CHAPTER 4 The Time Value of Money Dr. Mohammad Abuhaiba, PE 1.

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CHAPTER 4The Time Value of Money

Dr. Mohammad Abuhaiba, PE

. , Dr Mohammad Abuhaiba PE

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Money

Medium of Exchange -- Means of payment for goods or services; What sellers accept and buyers pay ; Store of Value -- A way to transport buying power from one time

period to another; Unit of Account -- A precise measurement of value or worth; Allows for tabulating debits and credits;


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Capital

Wealth in the form of money or property that can be used to produce more wealth.


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Kinds of Capital

Equity capital: owned by individuals who have invested their money or property in a business project or venture in the hope of receiving a profit.

Debt capital: often called borrowed capital, is obtained from lenders (e.g., through the sale of bonds) for investment.


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Interest Fee that a borrower pays to a

lender for the use of his or her money.

Interest Rate: percentage of money being borrowed that is paid to the lender on some time basis.


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Simple Interest Total interest earned or charged is linearly

proportional to initial amount of loan (principal), the interest rate and the number of interest periods for which the principal is committed.

When applied, total interest “I” may be found by

I = P N i P = principal amount lent or borrowed N = number of interest periods ( e.g., years ) i = interest rate per interest period


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Compound InterestWhenever the interest charge for any interest period is based on remaining principal amount plus any accumulated interest charges up to the beginning of that period.Perio

dAmount Owned

beginning of period

Interest amount for

period @10%

Amount Owned at end of period

1 $1000 $100 $1100

2 $1100 $110 $1210

3 $1210 $121 $1331


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ECONOMIC EQUIVALENCE

Established when we are indifferent between a future payment, or a series of future payments, and a present sum of money .

Considers the comparison of alternative options, or proposals, by reducing them to an equivalent basis, depending on: interest rate; amounts of money involved; timing of the affected monetary receipts and/or

expenditures; manner in which the interest , or profit on invested

capital is paid and the initial capital is recovered.


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Notation and Cash Flow Diagrams and Tables

i = effective interest rate per interest period N = number of compounding periods P = present sum of money F = future sum of money A = end-of-period cash flows in a uniform series

continuing for a specified number of periods, starting at end of first period and continuing through the last period

G = uniform gradient amounts - used if cash flows increase by a constant amount in each period


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Cash Flow Diagram Notation

1 2 3 4 5 = N1

1 Time scale with progression of time moving from left to right; numbers represent time periods and may be presented within a time interval or at the end of a time interval.

P =$8,000 2

2 Present expense (cash outflow) of $8,000 for lender.

A = $2,5243

3 Annual income (cash inflow) of $2,524 for lender.

i = 10% per year4

4 Interest rate of loan.

5

5 Dashed-arrow line indicates amount to be determined.


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Example 4-1:Cash Flow Diagraming

Before evaluating the economic merits of a proposed investment, the XYZ Corporation insists that its engineers develop a cash-flow diagram of the proposal. An investment of $10,000 can be made that will produce uniform annual revenue of $5,310 for five years and then have a market (recovery) value of $2,000 at the end of year five. Annual expenses will be $3,000 at the end of each year for operating and maintaining the project. Draw a cash-flow diagram for the five-year life of the project. Use the corporation’s viewpoint.


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Example 4-2Developing a Net Cash Flow Table

In a company’s renovation of a small office building, two feasible alternatives for upgrading the heating, ventilation, and air conditioning (HVAC) system have been identified. Either Alternative A or Alternative B must be implemented. The costs are as follows: Alternative A: Rebuild (overhaul) the existing HVAC system Equipment, labor, and materials to install: $18,000 Annual cost of electricity:$32,000 Annual maintenance expenses: $2,400 Alternative B: Install a new HVAC system that utilizes existing ductwork Equipment, labor, and materials to install: $60,000 Annual cost of electricity:$9,000 Annual maintenance expenses: 16,000 Replacement of a major component four years hence At the end of eight years, the estimated market value for Alternative A is $2,000, and for Alternative B it is $8,000. Assume that both alternatives will provide comparable service over an eight-year period. Assume that the major component replaced in Alternative B will have no market value at the end of year eight.(1) Use a cash-flow table and end-of-year convention to tabulate the net cash flows for both alternatives.(2) Determine the annual net cash flow difference between the alternatives (B-A).


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Relating Present and Future Equivalent Values of Single Cash Flows

Finding F when given P: Finding future value when given present value F = P ( 1+i )N

(1+i)N single payment compound amount factor functionally expressed as F = ( F / P, i%, N ) predetermined values of this are presented in

column 2 of Appendix C of text.

P

0

N =

F = ?


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Example 4-3Future Equivalent of a Present Sum

Suppose that you borrow $8,000 now, promising to repay the loan principal plus accumulated interest in four years at i=10% per year. How much would you repay at the end of four years?


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Relating Present and Future Equivalent Values of Single Cash Flows Finding P when given F: Finding present value when given future

value P = F [1 / (1 + i ) ] N

(1+i)-N single payment present worth factor functionally expressed as P = F ( P / F, i%, N ) predetermined values of this are presented in

column 3 of Appendix C of text;

P = ?

0 N = F


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Example 4-4Present Equivalent of a Future Amount of Money

An investor (owner) has an option to purchase a tract of land that will be worth $10,000 in six years. If the value of the land increases at %8 each year, how much should the investor be willing to pay now for this property?


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Example 4-5The Inflating Price of Gasoline

The average price of gasoline in 2005 was $2.31 per gallon. In 1993the average price was $1.07. What was the average annual rate of increase in the price of gasoline over this 12 year period?


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Example 4-6When Will Gasoline Cost $5.00 per Gallon?

In Example 4.5 the average price of gasoline was given as $2.31 in 2005. We computed the average annual rate of increase in the price of gasoline to be 6.62%. If we assume that the price of gasoline will continue of inflate at this rate, how long will it be before we are paying $5 per gallon?


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Relating a Uniform Series (Annuity) to Its Present and Future Equivalent Values

Finding F given AFinding future equivalent income (inflow) value given a series of uniform equal Payments

functionally expressed as F = A ( F / A, i%, N ) predetermined values are in column 4 of Appendix

C of textF = ?

1 2 3 4 5 6 7 8 A =

𝐹=𝐴 [ (1+𝑖 )𝑁−1𝑖 ]


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Example 4-7Future Value of College Degree

A recent government study reported that a college degree is worth an extra $23,000 per year income (A) compared to what a high school graduate makes. If the interest rate (i) is 6% per year and you work for 40 years (N). What is the future compound amount (F) of the extra income?


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Example 4-8Become a Millionaire by Saving $1.00 a Day!

If you are 20 years of age and save $1.00 each day for the rest of your life, you can become a millionaire.” Let us assume that you live to age 80 and that the annual interest rate is 10% (i = 10%). Compute the future compound amount.


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P = ?

1 2 3 4 5 6 7 8A =

Relating a Uniform Series (ordinary annuity) to present and future equivalent values

Finding P given A:Finding present equivalent value given a series of uniform equal receipts

• functionally expressed as P = A ( P / A, i%, N )• predetermined values are in column 5 of

Appendix C of text

𝑃=𝐴 [ (1+𝑖 )𝑁−1

𝑖 (1+𝑖 )𝑁 ]


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Example 4-9Present Equivalent of an Annuity (Uniform Series)

If a certain machine undergoes a major overhaul now, its output can be increased by 20% - which translates into additional cash flow of $20,000 at the end of each year for five years. If i=15% per year, how much can we afford to invest to overhaul this machine?


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Example 4-10How Much is a Lifetime Oil Change Offer Worth?

“Make your best deal with us on a new automobile and we’ll change your oil for free for as long as you own the car!” If you purchase a car from this dealership, you expect to have four free oil changes per year during the five years you keep the car. Each oil change would normally cost you $30. If you save your money in a mutual fund earning 2% per quarter, how much are the oil changes worth to you at the time you buy the car?


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F =

1 2 3 4 5 6 7 8 A =?

Relating a Uniform Series (Annuity) to Present and Future Equivalent Values

Finding A given F

Finding amount A of a uniform series when given the equivalent future value

– functionally expressed as A = F ( A / F, i%, N )– predetermined values are in column 6 of

Appendix C of text

𝐴=𝐹 [ 𝑖(1+𝑖 )𝑁−1 ]


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P =

1 2 3 4 5 6 7 8 A =?

Relating a Uniform Series (Annuity) to Present and Future Equivalent Values

Finding A given P:

Finding amount A of a uniform series when given the equivalent present value

– capital recovery factor in [ ]– functionally expressed as A = P ( A / P ,i% ,N )– predetermined values are in column 7 of Appendix

C of text

𝐴=𝑃 [ 𝑖 (1+𝑖 )𝑁

(1+𝑖 )𝑁−1 ]


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Example 4-11Computing Your Monthly Car Payment

You borrow $ 15,000 from your credit union to purchase a used car. The interest rate on your loan is 0.25% per month and you will make a total of 36 monthly payments. What is your monthly payment?


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Example 4-12Prepaying a Loan – Finding N

Your company has a $ 100,000 loan for a new security system it just bought. The annual payment is $8,880 and the interest rate is 8% per year for 30 years. Your company decides that it can afford to pay $10,000 per year. After how may payments (years) will the loan be paid off?


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Example 4-13Finding the Interest Rate to Meet an Investment Goal

After years of being a poor debt encumbered college student, you decide that you want to pay for four dream car in cash. Not having enough money now, you decide to specifically put money away each year in a “dream car” fund. The car you want to buy will cost $60,000 in eight years. You are going to put aside $6,000 each year (for eight years) to save for this. At what interest rate must you invest your money to achieve you goal of having enough to purchase the car after eight years?


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Example 4-14Present Equivalent of a Deferred Annuity

Suppose that a father, on the day his daughter is born, wishes to determine what lump amount would have to be paid into an account bearing interest of 12% per year to provide withdrawals of $2,000 on each of his daughter’s 18th, 19th, 20th, and 21st birthdays.


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Example 4-15Deferred Future Value of an Annuity

When you take your first job, you decide to start saving right away for your retirement. You put $5,000 per year into the company’s 401(k) plan, which averages 8% interest per year. Five years later, you move to another job and start a new 401(k). You never get around to your merging the funds in the two plans. If the first plan continued to earn interest at the rate of 8% per year for 35 years after you stopped making contributions, how much is the account worth?

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Multiple Interest FormulasExample 4-16: Calculating Equivalent P, F, and A Values

Figure 4.10 depicts an example problem with a series of year-end cash flows extending over eight years. The amounts are $100 for the first year, $200 for the second year, $500 for the third year, and $400 for each year from the fourth through the eighth. These could represent something like the expected maintenance expenditures for a certain piece of equipment or payments into a fund. Note that the payments are shown at the end of each year, which is a standard assumption (convention) for economic analyses in general, unless we have information to the contrary. It is desired to find thea. present equivalent expenditure, (this means, P0);b. future equivalent expenditure, (this means, F8);c. annual equivalent expenditure, (this means, A),of these cash flows if the annual interest rate is 20%. Solve by hand and by using a spreadsheet. . , Dr Mohammad Abuhaiba PE


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Multiple Interest FormulasExample 4-17: How Much Is That Payment?

In example 4-12, we looked at paying off a loan early by increasing the annual payment. The $100,000 loan was to be paid in 30 annual installments of $8,880 at an interest rate of 8% per year. As part of the example, we determined that the loan could be paid in full after 21 years if the annual payment was increased to $10,000.As with most real-life loans, the final payment will be something different (usually less) that the annuity amount. This is due to the effect of rounding in the interest calculations – you can’t pay in fractions of a cent! For this example, determine the amount of the 21st (and final) payment on the $100,000 loan when 20 payments of $10,000 have already been made. The interest rate remains at 8% per year.

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Multiple Interest FormulasExample 4-18: Equivalence Calculations Involving Unknown Quantities

Transform the cash flows on the left-hand side of figure 4-12 to their equivalent cash flow on the right-hand side. That is, take the left-hand quantities as given and determine the unknown value of Q in terms of H in figure 4-12. The interest rate is 10% per year.


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Multiple Interest FormulasExample 4-19: Determining an Unknown Annuity Amount

Two receipts of $1,000 each are desired at the EOYs 10 and 11.To make these receipts possible, four EOY annuity amounts will be deposited in a bank at EOYs 2, 3, 4 and 5. The bank’s interest rate (i) is 12% per year.a. Draw a cash flow diagram for this situation.b. Determine the value of A that establishes

equivalence in your cash flow diagram.c. Determine the lump-sum value at the end of

year 11 of the completed cash flow diagram based on your answers to part (a) and (b).



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Uniform (Arithmetic) Gradient of Cash Flows

1 2 3 4 N-2 N-1 N

G2G

3G

(N-3)G

(N-2)G(N-1)Gi = effective interest rate

per period

End of Period


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Uniform (Arithmetic) Gradient of Cash Flows Find P when given G: Find the present equivalent value when given the

uniform gradient amount

Functionally represented as P = G ( P / G, i%, N ) The value shown in { } is the gradient to present

equivalent conversion factor and is presented in column 8 of Appendix

𝑃=𝐺 {1𝑖 [ (1+𝑖 )𝑁−1

𝑖 (1+ 𝑖 )𝑁−

𝑁(1+ 𝑖 )𝑁 ]}


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Uniform (Arithmetic) Gradient of Cash Flows Find A when given G: Find the annual equivalent value when given the

uniform gradient amount

Functionally represented as A = G ( A / G, i%, N ) The value shown in [ ] is the gradient to uniform

series conversion factor and is presented in column 9 of Appendix C.

𝐴=𝐺[ 1𝑖 − 𝑁(1+ 𝑖 )𝑁−1 ]


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Uniform (Arithmetic) Gradient of Cash FlowsFind F when given G

Find the future equivalent value when given the uniform gradient amount

𝐹=𝐺𝑖 ( 𝐹𝐴 , 𝑖% ,𝑁 )− 𝑁𝐺𝑖


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Example 4-20Using the Gradient Conversion Factors to Find P and A

As an example of the straight forward use of the gradient conversion factors, suppose that certain EOY cash flows are expected to be $1,000 for the second year, $2,000 for the third year , and $3,000 for the fourth year and that, if interest is 15% per year, it is desired to finda. Present equivalent value at the beginning of

the first year,b. Uniform annual equivalent value at the end of

the four year.


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Example 4-21Present Equivalent of an Increasing Arithmetic Gradient Series

Suppose that we have cash flows as shown in the table below. Assume that we wish to calculate their present equivalent at I =15% per year, using gradient conversion factors.

End of year Cash flows ($)

1 5,000

2 6,0003 7,0004 8,000


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Example 4-22Present Equivalent of a Decreasing Arithmetic Gradient Series

For another example of the use of arithmetic gradient formulas suppose that we have cash flows that are timed in exact reverse of the situation depicted in example 4-21, the left hand diagram of figure 4-15 shows the following sequence of cash flows:

Calculate the present equivalent at i=15% per year, using arithmetic gradient interest factors.

End of year

Cash flows ($)

1 5,0002 6,0003 7,0004 8,000


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Geometric Sequence of Cash Flows Projected cash flow patterns changing at an

average rate of f each period; Resultant end-of-period cash-flow pattern is

referred to as a geometric gradient series; A1 is cash flow at end of period 1 Ak = Ak-1 ( 1 +f ), 2 < k < N AN = A1 ( 1 + f ) N-1

f = (Ak - A k-1 ) / A k-1 f may be either positive or negative


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0 1 2 3 4 N

A1

A2 =A1(1+f )

A3 =A1(1+f )2

AN =A1(1+f )N - 1

End of Period

Geometric Sequences of Cash Flows


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Geometric Sequences of Cash Flows

Find P when given A:

𝑃={𝐴1 ⌊1− (𝑃 /𝐹 , 𝑖% ,𝑁 ) (𝐹 /𝑃 , 𝑓 % ,𝑁 ) ⌋𝑖− 𝑓

𝑓 ≠ 𝑖

𝐴1𝑁 (𝑃 /𝐹 ,𝑖% ,1 ) 𝑓 =𝑖


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Example 4-23Equivalence Calculations for an Increasing Geometric Gradient Series

Consider the following EOY geometric sequence of cash flows and determine the P, A and F equivalent values. The rate of increase is 20% per year after the first year, and the interest rate is 25% per year.


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Example 4-24Equivalence Calculations for a Decreasing Geometric Gradient Series

Suppose that the geometric gradient in example 4-23 begins with $1,000 at EOY one and decrease by 20% per year after the first year. Determine P, A and F under this condition.


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Example 4-26A Retirement Savings Plan

On your 23rd birthday you decided to invest $4,500 (10% of your annual salary) in a mutual fund earning 7% per year. You will continue to make annual deposits equal to 10% of your annual salary until you retire at age 62 (40 years after you started your job). You expect your salary to increase by an average of 4% each year during this time. How much money will you have accumulated in your mutual fund when you retire?


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Interest Rates That Vary With Time

Find P given F

𝑃=𝐹𝑁

∏𝑘=1

𝑁

(1+𝑖𝑘)


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Example 4-27Compounding with Changing Interest Rates

Ashea smith is a 22-year old senior who used the Stafford loan program to borrow $4,000 four years ago when the interest rate was 4.06% per year. $5,000 was borrowed three years ago at 3.42%. Two years ago she borrowed $6,000 at 5.23%, and last year $7,000 was borrowed at 6.03% per year. Now she would like to consolidate her debt into a single 20-year loan with a 5% fixed annual interest rate. If Ashea makes annual payments (starting in one year) to repay her total debt, what is the amount of each payment?


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Nominal and Effective Interest Rates

Nominal Interest Rate , r: For rates compounded more frequently than one year, the stated annual interest rate.

Effective Interest Rate - i - For rates compounded more frequently than one year, the actual amount of interest paid.

M: number of compounding periods per year Annual Percentage Rate (APR): percentage rate per

period times number of periods.

APR = r x M

𝑖=(1+ 𝑟𝑀 )

𝑀


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Example 4-28Effective Annual Interest Rate

A credit card company charges an interest rate of 1.735% per month on the unpaid balance of all accounts. The annual interest rate they claim is 12(1.375% )= 16.5%. what is the effective rate of interest per year being charged by the company?


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Compounding More Often than Once per YearSingle Amounts Given nominal interest rate and total number of

compounding periods, P, F or A can be determined byF = P ( F / P, i%, N )i% = ( 1 + r / M ) M - 1

Uniform and / or Gradient Series Given nominal interest rate, total number of

compounding periods, and existence of a cash flow at the end of each period, P, F or A may be determined by the formulas and tables for uniform annual series and uniform gradient series.


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Example 4-29

Suppose that a $100 lump sum amount is invested for 10 years at a nominal interest rate of 6% compounded quarterly. How much is it worth at the end of the 10th rate?


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Example 4-30

Stan moneymaker has a bank loan for $10,000 to pay for his new truck. This loan is to be repaid in equal end-of-month installment for five years with a nominal interest rate of 12% compounded monthly. What is the amount of each payment?


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Example 4-31

Certain operating savings are expected to be 0 at the end of the first six months, to be $1,000 at the end of the second six months, and to increase by $1,000 at the end of each six-month period thereafter, for a total of four years. It is desired to find the equivalent uniform amount, A, at the end of each of the eight six-month periods if the nominal interest if the nominal interest rate is 20% compounded semiannually.


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Example 4-32

A loan of $15,000 requires monthly payments of $477 over a 36-month period of time. These payments include both principal and interest.a. What is the nominal interest rate (ARP) for

this loan?b. What is the effective interest rate per

year?c. Determine the amount of unpaid loan

principal after 20 months.


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Continuous Compounding and Discrete Cash Flows

Continuous compounding assumes cash flows occur at discrete intervals, but compounding is continuous throughout the interval.

i = e r - 1


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Continuous Compounding and Discrete Cash Flows - Single Cash Flow

Finding F given PF = P e rN

Functionally expressed as ( F / P, r%, N ) erN is continuous compounding

compound amount Predetermined values are in column 2 of

appendix D of text


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Continuous Compounding and Discrete Cash Flows - Single Cash Flow

Finding P given FP = F e-rN

Functionally expressed as ( P / F, r%, N ) e-rN is continuous compounding present

equivalent Predetermined values are in column 3 of

appendix D of text


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Continuous Compounding and Discrete Cash Flows - Uniform Series

Finding F given AF = A (erN- 1)/(er- 1)

Functionally expressed as ( F / A, r%, N ) (erN- 1)/(er- 1) is continuous

compounding compound amount Predetermined values are in column 4 of

appendix D of text


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Finding P given A

Functionally expressed as ( P / A, r%, N ) Predetermined values are in column 5 of

appendix D of text

𝑃=𝐴 𝑒𝑟𝑁−1

𝑒𝑟𝑁 (𝑒𝑟−1 )


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Finding A given F

Functionally expressed as ( A / F, r%, N ) Predetermined values are in column 6 of

appendix D of text

𝐴=𝐹 𝑒𝑟−1(𝑒𝑟 𝑁−1 )


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Finding A given P

Functionally expressed as ( A / P, r%, N ) Predetermined values are in column 7 of

appendix D of text

𝐴=𝑃𝑒𝑟𝑁 (𝑒𝑟−1 )𝑒𝑟𝑁−1


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Example 4-33

You have a $10,000 to invest for two years. Your bank offers 5% interest, compounded continuously for funds in a money market account, assuming no additional deposits or withdrawals , how much money will be in that account at the end of the two years?


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Example 4-34

Suppose that one has a present loan of $1,000 and desires to determine what equivalent uniform EOY payments, A, could be obtained from it for 10 years if the nominal interest rate is 20% compounded continuously (M = infinity )


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Example 4-35

An individual need $12,000 immediately as a down payment on a new home suppose that he can borrow this money from his insurance company, he must repay the loan in equal payments every six months over the next eight years. The nominal interest rate being charges is 7% compounded continuously. What is the amount if each payment?


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Home Work Assignment HW: 1, 7, 13, 21, 28, 34, 40, 49, 55, 60,

66, 72, 79, 83, 89, 96, 103, 110, 116, 122

Case Study: Resolve case study on page 171 (section

4.17) Solve case studies: 4-133, 4-134, 4-135

Case study and HW are due on Wednesday 19/10/2011

CHAPTER 4 The Time Value of Money Dr. Mohammad Abuhaiba, PE 1.

Documents

mohammad abuhaiba

period n

end of period

time value of money

period cash flows

time periods

period g

rate amounts of money