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CE 382 L7 - Deflections

May 29, 2018

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    StructuralDisplacements

    Beam Displacement

    1

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    StructuralDisplacements

    P

    2

    Truss Displacements

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    -

    ing structures under the action ofusual design loads are known to

    be small in relation to both the

    overall dimensions and member

    . y udeflections? Basically, the

    that the predicted design loads

    will not result in large deflectionsthat may lead to structural failure,

    impede serviceability, or result in

    distorted structure.

    3

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    Several examples which demon-

    analysis include (Tartaglione,1991):

    1. Wind forces on tall buildings

    have been known to produce

    excessive lateral deflections that

    have resulted in cracked windows

    ,

    the occupants.

    . arge oor e ec ons n a

    building are aesthetically

    ,

    confidence, may crack brittlefinishes or cause other damage,

    4and can be unsafe.

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    3. Floor systems are often

    designed to support motor-

    driven machines or sensitiveequipment that will run satisfac-

    undergoes limited deflections.

    . arge e ec ons on a ra wayor highway structural support

    ,

    cause passenger discomfort,

    and be unsafe.

    5.Deflection control and camber

    behavior of re-stressed con-

    crete beams during variousstages of construction and load-

    5

    ng are v a or a success u

    design.

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    6.Deflection computations serve to

    dynamic characteristics ofstructures that must withstand

    moving loads, vibration, and

    shock environment -- inclusive of

    .

    Elastic Deformations structuree ec ons sappear an e

    structure regains its original

    the deformations are removed.

    structures are referred to asinelastic or plastic deformations.

    6

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    This course will focus on linear.

    deformations vary linearly with

    a lied loads and the rinci le of

    superposition is valid for such

    structures. Furthermore, since

    the deflections are expected to be

    small, deflections are measured

    , -

    formed or reference geometry.

    7

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    Work-Energy Methods

    Work-energy methods for truss,beam and frame structures are

    considered. Such methods are

    based on the principle of

    ,states that the work done by a

    structure (W) equals the strain

    energy stored (U) in the structure.

    This statement is based on slowly

    applied loads that do not produce

    kinetic energy, which can bewritten as

    8W = U

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    A disadvantage of work-energymethods is that only one dis-

    rotation can be computed with

    each a lication.

    Work force (moment) times

    displacement (rotation) in the

    Differential work of Fig. 1 can be

    expresse as

    dW = P (d)

    9

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    .

    Displacement Curves

    10

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    ForP = F (force), equals

    = F d

    ForP = M (moment), equals

    =

    0

    Eqs. (1, 2) indicate that work issimply the area under the force

    11

    sp acemen or momen ro a-

    tion) diagrams shown in Fig. 1.

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    Linear Elastic Structure

    W = 1 F

    W =

    1

    M

    Com lementar Work

    The area above the load- .

    known as complementary work,as shown in Fig 2. For aW

    linear-elastic system:112

    2

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    Fig. 2. Complementary Work

    Load complementary

    work

    W

    -

    Displacement

    calculations is only capable of

    calculating displacements at thelocation of an applied point force

    and rotations at the point of

    obviously a very restrictive

    13

    . ,

    work principles are developed in

    the subsequent sections.

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    Virtual Work

    Virtual (virtual imaginary, notreal or in essence but not in fact

    work procedures can produce a

    single displacement component at

    any desired location on the

    structure. To calculate the desired

    ,

    load(normally of unit magnitude)

    is a lied at the location and in

    the direction of the desired

    displacement component. Forces

    associated with this virtual force

    are subscripted with a V.

    14

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    Use of a virtual force in calcula-

    principle of virtual forces (which

    will be the focus of this cha ter :

    Principle of Virtual ForcesIf a deformable structure is in

    equilibrium under a virtual system

    ,

    done by the virtual forces going

    throu h the real dis lacements

    equals the internal virtual work

    done by the virtual stress

    resultants going through the real

    displacement differentials.

    15

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    Alternatively, if virtual displace-

    work is defined as the principle of

    virtual dis lacements:

    Principle of VirtualDisplacementsIf a deformable structure is in

    equilibrium while it is subject to a

    virtual distortion the external

    virtual work done by the external

    forces acting on the structure is

    equal to the internal virtual work

    done by the stress resultants.

    16

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    The virtual work principles (forces

    conserving the change in energy

    due to the a lied virtual load or

    displacement, which can be

    expressed mathematically as

    =V VW U

    for the principle of virtual forces,

    which is the focus of this chapter,

    complementary energy. The realand virtual com lementar exter-

    nal work is shown schematically inFig. 3.

    17

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    Pv = virtual force or moment

    = real displacement orrotation P + Pv

    WP

    Fig. 3. Complementary Real

    18

    an r ua or s

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    Complementary Axial

    Strain EnergyFor a sin le axial force

    member subjected to a real

    force F, the com lementarstrain energy (internal work)

    isF

    U2

    =

    F L =

    2F L=

    192 E A

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    For a single axial force

    member in equilibriumsubjected to a virtual force

    FV, the virtual complemen-

    tary strain energy (virtual

    complementary internal

    work) is

    V VU F= F L

    V VE A

    =

    -

    tary strain energies for asingle member are shown

    20schematically in Fig. 4.

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    Fig. 4. Complementary Real and

    Virtual Strain Ener ies for

    a Single Truss Member

    +

    F

    vUV

    U

    For a truss structure:

    m mV Vi vi iU U F= =

    21i 1 i 1= =

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    ViU Complementary Virtual=

    Strain Energy for Truss Member i

    i Real Member i Deformation =

    F Lii iE A

    =

    loaded truss member

    linear coefficient of

    thermal expansion

    =

    22T change in temperature =

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    =

    ferror of L in the truss

    member

    Non-mechanical i are positive

    change in member length

    consistent with tensionpositive forces in trussmembers.

    23

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    Example Deflection

    Loaded Truss Structure

    EA = constant

    oc er

    Calculate the horizontal displace-

    24

    .

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    Example Deflection

    Loaded Truss Structure

    =EA = constant

    = constant

    Calculate the horizontal displace-

    ment at G if the top chord mem-

    bers are subjected to a temper-

    25

    .

    Equation of condition at C!

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    Complementary BendingStrain Energy

    MdU d

    2=

    Md dx

    E I =

    1 MU M dx = 26

    L

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    V VdU M d=

    V VMU M dxE I

    =

    M + Mv

    MdUV

    dU

    Fig. 6. Complementary Real andd

    27

    a Differential Bending

    Segment

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    = rea en ng equa on ueto the external applied loading

    VM = for a virtual momentVM

    for a point displacement

    calculation at the desired

    point in the assumed direc-

    tion of the displacement

    = for a virtual moment

    equation for a unit virtualVM

    couple for a point rotation

    calculation at the desired

    28

    direction

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    For a multi-segment beam:

    iV Vi

    MU M dx=

    iL

    w

    segment.

    29

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    Beam Deflection Example

    and rotation for the cantilever

    beam.

    30

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    For a frame structure:

    jV Vj

    j1

    U M dxE I

    =

    =

    where m equals the number of

    frame members. Note, axial

    deformation has beengnore . so, a rame

    member is composed of multi-

    ,

    over the segments must also beincluded.

    31

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    Frame Deflection Example

    alculate the vertical displace-

    ment and rotation at C.

    32