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Chain Discounts— Complement Method pp. 498-501 SECTION SECTION 15-5 15-5
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Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

Jan 20, 2018

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Jerome Watts

SECTION MBA, Section 15-5, Slide 3 of Key Words to Know net-price rate (p. 498) The percent of the price paid for an item, found by multiplying the complements of the chain discounts.
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Page 1: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

Chain Discounts—Complement Method pp. 498-501SECTION 15-5SECTION 15-5

Page 2: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 2 of 18

15-5

Section ObjectiveSection ObjectiveCompute:

• final net price using the complement method

Page 3: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 3 of 18

15-5

Key Words to KnowKey Words to Know net-price rate (p. 498)The percent of the price paid for an item, found by multiplying the complements of the chain discounts.

Page 4: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 4 of 18

15-5

Net Price Rate = Product of Complements of Chain-Discount RatesNet Price = List Price × Net-Price Rate

FormulaFormula

Page 5: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 5 of 18

15-5

Restoring Vintage Vehicles p. 498Restoring Vintage Vehicles p. 498

How do you find the final net price using the complement method?

Page 6: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 6 of 18

15-5

Dell’s manufactures a riding mower, which is priced at $1,450. A new model is ready for production, so the model will be discontinued. Dell’s is offering a chain discount of 25 percent less 20 percent less 10 percent. What is the net price for the mower?

Example 1Example 1

Page 7: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 7 of 18

15-5

Find the complements.Complement of 25 percent: 100% – 25% = 75%Complement of 20 percent: 100% – 20% = 80%Complement of 10 percent: 100% – 10% = 90%

Example 1 Answer: Example 1 Answer: Step 1Step 1

Page 8: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 8 of 18

15-5

Find the net-price rate.Product of Complements of Chain-Discount Rates

75% × 80% × 90% = 54%

Example 1 Answer: Example 1 Answer: Step 2Step 2

Page 9: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 9 of 18

15-5

Find the net price.List Price × Net-Price Rate$1,450 × 54% = $783

Example 1 Answer: Example 1 Answer: Step 3Step 3

Page 10: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 10 of 18

15-5

Key Words to KnowKey Words to Know single equivalent discount (SED) (p. 499)One discount that is equal to a chain discount.

Page 11: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 11 of 18

15-5

SED = Complement of Net-Price RateDiscount = List Price × SED

FormulaFormula

Page 12: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 12 of 18

15-5

In Example 1 the chain discount complements were 75 percent/80 percent/90 percent and the net-price rate was 54 percent. What is the SED? What is the discount?

Example 2Example 2

Page 13: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 13 of 18

15-5

Find the SED.Complement of the Net-Price Rate100% – 54% = 46% (Note that 54% paid implies 46% off.)

Example 2 Answer: Example 2 Answer: Step 1Step 1

Page 14: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 14 of 18

15-5

Find the discount.List Price × SED$1,450 × 46% = $667

Example 2 Answer: Example 2 Answer: Step 2Step 2

Page 15: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 15 of 18

15-5

Check: List Price – Discount = Net Price$1,450 – $667 = $783 (same as Example 1)

Example 2 Answer: Example 2 Answer: Step 3Step 3

Page 16: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 16 of 18

15-5

Find the SED and the discount.List price: $398.55Chain discount: 40/25/15

Practice 1Practice 1

Page 17: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

SECTION

MBA, Section 15-5, Slide 17 of 18

15-5

SED: 61.75%Discount: $246.10

Practice 1 AnswerPractice 1 Answer

Page 18: Chain Discounts— Complement Method pp. 498-501 SECTION 15-5.

Chain Discounts—Complement Method

END OF SECTION 15-5END OF SECTION 15-5