M4

    '*'t batang 2 : = 0

    Mat!$ tanma! ta! :

    0 0

    = 0 0

    0 0 1 0

    0 0 0

    0 0 00 0 0 0

    2

    , 1

    !n 1

    - !n 1

    , 1

    , 1

    - !n

    1

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    an+e mat!$ ta! 6

    1.00 0 0 0

    = 0 1.00 0 0

    0 0 1 0

    0 0 0 1.00

    0 0 0 0

    0 0 0 0

    Mat!$ $e$a$'an t'$t' mena*! :

    1.00 0.00 0.00 0.00

    0.00 1.00 0.00 0.00

    0.00 0.00 1.00 0.00

    M 2 = 0.00 0.00 0.00 1.000.00 0.00 0.00 0.00

    0.00 0.00 0.00 0.00

    378000 0 0 -378000

    0 301.8 754.5 0

    0 754.5 25515 0

    -378000 0 0 378000

    0 -301.8 -754.5 0

    0 754.5 12757.5 0

    Susun MATRIKS KEKAKUAN STRUKTUR

    1

    1 2 3 7

    7350 0 -1283 -7350

    0 735000 0 0

    M 1 = -1283 0 30013 1283

    -7350 0 1283 7350

    0 -735000 0 0

    -1283 0 1500 1283

    1 2 3

    7 8 9 4

    378000 0 0 -378000

    0 302 755 0

    M 2 = 0 755 25515 0

    -378000 0 0 378000

    0 -302 -755 0

    0 755 12758 0

    MATRIKS KEKAKUAN STRUKTUR

    M = . M .

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    1 2 3

    7 8 9

    385350 0 1283 7

    M = 0 73802 755 8

    1283 755 55528 9

    Batang 1

    Gbr AM 1 =

    Batang 2

    Gbr AM 2 =

    Transformasi dari sumbu lokal ke sumbu global struktur

    Batang 1

    0 1

    0 2

    AM 1 = 0 3

    0 4

    0 5

    0 6

    SB LOKAL

    0.00 -1.00 0.00 0.00

    1.00 0.00 0.00 0.00

    = 0.00 0.00 1.00 0.00

    0.00 0.00 0.00 0.00

    Hitung rekasi di ujung batang / freebody (AML) --- Beban dimasukkan ke!uali beban di joint

    AML1

    AML2

    AML3

    AML4

    AML5

    AML6

    AML1

    AML2

    AML3

    AML4

    AML5AM

    L6

    RT

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    0.00 0.00 0.00 1.00

    0.00 0.00 0.00 0.00

    0 2 1

    0 1 2

    = 0 3 30 5 7 D1

    0 4 8 D2

    0 9 D3

    SB GLOBAL

    Batang 2

    0 1 7

    150 2 8AM 2 = 125 3 9

    0 4 4

    150 5 5

    -125 6

    SB LOKAL

    1.00 0.00 0.00 0.00

    0.00 1.00 0.00 0.00= 0.00 0.00 1.00 0.00

    0.00 0.00 0.00 1.00

    0.00 0.00 0.00 0.00

    0.00 0.00 0.00 0.00

    0 1 7 D1

    150 2 8 D2

    = 125 3 9 D3

    0 4 4150 5 5

    -125 6

    SB GLOBAL

    BEBAN EKIVALEN GABNGAN !AE"

    B 1 B 2

    1 0 0

    2 0 0

    3 0 0

    4 0 0

    5 0 150

    AMS1

    RT

    AMS2

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    -A# = 0 ; -125

    1 7 0 0

    2 8 0 150

    3 9 0 125

    SB GLOBAL

    B#b$% &$'$ ()*%+ ,$%/% !A("

    1 0

    2 0

    3 0

    4 0

    A = 5 0

    0

    1 7 40

    2 8 03 9 0

    SB GLOBAL

    BEBAN OINT GABNGAN !A"

    A = A( AE

    1 0 0

    2 0 0

    3 0 04 0 0

    A, = 5 0 ; -150 =

    0 125

    7 40 0

    8 0 -150

    9 0 -125

    1 402 -150

    3 -125

    "#$%&MA' 'T&*T&

    &!t'ng +e+!n*ahan

    2.1529#-00 .292#-009 -.07#-007

    = .29192#-009 1.357#-00 -1.885#-007 'at!n:

    ea,t!n A++"!e*

    40 ; 0

    0 ; -1500 ; -125

    &1 ; 0 =

    E1 ; 0

    M1 ; 0

    &3 ; 0

    E3 ; -150

    M3 ; 125

    an*a (;) (-) *!tent'$an "eh aa

    THEOR10

    1

    2

    1=

    2=

    eF!te 1: $G*1=1-$G*2

    *1=!nee($)G(1-$G*2)

    !+"a,ement: '2 = 0.0001795029

    2 = -0.000179714

    +h!2 = -0.002279435

    ea,t!n: &1 = 0

    E1 = 0

    M1 = 0

    &3 = 0

    E3 = 150M3 = -125

    ata' 27.852077784

    132.089777923

    -31.724472274

    -7.852077785

    17.910222077

    -155.3089103

    ata' 27.852077784

    132.089777923

    -31.724472274

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    -7.852077785

    17.910222077

    -155.3089103

    ata' 27.852077784

    132.089777923

    -31.724472274-7.852077785

    17.910222077

    -155.3089103

    Ata'

    Bent'$ mat!$ A, *ah'"' : 1

    2

    A/ A3 Ae A = 3

    4

    5

    7

    8

    9

    b g"ba"

    0.0001795029m

    *! = -0.000179714 m

    -0.002279435 a*

    0 27.852077784

    0 132.089777923

    0 ; -31.724472274 =

    ea,t = 0 -7.852077785

    150 17.910222077

    -125 -30.308910357

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    @atatan a = %/m2

    Batang 2 :

    0.20

    0.45

    9.00#-02

    # = 2.10#;07

    1.52#-03

    5

    0

    E!emen "a!am matri#s #e#a#uan atang

    12.EI L>3 EA L 4.EI L

    7.35#;03 3.78#;05 2.55#;04

    .#I / L2 12.#I / L3 theta

    1.29#;04 7.35#;03 90 *eg7.5#;03 3.0#;03 0 *eg

    AM SUM$U STRUKTUR)*(O$A(

    12.#I / L3

    7.35#;03

    b2=

    h2=

    A2=

    I2=

    L2=

    theta2=

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    '2 2 +h!2 ,e$ :

    -7350 -4.45739#-011 -1282.5 7350

    -4.45739#-011 -735000 7.88#-13 0

    1.29#;04 -7.87923#-013 1.50#;04 -1283

    7.35#;03 4.45739#-011 1.29#;04 -7350

    4.45739#-011 7.35#;05 -7.87924#-013 01.29#;04 -7.87923#-013 3.00#;04 -1283

    AM SUM$U STRUKTUR)*(O$A(

    12.#I / L3

    3.0#;03

    '3 3 +h!3 ,e$ :

    -378000 0 0 378000

    0 -301.8 7.5#;03 0

    0.00#;00 -754.5 1.28#;04 0

    3.78#;05 0 0.00#;00 -378000

    0 3.0#;03 -754.5 0

    0.00#;00 -754.5 2.55#;04 0

    0 0 0 0 0 0

    '1 1 +h!1 '3 3 +h!3

    -7350 -4.45739#-011 1282.5 -378000 0 0

    -4.45739#-011 -735000 -7.87924#-013 0 -301.8 754.5

    -1282.5 7.87923#-013 1500.25 0 -754.5 12757.5

    7350 4.45739#-011 -1282.5 0 0 0

    4.45739#-011 735000 7.87923#-013 0 0 0

    -1282.5 7.87923#-013 30012.5 0 0 00 0 0 378000 0 0

    0 0 0 0 301.8 -754.5

    0 0 0 0 -754.5 25515

    6K < C*D

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    H,e ! a,t!ng *FnFa*

    '2 2 +h!2 '1 1

    '2 385350 4.45739#-011 1282.5 -7350 -4.45739#-011

    2 4.45739#-011 73801.8 754.5 -4.45739#-011 -735000+h!2 1282.5 754.5 55527.5 -1282.5 7.87923#-013

    '1 -7350 -4.45740#-011 -1282.5 7350 4.45739#-011

    1 -4.45739#-011 -735000 7.879#-013 4.45739#-011 735000

    +h!1 1282.5 -7.87924#-013 1500.25 -1282.5 7.87923#-013

    '3 -378000 0 0 0 0

    3 0 -301.8 -754.5 0 0

    +h!3 0 754.5 12757.5 0 0

    b g"ba"

    = $ $ G *1

    $ $ *2

    $G*1;$G*2

    $G*1;$G*2

    m

    m

    a*

    ; 27.852077784 = 27.8520778 $%

    ; 132.089777923 = 132.089778 $%

    ; -31.724472274 = -31.7244723 $%.m

    ; -7.852077785 = -7.8520778 $%

    ; 17.910222077 = 17.910222 $%; -30.308910357 = -155.30891 $%.m

    -

    -

    -

    -

    -

    -

    -

    -

    -

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    -

    -

    -

    -

    -

    --

    -

    -

    0 1 0

    0 2 0

    0 -Ae = 3 0

    40 4 0

    0 5 150

    0 125

    0 7 0

    0 8 150

    0 9 -125

    b g"ba"

    @e$:

    -

    -

    -

    @e$:

    27.852077784 $% &1 -

    132.089777923 $% E1 -

    -31.724472274 $%.m M1 -

    -7.852077785 $% &3 -

    17.910222077 $% E3 -

    -155.3089103 $%.m M3 -

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    m

    m

    m2

    $%/m2

    m4

    m

    *egee

    2.EI L 6.EI L>2 12.EI L>3

    1.28#;04 7.5#;03 3.0#;03

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    0 -1283 -7350 0 -1283

    735000 0 0 -735000 0

    0 30013 1283 0 1500

    0 1283 7350 0 1283

    -735000 0 0 735000 00 1500 1283 0 30013

    0 0 -378000 0 0

    302 755 0 -302 755

    755 25515 0 -755 12758

    0 0 378000 0 0

    -302 -755 0 302 -755

    755 12758 0 -755 25515

    ,e$ :

    *1 385350 4.45740#-011 1282.5

    *2 4.45739#-011 73801.8 754.5

    *3 1282.5 754.5 55527.5

    0

    0

    00

    0

    0

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    +h!1 '3 3 +h!3

    1282.5 -378000 0 0 '2

    -7.87923#-013 0 -301.8 754.5 21500.25 0 -754.5 12757.5 +h!2

    -1282.5 0 0 0 < 0

    7.87923#-013 0 0 0 0

    30012.5 0 0 0 0

    0 378000 0 0 0

    0 0 301.8 -754.5 0

    0 0 -754.5 25515 0

    ,e$:

    0.000179503

    -0.000179714

    -0.00227944

    ,e$:

    132.09

    -27.85

    -31.72

    -7.85

    17.91-155.31

    b "$a"

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    0 0 1

    0 0 2

    Ae = 0 A, = 0 3

    0 40 4

    -150 -150 5

    -125 -125

    0 0 7

    -150 -150 8

    125 125 9

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    - - - - - -

    - - - - - -

    - - - - - -

    - - - - - -

    - - - - - -- - - - - -

    - - - - - -

    - - - - - -

    - - - - - -

    - - - - - -

    - - - - - -

    - - - - - -

    385350 0 1283 - - -

    0 73802 755 - - -

    1283 755 55528 - - -

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    -

    -

    -

    27.8520778 -

    132.09 -

    -31.72 -

    -7.85 -

    17.91 --155.31 -

    b g"ba"

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    40 *1 4

    -150 *2 5

    A, = -125 *3

    *1 0 1

    *2 0 2

    *3 0 3

    0 7

    -150 8

    125 9

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    Properties penampang

    Bahan / mate!a" :

    # = 2.10#;07 $%/m2

    Batang 1 :

    0.35m

    0.35m

    1.23#-01 m2

    # = 2.10#;07 $%/m2

    1.25#-03 m4

    3.5m

    90 *egee

    E!emen "a!am matri#s #e#a#uan atang

    EA L 4.EI L 2.EI L 6.EI L>2

    7.35#;05 3.00#;04 1.50#;04 1.29#;04

    Re#ap E!emen "a!am Matri#s Ke#a#uan $atangBatang #A / L 4.#I / L 2.#I / L

    1 7.35#;05 3.00#;04 1.50#;04

    2 3.78#;05 2.55#;04 1.28#;04

    %%%& su"a' DA(

    u1 v1 phi1

    u1 7350 0 -12862.5

    v1 0 735000 0

    phi1 -12862.5 0 30012.5

    u2 -7350 0 12862.5

    b1=

    h1=

    A1=

    I1=

    L1=

    theta1=

    Hitung matri#s #e#a#uan atang + ,SM+-

    6M1 =

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    v2 0 -735000 0

    phi2 -12862.5 0 15006.25

    %%%& su"a' DA(

    u2 v2 phi2

    u2 378000 0 0

    v2 0 3061.8 7654.5

    phi2 0 7654.5 25515

    u3 -378000 0 0

    v3 0 -3061.8 -7654.5

    phi3 0 7654.5 12757.5

    u2 v2 phi2u2 385350 0 12862.5

    v2 0 738061.8 7654.5

    phi2 12862.5 7654.5 55527.5

    u1 -7350 0 -12862.5

    v1 0 -735000 0

    phi1 12862.5 0 15006.25

    u3 -378000 0 0

    v3 0 -3061.8 -7654.5

    phi3 0 7654.5 12757.5

    Hitung matri#s #e#a#uan atang 2 ,SM2-

    6M2 =

    MATRIKS KEKAKUAN STRUKTUR ,SMS-

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    @atatan a = %/m2

    Batang 2 :

    # =

    E!emen "a!am matri#s #e#a#ua

    12.EI L>3 EA L

    7.35#;03 3.78#;05

    .#I / L2 12.#I / L3 theta

    1.29#;04 7.35#;03 90 *eg

    7.5#;03 3.0#;03 0 *eg

    M SUM$U STRUKTUR)*(O$A(

    u2 v2 phi2

    -7350 0 -12862.5 7350

    0 -735000 0 4.45740E-011

    12862.5 0 15006.25 -12862.5

    7350 0 12862.5 -7350

    b2=

    h2=

    A2=

    I2=

    L2=

    theta2=

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    0 735000 0 -4.4574E-011

    12862.5 0 30012.5 -12862.5

    M SUM$U STRUKTUR)*(O$A(

    u3 v3 phi3 u2

    -3.78E+05 0 0 378000

    0 -3061.8 7654.5 0

    0 -7654.5 12757.5 0

    3.78E+05 0 0 -378000

    0 3061.8 -7654.5 0

    0 -7654.5 25515 0

    u1 v1 phi1 u3 v3-7350 0 12862.5 -378000 0

    0 -735000 0 0 -3061.8

    -12862.5 0 15006.25 0 -7654.5

    7350 0 -12862.5 0 0

    0 735000 0 0 0

    -12862.5 0 30012.5 0 0

    0 0 0 378000 0

    0 0 0 0 3061.8

    0 0 0 0 -7654.5

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    0.20m

    0.45m

    9.00#-02m2

    2.10#;07$%/m2

    1.52#-03m4

    5 m

    0 *egee

    atang

    4.EI L 2.EI L 6.EI L>2 12.EI L>3

    2.55#;04 1.28#;04 7.5#;03 3.0#;03

    4.45740E-011 -12862.5 -7350 -4.4574E-011 -12862.5

    735000 7.87924E-013 -4.4574E-011 -735000 7.88E-013

    7.87924E-013 30012.5 12862.5 -7.8792E-013 15006.25

    -4.4574E-011 12862.5 7350 4.45740E-011 12862.5

  • 7/25/2019 Contoh Soal Analisa Matriks (Portal Hal.172)

    62/70

    -735000 -7.8792E-013 4.45740E-011 735000 -7.9E-013

    7.87924E-013 15006.25 12862.5 -7.8792E-013 30012.5

    v2 phi2 u3 v3 phi3

    0 0 -378000 0 0

    3061.8 7654.5 0 -3061.8 7654.5

    7654.5 25515 0 -7654.5 12757.5

    0 0 378000 0 0

    -3061.8 -7654.5 0 3061.8 -7654.5

    7654.5 12757.5 0 -7654.5 25515

    phi30

    7654.5

    12757.5

    0

    0

    0

    0

    -7654.5

    25515

  • 7/25/2019 Contoh Soal Analisa Matriks (Portal Hal.172)

    63/70

    - -4.45740E-011 - - 4.46E-011 -

    -4.45740E-011 - -7.8792360E-013 4.46E-011 - -7.9E-013

    - -7.87924E-013 - - 7.88E-013 -

    - 4.457396E-011 - - -4.5E-011 -

  • 7/25/2019 Contoh Soal Analisa Matriks (Portal Hal.172)

    64/70

    4.457396E-011 - 7.8792360E-013 -4.5E-011 - 7.88E-013

    - -7.87924E-013 - - 7.88E-013 -

    - - - - - -

    - - - - - -

    - - - - - -

    - - - - - -

    - - - - - -

    - - - - - -

    385350 4.457396E-011 12862.5 -7350 -4.5E-011 12862.5

    4.457396E-011 738061.8 7654.5 -4.5E-011 -735000 -7.9E-013

    12862.5 7654.5 55527.5 -12862.5 7.88E-013 15006.25

    -7350 -4.45740E-011 -12862.5 7350 4.46E-011 -12862.5

    -4.45740E-011 -735000 7.8792360E-013 4.46E-011 735000 7.88E-013

    12862.5 -7.87924E-013 15006.25 -12862.5 7.88E-013 30012.5

    -378000 0 0 0 0 0

    0 -3061.8 -7654.5 0 0 0

    0 7654.5 12757.5 0 0 0

  • 7/25/2019 Contoh Soal Analisa Matriks (Portal Hal.172)

    65/70

  • 7/25/2019 Contoh Soal Analisa Matriks (Portal Hal.172)

    66/70

    -378000 0 0 - -4.457396E-011

    0 -3061.8 7654.5 -4.45740E-011 -

    0 -7654.5 12757.5 - -

    0 0 0 - 4.4573964E-011

    0 0 0 4.457396E-011 -

    0 0 0 - 7.8792360E-013

    378000 0 0 - -

    0 3061.8 -7654.5 - -

    0 -7654.5 25515 - -

  • 7/25/2019 Contoh Soal Analisa Matriks (Portal Hal.172)

    67/70

  • 7/25/2019 Contoh Soal Analisa Matriks (Portal Hal.172)

    68/70

    - - 4.4573964E-011 - -

    - 4.457396E-011 - 7.8792360E-013 -

    - - -7.8792360E-013 - -

    - - -4.4573964E-011 - -

    -7.8792360E-013 -4.45740E-011 - -7.8792360E-013 -

    - - -7.8792360E-013 - -

    - - - - -

    - - - - -

    - - - - -

  • 7/25/2019 Contoh Soal Analisa Matriks (Portal Hal.172)

    69/70

  • 7/25/2019 Contoh Soal Analisa Matriks (Portal Hal.172)

    70/70

    - -

    - -

    - -

    - -

    - -

    - -

    - -

    - -

    - -