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CONSUMER ARITHMETIC PROBLEMS
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CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

Jan 02, 2016

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Page 1: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

CONSUMER ARITHMETIC PROBLEMS

Page 2: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

Check and discuss students’

homework on compound interest

STARTER

Page 3: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

To be able to calculate consumer

arithmetic problems involving money.

OBJECTIVE

Page 4: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

KEY WORDS

Appreciation

Depreciation

Discount

Mark – up

Sale price

Page 5: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

Appreciation vs. Depreciation

Appreciation is a term used to indicate a value is increasing.

Depreciation is a term used to indicate a value is decreasing.

Page 6: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

Common questions that use

appreciation/depreciation are:

Rises in house prices

Falling price of a car from new

Growth in bacteria culture

Drop in populations.

Page 7: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

FORMULA

Appreciation Formula

initial

initial

%Value = I 1

100I starting value

% = Percentage increase

n = Term of the calculation, for example years, months days

n

Page 8: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

FORMULA

Depreciation Formula

initial

initial

%Value = I 1

100I starting value

% = Percentage decrease

n = Term of the calculation, for example years, months days

n

Page 9: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

EXAMPLE 1

1. A holiday home is bought in 1985 at 30000 aed. If it increase in value by 5% each year, how much is it worth in 1989?

initial

4

%Value = I 1

100

Value = 30000 1 0.05

Value = 36465.19 aed

n

Page 10: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

EXAMPLE 2

1. A car is bough for 120,000 AED. If it decreases in value by 1% each month, after is it worth after a year?

initial

12

%Value = I 1

100

Value = 120000 1 0.01

Value = 106366.18 aed

n

Page 11: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

Common application of percent change are discounts and markups.

A discount is an amount by which an original price is reduced.

discount = % of original price

final price = original price – discount

A markup is an amount by which a wholesale cost is increased.

final price = wholesale cost markup+

markup wholesale cost= % of

Page 12: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

The entrance fee at an amusement park is $35. People over the age of 65 receive a 20% discount. What is the amount of the discount? How much do people over 65 pay?

Method 1 A discount is a percent decrease. So find $35 decreased by 20%.

0.20(35) = 7 Find 20% of 35. This is the amount of the discount.

35 – 7 = 28 Subtract 7 from 35. This is the entrance fee for people over the age of 65.

Page 13: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

Method 2 Subtract the percent discount from 100%.

100% – 20% = 80% People over the age of 65 pay 80% of the regular price, $35.

0.80(35) = 28 Find 80% of 35. This is the entrance fee for people over the age of 65.

35 – 28 = 7 Subtract 28 from 35. This is the amount of the discount.

By either method, the discount is $7. People over the age of 65 pay $28.00.

Page 14: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

Helpful Hint

Before solving, decide what is a reasonable answer. For example 3A, a 10% discount is $3.50 off. So a 20% discount would be more than $2 off.

Page 15: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

A student paid $31.20 for art supplies that normally cost $52.00. Find the percent discount .

$52.00 – $31.20 = $20.80Think: 20.80 is what

percent of 52.00? Let x represent the percent.

The discount is 40%

Page 16: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

A $220 bicycle was on sale for 60% off. Find the sale price.

Method 2 Subtract the percent discount from 100%.

100% – 60% = 40% The bicycle was 60% off of 100% .

0.40(220) = 88 Find 40% of 220. This is the discount from the original price. 220 – 88 = 142

By this method, the discount is $88. The sale price is $142.00.

Page 17: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

Ray paid $12 for a $15 T-shirt. What was the percent discount ?

$15 – $12 = $3Think: 3 is what percent of

15? Let x represent the percent.

The discount is 20%.

Page 18: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

The wholesale cost of a DVD is $7. The markup is 85%. What is the amount of the markup? What is the selling price?

Method 1A markup is a percent increase. So find $7 increased by 85%.0.85(7) = 5.95

7 + 5.95 = 12.95

Find 85% of 7. This is the amount of the markup.

Add to 7. This is the selling price.

Subtract from 12.95. This is the amount of the markup.

12.95 7 = 5.95

By either method, the amount of the markup is $5.95. The selling price is $12.95.

Method 2

Add percent markup to 100%

The selling price is 185% of the wholesale price, 7.

100% + 85% = 185%

Find 185% of 7. This is the selling price.

1.85(7) = 12.95

Page 19: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

A video game has a 70% markup. The wholesale cost is $9. What is the selling price?

Method 1

A markup is a percent increase. So find $9 increased by 70%.

0.70(9) = 6.30Find 70% of 9. This is the amount

of the markup.

9 + 6.30 = 15.30 Add to 9. This is the selling price.

The amount of the markup is $6.30. The selling price is $15.30.

Page 20: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

What is the percent markup on a car selling for $21,850 that had a wholesale cost of $9500?

21,850 – 9,500 = 12,350

The markup was 130 percent.

Think: 12,350 is what percent of 9,500? Let x represent the percent.

Page 21: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

G11 Maths Website

WEEK 4 – CLASSWORK 1 APPRECIATION

& DEPRECIATION PROBLEMS

Show an organized solution on your maths

notebook.

CLASS WORK 1Pair Work

Page 22: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

G11 Maths Website

WEEK 4 – CLASSWORK 1 CONSUMER

ARITHMETIC PROBLEMS

Show an organized solution on your maths

notebook.

CLASS WORK 1Individual Work

Page 23: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

1. On line worksheethttp

://www.math-only-math.com/worksheets-on

-profit-and-loss-percentage.html

2. Continue unfinished classwork.

Show an organized solution on your notebook

HOMEWORK

Page 24: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

Online worksheet:

http://studymaths.co.uk/workout.php?workoutID

=96

Show an organized solution on your notebook

EXTENSION ACTIVITY

Page 25: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

What is appreciation?

What is depreciation?

PLENARY

Page 26: CONSUMER ARITHMETIC PROBLEMS. Check and discuss students’ homework on compound interest STARTER.

THANK YOU!