7/23/2019 Chin's Method http://slidepdf.com/reader/full/chins-method 1/18 Chin’s Method The Chin’s method required the test pile result of load-settlement relationship. The Chin’s method just only to plot a graft which the settlement (∆) / load () against settlement (∆). Then the ultimate loads are deri!ing from the in!erse slopes of the lines. Chin’s method assumes the form of the load or deformation cur!e is hyper"olic and it is an empirical method. #t is useful in that if the result is plotted at the time of the test$ de!iation from the e%pected cur!e is easily seen and the test procedure can "e chec&ed
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7/23/2019 Chin's Method
http://slidepdf.com/reader/full/chins-method 1/18
Chin’s Method
The Chin’s method required the test pile result of load-settlement relationship. The Chin’s
method just only to plot a graft which the settlement (∆) / load () against settlement (∆).
Then the ultimate loads are deri!ing from the in!erse slopes of the lines. Chin’s method
assumes the form of the load or deformation cur!e is hyper"olic and it is an empirical
method. #t is useful in that if the result is plotted at the time of the test$ de!iation from the
e%pected cur!e is easily seen and the test procedure can "e chec&ed
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1. PILE A
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Table 1:
1st Cycle
Total Load,P
(Tons)
Ave.Sett, ∆(mm)
∆/P
0 0 0
690 0.37
0.00053
6
1323 0.980.00074
1
1975 1.72
0.00087
1
2755 2.75
0.00099
8
2006 2.49
0.00124
1
1191 2.04
0.00171
3
721 1.47
0.00203
90 0.95 0 Minus Residual
2nd CycleSett.(mm)
∆/P
0 0.95 0 0 0
741 1.3
0.00175
4 0.35
0.00047
2
1368 1.82 0.00133 0.87
0.00063
6
2056 2.39
0.00116
2 1.44 0.0007
2710 2.970.00109
6 2.020.00074
5
3409 4.02
0.00117
9 3.07
0.00090
1
4050 5.38
0.00132
8 4.43
0.00109
4
4750 7.03 0.00148 6.08 0.00128
5365 8.78
0.00163
7 7.83
0.00145
9
6310 10.78
0.00170
8 9.83
0.00155
8
6761 14.730.00217
9 13.780.00203
8
6119 14.44 0.00236
5427 14.08
0.00259
4
4555 13.36
0.00293
3
4059 13.03 0.00321
3330 12.26
0.00368
2
2632 11.59
0.00440
3
1993 10.91
0.00547
4
1402 10.23
0.00729
7
795 9.27 0.01166
0 8.03 0
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Calculation for Graph ∆/P against ∆ for Pile A
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Graft 1: ∆/P against ∆ for Pile A
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'stimation of u sing *irst Cycle +esult
'quation from graph, y .01% 2 .34
5lope of the plot, m .01 &6-
7now that the in!erse slope of the plot gi!es the ultimate capacity$ thusltimate Capacity of the pile$ ult /.01 &6-
5,347.59kN
'stimation of u sing 8inus +esidual +esult
'quation from graph, y .% 2 .393
5lope of the plot, m . &6-
7now that the in!erse slope of the plot gi!es the ultimate capacity$ thus
ltimate Capacity of the pile$ ult /. &6-
9,009.01 kN
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2. PILE B
Table 2: Calculation for Graft ∆/P against ∆ for Pile B
1st Cy!e
"ot#! Lo#d,
P$"ons%
A&'. sett. ($))%
(*P
:3 .4; .::1;
3 .4; .:;0
<;; :.: .941
;39 :.00 .9::
1:< :.4 .99:
41 :. .440;
:4< .3 .<90
.1< Min+s esid+#!
2nd Cy!e-ett. (
$))%(*P
.1<
:11 .43 .3:93 .<; .:4;
41 .0 .9049 .3 .:::;
13 :.9 .9:11 .33 .:;;
;31 :.;< .9;9 :.: .::;;
<9 9.1 .90 :.;4 .:3:0
90 4.1 .94< 9.;4 .:033
<:: 3.<3 .9409 4.0; .93
03 <.1; .9<1 <.9 .9:3;
:1< 0.0 .90;: 1.9: .93:<
:9;9 .<1 .443; ;.; .44
:: .:; .4<11
001 . .3930
<33 ;.19 .301;
491 ;.99 .<4;9
3< 0.<: .1431
;<0 0. .09<0199 1.39 .:19
34 <.1 .999
:0 3.09 .:141
9.;0
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Graft 2: ∆/P against ∆ for Pile B
'stimation of ltimate =oad$ u sing *irst Cycle +esult
Equation from graft, y .9:9% 2 .::0<
5lope of the plot, m .9:9 &6-
7now that the in!erse slope of the plot gi!es the ultimate capacity$ thus
ltimate Capacity of the pile$ ult /.9:9 &6-
3,095.9 kN
'stimation of ltimate =oad$ u sing 8inus +esidual +esult
Equation from graft, y .:03% 2 .344
5lope of the plot, m .:03 &6-
7now that the in!erse slope of the plot gi!es the ultimate capacity$ thus
ltimate Capacity of the pile$ ult /.:03 &6-
3,50.77 kN
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3. Pi!e C
Table 3: Calculation for Graft ∆/P against ∆ for Pile C