Challenger Center Cooling Tower Enev/Ench 435 September 23, 2008 Performed By: Dianah Dugan Alex Saputa
Mar 15, 2016
Challenger Center Cooling Tower
Enev/Ench 435September 23, 2008
Performed By:Dianah DuganAlex Saputa
Contents
Block Diagram Schematic Equipment Data Collection Results Conclusion
Block Diagram of Cooling Tower
Air Inlet
Air Outlet
CT unit
mh
T
i
i
ˆ
mh
T
o
o
ˆP= 1 atm
W= 0
Chilled WS
Chilled WR
H <0CW
H >0Air
Cooling Tower Schematic from Side View
Outside Intake
Outside Intake
Inside Intake
Exhaust A Exhaust B
Outside Inlet B Outside Inlet A
Inner Inlet B Inner Inlet A
Schematic of Exhaust Fan
0.22 ft
0.72 ft
1.22 ft
*Distances measured from center of fan
Equipment
Anemometer Yard Stick Ladder Sling Psychrometer Psychrometric Chart
Radial Dependence of Temperature for Week 1
99
101
103
105
107
109
111
0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4Radial Position (ft)
Tem
pera
ture
(F)
Fan #1Fan #2Fan #3Fan #4
Fan #4
Fan #3
Fan #2
Fan #1
Radial Dependence of Temperature for Week 2
99
101
103
105
107
109
111
0 0.2 0.4 0.6 0.8 1 1.2 1.4
Radial position (ft.)
Tem
pera
ture
(F)
Fan#1
Fan#2
Fan#3
Fan#4Fan #1
Fan #3
Fan #4
Fan #2
Average Air Velocity for Week 1
0
500
1000
1500
2000
2500
0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4
Radial Position (ft)
Velo
city
(ft/m
in)
Fan #1Fan #2Fan #3Fan #4
Fan #4
Fan #3
Fan #2Fan #1
Average Air Velocityfor Week 2
0
500
1000
1500
2000
2500
0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4
Radial distance (ft)
Velo
city
of a
ir (ft
/min
)
Fan#1Fan#2Fan#3Fan#4
Fan #2
Fan #2
Fan #2
Fan #2
Calculating the Cross-Sectional Area
r1 r2 r3 r4R1
R2
R3R4
r1= 0.22 ft
r2= 0.72 ft
r3= 1.22 ft
r4= 1.30 ft
A1= π*(R2² - R1²)
A2= π*(R3² - R2²)
A3= π*(R4² - R3²)
Formulas To Solve:
Volumetric Flow Rate = cross-sectional area* measured velocity
Mass Flow Rate = volumetric flow rate * density
Heat = mass flow rate * change in enthalpy
Density is found by taking the inverse of Humid Volume, found on Psychrometric chart
*Vm
vAV *
)(* inletexhaust hhmQ
Comparative Volumetric Flow for Each Exhaust Fan
0
800
1600
2400
3200
4000
4800
5600
6400
7200
0.22 0.72 1.22Radial Position (ft)
Volu
met
ric F
low
Rat
e (ft
^3/m
in)
Fan 1Fan 2Fan 3Fan 4
Mass Flow Rate Per Fan
729
772
727
747
690
700
710
720
730
740
750
760
770
780
1 2 3 4Fan #
Mas
s Fl
ow R
ate
(lb/m
in)
Calculating Enthalpy from Psychrometric Chart
Enthalpy for Inlet and Exhaust Fans
31 31 31 30
79 78 76 75
0
10
20
30
40
50
60
70
80
90
1 2 3 4Fan #
Enth
alpy
(Btu
/lb)
Inlet
Exhaust
Heat Generated
116657
271078
183596
266618
0
50000
100000
150000
200000
250000
300000
1 2 3 4
Fan #
Heat
(Btu
/hr)
Change to bar graph***
Date A B8/20/200
8 Starts 1915 1915
Running hours 3039 28878/21/200
8 Starts 1917 1917
Running hours 3060 28908/22/200
8 Starts 1919 1919
Running hours 3081 28918/25/200
8 Starts 1923 1923
Running hours 3125 2920
Conclusions
Velocity is the least in the center of the exhaust
Comments