Daniel L. Reger Scott R. Goode David W. Ball http://academic.cengage.com/chemistry/reger Chapter 12 Solutions
Jan 03, 2016
Daniel L. RegerScott R. GoodeDavid W. Ball
http://academic.cengage.com/chemistry/reger
Chapter 12Solutions
• There are a number of ways to express concentration. You have seen:• molarity;• mole fraction;• mass percentage:• for expressing the composition of a compound;• and can be used for solutions, as well.
• normality
Solution Concentration
• All concentration units are fractions.• The numerator contains the quantity of
solute.• The denominator is the quantity of either
solution or solvent.
• They differ in the units used to express these two quantities.
Solution Concentration
Units of Concentration Used Earlier
solution of liters
solute of moles
4) (ChapterMolarity
M
C... mol B mol A mol
Amol
6) (Chapter fraction Mole
Aχ
Mass Percent Composition
%100solution grams
solute gramspercent mass
• A solution is prepared by dissolving 3.00 g of NaCl (molar mass = 58.44 g/mol) in 150 g of water. Express its concentration as mass percent.
Example: Percent Composition
Molality• Molality (m or molal) is defined as
solvent of kilograms
solute of moles molality
Example: Calculate Molality
• What is the molality of a solution prepared by dissolving 3.00 g NaCl (molar mass = 58.44 g/mol) in 150 g of water?
• Express the concentration of a 3.00% H2O2 solution as
(a) molality;
(b) mole fraction.
Example: Concentration Conversion
Test Your Skill
• Calculate (a) the molality, and (b) the mole fraction of alcohol (C2H5OH; molar mass = 46.07 g/mol) in a wine that has an alcohol concentration of 7.50 mass percent.
• Conversion of most concentration units to molarity usually involve using the density of the solution to convert units of mass to units of volume.• The density of a 12.0% sulfuric acid
(H2SO4; molar mass = 98.08 g/mol) is 1.080 g/mL. What is the molarity of this solution?
Example: Conversion to Molarity
• For most substances, there is a limit to the quantity of solute that dissolves in a specific quantity of solvent.• A dynamic equilibrium exists between the
solute particles in solution and the undissolved solute.
Principles of Solubility
Normality• Normality, (N) is defined as the number of equivalents per
liter of solution.• Problem – what are equivalents – depends on reaction• Not used very often
• One place that normality is sometimes encountered is with acid-base chemistry.
• How many protons are release by an acid defines the equivalents• EX:• HCl – releases 1 H+ so… 1M = 1N
• H2SO4 – releases 2H+ so… 1M = 2N
• We will not be using normality, but you might encounter it in other chemistry classes!!
• Solubility is the concentration of solute that exists in equilibrium with an excess of that substance.• A saturated solution has a
concentration of solute equal to its solubility.
Definitions
Definitions (continued)• An unsaturated solution is one that has a solute concentration less than
the solubility.• A supersaturated solution is one with a solute concentration that is greater
than the solubility.• Supersaturation is an unstable condition.
• Many spontaneous processes are exothermic.• Enthalpy of solution: the H that
accompanies the dissolution of one mole of solute.• When a solid and a liquid form a
solution, the enthalpy change arises mainly from changes in the intermolecular attractions.
Solute-Solvent Interactions
The Solution Process
• Steps 1 and 2 are endothermic; step 3 is exothermic.
• A decrease in enthalpy is an important factor in causing spontaneous change.• However, many endothermic processes
are spontaneous, suggesting another contribution to spontaneity.
• In increase in disorder also favors spontaneous change.
Spontaneity
• An example of increasing disorder as a driving force is illustrated by the mixing of gases.
Spontaneous Mixing of Gases
(a) separated gases (b) spontaneously mixed
• An increase in disorder generally accompanies the mixing of molecules in the formation of a solution.• Ammonium nitrate is very soluble in water
because of the increase in disorder upon mixing, even though the process is quite exothermic (Hsoln = +26.4 kJ/mol).
Disorder and Spontaneity
• Relative solubilities can often be predicted by comparing the relative strengths of the intermolecular attractions of solute-solute, solvent-solvent, and solute-solvent interactions.
Solubility of Molecular Compounds
Like Dissolves Like
• In general, substances that have similar intermolecular forces have strong solute-solvent interactions and tend to form solution.
• (a) Is iodine (I2) more soluble in water or in hexane (C6H14)?
• (b) Is methanol (CH3OH) more soluble in water or in octane (C8H18)?
Example: Relative Solubility
• Hydration is the interaction of water molecules with ions, and is very exothermic.
Interaction of Ions with Water
• When an ionic compound dissolves in water, disorder changes because:• separating the ions increases disorder;• separating the water molecules increases disorder;• hydrating the ions, which restricts some water molecules, decreases disorder.
• A few examples are known where disorder decreases on dissolving ionic compounds.
Ionic Compounds in Water
Pressure and Solubility• Pressure has very little effect on the
solubilities of liquids and solids.• The solubility of gases in a liquid
depends on the pressure of the gas.• Henry’s Law: The solubility of a gas
is directly proportional to its partial pressure at any given temperature:
C = kP
Henry’s Law Constants in Water for Various Gases (molal/atm)
Gas 0°C 20°C 40°C 60°C
CO2 7.60 x 10-2 3.91 x 10-2 2.44 x 10-2 1.63 x 10-2
C2H4 1.14 x 10-2 5.60 x 10-3 3.43 x 10-3 ---
He 4.22 x 10-4 3.87 x 10-4 3.87 x 10-4 4.10 x 10-4
N2 1.03 x 10-3 7.34 x 10-4 5.55 x 10-4 4.85 x 10-4
O2 2.21 x 10-3 1.43 x 10-3 1.02 x 10-3 8.71 x 10-4
• Water at 20C is saturated with air that contains CO2 at a partial pressure of 8.0 torr. What is the molal concentration of CO2 in the solution?
Henry’s Law Calculation
• Experiments show that the way solubility changes with temperature depends on the sign of the enthalpy of solution.• Solubility increases with increasing
temperature if Hsoln is positive (endothermic).• Solubility decreases with increasing
temperature if Hsoln is negative (exothermic).
Solubility and Temperature
K2Cr2O7(s) → K2Cr2O7(aq) H = +66.5 kJ/mol
The solubility increases with increasingtemperature when Hsoln is positive.
Solubility and Hsoln
Temperature Dependence on Solubility
• Colligative property: Any property of a solution that changes in proportion to the concentration of solute particles.• Many colligative properties are directly
related to the lowering of solvent vapor pressure by the presence of solute particles.
Colligative Properties of Solutions
Effect of Solute on Evaporation• The rate of evaporation of solvent in a
solution is lower than that of the pure solvent. Solute particles block opportunities for solvent particles to enter the vapor phase.
Raoult’s Law• Raoult’s law: The vapor pressure of
solvent above a dilute solution equals the mole fraction of the solvent times the vapor pressure of the pure solvent.
Psolv = solvPsolv
• Another form of this equation gives the lowering of the vapor pressure.
Psolv = solutePsolv
• At 27C, the vapor pressure of benzene is 104 torr. What is the vapor pressure of a solution that has 0.100 mol of naphthalene in 9.90 mol of benzene?
Example: Raoult’s Law
Boiling Point Elevation• Because a solute lowers the vapor
pressure of the solvent, it raises the boiling point of the solution. Below, the concentration of the solution is increasing from (a) to (e).
Boiling Point Elevation• The boiling point elevation is
Tb = mkb
where m is the molal concentration and kb is the boiling point constant for the solvent.
Solvent B.P. (°C) kb (°C/m)
Acetic acid 117.90 3.07
Benzene 80.10 2.53
Water 100.0 0.512
Freezing Point Depression• Solute particles interfere with the ability
of solvent particles to form a crystal and freeze. Thus, it takes a lower temperature to freeze solvent from a solution than from the pure solvent. This is freezing point depression.
Freezing Point Depression• The freezing point depression is
Tf = mkf
where m is the molal concentration and kf is the freezing point constant for the solvent.
SolventFreezing Pt.
(°C)kf (°C/m)
Acetic acid 16.60 3.90
Benzene 5.51 4.90
Naphthalene 80.2 6.8
Water 0.00 1.86
• Benzophenone freezes at 48.1C. A solution of 1.05 g urea ((NH2)2CO, molar mass = 60.06 g/mol) in 30.0 g of benzophenone freezes at 42.4C. What is kf for benzophenone?
Example: Calculate kf
• Benzophenone freezes at 48.1C and has a kf of 9.8C/molal. A 2.50-g sample of solute whose molar mass is 130.0 g/mol is dissolved in 32.0 g of benzophenone. What is the freezing point of the solution?
Test Your Skill
• Semipermeable membranes allow water and small molecules to pass through them.• Osmosis is the diffusion of a fluid
through a semipermeable membrane.
Osmosis
• When a semipermeable membrane separates a solution from the pure solvent, the net effect is for pure solvent to move through the membrane into the solution.
• The higher level of liquid produces an additional pressure, called osmotic pressure.
Osmosis (continued)
• Osmotic pressure is a colligative property, and can be calculated by the equation
= MRTwhere:
= osmotic pressureM = molar concentration of soluteR = ideal gas law constantT = temperature in Kelvin
Osmotic Pressure
• A 5.70 mg sample of protein is dissolved in water to give 1.00 mL of solution. Calculate the molar mass of the protein if the solution has an osmotic pressure of 6.52 torr at 20C.
Example: Molar Mass by Osmotic Pressure
Colligative Properties - Summary
Property Symbol Conc. Unit Constant
Vapor pressure
∆P Mole fraction P°
Boiling Point ∆Tb Molal Kb
Freezing point
∆Tf Molal Kf
Osmotic pressure
Π Molar RT
Electrolyte Solutions• The colligative properties of electrolyte
solutions are more pronounced because electrolytes separate into ions in solution.• The van’t Hoff factor, i, is defined by the
equation
lytenonelectro for value expected
property ecolligativ measuredi
The van’t Hoff Factor• In dilute solution, the van’t Hoff factor for
salts approaches the number of ions produced by one formula unit of the substance.
NaCl → Na+(aq) + Cl-(aq) i = 2
MgBr2 → Mg2+(aq) + 2Br-(aq) i = 3
• The van’t Hoff factor generally decreases as the concentration increases.
Example: the van’t Hoff Factor
• Arrange the following aqueous solutions in order of increasing boiling points: 0.03 m urea (a nonelectrolyte), 0.01 m NaOH, 0.02 m BaCl2, 0.01 m Fe(NO3)3.
Mixtures of Volatile Substances• In a solution of two or more volatile
compounds, all components of the mixture are in equilibrium with their vapors.• An ideal solution is one in which all
volatile components obey Raoult’s law for all compositions.
PA = APA, PB = BPB, PC = CPC, etc.
Ideal Solutions• Mixtures of toluene and benzene form
nearly ideal solutions.
• At 27C, the vapor pressure of carbon tetrachloride (CCl4) is 127 torr and that of chloroform (CHCl3) is 212 torr. What is the partial pressure of each substance, and the total vapor pressure of the solution, of a solution that contains 0.40 mol of CCl4 and 0.60 mol of CHCl3?
Example: Vapor Pressure of Solutions
Distillation
• Distillation is the separation of a mixture of components based on differences in volatility (vapor pressure) by repeated evaporation and condensation of the mixture.• The vapor always contains a larger mole
fraction of the more volatile component.
Distillation Apparatus
Deviations from Raoult’s Law
• Most liquid-liquid solutions deviate from the ideal behavior predicted by Raoult’s law.• Solutions have positive deviations if the
vapor pressure is higher than predicted.• Solutions have negative deviations if the
vapor pressure is lower than predicted.