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Ground Water Hydrology Introduction - 2005 Philip B. Bedient Civil & Environmental Engineering Rice University
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Page 1: Ch02intro

Ground Water Hydrology

Introduction - 2005

Philip B. Bedient

Civil & Environmental Engineering

Rice University

Page 2: Ch02intro

GW Resources - Quantity

• Aquifer system parameters

• Rate and direction of GW flow

• Darcy’s Law - governing flow relation

• Dupuit Eqn for unconfined flow

• Recharge and discharge zones

• Well mechanics- pumping for water supply,

hydraulic control, or injection of wastes

Page 3: Ch02intro

GW Resources - Quality

• Contamination sources

• Contaminant transport mechanims

• Rate and direction of GW migration

• Fate processes-chemical, biological

• Remediation Systems for cleanup

Page 4: Ch02intro

Trends in Ground Water Use

Page 5: Ch02intro

Ground Water: A Valuable

Resource

• Ground water supplies 95% of the drinking water needs in rural areas.

• 75% of public water systems rely on groundwater.

• In the United States, ground water provides drinking water to approximately 140 million people.

• Supplies about 40% of Houston area

Page 6: Ch02intro

Regional Aquifer Issues

Page 7: Ch02intro

Typical Hydrocarbon Spill

Page 8: Ch02intro

Aquifer Characteristics

1. Matrix type

2. Porosity (n)

3. Confined or unconfined

4. Vertical distribution (stratigraphy or layering)

5. Hydraulic conductivity (K)

6. Intrinsic permeability (k)

7. Transmissivity (T)

8. Storage coefficient or Storativity (S)

Page 9: Ch02intro

Vertical Distribution of

Ground Water

Page 10: Ch02intro

Vertical Zones of Subsurface

Water

• Soil water zone: extends from the ground surface down through the major root zone, varies with soil type and vegetation but is usually a few feet in thickness

• Vadose zone (unsaturated zone): extends from the surface to the water table through the root zone, intermediate zone, and the capillary zone

• Capillary zone: extends from the water table up to the limit of capillary rise, which varies inversely with the pore size of the soil and directly with the surface tension

Page 11: Ch02intro

Typical Soil-Moisture

Relationship

Page 12: Ch02intro

Soil-Moisture Relationship

• The amount of moisture in the vadose zone

generally decreases with vertical distance

above the water table

• Soil moisture curves vary with soil type and

with the wetting cycle

Page 13: Ch02intro

Vertical Zones of Subsurface

Water Continued

• Water table: the level to which water will rise in a

well drilled into the saturated zone

• Saturated zone: occurs beneath the water table

where porosity is a direct measure of the water

contained per unit volume

Page 14: Ch02intro

Porosity

– Porosity averages about 25% to 35% for most

aquifer systems

– Expressed as the ratio of the volume of voids Vv to

the total volume V:

n = Vv/V = 1- b/m

where:

b is the bulk density, and

m is the density of grains

Page 15: Ch02intro

Porosity

Water

Page 16: Ch02intro

Arrangement of Particles in a

Subsurface Matrix

Porosity depends on:

• particle size

• particle packing

• Cubic packing of spheres with a theoretical

porosity of 47.65%

Page 17: Ch02intro

• Rhombohedral packing of spheres with a

theoretical porosity of 25.95%

Page 18: Ch02intro

Soil Classification Based on

Particle Size(after Morris and Johnson)

Material Particle Size, mm

Clay <0.004

Silt 0.004 - 0.062

Very fine sand 0.062 - 0.125

Fine sand 0.125 - 0.25

Medium sand 0.25 - 0.5

Coarse sand 0.5 - 1.0

Page 19: Ch02intro

Soil Classification…cont.

Material Particle Size, mm

Very coarse sand 1.0 - 2.0

Very fine gravel 2.0 - 4.0

Fine gravel 4.0 - 8.0

Medium gravel 8.0 - 16.0

Coarse gravel 16.0 - 32.0

Very coarse gravel 32.0 - 64.0

Page 20: Ch02intro

Particle Size Distribution

Graph

Page 21: Ch02intro

Particle Size Distribution

and Uniformity

• The uniformity

coefficient U indicates

the relative sorting of

the material and is

defined as D60/D10

U is a low value for

fine sand compared

to alluvium which is

made up of a range

of particle sizes

Page 22: Ch02intro

Cross Section of Unconfined

and Confined Aquifers

Page 23: Ch02intro

Unconfined Aquifer Systems

• Unconfined aquifer: an aquifer where the

water table exists under atmospheric

pressure as defined by levels in shallow

wells

• Water table: the level to which water will

rise in a well drilled into the saturated zone

Page 24: Ch02intro

Confined Aquifer Systems

• Confined aquifer: an aquifer that is overlain by a relatively impermeable unit such that the aquifer is under pressure and the water level rises above the confined unit

• Potentiometric surface: in a confined aquifer, the hydrostatic pressure level of water in the aquifer, defined by the water level that occurs in a lined penetrating well

Page 25: Ch02intro

Special Aquifer Systems

• Leaky confined aquifer: represents a stratum that allows water to flow from above through a leaky confining zone into the underlying aquifer

• Perched aquifer: occurs when an unconfined water zone sits on top of a clay lens, separated from the main aquifer below

Page 26: Ch02intro

Ground Water Flow

Darcy’s Law

Continuity Equation

Dupuit Equation

Page 27: Ch02intro

Darcy’s Law

• Darcy investigated the flow of water through beds of permeable sand and found that the flow rate through porous media is proportional to the head loss and inversely proportional to the length of the flow path

• Darcy derived equation of governing ground water flow and defined hydraulic conductivity K:

V = Q/A

where:

A is the cross-sectional area

V -∆h, and

V 1/∆L

Page 28: Ch02intro

Darcy’s LawV= - K dh/dl

Q = - KA dh/dl

Page 29: Ch02intro

Example of Darcy’s Law

• A confined aquifer has a source of recharge.

• K for the aquifer is 50 m/day, and n is 0.2.

• The piezometric head in two wells 1000 m apart is

55 m and 50 m respectively, from a common

datum.

• The average thickness of the aquifer is 30 m,

• The average width of flow is 5 km.

Page 30: Ch02intro

Calculate:

• the Darcy and seepage velocity in the aquifer

• the average time of travel from the head of the

aquifer to a point 4 km downstream

• assume no dispersion or diffusion

Page 31: Ch02intro

The solution

• Cross-Sectional area 30(5)(1000) = 15 x 10

4 m2

• Hydraulic gradient (55-50)/1000 = 5 x 10-3

• Rate of Flow through aquiferQ = (50 m/day) (75 x 10

1 m2)

= 37,500 m3/day

• Darcy Velocity:V = Q/A = (37,500m3/day) / (15 x 10

4 m2) = 0.25m/day

Page 32: Ch02intro

Therefore:

• Seepage Velocity:

Vs = V/n = 0.25 / 0.2 =

1.25 m/day (about 4.1 ft/day)

• Time to travel 4 km downstream:

T = 4(1000m) / (1.25m/day) =

3200 days or 8.77 years

• This example shows that water moves

very slowly underground.

Page 33: Ch02intro

Ground Water Hydraulics

• Hydraulic conductivity, K, is an indication

of an aquifer’s ability to transmit water

– Typical values:

10-2 to 10-3 cm/sec for Sands

10-4 to 10-5 cm/sec for Silts

10-7 to 10-9 cm/sec for Clays

Page 34: Ch02intro

Ground Water Hydraulics

Transmissivity (T) of Confined Aquifer

-The product of K and the saturated

thickness of the aquifer T = Kb

- Expressed in m2/day or ft2/day

- Major parameter of concern

- Measured thru a number of

tests - pump, slug, tracer

Page 35: Ch02intro

Ground Water Hydraulics

Intrinsic permeability (k)

Property of the medium only, independent of fluid properties

Can be related to K by:

K = k(g/µ)

where: µ = dynamic viscosity

= fluid density

g = gravitational constant

Page 36: Ch02intro

Storage Coefficient

Relates to the water-yielding capacity of an aquifer

S = Vol/ (AsH)

– It is defined as the volume of water that an aquifer

releases from or takes into storage per unit surface

area per unit change in piezometric head - used

extensively in pump tests.

• For confined aquifers, S values range between

0.00005 to 0.005

• For unconfined aquifers, S values range

between 0.07 and 0.25, roughly equal to the

specific yield

Page 37: Ch02intro

Regional Aquifer Flows are

Affected by Pump Centers

Streamlines and Equipotential lines

Page 38: Ch02intro

Derivation of the Dupuit

Equation - Unconfined Flow

Page 39: Ch02intro

Dupuit Assumptions

For unconfined ground water flow Dupuit

developed a theory that allows for a simple

solution based off the following assumptions:

1) The water table or free surface is only

slightly inclined

2) Streamlines may be considered horizontal

and equipotential lines, vertical

3) Slopes of the free surface and hydraulic

gradient are equal

Page 40: Ch02intro

Derivation of the Dupuit

Equation

Darcy’s law gives one-dimensional flow per unit

width as:

q = -Kh dh/dx

At steady state, the rate of change of q with

distance is zero, or

d/dx(-Kh dh/dx) = 0

OR (-K/2) d2h2/dx2 = 0

Which implies that,

d2h2/dx2 = 0

Page 41: Ch02intro

Dupuit Equation

Integration of d2h2/dx2 = 0 yields

h2 = ax + b

Where a and b are constants. Setting the boundary

condition h = ho at x = 0, we can solve for b

b = ho2

Differentiation of h2 = ax + b allows us to solve for a,

a = 2h dh/dx

And from Darcy’s law,

hdh/dx = -q/K

Page 42: Ch02intro

Dupuit Equation

So, by substitution

h2 = h02 – 2qx/K

Setting h = hL2 = h0

2 – 2qL/K

Rearrangement gives

q = K/2L (h02- hL

2) Dupuit Equation

Then the general equation for the shape of the parabola is

h2 = h02 – x/L(h0

2- hL2) Dupuit Parabola

However, this example does not consider recharge to the aquifer.

Page 43: Ch02intro

Cross Section of Flow

q

Page 44: Ch02intro

Adding Recharge W -

Causes a Mound to Form

Divide

Page 45: Ch02intro

Dupuit Example

Example:

2 rivers 1000 m apart

K is 0.5 m/day

average rainfall is 15 cm/yr

evaporation is 10 cm/yr

water elevation in river 1 is 20 m

water elevation in river 2 is 18 m

Determine the daily discharge per meter width into each

River.

Page 46: Ch02intro

Example

Dupuit equation with recharge becomes

h2 = h02 + (hL

2 - h02) + W(x - L/2)

If W = 0, this equation will reduce to the parabolic

Equation found in the previous example, and

q = K/2L (h02- hL

2) + W(x-L/2)

Given:

L = 1000 m

K = 0.5 m/day

h0 = 20 m

hL= 28 m

W = 5 cm/yr = 1.369 x 10-4 m/day

Page 47: Ch02intro

Example

For discharge into River 1, set x = 0 m

q = K/2L (h02- hL

2) + W(0-L/2)

= [(0.5 m/day)/(2)(1000 m)] (202 m2 – 18 m2 ) +

(1.369 x 10-4 m/day)(-1000 m / 2)

q = – 0.05 m2 /day

The negative sign indicates that flow is in the opposite direction

From the x direction. Therefore,

q = 0.05 m2 /day into river 1

Page 48: Ch02intro

Example

For discharge into River 2, set x = L = 1000 m:

q = K/2L (h02- hL

2) + W(L-L/2)

= [(0.5 m/day)/(2)(1000 m)] (202 m2 – 18 m2 ) +

(1.369 x 10-4 m/day)(1000 m –(1000 m / 2))

q = 0.087 m2/day into River 2

By setting q = 0 at the divide and solving for xd, the

water divide is located 361.2 m from the edge of

River 1 and is 20.9 m high

Page 49: Ch02intro

Flow Nets - Graphical Flow Tool

Q = KmH / n

n = # head drops

m= # streamtubes

K = hyd cond

H = total head drop

Page 50: Ch02intro

Flow Net in Isotropic Soil

Portion of a flow net is shown below

F

Y

Curvilinear Squares

Page 51: Ch02intro

Flow Net Theory

1. Streamlines Y and Equip. lines are .

2. Streamlines Y are parallel to no flow

boundaries.

3. Grids are curvilinear squares, where

diagonals cross at right angles.

4. Each stream tube carries the same flow.

Page 52: Ch02intro

Seepage Flow under a Dam