C H A P T E R 10engr response.pdf · Sedra/Smith Copyright © 2010 by Oxford University Press, Inc. Example: low frequency response. of a CE amplifier. R. sig =100. Ω. R. G1//R G2=4

Microelectronic Circuits, 7th Edition Sedra/Smith Copyright © 2010 by Oxford University Press, Inc.

C H A P T E R 10

Frequency Response


A sketch of the frequency response of an amplifier delineating the three frequency bands of interest.

BW=fH-fL

GB=|AM|BW


Frequency response of a CS amplifier with a source resistor.


Method of Short-Circuit Time Constants


Method of Short-Circuit Time Constants

ω = 1/τ = 2πf


Example: low frequency response of a CE amplifier.

Rsig=100ΩRG1//RG2=4.7MCC1=3.33uFCS=1.75uFRD=RL=15KRS=10KCC2=0.53uFgm=1mA/V


Method of Short-Circuit Time ConstantsRsig=100ΩRG1//RG2=4.7MCC1=3.33uFCS=1.75uFRD=RL=15KRS=10KCC2=0.53uFgm=1mA/V

100KΩ 4.7M

3.3uF

1.75uF10K

1K

15K 15K

0.53uF

10Hz 100Hz 10Hz


A sketch of the low frequency response of a CE amplifier.

100Hz10Hz9.1Hzτ=CsRs


Frequency response of an op-amp

Non-inverting Inverting

Replacing R=Z(s) for frequency responsewhere s=jω=j2πf


Frequency response of an op-amp(High Pass Filter)


Frequency response of an op-amp(Low Pass Filter)


Frequency response of an op-amp(Band Pass Filter)

C H A P T E R 10engr response.pdf · Sedra/Smith Copyright © 2010 by Oxford University Press, Inc. Example: low frequency response. of a CE amplifier. R. sig =100. Ω. R. G1//R G2=4

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