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Digital CommunicationsChapter 13 Fading Channels I: Characterization and Signaling
Po-Ning Chen
Institute of Communication Engineering
National Chiao-Tung University, Taiwan
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13.1 Characterization of fading multipath
channels
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The multipath fading channels with additive noise
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Time spread phenomenon of multipath channels(Unpredictable) Time-variant factors
DelayNumber of spreads
Size of the receive pulses
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Transmitted signal
s(t) = Res(t)e2fct
Received signal in absence of additive noiser
(t
)=
c
(; t
)s
(t
)d
=
c(; t)Res(t )e2fc(t)d= Re
c(; t)e 2fcs(t )d e2fct= Res(t) c(; t)e 2fc
c(;t) e2fct
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Note that now it is not appropriate to write s(t) c(t)because t and are now specifically for time argument andconvolution argument!
We should perhaps write s(t) c() and s(t) c(; t),which respectively denote:
s(t) c() =
c()s(t )dand
s
(t
) c
(; t
)=
c
(; t
)s
(t
)d.
From the previous slide, we know
c
(; t
)= c
(; t
)e 2fc and c
(; t
)=
c
(; t
).
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Rayleigh and Rician
The measurement suggests that c
(; t
)is a 2-D Gaussain
random process in t (not in ), which can be supported by thecentral limit theorem (CLT) because it is the the sum effectof many paths.
If zero mean,
c
(; t
)is Rayleigh distributed. The
channel is said to be a Rayleigh fading channel
If nonzero mean, c(; t) is Rician distributed. Thechannel is said to be a Rician fading channel
When diversity technique is used, c(; t) can be well modeledby Nakagami m-distribution.
Detail of these distributions can be found in Section 2.3.
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13.1-1 Channel correlation functions and
power spectra
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Assumption (WSS)
Assume c
(; t
)is WSS in t.
Rc ( , ; t) = E{c(; t+t)c (; t)}is only a function of time difference t.
Assumption (Uncorrelated scattering or US of a WSS channel)
For , assume c(; t1) and c(; t2) are uncorrelated forany t1, t2.
is the convolution argument and actually represents the
delay for a certain path.
Assumption (Math definition of US)
Rc ( , ; t
)= Rc(
; t
)
(
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Discussions
It may appear unnatural to define the autocorrelationfunction of a channel impulse response using the Dirac
delta function.
However, we have already learned that is theconvolution argument, and
(
)is the impulse response
of the identity channel. This hints somehow theconnection between channel impulse response andDirac delta function.
Recall that a WSS white (noise) process z() is definedbased onE
[z
(
)z
(+
)]=
N0
2
(
).
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Discussions
We can extensionally view that the autocorrelation functionof a 2-dimensional WSS white noise z
(; t
)is defined as
E[z(; t1)z(+ ; t2)] = N0(t1, t2)2
().US indicates that the accumulated power correlation from all
other paths is essentially zero!
Some researchers interpret US as zero-correlationscattering. So, from this, they dont interpret it as
E[z(; t1)z
(+ ; t2)] = E[z(; t1)]E[z
(+ ; t2)] = 0,which requires zero-mean assumption but simply sayE
[z
(; t1
)z
(+ ; t2
)]= 0 when 0.
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M l i h i i fil f US WSS h l
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Multipath intensity profile of an US-WSS channel
The multipath intensity profile or delay powerspectrum for a US-WSS multipath fading channel is
given by: Rc () = Rcell (; t= 0) .It can be interpreted as the average signal powerremained after delay :
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M l i h d f US WSS h l
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Multipath spread of an US-WSS channel
The multipath spread or delay spread of a US-WSSmultipath fading channel
The range of over which Rc() is essentially nonzero;it is usually denoted by Tm.
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Each corresponds to one path.No Tx power will remain at Rx after for path with delay > Tm.
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T f f ti f lti th f di h l
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Transfer function of a multipath fading channel
The transfer function of a channel impulse response c(; t
)is
the Fourier transform with respect to the convolutionalargument :
C
(f; t
)=
c
(; t
)e 2f d
Property: If c
(; t
)is WSS; then so is C
(f; t
).
The autocorrelation function of WSS C(f; t) is equal to:RC(f, f; t) = EC(f; t+t)C (f; t)
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With an additional US assumption,
RC
(f, f; t
)= EC(f; t+t)C
(f; t)= E
c(; t+t)e 2f d
c (; t)e2f d=
Rc
(; t
)
(
)e2(ff) dd
=
Rc (; t) e 2ff1 d1= RC
(f; t
)For a US-WSS multipath fading channel,RC(f; t) = EC(f+f; t+t)C (f; t)This is often called spaced-frequency, spaced-timecorrelation function of a US-WSS channel.
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C h t b d idth
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Coherent bandwidth
RC (f; t) = Rc (; t) e 2(f) dFor the case of t= 0, we have
RC (f)spaced-frequencycorrelation function
=
Rc () e 2(f) dRecall that Rc() = 0 outside [0,Tm).In freq domain, (f)c = 1Tm is correspondingly calledcoherent bandwidth.
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Example
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Example.
Give Rc
(
)= 107
(107
)for 0 < 100 ns. Then,
RC(f) = 107
42(f)2 e 2107f 1 12f .
RC(f)RC(0) Rc
(
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Coherent bandwidth
Since the channel output due to input s(t
)is equal to:
r(f) = s(f)C(f; t),where we abuse the notations to denote the Fourier transformsof r
(t) and s(t) as r(f) and s(f), we would sayr(f) = s(f)C(f; t)will have weak (power) affection on
r(f+f) = s(f+f)C(f+f; t)when f>
(f
)c.
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If signal transmitted bandwidth
B> (f)c, the channel is calledfrequency selective.
If signal transmitted bandwidthB< (f)c, the channel is calledfrequency non-selective.
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For frequency selective channels, the signal shape is moreseverely distorted than that of frequency non-selectivechannels.
Criterion for frequency selectivity:
B> (f)c 1T
>1
Tm T < Tm.
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Time varying characterization: Doppler
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Time varying characterization: Doppler
Doppler effect appears via the argument t.
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Doppler power spectrum of a US-WSS channel
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Doppler power spectrum of a US WSS channel
The Doppler power spectrum is
SC() =
RC(f= 0; t)e 2(t)d(t),where is referred to as the Doppler frequency.
Bd = Doppler spread is the range such that SC() isessentially zero.(t)c = 1Bd is called the coherent time.If symbol period T >
(t
)c
, the channel is classified as
Fast Fading.I.e., channel statistics changes within one symbol!
If symbol period T < (t)c
, the channel is classified asSlow Fading.
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Scattering function
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Scattering function
Summary:
Rc(; t) Channel autocorrelation function1-D FT:
RC
(f; t
)= F
{Rc
(; t
)}Spaced-freqspaced-timecorrelation func
S(;) = Ft{Rc(; t)} Scattering function2D FT: ??? = F,t{Rc(; t)}RC
(f; t
)1-D FT: ??? = Ff{RC(f; t)}SC(f;) = Ft{RC(f; t)} Doppler powerspectrum (f= 0)2D FT: S
(;
)= Ff,t
{RC
(f; t
)}Digital Communications: Chapter 13 Ver 2010.09.06 Po-Ning Chen 26 / 110 Scattering function
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Scattering function
The scattering function can be used to identify delayspread and Doppler spread at the same time.
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Example. Medium-range tropospheric scatter
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Example. Medium range tropospheric scatter
channel
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Example study of delay spread
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p y y p
The median delay spread is the 50% value, meaning that50% of all channels has a delay spread that is lower than themedian value. Clearly, the median value is not so interestingfor designing a wireless link, because you want to guaranteethat the link works for at least 90% or 99% of all channels.
Therefore the second column gives the measured maximumdelay spread values. The reason to use maximum delayspread instead of a 90% or 99% value is that many papersonly mention the maximum value. From the papers that do
present cumulative distribution functions of their measureddelay spreads, it can be deduced that the 99% value is only afew percent smaller than the maximum delay spread.
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Measured delay spreads in frequency range of 800M to 1.5GHz (surveyed by Richard van Nee)
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Measured delay spreads in frequency range of 1.8 GHz to 2.4GHz (surveyed by Richard van Nee)
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Measured delay spreads in frequency range of 4 GHz to 6 GHz(surveyed by Richard van Nee)
Conclusion by Richard van Nee: Measurements done atdifferent frequencies show the multipath channelcharacteristics are almost the same from 1 to 5 GHz.
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Jakes model: Example 13.1-3
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p
Jakes modelA widely used model for Doppler power spectrum is the
so-called Jakes model (Jakes, 1974)RC(t) = J0(2fm(t))
and
SC() = 1
fm
1
1
(fm)
2,
fm
0, otherwise
where
fm = vfc
c is the maximum Doppler shift
v is the vehicle speed (m/s)
c is the light speed (3 108 m/s)fc is the carrier frequency
J0
(
)is the zero-order Bessel function
of the first kind.
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Jakes model: Example 13.1-3
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Difference in path length
L = (L sin())2 + (L cos() + v t)
2 L
= L2 + v2(t)2 + 2L v t cos() LPhase change = 2 L(cfc)
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Estimated Doppler shift
m = limt0
12
t
=1
c
fc
limt0
L2 + v2(t)2 + 2L v t cos() L
t
= vfcc
cos() = fm cos()Example. v = 108 km/hour, fc = 5 GHz and c= 1.08 10
9
km/hour.
m = 500cos() Hz.This is ok because 500 Hz5GHz = 0.1 ppm.
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Jakes model
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Here, a rough (and no so rigorous) derivation is provided for
Jakes model.
Just to give you a rough idea of how this model is obtained.
Suppose
(t
)is the delay
of some path.
(t) = limt0 (t+t)(t)t= limt0
L+Lc
L
c
t
= limt0L
ct
= vc
cos() (t) v
ccos()t +
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A ( ) ( )( ) d i i d d f ( )
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Assume c(; t) c(t)() and is independent of c(t).c
(; t
) c
(t
)
(
)e 2fc(t)
= c(t)()e 2fc vc cos()t+= c(t)()e 2fce 2fm cos()t
Rc(; t) =
E [c(; t + t)c
(; t)] d= E c(t + t)()e 2fce 2fm cos()(t+t)c
(t
)
(
)e2fce2fm cos()t
= E [c(t)c(t + t)]E e 2fm cos()t ()Recall Rc( , ; t) = Rc(; t)( ).
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RC(f= 0; t)=
Rc(; t)d=
E
[c
(t
)c
(t+ t
)]E
e 2fm cos()t
(
)d
= E [c(t)c(t + t)]E e 2fm cos()t= E [c(t)c(t + t)] J0(2fm(t)),
where the last step is valid if is uniformly distributed over
[, ).
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can be treated as uniformly distributed over [, ) and
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y [ , )independent of attenuation and delay path .
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Channel model from IEEE 802.11 Handbook
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A consistent channel model is required to allowcomparison among different WLAN systems.
The IEEE 802.11 Working Group adopted the followingchannel model as the baseline for predicting multipath for
modulations used in IEEE 802.11a and IEEE 802.11b,which is ideal for software simulations.
The phase is uniformly distributed.
The magnitude is Rayleigh distributed with averagepower decaying exponentially.
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imax1
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c(; t) = i=0
ie i( iTs)
where
Ts sampling periodie i N(0, 2i 2) + N(0, 2i 2)2
i= 20 e
iTsrms20 = 1 e
Tsrms
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R ( ) E [ ( ) ( )]d
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Rc() =
E [c(; t)c (; t)]d=
imax1
i=0
E 2i ( iTs)( )d
=imax1
i=0
E 2i ( iTs)=
imax1
i=0 2
0e
iTs
rms
( iTs)By this example, I want to introduce the rms delay. By definition,the effective rms delay is
T2rms =
2Rc()d Rc()d
Rc()d Rc()d
2
=imax1i=0 (iTs)220eiTsrmsimax1i=0 20eiTsrms
imax1i=0 (iTs)20eiTsrmsimax1i=0 20eiTsrms
2
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We wish to choose imax such that Trms rms.
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Let rms =rmsTs
, Trms =Trms
Tsand imax =
imaxrms
.
We obtain
Trms =
e1rms
(1 e1rms
)2
i2maxe
imax
(1 eimax
)2
1
2rms
= 2rms 112 + 1240 12rms + i2maxeimax(1 eimax)2 12rmsTaking Trms =
2rms 1
12 andi2maxe
imax
(1eimax
)2= 1240 yield
imax = 10.1072 . . . (or equivalently, imax = 10rms
Ts).
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Typical Multipath Delay Spread for Indoor environment (Table 8-1of IEEE 802.11 Handbook)
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13.1-2 Statistical models for fading
channels
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In addition to zero-mean Gaussian (Rayleigh), non-zero-meanGaussian (Rice) and Nakagami-m distributions, there are other
models for c(; t) have been proposed in literature.Example.
Channels with a direct path and a single multipath
component, such as airplane-to-ground communications
c(; t) = () + (t)( 0(t))where controls the power in the direct path and is
named specular component, and (t) is modeled aszero-mean Gaussian.Digital Communications: Chapter 13 Ver 2010.09.06 Po-Ning Chen 47 / 110
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Example.
Microwave LOS radio channels used for long-distance
voice and video transmission by telephone companies inthe 6 GHz band (Rummler 1979)
c
(
)=
(
) e2f0
( 0
)where
overall attenuation parameter
shape parameter due to multipath components
0 time delay
f0 frequency of the fade minimum, i.e., f0 = arg minfR C(f)Digital Communications: Chapter 13 Ver 2010.09.06 Po-Ning Chen 48 / 110
Rummler found that
1
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1
2 f
(
)
(1
)2.3
3
log() Gaussian distributed (i.e., lognormaldistributed)4 0 6.3 ns
Deep fading phenomenon: At f= f0, the so-called deep fading occurs.
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13.2 The effect of signal characteristics on
the choice of a channel model
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Usually, we prefer slowly fading and frequency
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y g y
non-selectivity.
So we wish to choose symbol time T and transmissionbandwidth B such that
T W2
In such case, we shall add a lowpass filter at the Rx.
where L(f) = 1, f W20 otherwise
.
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r t =
s f C f e2ftdf+ zW t
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For a bandlimited C f , sampling theorem gives:
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( )
c(t) = n=
c nW sincWt nWC
(f
)=
c
(t
)e 2ftdt
=
1W
n=
c nW e 2fnW, f W20, otherwise
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.06 Po Ning Chen 94 / 110
r(t) =
s(f)C(f)e2ftdf+ zW(t)=
1 c n W2
s f e 2f(tnW)df + zW t
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W
n=
c
W
W
2
s
(f
)e df+ zW
(t
)= 1W
n=
c nW
s t nW
+ zW(t)=
n=
cn s
t
n
W
+ zW
(t
), where cn =
1
Wc
n
W
For a time-varying channel, we replace c() and C(f) by c(; t)and C
(f; t
)and obtain
r(t) = n= cn(t) s t nW + zW(t)where cn =
1W
cn
W; t .
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.06 Po Ning Chen 95 / 110
Statistically, c() = 0 for > Tm and < 0.So, c() is assumed band-limited and is also statistically time-limited!Hence, cn = 0 for n < 0 and n > TmW (since = nW > Tm).
tTm W t t n t
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r
(t
)=
n=0
cn
(t
) s
t
W+ zW
(t
)
For convenience, the text re-index the system as
r t =L
k=1
ck t s t k
W+ zW t .
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13.5-2 The RAKE demodulator
Di it l C i ti s Ch t 13 V 2010.09
.06 P Ni Ch 97 / 110
Assumption (Gaussian and US (uncorrelated scattering)){ck(t)}Lk=1 complex i.i.d. Gaussian and can be perfectly estimatedby Rx.
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So the Rx can regard the transmitted signal as one of
v1,(t) =Lk=1 ck(t) s1, t kW
vM,
(t
)=Lk=1 ck
(t
) sM,
t k
W
So slide 4-162 said:Coherent MAP detectionm = arg max
1mMRe
r
vm,
= arg max
1mMRe
T
0r
(t
)vm,
(t
)dt
= arg max1mM
Re Lk=1
T
0r(t)ck(t)sm, t k
Wdt
Um
Di it l C i ti Ch t 13 V 2010.09
.06 P Ni Ch 98 / 110
Discussions on assumptions:We assume:s(t) is band-limited to W.c is causal and time-limited to Tm and, at the same time,b d li it d t W
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( )band-limited to W.
W (f)c = 1Tm (i.e., L WTm 1) as stated in page 879in textbook.
The definition of Um requires T Tm (See page 871 in
textbook) such that the longest delayed version
s(t LW) = s(t WTmW) = s(t Tm)is still well-confined within the integration range
[0,T
). As a
result, the signal bandwidth is much larger than 1T; RAKEis used in the demodulation of spread-spectrum signals!WT WTm 1 W
1T
.
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09.
06 P Ni Ch 99 / 110
M = 2 case
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The receiver collectsthe signal energy fromall the received paths,which is somewhat anal-ogous to the gardenrake that is used to
gather together leaves,hays, etc. Consequently,the name RAKE re-ceiver has been coinedfor this receiver struc-
ture by Price and Green(1958). (I use sm,, but the textuses s,m.)
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09.
06 P Ni Ch 100 / 110
Alternative realization of RAKE receiver
The previous structure requires M delay lines.
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We can reduce the number of the delay lines to one by thefollowing derivation.
Let u= t tW
.
Um = Re Lk=1
T
0r(t)ck(t)sm, t kWdt
= Re L
k=1
T
0 r u+k
W ck u+k
W sm, (u)dtDi i l C i i Ch 13 V 2010
.
09.
06 P Ni Ch 101 / 110
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Di i l C i i Ch 13 V 2010.
09.
06 P Ni Ch 102 / 110
Performance of RAKE receiver
Suppose ck t = ck. Then,
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( )Um = Re Lk=1
T
0r(t)ck sm, t k
Wdt
= Re
L
k=
1
T
0 L
n=
1
cns1,
t
n
W+ zW
(t
)ck s
m,
t
k
Wdt
= Re L
k=1
L
n=1
cnc
k T
0s1, t k
W sm, t k
Wdt
+Re
L
k=1
T
0
zW
(t
)ck s
m, t
k
Wdt
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Assumption (Add-and-delay property)The transmitted signal is orthogonal to its shifted
counterparts.
U d T TT
t k t k dt i l t
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Under T Tm,
T
0s
1, tk
W s
m, tk
Wdt is almostindependent of k,and nk = ReT0 zW(t)sm, t kWdtL
k=1Gaussian
white because
{s
m,
t k
W
}L
k=1 orthogonal;
hence, with k = ck,Um = Re L
k=1
ck2T0
s1, (t) sm, (t)dt+
Re L
k=1 c
k T
0 zW(t)sm, tk
Wdt=
L
k=1
2k
Re s1, t , sm, t +L
k=1
knk.
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Therefore, the performance of RAKE is the same as theL-diversity maximal ratio combiner if{k}Lk=1 i.i.d.However, {k = ck}Lk=1 may not be identically distributed.In such case we can still obtain the pdf of b =
L k (if
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In such case, we can still obtain the pdf ofb =
k=1 k (if
M= 2) from
characteristic function ofk k( ) = 11 k
characteristic function ofb =
L
k=1 k L
k=1 k( ) =L
k=11
1 k
The pdf of is then given by the Fourier transform ofcharacteristic function:
f() =L
k=1k
k e
k
where k =L
i=1,ik
k
k i.
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Then,
Pe =
12 Lk=1 k
1
k
1+k
2L1
L
Lk=1 14k , BPSK, RAKE
12 Lk=1 k
1
k
2+k
2L1
L Lk=1 12k , BFSK, RAKE
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Estimation of ckFor orthogonal signaling, we can estimate cn via
T
r t +n
s t + + s t dt
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0r t+ Ws1,(t) ++ sM,(t)dt
=L
k=1
ckT
0sm, t+ n
W
k
Ws1,(t) ++ sM,(t)dt
+
T
0 zt+n
Ws
1,(t) ++ s
M,(t)dt=
L
k=1
ckT
0sm, t+ n
W
k
W s
m,(t)dt+
T
0 zt+n
Ws1,(t) ++ sM,(t)dt (Orthogonality)= cn
T
0sm, (t) 2dt+ noise term (Add-and-delay)
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M = 2 case
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Decision-feedback estimatorThis previous estimator only works for orthogonal signaling.For, e.g., PAM signal with
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s(t) = I g(t) where I {1,3, . . . ,(M 1)},we can estimate cn via
T
0
r t+n
Wg
(t)=
T
0 L
k=1
ck I gt+ nW
k
W + zt+ n
Wg(t)
=
L
k=1 ck
I
T
0 gt+n
W
k
Wg
(t)dt+ noise term= cn I
T
0g(t) 2dt+ noise term (Add-and-delay)
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Final notes
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Usually it requires (t)cT > 100 in order to have an accurateestimate of{cn}Ln=1.Note that for DPSK and FSK with square-law combiner, it is
unnecessary to estimate {cn}Ln=1.So, they have no further performance loss due to aninaccurate estimate of
{cn
}Ln=1.
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