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Chapter 07 and 08 Chemical Bonding and Molecular Structure
35

Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Jan 05, 2016

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Page 1: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Chapter 07 and 08Chemical Bonding

and MolecularStructure

Page 2: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Compound• Pure substance

• Made of 2 or more elements in a definite proportion by mass

• Physically and chemically different from the elements that make up the compound

• All elements (except Noble gases) react to gain a stable octet. (duet-for H through B)

• Compounds form to gain a stable valence shell which is LOWER IN ENERGY than the atoms before the reaction

Page 3: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Ionic compounds

• Metal gives all valence electrons to a nonmetal or semimetal.

• Both gain stable octets or duets.

• Ionic bond forms due to electrostatic attraction of cation(s) and anion(s)

• One unit is the lowest whole number ratio between the cation and anion. This unit is called a FORMULA UNIT

Page 4: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Covalent Compounds

• Formed when 2 or more nonmetals or a nonmetal and semimetal SHARE valence electrons in order to gain a stable octet.

• Tendency for atoms to obtain a stable octet is called the OCTET RULE.

Page 5: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Part 01Ionic

Bonding

Page 6: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

1. Draw the electron dot (Lewis) Dot Diagram for the ionic compound formed between sodium and fluorine.

Page 7: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

NaAtom

FAtom

d

Sodium must lose its one valence electron to get a stable octet.Fluorine must gain one electron to get a stable octet.The electron transfer is from sodium to fluorine and is always from metal to nonmetal.

Page 8: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

[Na]Cation Anion

This is an ionic compound because it contains a metal cation and a nonmetal anion. Both ions have a stable octet.The stable octet is NEVER shown on the cation; it is ALWAYS shown on the anion.

1+ 1-

[ F ]d

Page 9: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

This is a very stable compound. The positive and negative ions exerts a strong electrostatic attraction on each other and bond the ions together.

[Na]Cation Anion

1+ 1-

[ F ]d

Page 10: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

The overall charge of the compound is zero because 1+ and 1- sums to zero. The overall charge must always be zero which shows that the number of electrons lost is equal to the number of electrons gained.

[Na]Cation Anion

1+ 1-

[ F ]d

Page 11: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Binary Ionic SaltBinary: Two ElementsIonic: Metal and NonmetalSalt: Metal and Nonmetal

Electron Dot or Lewis Dot Diagram

[Na]Cation Anion

1+ 1-

[ F ]d

Page 12: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

FormulaShorthand method of representing a compound

Electron Dot or Lewis Dot Diagram

Na F1+

1-

Metal on leftNonmetal on rightPositive on leftNegative on right

ALWAYS

[Na]Cation Anion

1+ 1-

[ F ]d

Page 13: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

NameSodium Fluoride

Electron Dot or Lewis Dot Diagram

Names of all binary compounds end in –ide.

[Na]Cation Anion

1+ 1-

[ F ]d

Page 14: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

2. Draw the electron dot (Lewis) Dot Diagram for the ionic compound formed between calcium and chlorine.

Page 15: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Ca ClAtom Atom

Calcium must lose its TWO valence electrons to get a stable octet.Chlorine must gain one electron to get a stable octet.The electron transfer is from calcium to chlorine and is always from metal to nonmetal.

Page 16: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Ca Cl Cl This is an ionic compound because it contains a metal cation and a nonmetal anion. Both ions have a stable octet.The stable octet is NEVER shown on the cation; it is ALWAYS shown on the anion.

Page 17: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

This is a very stable compound. The positive and negative ions exerts a strong electrostatic attraction on each other and bond the ions together.

1-

[Ca] [ Cl ] [ Cl ]2+1-

CationAnion Anion

Page 18: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

The overall charge of the compound is zero because 2+ and 1- and 1- sums to zero. The overall charge must always be zero which shows that the number of electrons lost is equal to the number of electrons gained.

1-

[Ca] [ Cl ] [ Cl ]2+1-

CationAnion Anion

Page 19: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Binary Ionic SaltBinary: Two ElementsIonic: Metal and NonmetalSalt: Metal and Nonmetal

Electron Dot or Lewis Dot Diagram

1-

[Ca] [ Cl ] [ Cl ]2+1-

CationAnion Anion

Page 20: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

FormulaShorthand method of representing a compound

Ca Cl2+

1-

Metal on leftNonmetal on rightPositive on leftNegative on right

ALWAYS

Electron Dot or Lewis Dot Diagram

2

1-

[Ca] [ Cl ] [ Cl ]2+1-

CationAnion Anion

Page 21: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

3. Draw the electron dotdiagram for the ionic compound formed between potassium andoxygen.

Page 22: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

KAtom

OAtom

d

Potassium must lose its one valenceelectron to get a stable octet.Oxygen must gain two electrons toget a stable octet.The electron transfer is frompotassium to oxygen.

Page 23: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

K O d

This does not represent the formation of a compound. Oxygen does not havea stable octet because it has not gained two electrons.

Page 24: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

A stable compound can form if a second potassium atom loses its one valence electron to the oxygen.

Page 25: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

K O d

K

Page 26: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

[K] [ O ]d

[K] 1+

1+ 2-

The name of the compound is potassium oxide. Its formula is K2

1+O2-.There are two electrons lostand two electrons gained.

Page 27: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

4. Draw the electron dot diagram for the ionic compound formed between iron and bromine when iron has three valence electrons.

Page 28: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Fe Brd

Iron must lose its three valence electron to get a stable octet. Bromine can only gain one. The electron transfer is from iron to bromine.

Page 29: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Fe Br d

Br d

Br d

The three electrons are transferred from the iron to the brominewhen three bromine atoms are available.

Page 30: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

[ Br ] [Fe]d

1- 3+

[ Br ] d

1-

[ Br ] d 1-

Page 31: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

The name of the compound is iron(III) bromide. The Roman numeral is inserted after the name of the metal to indicate the number of electrons lost and the oxidation number. This is only done with elements that can change their oxidation numbers.

Page 32: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

The formula of the compound is Fe3+Cl1-

3.

Page 33: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

Rule: Transition metals and lead and tin can have variable oxidation numbers. Therefore a Roman numeral must be inserted into the name of the compound to indicate the number of electrons lost and the oxidation number of the metal. Exceptions Ag is always 1+, Cd and Zn are 2+

Page 34: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

What is the formula for:Calcium Fluoride Ca

2+F

1-

2

Aluminum oxide Al3+ O 2-2 3

Tungsten(IV) Sulfide W4+

S2-

2

Sodium Carbide Na1+

C4-

4

Go to page 73 in notes

Page 35: Chapter 07 and 08 Chemical Bonding and Molecular Structure.

What is the name of: 42

2 CMg Magnesium Carbide

3ScF Scandium (III) Fluoride

OAg2 Silver Oxide NO ROMAN numeral!

2SnS Tin (IV) Sulfide

FrH Francium Hydride

Assignment: p 74-76 (notes)