Chapter 6 Answers Skill and Practice Sheet Answers 6A Adding Displacement Vectors Practice set 1: 1. The total displacement is 5 meters east and 5 meters north. 2. The total displacement is 2 meters east and 2 meters south. 3. The total displacement is zero. Total distance traveled is 40 meters. Practice set 2: 1. x R = (1, –5)m 2. x R = (3, 3)m; diagram at right: 3. x R = (5, 5)m 4. x R = (6, 2)m 5. x R = (2, 0)m 6B Projectile Motion 1. Answers are: a. horizontal and vertical distance b. horizontal speed c. d x = v x t; d y = 4.9t 2 d. 6.4 m/s 2. Answers are: a. horizontal speed, time b. vertical distance, horizontal distance c. d y = 4.9t 2 ; d x = v x t d. height = 44.1 meters, horizontal distance = 30 meters 3. Answers are: a. vertical distance b. time c. d y = 4.9t 2 d. 1.4 seconds 4. Answers are: a. horizontal and vertical distance b. horizontal speed c. d x = v x t; d y = 4.9t 2 d. 59 m/s 5. Answers are: a. horizontal speed, time b. vertical distance c. d y = 4.9t 2 d. 2.8 meters 6. Answers are: a. horizontal speed, vertical distance b. time c. d y = 4.9t 2 d. 0.45 seconds 7. Answers are: a. height of bridge, time b. height of person c. bridge height - vertical distance marshmallow travels = person’s height; d y = 4.9t 2 d. marshmallow travels 3.38 meters; person’s height = 1.62 meters Page 1 of 2
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Chapter 6 Answers
Skill and Practice Sheet Answers
6A Adding Displacement Vectors
Practice set 1:1. The total displacement is 5 meters east and 5 meters north.2. The total displacement is 2 meters east and 2 meters south.3. The total displacement is zero. Total distance traveled is 40 meters.
Practice set 2:1. xR = (1, –5)m2. xR = (3, 3)m; diagram at right:3. xR = (5, 5)m4. xR = (6, 2)m5. xR = (2, 0)m
6B Projectile Motion
1. Answers are:a. horizontal and vertical distanceb. horizontal speedc. dx = vxt; dy = 4.9t2
d. 6.4 m/s2. Answers are:
a. horizontal speed, timeb. vertical distance, horizontal distancec. dy = 4.9t2; dx = vxt
d. height = 44.1 meters, horizontal distance = 30 meters3. Answers are:
a. vertical distanceb. timec. dy = 4.9t2
d. 1.4 seconds4. Answers are:
a. horizontal and vertical distanceb. horizontal speedc. dx = vxt; dy = 4.9t2
d. 59 m/s5. Answers are:
a. horizontal speed, timeb. vertical distancec. dy = 4.9t2
d. 2.8 meters6. Answers are:
a. horizontal speed, vertical distanceb. timec. dy = 4.9t2
d. 0.45 seconds7. Answers are:
a. height of bridge, timeb. height of personc. bridge height - vertical distance marshmallow travels = person’s
height; dy = 4.9t2
d. marshmallow travels 3.38 meters; person’s height = 1.62 meters
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UNIT 2: FORCES
CHAPTER 6: SYSTEMS IN MOTION
6C Circular Motion
1. Answers are:a. 1,188°/secondb. 200 rpm
2. Answers are:a. 0.38 meterb. 1.52 m/sc. 0.75 m/s
3. Slower. A cd rotates at about 500 rpm when the head reads the inneredge and 200 rpm when the head reads the outer edge.
4. Answers are:a. 0.96 meterb. 2.15 meterc. 1,042 revsd. 465 revs
6D Universal Gravitation
1. F = 9.34 × 10–6 N. This is basically the force between you and yourcar when you are at the door.
2. 5.27 × 10-10 N3. 4.42 N4. 7.36 × 1022 kilograms5. Answers are:
a. 9.8 N/kg = 9.8 kg·m/s2-kg = 9.8 m/s2
b. Acceleration due to the force of gravity of Earth.c. Earth’s mass and radius.
6. 1.99 ×1020 N7. 4,848 N8. 3.52 × 1022 N
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