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Chapter 1 (Part 1) Introduction to Engineering Calculations

Jul 05, 2018

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    CHAPTER 1

    Basic Concepts

    emical Engineering Process Princip

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    In designing a new process or analyzing anexisting one, calculation of amounts andproperties of raw materials and products iscrucial.

    This chapter presents the calculationtechniques of expressing the values of

    process variables.

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    Topic Outcomes

    At the end of Chapter , you should!

    • Convert one set of units in a function orequation into another equivalent set formass, length, area, volume, time, energy and

    force using conversion factor tables.

    • Identify the units commonly used to expressboth mass and weight.

    • Identify the number of signicant gures in a

    given value and state the precision withwhich the value is known.

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    Introduction to

    Engineering

    Calculations

    Units andDimensions

    Conversion ofUnits

    Systems ofUnits

    What are in this chapter?

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    dded  !xample" #.$%kg

    &'.%(kg )yes* +ubtracted !xample" %m 'm

    )yes*-hr #min )no*

    ultiplied/ivided!xample " 0m x 'm 1

    2# m# 

    Units

    Units

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    "# mg g $ %.%"# g

      %%% mg

    Conversion of Units

    & To convert a quantity expressed in terms of one unit toequivalent in terms of another unit, multiply the givenquantity by the conversion factor.

    & Conversion factor ' a ratio of equivalent valuesof a quantity expressed in different units.

    & (et say to convert "# mg to gram.

    Conversionfactor

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    Dimensional Equation

    & Convert cm)s

    *

     to +m)yr

    *

    . rite the given quantity and units on left.

    *. rite the units of conversion factors that cancel the old unit andreplace them with the desired unit.

    ". -ill the value of the conversion factors

    cm s* h* day* m +m

    s* h* day* yr* cm m

    cm "#%%* s* ** h* "#/* day*  m  +m

    s* * h* * day* * yr* %% cm %%% m

    "#%%* x ** x "#/*  +m$ 0.0/ x %0 +m) yr *

    %% x %%% yr*

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    1

    Systems of Units

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    Base Units

    Base Units

    2uantity 3I 3ymbol American 3ymbol C43 3ymbol

    (ength meter m foot ft centimeter cm

    5ass +ilogram +gpoundmass lbm gram g

    5olesgram6mole mole pound mole lbmole gram6mole mole

    Time second s second s second s

    Temperature 7elvin 7 8an+ine 8 7elvin 7

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    Multiple Units%

    ● Fractions of base unit

      -Example :  Years  Days

      Hours

      Minutes

    ● Multiple Unit prefixes

    -Example :

    3econds

    5ultiple 9nit :references

    tera ;T< $ % * centi ;c< $ % 6*

    giga ;4< $ % 0 milli ;m< $ % 6"

    mega ;5< $ % # micro ;μ) = % 6#

    +ilo ;+< $ %*

    nano ;n< $ %60

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    Derivatives SI Units

    Derive SI Units

    !uantity Unit Sym"ol Equivalent to the Base Unit

    =olume (iter ( %.%%m" $ %%% cm"

    -orce >ewton

    ;3I<?yne

    ;C43<

    > +g.m)s*

    g.cm)s*

    :ressure :ascal :a >)m*

    @nergy)

    or+

    oule

    Calorie

    cal

    >.m $ +g.m* )s*

    .1 $.1 +g.m*

     )s*

    :ower att )s $ +g.m* )s"

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    Systems of Units

    • 3 systems of unit:

    a) ! system

     b) "merican en#ineerin# system

    c) $% system

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    Chec# $our Unerstanin%

    Derived unit for &elocity  in t'e ! ystem( 'e $%ystem( 'e "merican En#ineerin# ystem(

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    EXERCISE& Convert miles per hour to meter per

    second

    Length1 m = 100 cm = 1000 mm

    =106 microns = 1010angstrom  = 39.37 in = 3.2808 ft  = 1.0936 y =0.000621! mile1 ft = 12 in = 1"3 y =0.30!8 m

      = 30.!8 cm

    sm447.0

    shr 

    36001

    milem

    0006214.01

    hr mile1

    hr mi 1   =××=

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    /

    EXERCISE& Convert *" Ibm.ft)min* to its equivalent

    +g.cm)s*

    #ass1 $g = 1000 g = 0.001

    metric tonne= 2.20!62 %&m =

    3'.2739 o(

     1 %&m = 16 o( = ' ) 10*! ton

      = !'3.'93 g =0.!'3'93 $g

    22

    2

    2

    2

    22 s

    kg.cm088.0

    s

    min

    60

    1

    2808.3

    cm100

    Ibm1

    kg0.453593

    min

    ftIbm. 23

    min

    ftIbm. 23   =×××=

     ft 

    Length1 m = 100 cm = 1000 mm

    =106

     microns = 1010angstrom  = 39.37 in = 3.2808 ft  = 1.0936 y =0.000621! mile

    1 ft = 12 in = 1"3 y =0.30!8 m  = 30.!8 cm

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    #

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    &orce ' Wei%ht

    • Force is proportional to pro*uct of mass an* acceleration+ 

    • Usually *efine* usin# *eri&e* units ,

    .e/ton 0.) 1 2#+ms4

    *yne 1 #+cms4

    !bf    1 34+56 !bm+fts4

    •  7ei#'t of an ob8ect is force exerte* on t'e ob8ect by#ra&itational attraction of t'e eart' i+e+ force of #ra&ity9 #+

    •  alue of #ra&itational acceleration:

    # 1 ;+> ms4 1 ;> cms4

    1 34+56 fts4

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    &orce ' Wei%ht

    • #c is use* to *enote t'e con&ersion factor from a natural

    force unit to a *eri&e* force unit+

    gc $ +g.m)s* $ "*.B lbm.ft)s

    *

    > lbf 

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    Dimensions

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    *

    +,antity -%

    nit

    /imension

    #ass ilogra

    m

    #

    Length #eter L

    emperat,re

    ime s

    B(SE U)ITS DIME)SIO)S

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    **

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    *"

    -paghetti ecipe

    %ngreients4

    20 ml of coo$ing oil100 gram of mince meat1' cm spaghetti stic$s 

    5al,e nit /imension

    20 milliliter LE

    L:

    100 gram #;--

    #:

    1' centimeter

    LE

    L:

     

    E*(M+,E

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    *

    Dimensional Homogeneity

    • ?uantities can be a**e*subtracte* if @.AY  t'eir unitsare same+

    • Unit same9 t'e D!ME.!@. of eac' term must be t'esame+

    E#+ : EA@$!Y 1 AE.%H !ME0A) 0) 0A) 0)

      0ms) 0ms)

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    */

    • E

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    *#

    Examples:• F 1 ma /'ere F 1 Force 0. 1 2#+ms4)

    m 1 mass 02#) 1 0 M )

    a 1 acceleration 0ms4)1 0 A) 0 )4

    2#+ms4 1 02# )0ms4)

     ; 5 < ; ( < $ ; 5 < x ; ( <  ; T

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    *B

    Dimensional Analysis

    • 'is is a &ery important tool to c'ec2 your /or2 E#+ : Doin# a problem you #et t'e ans/er *istance

    * 1 & t4 0&elocity x time4)

    Units on left si*e 1 0 A )

    Units on ri#'t si*e 1 ( A )0 ) x 0 )4 1 0 A ) +0 )

    •   Aeft units an* ri#'t units *onBt matc'9 soans/er must be /ron#CC

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    *1

    Check your understanding…& The period P  of a swinging pendulum depends only

    on the length of the pendulum d and theacceleration of gravity g.

    ' hich of the following formulas for P  could   becorrect D

     g 

    d  P    π   2=

    (a)(a)

    (b)(b)

    (c(c))   g 

    d  P    π  2=

    4iven ! d   $ units of length ; ( 

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    *0

    • Identify unit of P.  P   has units of time (TT )

    • Make sure Left Ri!ht unit dimensiona""y

    homo!eneous (#onsistent)$

    (a)(a)

    (a)(a)

    L  L

    L

    T T ⋅ 

        

        = ≠

    2    4

    4

    (   )P dg = 2    2 π 

    ot

    ot

    ight !!

    ight !!

    P   d 

    g = 2 π   

    L

    L

    T T 

    2 = ≠

    ot

    ot

    ight !!

    ight !!

    T T 

    L

    L   2 

    ==

    P   d 

    g =  2 π  

    CorrectCorrect units!!

    (a)(a) (b)(b) (c)(c)

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    -ree Template from www.brainybetty.com "%

    • If an equation is dimensionallyhomogeneous but its additive terms haveinconsistent unit, the terms may be madeconsistent by applying conversion factors

    !xample"

     V (m/s) = Vo (m/s) + g (m/s2 ) t(min>

     " Apply the con#ersion $actor

    V (m/s) = Vo (m/s) + g (m/s2 ) t(min>(60s/min)V = Vo + 60 g t V = Vo + 60 g t 

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    -ree Template from www.brainybetty.com "

     "n euation is only %ALID /'en it is *imensionally

    Homo#eneous

    & #onsistent in 'IT***

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    "*

    Dimensionless %uantities

    • $an be a pure number E#+ : 49 +3 94

    • a multiplicati&e combination of &ariables /it' no net*imensions

    E#+ :

     µ 

     ρ ud =Re

    + & (!,#m-) . u & (#m,s).d & (#m). / & (!,#m$s)

    /%#E-%?LE--

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    What have you learned?