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Apr 06, 2018

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    Chapter 4

    4.1 Lookback options and Neumann boundary condition

    Lattice Methods for American Opt4.2 ions

    Applications of Lattice Methods

    4.3 Options with two underlying assets

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    4.1 Lookback options and Neumann Boundary Condition

    22 2

    2

    1( ) 0, 0 >

    =S t T

    V S S T f S SS

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    Finite difference schemes for options on two

    assets

    1, 2, 1 2, , ) ( , , ) : 0,1, , ;

    :

    0,1, , ; 0,1, , }

    {( i j nS t ih jh n t n N

    i I j J

    S = =

    = =

    Mesh

    , 1 2( , , ).Denoten

    i jV ih jh nV t=

    Two questions:

    the discretization of the cross derivative;boundary conditions.

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    Discretization of the cross derivative

    21, 1 1, 1 1, 1 1, 1

    1 2 1 2

    21, 1 1, 1 , 1, 1, , 1 , 1

    1 2 1 2

    21, 1 1, 1 , 1, 1,

    1 2

    1.

    22.

    23.

    4

    2

    n n n n

    i j i j i j i j

    n n n n n n n

    i j i j i j i j i j i j i j

    n n n n n

    i j i j i j i j i j

    V V

    V V V

    V VV

    S S h h

    V VV

    S S h hV VV

    S

    V V

    V V V

    S

    + + + +

    + + + +

    + + +

    +

    +

    +

    +

    + , 1 , 1

    1 22

    n n

    i j i j

    h

    V V

    h

    +

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    Boundary conditions

    1 2Consider the spread option with payoff ( ) .S SX+

    Let ( , be the price function of a European vanilla put.

    at time for a given asset with current price , v

    , , )

    and

    continuous

    olatili

    dividend yi

    ty

    eld .

    EP S

    t

    q t

    S

    q

    1

    2

    1 2

    1

    2 2 20

    1 10

    Boundary conditions for the spread option can be imposed

    as follows:

    ( , , , ),( , ,

    0

    , ),

    .

    E

    E

    IS J

    S

    S

    S

    S q tS q

    V PtV P

    V V

    =

    =

    = =

    =

    =

    = =

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    Implicit difference scheme

    Proceed with similar choice of FD formulae as for the 1-asset

    case and with FD formula (1) for the cross derivative yields

    the FDE:

    1

    , , 1, , 1,2 2 2

    1 1 2

    1

    1, 1 1, 1 1, 1 1, 1

    1 2 1 2

    1 2

    , 1 , , 12 2 2

    1

    2

    1

    2 2 2

    +

    21

    2

    4

    21

    (

    2

    )

    + +

    + + + +

    +

    ++

    +

    +

    ++

    n n n n

    i j i j i j i j i j

    n n n n

    i j i j i j i j

    n n

    i j i j i j

    V V V V i h

    t

    V Vij

    V

    h

    V V

    Vj

    h

    Vr

    h hh h

    q

    V Vh

    ih1, 1, ,

    2

    1

    1

    2

    , 1

    2

    ,

    1, , 1, 1, 2, , 1.2,

    ( 0,2 2

    )+ +

    = =

    +

    =n n n n

    i j i j i j i j n

    i j

    I Ji j

    Vr q rV

    h

    V Vjh

    h