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Strategic CapacityManagement
Chapter 5
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Strategic Capacity Management
Capacity
The maximum level ofoutput
The amount of resource inputs availablerelative to output requirements at a particular
time
Capacity is the upper limit or ceiling on theload that an operating unit can handle. (often,
this is characterized as output)
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Examples of Capacity Measures
Type of Measures of Capacity
Organization Inputs Outputs
Manufacturer Machine hours
per shift
Number of units
per shiftHospital Number of beds Number of
patients treated
Airline Number of planes
or seats
Number of
seat-miles flownRestaurant Number of seats Customers/time
Retailer Area of store Sales dollars
Theater Number of seats Customers/time
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Capacity Planning
The basic questions in capacity planning
are:
What type of capacity is needed? [5Ms/5Ps]
How much is needed? [opportunity cost]
When is it needed? [opportunity cost]
How does productivity relate to capacity?
What is the basic Capacity Strategy?
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Two Capacity Strategies
Time between
increments
Forecast of
capacity needed
Forecast of
capacity needed
Planned unused
capacity Planned use of
short-term options
Expansionist Strategy Wait-and-See Strategy
Capacity
Capacity
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Some Short-Term Capacity Options
lease extra space temporarily
authorize overtime
staff second or third shift with temporary workers add weekend shifts
schedule longer runs to minimize
capacity losses
postpone preventive maintenance (risky)
allow backorders to increase, extend due datepromises, or have stock-outs.
subcontract work
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Advantages/Disadvantages of each strategy
Expansionist ahead of competition risky if demand no lost sales changes
Idle Capacity
Wait-and-See no unused capacity rely on short-
easier to adapt to term optionsnew technologies
lost opportunity
Advantages Disadvantages
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Capacity Utilization
Capacity used [1350]
rate of output actually achieved
Best operating level [40x16x3=1920]capacity for which the process was designed
(effective or maximum capacity)
Utilization = _______________Capacity Used
Best Operating Level
1350/1920=70%
1100/1680=65%
1100/1920=57%
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Capacity Utilization &
Service Quality
Best operating point is near 70% of
capacity
From 70% to 100% of service capacity,
what do you think happens to servicequality? Why?
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Utilization--Example
Best operating level = 120 units/week
Actual Scheduled output = 83 units/week
Utilization = ?.692
units/wk120units/wk83=
leveloperatingBestusedCapacitynUtilizatio ==
Hair Salon
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Best Operating Level
Underutilization
Best OperatingLevel (120 Hairdos)
Average
unit cost
of output
Volume
Overutilization
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Economies & Diseconomies of Scale
100-unitplant
200-unit
plant 300-unit
plant
400-unit
plant
Volume
Average
unit cost
of output
Long Run Average Cost Curve
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Capacity Cushion
Capacity Cushion = level of capacity in excess of the average
utilization rate or level of capacity in excess of the expected
demand.
Cushion = Best Operating Level
Capacity Used
- 1
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Large capacity cushion
Required to handle uncertainty in demand service industries
high level of uncertainty in demand (in terms ofboth volume and product-mix)
Fashion/Fads/Electronics to permit allowances for vacations,
holidays, supply of materials delays, equipmentbreakdowns, etc.
if subcontracting, overtime, or the cost ofmissed demand is very high (i.e. penalty cost)Construction of Retail Space
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Small capacitycushion
Given that: Unused capacity still incurs the fixed
costs
highly capital intensive businesses
(Utilities requesting customers to conserve during peak)
time perishable capacity (Airline, movie theater)
(Conversion of large theaters to multi-cinema)
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Capacity Cushion Example
An automobile equipment supplier wishes to install a
sufficient number of ovens to produce 400,000 good
castings per year. The baking operation takes 2.0
minutes per casting, and management requires acapacity cushion of 5%. How many ovens will be
required if each one is available for 1800 hours (of
capacity) per year?
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Example: Target 5% Cushion
- 1cushion = Best Operating LevelCapacity Used
.05 = (1800/x) - 1
1.05 = (1800/x) 1714.3/1800 = .9524
1.05x = 1800x = 1714.3
85.7/1714.3=.049991
85.7/1800=.047611
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Solution
Required system capacity =400,000 good units per year
Number of oven minutes required =400,000 x 2 min/unit = 800,000
Number of oven minutes available/oven =(1800 hrs/oven) x(60 minutes/hour) (.9524)
= 102,859minutes/oven
Number of ovens required= 800,000 min /102,859 mins per oven
= 7.8 or 8 ovens
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Quantity
Step fixed costs and variable costs.
1 machine
2 machines
3 machines
A Way to Gain Capacitybuy resource
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The Experience Curve
Total accumulated production of units
Cost or
price
per unit
As plants produce more products, or
services deliver more of a service, they
gain experience in the best production
methods and inherently or naturallyreduce their costs per unit.
Other Ways to Gain Capacity
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Capacity Flexibility: Having the ability
to respond rapidly to demand volume
changes and product mix changes.
Flexible plantsShare processes
Flexible processesGroup equipment
around productfamilies
Flexible workersCross-train
Cell
Manuf.
Other Ways to Gain Capacity
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Capacity Bottlenecks
Rawmaterial
200/hour 75/hour 200/hour
Operation 1 Operation 2 Operation 3
Bottleneck
Operation
Other Ways to Gain Capacity
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Capacity Planning
Maintaining System Balance
Stage 1 Stage 2 Stage 3
Unitsper
month
6,000 7,000 4,500
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Determining Capacity
Requirements [1] Forecast sales within each individual
product line
[2] Calculate equipment and laborrequirements to meet the forecasts
[3] Project equipment and laboravailability over the planning horizon
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Example--Capacity
RequirementsA manufacturer produces two lines of ketchup,FancyFine and a generic line. Each is sold in
small and family-size plastic bottles.
The following table shows forecast demand for
the next four years.
Year: 1 2 3 4
FancyFine
Small (000s) 50 60 80 100
Family (000s) 35 50 70 90
Generic
Small (000s) 100 110 120 140
Family (000s) 80 90 100 110
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Example of Capacity Requirements:
The Product from a Capacity Viewpoint
Question: Are we really producing
two different types of ketchup from
the standpoint of capacity
requirements?
Answer: No, its the same product just
packaged differently (and water added)
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Example of Capacity Requirements:
Equipment and Labor Requirements
Year: 1 2 3 4
Small (000s) 150 170 200 240
Family (000s) 115 140 170 200
Three 100,000 units-per-year machines are available
for small-bottle production. Two operators required
per machine.
Two 120,000 units-per-year machines are available
for family-sized-bottle production. Three operators
required per machine.
39
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Year: 1 2 3 4
Small (000s) 150 170 200 240
Family (000s) 115 140 170 200
Small Mach. Cap. 300,000 Labor 6
Family-size Mach. Cap. 240,000 Labor 6
Small
Percent capacity used 50.00%
Machine requirement 1.50
Labor requirement 3.00Family-size
Percent capacity used 47.92%
Machine requirement 0.96
Labor requirement 2.88
Question: Identify the Year 1 values for capacity, machine, and labor?
150,000/300,000=50% At 1 machine for 100,000, ittakes 1.5 machines for 150,000
At 2 operators for100,000, it takes 3
operators for 150,000
The McGraw-Hill Companies, Inc., 2001
40
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Year: 1 2 3 4
Small (000s) 150 170 200 240
Family (000s) 115 140 170 200
Small Mach. Cap. 300,000 Labor 6
Family-size Mach. Cap. 240,000 Labor 6
Small
Percent capacity used 50.00%
Machine requirement 1.50
Labor requirement 3.00Family-size
Percent capacity used 47.92%
Machine requirement 0.96
Labor requirement 2.88
Question: What are the values for columns 2, 3 and 4 in the table below?
56.67%
1.70
3.40
58.33%
1.17
3.50
66.67%
2.00
4.00
70.83%
1.42
4.25
80.00%
2.40
4.80
83.33%
1.67
5.00
The McGraw-Hill Companies, Inc., 2001
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How does Quality affect
capacity?
Suppose a three operation process is
followed by an inspection. If the averageproportion of defectives produced at
operations 1, 2, and 3 are .04, .01, and
.02 respectively, and if the demand is 200units, then what is the required capacity
for this operation? [i.e. material inputs]
C it i t ith
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Capacity requirements with
Yield Loss
Notation:
di = avg. proportion of defective units at operation i
n = number of operations in the production process
M = order quantity (good units only or desired yield)
B = avg. number of units at the start of the
production process
B =M
[(1-d1)(1-d2).(1-dn)]
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Solution
Desired yield = 200Operation Defective rate
1 .04
2 .01
3 .02(1) What is the capacity required?
B = = 215200
(1-.04)(1-.01)(1-.02)
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Capacity and Quality
Suppose we have a 6 process assembly
line that must produce 1000 good
products. Each process produces only
1% defects. How is capacity affected?
Capacity required =
= 1062 units
1000(.99)6
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Decision TreesA glass factory specializing in crystal is experiencing a
substantial backlog, and the firm's management is
considering three courses of action:
A) Arrange for subcontracting,
B) Construct new facilities.C) Do nothing (no change)
The correct choice depends largely upon demand, which
may be low, medium, or high. By consensus,management ranks the respective probabilities as .10,
.50, and .40. A cost analysis that reveals the effects
upon costs is shown in the following table.
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Payoff Table
0.1 0.5 0.4
Low Medium HighA 10 50 90
B -120 25 200
C 20 40 60
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We start with our decisions...
AB
C
Subcontracting
Do nothing
Construct new facilities
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Then add our possible states of
nature, probabilities, and payoffs
A
B
C
High demand (.4)
Medium demand (.5)
Low demand (.1)
$90k
$50k
$10k
High demand (.4)
Medium demand (.5)
Low demand (.1)
$200k
$25k
-$120k
High demand (.4)
Medium demand (.5)
Low demand (.1)
$60k
$40k
$20k
D t i th t d l
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Determine the expected value
of each decision
High demand (.4)
Medium demand (.5)
Low demand (.1)
A
$90k
$50k
$10k
EVA=.4(90)+.5(50)+.1(10)=$62k
$62k
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Solution
High demand (.4)
Medium demand (.5)
Low demand (.1)
High demand (.4)Medium demand (.5)
Low demand (.1)
AB
CHigh demand (.4)
Medium demand (.5)
Low demand (.1)
$90k$50k
$10k
$200k$25k
-$120k
$60k
$40k
$20k
$62k
$80.5k
$46k