Chapter 5 – Operational Amplifiers Note: We are temporarily skipping the remaining sections of Chapter 4. We will cover them after completing Chapter 5. Operational Amplifier - An operational amplifier (op amp) is a high gain differential amplifier with nearly ideal external characteristics. Internally the op amp is constructed using many transistors. Terminology : V + = non-inverting input voltage V - = inverting input voltage V o = output voltage I o = output current I + = non-inverting input current I - = inverting input current V DC = positive and negative DC supply voltages used to power the op amp (typically Note : Sometimes the supply voltage connections are not shown Reading Assignment: Chapter 5 in Electric Circuits, 9 th Edition by Nilsson 1 Chapter 5 EGR 271 – Circuit Theory I V O V + V - V + - I + I - +V DC -V DC + _ I o
Chapter 5 EGR 271 – Circuit Theory I. 1. Reading Assignment: Chapter 5 in Electric Circuits, 9 th Edition by Nilsson . Chapter 5 – Operational Amplifiers Note: We are temporarily skipping the remaining sections of Chapter 4. We will cover them after completing Chapter 5. - PowerPoint PPT Presentation
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Chapter 5 – Operational AmplifiersNote: We are temporarily skipping the remaining sections of Chapter 4. We will cover them after completing Chapter 5.
Operational Amplifier - An operational amplifier (op amp) is a high gain differential amplifier with nearly ideal external characteristics. Internally the op amp is constructed using many transistors.
voltages used to power the op amp (typically 5V to 30V)
V = V+ - V- = difference voltageNote: Sometimes the supply voltage connections are not shown
Reading Assignment: Chapter 5 in Electric Circuits, 9th Edition by Nilsson
1Chapter 5 EGR 271 – Circuit Theory I
Operational Amplifiers
U1
uA741
3
2
74
6
1
5+
-
V+V-
OUT
OS1
OS2
8-pin package (3D view)
8-pin package pinout
uA741 symbol in PSPICE
2Chapter 5 EGR 271 – Circuit Theory I
Typical Operational Amplifier Schematic
3Chapter 5 EGR 271 – Circuit Theory I
Open-loop versus closed-loop operation:
Open-loop:• Relatively rare• Op amp specifications may be important
OL
OL
oo OL OL
A = open-loop gain (typical value: A = 100,000)
V = differential input voltageVIn general, V = A V or A = V
Closed-loop:
• Most commonly used• Some sort of feedback from output to input exists• The input voltage, Vin, is defined according to the
applicationCL
oCL
in
A = closed-loop gain VA = V
VO
V+
V-
V +
-
+
_
VO
+
_
Feedback
Vin
4Chapter 5 EGR 271 – Circuit Theory I
An op amp circuit can be easily analyzed using the following ideal assumptions.Ideal op-amp assumptions:· Assume that V = 0, so V+ = V-
· Assume the input resistance is infinite, so I+ = I- = 0· Realize the all voltages defined above are node voltages w.r.t. a common
ground (as illustrated below)
Illustration: Draw an op amp showing a common negative terminal for all node voltages.
5Chapter 5 EGR 271 – Circuit Theory I
Example: Determine an expression for Vo in the inverting amplifier shown below. Illustrate the results using both DC and AC inputs.
Vo +
_ Vin R1
R2
6Chapter 5 EGR 271 – Circuit Theory I
Example: Find Vo , I1, V2, and Io below.
Vo
+
_ 2V 4k
12k
1k
6k
3k
9k V2
+
_
I1
Io
Load Connections: Vo is typically determined independent of the load (the circuit connected to the output). Once Vo has been determined, it essentially acts like a voltage source to the load.Load Current: Io is the output current for an op amp. It can be found using KCL.
7Chapter 5 EGR 271 – Circuit Theory I
Example: Determine an expression for Vo in the non-inverting amplifier shown below.
Vo +
_
Vin
R1
R2
8Chapter 5 EGR 271 – Circuit Theory I
Example: Determine Vo in the inverting summing amplifier shown below.
Vo +
_ V1 R 1
RF
V2 R 2
V3 R 3
9Chapter 5 EGR 271 – Circuit Theory I
Example: Determine Vo in the non-inverting summing amplifier shown below.
Vo +
_
V1 R1
RF
V2 R2
V3 R3
R
10Chapter 5 EGR 271 – Circuit Theory I
Example: Determine VL in the circuit shown below.
+
_ 2k
3k
3k 2k
4k VL
+
_ 12k
4k + _ 12 V
11Chapter 5 EGR 271 – Circuit Theory I
Example: Determine Vo in the circuit shown below.
10k
+ _ 2 V
8k
+
_
20k
2k
4k +
_
12k
Vo
12Chapter 5 EGR 271 – Circuit Theory I
Practical Limitations in op ampsOperational amplifier circuits are generally easy to analyze, design, and construct and their behavior is fairly ideal. There are, however, some limitations to op amps which the engineer should recognize. There are three primary limitations as well as some minor limitations that will be discussed in later courses.
The three primary limitations in op amps are:1) Limited voltage - In general, the output voltage is limited by the DC supply
voltages.2) Limited current - The output current has a maximum limit set by the
manufacturer (check the data sheet).3) Frequency limitations - Op amp performance may deteriorate significantly
as frequency increases (studied in later courses)
13Chapter 5 EGR 271 – Circuit Theory I
Voltage LimitationsVo for any op amp circuit is limited by the supply voltage. In general,
If Vo attempts to exceed these limits, the output is limited to +VDC or -VDC and we say that the op amp is “saturated” or is “in saturation.” Practically, Vo is often about 2V under the supply voltage, or
DC o DC-V V V
DC o DC-V 2 V V - 2 Example: Consider the inverting amplifier shown below (covered earlier).1) Determine the voltage gain, ACL = Vo/Vin
Vo +
_ Vin 4k
12k
+12V
-12V
14Chapter 5 EGR 271 – Circuit Theory I
2) Determine Vo for various possible values of Vin (fill out the table shown below) Vin Vo Vin Vo
0V1V -1V2V -2V3V -3V4V -4V5V -5V
3) Graph Vo versus Vin . Identify the saturation and linear regions of operation. Vo
Vin
15Chapter 5 EGR 271 – Circuit Theory I
Example: Consider the inverting amplifier shown below (covered earlier).1) If R2 = 4k, determine range of values for Vin such that the op am will
operate in the linear range2) If Vin = 2V, determine R2 (max) such that the op am will operate in the
linear range
Vo
+
_Vin
2k
R2
-12V
+12V
16Chapter 5 EGR 271 – Circuit Theory I
Example: Sketch Vo (on the same graph) for the circuit shown below if Vin is a triangle wave as specified below.
Vo
+
_Vin
2k
4k
-10V
+10V
Vin 10V
-10V
20V
-20V
0V
17Chapter 5 EGR 271 – Circuit Theory I
Current LimitationsThe maximum output current, Io for an op amp is specified by the manufacturer. Exceeding this limit will typically destroy the op amp. The output current can be calculated using KCL at the output node. An op amp circuit should be designed to insure that its output current does not exceed the maximum value, Io (max), specified by the manufacturer.
Example: If Io (max) is specified at 25 mA by the manufacturer, determine the
minimum value of RL that can safely be used in the circuit shown below.
Vo +
_
4 V
500
1000
RL
Io
18Chapter 5 EGR 271 – Circuit Theory I
Using node equations to analyze op amp circuitsAs op amp circuits become more complex, simultaneous equations may be needed to analyze them. Node equations are a natural choice since many op amp voltages are expressed as node voltages. Note: Writing a KCL (node) equation at the output node is not typically helpful except to find Io since it introduced another unknown (Io).
Example: Determine Vo in the circuit shown below.
+ _ 2 V
1k
1k +
_
2k
Vo
3k
Note: Writing a KCL equation (node equation) at the output is only helpful for finding Io since it introduces another unknown (Io).
19Chapter 5 EGR 271 – Circuit Theory I
Example: Determine Vo in the circuit shown below.
Vo +
_ 5k
10k
2k
+ _ 10V
4k
20Chapter 5 EGR 271 – Circuit Theory I
Example: The circuit shown below is a current amplifier. Determine an expression for IL . Also find the current gain, AI = IL/IS.
Vo +
_
R1 RL
R2
IS
IL
21Chapter 5 EGR 271 – Circuit Theory I
Op amp modelsSo far we have analyzed op amps using a few ideal assumptions about op amps (such as V+ = V- and I+ = I- = 0) . How would we convey these assumptions to a Circuit Theory I program like PSPICE? Typically, we would construct a circuit model that acts like the op amp that we desire. A simple op amp model is shown below. Also note that PSPICE can be used to model op amps with specific part numbers (such as the uA741 in the PSPICE library EVAL.SLB). In these cases, ORCAD develops very detailed circuit models that match the characteristics of the particular op amp. The ORCAD model might look like the model shown below plus additional components to more accurately model additional features.
R Vo +
- AOLV V +
_ V-
V+
Simple op-amp model
Lines added only for emphasis
Typical values for the op amp model shown:AOL = 100,000Rin = 2M - 10M
22Chapter 5 EGR 271 – Circuit Theory I
Example: Determine Vo in the circuit shown in two ways:1) by making ideal op amp assumptions
+ _
2V 1k
+
_ 4k
Vo
23Chapter 5 EGR 271 – Circuit Theory I
Example: Determine Vo in the circuit shown in two ways:2) by using an ideal op amp model with Rin = 2M and AOL = 100,000.
+ _
2V 1k
+
_ 4k
Vo
24Chapter 5 EGR 271 – Circuit Theory I
Analyzing operational amplifier circuits using PSPICE:
There are two ways to analyze op amp circuits using PSPICE.
1) Use the general op amp model just introduced (consisting of a resistor and a voltage-controlled voltage source.
2) Use one of the op amp models from a PSPICE library (such as the uA741).
Refer to two examples on the course web site:1) Op Amp Example using a General Op Amp Model 2) Op Amp Circuit using a Library Model ( uA741)