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CALCULATIONS CHAPTER 6
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CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Dec 18, 2015

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Page 1: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

CALCULATIONS

CHAPTER 6

Page 2: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

ROMAN NUMERALS

Page 3: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

ROMAN NUMERALS

• Positional notation– When the second of two letters has a value equal

to or smaller than that of the first, add their values• ixvi = 50 + 10 + 5 + 1 = 66

– When the second of two letters has a value greater than that of the first, subtract the smaller from the larger• xc = 10 subtracted from 100

Page 4: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

SIGNIFICANT FIGURES

• Four rules for assigning significant figures:

1. Digits other than zero are always significant.2. Final zeros after a decimal point are always

significant.3. Zeros between two other significant digits are

always significant.4. Zeros used only to space the decimal are never

significant.

Page 5: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

METRIC SYSTEM LIQUIDS

Page 6: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

METRIC SYSTEM SOLIDS

Page 7: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

AVOIRDUPOIS SYSTEM

Page 8: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

APOTHECARY SYSTEM

Page 9: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

HOUSEHOLD UNITS

Page 10: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

TEMPERATURE

9C = 5F - 160For example, to convert 37C to Fahrenheit:

9(37) = 5(F) – 160333 = 5F – 160493 = 5F98.6 = F

For example, to convert 98.6F to Celsius:

9C = 5(98.6) – 1609C = 493 – 1609C = 333C = 37

Page 11: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

RATIO & PROPORTION

• A ratio states a relationship between two quantities

• Two equal ratios form a proportion

Rules for using ratios and proportions

1. 3 of the 4 values must be known2. Numerators (values in front of colons) must have same units3. Denominators (values behind colons) must have same units

Page 12: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

ExamplesYou receive a prescription for KTabs one tablet bid x 30 days. How many tablets are needed to fill this prescription?

1. Define the variable and correct rations:

Unknown variable (X) is the total tablets neededKnown ratio is 2 tablets per dayUnknown ratio is how many tables are needed for 30 days

2. Set up the proportion equation: X tabs : 30 days = 2 tabs : 1 day

3. Solve:

X = 60 tabs

Page 13: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

ExamplesIf an antidiarrheal mixture contains 3ml of paregoric in each 30ml of mixture, how many ml of paregoric would be contained in a tsp of mixture?

(note 1 tsp = 5ml)

3ml paregoric : 30ml mixture = xml paregoric : 5ml mixture

15ml = 30x

0.5ml = x

Page 14: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Complete page 143 1-5:

Answers:1.2ml2.8ml3.75ml4.2.08 ml/mn5.4.8 ml

Page 15: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Percents & Solutions

Percents are used to indicate the amount, or concentration, of something in a solution.

Weight-to-Volume: grams per 100 milliliters g/100ml

Volume-to-Volume: milliliters per 100 milliliters ml/100ml

Page 16: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

PERCENTS & SOLUTIONS

• Percent Weight-to-Volume– Grams per 100 milliliters

• Percent Volume-to-Volume– Milliliters per 100 milliliters

• Milliequivalents– mEq

Page 17: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Percents / Solutions ExamplesIf there is 50% dextrose in a 1,000 ml IV bag, how many grams of dextrose are there in the bag?

1. Proportion equation: Since 50% dextrose means there are 50 grams of dextrose in 100 ml, the equation would be:

xg / 1,000ml = 50g / 100ml

2. The x equation: xg = 1,000ml x 50g/100ml = 10 x 50g = 500g

Answer = There are 500g of dextrose in the bag

Page 18: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Example

Now how many ml will give you a 10g of dextrose solution?

1. The proportion equation: xml: 10g = 100ml: 500g

2. The x equation: 500xml/g = 1000ml/g

X = 20ml

Page 19: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Complete page 145 1-13 (click for answers)

1. 60%2. 80%3. 12%4. .55. .1256. .997. 35g8. 52.5g9. 14g10.50ml11.70ml12.20ml13.0.12%

Page 20: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

ALLIGATION

A way to solve problems when mixing preparations of 2 different strengths of the same ingredient to obtain a strength in-between the starting preparation.

Use a tic-tac-toe grid.

Place the lowest strength component in the upper left hand box.

Place the highest strength component in the lower left hand box.

Place the desired strength in the middle box.

Place the lowest strength

component in the upper left hand

box.

Place the highest strength

component in the lower left hand

box.

Place the desired strength in the

middle box.

Page 21: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

POWDER VOLUME

FV = D + PV

Final volume = Diluent + Powder volume

Page 22: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

A dry powder antibiotic must be reconstituted for use. The label states that the dry powder occupies 0.5 mL . Using the formula for solving powder volume, determine the diluent volume (the amount of solvent added). You are given the final volume for three different examples with the same powder volumes.

Final Volume Powder Volume

1 – 2 mL 1 – 0.5 mL2 – 5 mL 2 – 0.5 mL3 – 10 mL 3 – 0.5 mL

Example

Page 23: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

FV = D+PV or D = FV – PV

1 - D = 2mL – 0.5mL = 1.5 mL2 - D = 5 mL – 0.5 mL = 4.5 mL3 - D = 10 mL – 0.5 mL = 9.5 mL

Page 24: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Example

You are to reconstitute 1 g of dry powder. The label states that you are to add 9.3 mL of diluent to make a final solution of 100 mg/mL. What is the powder volume?

Page 25: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Example 13 What is the powder volume?

Step 1. Calculate the final volume. The strength of the final solution will be 100 mg/mL.

Page 26: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Example What is the powder volume?

Page 27: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Example

Dexamethasone is available as a 4 mg/mL preparation. An infant is to receive 0.35 mg. Prepare a dilution so that the final concentration is 1 mg/mL. How much diluent will you need if the original product is in a 1 mL vial and you dilute the entire vial?

Page 28: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Example How much diluent will you need if the original product is in a 1 mL vial and

you dilute the entire vial?

Page 29: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Example How much diluent will you need if the original product

is in a 1 mL vial and you dilute the entire vial?

Page 30: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

CHILDREN’S DOSES

• Clark’s Rule

• Young’s Rule

These methods are used when either the manufacturer has not recommended dosages for children or the prescriber has requested them to be used. The best explanation for these is simply that children vary so much in weight, size, tolerances, etc.

Page 31: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Clark's Rule

Uses Weight in Lbs, NEVER in Kg.

Here is the formula:

Adult Dose X (Weight ÷ 150) = Childs Dose

Example11 year old girl / 70 Lbs

500mg X (70 ÷ 150) = Child's Dose

500mg X ( .47 )= Child's Dose

500mg X .47 = 235mg

Child's Dose = 235Mg

Page 32: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

Young's RuleYoung’s Rule uses age.(which makes it easier to remember, the word young refers to age)

Here is the formula:

Adult Dose X (Age ÷ (Age+12)) = Child's Dose

Example11 year old girl / 70 Lbs

500mg X (11 ÷ (11+12)) = Child's Dose

500mg X (11 ÷ 23) = Child's Dose

500mg X .48 = Child's Dose

Child's Dose = 240mg

Page 33: CALCULATIONS CHAPTER 6. ROMAN NUMERALS Positional notation – When the second of two letters has a value equal to or smaller than that of the first, add.

CALCULATIONS FOR BUSINESSAverage wholesale price (AWP) + professional fee = selling price of prescription

Gross profit = difference between the selling price and the cost of acquiring the product (acquisition cost)

Net profit = difference between the selling price and all the costs associated with filling the prescription (dispensing fee)

Gross profit = selling price – acquisition cost

Net profit = gross profit – dispensing fee