FLUID MECHANICS Chapter 14 1 st semester, AY 2009-2010
FLUID MECHANICS
Chapter 14Chapter 14 1st semester, AY 2009-20101st semester, AY 2009-2010
Chapter 14Chapter 14 Classification of matter 2Classification of matter 2
• Solids– tightly packed, usually in a regular pattern– retains a fixed volume and shape – not easily compressible – doesn’t easily flow
Liquids close together with no regular arrangement assumes the shape of the part of the container
which it occupies not easily compressible, flow easilyflow easily
Gas well separated with no regular arrangement assumes the shape of the part of the container easily compressible, flow easilyflow easily
Images from:http://www.chem.purdue.edu/gchelp/liquids/character.html
Chapter 14Chapter 14 What’s in store for us? 3What’s in store for us? 3
Fluid statics
• Density
• Pressure
• Buoyancy
Fluid dynamics
• Continuity equation
• Bernoulli’s equation
Chapter 14Chapter 14 Properties of fluids 4Properties of fluids 4
Density
M
V
Units :
1 kg/m3 = 10-3 g/cm3
Material Density, kg/m3
Air (1 atm, 200 C) 1.21
Water 0.998 x 103
Ice 0.917 x 103
Blood 1.060 x 103
Seawater 1.024 x 103
Styrofoam 1 x 102
Gold 19.3 x 103
• Density may vary from point to point
• Higher ρ sinks under lower ρ
• Solids and liquids: ρ independent of T & P
Gases: strongly dependent on T & P
Chapter 14Chapter 14 Properties of fluids 5Properties of fluids 5
Specific gravity/relative density
water
materialSG
• Specific gravity is dimensionless.
• ρ > 1 object sinks under water
ρ < 1 object floats over water
Chapter 14Chapter 14 Properties of fluids 6Properties of fluids 6
Pressure
A
Fp
Useful Units :
1 Pa = 1 N/m2
1 atm = 101 325 Pa = 760 Torr =1013 mbar
• Fluid exerts a force at each point on the surface of an object in
contact with it.
• Force is perpendicular to the object surface
• Pressure has no preferred direction (scalar)
Chapter 14Chapter 14 Fluid pressure 7Fluid pressure 7
At equilibrium, the pressure in a fluid of uniform density depends depends only on the depthonly on the depth, NOT THE SHAPE, of the container.
ghpp 0
p = pressure at a some depth h
po = pressure at the surface (or the atmosphere)
= density of the fluid
gh = gauge pressure
* With the assumption that g is uniform all throughout the fluid.
• Pressure below > Pressure above
• Pressure is the same at all points at the same depth of the fluid.
Chapter 14Chapter 14 Fluid pressure 8Fluid pressure 8
For a homogeneoushomogeneous fluid in an open container, the pressure is the same at a given depth independent of the container’s shape.
p(y)
y
Differences in fluid pressure at the same elevation will arise only if the densities are different.
Chapter 14Chapter 14 Fluid pressure 9Fluid pressure 9
Examples:• Ear-popping
• SCUBA
• Using a sphygmomanometer
• Bath tub vs. Pitcher
Chapter 14Chapter 14 Fluid pressure 11Fluid pressure 11
Example:• A U tube contain immiscible liquids of
density 1 and 2. Compare the densities of the liquids.
1
2
d
dhgpp 10
At the bottom, both liquids have the same pressure.At the top, both are in equilibrium with the atmosphere.At the interface, both have the same pressure as well.So from the Pressure-Depth relation:
ghpp 20
h
dhgpghp 1020
dhh 12 12 h
dh 12
hdh
Chapter 14Chapter 14 Fluid pressure variation w/ altitude 12Fluid pressure variation w/ altitude 12
WHY?(i) The gravitational force on air
molecules is greater for those near the earth’s surface, dragging them closer together and increasing the pressure between them.
(ii) Molecules further away from the earth have less weight but exert compressive force on those below them. In turn, those lower down have to support more molecules above them and are further compressed in the process.
o
o
g
hp
epp
0
Mt. Everest
Commercial jet cruising altitude
Chapter 14Chapter 14 Fluid pressure 13Fluid pressure 13
Problem set 11.1:(a) What water pressure would a diver experience at a depth of 200
m? Express your answer in atmospheres.
(b) Find the total weight of water on top of a nuclear submarine at this depth, assuming that its horizontal cross-sectional hull area is 3000 m2.
(Assume that the density of sea water is 1.03 g/cm3)
(a) What water pressure would a diver experience at a depth of 200 m? Express your answer in atmospheres.
(b) Find the total weight of water on top of a nuclear submarine at this depth, assuming that its horizontal cross-sectional hull area is 3000 m2.
(Assume that the density of sea water is 1.03 g/cm3)
Chapter 14Chapter 14 Pressure applied to fluid 14Pressure applied to fluid 14
Pascal’s Principle
“PPressure applied to an enclosed fluid is transmitted
undiminished to every portion of the fluid and to the walls of the
containing vessel.”
By adding more weight at the top, the pressure also increases proportionally within the fluid.
Chapter 14Chapter 14 Pascal’s principle 15Pascal’s principle 15
Applications:• Heimlich maneuver
• Squeezing the end of toothpaste tube
• Hydraulic lift
Chapter 14Chapter 14 Pascal’s principle 16Pascal’s principle 16
Application: Hydraulic lift
Small applied force, F1
A1
1
1
A
Fp
p is transmitted through the larger piston
11
22 F
A
AF
Larger than F1
2
2
A
Fp
1
1
A
F
Chapter 14Chapter 14 Pascal’s principle 17Pascal’s principle 17
Example:
A1A2 = 20m2
200 kg40 kg
Chapter 14Chapter 14 Measuring pressure 18Measuring pressure 18
Pressure measurements are always done with respect to the pressure of the surroundings.
atmabsolutegauge PPP
Pabsolute = total pressure
Patm = atmospheric pressure
Pgauge = pressure excess of atmospeheric
Chapter 14Chapter 14 Measuring pressure 19Measuring pressure 19
Open-tube manometer• Measures gauge pressure directly
21 gyPgyP atm
ghyygPP atm )( 12
ghPgauge
Chapter 14Chapter 14 Measuring pressure 20Measuring pressure 20
Example:A manometer tube is partially filled with mercury. Water is then
poured into the left arm of the tube until the mercury-water interface is at the midpoint. Both arms of the tube are open to air. Find the relationship between hH2O and hmercury.
hH2O hmercury
Chapter 14Chapter 14 Measuring pressure 21Measuring pressure 21
Example:A barrel contains a 0.120 m-layer of oil floating on water that is 0.250 m-deep. The density of the oil is 600 kg/m3.
(a)What are the gauge and absolute pressures at the oil-water interface?
(b)What are the gauge and absolute pressures at the bottom of the barrel?
Chapter 14Chapter 14 Properties of fluids 22Properties of fluids 22
Buoyancy• Apparent weight loss of an object when totally/partially
immersed in a fluid
FB
Lower Pressure
Higher Pressure
mg
Chapter 14Chapter 14 Buoyancy 23Buoyancy 23
Archimedes’ Principle
““WWhen a body is fully or partially submerged in a fluid, a hen a body is fully or partially submerged in a fluid, a buoyant force from the surrounding fluid acts on the buoyant force from the surrounding fluid acts on the body.” body.”
““TThe buoyant force is directed he buoyant force is directed UPWARDUPWARD and has a and has a magnitude equal to the magnitude equal to the WEIGHTWEIGHT of the of the displaced FLUIDdisplaced FLUID by the body.”by the body.”
• The line of action of FB passes through the CoG of the displaced fluid, which doesn’t necessarily coincide with the CoG of the submerged object
Chapter 14Chapter 14 Buoyancy 24Buoyancy 24
Example: Compare the magnitude of tension on the string for the three cases.
A B C
m
m
m
ρf
Chapter 14Chapter 14 Buoyancy 25Buoyancy 25
Question:Based on the summation of forces, therefore, what makes an object sink, float or hover?
Sink(accelerate downwards)
Float(accelerate upwards)
Hover(stay at the same level)
objB WF
objB WF
objB WF
objf
objf
objf
Chapter 14Chapter 14 Buoyancy 26Buoyancy 26
Examples:• Fishes and their air sacs
• Life vests
• Ice cubes
• Boats/ships
Chapter 14Chapter 14 Buoyancy 27Buoyancy 27
Example:What fraction of the iceberg afloat in seawater is visible from
the surface?
VVicebergiceberg = total volume of iceberg = total volume of iceberg
VVfluid,disp.fluid,disp. = equal to the submerged portion of the iceberg = equal to the submerged portion of the iceberg
= V= Vsubsub
Chapter 14Chapter 14 Buoyancy 28Buoyancy 28
Example:You have found a treasure chest afloat
at sea! To keep it, though, from other
pirates coming your way, you jumped on
the water and stood on top of the chest.
What should your mass be to be able
to keep the chest totally submerged
in water while keeping you afloat?
Chapter 14Chapter 14 Buoyancy 29Buoyancy 29
Problem set 11.2:Three children, each of weight 36 kg, make a log raft by lashing together logs of diameter 0.3 m and length 1.8 m. How many logs will be needed to keep them afloat? Consider the density of wood to be 842 kg/m3.
Density of water = 1 x 103 kg/m3
Minimum requirement is for the logs to be completely submerged, but the children standing on them are not.
Chapter 14Chapter 14 What’s in store for us? 30
What’s in store for us? 30
Fluid dynamics• We will only consider fluids that are:
• Non-viscous
(no internal friction)
• Incompressible
(constant density)
• Steady/ non-turbulent
(P, V and flow velocity are
constant in time)
Chapter 14Chapter 14 Fluid dynamics 31Fluid dynamics 31
Continuity equationIdeal fluids obey continuity equation. Ideal fluids obey continuity equation. Conservation of Mass: “What goes in comes out”Conservation of Mass: “What goes in comes out”
222111 vAvA (Mass Flux of (Mass Flux of Compressible Fluids)Compressible Fluids)
2211 vAvA (Incompressible Fluids)(Incompressible Fluids)
21
21 v
A
Av
The narrower the The narrower the constriction (area), the constriction (area), the
faster a fluid flows through faster a fluid flows through it!it!
Volume Volume flow rateflow rate
Chapter 14Chapter 14 Continuity equation 32Continuity equation 32
Examples:• “ Still waters run deep”
• Necking down of water from faucets
• A housing contractor saves some money by reducing the size of a
pipe from 1” diameter to 1/2” diameter at some point in your
house.
Assuming the water moving in the pipe is an ideal fluid (incompressible),
relative to its speed in the 1” diameter pipe, how fast is the water going in
the 1/2” pipe? v1 v1/2
Chapter 14Chapter 14 Fluid dynamics 33Fluid dynamics 33
Bernoulli’s equationAn ideal fluid flowing through a pipe may change its motion
depending on the:(i) cross-section area of the pipe, (ii) elevation of the inlet and outlet, and
(iii) variation in pressure between inlet and outlet
y1
y2
A1
A2v1
v2
P1, V1
P2, V2
Chapter 14Chapter 14 Bernoulli’s equation 34Bernoulli’s equation 34
Based on Energy Conservation:Based on Energy Conservation:
22222211
211 2
1
2
11
gyvpgyvp
constant2
1 2 gyvp (For ideal (incompressible) fluid)
Chapter 14Chapter 14 Bernoulli’s equation 35Bernoulli’s equation 35
Case 1. Static pressure: No flow (but with elevation change)Case 1. Static pressure: No flow (but with elevation change)
22221
211 2
1
2
1gyvpgyvp
1212 yygpp
Same with what we have derived before for static fluid.Same with what we have derived before for static fluid.
i.e. since the pressure at a higher elevation yi.e. since the pressure at a higher elevation y22 is less than is less than
at lower depth yat lower depth y11
=0
Chapter 14Chapter 14 Bernoulli’s equation 36Bernoulli’s equation 36
Case 2. Dynamic pressure: with flow (but no elevation change)Case 2. Dynamic pressure: with flow (but no elevation change)
22221
211 2
1
2
1gyvpgyvp
Implication: Implication: Where the Where the SPEEDSPEED is is LARGELARGE, the , the PRESSUREPRESSURE must be must be SMALLSMALL!!!!!!
222
211 2
1
2
1vpvp
y2 – y1 =0
Chapter 14Chapter 14 Bernoulli’s equation 37Bernoulli’s equation 37
Examples:• Blowing on top of paper
• Roofs flying off houses during storms
• MRT’s yellow line
• Airplane wings
higher velocity lower pressure
lower velocityhigher pressure
Chapter 14Chapter 14 Bernoulli’s equation 38Bernoulli’s equation 38
Example:
A B C D
Vol flow rate, y, ρ, g
Cross-sectional area
Speed
Pressure
DCBA DCAB
BCAD
DCAB
Chapter 14Chapter 14 Bernoulli’s equation 40Bernoulli’s equation 40
Example:Water circulates throughout a house in a hot-water heating system. If water is pumped out at a speed of 0.50 m/s through a 4.0 cm diameter pipe in the basement under a pressure of 3.0 atm, what will be the flow speed and flow speed and pressure pressure in a 2.6 cm diameter pipe on the second floor 5.0 m above assuming that the pipes do not divide into branches.
Chapter 14Chapter 14 Bernoulli’s equation 41Bernoulli’s equation 41
Problem set 12.1:A large tank of water has a small hole a distance h below the water surface. Find the speed of the water as it flows out of the hole.
h
yB
yA
Hints:
Cross-sectional area of the flow tube at A << area at B
Velocity at A is negligible
A
B