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Chemistry, The Central Science, 10th edition Theodore L. Brown; H. Eugene LeMay, Jr.; and Bruce E. Bursten Chapter 8 Basic Concepts of Chemical Bonding Troy Wood University of Buffalo Buffalo, NY 2006, Prentice
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Chapter 8 Basic Concepts of Chemical Bonding

Mar 18, 2016

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Chapter 8 Basic Concepts of Chemical Bonding. Chemistry, The Central Science , 10th edition Theodore L. Brown; H. Eugene LeMay, Jr.; and Bruce E. Bursten. Troy Wood University of Buffalo Buffalo, NY  2006, Prentice Hall. - PowerPoint PPT Presentation
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Page 1: Chapter 8 Basic Concepts of Chemical Bonding

Chemistry, The Central Science, 10th edition

Theodore L. Brown; H. Eugene LeMay, Jr.;and Bruce E. Bursten

Chapter 8Basic Concepts of Chemical Bonding

Troy WoodUniversity of BuffaloBuffalo, NY 2006, Prentice Hall

Page 2: Chapter 8 Basic Concepts of Chemical Bonding

The electron configuration: 1s22s22p53s23p64s23d

7 is consistent with which atom?

1. Fe2. Co3. Cu4. Ni

Page 3: Chapter 8 Basic Concepts of Chemical Bonding

Correct Answer:

The electron configuration [Ar]4s23d

7 corresponds to cobalt.

1. Fe2. Co3. Cu4. Ni

Page 4: Chapter 8 Basic Concepts of Chemical Bonding

The electron configuration of Fe3+ is which of the following?

1. 1s22s22p53s23p64s23d6

2. 1s22s22p53s23p64s23d3

3. 1s22s22p53s23p63d5

4. 1s22s22p53s23p64s13d4

Page 5: Chapter 8 Basic Concepts of Chemical Bonding

Correct Answer:

1. 1s22s22p53s23p64s23d6

2. 1s22s22p53s23p64s23d3

3. 1s22s22p53s23p63d5

4. 1s22s22p53s23p64s13d4

Page 6: Chapter 8 Basic Concepts of Chemical Bonding

Arrange the following ionic compounds in order of increasing lattice energy: LiCl, NaCl, MgCl2

1. NaCl < LiCl < MgCl2

2. LiCl < NaCl < MgCl2

3. MgCl2 < NaCl < LiCl

Page 7: Chapter 8 Basic Concepts of Chemical Bonding

Correct Answer:

1. NaCl < LiCl < MgCl2

2. LiCl < NaCl < MgCl2

3. MgCl2 < NaCl < LiCl

Lattice energy depends on size of the ions and their charges. MgCl2 has the highest lattice energy because it has a more positive cation. LiCl is higher than NaCl because the interatomic distance between cation and ion is shorter.

Page 8: Chapter 8 Basic Concepts of Chemical Bonding

Which of the following carbon–carbon atom bonds would be expected to be the shortest?

1. CC

2. CC

3. CC

Page 9: Chapter 8 Basic Concepts of Chemical Bonding

1. CC

2. CC

3. CC

Correct Answer:

The bond length decreases as the bond enthalpy increases; in general, as the number of bonds between two atoms increases, the bond grows shorter and stronger.

Page 10: Chapter 8 Basic Concepts of Chemical Bonding

Based on the electronegativities of the atoms, which of the following bonds would you predict is most polar?

1. CC2. CN3. CO4. CSi5. CBr

Page 11: Chapter 8 Basic Concepts of Chemical Bonding

Correct Answer:

The difference in electronegativities is greatest between O (3.5) and C (2.5) for a net difference of 1.0. Each of the other combinations yields a smaller value for electronegativity difference.

1. CC2. CN3. CO4. CSi5. CBr

Page 12: Chapter 8 Basic Concepts of Chemical Bonding

Boron (B) has an electronegativity of 2.0; chlorine (Cl) has an electronegativity of 3.0. Which of the following BEST describes a BCl bond? 1. Ionic

2. Polar covalent

3. Nonpolar covalent

Page 13: Chapter 8 Basic Concepts of Chemical Bonding

1. Ionic

2. Polar covalent

3. Nonpolar covalent

Correct Answer:

The difference in electronegativities is 1.0 because Cl = 3.0 and B = 2.0. This is too low to be an ionic bond but too high to be a nonpolar covalent bond.

Page 14: Chapter 8 Basic Concepts of Chemical Bonding

Which of the following molecules has a zero dipole moment?

1. HF

2. H2O

3. CS2

4. CHCl3

Page 15: Chapter 8 Basic Concepts of Chemical Bonding

Correct Answer:

1. HF

2. H2O

3. CS2

4. CHCl3

Even though each C=S bond is polar, their dipole vector quantities cancel each other out, and CS2 has no net dipole.

Page 16: Chapter 8 Basic Concepts of Chemical Bonding

Which of the following BEST describes the formal charges on the atoms in the cyanide ion, CN ?

1. C = +1, N = 1

2. C = 1, N = +1

3. C = 0, N = 1

4. C = 1, N = 0

Page 17: Chapter 8 Basic Concepts of Chemical Bonding

Correct Answer:

The formal charges are calculated from the difference between number of valence electrons and number of electrons assigned to each atom in the Lewis structure, thus:

C: 4 valence e 5 e = 1N: 5 valence e 5 e = 0

1. C = +1, N = 1

2. C = 1, N = +1

3. C = 0, N = 1

4. C = 1, N = 0

Page 18: Chapter 8 Basic Concepts of Chemical Bonding

Which is predicted to have the longest carbon–oxygen bonds: CO, CO2, or CO3

2?

1. CO32

2. CO2

3. CO

Page 19: Chapter 8 Basic Concepts of Chemical Bonding

Correct Answer:

In CO, the carbon–oxygen bond is a triple bond, while in CO2 both carbon–oxygen bonds are double bonds. In CO3

2, there are three resonance structures and the average carbon–oxygen bond is 1 1/3.

1. CO32

2. CO2

3. CO

Page 20: Chapter 8 Basic Concepts of Chemical Bonding

1. 467 kJ2. +467 kJ3. +17 kJ4. 983 kJ

Calculate H from the following bond enthalpies for the reaction:

2 NCl3 N2 + 3 Cl2D(NCl) = 200, D(NN) = 941, D(ClCl) = 242 (all kJ/mol).

Page 21: Chapter 8 Basic Concepts of Chemical Bonding

Correct Answer:

H = (bond enthalpies of bonds broken) ( bond enthalpies of bonds formed)

H = 6(200) [941 + 3(242)]

H = 1200 (1667)

H = 467

1. 467 kJ2. +467 kJ3. +17 kJ4. 983 kJ