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Chapter 10 Sym Comp and Unbalanced Fault(2)

Jun 02, 2018

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    1/45

    C

    F

    C 10

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    2/45

    F

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    3/45

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    4/45

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    5/45

    2

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    C

    210 aaaa IIII ++=

    210

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    210

    cccc IIII ++=

    000

    acb III ==

    1211 240 aab IaII ==

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    222

    120 aab aIII ==

    1212 240 aac IaII ==

    I

    = 1201a

    = 24012a

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    7/45

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    =

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    === 120200;120230;0200 cba VVV

    EG ,

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    =

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    9/45

    =

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    1 21cbaa VaaVVV

    =++= 0210)(3

    1 22cbaa aVVaVV

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    10/45

    === 180100;00;0150 cba III

    EG , ,

    ,

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    11/45

    =

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    12/45

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    13/45

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    14/45

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    L

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    nXXX 310+=

    )ln2.0(2D

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    0 = + 3

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    20/45

    0 = + 3

    =

    I0=0I0=0

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    0 = + 3

    I0 I0=0

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    0 = + 3

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    23/45

    0 = + 3

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    24/45

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    30/45

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    33/45

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  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    34/45

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    F

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    F 3

    .

    Generators G1 and G2: 1.021 jXX == p.u; 05.00

    jX = p.u; Voltage: 11 kV

    Transformers T1 and T2: 15.0021 jXXX === p.u; Voltage: 11/275 kV

    Line: 05.021 jZZ == p.u, 1.00 jZ = p.u ; Voltage: 275 kV

    All per unit values are on a base of 100 MVA, and pre-fault voltage is 1.0 per unit.

    C B

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    D ,

    .

    .

    j0 1 j0 1j0 15 j0 15j0 05

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    37/45

    j0.1 j0.1j0.15 j0.15j0.05

    j0.05 j0.05j0.15 j0.15j0.1

    A B

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    D

    B.

    fBBB

    a

    aaa ZZZZ

    E

    III 3021210

    +++===

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    12BB ZZ = = j0.1364

    )15.0//()1.015.0(0 jjjZB += = j0.09375

    009375.01364.01364.0

    0.1210

    +++=== jjjIII aaa = -j2.728 .pu

    1844.83)(0

    jIFI aB == p.u

    B

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    D

    B.

    A B,

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    )55.0

    25.0)((*)15.01.0( 11 FIjjV BA += = 454.0*728.2*25.0 jj = -0.31

    111 )0()( AAA VVFV += = 1.0 0.31 = 0.69 p.u

    )55.0

    25.0

    )((*)05.015.01.0(11

    FIjjjV BB ++= = -0.372

    111 )0()( BBB VVFV += = 1.0 0.372 = 0.628 p.u

    Negative sequence voltage buses A and B,

    222 )0()( AAA VVFV += = 0.0 0.31 = - 0.31

    222 )0()( BBB VVFV += = 0.0 0.372 = -0.372

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    Zero sequence voltage buses A

    and B,

    )55.0

    25.0)((*)15.0(

    00

    FIjV BA = = - 0.186

    000 )0()( AAA VVFV += = 0.0 0.186 = -0.186 p.u

    )55.0

    25.0

    )((*)1.015.0(00

    FIjjV BB += = - 0.31 p.u000 )0()( BBB VVFV += = 0.0 0.31 = -0.31 p.u

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    =

    2

    22

    1

    11

    0

    00

    012

    )()(

    )()(

    )()(

    AB

    BA

    AB

    BA

    AB

    BA

    AB

    z

    FVFV

    z

    FVFV

    z

    FVFV

    I =

    05.0

    )372.0(31.0

    05.0

    628.069.0

    1.0

    )31.0(186.0

    j

    j

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    =

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    24.1

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    24.1

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    1

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    ++++= 1209024.12409024.19024.1bABI = 0.0 p.u

    ++++= 2409024.11209024.19024.1cABI = 0.0 p.u

    C

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

    43/45

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    F 3

    .

    Generators G1 and G2: 1.021 jXX == p.u; 05.00

    jX = p.u; Voltage: 11 kV

    Transformers T1 and T2: 15.0021 jXXX === p.u; Voltage: 11/275 kV

    Line: 05.021 jZZ == p.u, 1.00 jZ = p.u ; Voltage: 275 kV

    All per unit values are on a base of 100 MVA, and pre-fault voltage is 1.0 per unit.

    C B

  • 8/10/2019 Chapter 10 Sym Comp and Unbalanced Fault(2)

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    D

    B.

    F ,

    12 )( acb IaaII ==ZfZZ

    EIa

    ++=

    21

    01

    upjjj

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    133 1 =

    ++===