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CHEMICAL KINETICS CHAPTER 13
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CHEMICAL KINETICS CHAPTER 13

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CHEMICAL KINETICS CHAPTER 13. I. Introduction. A. Definition of Chemical Kinetics “The study of the speed or rate of reactions and the nanoscale pathways or processes by which reactants are transformed into products. B. Examples of Reactions and Rates Rusting of Iron Combustion Reaction - PowerPoint PPT Presentation
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Page 1: CHEMICAL KINETICS CHAPTER 13

CHEMICAL KINETICSCHAPTER 13

Page 2: CHEMICAL KINETICS CHAPTER 13

I. Introduction

A. Definition of Chemical Kinetics“The study of the speed or rate of reactions and the nanoscale pathways or processes by which reactants are transformed into products.

B. Examples of Reactions and RatesRusting of IronCombustion Reaction

C. Significance of Studying Kinetics

Page 3: CHEMICAL KINETICS CHAPTER 13

D. Factors Affecting Reaction Rate1. Concentration of Reactants

2. Temperature

3. Presence of a Catalyst

4. Surface Area of a Solid Reactant or Catalyst

5. Properties of Reactants and Products

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II. Understanding Reaction Rates

A. Kinetic Molecular TheoryMatter composed of particles in constant motion.Increase in temperature increases particle’s kinetic energy.

B. Collision TheoryFor a reaction to occur , reactant molecules must collide with the proper orientation and with an energy greater than some minimum value.Activation Energy (Ea) – minimum energy

required for reaction to occur.

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Importance of OrientationOne hydrogen atom

can approach another from any direction …

… and reaction will still occur; the spherical symmetry of the atoms means

that orientation does not matter.

Effective collision; the I atom can bond to the C atom to form CH3I

Ineffective collision; orientation is important

in this reaction.

Page 6: CHEMICAL KINETICS CHAPTER 13

Distribution of Kinetic Energies

At higher temperature (red), more molecules

have the necessary activation energy.

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C. Transition State Theory 1. Note Reaction Profile:

CO(g) + NO2(g) CO2(g) + NO(g)

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2. Note Ea for either forward or reverse reaction. “At a given temperature, the higher the energy

barrier, the slower the reaction.”

3. Transition State or “Activated Complex” “Transition structure (between reactants and

products) which is always found on top of the

energy hill (energy of activation).

4. Is reaction, exothermic or endothermic as written from left to right?

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Reconsideration of Factors Affecting Reaction Rate!!

1. Concentration

2. Temperature

3. Catalyst

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III. Rates of Reactions

A. Definition 1. Reaction rate: expresses how much

product is appearing or how much reactant in disappearing per unit time.

2. Units for reaction rates: (Examples) Ms-1 or M/s or mol L-1s-1

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For Reaction: A → P

Rate of Disappearance of “A” = - ΔA / Δt

Rate of Formation of “P” = + ΔP / Δt

tA

tA

tA

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B. Example Average Rate Determination For Rxn of Cisplatin and Water: H2O + Pt(NH3)2Cl2 Pt(NH3)2Cl(H2O) + Cl-

Cisplatin Time (min) [Cisplatin] (mol/L) 0 0.01000 200 0.00747 400 0.00558

What is average rate of disappearance of cisplatin (in mol L-1 min-1) for the first 200 min? What is average rate of disappearance of cisplatin (in mol L-1 min-1) for the next 200 min?

Page 13: CHEMICAL KINETICS CHAPTER 13

C. Instantaneous Rate Determination

Significance of Measuring Instantaneous Rates!!

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D. Reaction Rates and Stoichiometry Given the reaction:

2 N2O5(g) 4 NO2(g) + O2 (g)

If the rate of NO2 formation is 0.060 mol L-1 s-1:

1. What is the rate of disappearance of N2O5?

2. What is the rate of formation of O2?

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IV. Concentration and Rxn Rate

A. Rate Law Equation: 1. An equation that relates the rate of a reaction to the concentrations of reactants

(and catalyst) raised to various powers.

2. Must be experimentally determined!!

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3. For reaction: A + B C Rate is proportional to reactant concentrations Rate = k[A]m [B]n k = rate constant (exponents “m” and “n” must be

experimentally determined). 4. For reaction: 2 NO2(g) + F2(g) 2 NO2F(g) (experimentally determined Rate Law is:) Rate = k [NO2]1[F2]1 = k [NO2][F2]

Exponents not necessarily same as rxn coefficients!!

Page 17: CHEMICAL KINETICS CHAPTER 13

4. For hypothetical reaction: 2 A(g) + B2(g) 2 AB(g) (experimentally determined Rate Law is:) Rate = k [A]2

Not all reactants necessarily show up in the rate law equation!!

Page 18: CHEMICAL KINETICS CHAPTER 13

B. Reaction Order For the general equation:

aA + bB pP The rate equation is:

Rate = k [A]m [B]n

m and n are experimentally determined and are usually integers (0, 1, 2, 3, …). They may be fractions.

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This reaction is said to m th order with respect to A and n th order with respect to B.

The overall reaction order is the sum of the individual orders, or Overall Reaction Order = m + n

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Example: For the following reaction:

2 NO(g) + Cl2(g) 2 NOCl(g) The observed rate law is:

Rate = k [NO]2 [Cl2] What is the reaction order with respect to NO? What is the reaction order with respect to Cl2? What is the overall reaction order? How would the rate of the reaction be affected by doubling the concentration of both NO and Cl2?

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C. Determination of Rate Law Exponents Done experimentally by measuring initial rates for several different known concentrations of reactants. Consider the reaction:

2 NO(g) + 2 H2(g) N2(g) + 2 H2O(g) Given the information on the next slide:

1. Determine the rate law. 2. What is the order of the reaction? 3. What is the value of the rate constant? “units”

Page 22: CHEMICAL KINETICS CHAPTER 13

Initial Concentration (M) Rate

Experiment [NO] [H2] mol / L.s 1 0.100 0.100 1.23 x 10-3

2 0.100 0.200 2.45 x 10-3

3 0.200 0.100 4.93 x 10-3

4 0.300 0.100 1.11 x 10-2

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1. Determine the rate law. a. Determine general form of rate law. rate = k [NO]m[H2]n

b. Determine exponents. For each reactant, compare two

experiments or trials where its concentration is changing

and all other reactant concentrations are held constant.

Page 24: CHEMICAL KINETICS CHAPTER 13

Methods For Determining Rate Law Exponents

Method 1 – solve analytically Substitute data into rate law and compare Divide equation with larger rate by eq. with

smaller rate. Cancel terms and solve.

or simplifying

Method 2 - solve by inspection How does changing conc. affect rate?

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2. Determine order of the reaction.

3. Determine rate constant (include units). Use rate law and either set of data.

4. What is the rate of the reaction when [NO] = [H2] = 0.200 M ?

Page 26: CHEMICAL KINETICS CHAPTER 13

V. Integrated Rate Law

Equations derived from rate law (by using calculus) which are convenient for solving concentration versus time problems.

For: 1. First Order Rxns – only one covered

2. Second Order Rxns 3. Zero Order Rxns

Page 27: CHEMICAL KINETICS CHAPTER 13

A. Integrated First Order Rate Law For reaction:

aA Product rate = - Δ[A] / Δt = k[A] and using calculus:

where [A]o is the concentration of A at time zero (t = 0) and [A]t is the concentration at time t.

*** A and A0 may be replaced by quantities that are proportional to concentration !!!!

[ ]ln[ ]

t

o

A ktA

Page 28: CHEMICAL KINETICS CHAPTER 13

B. Problem The sugar, sucrose, will undergo the following (first order) hydrolysis reaction C12H22O11 + H2O C6H12O6 + C6H12O6

sucrose glucose fructose with a rate constant of 6.2 x 10-5 s-1 at 35oC.

A sample of 0.20 mol of sucrose was initially dissolved in a total volume of 500 mL.

1. What is the sucrose conc. after 2 hours?

Page 29: CHEMICAL KINETICS CHAPTER 13

2. What will be the glucose concentration after the 2 hours have elapsed?

3. How many minutes will it take for the

sucrose concentration to drop to 0.30M?

Page 30: CHEMICAL KINETICS CHAPTER 13

C. Half-Life and First Order Reactions 1. Definition (t1/2) – the time required for the

concentration of a reactant to fall to one half its initial value.

2. Significance: Useful in describing radioactive decay rates

Useful in describing rates of 1st order reactions

3. Equation derived from Integrated Rate Law

12

.693tk

Page 31: CHEMICAL KINETICS CHAPTER 13
Page 32: CHEMICAL KINETICS CHAPTER 13

4. Problem - Radioactive Iodine-131 has t1/2 of 8

days. If you had a sample of 10,000 I-131

atoms initially, how many I-131 atoms would remain after 32 days?

Page 33: CHEMICAL KINETICS CHAPTER 13

5. Problem – The first order hydrolysis reaction of sucrose C12H22O11 + H2O C6H12O6 + C6H12O6

sucrose glucose fructose

has a rate constant of 6.17 x 10-4 s-1 under experimental conditions.

a. What is the half-life for the hydrolysis of sucrose?

b. How many minutes are required for 75% of the initial sucrose to react?

Page 34: CHEMICAL KINETICS CHAPTER 13

VI. Temperature and Rxn Rate

A. Nanoscale Explanation as to why increasing temperature increase reaction

rate.

B. Mathematical RelationshipArrhenius Equation

(not responsible for problem solving)

/Ea RTk Ae

Page 35: CHEMICAL KINETICS CHAPTER 13

VII. Reaction Mechanisms A. Introduction Reaction mechanism is a series of elementary

reactions or simple steps whose overall effect is given by the net chemical reaction (equation).

1. It is a theory of how the reaction occurs which is based on experimental data.

2. Cannot be absolutely proven. 3. Steps must be elementary reactions.

Page 36: CHEMICAL KINETICS CHAPTER 13

B. Elementary Reaction 1. Definition- the simplest step in what is

often a multi-step mechanism for an observed chemical reaction. a. The equation for an elementary reaction

shows exactly which molecules, atoms, or ions take part in the elementary reaction.

b. For an elementary reaction, the rate law is directly determined from the elementary reaction.

Page 37: CHEMICAL KINETICS CHAPTER 13

2. Elementary Reactions in Mechanisms Types

a. Unimolecular Reaction – structure of a single particle (atom, molecule,

or ion) rearranges to produce a different particle or particles.

b. Bimolecular Reaction - two particles (atoms, ions, or molecules)

collide and rearrange into products. c. Termolecular Reaction – (less likely)

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3. ProblemsIdentify the type of elementary reaction and give the rate law for the following

elementary reactions:

a. Cl + Cl Cl2

b. N2O5 NO2 + NO3

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C. Properties of Valid Mechanisms 1. Must consist of only unimolecular, bimolecular, or termolecular elementary reactions. (True for any mechanisms given to

you.)***2. Sum of the elementary reactions should be

equal to the overall reaction equation.

***3. Should predict the experimentally observed rate law.

The overall rate of the reaction is dependent on the slowest step in the mechanism - the rate-limiting step.

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D. Example Mechanism Problems 1. For the overall reaction: 2 NO2Cl 2 NO2 + Cl2 the following mechanism is proposed.

NO2Cl NO2 + Cl (slow)NO2Cl + Cl NO2 + Cl2 (fast)

a. Does the sum of the elementary processes equal the overall reaction? b. What is the rate law for the overall rxn? c. Identify any reaction intermediates.

Page 41: CHEMICAL KINETICS CHAPTER 13

2. For the overall reaction:(CH3)3CCl + OH- (CH3)3COH + Cl-

there are two proposed mechanisms.

1) Concerted mechanism (CH3)3CCl + OH- (CH3)3COH + Cl-

2) Two Step Mechanism

(CH3)3CCl (CH3)3C + + Cl - (slow) (CH3)3C+ + OH - (CH3)3COH (fast)

Page 42: CHEMICAL KINETICS CHAPTER 13

From kinetic data, the correct rate law for the overall reaction is:

rate = k[(CH3)3CCl] Questions:

1. Which is the correct mechanism? Why?

2. What is the order of the overall reaction?

3. Identify reaction intermediates in eachproposed mechanism.

Page 43: CHEMICAL KINETICS CHAPTER 13

VIII. Catalysts

A. DefinitionCatalyst – a species that increases the rate

of an overall reaction but is not consumed in the reaction.

Not shown in overall reaction.Will show up in rate law for catalyzed reaction.

Page 44: CHEMICAL KINETICS CHAPTER 13

B. How Do They Increase Reaction Rate? 1. Catalysts alter / participate in rxn mechanism. 2. Lower activation energy. Speeds reaction.

3. See Fig 13.17 (next slide)

4. Catalyst changes kinetics, but not thermodynamics of reaction. Increases speed of reaction.

Does not change net energy of reaction, type of product produced, or direction of reaction.

Page 45: CHEMICAL KINETICS CHAPTER 13
Page 46: CHEMICAL KINETICS CHAPTER 13

C. Homogeneous vs. Heterogeneous Catalysts

Heterogeneous Catalyst- catalyst in different phase from reacting substance.(hydrogenation of vegetable oils – next slide)

(catalytic converters in autos)

Homogeneous Catalyst – catalyst in same phase as reacting substance.

(enzymes)

Page 47: CHEMICAL KINETICS CHAPTER 13

Heterogeneous Catalysis

Hydrogen is adsorbed onto the surface of a

nickel catalyst. A C=C approaches …

… and is adsorbed.

Hydrogen atoms attach to the carbon

atoms, and the molecule is desorbed.

Page 48: CHEMICAL KINETICS CHAPTER 13

D. Enzymes (Homogeneous Catalysts) 1. Protein that catalyzes reaction.

2. Most efficient catalysts known to man. 3. Specifically binds to reactants (substrates), holding them in correct position for reaction

to occur. 4. Lower activation energy by stabilizing transition state or altering mechanism. 5. Examples: Lysozyme Next slide

Page 49: CHEMICAL KINETICS CHAPTER 13