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Chapter Chapter 8 8 Section Section 6 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
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Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Jan 05, 2016

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Page 1: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Chapter Chapter 88Section Section 66

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Page 2: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solving Equations with Radicals

Solve radical equations having square root radicals.Identify equations with no solutions.Solve equations by squaring a binomial.Solve radical equations having cube root radicals.

11

44

33

22

8.68.68.68.6

Page 3: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solving Equations with Radicals.

A radical equation is an equation having a variable in the radicand, such as

Slide 8.6 - 3

1 3x or 3 8 9x x

Page 4: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Objective 11

Slide 8.6 - 4

Solve radical equations having square root radicals.

Page 5: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

To solve radical equations having square root radicals, we need a new property, called the squaring property of equality.

Be very careful with the squaring property: Using this property can give a new equation with more solutions than the original equation has. Because of this possibility, checking is an essential part of the process. All proposed solutions

from the squared equation must be checked in the original equation.

Slide 8.6 - 5

Solve radical equations having square root radicals.

If each side of a given equation is squared, then all solutions of the original equation are among the solutions of the squared equation.

Page 6: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 1

Solve.

Solution:

Using the Squaring Property of Equality

Slide 8.6 - 6

It is important to note that even though the algebraic work may be done perfectly, the answer produced may not make the original equation true.

9 4x

229 4x

9 16x 9 169 9x

7x 7x 7

Page 7: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solve.

EXAMPLE 2 Using the Squaring Property with a Radical on Each Side

Slide 8.6 - 7

Solution:

3 9 2x x

2 2

3 9 2x x

3 9 4x x

3 33 9 4xx x x

9x

9

Page 8: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Objective 22

Identify equations with no solutions.

Slide 8.6 - 8

Page 9: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 3

Solution:

Using the Squaring Property when One Side Is Negative

Slide 8.6 - 9

Solve.4x

2 2

4x

16x 16 4

4 4

4x

False

Because represents the principal or nonnegative square root of x in Example 3, we might have seen immediately that there is no solution.

x

Check:

Page 10: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Use the following steps when solving an equation with radicals.

Step 1 Isolate a radical. Arrange the terms so that a radical is isolated on one side of the equation.

Solving a Radical Equation.

Slide 8.6 - 10

Step 6 Check all proposed solutions in the original equation.

Step 5 Solve the equation. Find all proposed solutions.

Step 4 Repeat Steps 1-3 if there is still a term with a radical.

Step 3 Combine like terms.

Step 2 Square both sides.

Page 11: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 4

Solution:

Using the Squaring Property with a Quadratic Expression

Slide 8.6 - 11

Solve 2 4 16.x x x

22 2 4 16x x x

2 22 24 16x xx x x

44 40 16xx x 4 1

4 4

6x

4x Since x must be a positive number the solution set is Ø.

Page 12: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Objective 33

Slide 8.6 - 12

Solve equations by squaring a binomial.

Page 13: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 5

Solve

Solution:

Using the Squaring Property when One Side Has Two Terms

Slide 8.6 - 13

2 1 10 9.x x

222 1 10 9x x

2 10 94 4 1 10 99 10x x xx x 24 14 8 0x x

2 1 2 8 0x x

2 8 0x 2 1 0x 4x 1

2x

Since x must be positive the solution set is {4}.

or

Page 14: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solve.

EXAMPLE 6 Rewriting an Equation before using the Squaring Property

Slide 8.6 - 14

Solution:

25 6x x

625 66x x

2 2

25 6x x 225 12 325 256x x xx x 20 13 36x x

0 4 9x x 0 9x 0 4x

9x 4x

The solution set is {4,9}.

or

Page 15: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solve equations by squaring a binomial.

Errors often occur when both sides of an equation are squared. For instance, when both sides of

are squared, the entire binomial 2x + 1 must be squared to get 4x2 + 4x + 1. It is incorrect to square the 2x and the 1 separately to get 4x2 + 1.

Slide 8.6 - 15

9 2 1x x

Page 16: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 7 Using the Squaring Property Twice

Slide 8.6 - 16

Solve.

Solution:

1 4 1x x

1 1 4x x

2 2

1 1 4x x

1 1 2 4 4x x x

224 2 4x

16 4 16x 32

4 4

4x

8x The solution set is {8}.

Page 17: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Objective 44

Slide 8.6 - 17

Solve radical equations having cube root radicals.

Page 18: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solve radical equations having cube root radicals.

Slide 8.6 - 18

We can extend the concept of raising both sides of an equation to a power in order to solve radical equations with cube roots.

Page 19: Chapter 8 Section 6 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

EXAMPLE 8Solving Equations with Cube Root Radicals

Slide 8.6 - 19

Solve each equation.

Solution:

3 37 4 2x x 3 2 3 26 27x x

3 3

3 2 3 26 27x x 2 26 27x x

20 26 27x 0 27 1x x

0 27x 0 1x 27x 1x

3 33 37 4 2x x

7 4 2x x 3 2

3 3

x

2

3x

2

3

27,1

or