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C2: Geometric Series Dr J Frost ([email protected]) Last modified: 24 th September 2013
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C2: Geometric Series Dr J Frost ([email protected]) Last modified: 24 th September 2013.

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Page 1: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

C2: Geometric Series

Dr J Frost ([email protected])

Last modified: 24th September 2013

Page 2: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Types of series

2, 5, 8, 11, 14, …+3 +3 +3 This is a:

Arithmetic Series?

Geometric Series?3, 6, 12, 24, 48, …×2 ×2 ×2

common difference

common ratio

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Page 3: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Common Ratio

Identify the common ratio :

1 ,2 ,4 ,8 ,16 ,32 ,… 𝑟=21

24 ,18 ,12 ,8 ,… 𝑟=2/32

10 ,5 ,2.5 ,1.25 ,… 𝑟=1/23

5 ,−5 ,5 ,−5 ,5 ,−5 ,… 𝑟=−14

𝑥 ,−2 𝑥2 , 4 𝑥3 𝑟=−2 𝑥5

1 ,𝑝 ,𝑝2 ,𝑝3 ,… 𝑟=𝑝6

4 ,−1 ,0.25 ,−0.0625 ,… 𝑟=−0.257

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Page 4: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Common Ratio Exam QuestionMay 2013 (Retracted)

Hint for (a): the common ratio between the first and second terms, and the second and third terms, is the same.

𝑟=3𝑝+154𝑝

=3020

=32

a

b

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Page 5: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

th term

Arithmetic Series Geometric Series

𝑈𝑛=𝑎+(𝑛−1 )𝑑 𝑈𝑛=𝑎𝑟𝑛−1

Determine the following:

3, 6, 12, 24, … 𝑈 10=1536

40, -20, 10, -5, … 𝑈 10=−564

𝑈𝑛=(−1 )𝑛− 1× 5

2𝑛− 4

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Page 6: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Another Common Ratio Example

The numbers and form the first three terms of a positive geometric sequence. Find:

a) The possible values of .b) The 10th term in the sequence.

But there are no negative terms so

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Page 7: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Missing information

The second term of a geometric sequence is 4 and the 4th term is 8.The common ratio is positive. Find the exact values of:a) The common ratio.b) The first term.c) The 10th term.

a) Dividing (1) by (2) gives b) Substituting, c)

Bro Tip: Explicitly writing first helps you avoid confusing the th term with the ‘sum of the first terms’ (the latter of which we’ll get onto).

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Page 8: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

th term with inequalities

What is the first term in the geometric progression to exceed 1 million?

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Page 9: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Exam QuestionEdexcel June 2010

25000×1.03=25750

𝑟=1.03

𝑈 𝑁>40000

𝑆10=25000 (1−1.0310 )

1−1.03=£ 287,000

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Page 10: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Sum of the first terms

Arithmetic Series Geometric Series

𝑆𝑛=𝑛2

(2𝑎+ (𝑛−1 )𝑑 )𝑆𝑛=

𝑎 (1−𝑟𝑛)1−𝑟

? ?

Technically you could be asked in an exam the proof of the sum of a geometric series (it once came up!)So let’s prove it…

Page 11: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Sum of the first terms

Geometric Series 𝑆𝑛=𝑎 (1−𝑟𝑛)1−𝑟

3 ,6 ,12 ,24 , 48 ,…

Find the sum of the first 10 terms.

𝑎=3 ,𝑟=2 ,𝑛=104 ,2,1 ,

12,14,18,…

𝑎=4 ,𝑟=12,𝑛=10

? ? ?

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Page 12: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Summation Notation

Find

𝑎=6 ,𝑟=2 ,𝑛=10

𝑆10=6 (1−210 )1−2

=6138

? ? ?

?

Page 13: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Harder Questions: Type 1

Find the least value of such that the sum of to terms would exceed 2 000 000.

An investor invests £2000 on January 1st every year in a savings account that guarantees him 4% per annum for life. If interest is calculated on the 31st of December each year, how much will be in the account at the end of the 10th year?

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Page 14: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Exercise 7DFind the sum of the following geometric series (to 3dp if necessary).

a) (8 terms)c) (6 terms)e) h)

The sum of the first three terms of a geometric series is 30.5. If the first term is 8, find the possible values of .

Jane invest £4000 at the start of every year. She negotiates a rate of interest of 4% per annum, which is paid at the end of the year. How much is her investment worth at the end of (a) the 10th year and (b) the 20th year. (a) (b)

A ball is dropped from a height of 10m. It bounces to a height of 7m and continues to bounce. Subsequent heights to which it bounces follow a geometric sequence. Find out:a) How high it will bounce after the fourth bounce,b) The total distance travelled until it hits the ground for a sixth time.

Find the least value of such that the sum to terms would first exceed 1.5 million.

1

2

4

5

6

???

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??

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Page 15: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Different types of series

1 + 2 + 4 + 8 + 16 + ...

What can you say about the sum of each series up to infinity?

1 + 2 + 3 + 4 + 5 + ...

1 + 0.5 + 0.25 + 0.125 + ...

11+12+13+14+…

This is divergent – the sum of the values tends towards infinity.

This is divergent – the sum of the values tends towards infinity. But arguably, the sum of the natural numbers is .

This is convergent – the sum of the values tends towards a fixed value, in this case 2.

This is divergent . This is known as the Harmonic Series

11+14+19+116

+…This is convergent . This is known as the Basel Problem, and the value is .

Just for fun...

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Page 16: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Sum to InfinityThink about our formula for the sum of the first terms. If we make infinity, what do we require of for not to be infinity (i.e. we want to keep the series convergent). And what will the formula become?

Restriction on : ?

𝑆𝑛=𝑎 (1−𝑟𝑛)1−𝑟

𝑆∞=𝑎1−𝑟?

Page 17: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Examples

1 ,12,14,18,… 𝒂=𝟏 ,𝒓=

𝟏𝟐𝑺∞=𝟐

27 ,−9,3 ,−1 ,… 𝒂=𝟐𝟕 ,𝒓=−𝟏𝟑𝑺∞=

𝟖𝟏𝟒

𝑝 ,𝑝2 ,𝑝3 ,𝑝4 ,… 𝒂=𝒑 ,𝒓=𝒑𝑺∞=𝒑

𝟏−𝒑h𝑤 𝑒𝑟𝑒−1<𝑝<1

? ?

? ?

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𝑝 ,1 ,1𝑝,1

𝑝2,… 𝒂=𝒑 ,𝒓=𝟏

𝒑𝑺∞=

𝒑𝟐

𝒑−𝟏???

Page 18: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

A somewhat esoteric Futurama joke explained

Bender (the robot) manages to self-clone himself, where some excess is required to produce the duplicates (e.g. alcohol), but the duplicates are smaller versions of himself. These smaller clones also have the capacity to clone themselves. The Professor is worried that the total amount mass consumed by the growing population is divergent, and hence they’ll consume to Earth’s entire resources.

Page 19: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

A somewhat esoteric Futurama joke explained

This simplifies to

The sum is known as the harmonic series, which is divergent.

Page 20: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Another Example

The sum to 4 terms of a geometric series is 15 and the sum to infinity is 16.a) Find the possible values of .

b) Given that the terms are all positive, find the first term in the series.

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Page 21: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Another Example

Edexcel May 2011

𝒓=𝟑𝟒

𝒂=𝟐𝟓𝟔

𝑺∞=𝟏𝟎𝟐𝟒

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Page 22: C2: Geometric Series Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 24 th September 2013.

Exercises

Exercise 7D Q6, 7Exercise 7E Q8Exercise 7F Q10