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Chapter 13 States of Matter
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Chapter 13

Dec 31, 2015

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Chapter 13. States of Matter. 13.1- Properties of Fluids. Fluids - liquids and gases; materials that flow and have no definite shapes of their own *For now imagine these are ideal Particles take up no space Particles have no intermolecular attractive forces. Pressure in Fluids. - PowerPoint PPT Presentation
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Page 1: Chapter 13

Chapter 13

States of Matter

Page 2: Chapter 13

13.1- Properties of Fluids

• Fluids- liquids and gases; materials that flow and have no definite shapes of their own

*For now imagine these are ideal– Particles take up no space– Particles have no intermolecular attractive forces

Page 3: Chapter 13

Pressure in Fluids

• Pressure- the force on a surface divided by the area of the surface

• P=F/A

• Anything that exerts pressure is capable of producing change and doing work.

• Pascal (Pa)- 1N/m2

Page 4: Chapter 13

Solids, Liquids, and Pressure

Page 5: Chapter 13

Gas Particles and Pressure

Page 6: Chapter 13

Atmospheric Pressure

• On every square centimenter of Earth’s surface at sea level, the atmospheric gas exerts a force of approximately 10 N, about the weight of a 1 kg object.

• Why don’t we “feel” this pressure?

• When might we “feel” this pressure?

Page 7: Chapter 13
Page 8: Chapter 13

The Gas Laws

• Boyle’s Law- P1V1=P2V2

(Pressure must be in kPa)

• Charles’s Law- V1/T1=V2/T2

(Volume must be in Liters)• Combined Gas Law- P1V1/T1=P2V2/T2

(Temperature must be in Kelvins)• Ideal Gas Law- PV=nRT

Page 9: Chapter 13

Ideal Gas Law

• PV=nRT– P is pressure in _______________– V is volume in _______________– n= number of moles of the substance

• 1 mole= _______________ particles (Avagadro’s Number)

– R= 8.31 Pa m3/mol K– T= temperature in _______________

Does not work well with high pressures or low temperatures

Page 10: Chapter 13

• The pressure on a can of soda is 375 kPa and the volume is 20.8 L. What would the new volume be if the pressure increased to 480 kPa?

• Do pressure and volume have a direct or inverse relationship?

Page 11: Chapter 13

• If a Balloon has a volume of 20.0 L at a temperature of 27.2 oC what will be the new volume if the temperature decreases to 0.00 oC?

• Do volume and temperature have a direct or inverse relationship?

Page 12: Chapter 13

Thermal Expansion

• Hot items become less dense and fill up more space- They will _______________

• Cold items become more dense and take up less space- They will _______________

Page 13: Chapter 13

Plasma

• Gas-like state of negatively charged and positively charged ions– Found in stars, lightning, and neon signs

Page 14: Chapter 13

13.2- Forces within Liquid

• Surface Tension- tendency of the surface of a liquid to contract to the smallest possible area

• Cohesive Forces- attraction between like molecules

Page 15: Chapter 13

Viscosity

• Ability to resist flow

Maple syrup vs Kool-Aid

Water vs Honey

Rubbing Alcohol vs Ketchup

Page 16: Chapter 13

Adhesive Forces

• Electromagnetic attractive forces that act between particles of different substances

• Capillary Action- liquid rising due to adhesive forces– Water in Tube– Wax on Wick of Candle– Water in Soil and Roots

Page 17: Chapter 13

Evaporation and Condensation

• Evaporation- escape of the most energetic particles of a liquid to a gas; Leaves liquid with less KE so temperature will _______________.

• Condensation- loss of energy causing particles of gas to convert to liquid

Page 18: Chapter 13

Isopropyl ( ) Methyl( ) Ethyl( )

Page 19: Chapter 13

+ Δ

• Easy to follow• Fun!• Hands On• Visualize what we talk

about in class!

• Go over more questions together

• Some questions are confusing

• Long questions• Goggles

Page 20: Chapter 13

13.3- Fluids at Rest and in Motion

• Pascal’s Prinicple- any change in pressure applied at any point on a confined fluid is transmitted undiminished throughout a fluid– Example: Squeezing a tube of toothpaste

• F1A1=F2A2

• Pascal's Principle

Page 21: Chapter 13

Swimming Under Pressure

• The pressure of the water is equal to the weight of the water directly above the object divided by the cross sectional area of the column above the object

Page 22: Chapter 13

• P=Fg/A• Density=mass/volume• Volume=length x width x height• Area=length x width• Force=mass x acceleration

Use these formulas to derive P=phg from P=Fg/A

(5 minutes: YOU CAN DO IT!!!)

Page 23: Chapter 13

• P=F/A• P=ma/A• P=ρVg/A• P=ρhAg/A• P=ρhg

The pressure that a column of water exerts on a body is equal to the density of water times the height of the column times the acceleration due to gravity.

Page 24: Chapter 13

Buoyancy

• Archimedes Principle and Buoyant Force

• Buoyant force- the increase in pressure with increasing depth creates this upward force

• To see if an object will float compare downward force to upward force– Ptop=Ftop/Atop=ρhgA

– Pbottom=Fbottom/Abottom=ρ(l+h)gA

– Fbuoyant=Fbottom-Ftop=ρlga=ρfluidVg

Page 25: Chapter 13

Fbuoyant=Fbottom-Ftop=ρlga=ρfluidVg

• The buoyant force on an object is equal to the weight of the fluid displaced by the object, which is equal to the density of the fluid in which the object is immersed multiplied by the object’s volume and the acceleration due to gravity.

Page 26: Chapter 13

Archimedes' Principle

• An object immersed in a fluid has an upward force on it that is equal to the weight of the fluid displaced by the object.

Page 27: Chapter 13

Sink or Float?

• All objects in a liquid, even those that sink, have an apparent weight that is less than when the object is in air.

• Fapparent= Fg- Fbuoyant

Page 28: Chapter 13