-
11/21/2018
1
CE 413Highway and Traffic Engineering
Lecture 5
Geometric Design of Highways
Engr. Amjad Khan
MS Transportation Engineering (NUST)
The alignment of a highway is composed of horizontal andvertical
elements
The horizontal alignment:
includes the straight (tangent) sections of the roadway
circular curves that connect their change in direction
The vertical alignment:
includes straight (tangent) highway grades
parabolic curves that connect these grades
Geometric Design of Highways
2
-
11/21/2018
2
Highway alignment is in reality a three-dimensionalproblem
Design & construction is difficult in 3-D so highway
designis typically treated as two 2-D problems:
Horizontalalignment, vertical alignment
Geometric Design of Highways
3
Geometric roadway design can be broken into three main parts:
alignment, profile, and cross-section. Combined, they provide a
three-dimensional layout for a roadway.
Horizontal Alignment
Corresponds to “X” and “Z” Coordinates
Plan view – Roughlyequivalent to the perspectiveof an aerial
photograph ofhighway
Vertical Alignment
Corresponds to highwaylength and “Y” Coordinate
Presented in a profile view
Gives elevation of all pointsmeasured along the length ofa
highway
Geometric Design of Highways
VerticalAlignment
Horizontal Alignment
4
-
11/21/2018
3
Geometric Design of Highways - Stationing
• Instead of using the coordinates system, highway positioning
and length aredefined as the distance usually measured along the
center line of thehighway from a specified point
• The notation for stationing distance is such that a point on
highway 4250 ft(1295.3 m) from a specified origin (0+00 or 0+000)
is said to be at station:
– 42+50 ft (42 stations and 50 feet)
– I + 295.300 meter( 1 station and 295.300 meters)
Horizontal Alignment
Vertical Alignment
5
The horizontal alignment consists of tangents and curves
The curves are usually segments of circles, which have radii
that will provide for a smooth flow of traffic
The critical design feature of horizontal alignment:
horizontal curve that transitions the roadway between two
straight (tangent) sections
focus on the design of directional transition of the roadway in
a horizontal plan
A key concern in the directional transition is the ability of
the vehicle to negotiate the horizontal curve
Horizontal Alignment
6
-
11/21/2018
4
Tangents Curves
Horizontal Alignment
7
Horizontal alignment to accommodate the cornering capabilityof a
variety of vehicles (cars to combination trucks)
The design of the horizontal alignment entails the determination
of:
the minimum radius of the curve
determination of the length of the curve
Side friction factor
Superelevation
Adequate stopping sight distance
Horizontal Alignment
8
-
11/21/2018
5
Horizontal Alignment
94/3/2015
Horizontal Alignment
104/3/2015
-
11/21/2018
6
Horizontal Alignment
114/3/2015
Horizontal Alignment
124/3/2015
-
11/21/2018
7
Tangent
Curve
Tangent to Circular Curve
Tangent to Spiral Curve
Horizontal Alignment
134/3/2015
Concept of Super-elevation
Centrifugal force and Centripetal Forces
o Centrifugal force (Latin for "center fleeing") describes the
tendencyof an object following a curved path to fly outwards, away
from thecenter of the curve. It's not really a force; it results
from inertia i.e.the tendency of an object to resist any change in
its state of rest ormotion
o Example: Mud flying off a tire; children pushed out on a
roundabout
14
-
11/21/2018
8
Concept of Super-elevation
15
Concept of Super-elevation
Centrifugal force and Centripetal Forces
o Centripetal force is a "real" force that counteracts the
centrifugalforce and prevents the object from "flying out", keeping
it movinginstead with a uniform speed along a circular path
o Example: Satellite orbiting a planet
16
-
11/21/2018
9
Horizontal highway curve is a curve in plan to provide change in
direction to the center line of a road. When a vehicle traverses a
horizontal curve, the centrifugal force acts horizontally outwards
through the center of gravity of the vehicle.
The centrifugal force is counteracted by the transverse
frictional resistance developed between the tires and the pavement
and weight of the vehicle.
Centrifugal force = ��²
�or
��²
��
The centrifugal force acting on a vehicle negotiating a
horizontal curve has two effects1.Tendency to overturn the vehicle
outwards about the outer
wheels 2.Tendency to skid the vehicle laterally outwards.
Concept of Super-elevation
Concept of Super-elevation
Super-elevation or banking is the transverse slope providedat
horizontal curve to counteract the centrifugal force, byraising the
outer edge of the pavement with respect to theinner edge,
throughout the length of the horizontal curve.
-
11/21/2018
10
Concept of Super-elevation
C.GCentrifugal force = P
Weight = W
RA RB
FA = f RA FB = f RBCurve Direction
Concept of Super-elevation
C.GCentrifugal force = P
Weight = W
RA
RB
Curve Direction
θ
θ
θ
PSinθ
PCosθ
WCosθ
WSinθ
-
11/21/2018
11
At Equilibrium PCosθ = ����� + �� + ��PCosθ = ����� + ��� +
���PCosθ = ����� + � �� + ��PCosθ = ����� + � ����� + �����
Dividing by Wcosθ and rearranging�����
�����=
�����
�����+
������
�����+
������
�����
�
�= ���� + f + f
�
�����
�
�- f
�
����� = ���� + f
�
�(1- f����) = ���� + f
�
�=
������
������� As �
�=
��
��
��
��=
������
�������
��
��=
� ��
� � ��
Since ef ≈ 0 when max.allowable values of f and e are taken
��
��=
� ��
� ��
��
��= e + f
R =��
�(���)
Here V = velocity in ft/sece = superelevation rate in %R =
radius in ft.g = 32.2 ft/sec2
-
11/21/2018
12
R =��
��(���)
Here V = velocity in miles/hr.e = superelevation rate in %R =
radius in ft.g = 32.2 ft/sec2
Eq shows that to reduce R for a given velocity, either e or f or
both should be increased.
Concept of Super-elevation
• AASHTO expression for superelevation after simplification
V 2 V 2
0.01e fv2
0.01e f
v2
15R 1 0.01ef gR
e = rate of roadway superelevation, %
f = side friction (demand) factor
v = vehicle speed, ft/s
g = gravitational constant, 32.2 ft/s2
V = vehicle speed, mph
R = radius of curve measured to a
vehicle’s center of gravity, ft
127R 1 0.01ef gR
e = rate of roadway superelevation, %
f = side friction (demand) factor
v = vehicle speed, m/s
g = gravitational constant, 9.81 m/s2
V = vehicle speed, Kmph
R = radius of curve measured to a
vehicle’s center of gravity, meter
-
11/21/2018
13
Superelevation Example -1
25
An existing horizontal curve on a highway has a radius of 465
ft, which restricts the posted speed limit on this section of the
road to only 61.5% of the design speed of the highway. If the curve
is to be improved so that its posted speed will be the design speed
of the highway, determine the minimum radius of the new curve.
Assume that the rate of superelevation is 0.08 for both the
existing curve and the new curve to be designed.
Maximum Super-elevation
26
o The maximum rates of superelevation:
o Climate conditions: (i.e., frequency and amount of snow and
ice)
o Terrain conditions (i.e., flat, rolling, or mountainous)
o Type of area (i.e., rural or urban)
o Frequency of very slow-moving vehicles whose operation mightbe
affected by high superelevation rates
o No single maximum superelevation rate is universally
applicable
o Design consistency: Using only one maximum superelevation rate
within a region of similar climate and land use is desirable
-
11/21/2018
14
Side-Friction Factor
27
Achieving Superelevation
o The superelevation transition section consists of
thesuperelevation runoff and tangent runout sections
o Tangent Runout: The tangent runout section consists ofthe
length of roadway needed to accomplish a change inoutside-lane
cross slope from the normal cross slope rateto zero (flat), or vice
versa
o Superelevation Runoff: The superelevation runoff
sectionconsists of the length of roadway needed to accomplish
achange in outside-lane cross slope from zero (flat at) to
fullsuperelevation, or vice versa
12
-
11/21/2018
15
13
Superelevation Runoff and Tangent Run out (Crown Runoff)
Fully superelevated cross section
Cross section with the adversecrown removed
Normal cross section
14
Tangent Runout Section
• Length of roadway needed to accomplish a change in
outside-lane cross slope from normal cross slope rate to zero
For rotation about centerline
-
11/21/2018
16
15
Superelevation Runoff Section
• Length of roadway needed to accomplish a change in
outside-lane cross slope from 0 to full superelevation or vice
versa
• For undivided highways with cross-section rotated about
centerline
16
Source: CalTrans Design Manual online,
http://www.dot.ca.gov/hq/oppd/hdm/pdf/chp0200.pdf
-
11/21/2018
17
17
Achieving Superelevation
18
-
11/21/2018
18
Achieving Superelevation
19
PC Superelevation runoff
Tangent runout
(Normal Crown)
(Adverse Crown)
(Full Superelevation)
Steps in Highway Rotation to Achieve Superelevation
o The outside lane(s) are rotated from their normal cross-slope
to aflat condition
o The outside lane(s) are rotated from the flat position until
they equal the normal cross-slope of the inside lanes.
o All lanes are rotated from the condition of step 2 to the full
superelevation of the horizontal curve.
20