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Introduction to Number Theory 1
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CIS 5371 Cryptography

Jan 15, 2016

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CIS 5371 Cryptography. Introduction to Number Theory. Preview. Number Theory Essentials Congruence classes, Modular arithmetic Prime numbers challenges Fermat’s Little theorem The Totient function Euler's Theorem Quadratic residuocity Foundation of RSA. Number Theory Essentials. - PowerPoint PPT Presentation
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Page 1: CIS 5371 Cryptography

Introduction to Number Theory

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Page 2: CIS 5371 Cryptography

Preview• Number Theory Essentials• Congruence classes, Modular arithmetic• Prime numbers challenges• Fermat’s Little theorem• The Totient function• Euler's Theorem• Quadratic residuocity• Foundation of RSA

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Page 3: CIS 5371 Cryptography

Number Theory Essentials

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• Fundamental theorem of arithmetic: Every positive integer has a unique factorization that is a product of prime powers.

Page 4: CIS 5371 Cryptography

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8 7

5

6

0

4

3 2

19

10

11

1213

14 ……..

.. .

…….. ……..

1 6 11 (mod 5)

……..

Page 5: CIS 5371 Cryptography

Modular arithmetic

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Page 6: CIS 5371 Cryptography

The integers modulo n a,b,n I, a b mod n iff n | (a-b) *

28 6 mod 11: (28-6)/11 = 2 I

219 49 mod 17: (219-49)/17 = 12 I

Symmetry: If a b mod n then b a mod n

Transitivity: If a b mod n and b c mod n then a c mod n

* n divides (a-b)

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Page 7: CIS 5371 Cryptography

Modular arithmetic:notation

Form: a b mod n (congruence relation) a = b mod n (modulus operator)

indicates that the integers a and b fall into the same congruence class modulo n

= means that integer a is the reminder of the division of integer b by integer n.

Example: 14 2 mod 3 and 2 = 14 mod 3

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Page 8: CIS 5371 Cryptography

Modular arithmetic & cryptography

Modular computations can be utilized to scramble data.

Cryptographic systems utilize modular (or elliptic curve (EC)) arithmetic.

Several cryptographic systems use prime modulus arithmetic.

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Page 9: CIS 5371 Cryptography

Prime Number Challenges

1. Finding large prime numbers.

2. Recognizing large numbers as prime.

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Page 10: CIS 5371 Cryptography

How Do We Find Large Prime Numbers?

Look them up ?

Compute them ?

Do they REALLY have to be prime?

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Finding large primes

m

Page 12: CIS 5371 Cryptography

Fermat's Little Theorem

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Page 13: CIS 5371 Cryptography

Let p = 5, pick values for a: a =2: 24 = 16 mod 5 = 1 a =3: 34 = 81 mod 5 = 1 a =4: 44 = 256 mod 5 = 1

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Page 14: CIS 5371 Cryptography

Let p = 11, pick values a :

• a=3: 310 = 59049 mod 11 = 1

• a=5: 510 = 9765625 mod 11 = 1

• a=7: 710 = 282475249 mod 11 = 1

• a=8: 810 = 1073741824 mod 11 = 1

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Page 15: CIS 5371 Cryptography

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Page 16: CIS 5371 Cryptography

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Page 17: CIS 5371 Cryptography

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Page 18: CIS 5371 Cryptography

Exponentiations

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3811502 mod 751 == 3812 * 381750 * 381750 mod 751= 3812 mod 751 * 1 mod 751= 145161 mod 751= 218

Page 19: CIS 5371 Cryptography

Exponentiations

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a p-1 1 mod p

• 713 mod 11 x

• 710 mod 11* 73 mod 11 x

• 1 mod 11 * 73 mod 11 x

• 73 mod 11 x

• 343 mod 11 2

Page 20: CIS 5371 Cryptography

The totient function (n)

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Page 21: CIS 5371 Cryptography

Deriving (n) Primes: (p) = p-1

Product of 2 primes: (pq) = (p-1)(q-1)

General case (i.e. for all integers x) = ?

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Page 22: CIS 5371 Cryptography

Deriving (n)Product of 2 relatively prime numbers

if gcd (m,n) = 1, then: (mn) = (m) * (n) 15 = 3*5 and Example: (15)=2*4=8

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Page 23: CIS 5371 Cryptography

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Page 24: CIS 5371 Cryptography

Quadratic Residuosity• An integer a is a quadratic residue with

respect to n if:• a is relatively prime to n and • there exists an integer b such that: a = b2 mod n

• Quadratic Residues for n = 7: QR(7)={1, 2, 4}• a = 1: b = 1 (12 = 1 mod 7), 6, 8, 13, 15, 16, 20, 22, …• a = 2: b = 3 (32 = 2 mod 7), 4, 10, 11, 17, 18, 24, 25, …• a = 4: b = 5, 9, 12, 19, 23, 26, …

• Notice that 2, 3, 5, and 6 are not QR mod 7.• QR(n) forms a group with respect to

multiplication.24

Page 25: CIS 5371 Cryptography

The Foundation of RSA x y mod n = x (y mod (n)) mod n The proof of this follows from Euler's

Theorem If y mod (n) = 1,

then for any x : xy mod n = x mod n If we can choose e and d such that

ed = 1 mod (n) then we can encrypt by raising x to the e th

power and decrypt by raising to the d th power.

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