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Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard Normal Distribution Transforming Z Scores into Proportions Transforming Proportions into Z Scores Finding the Percentile Rank of a Raw Score Finding the Raw Score for a Percentile
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Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Dec 17, 2015

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Page 1: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 1

Chapter 9:The Normal Distribution

• Properties of the Normal Distribution

• Shapes of Normal Distributions

• Standard (Z) Scores

• The Standard Normal Distribution

• Transforming Z Scores into Proportions

• Transforming Proportions into Z Scores

• Finding the Percentile Rank of a Raw Score

• Finding the Raw Score for a Percentile

Page 2: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 2

• Normal Distribution – A bell-shaped and symmetrical theoretical distribution, with the mean, the median, and the mode all coinciding at its peak and with frequencies gradually decreasing at both ends of the curve.

Normal Distributions

• The normal distribution is a theoretical ideal distribution. Real-life empirical distributions never match this model perfectly. However, many things in life do approximate the normal distribution, and are said to be “normally distributed.”

Page 3: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 3

Scores “Normally Distributed?”

• Is this distribution normal?• There are two things to initially examine: (1) look

at the shape illustrated by the bar chart, and (2) calculate the mean, median, and mode.

Table 10.1 Final Grades in Social Statistics of 1,200 Students (1983-1993)Midpoint

Score Frequency Bar Chart Freq.Cum. Freq.

(below) %Cum % (below)

40 * 4 4 0.33 0.3350 ******* 78 82 6.5 6.83

60 *************** 275 357 22.92 29.75

70 *********************** 483 840 40.25 7080 *************** 274 1114 22.83 92.8390 ******* 81 1195 6.75 99.58100 * 5 1200 0.42 100

Page 4: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 4

Scores Normally Distributed!

• The Mean = 70.07• The Median = 70• The Mode = 70• Since all three are essentially equal, and this is

reflected in the bar graph, we can assume that these data are normally distributed.

• Also, since the median is approximately equal to the mean, we know that the distribution is symmetrical.

Page 5: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 5

The Shape of a Normal Distribution: The Normal Curve

Page 6: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 6

The Shape of a Normal Distribution

Notice the shape of the normal curve in this graph. Some normal distributions are tall and thin, while others are short and wide. All normal distributions, though, are wider in the middle and symmetrical.

Page 7: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 7

Notice that the standard deviation changes the relative width of the distribution; the larger the standard deviation, the wider the curve.

Different Shapes of the Normal Distribution

Page 8: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 8

Areas Under the Normal Curve by Measuring Standard Deviations

Page 9: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 9

Standard (Z) Scores

• A standard score (also called Z score) is the number of standard deviations that a given raw score is above or below the mean.

yS

YYZ

Page 10: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 10

The Standard Normal Table

• A table showing the area (as a proportion, which can be translated into a percentage) under the standard normal curve corresponding to any Z score or its fraction

Area up to a given score

Page 11: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 11

The Standard Normal Table

• A table showing the area (as a proportion, which can be translated into a percentage) under the standard normal curve corresponding to any Z score or its fraction

Area beyond a given score

Page 12: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 12

Finding the Area Between the Mean and a Positive Z Score

• Using the data presented in Table 10.1, find the percentage of students whose scores range from the mean (70.07) to 85.

• (1) Convert 85 to a Z score:

Z = (85-70.07)/10.27 = 1.45

(2) Look up the Z score (1.45) in Column A, finding the proportion (.4265)

Page 13: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 13

Finding the Area Between the Mean and a Positive Z Score

(3) Convert the proportion (.4265) to a percentage (42.65%); this is the percentage of students scoring between the mean and 85 in the course.

Page 14: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 14

Finding the Area Between the Mean and a Negative Z Score

• Using the data presented in Table 10.1, find the percentage of students scoring between 65 and the mean (70.07)

• (1) Convert 65 to a Z score:

Z = (65-70.07)/10.27 =•(2) Since the curve is symmetrical and negative area does not exist, use .49 to find the area in the standard normal table:

-.49

.1879

Page 15: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 15

Finding the Area Between the Mean and a Negative Z Score

(3) Convert the proportion (.1879) to a percentage (18.79%); this is the percentage of students scoring between 65 and the mean (70.07)

Page 16: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 16

Finding the Area Between 2 Z Scores on the Same Side of the Mean

• Using the same data presented in Table 10.1, find the percentage of students scoring between 74 and 84.

• (1) Find the Z scores for 74 and 84:

Z = .38 and Z = 1.36• (2) Look up the corresponding areas for those Z

scores: .1480 and .4131

Page 17: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 17

Finding the Area Between 2 Z Scores on the Same Side of the Mean

(3) To find the highlighted area above, subtract the smaller area from the larger area (.4131-.1480 = ) .2651Now, we have the percentage of students scoring between 74 and 84.

Page 18: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 18

Finding the Area Between 2 Z Scores on Opposite Sides of the Mean

• Using the same data, find the percentage of students scoring between 62 and 72.

• (1) Find the Z scores for 62 and 72:

Z = (72-70.07)/10.27 =.19

-.79

.3605

Z = (62-70.07)/10.27 =(2) Look up the areas between these Z scores and the mean, like in the previous 2 examples:

Z = .19 is .0753 and Z = -.79 is .2852

(3) Add the two areas together: .0753 + .2852 =

Page 19: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 19

Finding the Area Between 2 Z Scores on Opposite Sides of the Mean

(4) Convert the proportion (.3605) to a percentage (36.05%); this is the percentage of students scoring between 62 and 72.

Page 20: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 20

Finding Area Above a Positive Z Score or Below a Negative Z Score

• Find the percentage of students who did (a) very well, scoring above 85, and (b) those students who did poorly, scoring below 50.

• (a) Convert 85 to a Z score, then look up the value in Column C of the Standard Normal Table:

Z = (85-70.07)/10.27 =1.45 (b) Convert 50 to a Z score, then look up the value (look for a positive Z score!) in Column C:

Z = (50-70.07)/10.27 = -1.95

7.35%

2.56%

Page 21: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 21

Finding Area Above a Positive Z Score or Below a Negative Z Score

Page 22: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 22

Finding a Z Score Bounding an Area Above It

• Find the raw score that bounds the top 10 percent of the distribution (Table 10.1)

• (1) 10% = a proportion of .10• (2) Using the Standard Normal Table, look in

Column C for .1000, then take the value in Column A; this is the Z score (1.28)

(3) Finally convert the Z score to a raw score:

Y=70.07 + 1.28 (10.27) = 83.22

Page 23: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 23

Finding a Z Score Bounding an Area Above It

(4) 83.22 is the raw score that bounds the upper 10% of the distribution. The Z score associated with 83.22 in this distribution is 1.28

Page 24: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 24

Finding a Z Score Bounding an Area Below It

• Find the raw score that bounds the lowest 5 percent of the distribution (Table 10.1)

• (1) 5% = a proportion of .05• (2) Using the Standard Normal Table, look in

Column C for .05, then take the value in Column A; this is the Z score (-1.65); negative, since it is on the left side of the distribution

• (3) Finally convert the Z score to a raw score:Y=70.07 + -1.65 (10.27) =53.12

Page 25: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 25

Finding a Z Score Bounding an Area Below It

(4) 53.12 is the raw score that bounds the lower 5% of the distribution. The Z score associated with 53.12 in this distribution is -1.65

Page 26: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 26

Finding the Percentile Rank of a Score Higher than the Mean

• Suppose your raw score was 85. You want to calculate the percentile (to see where in the class you rank.)

• (1) Convert the raw score to a Z score:

Z = (85-70.07)/10.27 =1.45

(2) Find the area beyond Z in the Standard Normal Table (Column C): .0735

(3) Subtract the area from 1.00 for the percentile, since .0735 is only the area not below the score:

1.00 - .0735 = .9265 (proportion of scores below 85)

Page 27: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 27

Finding the Percentile Rank of a Score Higher than the Mean

(4) .9265 represents the proportion of scores less than 85 corresponding to a percentile rank of 92.65%

Page 28: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 28

Finding the Percentile Rank of a Score Lower than the Mean

• Now, suppose your raw score was 65.• (1) Convert the raw score to a Z score

Z = (65-70.07)/10.27 =-.49

(2) Find the are beyond Z in the Standard Normal Table, Column C: .3121

(3) Multiply by 100 to obtain the percentile rank:

.3121 x 100 = 31.21%

Page 29: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 29

Finding the Percentile Rank of a Score Lower than the Mean

Page 30: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 30

Finding the Raw Score of a Percentile Higher than 50

• Say you need to score in the 95th% to be accepted to a particular grad school program. What’s the cutoff for the 95th%?

• (1) Find the area associated with the percentile:95/100 = .9500

• (2) Subtract the area from 1.00 to find the area above & beyond the percentile rank:

1.00 - .9500 = .0500• (3) Find the Z Score by looking in Column C of

the Standard Normal Table for .0500: Z = 1.65

Page 31: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 31

Finding the Raw Score of a Percentile Higher than 50

(4) Convert the Z score to a raw score.Y= 70.07 + 1.65(10.27) = 87.02

Page 32: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 32

Finding the Raw Score of a Percentile Lower than 50

• What score is associated with the 40th%?• (1) Find the area below the percentile:

40/100 = .4000• (2) Find the Z score associated with this area. Use

Column C, but remember that this is a negative Z score since it is less than the mean; so, Sy = -.25

• (3) Convert the Z score to a raw score:

Y = 70.07 + -.25(10.27) =67.5

Page 33: Chapter 9 – 1 Chapter 9: The Normal Distribution Properties of the Normal Distribution Shapes of Normal Distributions Standard (Z) Scores The Standard.

Chapter 9 – 33

Finding the Raw Score of a Percentile Lower than 50