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[email protected] MTH16_MTE1_Review.pptx 1 Bruce Mayer, PE Mathematics 16: Applied Calculus-II Bruce Mayer, PE Licensed Electrical & Mechanical Engineer [email protected] MTH 16 MidTerm Exam-1 Review
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Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

Feb 06, 2016

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Page 1: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx1

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Bruce Mayer, PELicensed Electrical & Mechanical Engineer

[email protected]

MTH 16

MidTerm

Exam-1Review

Page 2: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx2

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Student Reference Card

Student Reference CARD = A 3"x5" Flash-Card upon which the student may write ANYTHING that he/she thinks might help him/her do better on the MidTerm Exam

Page 3: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx3

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Improper Integral

Determine the Value (a number) of J as defined by the Improper Integral Below𝐽= 7

ሺ𝑧2+2𝑧+1ሻξ𝑧2+2𝑧−8𝑑𝑧∞2 =

Page 4: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx4

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Page 5: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx5

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Page 6: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx6

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

IJ = 7/((z^2+2*z+1)*sqrt(z^2+2*z-8))

JJ:=int(7/((z^2+2*z+1)*sqrt(z^2+2*z-8)),z)

J:=int(7/((z^2+2*z+1)*sqrt(z^2+2*z-8)), z=2..infinity)

Page 7: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx7

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Adding Integrals

Page 8: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx8

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Adding Integrals

Page 9: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx9

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Cobb-Douglas Model

The Cobb-Douglas Model for the Chabot Motor Company

• Where– P ≡ Vehicle Production in k-

Vehicles per Year– L ≡ Labor Costs in $M/year– K ≡ Capital Costs in $M/year

In Calendar Year 2013 CMC• Produced 7525 k-Vehicles• Spent $25 800M on Labor

544.0456.0532.0, KLKLP

Page 10: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx10

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Cobb-Douglas Model

CMC plans to Increase Production by 1% in 2014• If there is NO additional

Capital, How much added Labor, ΔL, is required?

• If there is NO additional Labor, How much added Capital, ΔK, is required?

Chabot Motor Company

Page 11: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx11

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Page 12: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx12

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Page 13: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx13

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Page 14: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx14

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Chabot Motor Co.P := 7525; a := 0.532; L := 25800; u := 0.456; v := 0.544;

K := (P/(a*L^u))^(1/v)

dPdL := a*K^v*u*L^(u-1)

dPdK := a*L^u*v*K^(v-1)

DL := 0.01*P/dPdL

DK := 0.01*P/dPdK

Page 15: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx15

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

2nd Partials Test

FIND For This Function

• Relative Max or Min• Saddle Points

Page 16: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx16

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Page 17: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx17

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Page 18: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx18

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

Page 19: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH16_MTE1_Review.pptx19

Bruce Mayer, PE Mathematics 16: Applied Calculus-II

2nd Partials Test

See Also MuPAD File:3D_Plot_Max_Min_MTE1_Review_BMayer_1402.mn