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Chemistry 103 Lecture 15
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Chemistry 103

Feb 12, 2016

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Chemistry 103. Lecture 15. Outline. I. Chemical Reactions - balancing (review) II. Stoichiometry - Limiting Reactant III. Classification of Reaction Types. Molar Mass from Periodic Table. Molar mass Is the atomic mass expressed in grams. Avogadro’s Number. - PowerPoint PPT Presentation
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Page 1: Chemistry 103

Chemistry 103

Lecture 15

Page 2: Chemistry 103

Outline

I. Chemical Reactions - balancing (review)II. Stoichiometry - Limiting ReactantIII. Classification of Reaction Types

Page 3: Chemistry 103

Molar Mass from Periodic TableMolar mass • Is the atomic

mass expressed in grams

Page 4: Chemistry 103

Avogadro’s Number

Solution = 6.022 x 1023

Avogadro’s number is equal to 1 mole

Makes working with large numbers easier

Page 5: Chemistry 103

The Mole

Molar mass 1 mole 6.022 x 1023

Mass in grams Individual particles

Page 6: Chemistry 103

Concept Review

Do 7.0g of CO and 7.5 g of C2H6 contain the same number of C atoms?

(Prove your answer mathematically)

A. YES B. NO

Page 7: Chemistry 103

Chemical ReactionIn a chemical reaction, Old bonds are broken and

new bonds are formed Atoms in the reactants are

rearranged to form one or more different substances

Fe and O2 form rust (Fe2O3)

Page 8: Chemistry 103

Chemical’s Shorthand - Chemical Rxn Fe (s) + O2(g) --------> Fe2O3 (s)

2Fe(s) + O2(g) --------> Fe2O3(s)

4Fe(s) + O2(g) --------> 2Fe2O3(s)

4Fe(s) + 3O2(g) --------> 2Fe2O3(s) BALANCED!!!!!

Page 9: Chemistry 103

Balancing Practice

Li3N(s) -------> Li(s) + N2(g)

Mg + H3PO4 ------> Mg3(PO4)2 + H2

MgCl2 + AgNO3 ------> Mg(NO3)2 + AgCl

Page 10: Chemistry 103

Stoichiometry Chemical Stoichiometry: using mass and quantity

relationships among reactants and products in a chemical reaction to make predictions about how much product will be made.

Page 11: Chemistry 103

We can read the equation in “moles” by placing the word “mole” or “mol” between each coefficient and formula.

4Fe(s) + 3O2(g) 2Fe2O3(s)

4 mol Fe + 3 mol O2 2 mol Fe2O3

Moles in Equations

Page 12: Chemistry 103

Mole to Mole problems

Using the balanced chemical reaction, how many moles of O2 will react with 4.28 moles of CS2 to produce CO2 and SO2?

CS2 + O2 ------> CO2 + SO2 (unbalanced)

Page 13: Chemistry 103

Mole to Mole problems

When 4.28 moles of CS2 reacts according to the balanced chemical equation below, how many moles of CO2 will be produced?

CS2 + 3O2 ------> CO2 + 2SO2

Page 14: Chemistry 103

Mole to Mole problems

When 4.28 moles of CS2 reacts according to the balanced chemical equation below, how many moles of SO2 will be produced?

CS2 + 3O2 ------> CO2 + 2SO2

Page 15: Chemistry 103

Reaction Interpretation

Using the balanced chemical reaction, how many moles of O2 will react with 4.28 moles of CS2 to produce CO2 and SO2?

CS2 + 3O2 ------> CO2 + 2SO2BEFORE

AFTER

Page 16: Chemistry 103

Moles-to-Grams or Grams-to-Mole

Page 17: Chemistry 103

Chemical Stoichiometry2H2 + O2 ----> 2H2O

mole to mole comparisons: How many moles of O2 are needed to produce

1.39 moles of H2O?

Page 18: Chemistry 103

Chemical Stoichiometry

2H2 + O2 ----> 2H2O

mole to gram or gram to mole comparisons:How many moles of O2 are needed to produce 7.4g

of H2O?

Page 19: Chemistry 103

Chemical Stoichiometry

2H2 + O2 ----> 2H2O

mole to mole comparisons: How many moles of O2 are needed to exactly react

with 4.28 moles of H2?

Page 20: Chemistry 103

Chemical Stoichiometry

2H2 + O2 ----> 2H2O

mole to gram or gram to mole comparisons:How many moles of O2 are needed to exactly react

with 12.4g of H2?

Page 21: Chemistry 103

How many grams of O2 are needed to produce 0.400 mol Fe2O3?

4Fe(s) + 3O2(g) 2 Fe2O3(s)

A) 38.4 g O2

B) 19.2 g O2

C) 1.90 g O2

Grams-to-Mole

Page 22: Chemistry 103

“gram to gram” calculations

Page 23: Chemistry 103

The reaction between H2 and O2 produces 13.1 g water.

How many grams of O2 reacted?

2H2(g) + O2(g) 2H2O(g)

Plan: g H2O mole H2O mole O2 g O2

Calculating the Mass of a Reactant

Page 24: Chemistry 103

The reaction between H2 and O2 produces 13.1 g water.

How many grams of O2 reacted?

2H2(g) + O2(g) 2H2O(g)

Before: x g

After: 13.1 g

Plan: g H2O mole H2O mole O2 g O2

Calculating the Mass of a Reactant

Page 25: Chemistry 103

Mass calculations

How many grams of CS2 are needed to completely react with 6.0g of O2 according to the following reaction?

CS2 + 3O2 ------> CO2 + 2SO2

Page 26: Chemistry 103

“gram to gram” continued….

One way to remove gaseous carbon dioxide from the air in a spacecraft is to let canisters of solid lithium hydroxide absorb it according to the following reaction:

2LiOH(s) + CO2(g) ------> Li2CO3(s) + H2O(l)

How many grams of LiOH must be used to produce 10.0g of Li2CO3?

Page 27: Chemistry 103

Learning Check

Acetylene gas C2H2 burns in the oxyacetylene torch for welding. How many grams of C2H2 are burned if the reaction produces 75.0 g CO2?

2C2H2(g) + 5O2(g) 4CO2(g) + 2H2O(g)

A) 88.6 g C2H2

B) 44.3 g C2H2

C) 22.2 g C2H2

Page 28: Chemistry 103

Chemical Reactions

Limiting Reactant &

Percent Yield

Page 29: Chemistry 103

Limiting Reactant

A limiting reactant in a chemical reaction is thesubstance that: • Is used up first• Stops the reaction• Limits the amount of product that can form

Page 30: Chemistry 103

Reacting Amounts

In a table setting, there is 1plate, 1 fork, 1 knife, and 1 spoon.

How many table settings arepossible from 5 plates, 6 forks, 4spoons, and 7 knives?

What is the limiting item?

Page 31: Chemistry 103

Reaction Equivalent

1plate + 1fork + 1knife + 1spoon ----> 1place setting

BEFORE 5 6 7 4 0

AFTER 1 2 3 0 4 LR

Page 32: Chemistry 103

Reacting Amounts

In a table setting, there is 1plate, 2 forks, 1 knife, and

1spoon.

How many table settings arepossible from 5 plates, 6 forks, 4spoons, and 7 knives?

What is the limiting item?

Page 33: Chemistry 103

Reaction Equivalent

1plate + 2fork + 1knife + 1spoon ----> 1place setting

BEFORE 5 6 7 4 0

AFTER 2 0 4 1 3 LR

Page 34: Chemistry 103

Limiting Reactants

When 4.00 mol H2 is mixed with 2.00 mol Cl2,how many moles of HCl can form?

H2(g) + Cl2(g) 2HCl (g)

4.00 mol 2.00 mol ??? Mol

STEPS:

• Calculate the moles of product from each reactant, H2 and Cl2.

• The limiting reactant is the one that produces the smallest amount of product.

Page 35: Chemistry 103

Checking Calculations

Initially H2

4.00 mol

Cl2

2.00 mol

2HCl

0 mol

Reacted/Formed

-2.00 mol -2.00 mol +4.00 mol

Left after reaction

2.00 mol Excess

0 mol Limiting

4.00 mol

Page 36: Chemistry 103

Limiting Reactant

If 4.80 grams Ca mixed with 2.00 grams N2, which is the limiting reactant?

3Ca(s) + N2(g) Ca3N2(s)

Page 37: Chemistry 103

Limiting Reactants Using MassCalculate the mass of water produced when 8.00 g H2

and 24.0 g O2 react?

2H2(g) + O2(g) 2H2O(l)