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Chapter 3 Limits and the Derivative Section 7 Marginal Analysis in Business and Economics
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Chapter 3 Limits and the Derivative

Jan 03, 2016

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Chapter 3 Limits and the Derivative. Section 7 Marginal Analysis in Business and Economics. Objectives for Section 3.7 Marginal Analysis. The student will be able to compute: Marginal cost, revenue and profit Marginal average cost, revenue and profit - PowerPoint PPT Presentation
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Page 1: Chapter 3 Limits and the Derivative

Chapter 3

Limits and the Derivative

Section 7

Marginal Analysis in Business and Economics

Page 2: Chapter 3 Limits and the Derivative

2

Objectives for Section 3.7 Marginal Analysis

The student will be able to compute:

■ Marginal cost, revenue and profit

■ Marginal average cost, revenue and profit

■ The student will be able to solve applications

Page 3: Chapter 3 Limits and the Derivative

3Barnett/Ziegler/Byleen Business Calculus 12e

Marginal Cost

Remember that marginal refers to an instantaneous rate of change, that is, a derivative.

Definition:

If x is the number of units of a product produced in some time interval, then

Total cost = C(x)

Marginal cost = C(x)

Page 4: Chapter 3 Limits and the Derivative

4

Marginal Revenue andMarginal Profit

Definition:If x is the number of units of a product sold in some time interval, then

Total revenue = R(x) Marginal revenue = R(x)

If x is the number of units of a product produced and sold in some time interval, then

Total profit = P(x) = R(x) – C(x)Marginal profit = P(x) = R(x) – C(x)

Page 5: Chapter 3 Limits and the Derivative

5

Marginal Cost and Exact Cost

Assume C(x) is the total cost of producing x items. Then the exact cost of producing the (x + 1)st item is

C(x + 1) – C(x).

The marginal cost is an approximation of the exact cost.

C(x) ≈ C(x + 1) – C(x).

Similar statements are true for revenue and profit.

Page 6: Chapter 3 Limits and the Derivative

6

Example 1

The total cost of producing x electric guitars is C(x) = 1,000 + 100x – 0.25x2.

1. Find the exact cost of producing the 51st guitar.

2. Use the marginal cost to approximate the cost of producing the 51st guitar.

Page 7: Chapter 3 Limits and the Derivative

7

Example 1(continued)

The total cost of producing x electric guitars is C(x) = 1,000 + 100x – 0.25x2.

1. Find the exact cost of producing the 51st guitar.

The exact cost is C(x + 1) – C(x).

C(51) – C(50) = 5,449.75 – 5375 = $74.75.

2. Use the marginal cost to approximate the cost of producing the 51st guitar.

The marginal cost is C(x) = 100 – 0.5x

C(50) = $75.

Page 8: Chapter 3 Limits and the Derivative

8

Marginal Average Cost

Definition:

If x is the number of units of a product produced in some time interval, then

Average cost per unit =

Marginal average cost =

x

xCxC

)()(

C (x)

d

dxC (x)

Page 9: Chapter 3 Limits and the Derivative

9

If x is the number of units of a product sold in some time interval, then

Average revenue per unit =

Marginal average revenue =

If x is the number of units of a product produced and sold in some time interval, then

Average profit per unit =

Marginal average profit =

Marginal Average Revenue Marginal Average Profit

x

xRxR

)()(

R (x)

d

dxR (x)

x

xPxP

)()(

P (x)

d

dxP(x)

Page 10: Chapter 3 Limits and the Derivative

10Barnett/Ziegler/Byleen Business Calculus 12e

Warning!

To calculate the marginal averages you must calculate the average first (divide by x), and then the derivative. If you change this order you will get no useful economic interpretations.

STOP

Page 11: Chapter 3 Limits and the Derivative

11

Example 2

The total cost of printing x dictionaries is

C(x) = 20,000 + 10x

1. Find the average cost per unit if 1,000 dictionaries are produced.

Page 12: Chapter 3 Limits and the Derivative

12

Example 2(continued)

The total cost of printing x dictionaries is

C(x) = 20,000 + 10x

1. Find the average cost per unit if 1,000 dictionaries are produced.

= $30

x

xCxC

)()(

)000,1(C000,1

000,10000,20

x

x10000,20

Page 13: Chapter 3 Limits and the Derivative

13

Example 2(continued)

2. Find the marginal average cost at a production level of 1,000 dictionaries, and interpret the results.

Page 14: Chapter 3 Limits and the Derivative

14

Example 2(continued)

2. Find the marginal average cost at a production level of 1,000 dictionaries, and interpret the results.

Marginal average cost =

2

20000

x

This means that if you raise production from 1,000 to 1,001 dictionaries, the price per book will fall approximately 2 cents.

C (x)

d

dxC (x)

C (x)

d

dx

20000 10 x

x

C (1000)

20000

10002 0.02

Page 15: Chapter 3 Limits and the Derivative

15

Example 2(continued)

3. Use the results from above to estimate the average cost per dictionary if 1,001 dictionaries are produced.

Page 16: Chapter 3 Limits and the Derivative

16

Example 2(continued)

3. Use the results from above to estimate the average cost per dictionary if 1,001 dictionaries are produced.

Average cost for 1000 dictionaries = $30.00Marginal average cost = - 0.02

The average cost per dictionary for 1001 dictionaries would be the average for 1000, plus the marginal average cost, or

$30.00 + $(- 0.02) = $29.98

Page 17: Chapter 3 Limits and the Derivative

17

The price-demand equation and the cost function for the production of television sets are given by

where x is the number of sets that can be sold at a price of $p per set, and C(x) is the total cost of producing x sets.

1. Find the marginal cost.

Example 3

xxCx

xp 30000,150)(and30

300)(

Page 18: Chapter 3 Limits and the Derivative

18

The price-demand equation and the cost function for the production of television sets are given by

where x is the number of sets that can be sold at a price of $p per set, and C(x) is the total cost of producing x sets.

1. Find the marginal cost.

Solution: The marginal cost is C(x) = $30.

Example 3(continued)

xxCx

xp 30000,150)(and30

300)(

Page 19: Chapter 3 Limits and the Derivative

19

2. Find the revenue function in terms of x.

Example 3(continued)

Page 20: Chapter 3 Limits and the Derivative

20

2. Find the revenue function in terms of x.

The revenue function is

3. Find the marginal revenue.

Example 3(continued)

30300)()(

2xxxpxxR

Page 21: Chapter 3 Limits and the Derivative

21

2. Find the revenue function in terms of x.

The revenue function is

3. Find the marginal revenue.

The marginal revenue is

4. Find R(1500) and interpret the results.

Example 3(continued)

30300)()(

2xxxpxxR

R (x) 300

x

15

Page 22: Chapter 3 Limits and the Derivative

22

2. Find the revenue function in terms of x.

The revenue function is

3. Find the marginal revenue.

The marginal revenue is

4. Find R(1500) and interpret the results.

At a production rate of 1,500, each additional set increases revenue by approximately $200.

Example 3(continued)

30300)()(

2xxxpxxR

R (x) 300

x

15

R (1500) 300

1500

15$200

Page 23: Chapter 3 Limits and the Derivative

23

Example 3(continued)

5. Graph the cost function and the revenue function on the same coordinate. Find the break-even point.

0 < y < 700,000

0 < x < 9,000

Page 24: Chapter 3 Limits and the Derivative

24

Example 3(continued)

5. Graph the cost function and the revenue function on the same coordinate. Find the break-even point.

0 < y < 700,000

0 < x < 9,000

(600,168,000)(7500, 375,000)

Solution: There are two break-even points.

C(x)

R(x)

Page 25: Chapter 3 Limits and the Derivative

25

6. Find the profit function in terms of x.

Example 3(continued)

Page 26: Chapter 3 Limits and the Derivative

26

6. Find the profit function in terms of x.

The profit is revenue minus cost, so

7. Find the marginal profit.

Example 3(continued)

15000027030

)(2

xx

xP

Page 27: Chapter 3 Limits and the Derivative

27

6. Find the profit function in terms of x.

The profit is revenue minus cost, so

7. Find the marginal profit.

8. Find P(1500) and interpret the results.

Example 3(continued)

P(x)

x2

30 270x 150000

P (x) 270

x

15

Page 28: Chapter 3 Limits and the Derivative

28

6. Find the profit function in terms of x.

The profit is revenue minus cost, so

7. Find the marginal profit.

8. Find P’(1500) and interpret the results.

At a production level of 1500 sets, profit is increasing at a rate of about $170 per set.

Example 3(continued)

15000027030

)(2

xx

xP

P (x) 270

x

15

P (1500) 270

1500

15170