CHAMBO kounsakda

8/2/2019 CHAMBO kounsakda

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n tt nghip GVHD: Th.S Phan Th Bch Ngc

LI M U

Bia l mt loi nc gii kht ln men c cn thp, rt hp dn vi hng thmc trng v v ng d chu ca hoa houblon. Ngoi tc dng gii kht, bia cn cung

cp mt lng ln cc cht dinh dng, cc cht gip tng cng tiu ho c bit l

nhm enzim kch thch tiu ha amylaza v cc vitamin, nht l cc vitamin nhm B.

Bia c a vo Vit Nam t na cui th k 19. Ban u, n c coi l thc

ung xa x, ch c gii thng lu, giu c mi s dung. Nhng n nay, mt phn l do

i sng ca nhn dn ta so vi trc y tin b hn rt nhiu, mt phn l do c

nhiu nh my bia c xy dng trn t nc ta nn bia dn dn c s dng rng

ri trong nhn dn.Trong nhng cuc gp g, sum hp gia nh, trong cc cuc gp mt

lin hoan, trong cc bui tic...khng th thiu bia bi mt l, n gip cho khng kh vui

v, si ng hn rt nhiu.

nc ta trong khong 10 nm tr li y, ngnh cng nghip thc phm ni chung

v cng nghip sn xut bia ni ring c mt din mo mi vi nhiu nh my bia ra

i, nhiu sn phm mi c gii thiu rng ri... nhng vn khng p ng c nhucu tiu th bia ang ngy cng tng.

khc phc tnh trng ny chng ta phi ra cc cch gii quyt p ng nhu

cu ngy cng cao. Do ti chn ti tt nghip l:"Thit k nh my sn xut bia

ln men bng phng php lin tc nng sut 40 triu lt/nm" nhm cung cp c

mt lng bia kh ln cho th trng ang ngy cng m rng, hn ch vic nhp khu

bia ng thi tin n xut khu ra nc ngoi thu ngoi t cho t nc.

Thit k nh my bia 1 SVTH: Khounsakda Chambo


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CHNG 1: LP LUN KINH T K THUT

1.1. S cn thit phi u t

Nng hin nay tr thnh th loi I ca t nc, nn kinh t c nhng

bc pht trin vt bc, dn c tp trung ng c. Thm vo , cc im du lch nh

Non Nc, B N... ngy cng thu ht nhiu khch du lch trong nc v quc t, nhu

cu ch bin thc phm ngy cng tng v khng ngng pht trin, nht l nc gii

kht m quan trng nht l bia - mt loi nc ung c ng o ngi dn v khch

du lch a chung.

1.2. Phng n sn xut

Nh my bia c thit k lm vic theo phng php ln men lin tc s dng

nguyn liu l 58% malt i mch, 40% go v 2% ng saccarozo.

1.3. C s kinh t k thut

V v tr a l: a im xy dng nh my ti khu cng nghip Ha Khnh, cch

Quc l 1A khong 1km.

V kh hu: Nng nm trong vng kh hu nhit i gi ma. Nhit trung bnh

khong 260C n 280C, m trung bnh l 80%, hng gi ch o l hng ng

Nam.

1.3.1. H thng giao thng vn ti

V ng b, c quc l 1A ni trung tm thnh ph vi cc tnh khc, n cc

nc lng ging nh Lo, Campuchia. V ng thy, Nng c cng Tin Sa, cng

Sng Hn, rt thun tin khi lu thng hng ha vi cc tnh trong nc v nc ngoi.

1.3.2. Ngun nguyn liu

Nguyn liu chnh sn xut bia l malt i mch, hoa houblon v nc. Ngoi ra

nh my cn dng nguyn liu thay th l go.

Do kh hu, t ai nc ta khng trng c a mch v cy hoa houblon nn hai

nguyn liu ny c nhp t nc ngoi.



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Nguyn liu thay th l go c mua t cc tnh trong nc nh: Qung Nam,

Qung Ngi, Tha Thin Hu, Bnh nh,........ cc vng nguyn liu ny c kh nng

p ng nhu cu ca nh my mt cch y v kp thi

1.3.3. Ngun cung cp in

Nh my s dng ngun in ly t li in quc gia qua my bin p ring ca

nh my. Ngoi ra nh my cn trang b my pht in d phng dng trong cc thi

im cao im v phng khi mt in.

1.3.4. Ngun cung cp hi v nhin liu

Nh my dng l hi cp hi, nhin liu dng cho l hi l du FO.1.3.5.Ngun cung cp nc

Nh my ly nc ch yu t ngun ca nh my nc cung cp cho khu cng

nghip Ha Khnh.

1.3.6. H thng thot nc

Nc thi sau khi c x l s theo ng ng dn n ni cha nc thi x l

ca khu cng nghip, sau c dn ra sng.

1.3.7. Ngun tiu th sn phm

Th trng tiu th trong nc c bit l th trng min Trung. Bn cnh , cc

nc nh Indonesia, Malaysia, Philipin...l cc th trng c trin vng ln .

1.3.8. Ngun nhn lc

Nng tp trung i ng cng nhn lnh ngh k thut cao, i ng cn b, k s

gii thun li cho pht trin ca nh my.

1.3.9. Hp tc ho

Hin nay, c cc khu cng nghip pht trin mnh ca min Trung nh Ho Khnh -

Lin Chiu - Nng, khu cng nghip in Ngc - in Bn - Qung Nam, khu cng

nghip Dung Qut - Bnh Sn - Qung Ngi. y l iu kin tt cho s hp tc - lin

hp ho gia cc khu cng nghip, to ra s a dng sn phm, rt ngn thi gian hon

vn xy dng nh my, gim gi thnh sn phm.



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1.3.10. Thit b

Nh my ch yu nhp thit b t nc ngoi m bo tnh cng ngh. Bn cnh

, gim chi ph u t ban u th cng c th gia cng mt s thit b m n khng

nh hng n cng ngh.

Kt lun: Qua phn tch cc iu kin thc t nh trn cho thy vic xy dng nh

my bia ti khu cng ngip Ha Khnh- Lin Chiu- Nng l cn thit v kh thi.

Vi nng sut 40 triu lt/ nm c th p ng c nhu cu ca ngi tiu dng v gp

mt phn vo ngn sch nh nc.



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Chng 2: TNG QUAN NGUYN LIU2.1. Sn phm [ 16 ]

[ 16 ]

Bia l loi thc ung c t lu i. N hp dn ngi s dng bi nhng cng dng

chnh sau:

- Gim nguy c pht trin cc bnh tim mch

- Bia c th a mui nhm ra khi c th.

- Phn gii cht bo trong c th.

- Gip b my tiu ha lm vic tt hn

- Men bia c li trong vic phng trnh mt s bnh truyn nhim, ung nht, pht

ban, bnh tiu ng v mt s bnh ngoi da.

- Bia c cha mt s cht gip ng ngon hn, trnh cng thng v trm cm.

Trn th gii, bia c rt nhiu loi. Ngi ta c th phn loi bia theo mu sc nh

sau:

2.1.1. Bia en [ 16 ]

Bia en c trn thm mt t malt en v mt s cht to mu khc nh caramen.

Bia en c thnh phn la mch nhiu hn v li l loi la mch c sy kh cho c

mu en (cn gi l carafamalt).

Qu trnh bia en s i hi nhiu calo hn cc loi bia khc v chng cng

chuyn ha nhiu cht chng xy ha t la m v ng cc hn lm bia c v ngt c

trng.

Bia en ph bin Ailen, Anh.

2.1.2. Bia [ 16 ]

Ngi ta s dng nhng loi mch nha c bit lm nc hm nu bia mang li

mu hay mu h phch ca loi bia c bit . iu cn bn l loi mch nha mu

nu nht hay mch nha c nng k s mang li sc mu o cng nh ci hng



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v ring ca bia kia (khc vi bia vng l h s ch sy hay hong kh loi mch nha

thng thng thi).

Bia c s dng ch yu th trng M, Jamaica

2.1.3.Bia trng [ 16 ]

Bia trng l loi bia lm t la m (wheat) m c nu ch yu ti B, H lan. Bia

trng mang tn ny do bi cc men l lng (ln men ni) v cc protein ca la m lm

bia trng nh m m sng khi hay c mu trng khi bia c lm lnh.

2.1.4. Bia vng [ 16 ]

Bia vng c t l hoa houblon nhiu v l loi bia ph bin nht trn th gii, datheo cng ngh ca bia lager Pilsner Bohemia, Sc.

2.2. Nguyn liu

2.2.1. Malt i mch

- Malt i mch l ht i mch ny mm trong iu kin nhit , m nhn

to xc nh t hot lc enzim v thnh phn dinh dng ca ht mc

cn thit.

- Trong cng ngh sn xut bia, malt i mch va l tc nhn ng ho va l

nguyn liu c trng to nn sn phm.

- Yu cu ca malt i mch :

+Phi sch, c mi thm c trng, c v ngt, mu vng sng u.

+ Kch thc ht malt phi ng u

+ Khi lng ring ca malt trong khong 520 - 600gam/lt.

+ m ca malt khng qu 6%

+Malt c thi gian ng ho 10 - 35pht, hot lc amylaza cao.

2.2.2. Hoa houblon

Hoa houblon (Houmulns lupulus) l loi thc vt lu nin n tnh, thuc h Gaimo (Canabinaceac). c im ca ging ny l hoa c v hoa ci sinh ra trn hai



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thn khc nhau. Ngi ta trng hoa houblon thu nhng hoa ci cha th phn cho sn

xut bia, v nu s dng hoa ci c th phn s lm gim cht lng ca bia.

Chnh v vy m ngi ta phi tin hnh loi b ngay nhng cy c trong vn hoa

houblon.

Hoa houblon l nguyn liu ng v tr th hai sau malt i mch trong sn xut bia.

N truyn cho bia v ng du, hng thm rt c trng, n lm tng kh nng gi bt,

lm tng bn keo v n nh thnh phn sinh hc ca sn phm.

Nh my s dng hoa vin sn xut bia v u im l d bo qun, cht lng tt.

2.2.2.1. Thnh phn ha hc ca hoa houblon

Nha houblon :

Nha houblon l thnh phn chnh v rt quan trng ca hoa, bao gm nha cng v

nha mm. Trong nha mm c cc axit ng nh : - axt ng (gumulon), - axt

ng (lupulon), - axt ng (gumulinon) v - axt ng (gulupon), nha cng gm

- nha cng v - nha cng. Cc cht ng ngoi tc dng truyn v cho bia cn c tc

dng st trng. Trong cc nha th quan trng hn c l nha mm v ch yu nht l -axit ng

Cc tanin :

Tanin ca hoa d ha tan trong nc v trong dch ng, do trong qu trnh

houblon ha cc tanin cng d ha tan vo dch ng v d dng lin kt vi protein

cao phn t to thnh cc phc cht khng ha tan. Nh m loi tr c cc cu

t protein kh bin tnh v kt lng ra khi dch ng.Tanin ca hoa d b oxi ho nn n bo v nha houblon m c bit l - axit ng

khi b oxi ho. Mt khc, tanin tham gia vo vic hon thin v cho bia v c nh

hng n qu trnh nu bia.

Tinh du:

Tinh du hoa houblon l mt hn hp phc tp bao gm trn 100 hp cht khc

nhau, phn ln l nhng terpen, ru, xeton, aldehit, ester v axit. N khng ho tantrong nc nhng rt d bay hi theo hi nc. Hn 90% lng tinh du bay i trong



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qu trnh houblon ho. Mt t tinh du ho tan trong dch ng s tip tc bay hi

trong qu trnh ln men chnh v ph. Do trong bia thnh phm lng tinh du cn

li khng ng k, tuy nhin n gp phn lm cho bia thm hn.

2.2.2.2. Bo qun hoa nng cao hiu qu s dng

- Bo qun nhit thp (gn 00C)

- Ngn chn s xm nhp ca khng kh vo hoa

- Kho phi c cch m tt.

- C th c ch s hot ng ca vi sinh vt bng cch xng hi lu

hunh

2.2.3. Nc

Trong bia thnh phm, hm lng nc chim trung bnh khong 77 - 90%. Trong

nh my, nc c dng vi nhiu mc ch khc nhau nh l: nu, chit, thanh trng

v v sinh thit b ....nn lng nc c s dng rt ln. Tuy lng nc dng

trc tip nu bia khng nhiu nhng n nh hng nhiu n cht lng ca bia, do

nc dng nu bia phi m bo cc yu cu ca nc ung nh sau : trong sut,

khng mu, c v d chu, khng c mi v l v khng cha vi sinh vt gy bnh, m

bo cc yu cu cho cng ngh bia.

Cc cng on x l nc bao gm: lng trong v lc, lm mm nc, b sung cc

thnh phn cn thit cho nc v ci to thnh phn sinh hc ca nc.

2.2.4. Nguyn liu thay th

2.2.4.1. Go

Nh my s dng nguyn liu thay th l go. V kh nng thay th malt i mch

dng trong bia th go l loi ng cc c dng nhiu hn c. Ni nh ca go c th

l trng trong hay trng c. Ht trng trong c hm lng protein cao, ht chc v cng

hn. thay th malt i mch ngi ta thng chn ht go c trng c l tt

nht.



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2.2.4.2. ng saccarozo

Mt lng nh ng saccarozo b sung vo ni houblon nhm tng ng cho

dch ln men sau ny. ng l cht ha tan c th ln men c.



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2.3. Cht h tr v ph gia

2.3.1. Enzym

tng cng s thy phn trong khi nu, nh my s dng ch phm enzym -amylaza chu nhit, c tn thng mi l Termamyl, dng lng, c pH trung tnh,

trong phn t c ion Ca2+. Ch phm Termamyl c sn xut t dch nui cy vi khun

Bacillus licherifomis. Ch phm Termamyl dng dch ha nguyn liu giu tinh bt,

t l s dng l 0,05 0,1% so vi tinh bt. Ch phm ny c t0opt=95 1000C v hot

ng n nh nu trong dch thy phn c mt lng 50 70 ppm Ca2+.

Enzym Termamyl d dng tan trong nc mi nng trong iu kin thngdng. vn c c th xy ra trong ch phm enzym nhng khng nh hng ti hot

tnh chung hoc tnh nng sn phm.

i vi cng ngh sn xut bia, enzym ny c b sung vo ni go nhm ph

gip cho vic dch ha d dng. Do n nh nhit cao ca enzym nn quy trnh nu

c th c n gin ha. Nh th, vic gia tng t l cc loi nguyn liu khng cha

enzym cng c th thc hin c.

2.3.2. Ha cht

2.3.2.1. Axit lactic

Axit lactic l mt axit hu c, c dng iu chnh pH ca mi trng v mi

trng axit yu. Axit lactic ha tan tt trong nc v etanol, trong cng nghip axit

lactic c tng hp t vi khun lactobacillus.

Nh my mua axit lactic ngoi th trng b sung vo ni malt nhm iu chnh pHca dch v gi tr 5,66 to iu kin thun li cho qu trnh hot ng ca cc

enzym thy phn.

2.3.2.2. Cc ha cht khc

Cc loi ha cht c s dng di dng nguyn liu ph nhm khc phc nhng

yu cu k thut cn thit m trong qu trnh sn xut cha t ti, ta c cc loi ha

cht ch yu sau:



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+ Ha cht dng x l nc: than hot tnh (hp ph mi), Cl2 (c tc dng dit

khun), HCl, NaOH (ti sinh ht nha sau qu trnh trao i anion v cation a

nc nu v nc mm).

+ Ha cht v sinh thit b: dung dch NaOH, dung dch HCl, cht dit khun.

+ Cht tr lc: Diatomit.

2.3.3. Nm men

Nm men bia: C 2 loi.

- Saccharomyces cerevisiae - thuc loi ln men ni.

- Saccharomyces carlsbergensis - thuc loi ln men chm.

Hai chng nm men ny khc nhau v nhiu c im, nh khc nhau v ch cng

ngh, khc nhau v sinh l...

y ta s dng nm men chm, nhit ln men chnh l 8 0 - 100C v ngng ln men

00C.

2.4. Cc qu trnh sinh ho quan trng

Trong cng ngh sn xut bia c nhiu qu trnh sinh ho xy ra, nhng quan

trng nht l cc qu trnh xy ra cng on nu v ln men bia.

2.4.1. Cc qu trnh xy ra khi nu

Cc qu trnh xy ra trong khi nu c chia lm 2 nhm l: qu trnh enzym v

qu trnh phi enzym.

a) Qu trnh enzym:S thu phn tinh bt:

Tinh bt i tc dng ca h enzym amylaza s b thu phn thnh ng v

cc dextrin vi phn t lng khc nhau. ng c ngha ln vi qu trnh ln men

cn cc dextrin tuy khng ln men c nhng n gp phn quan trng vo vic hon

thin v ca bia.

S thu phn protein:



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Di tc dng ca enzym proteaza th protein b thy phn thnh cc axit amin

v cc sn phm c phn t lng ln hn nh peptit, peptone, polypeptit. Cc sn

phm thp phn t ca qu trnh thu phn nh axit amin v peptit l ngun dinh dng

nit cho nm men, cn pha c phn t lng trung bnh nh pepton v polipeptit to v

m , tham gia vo qu trnh to v gi bt cho bia. Tuy nhin nu hm lng ca

chng qu cao s lm cho bia d b c v kh bo qun.

S thu phn fitin:

Di tc dng ca h enzym fitaza xy ra s thu phn fitin to thnh axit

phosphoric v cc sn phm khc. Axit phosphoric l ngun dinh dng cung cp cho

nm men v ng vai tr quan trng trong vic to mi trng m thch hp cho cc

enzym hot ng.

S thu phn hemixenluloza v mt s cc cht khc:

Di tc ng ca enzym xitaza dn n s thu phn hemixenluloza v mt s

cht khc ca nguyn liu to thnh glucose, xilose, arabinose. S thu phn ny

mang 2 ngha l va b sung cht ho tan cho dch ng, va ph b hng ro chn,

to iu kin thun li cho cc enzym khc d dng tc ng.

b) Qu trnh phi enzym:

S kt lng v bin tnh ca protein:

Di tc ng ca nhit cao, mt phn protein b bin tnh v ng t. y l

yu t c li cho cng ngh sn xut bia v s loi c nhng protein d b bin tnh ra

khi dch ng lm tng bn keo ca bia tc l gim c kh nng gy c.

S to thnh melanoid:

y l mt phn ng c bit quan trng trong cng ngh sn xut bia. Tuy phn

ng ny gy ra hao tn axt amin v ng kh nhng vi mt lng melanoid va phi

li gp phn nng cao gi tr cm quan cho sn phm sau ny. Qu trnh to thnh

melanoid xy ra mt cch mnh m giai on sy malt, n giai on ng ho,

iu kin v nhit v cc yu t khc cha ti u cho qu trnh trn nhng d sao th

mt lng ng k melanoid cng c to thnh.



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Ngoi ra trong qu trnh nu cn xy ra phn ng gia cc mui ca nc v

photphat c trong khi cho, xy ra s ho tan cc thnh phn d ho tan ca malt vo

dung dch.

2.4.2. Ln men

2.4.2.1. Cc qu trnh xy ra khi ln men chnh

Qu trnh sinh l

Qu trnh sinh l th hin s sinh sn v pht trin ca t bo nm men. Nm men

sinh trng mnh nht trong thi k u ca qu trnh ln men chnh. y l giai on

tng s lng t bo m bo cho qu trnh ln men bia. Qu trnh sinh ha:

Qu trnh sinh ho c bn trong ln men chnh l s chuyn cc ng ln men

thnh ru v CO2, phn khng ln men c ch yu l dextrin, protein v cc cht

khong. Ngoi ra cn to cc sn phm ph: nh glyxerin, axt hu c, ru bc cao,

este, aldehit...

Qu trnh ha l: l nhng bin i ho l sau:

+ S thay i chua v nng lc m:

+ S thay i th oxy ho kh: th oxy ho kh gim dn

+ S ho tan CO2 v to bt: lng CO2 sinh ra trong qu trnh ln men chnh l rt

ln, mt phn nh (khong 0,2%) ho tan vo bia, cn phn ln l thi ra ngoi di

dng bong bng kh, cc bong bng ny ni ln b mt, dnh li vi nhau v to thnh

bt kh.

+ S kt mng ca cc t bo nm men: xy ra vo cui thi k ln men chnh, khi

nm men kt t ko theo cc cht l lng trong bia lm bia trong hn cn h nhit bia

non xung nm men kt lng tt hn

2.4.2.2. Cc qu trnh xy ra khi ln men ph v tng tr bia

+ S ho tan v lin kt ca CO2 trong bia: trong bia non cha khong 0,2% CO2 m

yu cu hm lng CO2 trong thnh phm khng nh hn 0,3% do phi b sung

thm CO2 cho bia, CO2 sinh ra khi ln men phn ng cn li trong bia l ngun b



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sung CO2 cho bia thnh phm. CO2 c trong bia tn ti s cn bng ng nh sau: CO2

lin kt CO2 ho tan CO2 dng kh.

+ S lm trong bia: bia non cn cha nhiu t bo nm men v cc cht huyn ph

khc cho nn cn c. Nhit ln men ph thp hn nhit ln men chnh nn xy ra

qu trnh ng t cc hp cht cao phn t.

+ Qu trnh xy ho kh v s hon thin cht lng ca bia: qu trnh tng tr cn

xy ra cc phn ng gia cc cht c trong bia lm tng thm hm lng este, ru bc

cao, v gim i hm lng diaxetyl c trong bia. Sau khi tng tr v ca bia tr nn

mm v du hn.



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CHNG III: DY CHUYN CNG NGH

3.1. S cng ngh sn xut bia



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3.2. Thuyt minh dy chuyn cng ngh

3.2.1. Lm sch

3.2.1.1. Mc chLm sch tch ht bi bn, loi b nhng tp cht nh: l kh, lng chim, kim

loi ln trong nguyn liu; i vi malt cn loi b phn r, mm cn st li loi cc

ht c kch thc nh qu hoc ln qu li nhng ht c kch thc ng u thun

li cho qu trnh nghin.

3.2.1.2. Tin hnh

Cu to:

Nguyn tc hot ng:

Ngn trn cng c gn li sao cho nguyn liu v cc tp cht nh c th lt qua

c, cn cc tp cht ln c gi li trn li v c a ra ngoi. Ngn th hai c

gn li vi cc l li ln hn m bo khng cho nguyn liu lt qua li m ch cho

cc tp cht nh hn qua ri a ra ngoi, nguyn liu c gi li trn li v c vt

ti a i nghin. tch cc tp cht c kch thc nh, nh cng vi bi bay l lng

ln trn th sn rung ca go v malt c gn thm qut ht dn bi ra ngoi.


3

3

Hnh 3.1: Thit b lm sch

Nguyn liuTp cht lnBiTp cht b

Nguyn liu sch

4


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3.2.2. Nghin nguyn liu

3.2.2.1. Mc ch nghin

Mc ch nghin l nhm ph v cu trc t bo ca ht, to iu kin thun li khi nu thu c mt dch ng c nng cao nht. Yu cu sau nghin:

*Malt:

+V cng nguyn cng tt. V nguyn s lm tng tc lc.

+Khi nghin cn to mt t l thch hp gia tm th, tm mn v bt.

*Go: phi tin hnh nghin mn trong qu trnh nu cc cht tinh bt, protein,

chuyn sang dng ho tan nhanh hn.

3.2.2.2. Phng php thc hin

My nghin trc (nghin malt):

- Cu to: .

Nguyn tc hot ng:

Malt c vo phu v c nghin s b cp rul th nht. Khong cch gia 2

trc nghin ca cp rul th nht ln hn so vi khong cch gia 2 trc nghin ca cp

rul th 2. Sau khi nghin s b, bt malt c a vo rul th 2 nghin tip.


Malt

Trc nghin

Hnh 3.2: My nghin trc (nghin malt)


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- My nghin ba ( nghin go ):

+ Cu to:

+ Nguyn tc hot ng:

Nguyn liu c a vo my nghin ba qua phu np liu (1). Go c nghin

nt nh vo lc va p ca ba nghin (2) vo thnh trong ca my nghin ba. Ba

c lp trn a treo s (4), cc ba c treo cch u nhau. Go sau khi c nghin

mn s i qua li s (3) ra ngoi v c a vo bunke cha.

3.2.3. Nu bia

3.2.3.1. Mc ch

Chuyn cc cht c trong nguyn liu t trng thi khng ho tan sang trng thi ho

tan nh tc ng ca cc h enzim thu phn.

3.2.3.2. Phng php nu

C ba phng php nu bia l phng php ngm, phng php un si v phuong

php kt hp, vi mi phng php c u nhc im ring v nh my c s dng

45% nguyn liu thay th giu tinh bt nn s dng phng php kt hp gia ngm v

un si mt ln l hp l nht.


1. Phu np liu2. Ba3. Li4. a treo5. Trc quay

Hnh 3.3: My nghin ba (nghin go)


19/109


3.2.3.2. Tin hnh nu

+Ni go:

u tin ng van x ni, bt cnh khuy, m van ly nc vo ni vi t l 5lit/1kggo, nc c nhit khong 320C. Sau cho vo ni 1/2 lng malt lt . Bt go

nghin mn cho vo ni nu khuy trn trong 5 pht. Sau khi khuy trn nhit

khi nu khong 300C, b sung axit lactic h pH xung cn 5,6. Tip theo gia nhit

nng nhit t 300C ln 660C trong khong 30 pht. Gi 660C trong 30 pht h

ha dch bt. Thm 50% lng malt lt cn li vo v ng thi lc ny b sung enzim

Termamyl ng ha tinh bt. Nng khi nu ln n nhit si trong 30 pht, gi

nhit ny trong 20 pht v em i hi cho.

+Ni malt:

Cho nc m 320C vo trc ri tin hnh xung bt ho malt trong 10 pht, t l

malt: nc l 1kg/4,5lt nc Dng axt lactic h pH ca mi trng n 5,6 ri tin

hnh nng nhit ln 520C mt khong 30 pht, gi nhit ny 20 pht. Phi tnh

sao cho khi ni cho go un si xong th qu trnh m ho ni malt cng va kt

thc. Bm cho go sang ni malt hi cho, mt khong 10 pht. Khi hi cho xong

th iu chnh nhit chung ca ton khi sao cho t 630C, gi 630C trong 25 pht

to iu kin cho enzim -amylaza thu phn tinh bt. Sau nng nhit ca

khi dch ln 730C trong vng 10 pht v gi nhit ny 25 pht enzim -

_amylaza tip tc thu phn tinh bt. Cui cng nng nhit ca ton khi nu ln

780C trong vng 5 pht ri sau bm dch i lc.



20/109


S NNG V GI NHIT CA QU TRNH NU

3.2.4. Lc dch ng

3.2.4.1. Mc ch

Dch ng ho bao gm cc cht ho tan v cht khng ho tan nn cn phi lc

tch cc cht ho tan ra khi cc cht khng ho tan.


Ni go

Ni malt

Hi cho

6 6

ts i

7 87 3

6 3

5 2

3 0

5 3 5 5 5 6 5 9 5 1 1 5 1 2 5 1 5 0 1 6 0 1 8 51 9 00

3 2 5 '

3 0 '

3 0 '

3 0 '

2 0 '

1 0 '

2 5 '1 0 '

2 5 ' 5 '

1 0 '

3 0 '

2 0 '1 0 '

t (ph

C


21/109


3.2.4.2. Thit b lc y bng


Hnh 3.4: Thit b lc y bng

1. Dch cho vo2. Dch ng ra3. Cnh gt b4. Cnh xi b5. Ca thot b hm6. ng c7. y li gi8. ng nc v sinh9. ng nc ra b10.Ca quan st11.Lp cch nhit12.Cc ng gom


22/109


3.2.4.3. Tin hnh lc dch ng

Trc ht l lc khi cho thu c dch ng u. Dch ng lc chy t trn

xung qua li lc. Dch lc c chy vo cc ng gp v chy tp trung vo cc vng

trn sau chy vo thng cha. Trong vng 15 pht u tin, dch ng chy ra cn

c nn bm hi lu v. Khi dch ng t c trong cn thit th cho qua thit b

houblon ho.

Sau khi lc xong th tin hnh ra b bng nc 78oC.

Qu trnh lc thng ko di khong 4 gi.

3.2.5. Houblon ho3.2.5.1. Mc ch ca vic houblon ho

Mc ch:

un si dch ng vi hoa houblon l n nh thnh phn ca dch ng,

truyn cho bia c mi v v ca hoa houblon, lm cho dch ng t nng theo yu

cu, lm keo t cc protein, v hot cc enzim v thanh trng dch ng.



23/109


3.2.5.3. Tin hnh houblon ho

Thit b houblon ha cng ging nh thit b nu nhng c b mt truyn nhit

ln hn do qu trnh houblon ha cn lm bay hi mt lng ln nc.Vt liu ch to tt nht l thp khng g.

Tin hnh: Dch ng v nc ra b t thit b lc chuyn vo ni houblon

ha. Dch ng lp y y ni th bt u cung cp nhit nhit dch ng lun

gi 7075oC. Duy tr nhit ny enzym -amylaza tip tc thy phn tinh bt

st. Khi nc ra b chy vo ni houblon ha gn kt thc th bt u nng nhit un

si.

3.2.6. Lng trong v lm lnh

3.2.6.1. Mc ch

Mc ch:

- H nhit dch ng n nhit ln men, kt ta cc huyn ph v bo ho xy

cho dch ng.

3.2.6.2. Phng php tin hnh lng trong v lm lnh

Cu to:


Hnh 3.5: Thit b lng trong

1. ng thot hi2. V thng3, 4 ng tho dch ng5. Ca thot b

6. Dch ng vo7. ng nc v sinh8. Ca lm v sinh


24/109


Nguyn tc hot ng:

Dch ng c a vo ni theo ng ng (6), theo phng tip tuyn vi thnh

thng, vn tc dch vo thng phi t 10 14 m/s nhm to mt sc y mnh, lc ny

lm cho c ct cht lng xoy trn. V th, dch ng sau khi vo thit b s chuyn

ng trn di tc dng ca lc hng tm, cn s lng tm thit b. Sau khi chuyn

ht dch ng vo thit b, yn trong 20 pht ri tho ra ng trn s (3) phn

di tip tc lng, tip tc tho ra qua ng di (4). Cn hoa c co v tho ra

ngoi qua ca tho b s (5). Sau m nc theo ng ng s (7) v sinh thit b.

3.2.6.3. Thit b lm lnh: thit b trao i dng tm

Cu to:

Nguyn tc hot ng

Dch nha c nhit 90- 95oC c bm vo 1 mng dn pha di, cn tc

nhn lnh l glycol lnh c bm vo 1 mng dn pha trn. Dch nha nng v

nc lnh i ngc chiu thc hin qu trnh trao i nhit, nh m nhit ca

dch nha nng h xung n nhit ln men 8oC v c a ra ngoi theo mng dn

pha trn, cn nc lnh sau khi trao i nhit vi nha nng thnh nc nng ra khi

my theo mng dn pha di.


Nha lnh

Nha nngvo

Nc nngra

Nc lnh

Hnh 3.6: Thit b lm lnh


25/109


3.2.7. Ln men

3.2.7.1. Ln men chnh

Mc ch ca qu trnh ln men chnh:

Nh tc ng ca enzim vi sinh vt chuyn ho ng thnh ru, CO2 v cc sn

phm khc gp phn to nn hng v cho bia.

Tin hnh ln men:

y ta s dng nm men chm, nhit ln men chnh l 8 0C v ngng ln men

00C.

S CNG NGH LN MEN LIN TC CA NH MY C M T

NH SAU:

H thng ny bao gm 4 thng ln men chnh (6) v 10 thng ln men ph (13) vcc thit b ph tr khc nh h thng lc khng kh (1), cc bm... H thng ny c

t trong bung lnh. Qu trnh ln men chnh v ph c tin hnh trong cc thng

ln men kn ni vi nhau bng ng chy chuyn v to thnh mt h thng lin tc.

Dch ng sau khi lng trong v lm lnh c chuyn n thng tip liu (2), ti

y n c chuyn i ln men v nhn ging. Men ging thun khit c a vo

thng (4) theo nh k 2 thng 1 ln. Dch ng lin tc c chuyn vo v dch men

c hot lc cao c lin tc a ra khi thng (4) vi th tch bng th tch dch ng


Hnh 3.7: S ln men lin tc


26/109


a vo. Qu trnh nui ging trong thng (4) c thc hin 100C v c sc khng

kh c v trng nh (1).

Nh h thng bm nh lng (5), dch ng t thng tip liu (2) v dch men

ging t thng (4) lin tc c a vo thng ln men chnh (6) vi t l 92:8. Nng

nm men trong thng ln men u tin l 70 triu t bo/1ml. Cc thng ln men chnh

(6) phi ni vi nhau sao cho dch ng i vo pha di v i ra t pha trn thng.

Bm (5) phi iu khin sao cho dch ng lu li trong mi thng la 24h.

Dch ng v men ging chy chuyn t thng u sang thng sau v tin hnh ln

men chnh nhit 8 - 90C cho n khi t ln men cn thit. Qu trnh ln men

chnh ko di 4 ngy m v p sut 0,2-0,3at.

Sau khi ln men chnh xong bia non c tp trung vo thng cha (7) ri nh bm

(8) chuyn vo thit b ly tm kn (9) tch bia non ra khi b men. B men c a

vo thng cha ri x l, bo qun v ti s dng. Cn bia non chy vo thng cha

(11) v c b sung thm mt lng bia non khng qua ly tm m bo nng

ca nm men trong bia non l 12 - 15 triu t bo /1lit. Sau bm (12) bm bia non t

thng (11) sang thng ln men ph u tin cua h thng (13). Cc thng ln men phcng c ni vi nhau nh cc thng ln men chnh v bia non cng lu li mi

thng 1 ngy m. S ngy ln men ph l 10 ngy, nhit ln men ph 1-20C v p

sut trong thit b ln men ph l 0,5-0,6 at. Bia t thng ln men ph c chuyn vo

thng cha (14) v t y c a i lc.

i vi h thng ln men lin tc iu ti k l nhim tp. Nu mt khu no

c xy ra s c th kh nng b nh hng c h thng l rt cao. Do , m bo dy

chuyn lm vic bnh thng v thnh phm c cht lng cao th cn phi m bo v

sinh thit b. C 2 thng 1 ln phi tin hnh tng v sinh v st trng ton b h thng,

ng thi phi tin hnh thng xuyn vic v sinh st trng thng tip liu v thng

men ging.



27/109


3.2.8. Lc bia

3.2.8.1. Mc ch

Lc bia bia t trong cn thit, lm tng gi tr cm quan, lm tng bn keoca bia.

3.2.8.2. Tin hnh

Dng h thng lc vi cht tr lc diatomit. u tin, bt diatomit c trn cng

vi nc v trng ri dng bm a dung dch ny vo my lc p tch ht nc, to

thnh mt lp lc diatomit. Tip theo, bia c lc qua lp lc ny.

3.2.8.3. Thit b lc a

Cu to :

Nguyn tc hot ng

Bia non c a vo my lc qua ca (1), do cc a lc c gn trn h thng

trc quay nn cn bia vo c phn phi u trn b mt a. Cu to ca a lc gm

c b mt li (8) c ph sn mt lp bt tr lc c kch thc ln. Khi bm bia vo

lc ngi ta b sung thm bt tr lc c kch thc ht nh hn. Cn bia, xc men, v

bt lc c phn phi u trn b mt li lc lm thnh mt lp tr lc tt. Bia c

lc trong nh vo s chnh lch p sut thy tnh ca dch lp trn v lp di b mt

lc, sau bia trong c thu hi qua ng ng gp gia (5). Khi lc xong ta tin


1. ng ng bia vo2. ng ng thng p3. ng ng CIP4. ng ng x y5. ng ng bia ra6. Ca x7. Trc my lc8. Li lc9. Bm x bt10. Van an ton

10

7

6

8

5

9

4

32

1

Hnh 3.8: Thit b lc a


28/109


hnh v sinh my lc, dng bm s 9 bm bt lc ra ngoi a v x theo ng s

(4) hay ca s (6).

3.2.9. n nh bia

Bia sau khi lc th hm lng CO2 b gim do khi phc li s bo ho CO2

trong bia th sau khi lc, bia c gi trong thng cha nhit 0,5-1 0C di p sut

ca CO2 l 0,5at v thi gian ti thiu l 4 gi. Hm lng CO 2 trong bia thnh phm

phi t t nht l 0,3% khi lng; cha t phi b sung CO2 cho bia.

3.2.10. Chit v ng np

Bia sau khi n nh xong c chit vo chai thu tinh mu xanh m, c th tch500ml. Chai a vo rt phi c tiu chun v kn, nguyn vn, v kch thc,

sch. Trc khi rt, chai c ra v st trng k bng nc nng 65 0C v dung dch

NaOH 2% c b sung stabilon lm bng chai, sau chai c lm ngui ri rt bia

vo. Bia rt trong iu kin ng p trnh tn tht CO2 v trnh tro bt gy tn tht

sn phm. Bia sau khi qua my chit s qua my ng np.

3.2.11. Thanh trng

Nh my s dng my thanh trng kiu tunel qua cc vng: vng lm nng, vng

thanh trng v vng lm ngui.

+ Vng lm nng: 3 khoang vi nhit : K1: 280C, K2: 400C, K3: 520C.

+ Vng thanh trng: c 2 khoang vi nhit : K 4: 680C, K5: 640C

+ Vng lm ngui: c 3 khoang vi nhit : K6: 520C,K7: 400C,.K 8: 280C

Trong qu trnh thanh trng, p sut ca bia trong chai s tng ln do s gii phngCO2. Do vy, khong khng trong chai ti thiu l 5% so vi tng th tch ca chai, nu

khng p sut tng ln c th lm v chai. Chai c np vo 1 u v c di chuyn

di cc vng c phun nc cc nhit khc nhau. Tng thi gian thanh trng l 55

pht, nhit thanh trng l 680C

3.2.12. Hon thin

Sau khi thanh trng xong, chai bia c qua my dn nhn, ri c a vo kt vsau a vo kho bo qun tiu th.



29/109




30/109


Chng 4: TNH CN BNG SN PHM

4.1. Cc s liu ban u

- bia ca sn phm: 10,50

- T l nguyn liu dng:

+ Malt i mch : 50%

+ Go : 45%

+ ng saccarozo : 5%

- Nng sut ca nh my : 40 triu lt/nm.

- Cc thng s trng thi ban u ca nguyn liu:

+ m ca malt : 5,5%

+ m ca go : 11,5%

+ m ca ng : 0,05%

+ chit ca malt : 81%+ chit ca go : 81,5%

+Tp cht trong ng: 2,5%

Bng 4.1:Bng tiu hao nguyn liu qua cc cng on

Cng on Tiu hao (%)Lm sch 1Nghin 1Nu, lc 3

Houblon ha 2Lng trong 1Lm lnh 0,5

Ln men chnh 1Ln men ph 0,5

Lc bia 1n nh bia 0,5

Chit rt v ng np 2

Thanh trng 2



31/109


Bng th hin t l hao ht qua tng cng on. Mc hao ht trong qu trnh lm

sch, nghin, nu, lc, lng trong, tnh theo phn trm cht kh ca nguyn liu trc

. Cn hao ht trong cc qu trnh lm lnh, ln men, lc bia, chit rt v thanh trng

c tnh theo phn trm th tch trc . Lng hoa houblon s dng: 2g/lit dch

ng em un si.

4.2. Tnh cn bng sn phm

4.2.1. Chn s m nu trong mt ngy

Theo quy trnh nu v s nu chn mc (3.2.3.2), thi gian nu 1 m l 190

pht nhng do 2 ni nu song song nhau nn thi gian nu trung bnh 1 m l 140 pht.

Chn s m nu trong mt ngy l 10 m.

Nh my lm vic 12 thng trong mt nm, ngh cc ngy l theo quy nh ca nh

nc, tt v ch nht, nu ngy l ng vo ngy ch nht th ngh b vo ngy sau.

Phn xng nu lm vic 3 ca/ngy, phn xng chit lm vic 2 ca/ngy. Ring i vi

phn xng ln men, do c th ca cng ngh nn lm vic lin tc. Cc thit b c th

c v sinh vo ngy ch nht.

4.2.2. Biu sn xut ca nh my

Bng 4.2:Biu sn xut ca nh my


Thng 1 2 3 4 5 6 7 8 9 10 11 12C

nm

S ngy lmvic/thng

25 20 27 26 25 26 26 27 25 26 26 27 306

S calm

vic /thng

Phnxng nu

75 60 81 78 75 78 78 81 75 78 78 81 918

Phnxng

chit rt50 40 54 52 50 52 52 54 50 52 52 54 612

S m nu / thng 250 200 270 260 250 260 260 270 250 260 260 270 3060


32/109


4.2.3. Tnh cn bng vt cht cho 100 kg nguyn liu ban u

4.2.3.1. Lng cht kh trong nguyn liu

+ Malt: 50(100 5,5)100

= 47,25 (kg)

+Go:45(100 11,5)

39,83100

= (kg)

+ ng:5(100 0,05)

5100

(kg)

4.2.3.2. Lng nguyn liu ht cn li sau khi lm sch

Cht kh:

+ Malt :100 1

47,25 46,78( )100

kg

=

+ Go :100 1

39,83 39,43100

= (kg)

Nguyn liu:

+ Malt :46,78 100

49,50100 5,5

=

(kg)

+ Go :39,43 100

44,55100 11, 5

=

(kg)

4.2.3.3. Lng nguyn liu ht cn li sau khi nghin

Cht kh:

+ Malt :100 1

46,78 46,31100

= (kg)

+ Go :100 1

39,43 39,03100

= (kg)

Nguyn liu:

+ Malt :46,31 100

49,01

100 5,5

=

(kg)



33/109


+ Go :39,03 100

44,10100 11, 5

=

(kg)

4.2.3.4. Lng cht kh ca ht chuyn vo dch ng sau khi nu

+ Malt: 46,31100

81= 37,51 (kg)

+ Go:81,5

39,03 31,81100

= (kg)

Tng lng cht kh chuyn vo dch ng sau nu: 37,51 + 31,81 = 69,32 (kg)

4.2.3.5. Lng cht kh ht cn li sau qu trnh nu v lc

100 369,32 67,24

100

= (kg)

4.2.3.6. Th tch ca dch ng khi un si

Nng cht kh ca dch ng sau khi lng trong v lm lnh l 10,5%, trong qu

trnh houblon ho c mt lng nc bay hi lm nng ca dch ng tng khong

1-1,5%, ta chn 1%, cn qu trnh lm lnh, nng ca dch ng tng khong 0,4-

1,2% ta chn 0,5%, do cn phi khng ch nng dch ng trc khi houblonho l: 10,5-1-0,5=9%.

Khi lng ring ca dch ng 9% 20C l: 1033,65 (kg/m). [6- 58]

Khi lng dch ng t 100 kg nguyn liu ban u sau khi b sung ng vo

l:100 2,5 100

(67,24 5 ) 801,28100 9

+ = (kg)

Th tch ca dch ng trc khi un si (quy v 20C):

3801,28 0,775( ) 775( )1033,65

= =m lit

V hm lng cht chit nh hn nhiu so vi hm lng nc trong dch ng

nn ta tnh th tch dch ng theo th tch nc.

Ta c:

Th tch ring ca nc 20C l: 1000,77.10-6m/kg



34/109


Th tch ring ca nc 1000C l: 1043,43.10-6 m/kg [6- 11]

Th tch dch ng khi un si l:6

6

775 1043,43.10808,04

1000,77.10

= (lt)

4.2.3.7. Lng cht kh cn li sau houblon ha l

100 2,5 100 2

(67,24 5 ) 70,68100 100

+ = (kg)

4.2.3.8. Lng dch ng cn li sau khi houblon ha

Lng ng cn li sau houblon l:

70,68 100706,8

9 1

=

+ (kg)

Khi lng ring dch ng 10% 200C l :1039,98 kg/m [6- 58]

Th tch dch ng sau khi houblon ho 1000C:

706,8

1039,98=

6

6

10.77,1000

10.43,10430,708(m3) = 708(lit)

4.2.3.9. Khi lng ca dch ng sau lng trong:

Lng cht kh cn li sau qu trnh lng trong:100 1

70,68 69,98100

= (kg)

Khi lng ca dch ng sau lng trong:

69,98 100666, 48( )

10,5

= kg

4.2.3.10. Th tch ca dch ng sau lng trong

Sau lng trong, nng dch ng l 10,5%

Khi lng ring ca dch ng 10,5% 200C l 1042,05 kg/m [6- 58]

Th tch ca dch ng sau lng trong 200C l :666,48

1042,05= 0,640 (m3) = 640(lit)

Sau khi lng trong, nhit dch ng lc ny gim cn khong 90 0C th c s

gim th tch ca dch v ta coi s gim ny cng l s gim th tch ring ca nc

theo nhit .



35/109


Th tch ring ca nc 200C l :1000,7710-6 m/kg

Th tch ring ca nc 900C l :1035,9010-6m/kg

Nh vy th tch ca dch ng sau lng trong :6

6

640 1035,90.10662,13

1000,77 10

=

(lt)

4.2.3.11. Lng cht kh cn li sau qu trnh lm lnh

(100 0,5)69,98

100

= 69,63

4.2.3.12. Khi lng ca dch ln men t 100kg nguyn liu ban u

100 69, 63

10,5

= 663,14 (kg)

4.2.3.13. Th tch ca dch ln men

Khi lng ring ca dch ng 10,5% 200C l: 1042,05 kg/m3 [6- 58]

Th tch ca dch ng 10,5% 200C l:

663,14

1042,05= 0,63638 (m3) =636,38 (lt)

Khi lm lnh dch ng n nhit ln men (80C) th c s gim th tch ca dch

ln men v ta coi s gim ny cng l s gim th tch ring ca nc theo nhit .

Th tch ring ca nc 200C l 1000,77.10-6m3/kg [6- 12]

v 80C l 1000,12.10-6m3/kg

Nh vy th tch ca dch ln men l :

6

6

1000,12 10636,38

1000,77 10

= 635,97 (lit)



36/109


4.2.3.14. Lng bia non sau khi ln men chnh

100 1635,97 629,61( )100

lt =

4.2.3.15. Lng bia cn li sau khi ln men ph v tng tr bia non

100 0,5629,61 626,46

100

= (lt)

4.2.3.16. Lng bia cn li sau khi lc

100 1626,46 620,20100 = (lt)

4.2.3.17. Lng bia cn li sau khi n nh

620,20100 0,5

100

= 617,10 (lt)

4.2.3.18. Lng bia sau chit rt v ng np

100 2617,10 604,76( )100 lt

=

4.2.3.19. Lng bia sau thanh trng

100 2604,76 592,66

100

= (lt)

4.2.3.20. Lng hoa houblon cn dng

Lng hoa nh my s dng l 2g/lit dch ng.

T th tch dch ng tnh mc 4.2.3.6 ta tnh ra lng hoa nguyn cnh cn

dng l:

808,04 2 = 1616,08 (g) = 1,62 (kg)

Nh my s dng hoa vin m 1g hoa vin thay th cho 3g hoa nguyn cnh. Vy lng

hoa vin cn dng l:1,62

0,54

3

=



37/109


4.2.3.21. Lng b nguyn liu

Thng thng c 100 kg nguyn liu ban u, sau khi nu v lc thu c khong

125 kg b t c m 75%. [10- 76]Lng nguyn liu sau khi nghin: 49,01 + 39,03 = 88,04 (kg)

Lng b t thu hi c:88,04 125

100

= 110,05 (kg)

4.2.3.23. Lng cn lng khi lng trong v lm lnh

Thng c 1 lt dch ng un si th lng cn lng l 0,05 gam. Vy lng cn

thu c l :

808,04 0,05 = 40,40 (g)

4.2.3.24. Lng men ging c cn dng

C 100 lt dch ln men th cn 0,9 1% lt men ging c

Chn t l l 1%, do lng men ging cn dng l :

635,97 1

100

= 6,36 (lt)

4.2.3.25. Lng ch phm enzyme s dng

B sung enzym Termamyl vo ni nu vi t l 0,05-0,1% so vi nguyn liu. Chn

0,1%, ta c lng enzym Termamyl s dng:

0,144,10

100 = 0,0441 (lt) = 44,10 (ml)

4.2.3.26. Lng CO2 thu c

ln men biu kin i vi bia vng t 60% n 65% , ln men thc lun nh

hn ln men biu kin. [10- 61]

Chn ln men thc l 55%.

Vy lng cht kh ha tan ln men l :

69,63 55100

= 38,30 (kg)



38/109


Phn ln cc cht ln men c trong dch ln men l disaccarit. Nn qu trnh ln

men c biu din bi phng trnh :

C12H22O11 + H2O 2C6H12O6

342

2C6H12O6 4 C2H5OH + 4CO2 + Q

176

Lng CO2 sinh ra :

38,30 176

342

= 19,71 (kg)

Hm lng CO2 trong bia chim 0,3%-0,45%, ta chn 0,4%, do hm lng CO2

trong bia l :

613, 95 0, 4

100

= 2,46 (kg)

Vy lng CO2 t do thu hi c :

19,71 2,46 = 17,25 (kg)

4.2.3.27. Lng men thu hi

Thng c 100 lt dch ln men th thu c 2 lt men b c m 85%, trong s

ch c 0,8 lt dng lm men ging, s cn li c s dng vo mc ch khc.

- Lng men b thu hi c:

635,97 212,72100 = (lt)

- Lng men ging thu hi c:

635,97 0,8

100

= 5,09 (lit)

- Lng men s dng cho mc ch khc:

12,72 5,09 = 7,63 (lit)



39/109


4.2.4. Tnh cn bng sn phm cho mt ngy

Nh tnh phn (4.2.3.17), t 100 kg nguyn liu ban u sn xut c 45,625

lt bia thnh phm. Nh vy, vi nng sut 40 triu lt/nm th lng nguyn liu cn

dng cho mt nm l:640 10 100

6749232,28592,66

= (kg)

Lng nguyn liu cn cho mt ngy l:6749232,28

22056,31306

= (kg)

4.2.4.1. Lng nguyn liu ban u

-Malt : 50 22056,31 11028,16100 = (kg)

-Go:45 22056,31

9925,34100

= (kg)

-ng saccarozo:5 22056,31

1102,82100

= (kg)

4.2.4.2. Lng nguyn liu sau khi lm sch

- Nguyn liu:

+ Malt:49,50 22056,31

10917,87100

= (kg)

+ Go:44,55 22056,31

982608,61100

= (kg)

4.2.4.3. Lng nguyn liu sau nghin

- Nguyn liu:

+ Malt:49,01 22056,31

10809,80100

= (kg)

+ Go:44,10 22056,31

9726,83100

= (kg)

4.2.4.4. Lng dch ng un si

808,04 22056,31100

= 178223,80 (lt)



40/109


4.2.4.5. Lng dch ng sau houblon ho 100C

708 22056,31

100

= 156158,70 (lt)

4.2.4.6. Lng dch sau lng trong

662,13 22056,31146041,45( )

100lt

=

4.2.4.7. Lng dch ln men

635,97 22056,31140271,52

100

= (lt)

4.2.4.8. Lng bia sau ln men chnh

629,61 22056,31138868,70

100

= (lt)

4.2.4.9. Lng bia sau ln men ph

626,46 22056,31138174

100

= (lt)

4.2.4.10. Lng bia sau lc

620,20 22056,31136793,20

100

= (lt)

4.2.4.11. Lng bia sau n nh

617,10 22056,31136109,50

100

= (lt)

4.2.4.12. Lng bia sau chit, ng np

604,76 22056,31133387,70

100

= (lt)

4.2.4.13. Lng bia sau thanh trng

592,66 22056,31

130718,90100

= (lt)



41/109


4.2.4.14. Lng hoa houblon cn dng

1,62 22056,31

357,31100

= (kg)

4.2.4.15. Lng b nguyn liu

110,05 22056,3124272,97

100

= (kg)

4.2.4.16. Lng b hoa

4,85 22056,31

1069,73100

= (kg)

4.2.4.17. Lng men ging c cn dng

6,36 22056,311402,78

100

= (lt)

4.2.4.18. Lng b men thu hi

12,72 22056,312805,56

100

=

4.2.4.19. Lng men thu hi

5,09 22056,311122,67

100

= (lt)

4.2.4.20. Lng b men s dng cho mc ch khc

7,63 22056,311682,90

100

=

4.2.4.21. Lng ch phm Enzym s dng

0,0441 22056,319,73

100

=

4.2.4.22. Lng CO2 thu hi

17,25 22056,313804,71

100

= (kg)



42/109


4.2.5. Chi ph bao b

4.2.5.1. Lng v chai

Nh my dng chai c dung tch 500ml cha bia.

Lng v chai cn dng trong mt ngy l:130718,90

2614380,5

= (chai)

Chu k quay vng chai l 30 ngy v lng chai hao ht l 5%/ chu k.

Lng chai cn s dng trong 1 chu k l: 261438 30 7843140 = (chai)

Lng chai cn s dng trong 1 nm: chu k + hao ht:

7843140 57843140 8235297

100+ = ( chai )

4.2.5.2. S lng nhn

Nh my s dng 1nhn/1 chai vi lng hao ht nhn l 3%/nm.

Lng nhn cn dng cho mt nm:130718,90 100 306

824741930,5 97

=

(nhn)

4.2.5.3. Lng np y

Lng hao ht np khong 3%/nm.

Lng np cn dng cho mt nm:130718,90 100 306

824741930,5 97

=

(np)

4.2.5.4. Kt ng chai

Nh my dng loi kt: 20 chai/kt .

Lng kt cn dng trong mt chu k l:7843140

39215720

= (kt)

Chn lng kt hao ht l: 2%/chu k. Do , lng kt cn b sung

trong mt nm l: 392157 0,02 12 94117,68 = (kt)

S kt cn cung cp cho mt nm: Nk t = 392157 94117,68 486274,68+ = (kt)



43/109


Bng 4.3


STT

Tn nguyn liu, bn thnh phm,thnh phm, ph liu

Tnh cho100kg

Tnh cho 1m

Tnh cho 1ngy

Tnh cho 1nm

1Nguyn liu trc lmsch

Malt (kg) 50 1102,82 11028,16 3374617Go (kg) 45 992,53 9925,34 3037154

ngsaccarozo(kg)

5 110,28 1102,82 337463

2Nguyn liu sau lmsch

Malt (kg) 49,50 1091,79 10917,87 334086Go (kg) 44,55 982,61 9826,09 3006784

3 Nguyn liu sau nghinMalt (kg) 49,01 1080,98 10809,80 3307799Go (kg) 44,10 972,68 9726,83 2976410

4 Dch ng un si (l) 808,04 17822,38 178223,80 54536483

5 Dch ng sau houblon hho(l) 708 15615.87 156158,70 477845626 Dch sau lng trong 662,13 14604,15 146041,45 44688683,707 Dch ln men (l) 635,97 14027,15 140271,52 42923085,128 Bia sau ln men chnh (l) 629,61 13886.87 138868,70 424938229 Bia sau ln men ph (l) 626,46 13817.40 138174 4228124410 Lng bia sau lc (l) 620,20 13679.32 136793,20 4185871911 Lng bia sau n nh 617,10 13610.95 136109,50 4164950712 Lng bia sau chit rt 604,76 13338.77 133387,70 4081663613 Lng bia thnh phm (l) 592,66 13071.89 130718,90 3999998314 Lng b nguyn liu (kg) 110,05 2427.30 24272,97 742752915 Lng hoa vin(kg) 1,62 35.73 357,31 10933716 Lng b hoa (kg) 4,85 106.97 1069,73 32733716 Lng CO2 thu hi (kg) 17,25 380.47 3804,71 116424117 Lng men ging (l) 6,36 140.28 1402,78 42925118 Lng men thu hi (l) 5,09 112.27 1122,67 34353719 Lng b men thu hi 12,72 280.56 2805,56 858501

20Lng b men s dng cho mc chkhc

7,63 168.29 1682,90 514967

21 Lng ch phm Enzym s dng 0,0441 0.97 9,73 2977

22 Lng chai (chai) 261438 825593123 Lng np (ci) 269524 8247419324 Lng nhn (ci) 269524 8247419320 Lng kt (ci) 1590 486275


44/109


CHNG V : TNH V CHN THIT B

5.1. Cng on x l nguyn liu

5.1.1. My lm sch nguyn liu

- Theo bng 4.3, lng nguyn liu cn lm sch trong mt ngy.

+Malt: 11028,16 (kg)

+Go: 9925,34 (kg)

Vy, tng lng nguyn liu cn lm sch trong mt ngy l:

11028,16 + 9925,34 = 20953,50 (kg/ngy) = 0,87 (tn/h)

- S dng sng lm sch k hiu CL-3 m bo sau khi qua sng lm sch, nguyn

liu thu c c sch cao, cc tp cht nh tch ra t bung kh ng s c thu gi

ti Cyclone lng bi. [13-tr 29]

Cc thng s k thut:

Nng sut : 2,5 tn/h

Cng sut tiu th: 11kW

sch : 99,5%

Kch thc (D x R x C) : 4000 x 2200 x 3800 mm

S lng thit b =0,85

0,34 12,5

= < , do vy ta chn 1 thit b.

5.1.2. My nghin nguyn liu

5.1.2.1. My nghin malt

Theo bng 4.3, lng malt cn nghin/ngy l: 10917,87 kg/ngy = 0,45 (tn/h)

- Chn my nghin BM c 2 cp trc vi cc c tnh sau: [ 13 90 ]

- Kch thc trc nghin D L : 0,3 0,6

- Nng sut mt cp trc : 36 tn/ngy = 1,5 tn/gi

- Cng sut ti a trn cp trc : 10 kW



45/109

h1

h2

H

h

60o

D

d


- Khi lng my : 3050 kg

- Kch thc : 1700 500 1600 (mm)

- S lng = 0,44 0,291,5 =


46/109


5.1.3.1. Bunke ch malt

Theo bng 4.3, lng malt/m sau khi lm sch l: 1091,79 (kg) . Khi lng ring ca

malt: =560 kg/m3

i ra th tch: Vm=1091,79

1,95560

= (m3)

T () 0,325D 3 + 0,042D 3 tg=1,950,9

D= 2,2

ng knh bunke cha malt sau nghin: D = 2,2 (m).

ng knh ng tho liu: d == 8D

2,2

0,288 = (m).

Chn chiu cao ng tho liu: h0 = 0,2 (m).

Chiu cao thn bunke H=1,3D=1,3 x 2,2= 2,86 (m).

Chiu cao chp: h = 0602

tgdD

= 02,2 0,28

tg602

=1,66 (m)

Chiu cao ca bunke cha: H + h + h0 = 2,86 + 1,66 + 0,2 = 4,72 (m).

S lng 2 ci: 1 cha malt trc nghin, 1 cha malt sau nghin.

5.1.3.2. Tnh bunke cha go

Theo bng 4.3, lng go sau khi lm sch (tnh cho mt m) l: 982,61 (kg)

Khi lng ring ca go:=680 kg/m3

i ra th tch: Vn =( )

3982,61 1,45 m680

=

0,325D 3 + 0,042D 3 tg =1,45

0,9 D= 1,61(m)

ng knh ng tho liu: d =D 1,56

8 8= = 0,2(m)

Chn chiu cao ng tho liu: h0 = 0,1 (m)

Chiu cao thn bunke : H = 1,3D = 1,3 x 1,61= 2,1 (m)



47/109


Chiu cao chp: h = 0602

tgdD

=1, 61 0, 2

32

= 1,22 (m) .

Chiu cao ca bunke cha: H + h + h0 = 2,1+ 1,22 + 0,1 = 3,42 (m).

S lng 2 ci: 1 cha go trc nghin, 1 cha go sau nghin.

5.1.4. Cn nguyn liu

Chn cn in t nhn hiu WG ca hng OVIM

Khi lng ln nht m cn c th cn c mt ln l 100kg. Chn 2 cn:

- 1 ci dng cn malt

- 1 ci dng cn go

5.2. Cng on nu dch ng

5.2.1. Ni nu nguyn liu

Gi: D: ng knh ni, m.

H: hiu cao phn thn ni, m.

h1: Chiu cao phn y ni, m.

h2 : Chiu cao phn np ni, m.

Chn: H =2

D3

, h1=D

5

Gc nghing gia np so vi mt ngang l: = 200

Chn tit din ng thot hi bng 1/40 din tch b mt bc hi ln nht, ngha l :

Sth= Sbh401

Do vy: thD =40

D, h2=

020.2

tgDD th

- Th tch phn hnh tr: .6

1.

12

2

3

2

433

2

DDDD

VT === (m3)

- Th tch phn y : ( )2 2

cV h h 3r 6

= + (m

3

)


d

h1

h3

h2


48/109


Vy, th tch ni nu l:Vni = VT + VD = 3333

..30

7..

90

21

15

..

6

..DD

DD

==+ (m3) ()

5.2.1.1. Ni nu go

Theo bng 4.3, lng go mang vo nu mt m l : 972,68kg

Lng malt lt ni bng 5% so vi lng go ca mt m nu :

malt lt ni = 972,68 5%= 48,63 (kg)

Khi lng ring ca go : = 680 kg/ m3.

Khi lng ring ca malt : = 560 kg/ m3

Th tch malt chim : Vm =348,63 0,09(m )

560=

Th tch go chim : Vg =3972,68 1,43(m )

680= .

T l malt : nc = 1kg : 4,5 lt.

T l go : nc = 1kg : 5 lt.

Th tch nc nu : (972,68 5) +( 48,63 4,5) = 5082,24 (lt) = 5,1 (m3)

Tng th tch nguyn liu cn nu mt m ni go l:

V = Vm + Vg + Vnc = 0,09 + 1,49 + 5,1 = 6,62 ( m3 )

V ni go tri qua qu trnh un si nn dch cho d tro ln ng thot hi. Do ,

ta chn h s cha y 5,0= . Vy th tch thc ca ni:36,62 13,24(m )

0,5=

Theo (**) 5.2.1. ta c :Vni =3

3T

7. .DV 13,24(m )

30

= = D = 2,62( )m

Chiu cao thn tr : H =2 2 2,62

1,83 3

D x= = (m )

Chiu cao y ni : h1 =2,62

0,55 5

D= = (m )

Chiu cao np ni: h2=020.

2tg

DD th (m)



49/109


ng knh ng thot hi : Dth =2,62

0,440 40

D= = (m)

Vy: h2=

020.2

tgDD th

=

02,62 0, 4 20 0,402

xtg

=(m)

Vy, chiu cao ca ni go l: H =H + h1 + h2 = 1,8 + 0,5 + 0,40 = 2,70 (m)

Chn cnh khuy: [ 6 625 ]

Chn cnh khuy m neo c ng knh: ( )3 3

D D 2,62 1,96 m4 4

= = =

S vng quay ca cnh khuy : 30v/p, Cng sut ng c in : 3 kW

5.2.1.2. Ni nu malt

Ni ny va nu malt va hi cho nn cn c th tch cha lng cho malt cn

li v lng dch t ni go chuyn sang.

Theo bng 4.3, lng malt nu mt m : 1080,98 (kg)

Trong , lng malt c chuyn vo ni nu malt l:

1080,98 48,63 = 1129,60 (kg)

Th tch malt chim : 3m1129,60

V 2,02(m )560

= =

Th tch ni go chim: Vg = 6,62 (m3)

Th tch ca nc nu phn malt: 1129,60 4,5 = 5083,20 (lt) = 5,08 m3

Tng th tch ca nguyn liu cha trong mt m :

V= Vm + Vnc + Vg = 2,02+4,50+ 6,62 = 13,14 (m3)

Chn h s cha y ca thit b : 75,0=

Vy th tch thc ca ni : VT =313,14 17,52(m )

0,75=

Theo (**) ta c :Vni =3

3T

7 DV 17,52(m )

30

= =

Do , ng knh ni malt l: D 2,9 (m)



50/109


Chiu cao ca thn hnh tr l: H = )(9,19,23

2

3

2mD ==

Chiu cao y ni : h1 = 58,05

9,2

5

==D

(m)

ng knh ng thot hi : Dth = 46,040

9,2

40==

D(m)

Chiu cao np ni: h2=020.

2tg

DD th = 44,0202

46,09,2 0 =

xtg (m)

Vy, ton b chiu cao ca ni malt l:

H =H + h1 + h2 = 1,9 + 0,58 + 0,44 = 2,92 (m)

Chn cnh khuy m neo c ng knh : )(2,29,24

3

4

3' mxDD ===

S vng quay ca cnh khuy : 30v/p [ 6 625 ]

Cng sut ng c in : 13 KW

S lng: 1 ni

5.2.1.3. Ni nu nc nng

Ni c th cha lng nc cn dng cho mt m nu v ra b.

Th tch nc nu mt m: 5,1 + 5,08 = 10,18 (m3).

Th tch nc ra b: Vra b =3

1Vnc nu =

3

110,18 = 3,40 (m3)

Vy lng nc cn dng cho mt m nu k c nc ra b:

10,18 + 3,40 = 13,58 (m3)

Chn h s cha y : = 0,8

Th tch tht ca ni: VT =13,58

16,980,8

= (m3)

Theo (**) ta c, VT30

7 3D= = 13,58 D = 2,65(m)



51/109


Chiu cao ca thn hnh tr l: H =2 2

2,65 1,80( )3 3

D m= =

Chiu cao y : h1 =2,65

0,53

5 5

D= = (m)

ng knh ng thot hi : Dth =2,65

0,4240 40

D= = (m)

Chiu cao np ni : h2=020.

2tg

DD th = 02, 65 0, 42

20 0,412

xtg

= (m)

Vy, chiu cao ca ni nu nc nng: 1,80 + 0,53 + 0,41 = 2,74 (m)

5.2.1.4. Ni houblon ha

Thit b ny dng un si dch ng vi hoa houblon. Cu to ni ging nh ni

nu nguyn liu.

Theo bng 4.3, th tch dch ng un si/m: 17822,38 = 17,82 (m3)

Chn h s cha y ca thit b: 8,0= ,Vni =317,82 22,28(m )

0,8=

Theo (**) ta c :Vni =3

37 22,28( )30 TD

V m

= = , D 3,1 (m)

Chiu cao thn hnh tr l : H = 07,21,33

2

3

2==D (m)

Chiu cao y : h1 = 62,05

1,3

5==

D(m)

Chn cnh khuy :

Dng mi cho c ng knh : mDD (33,21,34

3

4

3' === )

S vng quay ca cnh khuy : 30 v/p

Cng sut ng c in : 4 kw

ng knh ng thot hi : Dth = 49,040

1,3

40==

D(m)



52/109


Chiu cao np : h2 =0 0Dth 3,1 0,49tan 20 tan 20 0,48

2 2

Dg g

= = (m)

Vy, chiu cao ca ni houblon l: 2,07 + 0,62 + 0,48 = 3,17 (m)

* Cc thng s k thut khc ca cc loi ni l:

Chiu dy np ni : .4mm=

Chiu dy lp v trong : mm.4=

Chiu dy lp v ngoi : .5mm=

Khong cch gia hai lp v: 50mm

Kch thc ca tip liu v quan st ng ng: 250mm.

ng knh ca tho dch : 200mm.

ng knh ng cp hi t : 200mm.

ng knh ng tho nc ngng: 40mm.

5.2.2. Thit b lc thng

Hnh 5.3: Thng lcTheo bng 4.3, lng malt sau khi nghin cho mt m: 1080,98 (kg)


inD

200

H

l

1

D

h


53/109


Lng go sau khi nghin cho mt m : 972,68 ( kg)

Vy, tng lng nguyn liu nu mt m :

1080,98+972,68 = 2053,66 (kg)Theo nghin cu c 170 kg nguyn liu th chim 1m2 b mt lc.

Vy 1988,94 kg nguyn liu th chim:2053,66

170= 12,08 (m2)=

4

2D

Vy, ng knh thng lc : D =4 S 4 12,08

3,14

=

= 3,92 (m)

Theo mc (5.2.1.2) lng dch ca mt m lc: V = 13,14 (m3)

Chn h s cha y thit b : = 0,7

Th tch thc ca thit b lc : VT =V 13,14

0,7 0,7= =18,77(m3)

M: VT = HD

4

2

Nn, chiu cao phn tr thit b : H = T2 24V 4 18,77

D 3,14 3,92=

= 1,56 (m)

Chiu cao np thit b : h1 =oD 3,92tg tg20

2 2 = = 0,71 (m)

Chn khong cch t y chnh ca thit b n li l : l = 300 mm

Tng chiu cao thit b : H = H + h1 = 1,56 + 0,71 = 2,27 (m)

Chn tit din ng thot hi bng 1/40 tit din b mt bc hi ln nht

ng knh ng thot hi: Dth =40

9,3

40=

D= 0,62(m).

Chn cnh khuy dng bn co c ng knh: ( )'3 3

D D 3,9 2,93 mm4 4

= = =

+ S vng quay cnh khuy: 0,2 v/s [15 - 109]

[TL 2, trang 625]+ Cng sut ng c in: 17 Kw



54/109


Ta c thi gian trung bnh nu 1 m ht: 140 pht, thi gian lc gn 4 gi. Do ,

ta c t s gia thi gian cn nu v thi gian cn lc xong 1 m l: 78,1135

604=

x

.Vy, s thng lc cn chn l: 2 thit b

5.2.3. Thng cha b nguyn liu

Theo bng 4.3, lng b nguyn liu thi ra sau mt m lc l: 2427,30 kg

Chn khi lng ring ca b t : B = 1.000 kg/m3

Th tch b nguyn liu : VB =2427,30

2,431000

= (m3)

Chn h s cha y ca b : 7,0=

Th tch b : Vthng =2,43

3,470,7

= (m3)

Chn thng ng b nguyn liu hnh tr, y hnh nn :

Chn: H = 1,3D, gc nghing y nn l 600

Vthng=4

3,14

32 DHD =

Nn: D = 3 34V 4 3,47

1,3 1,3 3,14

=

= 1,5 (m)

H =1,3 95,15,1 = (m)

Chn ng knh ng tho dch : d = 0,3 m

Chn chiu cao ng tho dch : h1 = 0,2 m

Chiu cao y nn :

h = )(04,1602

3,05,160

200 mtgtg

dD=

=

Vy, chiu cao ton b thng lc: 1,95 + 0,2 + 1,04 = 3,19 (m)

S lng : 1 b.


H

Hnh 5.4:Thng cha b

h

D

D


55/109


5.2.4. Thit b lng trong

1 : ng thot hi2 : Ca quan st

3 : Thn thit b

4 : ng dn dch vo

5 : Van x cn

Theo bng 4.3, th tch dch ng sau khi houblon ha: 15615,87 (lt) = 15,62 m3

Chn h s cha y ca thit b : 8,0=

Th tch thit b : VT =15,62

19,530,8

= (m3)

Chn t l gia chiu cao v ng knh ca thit b l :3

5=

D

H

Chn gc nghing np thng: =100

VT =4

2HD=

12

5 3D= 19,53(m3)

D = 2,46(m)

H = 4,11 (m)

Chiu cao np: h1 =02,46 10

2 2D tg tg = = 0,22 (m)

Chiu cao thng lng : H + h = 4,11+ 0,22 = 4,33 (m)

Chn ca a dch vo t chiu cao bng 1/4 H, do :

h2 =4,11

1, 03( )4 4

Hm= =

Chn ng dn dch ung vo thit b c :d = 30 mm. B dy ng: 3 mm

Chn ng ng dn dch ra : d = 50 mm


3

4

2

1

D

H

h

5Hnh 5.4: Thit b lng trong


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Ta c, lu lng dch ng chy qua ng c tnh theo cng thc :

V = 0,785w d2

Trong , w : tc trung bnh ca dch ng chn: w = 11m/s V = 0,785 11 0,032 = 0,0078 (m3/s) = 27,98 (m3/h).

Vy thi gian dch vo :T =V

Vdichduong =15,123

27,98= 0,54 (gi) = 32 (pht)

Thi gian lng cn : 20 pht.

5.2.5. Thit b lm lnh

Theo bng 4.3, lng dch ung em i lm lnh/m: Vd = 14604,15 (lt)

Theo yu cu cng ngh, thi gian lm lnh khng qu 1 gi. Chn: 45 pht

Vy, nng sut lm vic ca thit b l:14,60x60

19,4745

= (m3/h)

Chn thit b lm lnh nhn hiu : BO1-Y5 vi cc thng s:

- Nng sut : 5000lt/h = 5(m3/h) [15 - 158]

- Khi lng : 430 kg

- Nhit ban u ca glycol : -150C

- S lng bn : 85 bn

- Nhit lm lnh sn phm : 80 C

- Kch thc bn : ( 800 225 1,2 ) mm

- B mt lm vic ca cc bn : 12,1 m2

- Vn tc ca cht ti lnh : 0,4 m/s

- Kch thc thit b : ( 1870x700x1400 ) mm

- S lng thit b: n =N 19,47

3,89Q 5

= = . Ta chn, n = 4



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5.2.6. Tnh v chn cc loi bm cho phn xng nu

5.2.6.1. Bm dch cho t ni nu go sang ni nu malt

Theo s nu mc (3.2.3.2), thi gian bm dch cho ni go sang ni malt l:10 pht . Theo mc (5.2.1.1) th tch dch trong ni go l: V = 6,62m3

Nng sut cn lm vic ca bm : N =6,62 60

39,7210

= (m3/h)

Chn bm nhn hiu :BH -40 vi cc thng s [15 - 372]

- Nng sut : 40 m3/h - p sut lm vic : 0,2 MPa

- Tc quay: 2910 v/pht - Cng sut ng c: 5,5 kW

- Chiu cao bm ln : 8 m

- Khi lng : 210 kg

- Kch thc : ( 1385x 510 x 907) mm

- S lng thit b: n =39,72

0,9940

= , ta chn 2 bm

5.2.6.2. Bm dch ng ho i lc

Th tch dch ng cn bm i lc theo mc (5.2.1.2) : V = 13,38 m3 . ging (mc

5.2.6.1)

Thi gian bm dch i lc : 20 pht

Nng sut lm vic ca bm : N =13,14 60

39,4220

= (m3/h)

Chn 1 bm ly tm nhn hiu :BH -40 vi cc thng s ging phn trn.

Chn 1 ci my bm

5.2.6.3. Bm dch ng i lng trong

Th tch dch ng bm i lng trong bng th tch dch ng sau khi houblon ho

: V = 15615,87 lt = 15,62(m3)

Nng sut lm vic ca bm : N = ( )315,62 28,93 m / h0,54 = ging (mc 5.2.6.1)



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Tng t chn 1 bm nhn hiu BH -40 vi cc thng s ging phn trn

5.2.6.4. Bm dch ng i lm lnh

Lng dch ng bm i lm lnh coi nh bng lng dch ng sau lng khitrong: V = 14,70 (m3)

Theo mc (5.2.5) thi gian lm lnh : 45 pht

V c 4 thit b lm lnh nn cn 4 bm

Nng sut cn lm vic ca bm :N =14, 70 60

4,904 45

=

(m3/h)

Chn bm ly tm nhn hiu : BH - 5 vi cc thng s [15 - 372]

- Nng sut : 5 m3/h

- p sut lm vic : 0,08 MPa

- Cng sut ng c : 1,7 kW

- Khi lng : 29,3 kg

- Kch thc : ( 432 x290 x285 ) mm - S lng: 4 bm

5.2.6.5. Bm dch ng lnh i ln men

Tnh tng t nh mc (5.2.7.4) ta chn 4 bm ly tm nhn hiu : BH - 5 bm

dch ln men sang phn xng ln men. [15 - 372]

5.3. Cng on ln men

Theo bng 4.3, lng dch ln men/ngy l : 140271,52 (lt) 140,27 (m3)

Lng dch ln men ln men/ ngy/thng l:140, 27 6

120,237

= (m3)

Chn 5 dy chuyn ln men, nh vy lng dch bm vo mi thng tip liu trong

mt ngy l:120,23

24,055

= (m3)

5.3.1. Thng ln men chnh

D: ng knh thng, chiu di thng : L = 1,5D


l


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Chn chiu di np thng: l = D/6

Th tch thng: V = Vtr + 2Vnp

Th tch thn tr: Vtr =4

2

LxD

Th tch phn np thit b

Vnp = )64

3(

6 2

22 DDh+

, m3 Hnh 5.6: Thng ln men

Th tch thng:

V =4

.2

LD + 2 )64

3(6 2

22

DDh + = 33245,135 D

Vi h s cha y =0,9; ta c:

Lng dch a vo thng ln men chnh bng lng dch bm vo thng tip liu cng

vi th tch men ging

Theo bng 4.3. Lng men ging trong mt ngy l: 1402,78 lt =1,4 m3

Vd = 6 1,40 25, 07 25, 317 5

+ = (m3)

3324

5,135D =

25,31

0,9

D = 2,78 (m),L = 4,17 (m), l = 0,46 (m)

Tng chiu di:

L0 = L + 2l = 4,17 + 2 0,46 = 5,09 (m)

Mi dy chuyn gm 4 thng ln men chnh v 1 thng d tr. Vy tng s thit b

ln men chnh ca 5 dy chuyn l: 5x 4 + 5 = 25 (thng)

5.3.2. Thng tip liu

Mi dy chuyn dng mt thng tip liu do tng s thng cn l: 5 thng

Hnh dng, kch thc thng tip liu ging thng ln men chnh. D = 2,78 (m),L = 4,17 (m), l = 0,46 (m)



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Tng chiu di:

L0 = L + 2l = 4,17 + 2 0,46 = 5,09 (m)

5.3.3. Thng nhn men ging trong dy chuynChn h s cha y thng l: = 0,5.

Theo trn, lng dch ng a vo mi h thng l 25,07 m3, vi t l gia dch

ng v dch men l 92:8 th th tch dch men cn l:25,07 8

2,1892

= (m3)

Th tch thng cn l: V=Vtr+ Vy=

4

2HD+ )

444

(

3

22 dDdDh ++

Chn H= 1,3D, d=10

D, 060= , h1= 0,1D

V=8000

3332600 33 tgDD +=

2,184,36

0,5= (m3)

V=4,36 (m3)

D=1,52 (m),H=1,3x1,52= 1,98 (m)

h1=0,1D = 0,1x1,52=0,15 (m)

Vy, chiu cao ca thng nhn men l: Hnh 5.7: Thng nhn men ging

1,98+0,15= 2,13(m)

Dng 5 thng cho 5 dy chuyn.

5.3.4. Thng cha bia non trc khi ly tm

Hnh dng, kch thc ca thng cha bia non trc khi ly tm ging thit b ln

men chnh. Cc kch thc ca thng: D = 2,78 (m),L = 4,17 (m), l = 0,46 (m)

Chn 5 thng cho 5 dy chuyn


h1

H

D


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5.3.5. My li tm tch men

Theo bng 4.3, lng bia non sau khi ln men chnh/ngy l: 138868,70 (lt) sau khi

ln men chnh ch mt phn bia non em ly tm. Do lng bia non a vo my ly

tm ti a /ngy l:138,87 6

119,037

= (m3)

Nng sut my li tm cn l: ( ) ( )3119,03

0,991 / 991 t /5 24

m h l h= =

Chn 5 my li tm nhn hiu A1-BCY cho 5 dy chuyn vi cc thng s -

Nng sut: 1000 1300 lt/h [15 - 125]

- S vng quay: 4455 vng/pht

- Cng sut ng c:14 kw

- Kch thc :1460 x 1050 x 1860 mm

- Khi lng

:1503 kg

5.3.6. Thit b ln men ph

Theo bng 4.3 lng bia non sau ln men chnh/ngy l:138868,70 (lt)

Lng bia a vo thit b ln men ph thc t l:138,87 6

119,037

= (m3)

Chn h s cha y ca thng l 0,9, ta c:119,03

5 0,9 =3

324

5,135D

Vy, D = 2,72 (m), L = 4,08 (m), l = 0,45 (m)

Mi dy chuyn dng 10 thit b v 5 thit b d tr do tng s thit b ln men

ph l:5 x 10 + 5 = 55 (thng)

5.3.7. Thng cha bia non sau ly tm

Chn 5thng hnh dng, kch thc ging thit b ln men ph.

Kch thc mi thng: D = 2,72 (m); L = 4,08 (m); l = 0,45 (m)



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5.3.8. Thng cha bia sau ln men ph

Chn 5 thng hnh dng, kch thc ging thit b ln men ph.

Kch thc mi thng: D = 2,72 (m); L = 4,08 (m); l = 0,45 (m)5.3.9. Thit b nui cy ging

Theo bng 4.3, lng men ging c cn cung cp/ngy:1402,78 (lt).

Lng men ging cn trong thc t l:1402, 78 6

1202,387

= (lt)

t c lng men ging ny th ly 10 lt men ging t phng th nghim tin

hnh nui cy sn xut qua 3 cp:

- Cp I: 10 50 (lt) = 0,05 (m3)

- Cp II: 50 250 (lt) = 0,25 (m3)

- Cp III: 250 1250 (lt) = 1,25(m3)

5.3.9.1. Thit b thanh trng dch ng

Theo mc (5.3.9), Th tch dch ng cn thanh trng cung cp cho mt t nui

cy l: 1202,38 (lt) =1,20 (m3)

Chn h s cha y thng: 0,85

Th tch thc ca thng: V=1,20

0,85=1,41(m3)

Tnh v chn ging thit b nhn ging ta c:

V= =+8000

333260033

tgDD 1,41(m3)

Chn: d=10

D, 060= , h1= 0,1D

Suy ra: D=1,04 (m), H=1,35(m), d = 0,14 (m)

h= 0602

D dtg

= 0,78(m)

h1=0,1 1,04 = 0,10(m)


Hnh 5.8: Thit b thanh trngdch nui cy ging


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Vy, chiu cao ca thng l: 1,35 + 0,78 + 0,10 = 2,23 (m)

S lng 1 thng.

5.3.9.2. Thit b nui cy cp ICc thit b nui cy sn xut u l cc thng tr ng c hnh dng ging thit b

thanh trng dch ng, c ng dn dch ng vo, ng dn dch men ra,b phn sc

kh v trng. Chn h s cha y thng l = 0,5

V= )444

(34

22 DxddDhHD+++

Chn: H= 1,3D, d= 10D ,060= , h1= 0,1D

Do vy ta c: V = =+

8000

3332600 33 tgDD 1,05,0

05,0= (m3)

D=0,43 (m), H=0,56 (m), h=0,34 (m), h1=0,1xD=0,04 (m)

Chiu cao ca c thit b l: 0,56 + 0,34 + 0,04 = 0,94(m)

5.3.9.3. Thit b nui cy cp II

Tng t phn 5.3.9.2, ta c: V = =+

8000

3332600 33 tgDD )(5,05,0

25,0 3m=

D=0,93 (m), H=1,21 (m), h= 0,73 (m), h1=0,1xD=0,09 (m)

Chiu cao ca c thit b l: 1,21 + 0,73 + 0,09 = 2,03 (m)

5.3.9.4. Thit b nui cy cp III

Tng t phn 5.3.9.3, V = =+

8000

3332600 33 tgDD 1,2

0,5=2,4 (m3)

D = 1,24 (m), d = 0,12 (m), H =1,62 (m), h = 0,37 (m),h1=0,12 (m)

Chiu cao ca c thit b l: 1,62 + 0,37 + 0,12 = 2,11 (m)

5.3.10. Thit b lc bia

Theo bng 4.3, ta c lng bia cn lc/ ngy l: 138174 (lt)Chn thit b lc : BOK vi cc thng s k thut sau: [15, 109]



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Nng sut : 10 m3/h

Tc quay ca thng: 1300

S lng a : 100

S lng thit b: 3138174

0,5824 10 10

=

Thi gian cn lc ht lng bia ca mt ngy l: t =138,17

13,80 ( )10

h=

Kch thc: D=3,90; H= 1,56; h1= 0,71; dth= 0,62

5.3.11. Thng phi trn cht tr lc

Thng phi trn dng hnh tr, c th cha c 200 lt.

Chn h s cha y ca thit b: = 0,85

Chn ng knh thng : D = 0,6 (m)

Th tch ca thng l : V =4

2HD= 3,235

85,0

200= (lt) = 0,24 (m3)

Suy ra, chiu cao ca thng l: H = 83,06,0.14,3

235,04..4

22==

x

D

V

(m)

5.3.12. Thng cha n nh bia sau khi lc trong

Thng cha c cu to v hnh dng ging thit b ln men ph, t nm ngang v c

b phn sc kh CO2 . S lng : 5 thng

Theo bng 4.3, lng bia sau khi lc cn cha / ngy:136793,20 (lt)

Th tch mi thng:136,79

5=27,36 (m3)

Chn h s cha y 0,95=

327, 36 135, 5

0,95 324D=

ta c:D = 2,79 (m), L =4,19 (m), l = 0,47 (m)



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5.3.13. Chn Bm

5.3.13.1. Bm nh lng

Theo phn (5.3.1), lng dch/thng ln men chnh/ ngy l: 25,07 m3

/ngy

Nng sut mi bm nh lng cn l:25,07

1,0724

= (m3/h)= 1070 (lt/h)

Chn bm CA-1500 M vi cc c tnh: [15- 372]

- Nng sut

: 0 1500 lt/h

- Cng sut ng c: 0,62 kw

- Kch thc

: 960 x 820 x 1140 mm

- Khi lng

: 146 kg

- S lng: 5 bm

5.3.13.1. Bm bia non vo my ly tm

Theo mc (5.3.5), ta c:

Nng sut my li tm cn l: ( ) ( )3119,03

0,991 / 991 t /5 24

m h l h= =

Chn 4 bm ly tm k kiu: H-HM3 vi cc thng s [15- 372]

- Nng sut: 2,36 m3/h - p sut lm vic: 0,1Mpa

-Tc quay:1420 vng/pht - Cng sut ng c:1,7 KW

- Chiu cao bm ln: 6 m - ng knh ng ht /y:35/35

- Kch thc: 6653401280 (mm) - Khi lng : 100 kg

5.3.13.2. Bm bia non vo thng ln men ph

Theo (5.3.6) lng bia a vo thit b ln men ph/ngy l: 119,03 (m3).



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Nng sut cn c ca bm l:119,03

0,995 24

=

(m3/h).

Chn 5 bm ly tm k hiu: : H-HM3 vi cc thng s ging phn (5.3.13.b).

5.3.13.3. Bm bia i lc

Theo mc (5.3.10) lng bia cn lc trong mt ngy l: 138,17 (m3)

V thi gian cn c lc trong 1 ngy l: 13,9 (h)

Vy, nng sut cn c ca bm l:138,17

13,9=9,94(m3/h)

Chn bm ly tm nhn hiu : :BH -10 vi cc thng s [15- 372]- Nng sut: 10 m3/h

- p sut lm vic : 0,2 MPa

- Tc quay: 2860 v/pht


- ng knh ng ht / y : 48/32 mm - Khi lng

: 103 kg

- Kch thc : ( 1307 x 380 x 740 )mm - S lng

: 1 bm

5.3.13.4. Bm nm men

Theo (5.3.9), lng men ging cn cung cp/ ngy: 1402,78(lt)

Chn bm ly tm k kiu: H-HM3 [15- 372]

Vi cc c tnh k thut nh phn (5.3.13.b)

5.3.13.5. Bm nc v sinh trong phn xng ln men

Chn 3 bm ly tm nhn hiu: BH - 10 nh chn phn 5.3.13.3

5.4. Cng on hon thin

Theo bng 4.3, lng bia cn chit rt trong mt ngy l: 136109,50 (lt)

Dng chai c th tch 0,5 lt chit. Phn xng chit lm vic 2 (ca/ngy), thi

gian ngh i ca l 20 pht, do mt ca lm vic 7,67(h).



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Vy nng sut ca dy chuyn chit chai l:136109,50

17745,700,5x2x7,67

= (chai/h)

Chn 1 dy chuyn chit chai, nng sut/dy chuyn l: 20000 (chai/h)

5.4.1. Bng ti chai, kt

Chn 1 h thng bng ti chai kt nhn hiu -2 vi cc thng s:

- Nng sut : 20000 chai /h [15- 386]

- Cng sut ng c : 2,2 kW.

5.4.2. My ra chai

Chn my ra chai nhn hiu AMM-12 vi cc thng s 15- 386]

- Nng sut : 20000 chai/h

- Cng sut ng c :18,8 KW

- Khi lng :10,400 kg

- Kch thc : 6195 3015 2672mm

- S u mang chai : 118

- Khong cch gia cc cacset: 100mm

- S lng n =17745,70

0,8920000

= , do vy ta chn : 1 my

5.4.3. My ra kt

Nng sut ca dy chuyn chit rt l 17745,70 chai/h, mi kt ng 20 chai.

Vy lng kt cn dng trong 1 gi l:17745,70

887,2920

= (kt/h).

Chn my ra kt nhn hiu: 2-AA [15 - 256]

Vi cc thng s k thut sau:

- Nng sut (kt/h) : 1700

- Vn tc bng chuyn (m/s) : 0,48

- Cng sut ng c (kW) : 0,6



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- Kch thc (mm) : 4000 x 1083 x 1175

- Khi lng (kg) : 645

- S lng (ci) : Chn 1

5.4.4. My chit rt

Chn my chit nhn hiu T1 BAP 12A vi cc thng s : [15 - 189]

- Nng sut :20000 chai/h

- Cng sut ng c:0,8kW

- Kch thc:(1620 x 1920 x 2290)mm

- Khi lng :2000 kg

- S lng vi:28 vi, s lng =17745,70

0,8920000

= ; do vy ta chn: 1 my.

5.4.5. My ng np

Chn my ng np nhn hiu: BYA-0,25 vi cc thng s [15 - 204]

- Nng sut : 12000 chai/h

- S mm ng : 10


- Khi lng : 732 kg

- Kch thc thit b : ( 850x710x1464) mm

- S lng =17745,70

0,89

20000

= ; do vy ta chn: 1 my.

5.4.6. My thanh trng

Chn my thanh trng nhn hiu Atlantico vi cc thng s [15 - 226]

- Nng sut : 20000chai/h

- Cng sut ng c :22 kW

- Kch thc: ( 8620x2700x2600)mm

- Khi lng:9400Kg



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- S lng : 1 ci

5.4.7. My dn nhn

Dng 1 my dn nhn c k hiu BB vi cc thng s k thut:

- Nng sut : 20000chai/h [21]

- Cng sut ng c :1,7 kW

- Kch thc: ( 3280x1100x1268 ) mm

- Khi lng :1065Kg

5.4.8. My d chai v my cho chai vo kt

Chn my c nhn hiu Meyer do sn xut vi cc thng s: [15 - 254]

+ My d chai : kch thc : 2000 x 500 x 1000, mm.

+ Cng sut ng c in : 3,0 kW

+ My cho chai vo kt : kch thc : 1500 x 500 x 1000,mm

+ Cng sut ng c in : 4,95 kW.

Bng 5.1



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STT Tn thit b Kch thc (mm) SLPhn xng nu1 My lm sch 4000220038002 My nghin malt 1700150016003 My nghin go 1100100011004 Bunke cha malt D = 2200; H = 2860; h = 1660; h0 = 2005 Bunke cha ng D = 1610; H = 2100; h = 1220; h0 = 1006 Cn nguyn liu7 Ni nu go D = 2620; dth =400; H=1800; h1 = 500; h2=400

8 Ni nu malt D = 2900; dth =460; H=1900; h1 = 580; h2=4409 Ni nu nc nng D = 2650; dth =420; H=1800; h1 = 530; h2=41010 Ni houblon ha D = 3100; dth =490; H=2070; h1 = 620; h2=48011 Thit b lc thng D = 3920 dth =620; H=1560; h1 = 71012 Thng cha b nguyn liu D = 1500; H = 1950; d=300; h1=20015 Thit b lng trong D = 2460; dth=400; H=4110; h1 = 220; h2=103016 Thit b lm lnh 1870x700x140017 Bm dch cho 1385x 510 x 90718 Bm dch ng ha i lc 1385 510 90719 Bm dch i houblon ha 1385x 510 x 90720 Bm dch i lng trong 1385x 510 x 90721 Bm dch i lm lnh 432 x290 x28522 Bm nc nng 1385 510 907Phn xng ln men23 Thit b ln men chnh D = 2780; L = 4170; l = 46024 Thng tip liu D = 2780; L = 4170; l = 46025 Thng nhn men ging D = 1520; H = 1980; h1=150

26Thng cha bia non trc litm

D = 2780; L = 4170; l = 460

27 My li tm tch men 1460 x 1050 x 186028 Thit b ln men ph D = 2720; L = 4080; l = 450

29Thng cha bia non sau khili tm

D = 2720; L = 4080; l = 450

30Thng cha bia non sau khiln men ph

D = 2720; L = 4080; l = 450

31 Thit b nui cy nm men+ Thng nui cp 1 D=430; H=560; h=340; h1=40+ Thng nui cp 2 D=930; H=1210; h=340; h1=90+ Thng nui cp 3 D=1240; H=1620; h=370; h1=120

32 Thit b thanh trng dchng

D =1240; H=120;d=140; h=780;h1=100

33 Thit b lc bia D=3900; H= 1560; h1= 710; dth= 620

34Thng trn cht tr lcDiatomit

D = 600; H = 830

35 Thit b n nh sau lc D = 2790; L = 4190; l = 47036 Bm nh lng 960 x 820 x 1140

37Bm bia non vo my lytm

6653401280

38

Bm bia non vo thng ln

men ph 6653401280 39 Bm bia i lc 1307 x 380 x 74040 Bm nm men 1307 x 380 x 740Phn xng chit rt44 My chit 1620 x 1920 x 229045 My ra chai 267230156195


71/109




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CHNG 6



73/109


CHNG 6



74/109


CHNG 6



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6.2. Kch thc cc cng trnh

6.2.1. Phn xng nu

Phn xng nu l nh 2 tng:

Bc ct 6 mNhp nh 6 mKch thc tng 1 (24 24 6) mKch thc tng 2 (24 24 5) mDin tch mt bng 576 m2

6.2.2. Phn xng ln men

Phn xng c xy dng gn phn xng nu tit kim ng ng v gimhao ht dch ln men. Phn xng ln men l nh 2 tng v gm nhng phng lnh ln,

c t tng cch nhit trnh tn tht lnh.

Cha v nn cha tnh c

Bc ct 6 mNhp nh 6mKch thc khu ln men ph tng 1 (60307,3) m

Kch thc khu ln men chnh tng 2 (60

30

3,2) mDin tch mt bng 1800m2

6.2.3. Phn xng chit rt

c xy dng gn phn xng ln men, kho thnh phm, kho cha kt v chai.

Phn xng chit rt xy dng nh 1 tng.

Bc ct 6 mNhp nh 6 mKch thc nh (30 18 6) mDin tch mt bng 540 m2



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6.2.4. Kho nguyn liu

y l ni d tr nguyn liu malt, go v ng cung cp cho phn xng nu.

Kho c ngn i, mt bn cha malt v mt bn cha go v ng.Lng malt nguyn liu cha trong kho sn xut trong 30 ngy. Lng go v

ng cha sn xut trong 10 ngy.

Nguyn liu c cho vo bao, khi lng mi bao l 50 Kg.

Kch thc bao: di x rng x cao: (1 x 0,4 x 0,3) m.

Trong kho cc bao nguyn liu c xp chng ln nhau to thnh khi c khong

trng thng gi v d kim tra, mi chng 10 bao. Vy chiu cao ca mi chng bao

l: 100,3 = 3 m

Theo bng (4.3) lng nguyn liu cn sn xut trong mt ngy:

- Khi lng malt: mmalt= 11028,16kg

- Khi lng go: mgo= 9925,34kg

- khi lng ng mng = 110,28 kgLng nguyn liu cn cha trong kho:

mmalt = 11028,1630 = 330844,80 kg

mgo = 9925,34 10 = 99253,40 kg

mng =110,28 10= 1102,8 kg

S bao nguyn liu c trong kho:

330844,80 99253,40 1102,88624

50N

+ += = (bao)

Din tch phn kho cha nguyn liu:bn

NfF

=1 (m2)

Trong : N: tng s bao nguyn liu, N = 8624 (bao)

f: din tch chim ch mi bao, f = 0,4 (m2)

nb: s bao trong mt chng, nb = 10



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: h s khong cch gia cc chng bao, =1,1

1

1,1 8624 0,4379,46

10F

= = (m2)

Din tch phn ng i li chim 20% din tch cha nguyn liu:

F2 = 379,460,2 = 75,89 (m2)

Din tch kho: F = 379,46 + 75,89 = 455,35 (m2)

Din tch mt bng: 26 18 = 468 (m2)

Kch thc kho: (26186) m

6.2.5. Kho thnh phm

Kho c xy dng cha bia thnh phm trong 7 ngy.

Theo 4.3 lng chai cn chit trong mt ngy l: 261438 (chai)

Chai c cha trong kt nha, mi kt 20 chai. Kch thc kt: 0,50,40,3 (m).

Cc kt c xp chng ln nhau, mi chng 10 kt, chiu cao ca 1 chng kt bia l:

0,310 = 3 (m)

Din tch phn kho cha kt bia: F1 =KC nn

Nfn, m2

Trong : n : s ngy d tr, n = 7

N : S chai thnh phm trong ngy, N = 261438 (chai)

f : Din tch mi chng kt, f = 0,50,4 = 0,2 (m2)

nc : S chai trong mt kt, nC = 20

nK: S kt trong 1 chng, nK= 10

: H s khong cch gia cc chng kt, = 1,1

F1 =1,1 7 261438 0,2

20 10

= 2013,07(m2)

Din tch kho cha: F = 1,1F1 = 1,12013,07 = 2214,38 ( m2)

Kch thc kho: (50506) m.



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6.2.6. Kho cha kt v chai

Lng chai v kt trong kho phi cha bia sn xut ra trong 7 ngy. Tng t

kho thnh phm ta tnh c kch thc kho l: F = (50506) m.

6.2.7. Phn xng l hi

Phn xng c kch thc: F = (12126) m

6.2.8. Phn xng c, in

Xy dng nh mt tng, kch thc: (18126) m

6.2.9. Nh hnh chnh

Bao gm cc phng sau:

- Phng gim c : 6 4 = 24 m2

- Phng ph gim c :2 (43) = 24 m2

- Phng k ton, ti v : 4 4 = 16 m2

- Phng t chc hnh chn: 4 4 = 16 m2

- Phng k thut : 6 4 = 24 m2

- Phng KCS : 6 4 = 24 m2

- Phng maketing: 4 4 = 16 m2

- Phng i sng : 4 4 = 16 m2

- Phng k hoch :4 4 = 16 m2

- Phng y t : 3 3 = 9 m2

- Phng v sinh: 4 4=16m2

- Hi trng :25 6 = 150 m2

Tng din tch cc phng : 351 m2

Xy dng nh hai tng, kch thc:

tng 1: (30 6 4) m.



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tng 2: (30 6 4) m.

6.2.10. Khu x l nc

Xy dng nh c kch thc: (12 6 6) m.6.2.11. i nc

i nc l ni cha nc x l cung cp cho ton nh my.

Kch thc:

+ Chiu cao t i nc: 14 m

+ ng knh i nc: 4 m

+ Chiu cao i nc: 6 m

6.2.12. Trm bin p

Trm bin p h th in cao p xung li in nh my s dng. Trm bin p

t gc nh my, ni t ngi qua li. Kch thc: (4 x 4 x 4) m.

6.2.13. Nh t my pht in d phng

Kch thc: (6 x 6 x 6) m.

6.2.14. Nh n - cn tin

Tnh cho 2/3 nhn vin ca ng nht.

S nhn vin ca ca ng nht l 87 ngi.

Do : 87 2/3 = 58 (ngi)

Din tch cho mi ngi : 2,25 m2

Din tch nh n : 58 2,25 = 130,5 m2

Kch thc : (2465,4) m



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6.2.16. Gara t

y l ni xe ca nh my v cng l trm bo qun v sa cha xe. S xe ca

nh my bao gm:- 01 xe lnh o nh my

- 04 xe nng

- 05 xe ch hng

Tnh din tch 6 m2 cho mt xe v 10 m2 lm phng np in acqui.

Kch thc gara: (1563,6) m.

6.2.17. Nh xe p, xe my

Kch thc: (1543,6) m.

6.2.18. Phng thng trc v bo v

Phng ny c xy gn cng chnh ca nh my. Kch thc: (433,6) m.

6.2.19. Kho nhin liu

Dng cha xng, nht cho xe v cc thit b my mc. Kch thc: (1265,4) m.

6.2.20. Khu x l nc thi

Kch thc: (1865,4) m.

T cc s liu trn ta lp c bng sau:



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STT Tn cng trnh Kch thc (m) Din tch (m2)1 Phn xng nu 24 24 9 576

2 Phn xng ln men 603010,5 18003 Phn xng chit rt 30 18 6 540

4 Kho nguyn liu 26186 468

5 Kho thnh phm 50506 25006 Kho cha kt v chai 50506 25007 Phn xng l hi 12126 144

8 Phn xng c, in 18126 216

9 Nh hnh chnh 3068 18010 Khu x l nc 1266 72

11 i nc D = 4, H = 14 12,57

12 Trm bin p 444 16

13 Nh t my pht in 666 36

14 Nh n - Cn tin 2466 14415 Gara t 1564 90

16 Nh xe p, xe my 1544 6017 Phng thng trc, bo v 434 1218 Kho nhin liu

CHAMBO kounsakda

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