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Computer Aided Computer Aided Design Design – SAAP 2000 – SAAP 2000 - - Atasiei Raul Atasiei Raul Gr. 3505 Gr. 3505
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Computer Aided Design – SAAP 2000

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Computer Aided Design – SAAP 2000
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Page 1: Computer Aided Design – SAAP 2000

Computer Aided DesignComputer Aided Design – SAAP 2000 -– SAAP 2000 -

Atasiei RaulAtasiei Raul

Gr. 3505Gr. 3505

Page 2: Computer Aided Design – SAAP 2000

PART 1PART 1 Perform the Linear Static Analysis Perform the Linear Static Analysis of a Steel Truss Structure.of a Steel Truss Structure.

GIVEN DATA :GIVEN DATA :

Materials Materials Steel OL37:Steel OL37:- Elasticity modulus: Es = 2,1*E11 - Elasticity modulus: Es = 2,1*E11

N/m2N/m2- Steel strengths: - Steel strengths: Fy = 235 Fy = 235

N/mm2N/mm2Fu = 350 Fu = 350

N/mm2N/mm2- Weight per unit volume:- Weight per unit volume: W = W =

78500 N/m378500 N/m3 Loading cases: Loading cases: Live Live F1= 15000 N, F2= F1= 15000 N, F2=

8000 N8000 NDead F1=3000N, F2=1500NDead F1=3000N, F2=1500N Analysis cases: static analysis Analysis cases: static analysis

cases – external loadingcases – external loading Combination: 1.35 DL + 1.5 LLCombination: 1.35 DL + 1.5 LL

REQUIRED OUTPUT :REQUIRED OUTPUT :

Maximum displacementMaximum displacement Effort diagramsEffort diagrams Stress checking (for the most Stress checking (for the most

loaded element):loaded element):

Page 3: Computer Aided Design – SAAP 2000

THE TRUSSTHE TRUSS

Page 4: Computer Aided Design – SAAP 2000

LOADING CASES : LIVE LOADLOADING CASES : LIVE LOAD

Page 5: Computer Aided Design – SAAP 2000

LOADING CASES : DEAD LOADLOADING CASES : DEAD LOAD

Page 6: Computer Aided Design – SAAP 2000

Deformed shape of the trussDeformed shape of the truss

Page 7: Computer Aided Design – SAAP 2000

TABLE : Joint Displacements

Joint OutputCase CaseType U1 U2 U3 R1 R2 R3

Text Text Text m m m Radians Radians Radians

1 FUNDAMENTALA Combination 0 0 0 0 0.004819 0

4 FUNDAMENTALA Combination 0.00317 0 -0.030081 0 -3.867E-18 0

7 FUNDAMENTALA Combination 0.00634 0 0 0 -0.004819 0

8 FUNDAMENTALA Combination 0.006842 0 -0.006857 0 0.003899 0

9 FUNDAMENTALA Combination 0.005583 0 -0.02138 0 0.001993 0

10 FUNDAMENTALA Combination 0.00432 0 -0.029074 0 0.000826 0

11 FUNDAMENTALA Combination 0.00202 0 -0.029074 0 -0.000826 0

12 FUNDAMENTALA Combination 0.000757 0 -0.02138 0 -0.001993 0

13 FUNDAMENTALA Combination -0.000501 0 -0.006857 0 -0.003899 0

16 FUNDAMENTALA Combination 0.00077 0 -0.02123 0 0.001696 0

17 FUNDAMENTALA Combination 0.005571 0 -0.02123 0 -0.001696 0

Page 8: Computer Aided Design – SAAP 2000

Joint reactions on the steel trussJoint reactions on the steel truss

Page 9: Computer Aided Design – SAAP 2000

Bending Moment diagram on the Bending Moment diagram on the truss under fundamental loadingtruss under fundamental loading

Page 10: Computer Aided Design – SAAP 2000

Axial diagram on the truss under Axial diagram on the truss under fundamental loadingfundamental loading

Page 11: Computer Aided Design – SAAP 2000

Stress checking (for the most loaded Stress checking (for the most loaded element):element):

σ = N/A ≤ Fyσ = N/A ≤ Fy A = 2850mm2A = 2850mm2 N =182395.44 NN =182395.44 N σσ = 182395.44 / = 182395.44 /

2850 ≤ Fy = 2850 ≤ Fy = 63.99 N/mm263.99 N/mm2

σσ = 63.99 ≤ 235 = 63.99 ≤ 235 N/mm2N/mm2

OK!OK!

Page 12: Computer Aided Design – SAAP 2000

PART 2PART 2 Perform the Linear Static Analysis of a Perform the Linear Static Analysis of a

Frame Structure.Frame Structure. GIVEN DATA :GIVEN DATA :

Materials Materials Concrete BC 25:Concrete BC 25: - Elasticity modulus: Es = - Elasticity modulus: Es =

2,7*E10 N/m22,7*E10 N/m2 - Concrete strengths:- Concrete strengths:F’c=12500000 N/m2 F’c=12500000 N/m2 Fy = 3E8 N/m2 Fy = 3E8 N/m2 Fu = 2.1E8 N/m2Fu = 2.1E8 N/m2

Weight per unit volume:Weight per unit volume:W = 25000 N/m3W = 25000 N/m3

Loading cases: Loading cases: Live Live F1= 10000N, F2= F1= 10000N, F2=

8000N8000NDead F1=12000N, Dead F1=12000N, Snow F1 =5000 NSnow F1 =5000 N Analysis cases: static analysis Analysis cases: static analysis

cases – external loadingcases – external loading Combination: 1.35 DL + 1.5 Combination: 1.35 DL + 1.5

LL+1.05SLL+1.05S

REQUIRED OUTPUT :REQUIRED OUTPUT :

Maximum displacementMaximum displacement Effort diagramsEffort diagrams

Page 13: Computer Aided Design – SAAP 2000

The FrameThe Frame

Page 14: Computer Aided Design – SAAP 2000

Dead LoadsDead Loads

Page 15: Computer Aided Design – SAAP 2000

Live LoadsLive Loads

Page 16: Computer Aided Design – SAAP 2000

Snow LoadsSnow Loads

Page 17: Computer Aided Design – SAAP 2000

Deformed Shape of the FrameDeformed Shape of the Frame

Page 18: Computer Aided Design – SAAP 2000

Table: Joint DisplacementsTable: Joint Displacements

Joint OutputCase CaseType U1 U2 U3 R1 R2 R3

Text Text Text m m m Radians Radians Radians

1 ULS Combination 0 0 0 0 0 0

2 ULS Combination 0.000052 0 -0.000034 0 0.000169 0

4 ULS Combination 0 0 0 0 0 0

5 ULS Combination -0.000000823 0 -0.000097 0 -0.000014 0

6 ULS Combination 0.000024 0 -0.000173 0 0.000666 0

7 ULS Combination 0 0 0 0 0 0

8 ULS Combination 0.000000823 0 -0.000097 0 0.000014 0

9 ULS Combination -0.000024 0 -0.000173 0 -0.000666 0

10 ULS Combination 0 0 0 0 0 0

11 ULS Combination -0.000052 0 -0.000034 0 -0.000169 0

Page 19: Computer Aided Design – SAAP 2000

Joint reactions on the frameJoint reactions on the frame

Page 20: Computer Aided Design – SAAP 2000

TABLE: Joint Reactions

Joint OutputCase CaseType F1 F2 F3 M1 M2 M3

Text Text Text N N N N-m N-m N-m

1 ULS Combination 41307.56 0 204349.2 0 31600.86 0

4 ULS Combination -4235.43 0 478807.05 0 -3776.9 0

7 ULS Combination 4235.43 0 478807.05 0 3776.9 0

10 ULS Combination -41307.56 0 204349.2 0 -31600.86 0

Page 21: Computer Aided Design – SAAP 2000

Axial diagram on the frame under Axial diagram on the frame under fundamental loadingfundamental loading

Page 22: Computer Aided Design – SAAP 2000

Shear Force diagram on the frame Shear Force diagram on the frame under fundamental loadingunder fundamental loading

Page 23: Computer Aided Design – SAAP 2000

Bending Moment diagram on the Bending Moment diagram on the frame under fundamental loading.frame under fundamental loading.

Page 24: Computer Aided Design – SAAP 2000

PART 3PART 3 Perform the Linear Static Analysis of a Perform the Linear Static Analysis of a

3D Frame Structure.3D Frame Structure. GIVEN DATA :GIVEN DATA :

Materials Materials Concrete BC 25:Concrete BC 25: - Elasticity modulus: Es = - Elasticity modulus: Es =

2,7*E10 N/m22,7*E10 N/m2 - Concrete strengths:- Concrete strengths: F’c=12500000 N/m2 F’c=12500000 N/m2 Fy = 3E8 N/m2 Fy = 3E8 N/m2 Fu = 2.1E8 Fu = 2.1E8

N/m2N/m2 Weight per unit volume:Weight per unit volume:

W = 25000 N/m3W = 25000 N/m3

Loading cases: Loading cases: Live Live F1= 10000N, F2= F1= 10000N, F2=

8000N8000N Dead F1=12000N, Dead F1=12000N, Analysis cases: static analysis Analysis cases: static analysis

cases – external loadingcases – external loading Combination: 1.35 DL + 1.5 LLCombination: 1.35 DL + 1.5 LL

REQUIRED OUTPUT :REQUIRED OUTPUT :

Maximum displacementMaximum displacement Effort diagramsEffort diagrams

Page 25: Computer Aided Design – SAAP 2000

The 3D FrameThe 3D Frame

Page 26: Computer Aided Design – SAAP 2000

Dead LoadsDead Loads

Page 27: Computer Aided Design – SAAP 2000

Live LoadsLive Loads

Page 28: Computer Aided Design – SAAP 2000

Deformed shape of the frame Deformed shape of the frame - ULS & SLS -- ULS & SLS -

Page 29: Computer Aided Design – SAAP 2000

TABLE: Joint Displacements  SLS          

Joint OutputCase CaseType U1 U2 U3 R1 R2 R3

Text Text Text m m m Radians Radians Radians

10 FUNDAMENTALA Combination 0 0 0 0 0 0

11 FUNDAMENTALA Combination -0.055995 -2.346539 -0.845901 0.019661 0.010065 -0.013542

12 FUNDAMENTALA Combination -0.054875 -3.574108 -1.257346 0.026367 0.01438 -0.020312

13 FUNDAMENTALA Combination 0 0 0 0 0 0

14 FUNDAMENTALA Combination 0.025254 -2.346539 -0.727988 0.019661 0.010065 -0.013542

15 FUNDAMENTALA Combination 0.066999 -3.574108 -1.099174 0.026367 0.01438 -0.020312

19 FUNDAMENTALA Combination 0 0 0 0 0 0

20 FUNDAMENTALA Combination -0.055995 -2.427799 -0.906337 0.019661 0.010065 -0.013542

21 FUNDAMENTALA Combination -0.054875 -3.695993 -1.343671 0.026367 0.01438 -0.020312

22 FUNDAMENTALA Combination 0 0 0 0 0 0

23 FUNDAMENTALA Combination 0.025254 -2.427801 -0.788458 0.019661 0.010065 -0.013542

24 FUNDAMENTALA Combination 0.066999 -3.695994 -1.185524 0.026367 0.01438 -0.020312

25 FUNDAMENTALA Combination 0 0 0 0 0 0

26 FUNDAMENTALA Combination 0.106501 -2.427795 -0.670477 0.019661 0.010065 -0.013542

27 FUNDAMENTALA Combination 0.188871 -3.695989 -1.02727 0.026368 0.01438 -0.020312

28 FUNDAMENTALA Combination 0 0 0 0 0 0

29 FUNDAMENTALA Combination -0.055995 -2.509042 -0.966669 0.019661 0.010065 -0.013542

30 FUNDAMENTALA Combination -0.054875 -3.817861 -1.429895 0.026367 0.014379 -0.020312

31 FUNDAMENTALA Combination 0 0 0 0 0 0

32 FUNDAMENTALA Combination 0.025253 -2.509045 -0.848804 0.019661 0.010065 -0.013542

33 FUNDAMENTALA Combination 0.066998 -3.817863 -1.27176 0.026367 0.014379 -0.020312

34 FUNDAMENTALA Combination 0 0 0 0 0 0

35 FUNDAMENTALA Combination 0.106501 -2.509041 -0.730842 0.019661 0.010065 -0.013542

36 FUNDAMENTALA Combination 0.188871 -3.817859 -1.113526 0.026368 0.014379 -0.020312

Page 30: Computer Aided Design – SAAP 2000

TABLE: Joint Displacements ULS           

Joint OutputCase CaseType U1 U2 U3 R1 R2 R3

Text Text Text m m m Radians Radians Radians

10 FUNDAMENTALA Combination 0 0 0 0 0 0

11 FUNDAMENTALA Combination -0.055995 -2.346539 -0.845901 0.019661 0.010065 -0.013542

12 FUNDAMENTALA Combination -0.054875 -3.574108 -1.257346 0.026367 0.01438 -0.020312

13 FUNDAMENTALA Combination 0 0 0 0 0 0

14 FUNDAMENTALA Combination 0.025254 -2.346539 -0.727988 0.019661 0.010065 -0.013542

15 FUNDAMENTALA Combination 0.066999 -3.574108 -1.099174 0.026367 0.01438 -0.020312

19 FUNDAMENTALA Combination 0 0 0 0 0 0

20 FUNDAMENTALA Combination -0.055995 -2.427799 -0.906337 0.019661 0.010065 -0.013542

21 FUNDAMENTALA Combination -0.054875 -3.695993 -1.343671 0.026367 0.01438 -0.020312

22 FUNDAMENTALA Combination 0 0 0 0 0 0

23 FUNDAMENTALA Combination 0.025254 -2.427801 -0.788458 0.019661 0.010065 -0.013542

24 FUNDAMENTALA Combination 0.066999 -3.695994 -1.185524 0.026367 0.01438 -0.020312

25 FUNDAMENTALA Combination 0 0 0 0 0 0

26 FUNDAMENTALA Combination 0.106501 -2.427795 -0.670477 0.019661 0.010065 -0.013542

27 FUNDAMENTALA Combination 0.188871 -3.695989 -1.02727 0.026368 0.01438 -0.020312

28 FUNDAMENTALA Combination 0 0 0 0 0 0

29 FUNDAMENTALA Combination -0.055995 -2.509042 -0.966669 0.019661 0.010065 -0.013542

30 FUNDAMENTALA Combination -0.054875 -3.817861 -1.429895 0.026367 0.014379 -0.020312

31 FUNDAMENTALA Combination 0 0 0 0 0 0

32 FUNDAMENTALA Combination 0.025253 -2.509045 -0.848804 0.019661 0.010065 -0.013542

33 FUNDAMENTALA Combination 0.066998 -3.817863 -1.27176 0.026367 0.014379 -0.020312

34 FUNDAMENTALA Combination 0 0 0 0 0 0

35 FUNDAMENTALA Combination 0.106501 -2.509041 -0.730842 0.019661 0.010065 -0.013542

36 FUNDAMENTALA Combination 0.188871 -3.817859 -1.113526 0.026368 0.014379 -0.020312

Page 31: Computer Aided Design – SAAP 2000

F maxF max

Page 32: Computer Aided Design – SAAP 2000

M maxM max

Page 33: Computer Aided Design – SAAP 2000

V maxV max

Page 34: Computer Aided Design – SAAP 2000

PART 4PART 4 Perform the Linear Static Perform the Linear Static Analysis of a 3D Frame Structure.Analysis of a 3D Frame Structure.

GIVEN DATA :GIVEN DATA :

Materials Materials Concrete BC 25:Concrete BC 25: - Elasticity modulus: Es = - Elasticity modulus: Es =

2,7*E10 N/m22,7*E10 N/m2 - Concrete strengths:- Concrete strengths: F’c=12500000 N/m2 F’c=12500000 N/m2 Fy = 3E8 N/m2 Fy = 3E8 N/m2 Fu = 2.1E8 Fu = 2.1E8

N/m2N/m2 Weight per unit volume:Weight per unit volume:

W = 25000 N/m3W = 25000 N/m3

Loading cases: Loading cases: Live Live F1= 10000N, F2= F1= 10000N, F2=

8000N8000N Dead F1=12000N, Dead F1=12000N, Analysis cases: static analysis Analysis cases: static analysis

cases – external loadingcases – external loading Combination: 1.35 DL + 1.5 LLCombination: 1.35 DL + 1.5 LL

REQUIRED OUTPUT :REQUIRED OUTPUT :

Displacements checkingDisplacements checking

Modal PeriodsModal Periods

Page 35: Computer Aided Design – SAAP 2000

The Frame and Analysis specterThe Frame and Analysis specterResponse Spectrum    

Name Period Accel

Text Sec Unitless

Spec-ias 0 1.962

Spec-ias 0.07 0.799333

Spec-ias 0.7 0.799333

Spec-ias 0.8 0.699417

Spec-ias 0.9 0.621704

Spec-ias 1 0.559533

Spec-ias 1.1 0.508667

Spec-ias 1.2 0.466278

Spec-ias 1.3 0.43041

Spec-ias 1.4 0.399667

Spec-ias 1.5 0.373022

Spec-ias 1.6 0.349708

Spec-ias 1.7 0.329137

Spec-ias 1.8 0.310852

Spec-ias 1.9 0.294491

Spec-ias 2 0.279767

Spec-ias 2.1 0.266444

Spec-ias 2.2 0.254333

Spec-ias 2.3 0.243275

Page 36: Computer Aided Design – SAAP 2000

TABLE: Response Spectrum Modal Information

OutputCase ModalCase StepType Period DampRatio U1Acc U2Acc U3Acc

Text Text Text Sec Unitless mm/sec2 mm/sec2 mm/sec2

Modala MODAL Mode 0.191566 0.05 0.8 0.8 0

Modala MODAL Mode 0.065947 0.05 0.87 0.87 0

Modala MODAL Mode 0.036365 0.05 1.36 1.36 0

Modala MODAL Mode 0.024585 0.05 1.55 1.55 0

Modala MODAL Mode 0.0221 0.05 1.59 1.59 0

Page 37: Computer Aided Design – SAAP 2000

Table : Modal participating RatiosTable : Modal participating Ratios

OutputCase Period UX UY UZ SumUX SumUY SumUZ

Text Sec Unitless Unitless Unitless Unitless Unitless Unitless

MODAL 0.164158 0.74 0 0 0.74 0 0

MODAL 0.062325 0.26 0 0 1 0 0

MODAL 0.033578 0 00.000007

564 1 00.000007

564

MODAL 0.020735 0 0 0.75 1 0 0.75

MODAL 0.0206880.000004

631 0 0 1 0 0.75

Page 38: Computer Aided Design – SAAP 2000

Deflected shape – Mode 1Deflected shape – Mode 1

Page 39: Computer Aided Design – SAAP 2000

Deflected shape – Mode 2Deflected shape – Mode 2

Page 40: Computer Aided Design – SAAP 2000

Deflected shape – Mode 3Deflected shape – Mode 3

Page 41: Computer Aided Design – SAAP 2000

Deflected shape – Mode 4Deflected shape – Mode 4

Page 42: Computer Aided Design – SAAP 2000

Deflected shape – Mode 5Deflected shape – Mode 5

Page 43: Computer Aided Design – SAAP 2000

Table : Displacement CheckingTable : Displacement Checking

 SLS ULS dr-SLS dr-ULS dra-SLS dra-ULS

ABS REL ABS REL        

0 0 0 0 0 0 0

0.0224 0.07

1 -0.00001 -0.00001 -0.00001 -0.00001 -3.4E-05 -0.00014

2 -0.000018 0.000008 -0.000018 0.000008 0.000027 0.000108

3 -0.000048 0.00003 -0.000048 0.00003 0.000101 0.000405

4 -0.00004 0.000008 -0.00004 0.000008 0.000027 0.000108

5 0.000029 0.000069 0.000029 0.000069 0.000233 0.000932