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Feb 23, 2018

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  • 7/24/2019 basis mol

    1/380

    GPM (GROSS PROFIT MARGIN)

    KOMPONEN $/kg $ / Lb BM $ /Lb molCH3OH 0.801 0.36332749 32.042 11.6417395HCl 0.4 0.18143695 36.461 6.61537263

    CH3Cl 2 0.90718475 50.488 45.8019436H2O 0 0 18.015 0

    1 Kg = 2.204623 Lb

    reaksi :

    GPM P!o"#k %&'k(') *1 + CH3Cl , 1 + H2O- *1 + CH3OH , 1 + HCl-

    27.5448315

    CH3OH + HCl CH3Cl + H2O

  • 7/24/2019 basis mol

    2/380

    Komponen BM perr!"s #$emi#al engineers" $an%book&'($ e%i(ion) (a

    CH3OH 32.042

    HCl 36.461

    CH3Cl 0.4''

    H2O 1'.01

    Kapasi(as 42000 (on,(a$-n reaksi CH3OH +

    1 (a$-n = 330 $ari

    24 /am

    (on = 1000 Kg

  • 7/24/2019 basis mol

    3/380

    le 2*13

    Cl ** CH3Cl + H2O

  • 7/24/2019 basis mol

    4/380

    rasio mol CH3OH : HCl HCl e#ess 1

    1 : 1.1

    ak(or s#ale*-p pabrik = 1

    as-msi basis CH3OH : 100 Kmol,/am

    3204.2 Kg,/am

    konersi CH3OH = .00 Kirk o($mer)

    kem-rnian CH3OH = .0 5llman& 40 ol)

    CH3OH reaksi = Konersi m-la*m-la

    komponen mol Kmol,/am Kg,/am bereaksi Kmol) sisa kmol)

    CH3OH . . 3200.64.0 4.

    H2O 0.1 0.1 1.'01

    CH3OH + HCl CH3Cl

    m-la . 114.''

    reaksi 4.0 4.0 4.0

    sisa 4. 1.' 4.0

    kon%isi operasi:

    7 = 300 Ckomponen8 = 3 bar = 2.6 a(m

    CH3OH

    pro%-k HCl

    CH3Cl

    H2O

    7o(al Kg,/am)

    -mpan

  • 7/24/2019 basis mol

    5/380

    gar (i%ak (erben(-k pro%-k samping& !ai(- %ime(il e($er pa(en( 4&22&043)

    HCl (eori(is = . kmol,/am 3642.43 Kg,/am

    HCl e#ess = 14.' Kmol,/am 46.36'0' Kg,/am

    HCl (o(al = 114.'' Kmol,/am 41''.'21' Kg,/am

    kem-rnian HCl = 31

    komponen mol Kmol,/am Kg,/am bereaksi kmol) sisa Kmol)

    HCl 31 114.'' 41''.'224.0 1.'

    H2O 6 2.91199 4606.64'

    + H2O

    4.0 H2O (o(al pro%-k = H2O %ari me(anol + H2O %ari H

    4.0

    ;857 O57857 np-(

    Kmol,/am Kg,/am Kmol,/am Kg,/am raksi b

    . 3200.' 4. 160.049 CH3OH 26.69''

    114.'' 41''.'21 1.' 92'.409' HCl 34.11

    0 0 4.0 491.636 CH3Cl 0.0000

    2.'11' 460'.4411 30.916994 631'.1629 H2O 3'.403

    490.6' 11'.266 490.6994 11'.269 100.0000

    kem-rnian C$3Cl =

  • 7/24/2019 basis mol

    6/380

    l + H2O reaksi

    O-(p-(

    era(

    1.333

    6.0916

    3.3

    2.60

    100.0000

    3.346

  • 7/24/2019 basis mol

    7/380

  • 7/24/2019 basis mol

    8/380

    bera(

    CH3OH 1.33341 0.430623 1.363

    HCl 6.091633 0.09''4' 9.91312

    CH3Cl 3.346 61.22'24 2.6223

    H2O 2.6'6 3'.2432039 39.16416

  • 7/24/2019 basis mol

    9/380

    ang bers-$- 10 * 20 C

    r $ar-s bers-$- 30*40 C

    77OM

    Kg,/am

    12'.03'32

    921.20'92223.9'1'2

    3494.'49'

    463.'134 Kmol !ang (erserap : 221.419 Kmol

    49'6.640' H2O %ari -(ili(as !ang %ib-(-$kan : 7o(al Kmol !aang (ers

    30.3994 3''.'03 Kg,/am

    169'4.'30'

    H2O e#ess 20 agar pen%inginan semp-rna = 49'6.64

  • 7/24/2019 basis mol

    10/380

  • 7/24/2019 basis mol

    11/380

    erap @ BM Kmol

    Kg,/am

  • 7/24/2019 basis mol

    12/380

  • 7/24/2019 basis mol

    13/380

    ke %is(ilasi

    CA

    (op pro%-#(

    %ari -en#$er

    ke -(ili(as

    ?s-msi: me(il klori%a (erserap ole$ H2O

    inp-( komponen Kmol (erserap kmol) Kg

    CH3OH 0.0 0.92 32.0100

    HCl 0.1' 0.1' 9.2'4

    CH3Cl 0.1' 4.0'0 41.'

    H2O 19.'22 126.2'0 2'43.1932

    7O7?L 131.921

    maka kebutuhan H2O :

    (o(al Kmol BM H2O = 2393.0291 Kg,/am

    %ig-nakan air proses berlebi$ 20 -n(-k men!emp-rnakan pen!erapan

    (o(al air proses = 2'49.6324'1320'Kg,/am

    H2O pro%-k baa$ = air proses + H2O !ang (erserap

    293.'0Kmol,/am

    komponeninp-( 7

    Kmol,/am Kg,/am Kmol,/am

    CH3OH 0.0 32.0100 0.1'

  • 7/24/2019 basis mol

    14/380

    HCl 0.1' 9.2'4 0.0400

    CH3Cl 0.1' 41.' '.61'

    H2O 19.'22 2'43.1932 31.64

    >5ML?H 9434.43

    C 1'.0901 2'49.632

    7O7?L 102'2.0'60

    komponeninp-(

    o-(p-(

    (op bo((om

    bera(

    CH3OH 0.43062321 0.13062431 1.010944'64'

    HCl 0.09''4991 0.0292'99 0.230029'16

    CH3Cl 61.22'24463 ''.2363624 '.'3323

    H2O 3'.24320390' 11.602903311 '.99'9''9'

    100 100 100

  • 7/24/2019 basis mol

    15/380

    lolos kmol) Kg

    0.1' 6.401

    0.0400 1.46'

    '.61' 4324.3'61

    31.64 6'.63464

    400.'9'0

    p Bo((om

    Kg,/am Kmol,/am Kg,/am

    6.4020 0.92 2.60'0

  • 7/24/2019 basis mol

    16/380

    1.490 0.1' .'29

    4324.3'62 4.0'0 229.3

    6'.6346 126.2'0 2294.3'6

    400.'9' 233.939

    2'49.632

    3'1.2062

    102'2.0'60

  • 7/24/2019 basis mol

    17/380

    D

    A

    NM OVER ALL : F = D + W

    komponen 7i(ik %i%i$ C ) 1 a(m)

    CH3OH 64.4 CH3Cl

    HCl 0. HCl

    CH3Cl *24.3 CH3OH

    H2O 100 H2O

    DEE

    komponen Kmol Kg Fi @i

    ? CH3OH 0.1' 6.40116 0.0019010621 0.001306

    B HCl 0.036 1.46'16 0.0003402124 0.00029

    C CH3Cl '.61962 4324.3'61' 0.922240416 0.''236

    H2O 31.6406' 6'.634641' 0.26'9346'3 0.116029

    7O7?L 119.460322 400.'9' 1 1

    NM komponen CH3OH (A

    mol CH3OH . D = !?. + @? . A

    !?. + @? . A = 0.1' Kmol . . . . 3)

    karena . CH3OH bera%a %i %is(ila( maka:

    . mol CH3OH . D = !? .

    F?. = 0.19'002Kmol . . . . 4)

  • 7/24/2019 basis mol

    18/380

    s-bs(i(-si 4) ke 3)

    @?. A= 0.00001' Kmol

    komponen @. D @. @A. A

    CH3OH 0.1' 0.19'002 0.00001'

    HCl 0.036 0.036 0CH3Cl '.61962 '.61962 0

    H2O 31.6406' 3.16406' 2'.40'0'909

    7O7?L 119.460322 '.04934 2'.40'09'6'9

    LA!" AL#R D# D#$%#LA% = '.04934'99Kmol

    LA!" AL#R D# &O%%OM = 2'.40'09'6'9Kmol

    7 ee% = 24 K 20.' C

    8 = 960 mmHg 1 a(m

    komponen @D 8sa( Ki G

    CH3OH 0.001901062 101.'69441 0.134033'93' .699'9

    HCl 0.000340212 3146.691'9 42.0304603 1946.144

    CH3Cl 0.92224042 3'1'.00'9' .0239114' 20'.6'94

    H2O 0.26'9346'4 1'.234 0.02409306' 1

    7 (rial = 300 K

    % 'e = 7 soler = 303.3139K 30.1639201C

    8 = 960 mmHg 1 a(mkomponen ! 8sa( Ki G

    CH3OH 0.00224311 16.1'96' 0.2193209 .16'2

    HCl 0.00044'949 3'30.6'34 1.22412414 121'.40

    CH3Cl 0.61'611 4''.1432 6.63346433' 16.112'

    H2O 0.03446642 31.21662 0.0420423232 1

    7rial = 30 K

    % bub)e 7 soler = 393.1201K 100.00200C

    8 = 960 mmHg 1 a(m

    komponen @ 8sa( Ki GCH3OH 9.03321E*009 26'.09462 3.494699132 3.49493

    HCl 0 12361.90 162.693263 162.696

    CH3Cl 0 23332.2291 30.9003'1429 30.90043

    H2O 0.29 9.'' 0.'446 1

  • 7/24/2019 basis mol

    19/380

    D*t,*bu* komponen

    komponen inp-( is(ila( as(e

    CH3OH 0.1' 0.19'002 0.00001'

    HCl 0.036 0.036 4.'134'E*022

    CH3Cl '.61962 '.61962 2.419'1E*012

    H2O 31.6406' 3.16406' 2'.40'0'909

    119.460322 '.04934 2'.40'09'6'9

    komponen;857

    O57

    Kmol,/am Kg,/am Kmol,/am Kg,/am

    CH3OH 0.1' 6.40116 0.19'002 6.40131

    HCl 0.036 1.46'16 0.036 1.46'2

    CH3Cl '.61962 4324.3'61' '.61962 4324.3'6

    H2O 31.6406' 6'.634641' 3.1640699 6.'634643'.10'

    400.'9'

    komponen inp-( (op bo((om

    bera(

    CH3OH 0.1306243 0.14'4626 0.00012046

    HCl 0.0292'' 0.033131 3.423E*021

    CH3Cl ''.236362 '.239 2.3'2E*011

    H2O 11.6029033 1.2'6 .'9403

    men-h*tun- ,e.u/

    7 ae = 7%e + 7b-bl = 33'.232'2'2'' K

    2

    8 = 1 a(m 960 mmHg

    komponen @ @% @ 8sa(

    C$3OH 0.001901062 0.00224311 9.033211E*009 999.214

    HCl 0.000340212 0.00044'949 1.6442E*023 93'32.64

    CH3Cl 0.92224042 0.61'611 '.11012E*014 11991.'9H2O 0.26'9346'4 0.03446642 0.269 1''.331

    -mpan mas-k %alam kea%aan /en-$ 1*=0)& maka = 1

    0.

    soler = 0.000

    (rial =

  • 7/24/2019 basis mol

    20/380

    komponen @ G G.@ , G*

    CH3OH 0.0019 4.1293 0.001

    HCl 0.0003 32.0366 0.0003

    CH3Cl 0.922 62.063 0.931

    H2O 0.26'9 1.0000 0.39

    7O7?L 1.0000 1.294'

    maka : = 0.

    komponen @% G G.@% , G*

    CH3OH 0.0022 4.1293 0.0026

    HCl 0.0004 121'.403 0.0004

    CH3Cl 0.61 16.112' 0.60

    H2O 0.034 1.0000 0.090

    7O7?L 1.0000 1.03''

    Komposisi reI- L)

    komponen @L kmol,/am

    CH3OH 0.0022 0.011641194

    HCl 0.0004 0.00232'46'

    CH3Cl 0.61 4.0243

    H2O 0.034 0.1'3262'

    .1'''201

    Komposisi -ap )

    komponen F Kmol,/am

    CH3OH 0.0022 0.21142114

    HCl 0.0004 0.0422''46'

    CH3Cl 0.61 0.6426'94

    H2O 0.034 3.340399249

    4.2369944

  • 7/24/2019 basis mol

    21/380

    *24.3

    0.

    011L

    455H

    F = raksi mol

    @ = raksi bera(

    NM komponen H2O (D

    !B . + @B . A = 31.6406994

    karena 0 H2O bera%a %ibo((om maka:

    0.0 mol H2O . D = @B . A

    @B . A = 2'.40'0'909

    mol H2O D = !B. + @

    B. A

  • 7/24/2019 basis mol

    22/380

    s-bs(i(-si 2) ke 1)

    !B. 3.1640699

    an(oine grain 7oler& C$emi#al enginee

    komponen ?

    CH3OH 1'.'9HCl 16.04

    CH3Cl 16.102

    H2O 1'.3036

    !D D#$%R#&"$# OM6ONEN

    0.00022' GL. = .16'200'

    0.014300'61 GL. A = 3.494929'3

    3.663440121 GL. ?e =

    0.00646296 4.2222046

    3.6'4

    ;m = 4.41099'

    0.62'6162413

    9.''111'4'2@

    0.010321'9

    '.9603'E*006

    0.146040'

    0.'4311'092

    1.0000 untuk komponen HC) (&

    GHCl. ?e =

    44.1993332906

    !A @B. = '.3016909E+012.4'4E*006 @B.A

    0 @B. = '.3016909E+01

    0

    0.991 @B.D = @B. + @B.A

    1.0000 s-bs(i(-si 1) ke 2)

    @BA.A = 4.'1349043E*022

    @B. = 0.036

    GL. GL. A)J0.

    G HCl. GHCl. A)J0.

    CT

    BAPsat

    +=l)

  • 7/24/2019 basis mol

    23/380

    untuk komponen met*) k)o,*'a ( C

    G CH3Cl. ?e =

    6.2266

    @C. = 342296402.1

    @[email protected] = 342296402.1

    @C.D = @C. + @C. A

    57 s-bs(i(-si 3) ke 4)

    A @C.A = 2.419'143'4E*012

    Kmol,/am Kg,/am @C. = '.61962

    0.00001' 0.0006402

    4.'13E*022 1.96E*020

    2.419'1E*012 1.22E*010

    2'.40'0'91 11.9911' kem-rnian CH3Cl %i%is(ila( =11.991'2 kem-rnian C$H3Cl %i bo((om =

    400.'9'

    ki G

    1.02291'0 4.1292622

    9.14'209 32.036'

    1.4'3029 62.06230.249'033 1

    geankoplis& persamaan 11.9*1)

    G CH3Cl. G CH3Cl. A

    = fX

    q.

    1

  • 7/24/2019 basis mol

    24/380

    m,m+1 = 0.03934

    m + 1 = G.@ , G*

    m 0.03''

    = 1.000 %m

    = 0.0'3

    eI-ks %is(ila(

    L = .1''' Kg,/am

    -ap !ang kel-ar %is(ila( men-/- kon%ensor

    = L +

    = 4.236'Kg,/am

  • 7/24/2019 basis mol

    25/380

    Kmol . . . . 1)

    Kmol . . . . 2)

  • 7/24/2019 basis mol

    26/380

    Kmol

    ing %esign)

    B C

    3626. *34.21914.2 *14.4

    2099.9 *2.

    3'16.44 *46.13

    8 = mmHg

    7 = Kelin

    ?& B& C = kons(an(a ?n(oine

    Meng$i(-ng s(age (eori(is ;m)

    s(age

    @?.A . . . 1)

    . . . 2)

    WLDLAverageL x ... =

    AverageL

    WL

    wH

    DH

    DL

    m

    Log

    WX

    WXx

    DX

    DXLog

    N

    .

    .

    .

    .

    . -.

    .*-

    .

    ./*

    =

    WBDBAverageL x ... =

    X

    Xx

    WX

    DX

    WH

    DH

    average

    WB

    DB mN

    .

    .-*

    .

    .

    .

    .

    .

    . =

  • 7/24/2019 basis mol

    27/380

    @C.A . . . . . 3)

    . . . . 4)

    '.23931 2.3'22'9E*011

    men-h*tun- kapa*taCH3Cl !ang %i%apa( %ari %is(ila( = 4324.3'61'1 Kg,/am

    1039'.26'44Kg,$ari

    342413'.'6Kg,(a$-n

    3424.13''67on,(a$-n

    kapasi(as !ang %i$arapkan = 2000 (on,(a$-n

    ak(or s#ale *-p pabrik = 0.0'3623

    maka keb-(-$an: me(anol .'363Kmol,/am 1'9.1113Kg,/amHCl 6.9149 Kmol,/am 244.'39 Kg,/am

    )J0.

  • 7/24/2019 basis mol

    28/380

  • 7/24/2019 basis mol

    29/380

  • 7/24/2019 basis mol

    30/380

  • 7/24/2019 basis mol

    31/380

  • 7/24/2019 basis mol

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  • 7/24/2019 basis mol

    33/380

    komponen;857 O578

    Kmol,/am Kg,/am Kmol,/am

    CH3OH . 3200.' 4.

    HCl 114.'' 41''.'21' 1.'

    CH3Cl 0 0 4.0

    H2O 2.'11994 460'.4411206' 30.91699413

    11'.266'906' 11'.266

    komponen ;857 7O

    Kmol,/am Kg,/am Kmol,/am

    CH3OH 4. 160.049 0.

    HCl 1.' 92'.409' 0.1'

    CH3Cl 4.0 491.6364 0.19

    H2O 30.916994 631'.1626'906' 19.'224'3'91

    air pen%ingin 26.6''11 49'6.6409'3 0

    169'4.'30966'06

    komponen;857

    ?8

    Kmol,/am Kg,/am Kmol,/am

    CH3OH 0. 32.00' 0.1'

    HCl 0.1' 9.2'409' 0.036CH3Cl 0.19 41.'4' '.61962

    H2O 19.'224' 2'43.19320136 31.6406994

    CA 1'.09009 2'49.6324'1320'

    102'2.0'60143144

    komponen;857

    7

    Kmol,/am Kg,/am Kmol,/am

    CH3OH 0.1' 6.40116 0.19'002

    HCl 0.036 1.46'16 0.036

    CH3Cl '.61962 4324.3'61'1 '.61962

    H2O 31.6409 6'.634641'3'9 3.1640699

    400.'9'000'9

  • 7/24/2019 basis mol

    34/380

    komponen ;857 Kg,/am)

    reak(or CA

  • 7/24/2019 basis mol

    35/380

    57

    Kg,/am REA%160.049

    92'.409'

    491.6364

    631'.1626'906'

    906'

    O57857

    BO77OM

    Kg,/am Kmol,/am Kg,/am

    32.00' 3.6 12'.03'32

    9.2'409' 1.9'02 921.20'922 "EN41.'4' 4.942 23.9'1'2

    2'43.19320136 12.'422'06 3494.'49903

    0 26.6''106' 49'6.6409'4

    9434.433236 30.3994436'9

    169'4.'30966'06

    O57857

    L

  • 7/24/2019 basis mol

    36/380

    O57857 Kg,/am)

    bo((om -en#$er L s#r-bber %is(ila( as(e NM OV12'.03'32 2.609664 6.40131400' 0.00064012

    921.20'922 .'292624 1.46'16 1.9069924222E*020

    23.9'1'2 229.292 4324.3'61'1 1.22090643411E*010

    '261.394'91 122.19104'6' 6.'634641'3 11.99119964'

    30.3994436'91 3'1.20621422 43'.109'224 11.991'19'41

    470321031895548

  • 7/24/2019 basis mol

    37/380

    OR

    H $;$%EM

    &ER

    $#

  • 7/24/2019 basis mol

    38/380

    ER ALL

  • 7/24/2019 basis mol

    39/380

    basis per$i(-ngan 1 /am operasi

    sa(-an operasi /o-le,/am

    7empera(-r basis 2 2'.1K

    ;E mi($& 2001)

    %eal gas

    komponen ? B C

    CH3OH 21.1 9.0E*02 2.E*0 *2.'E*0'

    HCl 30.69 *9.20E*03 1.2E*0 *3.0E*0

    CH3Cl 13.'' 1.01E*01 *3.'E*0 2.9E*0

    H2O 32.24 1.2E*03 1.06E*0 *3.60E*0

    CH3OCH3 9.4 1.69E*01 .E*06 *3.34E*0'

    Cp li-i%

    ase li-i% #1 #2 #3 #4 #

    CH3OH 1.06E+0 *362.23 0.39 0 0HCl 49300 0 0 0 0

    CH3Cl 610 *209. 0.3946 0.0004'' 0

    H2O 296390 *200.1 '.12 *0.014116 .3901E*006

    0C

    ==T

    T

    pii dTCnHQ0

    ..

    432

    32

    432T

    DT

    CT

    BATCp

    DTCTBTACpdtT

    To

    +++=

    +++=

    5432

    432

    5

    5

    4

    4

    3

    3

    2

    21

    54321

    TC

    TC

    TC

    TC

    TCCp

    TCTCTCTCCCpdt

    T

    To

    ++++=

    ++++=

  • 7/24/2019 basis mol

    40/380

    gain 7oler& C$emi#al engineering %esign)

    Cp gas

    ase gas

    HCl

    8err!& (able 2*16 $al 220)

    Cp = >,Kmol K

    += -&+*..

    DT

    CBAdTCp

  • 7/24/2019 basis mol

    41/380

    H2O

    L&b =

    7# =

    7b =

    L = la(en( $ea( (empera(-re 7& K/,Kmol

    L&b = la(en( $ea( a( ($e normal boiling poin(& K/,Kmol 7 =

    7# = #ri(i#al (empera(-re & K

    7b = boiling poin(& K L =7 = 7empera(-re& K

    6.9+0.000'47 8err!&(able 2*14 $al 211)

    =bc

    c

    bvvTT

    TTLL .

  • 7/24/2019 basis mol

    42/380

    406'3 K/,kmol

    649.3K

    100C

    393.1K

    30 C

    303.1K

    1090.9'

  • 7/24/2019 basis mol

    43/380

    s(eam

    7s = 300 C

    7i = 30 C 7o = 20 C

    s(eam kon%ensa(

    7= 300 C

    Ne,a

  • 7/24/2019 basis mol

    44/380

    N s(eam = 31'' K/,Kg 1312.03' b(-,lb

    < s(eam =

    M s(eam = 0.6261342Kg

    NERACA ENER>#

    inp-( o-(p-(Komponen H K/,/am) H K/,/am)

    CH3OH 6426.1'61309 19202.1'621

    H2O 166.24963092' 2149.41336192

    < s-ppl! 1936.16 0

    < loss 0 '996.'096

    1'1'1 1'1'1

    Ms(eam . Ns(eam

  • 7/24/2019 basis mol

    45/380

    D-ngsi : meng-apkan me($anol %engan ba

    kon%isi operasi : 7 = 20

    8 = 1.'

    li-i%

    komponen

    CH3OH

    HCl

    CH3Cl

    H2O

    as

    komponen

    CH3OH

    HCl

    CH3Cl

    H2O

    enta)p* k2 C 7 =

    2'.1K

    komponen

    CH3OH

    H2O

    enta)p* k

    gan maksim-m 10 ) -lri#$& $al 432)

    N CH3OH

    N H2O

    1 a(m = 101.32 Kpa

    komponen

    =T

    T

    p

    ref

    dCH

  • 7/24/2019 basis mol

    46/380

    geankoplis& s(eam (able ?.2*10 CH3OH

    H2O

    = bvv LL .

  • 7/24/2019 basis mol

    47/380

    (-an s(eam

    C

    a(m

    C4 C2 C3 C1 C8

    1.06E+0 *3.62E+02 .3'E*01 0.00E+00 0

    4.93E+04 .00E+01 0.00E+00 0.00E+00 0

    .6E+04 *2.0'E+02 3.9E*01 4.''E*04 0

    2.96E+0 *2.0E+03 '.13E+00 *1.41E*02 .39E*006

    A & C D

    2.12E+01 9.0E*02 2.E*0 *2.'E*0'

    3.09E+01 *9.20E*03 1.2E*0 *3.0E*0

    1.3E+01 1.01E*01 *3.'E*0 2.9E*0

    3.22E+01 1.2E*03 1.06E*0 *3.60E*0

    mponen ke)ua,20 C 7re = 2 C

    23.1 K 2'.1 K

    n Kmol,/am) H K/,/am)

    6633.'642461 122.0'1069 '12902.9

    9340.442426 0.122630'21 00.16

    '13602.

    mponen

    (er/a%i per-ba$an ase

    329' K/,Kmol gain 7oler& C$emi#al engineering %esign)

    406'3 K/,Kmol

    n Kmol,/am) H

    Cp %7

    Cp %7

    + nT -.*

  • 7/24/2019 basis mol

    48/380

    6633.'642461 122.0'1069 19202

    9340.442426 0.122630'21 2149.413

    193200

    H2O

    L&b =

    7# =

    7b =

    L = la(en( $ea( (empera(-re 7& K/,Kmol

    L&b = la(en( $ea( a( ($e normal boiling poin(& K/,Kmol 7 =

    7# = #ri(i#al (empera(-re & K

    7b = boiling poin(& K L =

    7 = 7empera(-re& K

    CH3OHL&b =

    7# =

    7b =

    7 =

    L =

    bc

    c

    TT

    TT

  • 7/24/2019 basis mol

    49/380

  • 7/24/2019 basis mol

    50/380

    406'3 K/,kmol

    93.1K

    100C

    393.1K

    20C

    23.1K

    10190.9

    329' K/,kmol 329'

    93.1K

    64.4C

    339.K

    20C

    23.1K

    94'6.'42

  • 7/24/2019 basis mol

    51/380

    s(eam

    7s = 300 C

    7i = 30 C 7o = 20 C

    s(eam kon%ensa(

    7 = 300 C

    ;era#a energi (o(al:

    H inp-( + < s-ppl! = H o-(p-( + < loss

    enta)p* komponen *nput7 = 30 C 7re =

    303.1K

    komponen n Kmol,/am) H K/,/am)

    HCl 23962 140.''4412' 33499.66

    H2O 136060.01'9' 313.'144366 4223.3

    4'912.

    ne,a

  • 7/24/2019 basis mol

    52/380

    M s(eam = 213.'10932060Kg

    NERACA ENER>#inp-( o-(p-(

    Komponen H K/,/am) H K/,/am)

    HCl 33499.660131493 1436040.299

    H2O 4223.2'04442 411''.'063

    < s-ppl! 6'0'64.613'0'4 0

    < loss 0 34044'.2306

    926969' 926969'

  • 7/24/2019 basis mol

    53/380

    D-ngsi : meng-apkan HCl %engan ban(-an s(eam

    kon%isi operasi : 7 = 20 C

    8 = 1.' a(m

    komponen ? B

    CH3OH 21.1 9.0E*02

    HCl 30.69 *9.20E*03

    CH3Cl 13.'' 1.01E*01

    H2O 32.24 1.2E*03

    komponen C1 C2CH3OH 1.06E+0 *3.62E+02

    HCl 4.93E+04 .00E+01

    CH3Cl .6E+04 *2.0'E+02

    H2O 2.96E+0 *2.0E+03

    enta)p* komponen ke)ua,2 C 7 = 20 C

    2'.1 K 23.1 K

    komponen n Kmol,/am)

    HCl 6963.2'6 140.''4412'

    H2O 9340.44 313.'14439

    enta)p* komponengan maksim-m 10 ) -lri#$& $al 432)

    N HCl 16161 K/,Kmol

    N H2O 406'3 K/,Kmol

    komponen n Kmol,/am)

    & s(eam (able ?.2*10 HCl 6963.2'6 140.''4412'

    H2O 9340.44 313.'14439

    Cp %7

    Cp %7

    +=T

    T

    p

    ref

    ndTCH -.*

  • 7/24/2019 basis mol

    54/380

    L = la(en( $ea( (em

    L&b = la(en( $ea( a( (

    7# = #ri(i#al (empera

    7b = boiling poin(& K

    7 = 7empera(-re& K

    =

    bc

    cbvv

    TT

    TTLL .

  • 7/24/2019 basis mol

    55/380

    C

    2.E*0 *2.'E*0'

    1.2E*0 *3.0E*0

    *3.'E*0 2.9E*0

    1.06E*0 *3.60E*0

    C3 C4 C.3'E*01 0.00E+00 0

    0.00E+00 0.00E+00 0

    3.9E*01 4.''E*04 0

    '.13E+00 *1.41E*02 .39E*006

    7re = 2 C

    2'.1K

    H

    2'41.9

    2301'30

    324692

    (er/a%i per-ba$an ase

    gain 7oler& C$emi#al engineering %esign)

    H

    1436041

    411'

  • 7/24/2019 basis mol

    56/380

    62922

    H2O

    L&b = 406'3 K/,kmol

    7# = 93.1 K

    7b = 100 C

    era(-re 7& K/,Kmol 393.1 K

    e normal boiling poin(& K/,Kmol 7 = 20 C

    (-re & K 23.1 K

    L = 10190.9

    CH3OH

    L&b = 16161 K/,kmol

    7# = 93.1 K

    7b = 64.4 C

    339.K

    7 = 20 C

    23.1K

    L = 342.94

  • 7/24/2019 basis mol

    57/380

    7i = 20 C 7o = 300 C

    Ne,a

  • 7/24/2019 basis mol

    58/380

    NERACA ENER>#komponen inp-( K/,/am) o-(p-( K/,/am)

    CH3OH '12902.909 10'03'.9316403

    HCl 0 1161299.139'1

    H2O 2302930.44632 2'242.9'93'

    < s-ppl! 2030'9.39

    < loss 10143.96'961

    7O7?L 146312.6' 146312.6'

  • 7/24/2019 basis mol

    59/380

    D-ngsi : memanaskan me($anol %an HCl %engan ban(-an s(eam

    kon%isi operasi : 7 = 300 C

    8 = 3 a(m

    komponen ?

    CH3OH 21.1

    HCl 30.69

    CH3Cl 13.''

    H2O 32.24

    enta)p* kompone2 C 7 = 300

    2'.1 K 93.1

    Me($anol

    komponen

    CH3OH '636.493

    H2O 006.94

    HCl

    komponen

    HCl '242.96

    H2O 006.94

    %O%AL O"%6"% =

    keb-(-$an s(eam

    gan maksim-m 10 ) -lri#$& $al 432) s(eam !ang %ig-nakan

    N s(eam = 31''

    < s(eam =

    M s(eam = 639.03''

    Cp %7

    Cp %7

    Ms(eam .

  • 7/24/2019 basis mol

    60/380

  • 7/24/2019 basis mol

    61/380

    B C

    9.0E*02 2.E*0 *2.'E*0'

    *9.20E*03 1.2E*0 *3.0E*0

    1.01E*01 *3.'E*0 2.9E*0

    1.2E*03 1.06E*0 *3.60E*0

    n outputC 7re = 2 C

    K 2'.1 K

    n Kmol,/am) H

    122.0'109 10'03

    0.122630'22 1104.0

    10143

    n Kmol,/am) H

    140.''4413 1161299

    313.'1444 2'2434'

    3'62

    04496K/,>am

    a%a (ekanan a(m %engan s-$- 360 C

    K/,Kg eankoplis& s(eam (able ?.2*10

    Kg

    s(eam

  • 7/24/2019 basis mol

    62/380

  • 7/24/2019 basis mol

    63/380

    7o = 330 C

    7i = 300 C

    300 C

    2 C PH reaksi 2 C

    Ne,a

  • 7/24/2019 basis mol

    64/380

    ber%asarkan Himmelbla- $alaman 46:

    panas reaksi s(an%ar& 2 C

    reaksi !ang (er/a%i :

    CH3OH + HCl ** CH3Cl + H2O

    %a(a en(alpii pemben(-kan ain 7oler& #$emi#al engineering %esig

    komponen PH K/,mol) K/,Kmol

    CH3OH *201.3 *201300

    HCl *2.36 *2360

    CH3Cl *'6.39 *'6390

    H2O *242 *242000

    *622030

    komponen n kmol) PH K/,/am) PH reaksi K/,/am)

    CH3OH 6.124034 *1233044.319 *110636'.012392

    HCl 24.0163'14 *226291.2'213

    CH3Cl 116.3'29'11 *1001'0.'0946

    H2O 430.0'6'613 *1040'1020.4423

    *111201.012392

    Ne,a

  • 7/24/2019 basis mol

    65/380

    -ngsi : mereaksikan me(anol %an HCl

    kon%isi operasi : 8 = 3 a(m

    7 = 300 C

    330 C

    komponen ?

    CH3OH 21.1

    HCl 30.69

    CH3Cl 13.''

    H2O 32.24

    enta)p* ke)ua,

    7 = 330

    603.1

    04496'.9130K/,/am

    komponen Cp %7

  • 7/24/2019 basis mol

    66/380

    CH3OH 32.3'2936

    HCl 12'.'21494133

    CH3Cl ''9.191'4'92

    H2O 10014.6'94'269

    NERACA ENER>#komponen inp-( K>,/am)

    n) CH3OH 10'03'.93164

    HCl 1161299.139'

    CH3Cl 0

    H2O 2'242.9'936

    PHr 110636'.01

    < serap

    116'193.923

    ekso(ermis

    110636'.01

    kebutuhan a*, pen'*n-*n:

    m = ,kmol K

  • 7/24/2019 basis mol

    70/380

    NERACA ENER>#

    komponeninp-( K/,/am) o-(p-( K/,/am)

    (op bo((om

    CH3OH 60'3.10131 1913.1'669 2943.10026

    HCl 223691.0'036 449.200063 61.100'

    CH3Cl 43.133102 1114'.'06 0

    H2O 43091'.0664 3919.033 14106'.9

    CA 9'0.349 0

    < serap *10964.0

    7O7?L 4'306.43 13061634.099

    13041.026 13041.026

    kebutuhan a*, pen'*n-*n: Cp air = 4.1'6'

    7in = 20

    m = < 7 o-( = 30

    Cp.P7

    26224.420Kg

    < = m.Cp.P7

  • 7/24/2019 basis mol

    71/380

    D-ngsi : men%inginkan se#ara men%a%ak %engan ban(-an air pen%ingin !a

    kon%isi operasi :

    7 = ' C

    8 = 1 a(m

    komponen C4 C2 C3

    CH3OH 10'00 *362.23 0.39

    HCl 49300 0 0

    CH3Cl 610 *209. 0.3946

    H2O 296390 *200.1 '.12

    komponen ? B C

    CH3OH 21.1 9.0E*02 2.E*0

    HCl 30.69 *9.20E*03 1.2E*0

    CH3Cl 13.'' 1.01E*01 *3.'E*0

    H2O 32.24 1.2E*03 1.06E*0

    CH3OCH3 9.4 1.69E*01 .E*06

    enta)p* output%O6 6ROD"C%

    7 = ' C 7re =

    3'.1K

    komponen n kmol) H

    CH3OH 13'.426 1.220'106' 1913.1'669'9

    C HCl 1'2'.123 0.240163'14 449.200063

    K CH3Cl 1012.2' 110.636420 1114'.'061

    H2O 13'.611 13.30'96 3919.032'

    4'306.429&O%%OM 6ROD"C%

    7 = 30 C 7re =

    303.1K

    N CH3OH 329' K/,Kmol

    N HCl 16161 K/,Kmol gain 7oler& C

    N H2O 406'3 K/,Kmol

    Cp %7

  • 7/24/2019 basis mol

    72/380

    komponen n Kmol,/am) H

    CH3OH 2411.2 4.003296291 2943.10026

    HCl 23962 24.2662194 61.100'

    H2O 136060 10131.2106 14106'.92

    141'.113

    L = la(en( $ea( (empera(-re 7& K/,K

    L&b = la(en( $ea( a( ($e normal boilin

    K/,Kg K 7# = #ri(i#al (empera(-re & K

    C 23.1 K 7b = boiling poin(& K

    C 303.1 K 7 = 7empera(-re& K

    Cp %7

    =bc

    c

    bvvTT

    TTLL .

  • 7/24/2019 basis mol

    73/380

    g bers-$- 10 s,% 20 C

    C1 C8

    0 0

    0 0

    0.0004'' 0

    *0.014116 .39E*006

    *2.'E*0'

    *3.0E*0

    2.9E*0

    *3.60E*0

    *3.34E*0'

    2 C

    2'.1K

    2 C

    2'.1K

    $emi#al engineering %esign)

  • 7/24/2019 basis mol

    74/380

    H2O

    L&b = 406'3 K/,kmol

    7# = 303.1K

    7b = 100 C

    ol 393.1 K

    poin(& K/,Kmol 7 = ' C

    3'.1K

    L = 316.21

    CH3OH

    L&b = 406'3 K/,kmol

    7# = 303.1K

    7b = 64.4 C

    339.K

    7 = ' C

    3'.1K

    L = 604.4

  • 7/24/2019 basis mol

    75/380

    CA

    7# = 30 C

    7i= ' 7o = 0 C

    CA

    7#o = 4 C

    NERACA ENER># %O%AL : H *nput = H o

    enta)p* *nputH o-(p-( %ari (op

  • 7/24/2019 basis mol

    76/380

    m = 4632.'243093Kg

  • 7/24/2019 basis mol

    77/380

    D-ngsi = men%inginkan -ap kel-aran -en#$er %engan ban(-an CA

    kon%isi operasi =

    7 = 0 C

    8 = 1 a(m

    utput + e,ap

    komponen ? B

    CH3OH 21.1 9.0E*02

    HCl 30.69 *9.20E*03

    CH3Cl 13.'' 1.01E*01

    H2O 32.24 1.2E*03

    NERACA ENER>#

    komponen inp-( K>,/am) o-(p-( K/,>am)CH3OH 1913.1'669'92 69.09402'

    HCl 449.200062' 1'9.33094231

    CH3Cl 1114'.'060' 41'46.90203339

    H2O 3919.032' 1611.436'6

    < serap 2049'.4030'21

    4'306.4292 4'306.429249

  • 7/24/2019 basis mol

    78/380

  • 7/24/2019 basis mol

    79/380

    C

    2.E*0 *2.'E*0'

    1.2E*0 *3.0E*0

    *3.'E*0 2.9E*0

    1.06E*0 *3.60E*0

  • 7/24/2019 basis mol

    80/380

  • 7/24/2019 basis mol

    81/380

    CA

    7# = 20 C 7o = 3 C

    7i = 0 C 7 = 30 C

    enta)p* *nputH o-(p-( %ari #ooler = 1''2'.436 K/,/am

    Cooling a(er = 493463.6'' K/,/am

    1731272232K/,/am

    H2O %ari -(ili(as

    7 = 20 C 7re = 2

    23.1 K 2'.1

    komponen kg,/am Kmol,/am HH2O 342.091014 13.'42639 136060.01 493464

    H *nput = H output + e,ap< serap = *''1292.1K/,/am

    Cp %7

  • 7/24/2019 basis mol

    82/380

    NERACA ENER>#

    komponeninp-( K/,/am) o-(p-( K/,/am)

    (op bo((om

    CH3OH 69.09403 263.44409 260.212296

    HCl 1'9.3309423 9.032126 963.99444

    CH3Cl 41'46.9020334 10.3'62 0

    H2O 1611.436'6 62416.219 1393'30.1

    CA 493463.6'' 0

    < serap *''1292.1

    7O7?L 9'660.1966 4'632.04

    43422.2316 43422.2320

    kebutuhan a*, pen'*n-*n: Cp air = 4.1'6'

    7in = 20

    m = < 7 o-( = 30

    Cp.P7

    212364.3'4Kg

    < = m.Cp.P7

  • 7/24/2019 basis mol

    83/380

    D-ngsi : men!erap HCl e#ess %an komponen lainn!a %engan ban(-an CA

    kon%isi operasi :

    7 = 3 C

    8 = 1 a(m

    komponen C4 C2 C3

    CH3OH 10'00 *362.23 0.39

    HCl 49300 0 0

    CH3Cl 610 *209. 0.3946

    H2O 296390 *200.1 '.12

    komponen ? B C

    CH3OH 21.1 9.0E*02 2.E*0

    HCl 30.69 *9.20E*03 1.2E*0

    CH3Cl 13.'' 1.01E*01 *3.'E*0

    H2O 32.24 1.2E*03 1.06E*0

    CH3OCH3 9.4 1.69E*01 .E*06

    enta)p* output%O6 6ROD"C%

    7 = 3 C 7re =

    30'.1K

    komponen n kmol) H

    CH3OH 21.046 1.220'106' 263.444069

    C HCl 306.3441 0.240163'14 9.0321261

    K CH3Cl 143.'9 110.636420 10.3'623

    H2O 322.49 13.30'96 62416.219

    9'660.1966&O%%OM 6ROD"C%

    7 = 30 C 7re =

    303.1K

    N CH3OH 329' K/,Kmol

    N HCl 16161 K/,Kmol gain 7oler& C

    N H2O 406'3 K/,Kmol

    Cp %7

  • 7/24/2019 basis mol

    84/380

    komponen n Kmol,/am) H

    CH3OH 2411.2 4.003296291 260.212296

    HCl 23962 24.2662194 963.99444

    H2O 136060 10131.2106 1393'30.1

    1394604.109

    L = la(en( $ea( (empera(-re 7& K/,K

    L&b = la(en( $ea( a( ($e normal boilin

    K/,Kg K 7# = #ri(i#al (empera(-re & K

    C 23.1 K 7b = boiling poin(& K

    C 303.1 K 7 = 7empera(-re& K

    Cp %7

    =bc

    c

    bvvTT

    TTLL .

  • 7/24/2019 basis mol

    85/380

    C1 C8

    0 0

    0 0

    0.0004'' 0

    *0.014116 .39E*006

    *2.'E*0'

    *3.0E*0

    2.9E*0

    *3.60E*0

    *3.34E*0'

    2 C

    2'.1K

    2 C

    2'.1K

    $emi#al engineering %esign)

  • 7/24/2019 basis mol

    86/380

    H2O

    L&b = 406'3 K/,kmol

    7# = 23.1K

    7b = 100 C

    ol 393.1 K

    poin(& K/,Kmol 7 = 30 C

    303.1K

    L = 0'.39

    CH3OH

    L&b = 329' K/,kmol

    7# = 23.1K

    7b = 64.4 C

    339.K

    7 = 30 C

    303.1K

    L = 94.4

    HCl

    L&b = 16161 K/,kmol

    7# = 23.1K

    7b = 0. C

    323.6K

    7 = 30 C

    303.1K

    L = 2'.6'

  • 7/24/2019 basis mol

    87/380

    CA

    7# = 30 C

    7i= 3 7o = 32. C

    CA

    7#o = 4 C

    NERACA ENER># %O%AL : H *nput = H o

    enta)p* *nputH o-(p-( %ari (op s#r-bber = 9'660.1'K/,>am

    enta)p* output

    7 = 20.' C 7re = 2 C

    24 K 2'.1 K

    komponen n kmol) HCH3OH *442211.'0469 0.24016 *10'.341

    HCl *11.'9 0.04003 *.'112

    CH3Cl *4039.66639914 10.03 *42431.99

    H2O *11612'.4640'4 3'.909'2 *40.'

    *'964.2'

    (er/a%i per-ba$an ase

    N CH3OH 329' K/,Kmol

    N HCl 16161 K/,Kmol gain 7oler& C$emi#al enginee

    N CH3Cl 21436 K/,Kmol

    N H2O 406'3 K/,Kmol

    komponen n kmol) H

    CH3OH ''.3'3'2611 0.24016 *904.'99

    HCl 129.21'9'9239 0.04003 *'030.02

    CH3Cl '.4942421 10.03 1'362

    Cp %7

    Cp %7

    +=T

    T

    p

    ref

    ndTCH -.*

  • 7/24/2019 basis mol

    88/380

    H2O 133.'12'13'3 3'.909'2 *910349

    112'12

    ;era#a energi (o(al

    H inp-( = H o-(p-( + < serap

    < serap = *10431.''2K/,/am 10432

    keb-(-$an air pen%ingin:

    H 4 C) = 1''.4 K/,Kg

    H 30 C) = 12.9 K/,Kg

    m =#komponen inp-( K>,/am) o-(p-( K/,>am)

    CH3OH 263.444066' *904.'992'6

    HCl 9.03212611 *'030.022349'4

    CH3Cl 10.3'6233 1'3624.6491

    H2O 62416.2194' *910349.42940'

    < serap *10431.''2

    9'660.1966 9'660.19660024

  • 7/24/2019 basis mol

    91/380

    C

    2.E*0 *2.'E*0'

    1.2E*0 *3.0E*0

    *3.'E*0 2.9E*0

    1.06E*0 *3.60E*0

    C3 C1 C8

    0.39 0 0

    0 0 0

    0.3946 0.0004'' 0

    '.12 *0.014116 .39E*006H2O

    L&b = 406'3 K/,kmol

    7# = 23.1 K

    7b = 100 C

    (empera(-re 7& K/,Kmol 393.1 K

    a( ($e normal boiling poin(& K/,Kmol 7 = *16.3 C

    pera(-re & K 26.' K

    (& K L = *1'4'.34

    re& K

    CH3OH

    L&b = 329' K/,kmol

    7# = 23.1 K

    7b = 64.4 C

    339.K

    7 = *16.3 C

    26.' K

    L = *2'''1.''

  • 7/24/2019 basis mol

    92/380

    HCl

    L&b = 16161 K/,kmol

    7# = 23.1 K

    7b = 0. C

    323.6K

    7 = 30 C

    *16.3K

    L = *1634

    CH3Cl

    L&b = 21436 K/,kmol

    7# = 23.1 K

    7b = *24.3 C

    24'.'K

    7 = *16.3 C

    26.' K

    L = 19'.13

  • 7/24/2019 basis mol

    93/380

    Ne,a

  • 7/24/2019 basis mol

    94/380

    HCl 0.00044 1.9'9'4' 0.0403 222.1239

    CH3Cl 0.61'61 306.412 10.1024 112.019

    H2O 0.03449 6.9966 3.'932 234.919

    < kon%ensasi = .H * .H% * L.HL 221639

    keb-(-$an air pen%ingin

    s-$- air pen%ingin mas-k = 30 C

    s-$- air pen%ingin kel-ar = 4 C

    Cp air pen%ingin = 4.1'4 K/,Kg

    < serap =

    m air pen%ingin = < serap

    3314.'Kg

    Ne,a

  • 7/24/2019 basis mol

    95/380

    -ngsi : memisa$kan me(il klori%a %ari imp-ri(iesn!a.

    kon%isi operasi = 8 = 1 a(m

    7 = (rial boiling poin( ee%

    kon'ena* + )o

    n'ena* + )o

    @9017294348308K/,/am

    7 = 2. C

    enta)p* '*t*)at

    C 7 = 30.163'322

    K 303.313'322

    N H komponen Kg,/am

    329' '693.' CH3OH 9.'002'1

  • 7/24/2019 basis mol

    96/380

    16161 '03.33'9 HCl 1.9'690'461

    21436 226494 CH3Cl 303.030303620

    406'3 1'4'4.9 H2O 6.932133262

    2294226

    K/,/am enta)p* bottom

    7 = 100.00200'6393.1200'6

    komponen Kg,/am

    CH3OH 0.0009'0'1

    HCl 2.1223033E*020

    CH3Cl 1.4661'0E*010

    H2O 629.'13'4

    NERACA ENER>#loss komponen inp-( K>,/am)

    ss

    CH3OH *10'.340'496

    m 10) HCl *.'11164

    CH3Cl *42431.963'4

    H2O *40.'1226191

    < reboiling 306'6.'1022

    < kon%ensasi

    < loss

    - 10 C m (able D*2 2'1010.3169306

  • 7/24/2019 basis mol

    97/380

    komponen ? B C

    CH3OH 21.1 9.0E*02 2.E*0 *2.'E*0'

    HCl 30.69 *9.20E*03 1.2E*0 *3.0E*0

    CH3Cl 13.'' 1.01E*01 *3.'E*0 2.9E*0

    H2O 32.24 1.2E*03 1.06E*0 *3.60E*0

    komponen C4 C2 C3 C1 C8

    CH3OH 10'00 *362.23 0.39 0 0

    HCl 49300 0 0 0 0

    CH3Cl 610 *209. 0.3946 0.0004'' 0

    H2O 296390 *200.1 '.12 *0.014116 .39E*006

    enta)p* ,e.u/

    C 7re = 2 C 7 = 30.163' C

    K 2'.1 K 303.3136 K

    n kmol) H komponen Kg,/am n kmol)

    0.2441'99 4121.2 132.66'3 CH3OH 0.00006 0.00016

    Cp %7

  • 7/24/2019 basis mol

    98/380

    0.040032963 24439.3 12.02923 HCl 0.00113 3.12E*00

    10.034' 4964'.6 2290.9 CH3Cl 3.3'161 0.0669'

    3.'909'192 1366 419.416 H2O 0.044466 0.00246'

    9'32.'6

    C 7re = 2 CK 2'.1 K

    n kmol) H

    2.40164E*00 904'23 0.1926

    .02'1E*022 3'00936 2.24E*01'

    2.64'E*012 6940236 2.00E*00'

    34.'390396' 1''039 33'9.6

    33'9.'

    o-(p-( K/,/am)

    %is(ila( bo((om

    132.66'302 0.1926

    12.029233609 2.24E*01'

    2290.913' 2.00E*00'

    419.4191 33'9.6

    221639

    13433

    9'32.'62613 2231992'1010.31693063

    Cp %7

  • 7/24/2019 basis mol

    99/380

    7re = 2 C

    2'.1K

    H

    4121.2 0.0'4

    Cp %7

  • 7/24/2019 basis mol

    100/380

    24439.3 0.00966

    4964'.6 33.33196

    1366 3.441

    36.'9''

  • 7/24/2019 basis mol

    101/380

    7ipe (angki silin%er (egak %engan %asar %a(ar %an a(asn!a b

    %asar pemili$an 5m-mn!a %ig-nakan -n(-k li-i% pa%a (ekanan a(mos

    8er$i(-ngan :

    MEN>H#%"N> DEN$#%A$ CAM6"RAN:

    komponen mol kmol,/am massa Kg,/am) Q Kg,m3) ol-me m

    CH3OH 0. 122.0'11 32.40944920 9'3. .00936

    H2O 0.001 0.122630'2 2.2014243 0.00222

    329.616636' .0096

    ensi(as #amp-ran = 9'3.3' Kg,m3

    4'.44919'lb,(3

    %iren#anakan pen!impanan -n(-k 10 $ari %engan 3 b-a$ (angki mem-%a$kan

    se$ingga ol-me masing*masing:

    pen!impanan = 10 $ari

    /-mla$ (angki = 6 b-a$

    keb-(-$an me(anol = 329.61664 Kg,/am selama 1 $ari

    42629.4 Kg selama 10 $ari

    259449 lb

    Bo)ume metano) pa'a tan-k*:

    ol-me (angki = 424'.4669 (3

    ol-me me(anol %alam 1 (angki = 9096.41112266 (3

    as-msi ba$an isi '0 ol-me (angki ak(or keamanan)

    se$ingga ol-me (angki = '41.6334949 (3

    '41.6334949(3

    MENEN%"AN D#MEN$# %AN>#

    rasio H, = 3,'

    = iame(er Brownel,1

    H = 7inggi 7angki

    R = 3.1413

    H = 11.4'''3 (

    3.04'm

    = 30.6636'' (

    .34622 m

    HDvo!me ...4

    1 2

    =

  • 7/24/2019 basis mol

    102/380

    %ig-nakan %iame(er 3 ( %an (inggi 16 ( &maka

    MENEN%"AN !"MLAH 6LA%E DAN %E&AL $HELL

    "Browne and $o!ng% pers &'()%(*++ , -./

    ( = (ebal s$ell S in

    8 = (ekanan in(ernal S psi

    % = insi%e %iame(er S in

    C = ak(or korosi S in 1,' in)

    E = ak(or pengelasan& %ig-nakan %o-ble el%

    = s(ress alloable& ba$an kons(r-ksi Carbon

    ra%e C& maka = 1260 psi

    8 = (ekanan in(ernal S 8si = %ensi(as air pa%a s-$- 30 Cel#i-s =H = (inggi #o-rseS (

    Cou,e 4

    H = 16 (

    (1 = 0.214' in

    %ipili$ (ebal s$ell s(an%ar = 0.2' in BronellS

    meng$i(-ng pan/ang pla(e%iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al

    /arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (

    L = pan/ang (iap pla(e S (

    % =%iame(er %alam (ang

    n = /-mla$ pla(e

    el% leng($ = n alloable el%e% /oin(

    L1 = 10.'''4 in

    /a%i = pan/ang pla(e = 10.'''3'3'in

    lebar pla(e = ' (

    (ebal pla(e = 0.2'

    Cou,e 2

    H = 16 ( * ' (

    (2 = 0.124431

    %ipili$ (ebal s$ell s(an%ar = 0.1 in

    %iren#anakan akan mengg-nakan s$ell pla(e %engan 6 in ' () butt-weldes cou

    C0f

    dP

    t += ..2.

    144-1* = HP

    n

    engt1weddL

    12

    .. =

  • 7/24/2019 basis mol

    103/380

    meng$i(-ng pan/ang pla(e

    %iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al

    /arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (

    L = pan/ang (iap pla(e S (

    % =%iame(er %alam (ang

    n = /-mla$ pla(e

    el% leng($ = n alloable el%e% /oin(

    L1 = 10.'92' in

    /a%i = pan/ang pla(e = 10.'929644in

    lebar pla(e = ' (

    (ebal pla(e = 0.1

    MENEN%"AN %O6 AN>LE "N%" CON#CAL ROOF

    bila %ig-nakan 10 pla(e (iap angle& maka pan/ang (iap angle :

    L = 10.093 (

    "MENEN%"AN %E&AL DAN %#N>># HEAD %AN>#

    "Browne and $o!ng% Pers')'(.-% (*++ , ((2/

    (ekanan pen!impanan = 1 a(m = 14.9 psi

    %an %iambil ak(or keamanan 10 maka:

    8 = 16.19 8si #os 30 = 0.'66

    ($ = 0.36001 in

    7op angle -n(-k (angki #oni#al %engan %iame(er an(ara 3 ( $ingga 60 ( a%ala$

    n

    engt1weddL

    12

    .. =

    -6.0.*o.2.

    P0fDPt1

    =

  • 7/24/2019 basis mol

    104/380

    -%-( a%ala$ s-%-( #one roo (er$a%ap garis $oriTon(al.

    "Browne and $o!ng% Pers'-')% (*++ , )-/

    = %iame(er (angki s(an

    ($ = #one s$ell ($i#knessS i

    0.2230004

    = 12.'' %era/a(

    Men-h*tun- t*n--* hea' (h

    $ = 3.02064 ( 1.1'4'321 m

    MENEN%"AN D#AME%ER 6#6A 6EN>#$#AN DAN 6EN>EL"ARAN

    = I-i% Io ra(e S (3 ,sQ = I-i% %ensi(! S lb,(3

    i = %iame(er op(im-m S in#$

    %iren#anakan ak(- pengisian selama ' /am.

  • 7/24/2019 basis mol

    105/380

    erben(-k ker-#-(

    $erik

    ONVER$#

    1Kg,m3 = 0.06243lbm,(3 3,/am) 1 Kg 2.2046 lb

    1 $ari 24 /am

    1 ( 12 in#$

    0.304'm

    roses pengisian %an pengosongan)

    77:41-43

  • 7/24/2019 basis mol

    106/380

    l = 2940 bbl = 133.' (3

    43.033m3

    e% & E = '

    (eel ?*2'3

    .6 Kg,m3

    62.1'43 lb,(3

    al 34'

    el%e% /oin(

    i + (ebal s$ellSin

    ses.

  • 7/24/2019 basis mol

    107/380

    el%e% /oin(

    i + (ebal s$ellSin

    21,2 21,

    2 ,

    16

  • 7/24/2019 basis mol

    108/380

    arS (

    n

    %(**( , &)./

  • 7/24/2019 basis mol

    109/380

    7ipe (angki silin%er (egak %engan %asar %a(ar %an a(asn!a b

    %asar pemili$an 5m-mn!a %ig-nakan -n(-k li-i% pa%a (ekanan a(mos

    8er$i(-ngan :

    MEN>H#%"N> DEN$#%A$ CAM6"RAN:

    komponen mol kmol,/am massa Kg,/am) Q Kg,m3) ol-me m

    HCl 31 140.''441 136.9'6'1139'1 113 4.30993

    H2O 6 313.'144 64.16'103244 .699'

    109'.6621902 .'333

    ensi(as #amp-ran = 10'0.366 Kg,m3

    69.44163lb,(3

    %iren#anakan pen!impanan -n(-k 9 $ari %engan b-a$ (angki mem-%a$kan pr

    se$ingga ol-me masing*masing:

    pen!impanan = 9 $ari

    /-mla$ (angki = 9 b-a$

    keb-(-$an HCl = 109'.66 Kg,/am selama 1 $ari

    1'12040.91 Kg selama 9 $ari

    3771928 lb

    Bo)ume metano) pa'a tan-k*:

    ol-me (angki = 229.1'3 (3

    ol-me HCl %alam 1 (angkki = '461.02'32'3'2(3

    as-msi ba$an isi '0 ol-me (angki ak(or keamanan)

    se$ingga ol-me (angki = 1013.2334069 (3

    1013.2334069(3

    MENEN%"AN D#MEN$# %AN>#

    rasio H, = 3,'

    = iame(er Brownel,1

    H = 7inggi 7angki

    R = 3.1413

    H = 12.20466 (

    3.91'03m

    = 32.496 (

    .1496m

    HDvo!me ...4

    1 2

    =

  • 7/24/2019 basis mol

    110/380

    %ig-nakan %iame(er 3 ( %an (inggi 16 ( &maka

    MENEN%"AN !"MLAH 6LA%E DAN %E&AL $HELL

    "Browne and $o!ng% pers &'()%(*++ , -./

    ( = (ebal s$ell S in

    8 = (ekanan in(ernal S psi

    % = insi%e %iame(er S in

    C = ak(or korosi S in 1,' in)

    E = ak(or pengelasan& %ig-nakan %o-ble el%

    =s(ress alloable& ba$an kons(r-ksi Lo all

    ra%e B& maka = 1'90 psi

    8 = (ekanan in(ernal S 8si = %ensi(as air pa%a s-$- 30 Cel#i-s =H = (inggi #o-rseS (

    Cou,e 4

    H = 16 (

    (1 = 0.21031 in

    %ipili$ (ebal s$ell s(an%ar = 0.2' in BronellS

    meng$i(-ng pan/ang pla(e%iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al

    /arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (

    L = pan/ang (iap pla(e S (

    % =%iame(er %alam (ang

    n = /-mla$ pla(e

    el% leng($ = n alloable el%e% /oin(

    L1 = 10.'''4 in

    /a%i = pan/ang pla(e = 10.'''3'3'in

    lebar pla(e = ' (

    (ebal pla(e = 0.2'

    Cou,e 2

    H = 16 ( * ' (

    (2 = 0.164'13

    %ipili$ (ebal s$ell s(an%ar = 0.1 in

    %iren#anakan akan mengg-nakan s$ell pla(e %engan 6 in ' () butt-weldes cou

    C0f

    dP

    t += ..2.

    144-1* = HP

    n

    engt1weddL

    12

    .. =

  • 7/24/2019 basis mol

    111/380

    meng$i(-ng pan/ang pla(e

    %iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al

    /arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (

    L = pan/ang (iap pla(e S (

    % =%iame(er %alam (ang

    n = /-mla$ pla(e

    el% leng($ = n alloable el%e% /oin(

    L1 = 10.'92' in

    /a%i = pan/ang pla(e = 10.'929644in

    lebar pla(e = ' (

    (ebal pla(e = 0.1

    MENEN%"AN %O6 AN>LE "N%" CON#CAL ROOF

    bila %ig-nakan 10 pla(e (iap angle& maka pan/ang (iap angle :

    L = 10.093 (

    "MENEN%"AN %E&AL DAN %#N>># HEAD %AN>#

    "Browne and $o!ng% Pers')'(.-% (*++ , ((2/

    (ekanan pen!impanan = 1 a(m = 14.9 psi

    %an %iambil ak(or keamanan 10 maka:

    8 = 16.19 8si #os 30 = 0.'66

    ($ = 0.2461'19 in

    7op angle -n(-k (angki #oni#al %engan %iame(er an(ara 3 ( $ingga 60 ( a%ala$

    n

    engt1weddL

    12

    .. =

    -6.0.*o.2.

    P0fDPt1

    =

  • 7/24/2019 basis mol

    112/380

    -%-( a%ala$ s-%-( #one roo (er$a%ap garis $oriTon(al.

    "Browne and $o!ng% Pers'-')% (*++ , )-/

    = %iame(er (angki s(an

    ($ = #one s$ell ($i#knessS i

    0.3306313

    = 1.26' %era/a(

    Men-h*tun- t*n--* hea' (h

    $ = .9'6049 ( 1.963'91133 m

    MENEN%"AN D#AME%ER 6#6A 6EN>#$#AN DAN 6EN>EL"ARAN

    = I-i% Io ra(e S (3 ,sQ = I-i% %ensi(! S lb,(3

    i = %iame(er op(im-m S in#$

    %iren#anakan ak(- pengisian selama ' /am.

  • 7/24/2019 basis mol

    113/380

    erben(-k ker-#-(

    $erik

    ONVER$#

    1Kg,m3 = 0.06243lbm,(3 3,/am) 1 Kg 2.2046 lb

    1 $ari 24 /am

    1 ( 12 in#$

    0.304'm

    oses pengisian %an pengosongan)

    77:41-43

  • 7/24/2019 basis mol

    114/380

    l = 3'0 bbl = 133.' (3

    43.033m3

    e% & E = '

    ! (eel ?*22

    .6 Kg,m3

    62.1'43 lb,(3

    al 34'

    el%e% /oin(

    i + (ebal s$ellSin

    ses.

  • 7/24/2019 basis mol

    115/380

    el%e% /oin(

    i + (ebal s$ellSin

    21,2 21,

    2 ,

    16

  • 7/24/2019 basis mol

    116/380

    arS (

    n

    %(**( , &)./

  • 7/24/2019 basis mol

    117/380

    pompa 1

    D-ngsi : Mengalirkan me(anol %ari (angki me(anol

    7-/-an 8eran#angan :

    1. Menen(-kan (ipe pompa

    2. menen(-kan %imensi pipa

    a. Meng$i(-ng kapasi(as %ebi() pemompaan

    b. Meng$i(-ng %iame(er op(imal pipa

    #. Menen(-kan pemili$an /enis pipa

    3. Meng$i(-ng ke$ilangan energi akiba( gesekan

    a. Meng$i(-ng ke#epa(an linier I-i%

    b. Meng$i(-ng bilangan e!nol%

    #. meng$i(-ng pan/ang ek-ialen pipa

    %. Meng$i(-ng risi %alam pemipaan

    4. Meng$i(-ng (enaga pompa

    a. Meng$i(-ng pres-re $ea%

    b. Meng$i(-ng po(ensial $ea%

    #. Meng$i(-ng elo#i(! $ea%

    %. Meng$i(-ng poer pompa

    Langka$ 8eran#angan :

    1. Menen(-kan (ipe pompa

    alam peran#angan ini %ipili$ pompa #en(ri-gal %engan per(imbanga

    a. kons(r-ksi se%er$ana

    b. Ke#epa(an p-(aran s(abil

    #. Dl-i%a %ialirkan pa%a (ekanan !ang -niorm

    %. 7i%ak memel-kan areal !ang l-as

    e. Bia!a peraa(ann!a paling m-ra$ %iban%ingkan (ipe pompa lain.

    4 Menentukan kapa*ta pemompaan (6e,an

  • 7/24/2019 basis mol

    118/380

    Komponen Q kg,m3) Q . @ M kg,/am)

    CH3OH 0.43923 9'3. 9'3.4094234 32.409446

    H2O 0.00062499 0.664691 2.201424

    >-mla$ 9'4.01'93'06' 329.61664

    La/- alir ee%

  • 7/24/2019 basis mol

    119/380

    0.0009119lb,(.s

    U #amp = 0.000344 lb,(.s Kern, fg 14, 1965 : 823

    46.434

    (Peters,198,

    5n(-k komersial s(eel :

    46.434

    1.3 in 0.040661' m

    e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#

    e, = 0.0003'

    *"nn'ng *r'ct'on *"ctor (* # + 0.03 ($e"n%o&l's '

    1 Men-h*tun- tena-a pompa

    ")enentu%"n &ressure !e"d

    a(a :

    g = 32.2

    g# = 32.194

    1 a(m 2116.1

    1.1 a(m 2329.91

    211.61

    4.320196322(.lb,lbm

    b) enentu%"n &otens'"l !e"d

    %iren#anakan :

    1 m 3.2' (

    3 m .'4 (

    V = 2 m 6.6 (

    Potens'"l e"d + 6.63012 (.lb,lbm

    c) enentu%"n .eloc't/ !e"d

    ;e

    =

    ;e

    W 2100 berar(i aliran !ang mas-k men-/- (angki pro%-k a%ala$ alira

    ;e

    =

    in =

    5n(-k e, s ;e

    )& maka :

    Kons(an(a ke#epa(an grai(asi (,s2

    Dak(or konersi& lb (,lbs2

    81 =8 #airan %lm (angki

    82= 8 mas-k aporiTer

    V1 =

    V2 =

    vD

    N

    =%&

    cg

    g5eadpotensiaH =

    2

    =

    P

  • 7/24/2019 basis mol

    120/380

    Karena ke#epa(an linear #airan (i(ik 1 %an (i(ik 2 rela(i sama& maka :

    1 = 2

    .eloc't/ e"d + 0 (.lb,lbm

    d) r'ct'on e"d (0#

    5n(-k komersial s(eel :

    &46.4

    1.3 in 0.040661' m

    e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#e, = 0.0003'

    *"nn'ng *r'ct'on *"ctor (* # + 0.03 ($e"n%o&l's '

    Menen(-kan 8an/ang ek-ialen :

    Komponen L, >-mla$ 8an/ang Le)

    8ipa l-r-s 1 12

    3 2 11.26

    a(e ale& -ll! open 13 1 2.021'1

    C$e#k ale& -ll! open 13 1 21.9264$arp e%ge en(ran#e 2' 1 4.06236

    k = 0&

    $arp e%ge ei( k=1&0) ' 1 .334346

    pipa l-r-s er(ikal 1 '.

    7o(al 8an/ang ekialen Le) 1'2.424'4'

    Ke$ilangan energi karena riksi

    ($e"n%o&l's s)2)1-6 &)89#

    14.69369' (.lb,lbm

    e. Menen(-kan 8oer Hea% *A)

    *A) = 2.'2'40'(.lb,lbm

    Kapasi(as

  • 7/24/2019 basis mol

    121/380

    iskosi(as kinema(ik = 9.14E*006 (2,s = 0.662'42

    ari Dig.14*36 pe(ers p.20& -n(-k kapasi(as 24.2 gallon,mn( %iperole$

    20

    B$p = Bro%e orse&ower + 0.61322H8

    ari Yg 14*3' 8e(ers p.21& -n(-k B$p = 1.3 %iperole$

    eZsiensi mo(or = '1

    8oer mo(or = 0.96619

    ipakai poer mo(or = 4

    Reume :

    Ko%e : 8*01

    D-ngsi : Mengalirkan me(anol %ari (angki me(anol

    7ipe : #en(ri-gal

    >-mla$ : 1

    Kapasi(as : 24.243613gallon,meni(

    7enaga 8ompa : 0.61326 H8

    Ba$an Kon(r-ksi : oerc'"l 0teel

    8ipa : 2 in

    O = 2.3' in

    = 1.3 in

    #$ = '0

    X pompa=

    nominal

    =

    motor

    B1pPowermotor

    =

    =550

    -* fQWfB1p

  • 7/24/2019 basis mol

    122/380

    1 kg = 2.2046 lb

    1 gr = 0.001 kg

    3.31469

    0.0000011 /am = 3600 %(k

    1 #-( = 9.4'01 gallon

    Ba$an bak- :

    Me(anol

    Kem-rnian .0

    0.10

    :

    (&eters, &)521#

    *u-a)

    1 m3 = in2

    1 #m3

    = m3

    H2O

  • 7/24/2019 basis mol

    123/380

    100

    #-(,%(k

    gallon,mn(

    0.194

    0.16039 (

    0.0204'4'

    (,%(k

    (2

  • 7/24/2019 basis mol

    124/380

    "l 496#

    )2)1-3 &)88#

    7-rb-len

    (,s2

    lb (,lbs2

    lb,(2

    lb,(2

  • 7/24/2019 basis mol

    125/380

    0.16039 (

    )2)1-3 &)88#

    ()

    gallon,mn(

    f+

  • 7/24/2019 basis mol

    126/380

    Cs

    eisiensi X)

    H8

  • 7/24/2019 basis mol

    127/380

    1 meni( = 60 se#on%

    0.00644

    1 m = 3.2' (

    1 a(m = 2116.11 in = 0.0'3 (

    1 Kg,m.s = 0.6919lb,(.s

    1 in2= (2

    lb,(2

  • 7/24/2019 basis mol

    128/380

  • 7/24/2019 basis mol

    129/380

  • 7/24/2019 basis mol

    130/380

  • 7/24/2019 basis mol

    131/380

  • 7/24/2019 basis mol

    132/380

    pompa 2

    D-ngsi : Mengalirkan HCl %ari (angki HCl

    7-/-an 8eran#angan :

    1. Menen(-kan (ipe pompa

    2. menen(-kan %imensi pipa

    a. Meng$i(-ng kapasi(as %ebi() pemompaan

    b. Meng$i(-ng %iame(er op(imal pipa

    #. Menen(-kan pemili$an /enis pipa

    3. Meng$i(-ng ke$ilangan energi akiba( gesekan

    a. Meng$i(-ng ke#epa(an linier I-i%

    b. Meng$i(-ng bilangan e!nol%

    #. meng$i(-ng pan/ang ek-ialen pipa

    %. Meng$i(-ng risi %alam pemipaan

    4. Meng$i(-ng (enaga pompa

    a. Meng$i(-ng pres-re $ea%

    b. Meng$i(-ng po(ensial $ea%

    #. Meng$i(-ng elo#i(! $ea%

    %. Meng$i(-ng poer pompa

    Langka$ 8eran#angan :

    1. Menen(-kan (ipe pompa

    alam peran#angan ini %ipili$ pompa #en(ri-gal %engan per(imbanga

    a. kons(r-ksi se%er$ana

    b. Ke#epa(an p-(aran s(abil

    #. Dl-i%a %ialirkan pa%a (ekanan !ang -niorm

    %. 7i%ak memel-kan areal !ang l-as

    e. Bia!a peraa(ann!a paling m-ra$ %iban%ingkan (ipe pompa lain.

    4 Menentukan kapa*ta pemompaan (6e,an

  • 7/24/2019 basis mol

    133/380

    Komponen Q Q . @ M kg,/am)

    HCl 0.49624969 113 6'.1634'144 136.9'6'11

    H2O 0.2392321 21.133''01 64.16'1

    >-mla$ 10'.29040246 109'.662

    La/- alir ee%

  • 7/24/2019 basis mol

    134/380

  • 7/24/2019 basis mol

    135/380

    Karena ke#epa(an linear #airan (i(ik 1 %an (i(ik 2 rela(i sama& maka :

    1 = 2

    .eloc't/ e"d + 0 (.lb,lbm

    d) r'ct'on e"d (0#

    5n(-k komersial s(eel :

    6120'.321

    2.323 in 0.0'9'32319 m

    e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#e, = 0.0009'3

    *"nn'ng *r'ct'on *"ctor (* # + 0.04 ($e"n%o&l's '

    Menen(-kan 8an/ang ek-ialen :

    Komponen L, >-mla$ 8an/ang Le)

    8ipa l-r-s 1 12

    3 2 13.4663

    a(e ale& -ll! open 13 1 2.0619

    C$e#k ale& -ll! open 13 1 26.0221$arp e%ge en(ran#e 2' 1 .3'62

    k = 0&

    $arp e%ge ei( k=1&0) ' 1 11.1'222

    pipa l-r-s er(ikal 1 '.

    7o(al 8an/ang ekialen Le) 12.11336

    Ke$ilangan energi karena riksi

    ($e"n%o&l's s)2)1-6 &)89#

    32.93130'9 (.lb,lbm

    e. Menen(-kan 8oer Hea% *A)

    *A) = 42.406129'3(.lb,lbm

    Kapasi(as

  • 7/24/2019 basis mol

    136/380

    iskosi(as kinema(ik = 1.14E*00 (2,s = 1.0636149

    ari Dig.14*36 pe(ers p.20& -n(-k kapasi(as 4.4 gallon,mn( %iperole$

    39

    B$p = Bro%e orse&ower + 1.140219H8

    ari Yg 14*3' 8e(ers p.21& -n(-k B$p = 1. %iperole$

    eZsiensi mo(or = '3

    8oer mo(or = 1.'241699

    ipakai poer mo(or = 4

    Reume :

    Ko%e : 8*02

    D-ngsi : Mengalirkan HCl %ari (angki HCl

    7ipe : #en(ri-gal

    >-mla$ : 1

    Kapasi(as : 49.1'22gallon,meni(

    7enaga 8ompa : 1.1402 H8

    Ba$an Kon(r-ksi : oerc'"l 0teel

    8ipa : 2 1,2 in

    O = 2.'' in

    = 2.323 in

    #$ = '0

    X pompa=

    nominal

    =

    motor

    B1pPowermotor

    =

    =550

    -* fQWfB1p

  • 7/24/2019 basis mol

    137/380

    1 kg = 2.2046 lb

    1 gr = 0.001 kg

    3.31469

    0.0000011 /am = 3600 %(k

    1 #-( = 9.4'01 gallon

    Ba$an bak- :

    HCl

    Kem-rnian 31.00

    6.00

    :

    (&eters, &)521#

    *u-a)

    1 m3 = in2

    1 #m3

    = m3

    H2O

  • 7/24/2019 basis mol

    138/380

    100

    #-(,%(k

    gallon,mn(

    0.2304 (

    0.12'0 (

    0.023931

    (,%(k

    (2

  • 7/24/2019 basis mol

    139/380

    "l 496#

    )2)1-3 &)88#

    7-rb-len

    (,s2

    lb (,lbs2

    lb,(2

    lb,(2

  • 7/24/2019 basis mol

    140/380

    0.12'0 (

    )2)1-3 &)88#

    ()

    gallon,mn(

    f+

  • 7/24/2019 basis mol

    141/380

    Cs

    isiensi X)

    H8

  • 7/24/2019 basis mol

    142/380

    1 meni( = 60 se#on%

    0.00644

    1 m = 3.2' (

    1 a(m = 2116.11 in = 0.0'3 (

    1 Kg,m.s = 0.6919lb,(.s

    1 in2= (2

    lb,(2

  • 7/24/2019 basis mol

    143/380

  • 7/24/2019 basis mol

    144/380

  • 7/24/2019 basis mol

    145/380

  • 7/24/2019 basis mol

    146/380

  • 7/24/2019 basis mol

    147/380

    'o!&! *01-

    #)g M&)g#'k') m&(')ol "'! '! m&)'" #'

    :& Do!be pipe 0xc1anger:##')

    *;-

    Ko)" O&!' l#"' P')' : *oC- : *K- : *o-:'o!&! ?! 1667626.386 K/'m

    1580604.805 B(#/'m;m') m'#k 'o!&! 3927.62 kg/'m

    8658.823644 lb/'mK&b#(#

  • 7/24/2019 basis mol

    148/380

    :enent!;an Temprat!r ;aori;

    572 "pers' .'

  • 7/24/2019 basis mol

    149/380

    N( 688= D

  • 7/24/2019 basis mol

    150/380

    %& 46.15014496H 16 -Fig&'" ern! hal "#$.

    0.105

    d. Menghitung ho

  • 7/24/2019 basis mol

    151/380

  • 7/24/2019 basis mol

    152/380

  • 7/24/2019 basis mol

    153/380

    0.006809379

    774.7118273

    k. Menentukan Pressure Drop ditube

    "'! Ag.29

  • 7/24/2019 basis mol

    154/380

    2.94825E005 P

    9APORI:ING

    Bl')g') !&)ol" *%&- 1847.980136"'! Ag 29 k&!) ""''(A 0.0016 A(2/)2D 0.79 3ern% tabe ) 1a 2

    =umlah 8rosses dan ba!!le

    L> 9.523714233 A(

    #ml'< !o&N , 1 N + L>/B 3.847965347

    #ml'< b'AAl&

    N 2.847965347= 0.00498 A(

    2.41633E007 P

    2.97241E005 P

    menentukan ?Ps

    PP

    menentukan P dishell (Ps)

    menentukan ?Ps

    PP

    Menentukan ?Ps total

    PP (o('l

    3

    10

    2

    -=&.3.*522.10

    1-.=3.*NA.G3OP3

    +=

    3

    10

    2

    -=&.3.*522.10

    1-.=3.*NA.G3OP3

    +=

  • 7/24/2019 basis mol

    155/380

    1 kg

    1 g!

    1 'm 1 #A(

    a'2*/

    1 m

    3

    ficient 1 m3

  • 7/24/2019 basis mol

    156/380

    a' *.4*)/

    A(A(

    28.2690092 )2

    m'll 100

  • 7/24/2019 basis mol

    157/380

    2*

    21.2031188

    ! %ig&'"

    5 K&!)

    lb*n+&%+'

  • 7/24/2019 basis mol

    158/380

    3ern%fig () 1a 2

  • 7/24/2019 basis mol

    159/380

    ern.

    ! %ig&'"

    5 K&!)

  • 7/24/2019 basis mol

    160/380

    3ern%fig () 1a 2

  • 7/24/2019 basis mol

    161/380

  • 7/24/2019 basis mol

    162/380

    =2

  • 7/24/2019 basis mol

    163/380

    2.2046 lb 1 m&)( 60 &o)" 1

    0.001 kg 0.006944

    35.31467 1 m 3.28 A(0.000001 1 '(m 2116.1

    3600 "(k 1 ) 0.083 A(7.480519 g'llo) 1 kk'l 3.968321 B(#

    1 KF 0.9478171 B(#

    1 )2 A(2

    )

    2

    m3 lbA/A(2

  • 7/24/2019 basis mol

    164/380

    k&!) .103

    (o 200 A(2 o! l&.

  • 7/24/2019 basis mol

    165/380

  • 7/24/2019 basis mol

    166/380

  • 7/24/2019 basis mol

    167/380

  • 7/24/2019 basis mol

    168/380

  • 7/24/2019 basis mol

    169/380

  • 7/24/2019 basis mol

    170/380

  • 7/24/2019 basis mol

    171/380

    2.42 lb/A(.'m

  • 7/24/2019 basis mol

    172/380

  • 7/24/2019 basis mol

    173/380

  • 7/24/2019 basis mol

    174/380

  • 7/24/2019 basis mol

    175/380

  • 7/24/2019 basis mol

    176/380

  • 7/24/2019 basis mol

    177/380

  • 7/24/2019 basis mol

    178/380

  • 7/24/2019 basis mol

    179/380

    'o!&! *02-

    #)g M&)g#'k') HCl "'! '! m&)'" #'

    :& Do!be pipe 0xc1anger:##')

    *;-

    Ko)" O&!' l#"' P')' : *oC- : *K- : *o-:'o!&! ?! 6468516.383 K/'m

    6130970.44 B(#/'m;m') m'#k 'o!&! 10785.96 kg/'m

    23778.71997 lb/'mK&b#(#

  • 7/24/2019 basis mol

    180/380

    :enent!;an Temprat!r ;aori;

    572 "pers' .'

  • 7/24/2019 basis mol

    181/380

    N( 1024= D

  • 7/24/2019 basis mol

    182/380

    %& 31.45671719H 11 -Fig&'" ern! hal "#$.

    0.16 3ern%fig () 1a 2& >ol'(l(' (' komo)&)

    ')' #)(#k &)g#') 1 mol #m') H> HH> H

    L

    +=

    1mx

    i

    iDi

    =

    i

    i9ixq1

    ( )( )

    ( )( )

    +

    +

    =+

    5.0

    m) 1

    U117.211

    4.541

    11

    0XPN

    NN

  • 7/24/2019 basis mol

    293/380

    Komo)&) A *kmol/'m- + PCH3OH 0.245 0.0017 9.5469HCl 0.049 0.0003 12301.0388CH3Cl 105.035 0.7292 1036.0150H2O 38.708 0.2687 1.1609:o('l 144.037 1.000

    Komo)&) k kU+ 'lA'CH3OH 0.0126 0.000021 8.2234365137HCl 16.1856 0.005507 10595.7797387032CH3Cl 1.3632 0.994062 892.3950727796H2O 0.0015 0.000411 1

    :o('l 1.000

    Penen+uan Te*pera+ur de6+ila+

    :&m&!'(#! "&(l'( "'! "&)g') (!'l "& o)( (&m&!'(#!. :&k')') o&!'"')gg' ko)(') '"' ko)" 1 '(m:&k')') 1 '(m 101.325:&m&!'(#! :!'l 30.1635975201 C 303.3136Komo)&) Akmol/'m PCH3OH 0.2449918797 0.0022 165.1879

    HCl 0.0490032763 0.0004 38930.6785CH3Cl 105.035459983 0.9619 4988.1414H2O 3.870781752 0.0354 31.9521:o('l 109.200 1.000

    Komo)&) k +/k 'lA'CH3OH 0.2174 0.0103 5.16985HCl 51.2246 0.0000 1218.40596CH3Cl 6.5633 0.1466 156.11290H2O 0.0420 0.8431 1.00000

    :o('l 1.000

    Penen+uan Te*pera+ur 4o++o* De6+ila6i

    :&m&!'(#! bo((om "&(l' m&!#'k') (&m&!'(#! b#bbl& o)( "'! #)(#km&)&)(#k') (&m&!'(#! o&!' !&bol&! *!&bol&! '!'l-:&k')') 1 '(m 101.325:&m&!'(#! :!'l 100.0020555086 C 373.1520555086Komo)&) Akmol/'m + PCH3OH 2.450163813569E005 7.03321059416E007 2658.0751643188

    HCl 5.902890849928E022 0 123619.564695223CH3Cl 2.964984906363E012 0 23332.2912520951H2O 34 8370357679 0 9999992967 759 9987597097

  • 7/24/2019 basis mol

    294/380

    :o('l 34.8371 1.000

    Komo)&) k kU+ 'lA'CH3OH 3.4974673215 2.45984242181E006 3.4974730292HCl 162.6573219674 0 162.6575874182CH3Cl 30.7003832264 0 30.7004333283H2O 0.999998368 0.9999976647 1:o('l 1.000

    Menghi+ung Bu*lah Pla+e Mini*u* Pada To+al Re%lu

    ;)(#k m&)g!

    L=

    Log

    WLog

    = LB

    HB

    HD X

    X

    X

    Nm

    WLDLAverageL x ... =

  • 7/24/2019 basis mol

    295/380

    %m) , 1 0.9043%m) 0.0957

    Menen+uan Bu*lah Pla+e Teori+i6 (N +eori+i6)

    Nm) 8% m) 0.0957

    =&)g') &!'m'')

    % T + %m)Y *% %m)-/*%,1-W *N Nm)-/*N,1-

    N *Nm) , W-/ *1 W-

    T % Y W1.05 0.1005131758 0.00434919 0.80250765661.1 0.1052995175 0.00866071 0.7286357419

    1.15 0.1100858592 0.01293506 0.6931379242

    1.2 0.1148722009 0.01717270 0.67201555791.25 0.1196585426 0.02137411 0.65766706741.3 0.1244448843 0.02553976 0.6469563344

    1.35 0.129231226 0.02967009 0.63837652911.4 0.1340175677 0.03376556 0.6311273522

    1.45 0.1388039094 0.03782660 0.6247522951.5 0.1435902511 0.04185364 0.618976578

    ='mbl T 1.25%&Al#k 0.1244448843

    F#ml'< Pl'(& :&o!( 24.94 25

    Menen+uan Bu*lah Pla+e a+ual

    M&)gg#)'k') OJCo))&llJ o!!&l'(o) Eo 51325 log *'.Z'- *o#lo) >ol.6g '"' #

  • 7/24/2019 basis mol

    296/380

    CH3OH 2.2'' 2.6E*01 .13E+02

    HCl 3.342 0.292 324.6CH3Cl 1.'19 2.E*01 416.2

    Aa(er 5.459 3.05@01 647.13

    : (o 303.3136 K komo)&) (o kmol/'m +" CH3OH 0.245 0.002 3.95E,00HCl 0.049 0.000 7.6784121084CH3Cl 105.035 0.962 3.3605984571H2O 3.871 0.035 9.9792504193

    #ml'< 109.200 1.000

    : bo((om 373.1520555086 K komo)&) bo((om kmol/'m +b CH3OH 2.450163813569E005 7.03321059416E007 0.03HCl 5.902890849928E022 0 0.75CH3Cl 2.964984906363E012 0 0.1H2O 34.8370357679 0.9999992967 0.2838

    #ml'< 34.8370602695 1

    Bu*lah Pla+e a+ual

    '>g 1.0105648667 1.0105648667

    Eo 50.8517 [

    N '(#'l N (&o!( 1 !&bol&! EAA

    47.0781057744 ('g& \ 47

    Menen+uan Loa6i ;*pan Ma6u

    P&!

  • 7/24/2019 basis mol

    297/380

    Log N!/N 3.112010322N!/N 22.4661632551N'( 1 N! , NN 2.0062123178

    F'" #m') m'#k '"' l'(& "'! 12 "''! m&)'!'.

    -M2T2: M2D:

    1. iame(er 8-n#ak Menara

    = eI-k a(io

    , = ? 1.6'00'433 kmol,/am

    = Lo + 122.9'6 kmol,/am

    B&!'( mol&k#l ;' =&(l'(

    Komo)&) X Bm X. BmCH3OH 0.0022 32.0420 0.0718865639

    HCl 0.0004 36.4610 0.0163617636CH3Cl 0.9619 50.4880 48.5624432199H2O 0.0354 18.0150 0.6385712636

    :o('l 1.0000 4.2'262'111

    49.2892628111 kg/kmolP 1.2 '(m 121.59 k': 294.000000 K M'k' "&)(' #' "&(l'(

    2.0432411242

    Menen+uan Den6i+a6

  • 7/24/2019 basis mol

    298/380

    ;)(#k m&)g

  • 7/24/2019 basis mol

    299/380

    #m :!' ')g ')g "g#)'k') 18='! g. 16.6 P&(&! ] :mm&!ol#m& '!')

    0.0106884

    '& Dia*e+er olo* 4a@ah

    M&)&)(#k') =&)(' ;' C'm#!') Bo((om=&)(' #' 'm#!') "

  • 7/24/2019 basis mol

    300/380

    B&!'( mol&k#l ;' bo((om

    Komo)&) X Bm X. BmCH3OH 0.0000025 32.0420 7.881827088E005HCl 0.0000000 36.4610 0CH3Cl 0.0000000 50.4880 0H2O 1.0000 18.0150 18.0149579299:o('l 1.0000 137.0060 18.0150367482

    18.0150367482 kg/kmolP 1 '(m 101.325 k'

    : 100.00 373.15

    M'k' "&)(' #' bo((om

    0.5883881842

    Menen+uan Den6i+a6

  • 7/24/2019 basis mol

    301/380

    ="''( "&)(' lI#" 'm#!') 99.49999

    =&)(' lI#" bo((om

    1792.4932141449

    #m :!' ')g ')g "g#)'k') 18='! g. 16.6 P&(&! ] :mm&!ol#m& #' m'km#m

    #m 418.083 kmol/'m + 31.131 kg/kmol 1.3774690356

    L'# l! >ol#m& '!') 305.091 kmol/'m + 28.8696kg/kmol 0.0000500

    ='! &!

    #'Bm+)+4

    "='m&(&!

    =

    =

    v

    vL3v6m

    -* =

  • 7/24/2019 basis mol

    302/380

    :o 2.3555085796

    Bo((om 0.1485754537

    F'" )&( '!&' ')g "&!ol&< &k('! 1.2520420166

    ;)(#k "'&!'< "o)om&! "'mbl 20[ l#' k&&l#!#

  • 7/24/2019 basis mol

    303/380

    2.1146373 m

    Menghi+ung Pre66uree Drop

    Dr7 Pate Pres!re Drop 13.24453574830.76790482497.0062202866m/

    2

    K.H "'! Ag 16.12 P&(&! ]

  • 7/24/2019 basis mol

    304/380

    1.2 + 14.7 17.64

    15.644264998 0.002760 P'

    P P" , P< 17.64 , 0.0026 17.642760 P='m&(&! kolom 1.0836 m 41.633 )llo'bl& (!& D 13750 PFo)( &AA&) E 0.8Co!oo) A'(o! C 0.125 )/10 ('

  • 7/24/2019 basis mol

    305/380

    21.5190257663)2 2

    18.2690257663

    BC ! ! 603.625 50.75

    47.3477053039)

    =&

  • 7/24/2019 basis mol

    306/380

  • 7/24/2019 basis mol

    307/380

  • 7/24/2019 basis mol

    308/380

    P'K

    P'K

  • 7/24/2019 basis mol

    309/380

    OC

  • 7/24/2019 basis mol

    310/380

    N43.969430260231.7276636413

    27.941726144

    26.077864133624.94292665424.155863220123.559020295823.076380333322.667348376122.3085885292

    l'(&

  • 7/24/2019 basis mol

    311/380

    2.4E*01

    3.22E*01

    '.10E*02

    8.10@02

    .+"8.85E033.45E033.23E,003.54E013.60E,00

    .+b2.11E08 g&') kol Ag .34 .3

    0.00E,00 g&') kol Ag .34 .40.00E,00 g&') kol Ag .34 .52.84E01 g&') kol ('bl& .24 .22.84E01

    mN/mR2

    ('g&

    =3''.

  • 7/24/2019 basis mol

    312/380

  • 7/24/2019 basis mol

    313/380

    K

    mmHg

    ol

  • 7/24/2019 basis mol

    314/380

    )A(.

  • 7/24/2019 basis mol

    315/380

    K

    Q. @i

    .133339'E*00

    0

    0.430016

    4'12

  • 7/24/2019 basis mol

    316/380

    )

    m/

    mol

    m3/

    m3/

  • 7/24/2019 basis mol

    317/380

    m2m2

    mm

    mm

    kg/

    m2

    m2

    m2

    m2

    m2

    m2

    m2

  • 7/24/2019 basis mol

    318/380

    m

    mm

    L#b')g

  • 7/24/2019 basis mol

    319/380

    42.6630515327)

    Xo#)g

    42.6630515327)

    ] Xo#)g-

    Xo#)g

  • 7/24/2019 basis mol

    320/380

    )

    )

    ))

  • 7/24/2019 basis mol

    321/380

    7# = 30 C

    7i= 32. 7o=30 C

    CA

    7#o = 4 C

    %ari nera#a massa %an nera#a panas %iperole$ :

    ba$an = 3'2.31914'6

    panas !g %ib-(-$kan&

  • 7/24/2019 basis mol

    322/380

    Menghitung density campuran

    Fluida panas

    Komponen BM Massa Massa

    (kmol) (kg)

    CH3OH 32.042 0.24 9.

    HCl 36.461 0.04 1.'CH3Cl 50.488 10.03 &303.0

    18.015 3.'91 6.9

    Total !09." 53#".$

    P! P/PJ 0.0022152319:! :/:J 0.1601936129T 1

    D&

  • 7/24/2019 basis mol

    323/380

    Total

    Mengitung konduktiitas te+mal *ampu+an

    7?BLE 2*31 7$ermal Con%-#(ii(! o norgani# an% Organi# Li-i%s A,mK)_

    Fluida /anas

    Komponen k i i.k

    1(m.K) 1(m.K)

    CH3OH !.09203 0.00!5 !.59206

    HCl ".9$20$ 0.0003 9.%520#

    CH3Cl $.5"20$ 0.9#53 $.$520$

    3.9#20$ 0.0!30 5.!5206

    Total !.00000 $.5020$

    Fluida -ingin

    Komponen k k i

    1(m.K) 1(m.K)

    2E+02 1.0E+02 1

    Total !

    Menentukan 4-

    Dari Tabel 8 Kern, Ud 50-125

    Ud = !"5

    Menghitung Luas Permukaan

    2++E50"

    Menentukan spesifikasi dan layout tube

    -s-nan Triangular

    8ass $ell 1

    8ass 7-be 2

    O-(si%e iame(er = 3/4 in#$ = 0.062

    8i(#$ 0.9375 in#$ = 0.09'12BA ;o. 16

    nsi%e iame(er = 0.62 in#$ = 0.016666669

    Dlo area per (-be = 0.302 0.002092222

    Outside sura!e / lin t = 0.163 2'.2692

    "nside sura!e / lin t = 0.1623 23.3912

    8an/ang = "5 (

    H"O

    H"O (B)

    #tu/ja$.t2.`%

    & = '/(Ud)PT* t2

    in2 =

    (2=

    (2=

  • 7/24/2019 basis mol

    324/380

    Menentukan jumlah tube

    +t = &/(,.a-* @rr>502

    ari (abel Kern& maka /-mla$ (-be %ib-la(kan men/a%i

    ;( = #"" (-be

    Menentukan diameter shell

    ari (abel Kern& /-mla$ (-be %ia(as& %i%apa(kan %iame(er s$ell

    s = 3! in#$ ".5#33333333

    Koreksi luas permukaan dan Ud

    ? = ;(.L.a = $033.965

    5% =

  • 7/24/2019 basis mol

    325/380

  • 7/24/2019 basis mol

    326/380

    at = +t ? at / n = 0.#6"0

    Mengitung ke*epatan massa (8a)

    !3%66.369#6!!! l/r.t2

    et = .t/ = "6%0.!!353%960#

    Mengitung koeisien pe+pindaan panas

    H 92 -Fig&'" ern! hal "#$.

    0.07 3ern%fig () 1a 2

  • 7/24/2019 basis mol

    327/380

    N'm' l'( CON=ENDO%Ko"& l'( C01F#ml'< 1 B#'am.(2.0D

    B(-,>am.(2.

    DDlo area :

    aT (2

    DMass elo#i(! :

    T Kg,/am (2

    lb,/am (2

    De!nol% ;-mber :

    aoLNA t UU=

    TmA

    Q>D

    =U

    n

    taNa TT

    U144

    JU=

    ta

    WT

    J=

    T

    t

    DU%& =

  • 7/24/2019 basis mol

    352/380

    /e+itungan sell side E

    ell side Cold luid (Cai+an medium o+ganik)

    ?s-msi $o = 300

    Kern& ')

    7 = 2'.6666669

    P7 =

    ari Yg 1&11 kern& maka %ig-nakan $o = 129

    D Fengitung lean O;erall ei!ient

    Kern&106)

    5# = 119.0'66626

    d = 0.0117

    d $ini$u$ = 0.001

    /+essu+e -+op tue

    Kern&14')

    ari Yg 2& kern %i%apa( :

    Dak(or rik = 0.001'

    Bt = 3.2615252895 sia

    B(-,>am.(2.0D

    D7empera(-r %in%ing (-be

    0D

    0D

    B(-,>am.(2.0D

    B(-,/am (20D

    Dir( Da#(or

    Aa$ t20%/#tu

    Aa$ t20%/#tu

    (2,in2

    ( )cccW tT1o1io

    1otT

    ++=

    -*

    -.*

    1o1io

    1o1io>c

    +

    =

    DC

    DCD>>>>B

    U=

    s

    t

    De

    LnfPt

    10

    2

    10U22.5=

  • 7/24/2019 basis mol

    353/380

    pesiYk ol-me s(ea = 0.64

    g s(eam = 0.024446142

    Kern&14')

    P8r = 1.49262 8sia

    Kern&14')

    BT = 4.7341502895 sia

    8ress-re rop s(an%a = 10 8sia

    (3,lb

    gs

    n6

    2

    4P!

    2

    =

    rT PPPT +=

  • 7/24/2019 basis mol

    354/380

    = 302

    = 302

    = 20

    = 20

    0D0D0D0D

  • 7/24/2019 basis mol

    355/380

  • 7/24/2019 basis mol

    356/380

    kern& 91).0D

  • 7/24/2019 basis mol

    357/380

  • 7/24/2019 basis mol

    358/380

  • 7/24/2019 basis mol

    359/380

    pompa 4

    D-ngsi : Mengalirkan me(il klori%a ke (angki pro%-k

    7-/-an 8eran#angan :

    1. Menen(-kan (ipe pompa

    2. menen(-kan %imensi pipa

    a. Meng$i(-ng kapasi(as %ebi() pemompaan

    b. Meng$i(-ng %iame(er op(imal pipa

    #. Menen(-kan pemili$an /enis pipa

    3. Meng$i(-ng ke$ilangan energi akiba( gesekan

    a. Meng$i(-ng ke#epa(an linier I-i%

    b. Meng$i(-ng bilangan e!nol%

    #. meng$i(-ng pan/ang ek-ialen pipa

    %. Meng$i(-ng risi %alam pemipaan

    4. Meng$i(-ng (enaga pompa

    a. Meng$i(-ng pres-re $ea%

    b. Meng$i(-ng po(ensial $ea%

    #. Meng$i(-ng elo#i(! $ea%

    %. Meng$i(-ng poer pompa

    Langka$ 8eran#angan :

    1. Menen(-kan (ipe pompa

    alam peran#angan ini %ipili$ pompa #en(ri-gal %engan per(imbanga

    a. kons(r-ksi se%er$ana

    b. Ke#epa(an p-(aran s(abil

    #. Dl-i%a %ialirkan pa%a (ekanan !ang -niorm

    %. 7i%ak memel-kan areal !ang l-as

    e. Bia!a peraa(ann!a paling m-ra$ %iban%ingkan (ipe pompa lain.

    4 Menentukan kapa*ta pemompaan (6e,an

  • 7/24/2019 basis mol

    360/380

    Komponen Q Q . M kg,/am)

    CH3OH 0.0014'463 9'3. 1.1432'111 9.'002'1

    HCl 0.0003314 113 0.36021019 1.9'690'46

    CH3Cl 0.'23' 1 01.09409940 303.030304

    H2O 0.012'6 12.'0'09694' 6.93213326

    >-mla$ 1.39242 3'2.319

    La/- alir ee%

  • 7/24/2019 basis mol

    361/380

    0.0003 lb,(.s 0.001009

    U air = 0.' Kg,m.s U me(il klori%= 0.1'

    0.0009119 lb,(.s 0.000120

    U #amp = 0.00012941 lb,(.s Kern, fg 14, 1965 : 823

    22362.909

    (Peters,198,

    5n(-k komersial s(eel :

    22362.909

    1.3 in 0.040661' m

    e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#

    e, = 0.0003'

    *"nn'ng *r'ct'on *"ctor (* # + 0.01 ($e"n%o&l's '

    1 Men-h*tun- tena-a pompa

    ")enentu%"n &ressure !e"d

    a(a :

    g = 32.2

    g# = 32.194

    1 a(m 2116.1

    1 a(m 2116.1

    0 (.lb,lbm

    b) enentu%"n &otens'"l !e"d

    %iren#anakan :

    1 m 3.2' (

    2 m 6.6 (

    V = 1 m 3.2' (

    Potens'"l e"d + 3.2'2606 (.lb,lbm

    ;e

    =

    ;e

    W 2100 berar(i aliran !ang mas-k men-/- (angki pro%-k a%ala$ alira

    ;e

    =

    in =

    5n(-k e, s ;e

    )& maka :

    Kons(an(a ke#epa(an grai(asi (,s2

    Dak(or konersi& lb (,lbs2

    81=8 #airan %lm (angki

    82= 8 mas-k (angki

    V1 =

    V2 =

    vDN

    =%&

    cg

    g5eadpotensiaH =

    =

    P

  • 7/24/2019 basis mol

    362/380

    c) enentu%"n .eloc't/ !e"d

    Karena ke#epa(an linear #airan (i(ik 1 %an (i(ik 2 rela(i sama& maka :

    1 = 2

    .eloc't/ e"d + 0 (.lb,lbm

    d) r'ct'on e"d (0#

    5n(-k komersial s(eel :

    223&62.9

    1.3 in 0.040661' m

    e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#

    e, = 0.0003'

    *"nn'ng *r'ct'on *"ctor (* # + 0.01 ($e"n%o&l's '

    Menen(-kan 8an/ang ek-ialen :

    Komponen L, >-mla$ 8an/ang Le)

    8ipa l-r-s 1 12

    3 1 .6329a(e ale& -ll! open 13 1 2.021'1

    C$e#k ale& -ll! open 13 1 21.9264

    $arp e%ge en(ran#e 2' 1 4.06236

    k = 0&

    $arp e%ge ei( k=1&0) ' 1 .334346

    pipa l-r-s er(ikal 1 '.

    7o(al 8an/ang ekialen Le) 196.9203

    Ke$ilangan energi karena riksi

    ($e"n%o&l's s)2)1-6 &)89#

    6.32'9''1 (.lb,lbm

    e. Menen(-kan 8oer Hea% *A)

    ;e

    =

    in =

    Elbo 0o

    * =

    =cg

    6ad6eocit7He

    2

    2

    cg

    v

    D

    Lff

    24

    2

    =

    adveocit71eeadpotensia1adpress!re1eWf ++=

  • 7/24/2019 basis mol

    363/380

    *A) = .'163'46(.lb,lbm

    Kapasi(as -mla$ : 1

    Kapasi(as : 2'.43'393gallon,meni(

    7enaga 8ompa : 0.2'1331 H8

    Ba$an Kon(r-ksi : oerc'"l 0teel

    8ipa : 2 in

    O = 2.3' in

    = 1.3 in

    #$ = '0

    X pompa=

    nominal

    =

    motor

    B1pPowermotor

    =

    =550

    -* fQWfB1p

  • 7/24/2019 basis mol

    364/380

    1 kg = 2.2046 lb

    1 gr = 0.001 kg

    3.31469

    0.0000011 /am = 3600 %(k

    1 #-( = 9.4'01 gallon

    Ba$an bak- :

    Me(anol

    Kem-rnian .0

    0.10

    :

    (&eters, &)521#

    *u-a)

    1 m3 = in2

    1 #m3

    = m3

    H2O

  • 7/24/2019 basis mol

    365/380

    100

    #-(,%(k

    gallon,mn(

    0.194 (

    0.16039 (

    0.0204'4'

    (,%(k

    Kg,m.s

    (2

  • 7/24/2019 basis mol

    366/380

    lb,(.s

    Kg,m.s

    lb,(.s

    "l 496#

    )2)1-3 &)94#

    7-rb-len

    (,s2

    lb (,lbs2

    lb,(2

    lb,(2

  • 7/24/2019 basis mol

    367/380

    0.16039 (

    )2)1-3 &)94#

    ()

    f+

  • 7/24/2019 basis mol

    368/380

    gallon,mn(

    Cs

    isiensi X)

    H8

  • 7/24/2019 basis mol

    369/380

    1 meni( = 60 se#on%

    0.00644

    1 m = 3.2' (

    1 a(m = 2116.11 in = 0.0'3 (

    1 Kg,m.s = 0.6919lb,(.s

    1 in2= (2

    lb,(2

  • 7/24/2019 basis mol

    370/380

  • 7/24/2019 basis mol

    371/380

  • 7/24/2019 basis mol

    372/380

  • 7/24/2019 basis mol

    373/380

  • 7/24/2019 basis mol

    374/380

    7ipe (angki silin%er (egak %engan %asar %a(ar %an a(asn!a berbe

    %asar pemili$an 5m-mn!a %ig-nakan -n(-k li-i% pa%a (ekanan a(mosp$eri

    8er$i(-ngan :

    MEN>H#%"N> DEN$#%A$ CAM6"RAN:

    komponen kmol,/am massa Kg,/am) Q Kg,m3) ol-me m3,/am)

    CH3OH 0.2441 9.'002'1 9'3. 0.010014

    HCl 0.040033 1.9'690'461 113 0.0014'

    CH3Cl 10.0346 303.03030362 1 .9662

    H2O 3.'909'1' 6.932133262 0.0900'3

    10.20024 3'2.31914 .'9926

    ensi(as #amp-ran = 1.'01412''6 Kg,m3

    9.1934'2206lb,(3

    %iren#anakan pen!impanan -n(-k 9 $ari %engan b-a$ (angki mem-%a$kan proses p

    se$ingga ol-me masing*masing:

    pen!impanan = 9 $ari

    /-mla$ (angki = b-a$

    keb-(-$an HCl = 3'2.31914 Kg,/am selama 1 $ari

    04243.06142 Kg selama 9 $ari

    477317128322 lb

    Bo)ume metano) pa'a tan-k*:

    ol-me (angki = 34'69.46261193 (3

    as-msi ba$an isi '0 ol-me (angki ak(or keamanan)

    se$ingga ol-me (angki = 41'40.134091' (3

    '36'.11026'144(3

    MENEN%"AN D#MEN$# %AN>#

    rasio H, = 3,'

    = iame(er Brownel,1

    H = 7inggi 7angki

    R = 3.1413

    H = 11.442'64 (

    3.4'99'm

    HDvo!me ...4

    1 2=

  • 7/24/2019 basis mol

    375/380

    = 30.1430 (

    .3009601m

    %ig-nakan %iame(er 3 ( %an (inggi 16 ( &maka

    MENEN%"AN !"MLAH 6LA%E DAN %E&AL $HELL

    "Browne and $o!ng% pers &'()%(*++ , -./

    ( = (ebal s$ell S in

    8 = (ekanan in(ernal S psi

    % = insi%e %iame(er S in

    C = ak(or korosi S in 1,' in)

    E = ak(or pengelasan& %ig-nakan %o-ble el%

    = s(ress alloable& ba$an kons(r-ksi Carbon

    ra%e C& maka = 1260 psi

    8 = (ekanan in(ernal S 8si

    = %ensi(as air pa%a s-$- 30 Cel#i-s =H =(inggi #o-rseS (

    Cou,e 4

    H = 16 (

    (1 = 0.214' in

    %ipili$ (ebal s$ell s(an%ar = 0.2' in BronellS

    meng$i(-ng pan/ang pla(e

    %iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al el%e

    /arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (

    L = pan/ang (iap pla(e S (

    % =%iame(er %alam (ang

    n = /-mla$ pla(e

    el% leng($ = n alloable el%e% /oin(

    L1 = 10.'''4 in

    /a%i = pan/ang pla(e = 10.'''3'3' in

    lebar pla(e = ' (

    (ebal pla(e = 0.2'

    Cou,e 2

    H = 24 ( * ' (

    (2 = 0.1'40129

    %iren#anakan akan mengg-nakan s$ell pla(e %engan 6 in ' () butt-weldes courses.

    C0f

    dPt +=

    ..2

    .

    144

    -1* =

    HP

    n

    engt1weddL

    12

    .. =

  • 7/24/2019 basis mol

    376/380

    %ipili$ (ebal s$ell s(an%ar = 0.1 in

    meng$i(-ng pan/ang pla(e

    %iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al el%e

    /arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (

    L = pan/ang (iap pla(e S (

    % =%iame(er %alam (angn = /-mla$ pla(e

    el% leng($ = n alloable el%e% /oin(

    L1 = 10.'92' in

    /a%i = pan/ang pla(e = 10.'929644in

    lebar pla(e = ' (

    (ebal pla(e = 0.1

    MENEN%"AN %O6 AN>LE "N%" CON#CAL ROOF

    bila %ig-nakan 10 pla(e (iap angle& maka pan/ang (iap angle :

    L = 10.093 (

    "MENEN%"AN %E&AL DAN %#N>># HEAD %AN>#

    "Browne and $o!ng% Pers')'(.-% (*++ , ((2/

    (ekanan pen!impanan = 1 a(m = 14.9 psi

    %an %iambil ak(or keamanan 10 maka:

    8 = 16.19 8si #os 30 = 0.'66

    7op angle -n(-k (angki #oni#al %engan %iame(er an(ara 3 ( $ingga 60 ( a%ala$ 21,2

    n

    engt1wedd

    L 12

    .. =

    -6.0.*o.2

    .

    P0f

    DPt1

    =

  • 7/24/2019 basis mol

    377/380

    ($ = 0.36001 in

    -%-( a%ala$ s-%-( #one roo (er$a%ap garis $oriTon(al.

    "Browne and $o!ng% Pers'-')% (*++ , )-/

    = %iame(er (angki s(an

    ($ = #one s$ell ($i#knessS i

    0.2230004

    = 12.'' %era/a(

    Men-h*tun- t*n--* hea' (h

    $ = 3.02064 (

    MENEN%"AN D#AME%ER 6#6A 6EN>#$#AN DAN 6EN>EL"ARAN

    = I-i% Io ra(e S (3 ,s

    Q = I-i% %ensi(! S lb,(3

    i = %iame(er op(im-m S in#$

    %iren#anakan ak(- pengisian selama ' /am.

  • 7/24/2019 basis mol

    378/380

    (-k ker-#-(

    ONVER$#

    1Kg,m3 = 0.06243lbm,(31 Kg 2.2046 lb

    1 $ari 24 /am

    1 ( 12 in#$

    0.304'm

    engisian %an pengosongan)

    77:41-43

  • 7/24/2019 basis mol

    379/380

    l = 2940 bbl = 133.' (3

    43.033m3

    e% & E = '

    (eel ?*2'3

    .6 Kg,m3

    62.1'43 lb,(3

    al 34'

    % /oin(

    i + (ebal s$ellSin

  • 7/24/2019 basis mol

    380/380

    % /oin(

    i + (ebal s$ellSin

    21,2 ,

    16