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Chapter 12 Universal Law of Gravity
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Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Jan 03, 2016

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Page 1: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Chapter 12

Universal Law of Gravity

Page 2: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Chapter 12: Universal Gravitation

• The earth exerts a gravitational force mg on a mass m.• By the action-reaction law, the mass m exerts a force

mg on the earth.• By symmetry, since the force mg is proportional to the

mass m, the value of g must also be proportional to the mass M of the earth.

• Isaac Newton realized that the motion of projectiles near the earth, the moon around the earth, the planets around the sun,… could be described by a universal law of gravitation

Page 3: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Gravity

If two particles of mass m1 and m2 are separated by a distance r, then the magnitude of the gravitational force is:

G is a constant = 6.67 10-11 N·m2/kg2

221

r

mmGF

The force is attractive:

The direction of the force on one mass is toward the other mass.

Page 4: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

The gravitational force varies like 1/r2. It decreases rapidly as r increases, but it never goes to zero.

Example: The gravitational force between two masses is 10-10 N when they are separated by 6 m. If the distance between the two masses is decreased to 3 m, what is the gravitational force between them?

Page 5: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Gravitational Attraction of Spherical Bodies

If you have an extended object, it behaves as if all of its mass is at the center of mass. Therefore, to calculate the gravitational force between two objects, use the distance between their centers of mass.

Gravitational force between the Earth and the moon.

Page 6: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Gravitation of finite objects

Newton invented Differential Calculus to interpret his theory: F = ma

Newton invented Integral Calculus to prove that the gravitational force of the earth and motion of the moon is the same as if the earth and moon were each concentrated in a single point.

Page 7: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

ExampleCalculate the gravitational force between a 70 kg man and the Earth.

F = m g = (70 kg) (9.8 m/s2) = 686 N, but

226

24

2

211

2

2

81.91037.6

1097.51067.6

s

m

m

kg

kg

mN

R

GMg

mgR

GMmF

E

E

Page 8: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Variation of g with height

The gravitational force between the Earth and the space shuttle in orbit is almost the same as when the shuttle is on the ground.

2)(

hR

GMhg

E

Page 9: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Kepler’s Laws of Orbital Motion

1. Objects follow elliptical orbits, with the mass being orbited at one focus of the ellipse.

A circle is just a special case of an ellipse.

Page 10: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Kepler’s Laws (cont.)

2. As an object moves in its orbit, it sweeps out an equal amount of area in an equal amount of time.

This law is just conservation of angular momentum. Gravity does not exert a torque on the planet Why?

perigee apogee

Page 11: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Kepler’s Laws (cont.)

3. The period of an object’s orbit, T, is proportional to the 3/2 power of its average distance from the thing it is orbiting, r:

2/32r

GMT

Note: M is the mass that is being orbited. The period does not depend on the mass of the orbiting object.

Page 12: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Example1. The space shuttle orbits the Earth with a period of about 90 min. Find the average distance of the shuttle above the Earth’s surface.answer: 6.65E6 m

Page 13: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Gravitational Potential Energy

The gravitational potential energy of a pair of objects is:

rmm

GU 21

The formula we have used in the past, U = mgy, is valid only near the surface of the Earth (and has a different location for U=0).

When we deal with astronomical objects, we usually choose U = 0 when two objects are infinitely far away from each other. In this case, gravitational potential energy is negative.

Page 14: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Escape SpeedWe can use conservation of energy to calculate the speed with which an object must be launched from Earth in order to entirely escape the Earth’s gravitational field.

Initially, the object has kinetic (velocity v) and potential energy. In order to escape, the object must have just enough energy to reach infinity with no speed left. In this case, M = mass of Earth and R = radius of Earth.

m/s200,11

2

00

2

221

vR

GMv

RmM

Gmv

UKUK

EE

ffii

fi

Page 15: Chapter 12 Universal Law of Gravity. Chapter 12: Universal Gravitation The earth exerts a gravitational force mg on a mass m. By the action-reaction law,

Example A satellite is orbiting the Earth as shown below. At

what part of the orbit, if any, are the following quantities largest?

(a) Kinetic energy

(b) Potential energy

(c) Total energy

(d) Velocity

(e) Gravitational force

(f) Centripetal acceleration

(g) Momentum

A B