7/24/2019 basis mol
1/380
GPM (GROSS PROFIT MARGIN)
KOMPONEN $/kg $ / Lb BM $ /Lb molCH3OH 0.801 0.36332749 32.042 11.6417395HCl 0.4 0.18143695 36.461 6.61537263
CH3Cl 2 0.90718475 50.488 45.8019436H2O 0 0 18.015 0
1 Kg = 2.204623 Lb
reaksi :
GPM P!o"#k %&'k(') *1 + CH3Cl , 1 + H2O- *1 + CH3OH , 1 + HCl-
27.5448315
CH3OH + HCl CH3Cl + H2O
7/24/2019 basis mol
2/380
Komponen BM perr!"s #$emi#al engineers" $an%book&'($ e%i(ion) (a
CH3OH 32.042
HCl 36.461
CH3Cl 0.4''
H2O 1'.01
Kapasi(as 42000 (on,(a$-n reaksi CH3OH +
1 (a$-n = 330 $ari
24 /am
(on = 1000 Kg
7/24/2019 basis mol
3/380
le 2*13
Cl ** CH3Cl + H2O
7/24/2019 basis mol
4/380
rasio mol CH3OH : HCl HCl e#ess 1
1 : 1.1
ak(or s#ale*-p pabrik = 1
as-msi basis CH3OH : 100 Kmol,/am
3204.2 Kg,/am
konersi CH3OH = .00 Kirk o($mer)
kem-rnian CH3OH = .0 5llman& 40 ol)
CH3OH reaksi = Konersi m-la*m-la
komponen mol Kmol,/am Kg,/am bereaksi Kmol) sisa kmol)
CH3OH . . 3200.64.0 4.
H2O 0.1 0.1 1.'01
CH3OH + HCl CH3Cl
m-la . 114.''
reaksi 4.0 4.0 4.0
sisa 4. 1.' 4.0
kon%isi operasi:
7 = 300 Ckomponen8 = 3 bar = 2.6 a(m
CH3OH
pro%-k HCl
CH3Cl
H2O
7o(al Kg,/am)
-mpan
7/24/2019 basis mol
5/380
gar (i%ak (erben(-k pro%-k samping& !ai(- %ime(il e($er pa(en( 4&22&043)
HCl (eori(is = . kmol,/am 3642.43 Kg,/am
HCl e#ess = 14.' Kmol,/am 46.36'0' Kg,/am
HCl (o(al = 114.'' Kmol,/am 41''.'21' Kg,/am
kem-rnian HCl = 31
komponen mol Kmol,/am Kg,/am bereaksi kmol) sisa Kmol)
HCl 31 114.'' 41''.'224.0 1.'
H2O 6 2.91199 4606.64'
+ H2O
4.0 H2O (o(al pro%-k = H2O %ari me(anol + H2O %ari H
4.0
;857 O57857 np-(
Kmol,/am Kg,/am Kmol,/am Kg,/am raksi b
. 3200.' 4. 160.049 CH3OH 26.69''
114.'' 41''.'21 1.' 92'.409' HCl 34.11
0 0 4.0 491.636 CH3Cl 0.0000
2.'11' 460'.4411 30.916994 631'.1629 H2O 3'.403
490.6' 11'.266 490.6994 11'.269 100.0000
kem-rnian C$3Cl =
7/24/2019 basis mol
6/380
l + H2O reaksi
O-(p-(
era(
1.333
6.0916
3.3
2.60
100.0000
3.346
7/24/2019 basis mol
7/380
7/24/2019 basis mol
8/380
bera(
CH3OH 1.33341 0.430623 1.363
HCl 6.091633 0.09''4' 9.91312
CH3Cl 3.346 61.22'24 2.6223
H2O 2.6'6 3'.2432039 39.16416
7/24/2019 basis mol
9/380
ang bers-$- 10 * 20 C
r $ar-s bers-$- 30*40 C
77OM
Kg,/am
12'.03'32
921.20'92223.9'1'2
3494.'49'
463.'134 Kmol !ang (erserap : 221.419 Kmol
49'6.640' H2O %ari -(ili(as !ang %ib-(-$kan : 7o(al Kmol !aang (ers
30.3994 3''.'03 Kg,/am
169'4.'30'
H2O e#ess 20 agar pen%inginan semp-rna = 49'6.64
7/24/2019 basis mol
10/380
7/24/2019 basis mol
11/380
erap @ BM Kmol
Kg,/am
7/24/2019 basis mol
12/380
7/24/2019 basis mol
13/380
ke %is(ilasi
CA
(op pro%-#(
%ari -en#$er
ke -(ili(as
?s-msi: me(il klori%a (erserap ole$ H2O
inp-( komponen Kmol (erserap kmol) Kg
CH3OH 0.0 0.92 32.0100
HCl 0.1' 0.1' 9.2'4
CH3Cl 0.1' 4.0'0 41.'
H2O 19.'22 126.2'0 2'43.1932
7O7?L 131.921
maka kebutuhan H2O :
(o(al Kmol BM H2O = 2393.0291 Kg,/am
%ig-nakan air proses berlebi$ 20 -n(-k men!emp-rnakan pen!erapan
(o(al air proses = 2'49.6324'1320'Kg,/am
H2O pro%-k baa$ = air proses + H2O !ang (erserap
293.'0Kmol,/am
komponeninp-( 7
Kmol,/am Kg,/am Kmol,/am
CH3OH 0.0 32.0100 0.1'
7/24/2019 basis mol
14/380
HCl 0.1' 9.2'4 0.0400
CH3Cl 0.1' 41.' '.61'
H2O 19.'22 2'43.1932 31.64
>5ML?H 9434.43
C 1'.0901 2'49.632
7O7?L 102'2.0'60
komponeninp-(
o-(p-(
(op bo((om
bera(
CH3OH 0.43062321 0.13062431 1.010944'64'
HCl 0.09''4991 0.0292'99 0.230029'16
CH3Cl 61.22'24463 ''.2363624 '.'3323
H2O 3'.24320390' 11.602903311 '.99'9''9'
100 100 100
7/24/2019 basis mol
15/380
lolos kmol) Kg
0.1' 6.401
0.0400 1.46'
'.61' 4324.3'61
31.64 6'.63464
400.'9'0
p Bo((om
Kg,/am Kmol,/am Kg,/am
6.4020 0.92 2.60'0
7/24/2019 basis mol
16/380
1.490 0.1' .'29
4324.3'62 4.0'0 229.3
6'.6346 126.2'0 2294.3'6
400.'9' 233.939
2'49.632
3'1.2062
102'2.0'60
7/24/2019 basis mol
17/380
D
A
NM OVER ALL : F = D + W
komponen 7i(ik %i%i$ C ) 1 a(m)
CH3OH 64.4 CH3Cl
HCl 0. HCl
CH3Cl *24.3 CH3OH
H2O 100 H2O
DEE
komponen Kmol Kg Fi @i
? CH3OH 0.1' 6.40116 0.0019010621 0.001306
B HCl 0.036 1.46'16 0.0003402124 0.00029
C CH3Cl '.61962 4324.3'61' 0.922240416 0.''236
H2O 31.6406' 6'.634641' 0.26'9346'3 0.116029
7O7?L 119.460322 400.'9' 1 1
NM komponen CH3OH (A
mol CH3OH . D = !?. + @? . A
!?. + @? . A = 0.1' Kmol . . . . 3)
karena . CH3OH bera%a %i %is(ila( maka:
. mol CH3OH . D = !? .
F?. = 0.19'002Kmol . . . . 4)
7/24/2019 basis mol
18/380
s-bs(i(-si 4) ke 3)
@?. A= 0.00001' Kmol
komponen @. D @. @A. A
CH3OH 0.1' 0.19'002 0.00001'
HCl 0.036 0.036 0CH3Cl '.61962 '.61962 0
H2O 31.6406' 3.16406' 2'.40'0'909
7O7?L 119.460322 '.04934 2'.40'09'6'9
LA!" AL#R D# D#$%#LA% = '.04934'99Kmol
LA!" AL#R D# &O%%OM = 2'.40'09'6'9Kmol
7 ee% = 24 K 20.' C
8 = 960 mmHg 1 a(m
komponen @D 8sa( Ki G
CH3OH 0.001901062 101.'69441 0.134033'93' .699'9
HCl 0.000340212 3146.691'9 42.0304603 1946.144
CH3Cl 0.92224042 3'1'.00'9' .0239114' 20'.6'94
H2O 0.26'9346'4 1'.234 0.02409306' 1
7 (rial = 300 K
% 'e = 7 soler = 303.3139K 30.1639201C
8 = 960 mmHg 1 a(mkomponen ! 8sa( Ki G
CH3OH 0.00224311 16.1'96' 0.2193209 .16'2
HCl 0.00044'949 3'30.6'34 1.22412414 121'.40
CH3Cl 0.61'611 4''.1432 6.63346433' 16.112'
H2O 0.03446642 31.21662 0.0420423232 1
7rial = 30 K
% bub)e 7 soler = 393.1201K 100.00200C
8 = 960 mmHg 1 a(m
komponen @ 8sa( Ki GCH3OH 9.03321E*009 26'.09462 3.494699132 3.49493
HCl 0 12361.90 162.693263 162.696
CH3Cl 0 23332.2291 30.9003'1429 30.90043
H2O 0.29 9.'' 0.'446 1
7/24/2019 basis mol
19/380
D*t,*bu* komponen
komponen inp-( is(ila( as(e
CH3OH 0.1' 0.19'002 0.00001'
HCl 0.036 0.036 4.'134'E*022
CH3Cl '.61962 '.61962 2.419'1E*012
H2O 31.6406' 3.16406' 2'.40'0'909
119.460322 '.04934 2'.40'09'6'9
komponen;857
O57
Kmol,/am Kg,/am Kmol,/am Kg,/am
CH3OH 0.1' 6.40116 0.19'002 6.40131
HCl 0.036 1.46'16 0.036 1.46'2
CH3Cl '.61962 4324.3'61' '.61962 4324.3'6
H2O 31.6406' 6'.634641' 3.1640699 6.'634643'.10'
400.'9'
komponen inp-( (op bo((om
bera(
CH3OH 0.1306243 0.14'4626 0.00012046
HCl 0.0292'' 0.033131 3.423E*021
CH3Cl ''.236362 '.239 2.3'2E*011
H2O 11.6029033 1.2'6 .'9403
men-h*tun- ,e.u/
7 ae = 7%e + 7b-bl = 33'.232'2'2'' K
2
8 = 1 a(m 960 mmHg
komponen @ @% @ 8sa(
C$3OH 0.001901062 0.00224311 9.033211E*009 999.214
HCl 0.000340212 0.00044'949 1.6442E*023 93'32.64
CH3Cl 0.92224042 0.61'611 '.11012E*014 11991.'9H2O 0.26'9346'4 0.03446642 0.269 1''.331
-mpan mas-k %alam kea%aan /en-$ 1*=0)& maka = 1
0.
soler = 0.000
(rial =
7/24/2019 basis mol
20/380
komponen @ G G.@ , G*
CH3OH 0.0019 4.1293 0.001
HCl 0.0003 32.0366 0.0003
CH3Cl 0.922 62.063 0.931
H2O 0.26'9 1.0000 0.39
7O7?L 1.0000 1.294'
maka : = 0.
komponen @% G G.@% , G*
CH3OH 0.0022 4.1293 0.0026
HCl 0.0004 121'.403 0.0004
CH3Cl 0.61 16.112' 0.60
H2O 0.034 1.0000 0.090
7O7?L 1.0000 1.03''
Komposisi reI- L)
komponen @L kmol,/am
CH3OH 0.0022 0.011641194
HCl 0.0004 0.00232'46'
CH3Cl 0.61 4.0243
H2O 0.034 0.1'3262'
.1'''201
Komposisi -ap )
komponen F Kmol,/am
CH3OH 0.0022 0.21142114
HCl 0.0004 0.0422''46'
CH3Cl 0.61 0.6426'94
H2O 0.034 3.340399249
4.2369944
7/24/2019 basis mol
21/380
*24.3
0.
011L
455H
F = raksi mol
@ = raksi bera(
NM komponen H2O (D
!B . + @B . A = 31.6406994
karena 0 H2O bera%a %ibo((om maka:
0.0 mol H2O . D = @B . A
@B . A = 2'.40'0'909
mol H2O D = !B. + @
B. A
7/24/2019 basis mol
22/380
s-bs(i(-si 2) ke 1)
!B. 3.1640699
an(oine grain 7oler& C$emi#al enginee
komponen ?
CH3OH 1'.'9HCl 16.04
CH3Cl 16.102
H2O 1'.3036
!D D#$%R#&"$# OM6ONEN
0.00022' GL. = .16'200'
0.014300'61 GL. A = 3.494929'3
3.663440121 GL. ?e =
0.00646296 4.2222046
3.6'4
;m = 4.41099'
0.62'6162413
9.''111'4'2@
0.010321'9
'.9603'E*006
0.146040'
0.'4311'092
1.0000 untuk komponen HC) (&
GHCl. ?e =
44.1993332906
!A @B. = '.3016909E+012.4'4E*006 @B.A
0 @B. = '.3016909E+01
0
0.991 @B.D = @B. + @B.A
1.0000 s-bs(i(-si 1) ke 2)
@BA.A = 4.'1349043E*022
@B. = 0.036
GL. GL. A)J0.
G HCl. GHCl. A)J0.
CT
BAPsat
+=l)
7/24/2019 basis mol
23/380
untuk komponen met*) k)o,*'a ( C
G CH3Cl. ?e =
6.2266
@C. = 342296402.1
@[email protected] = 342296402.1
@C.D = @C. + @C. A
57 s-bs(i(-si 3) ke 4)
A @C.A = 2.419'143'4E*012
Kmol,/am Kg,/am @C. = '.61962
0.00001' 0.0006402
4.'13E*022 1.96E*020
2.419'1E*012 1.22E*010
2'.40'0'91 11.9911' kem-rnian CH3Cl %i%is(ila( =11.991'2 kem-rnian C$H3Cl %i bo((om =
400.'9'
ki G
1.02291'0 4.1292622
9.14'209 32.036'
1.4'3029 62.06230.249'033 1
geankoplis& persamaan 11.9*1)
G CH3Cl. G CH3Cl. A
= fX
q.
1
7/24/2019 basis mol
24/380
m,m+1 = 0.03934
m + 1 = G.@ , G*
m 0.03''
= 1.000 %m
= 0.0'3
eI-ks %is(ila(
L = .1''' Kg,/am
-ap !ang kel-ar %is(ila( men-/- kon%ensor
= L +
= 4.236'Kg,/am
7/24/2019 basis mol
25/380
Kmol . . . . 1)
Kmol . . . . 2)
7/24/2019 basis mol
26/380
Kmol
ing %esign)
B C
3626. *34.21914.2 *14.4
2099.9 *2.
3'16.44 *46.13
8 = mmHg
7 = Kelin
?& B& C = kons(an(a ?n(oine
Meng$i(-ng s(age (eori(is ;m)
s(age
@?.A . . . 1)
. . . 2)
WLDLAverageL x ... =
AverageL
WL
wH
DH
DL
m
Log
WX
WXx
DX
DXLog
N
.
.
.
.
. -.
.*-
.
./*
=
WBDBAverageL x ... =
X
Xx
WX
DX
WH
DH
average
WB
DB mN
.
.-*
.
.
.
.
.
. =
7/24/2019 basis mol
27/380
@C.A . . . . . 3)
. . . . 4)
'.23931 2.3'22'9E*011
men-h*tun- kapa*taCH3Cl !ang %i%apa( %ari %is(ila( = 4324.3'61'1 Kg,/am
1039'.26'44Kg,$ari
342413'.'6Kg,(a$-n
3424.13''67on,(a$-n
kapasi(as !ang %i$arapkan = 2000 (on,(a$-n
ak(or s#ale *-p pabrik = 0.0'3623
maka keb-(-$an: me(anol .'363Kmol,/am 1'9.1113Kg,/amHCl 6.9149 Kmol,/am 244.'39 Kg,/am
)J0.
7/24/2019 basis mol
28/380
7/24/2019 basis mol
29/380
7/24/2019 basis mol
30/380
7/24/2019 basis mol
31/380
7/24/2019 basis mol
32/380
7/24/2019 basis mol
33/380
komponen;857 O578
Kmol,/am Kg,/am Kmol,/am
CH3OH . 3200.' 4.
HCl 114.'' 41''.'21' 1.'
CH3Cl 0 0 4.0
H2O 2.'11994 460'.4411206' 30.91699413
11'.266'906' 11'.266
komponen ;857 7O
Kmol,/am Kg,/am Kmol,/am
CH3OH 4. 160.049 0.
HCl 1.' 92'.409' 0.1'
CH3Cl 4.0 491.6364 0.19
H2O 30.916994 631'.1626'906' 19.'224'3'91
air pen%ingin 26.6''11 49'6.6409'3 0
169'4.'30966'06
komponen;857
?8
Kmol,/am Kg,/am Kmol,/am
CH3OH 0. 32.00' 0.1'
HCl 0.1' 9.2'409' 0.036CH3Cl 0.19 41.'4' '.61962
H2O 19.'224' 2'43.19320136 31.6406994
CA 1'.09009 2'49.6324'1320'
102'2.0'60143144
komponen;857
7
Kmol,/am Kg,/am Kmol,/am
CH3OH 0.1' 6.40116 0.19'002
HCl 0.036 1.46'16 0.036
CH3Cl '.61962 4324.3'61'1 '.61962
H2O 31.6409 6'.634641'3'9 3.1640699
400.'9'000'9
7/24/2019 basis mol
34/380
komponen ;857 Kg,/am)
reak(or CA
7/24/2019 basis mol
35/380
57
Kg,/am REA%160.049
92'.409'
491.6364
631'.1626'906'
906'
O57857
BO77OM
Kg,/am Kmol,/am Kg,/am
32.00' 3.6 12'.03'32
9.2'409' 1.9'02 921.20'922 "EN41.'4' 4.942 23.9'1'2
2'43.19320136 12.'422'06 3494.'49903
0 26.6''106' 49'6.6409'4
9434.433236 30.3994436'9
169'4.'30966'06
O57857
L
7/24/2019 basis mol
36/380
O57857 Kg,/am)
bo((om -en#$er L s#r-bber %is(ila( as(e NM OV12'.03'32 2.609664 6.40131400' 0.00064012
921.20'922 .'292624 1.46'16 1.9069924222E*020
23.9'1'2 229.292 4324.3'61'1 1.22090643411E*010
'261.394'91 122.19104'6' 6.'634641'3 11.99119964'
30.3994436'91 3'1.20621422 43'.109'224 11.991'19'41
470321031895548
7/24/2019 basis mol
37/380
OR
H $;$%EM
&ER
$#
7/24/2019 basis mol
38/380
ER ALL
7/24/2019 basis mol
39/380
basis per$i(-ngan 1 /am operasi
sa(-an operasi /o-le,/am
7empera(-r basis 2 2'.1K
;E mi($& 2001)
%eal gas
komponen ? B C
CH3OH 21.1 9.0E*02 2.E*0 *2.'E*0'
HCl 30.69 *9.20E*03 1.2E*0 *3.0E*0
CH3Cl 13.'' 1.01E*01 *3.'E*0 2.9E*0
H2O 32.24 1.2E*03 1.06E*0 *3.60E*0
CH3OCH3 9.4 1.69E*01 .E*06 *3.34E*0'
Cp li-i%
ase li-i% #1 #2 #3 #4 #
CH3OH 1.06E+0 *362.23 0.39 0 0HCl 49300 0 0 0 0
CH3Cl 610 *209. 0.3946 0.0004'' 0
H2O 296390 *200.1 '.12 *0.014116 .3901E*006
0C
==T
T
pii dTCnHQ0
..
432
32
432T
DT
CT
BATCp
DTCTBTACpdtT
To
+++=
+++=
5432
432
5
5
4
4
3
3
2
21
54321
TC
TC
TC
TC
TCCp
TCTCTCTCCCpdt
T
To
++++=
++++=
7/24/2019 basis mol
40/380
gain 7oler& C$emi#al engineering %esign)
Cp gas
ase gas
HCl
8err!& (able 2*16 $al 220)
Cp = >,Kmol K
+= -&+*..
DT
CBAdTCp
7/24/2019 basis mol
41/380
H2O
L&b =
7# =
7b =
L = la(en( $ea( (empera(-re 7& K/,Kmol
L&b = la(en( $ea( a( ($e normal boiling poin(& K/,Kmol 7 =
7# = #ri(i#al (empera(-re & K
7b = boiling poin(& K L =7 = 7empera(-re& K
6.9+0.000'47 8err!&(able 2*14 $al 211)
=bc
c
bvvTT
TTLL .
7/24/2019 basis mol
42/380
406'3 K/,kmol
649.3K
100C
393.1K
30 C
303.1K
1090.9'
7/24/2019 basis mol
43/380
s(eam
7s = 300 C
7i = 30 C 7o = 20 C
s(eam kon%ensa(
7= 300 C
Ne,a
7/24/2019 basis mol
44/380
N s(eam = 31'' K/,Kg 1312.03' b(-,lb
< s(eam =
M s(eam = 0.6261342Kg
NERACA ENER>#
inp-( o-(p-(Komponen H K/,/am) H K/,/am)
CH3OH 6426.1'61309 19202.1'621
H2O 166.24963092' 2149.41336192
< s-ppl! 1936.16 0
< loss 0 '996.'096
1'1'1 1'1'1
Ms(eam . Ns(eam
7/24/2019 basis mol
45/380
D-ngsi : meng-apkan me($anol %engan ba
kon%isi operasi : 7 = 20
8 = 1.'
li-i%
komponen
CH3OH
HCl
CH3Cl
H2O
as
komponen
CH3OH
HCl
CH3Cl
H2O
enta)p* k2 C 7 =
2'.1K
komponen
CH3OH
H2O
enta)p* k
gan maksim-m 10 ) -lri#$& $al 432)
N CH3OH
N H2O
1 a(m = 101.32 Kpa
komponen
=T
T
p
ref
dCH
7/24/2019 basis mol
46/380
geankoplis& s(eam (able ?.2*10 CH3OH
H2O
= bvv LL .
7/24/2019 basis mol
47/380
(-an s(eam
C
a(m
C4 C2 C3 C1 C8
1.06E+0 *3.62E+02 .3'E*01 0.00E+00 0
4.93E+04 .00E+01 0.00E+00 0.00E+00 0
.6E+04 *2.0'E+02 3.9E*01 4.''E*04 0
2.96E+0 *2.0E+03 '.13E+00 *1.41E*02 .39E*006
A & C D
2.12E+01 9.0E*02 2.E*0 *2.'E*0'
3.09E+01 *9.20E*03 1.2E*0 *3.0E*0
1.3E+01 1.01E*01 *3.'E*0 2.9E*0
3.22E+01 1.2E*03 1.06E*0 *3.60E*0
mponen ke)ua,20 C 7re = 2 C
23.1 K 2'.1 K
n Kmol,/am) H K/,/am)
6633.'642461 122.0'1069 '12902.9
9340.442426 0.122630'21 00.16
'13602.
mponen
(er/a%i per-ba$an ase
329' K/,Kmol gain 7oler& C$emi#al engineering %esign)
406'3 K/,Kmol
n Kmol,/am) H
Cp %7
Cp %7
+ nT -.*
7/24/2019 basis mol
48/380
6633.'642461 122.0'1069 19202
9340.442426 0.122630'21 2149.413
193200
H2O
L&b =
7# =
7b =
L = la(en( $ea( (empera(-re 7& K/,Kmol
L&b = la(en( $ea( a( ($e normal boiling poin(& K/,Kmol 7 =
7# = #ri(i#al (empera(-re & K
7b = boiling poin(& K L =
7 = 7empera(-re& K
CH3OHL&b =
7# =
7b =
7 =
L =
bc
c
TT
TT
7/24/2019 basis mol
49/380
7/24/2019 basis mol
50/380
406'3 K/,kmol
93.1K
100C
393.1K
20C
23.1K
10190.9
329' K/,kmol 329'
93.1K
64.4C
339.K
20C
23.1K
94'6.'42
7/24/2019 basis mol
51/380
s(eam
7s = 300 C
7i = 30 C 7o = 20 C
s(eam kon%ensa(
7 = 300 C
;era#a energi (o(al:
H inp-( + < s-ppl! = H o-(p-( + < loss
enta)p* komponen *nput7 = 30 C 7re =
303.1K
komponen n Kmol,/am) H K/,/am)
HCl 23962 140.''4412' 33499.66
H2O 136060.01'9' 313.'144366 4223.3
4'912.
ne,a
7/24/2019 basis mol
52/380
M s(eam = 213.'10932060Kg
NERACA ENER>#inp-( o-(p-(
Komponen H K/,/am) H K/,/am)
HCl 33499.660131493 1436040.299
H2O 4223.2'04442 411''.'063
< s-ppl! 6'0'64.613'0'4 0
< loss 0 34044'.2306
926969' 926969'
7/24/2019 basis mol
53/380
D-ngsi : meng-apkan HCl %engan ban(-an s(eam
kon%isi operasi : 7 = 20 C
8 = 1.' a(m
komponen ? B
CH3OH 21.1 9.0E*02
HCl 30.69 *9.20E*03
CH3Cl 13.'' 1.01E*01
H2O 32.24 1.2E*03
komponen C1 C2CH3OH 1.06E+0 *3.62E+02
HCl 4.93E+04 .00E+01
CH3Cl .6E+04 *2.0'E+02
H2O 2.96E+0 *2.0E+03
enta)p* komponen ke)ua,2 C 7 = 20 C
2'.1 K 23.1 K
komponen n Kmol,/am)
HCl 6963.2'6 140.''4412'
H2O 9340.44 313.'14439
enta)p* komponengan maksim-m 10 ) -lri#$& $al 432)
N HCl 16161 K/,Kmol
N H2O 406'3 K/,Kmol
komponen n Kmol,/am)
& s(eam (able ?.2*10 HCl 6963.2'6 140.''4412'
H2O 9340.44 313.'14439
Cp %7
Cp %7
+=T
T
p
ref
ndTCH -.*
7/24/2019 basis mol
54/380
L = la(en( $ea( (em
L&b = la(en( $ea( a( (
7# = #ri(i#al (empera
7b = boiling poin(& K
7 = 7empera(-re& K
=
bc
cbvv
TT
TTLL .
7/24/2019 basis mol
55/380
C
2.E*0 *2.'E*0'
1.2E*0 *3.0E*0
*3.'E*0 2.9E*0
1.06E*0 *3.60E*0
C3 C4 C.3'E*01 0.00E+00 0
0.00E+00 0.00E+00 0
3.9E*01 4.''E*04 0
'.13E+00 *1.41E*02 .39E*006
7re = 2 C
2'.1K
H
2'41.9
2301'30
324692
(er/a%i per-ba$an ase
gain 7oler& C$emi#al engineering %esign)
H
1436041
411'
7/24/2019 basis mol
56/380
62922
H2O
L&b = 406'3 K/,kmol
7# = 93.1 K
7b = 100 C
era(-re 7& K/,Kmol 393.1 K
e normal boiling poin(& K/,Kmol 7 = 20 C
(-re & K 23.1 K
L = 10190.9
CH3OH
L&b = 16161 K/,kmol
7# = 93.1 K
7b = 64.4 C
339.K
7 = 20 C
23.1K
L = 342.94
7/24/2019 basis mol
57/380
7i = 20 C 7o = 300 C
Ne,a
7/24/2019 basis mol
58/380
NERACA ENER>#komponen inp-( K/,/am) o-(p-( K/,/am)
CH3OH '12902.909 10'03'.9316403
HCl 0 1161299.139'1
H2O 2302930.44632 2'242.9'93'
< s-ppl! 2030'9.39
< loss 10143.96'961
7O7?L 146312.6' 146312.6'
7/24/2019 basis mol
59/380
D-ngsi : memanaskan me($anol %an HCl %engan ban(-an s(eam
kon%isi operasi : 7 = 300 C
8 = 3 a(m
komponen ?
CH3OH 21.1
HCl 30.69
CH3Cl 13.''
H2O 32.24
enta)p* kompone2 C 7 = 300
2'.1 K 93.1
Me($anol
komponen
CH3OH '636.493
H2O 006.94
HCl
komponen
HCl '242.96
H2O 006.94
%O%AL O"%6"% =
keb-(-$an s(eam
gan maksim-m 10 ) -lri#$& $al 432) s(eam !ang %ig-nakan
N s(eam = 31''
< s(eam =
M s(eam = 639.03''
Cp %7
Cp %7
Ms(eam .
7/24/2019 basis mol
60/380
7/24/2019 basis mol
61/380
B C
9.0E*02 2.E*0 *2.'E*0'
*9.20E*03 1.2E*0 *3.0E*0
1.01E*01 *3.'E*0 2.9E*0
1.2E*03 1.06E*0 *3.60E*0
n outputC 7re = 2 C
K 2'.1 K
n Kmol,/am) H
122.0'109 10'03
0.122630'22 1104.0
10143
n Kmol,/am) H
140.''4413 1161299
313.'1444 2'2434'
3'62
04496K/,>am
a%a (ekanan a(m %engan s-$- 360 C
K/,Kg eankoplis& s(eam (able ?.2*10
Kg
s(eam
7/24/2019 basis mol
62/380
7/24/2019 basis mol
63/380
7o = 330 C
7i = 300 C
300 C
2 C PH reaksi 2 C
Ne,a
7/24/2019 basis mol
64/380
ber%asarkan Himmelbla- $alaman 46:
panas reaksi s(an%ar& 2 C
reaksi !ang (er/a%i :
CH3OH + HCl ** CH3Cl + H2O
%a(a en(alpii pemben(-kan ain 7oler& #$emi#al engineering %esig
komponen PH K/,mol) K/,Kmol
CH3OH *201.3 *201300
HCl *2.36 *2360
CH3Cl *'6.39 *'6390
H2O *242 *242000
*622030
komponen n kmol) PH K/,/am) PH reaksi K/,/am)
CH3OH 6.124034 *1233044.319 *110636'.012392
HCl 24.0163'14 *226291.2'213
CH3Cl 116.3'29'11 *1001'0.'0946
H2O 430.0'6'613 *1040'1020.4423
*111201.012392
Ne,a
7/24/2019 basis mol
65/380
-ngsi : mereaksikan me(anol %an HCl
kon%isi operasi : 8 = 3 a(m
7 = 300 C
330 C
komponen ?
CH3OH 21.1
HCl 30.69
CH3Cl 13.''
H2O 32.24
enta)p* ke)ua,
7 = 330
603.1
04496'.9130K/,/am
komponen Cp %7
7/24/2019 basis mol
66/380
CH3OH 32.3'2936
HCl 12'.'21494133
CH3Cl ''9.191'4'92
H2O 10014.6'94'269
NERACA ENER>#komponen inp-( K>,/am)
n) CH3OH 10'03'.93164
HCl 1161299.139'
CH3Cl 0
H2O 2'242.9'936
PHr 110636'.01
< serap
116'193.923
ekso(ermis
110636'.01
kebutuhan a*, pen'*n-*n:
m = ,kmol K
7/24/2019 basis mol
70/380
NERACA ENER>#
komponeninp-( K/,/am) o-(p-( K/,/am)
(op bo((om
CH3OH 60'3.10131 1913.1'669 2943.10026
HCl 223691.0'036 449.200063 61.100'
CH3Cl 43.133102 1114'.'06 0
H2O 43091'.0664 3919.033 14106'.9
CA 9'0.349 0
< serap *10964.0
7O7?L 4'306.43 13061634.099
13041.026 13041.026
kebutuhan a*, pen'*n-*n: Cp air = 4.1'6'
7in = 20
m = < 7 o-( = 30
Cp.P7
26224.420Kg
< = m.Cp.P7
7/24/2019 basis mol
71/380
D-ngsi : men%inginkan se#ara men%a%ak %engan ban(-an air pen%ingin !a
kon%isi operasi :
7 = ' C
8 = 1 a(m
komponen C4 C2 C3
CH3OH 10'00 *362.23 0.39
HCl 49300 0 0
CH3Cl 610 *209. 0.3946
H2O 296390 *200.1 '.12
komponen ? B C
CH3OH 21.1 9.0E*02 2.E*0
HCl 30.69 *9.20E*03 1.2E*0
CH3Cl 13.'' 1.01E*01 *3.'E*0
H2O 32.24 1.2E*03 1.06E*0
CH3OCH3 9.4 1.69E*01 .E*06
enta)p* output%O6 6ROD"C%
7 = ' C 7re =
3'.1K
komponen n kmol) H
CH3OH 13'.426 1.220'106' 1913.1'669'9
C HCl 1'2'.123 0.240163'14 449.200063
K CH3Cl 1012.2' 110.636420 1114'.'061
H2O 13'.611 13.30'96 3919.032'
4'306.429&O%%OM 6ROD"C%
7 = 30 C 7re =
303.1K
N CH3OH 329' K/,Kmol
N HCl 16161 K/,Kmol gain 7oler& C
N H2O 406'3 K/,Kmol
Cp %7
7/24/2019 basis mol
72/380
komponen n Kmol,/am) H
CH3OH 2411.2 4.003296291 2943.10026
HCl 23962 24.2662194 61.100'
H2O 136060 10131.2106 14106'.92
141'.113
L = la(en( $ea( (empera(-re 7& K/,K
L&b = la(en( $ea( a( ($e normal boilin
K/,Kg K 7# = #ri(i#al (empera(-re & K
C 23.1 K 7b = boiling poin(& K
C 303.1 K 7 = 7empera(-re& K
Cp %7
=bc
c
bvvTT
TTLL .
7/24/2019 basis mol
73/380
g bers-$- 10 s,% 20 C
C1 C8
0 0
0 0
0.0004'' 0
*0.014116 .39E*006
*2.'E*0'
*3.0E*0
2.9E*0
*3.60E*0
*3.34E*0'
2 C
2'.1K
2 C
2'.1K
$emi#al engineering %esign)
7/24/2019 basis mol
74/380
H2O
L&b = 406'3 K/,kmol
7# = 303.1K
7b = 100 C
ol 393.1 K
poin(& K/,Kmol 7 = ' C
3'.1K
L = 316.21
CH3OH
L&b = 406'3 K/,kmol
7# = 303.1K
7b = 64.4 C
339.K
7 = ' C
3'.1K
L = 604.4
7/24/2019 basis mol
75/380
CA
7# = 30 C
7i= ' 7o = 0 C
CA
7#o = 4 C
NERACA ENER># %O%AL : H *nput = H o
enta)p* *nputH o-(p-( %ari (op
7/24/2019 basis mol
76/380
m = 4632.'243093Kg
7/24/2019 basis mol
77/380
D-ngsi = men%inginkan -ap kel-aran -en#$er %engan ban(-an CA
kon%isi operasi =
7 = 0 C
8 = 1 a(m
utput + e,ap
komponen ? B
CH3OH 21.1 9.0E*02
HCl 30.69 *9.20E*03
CH3Cl 13.'' 1.01E*01
H2O 32.24 1.2E*03
NERACA ENER>#
komponen inp-( K>,/am) o-(p-( K/,>am)CH3OH 1913.1'669'92 69.09402'
HCl 449.200062' 1'9.33094231
CH3Cl 1114'.'060' 41'46.90203339
H2O 3919.032' 1611.436'6
< serap 2049'.4030'21
4'306.4292 4'306.429249
7/24/2019 basis mol
78/380
7/24/2019 basis mol
79/380
C
2.E*0 *2.'E*0'
1.2E*0 *3.0E*0
*3.'E*0 2.9E*0
1.06E*0 *3.60E*0
7/24/2019 basis mol
80/380
7/24/2019 basis mol
81/380
CA
7# = 20 C 7o = 3 C
7i = 0 C 7 = 30 C
enta)p* *nputH o-(p-( %ari #ooler = 1''2'.436 K/,/am
Cooling a(er = 493463.6'' K/,/am
1731272232K/,/am
H2O %ari -(ili(as
7 = 20 C 7re = 2
23.1 K 2'.1
komponen kg,/am Kmol,/am HH2O 342.091014 13.'42639 136060.01 493464
H *nput = H output + e,ap< serap = *''1292.1K/,/am
Cp %7
7/24/2019 basis mol
82/380
NERACA ENER>#
komponeninp-( K/,/am) o-(p-( K/,/am)
(op bo((om
CH3OH 69.09403 263.44409 260.212296
HCl 1'9.3309423 9.032126 963.99444
CH3Cl 41'46.9020334 10.3'62 0
H2O 1611.436'6 62416.219 1393'30.1
CA 493463.6'' 0
< serap *''1292.1
7O7?L 9'660.1966 4'632.04
43422.2316 43422.2320
kebutuhan a*, pen'*n-*n: Cp air = 4.1'6'
7in = 20
m = < 7 o-( = 30
Cp.P7
212364.3'4Kg
< = m.Cp.P7
7/24/2019 basis mol
83/380
D-ngsi : men!erap HCl e#ess %an komponen lainn!a %engan ban(-an CA
kon%isi operasi :
7 = 3 C
8 = 1 a(m
komponen C4 C2 C3
CH3OH 10'00 *362.23 0.39
HCl 49300 0 0
CH3Cl 610 *209. 0.3946
H2O 296390 *200.1 '.12
komponen ? B C
CH3OH 21.1 9.0E*02 2.E*0
HCl 30.69 *9.20E*03 1.2E*0
CH3Cl 13.'' 1.01E*01 *3.'E*0
H2O 32.24 1.2E*03 1.06E*0
CH3OCH3 9.4 1.69E*01 .E*06
enta)p* output%O6 6ROD"C%
7 = 3 C 7re =
30'.1K
komponen n kmol) H
CH3OH 21.046 1.220'106' 263.444069
C HCl 306.3441 0.240163'14 9.0321261
K CH3Cl 143.'9 110.636420 10.3'623
H2O 322.49 13.30'96 62416.219
9'660.1966&O%%OM 6ROD"C%
7 = 30 C 7re =
303.1K
N CH3OH 329' K/,Kmol
N HCl 16161 K/,Kmol gain 7oler& C
N H2O 406'3 K/,Kmol
Cp %7
7/24/2019 basis mol
84/380
komponen n Kmol,/am) H
CH3OH 2411.2 4.003296291 260.212296
HCl 23962 24.2662194 963.99444
H2O 136060 10131.2106 1393'30.1
1394604.109
L = la(en( $ea( (empera(-re 7& K/,K
L&b = la(en( $ea( a( ($e normal boilin
K/,Kg K 7# = #ri(i#al (empera(-re & K
C 23.1 K 7b = boiling poin(& K
C 303.1 K 7 = 7empera(-re& K
Cp %7
=bc
c
bvvTT
TTLL .
7/24/2019 basis mol
85/380
C1 C8
0 0
0 0
0.0004'' 0
*0.014116 .39E*006
*2.'E*0'
*3.0E*0
2.9E*0
*3.60E*0
*3.34E*0'
2 C
2'.1K
2 C
2'.1K
$emi#al engineering %esign)
7/24/2019 basis mol
86/380
H2O
L&b = 406'3 K/,kmol
7# = 23.1K
7b = 100 C
ol 393.1 K
poin(& K/,Kmol 7 = 30 C
303.1K
L = 0'.39
CH3OH
L&b = 329' K/,kmol
7# = 23.1K
7b = 64.4 C
339.K
7 = 30 C
303.1K
L = 94.4
HCl
L&b = 16161 K/,kmol
7# = 23.1K
7b = 0. C
323.6K
7 = 30 C
303.1K
L = 2'.6'
7/24/2019 basis mol
87/380
CA
7# = 30 C
7i= 3 7o = 32. C
CA
7#o = 4 C
NERACA ENER># %O%AL : H *nput = H o
enta)p* *nputH o-(p-( %ari (op s#r-bber = 9'660.1'K/,>am
enta)p* output
7 = 20.' C 7re = 2 C
24 K 2'.1 K
komponen n kmol) HCH3OH *442211.'0469 0.24016 *10'.341
HCl *11.'9 0.04003 *.'112
CH3Cl *4039.66639914 10.03 *42431.99
H2O *11612'.4640'4 3'.909'2 *40.'
*'964.2'
(er/a%i per-ba$an ase
N CH3OH 329' K/,Kmol
N HCl 16161 K/,Kmol gain 7oler& C$emi#al enginee
N CH3Cl 21436 K/,Kmol
N H2O 406'3 K/,Kmol
komponen n kmol) H
CH3OH ''.3'3'2611 0.24016 *904.'99
HCl 129.21'9'9239 0.04003 *'030.02
CH3Cl '.4942421 10.03 1'362
Cp %7
Cp %7
+=T
T
p
ref
ndTCH -.*
7/24/2019 basis mol
88/380
H2O 133.'12'13'3 3'.909'2 *910349
112'12
;era#a energi (o(al
H inp-( = H o-(p-( + < serap
< serap = *10431.''2K/,/am 10432
keb-(-$an air pen%ingin:
H 4 C) = 1''.4 K/,Kg
H 30 C) = 12.9 K/,Kg
m =#komponen inp-( K>,/am) o-(p-( K/,>am)
CH3OH 263.444066' *904.'992'6
HCl 9.03212611 *'030.022349'4
CH3Cl 10.3'6233 1'3624.6491
H2O 62416.2194' *910349.42940'
< serap *10431.''2
9'660.1966 9'660.19660024
7/24/2019 basis mol
91/380
C
2.E*0 *2.'E*0'
1.2E*0 *3.0E*0
*3.'E*0 2.9E*0
1.06E*0 *3.60E*0
C3 C1 C8
0.39 0 0
0 0 0
0.3946 0.0004'' 0
'.12 *0.014116 .39E*006H2O
L&b = 406'3 K/,kmol
7# = 23.1 K
7b = 100 C
(empera(-re 7& K/,Kmol 393.1 K
a( ($e normal boiling poin(& K/,Kmol 7 = *16.3 C
pera(-re & K 26.' K
(& K L = *1'4'.34
re& K
CH3OH
L&b = 329' K/,kmol
7# = 23.1 K
7b = 64.4 C
339.K
7 = *16.3 C
26.' K
L = *2'''1.''
7/24/2019 basis mol
92/380
HCl
L&b = 16161 K/,kmol
7# = 23.1 K
7b = 0. C
323.6K
7 = 30 C
*16.3K
L = *1634
CH3Cl
L&b = 21436 K/,kmol
7# = 23.1 K
7b = *24.3 C
24'.'K
7 = *16.3 C
26.' K
L = 19'.13
7/24/2019 basis mol
93/380
Ne,a
7/24/2019 basis mol
94/380
HCl 0.00044 1.9'9'4' 0.0403 222.1239
CH3Cl 0.61'61 306.412 10.1024 112.019
H2O 0.03449 6.9966 3.'932 234.919
< kon%ensasi = .H * .H% * L.HL 221639
keb-(-$an air pen%ingin
s-$- air pen%ingin mas-k = 30 C
s-$- air pen%ingin kel-ar = 4 C
Cp air pen%ingin = 4.1'4 K/,Kg
< serap =
m air pen%ingin = < serap
3314.'Kg
Ne,a
7/24/2019 basis mol
95/380
-ngsi : memisa$kan me(il klori%a %ari imp-ri(iesn!a.
kon%isi operasi = 8 = 1 a(m
7 = (rial boiling poin( ee%
kon'ena* + )o
n'ena* + )o
@9017294348308K/,/am
7 = 2. C
enta)p* '*t*)at
C 7 = 30.163'322
K 303.313'322
N H komponen Kg,/am
329' '693.' CH3OH 9.'002'1
7/24/2019 basis mol
96/380
16161 '03.33'9 HCl 1.9'690'461
21436 226494 CH3Cl 303.030303620
406'3 1'4'4.9 H2O 6.932133262
2294226
K/,/am enta)p* bottom
7 = 100.00200'6393.1200'6
komponen Kg,/am
CH3OH 0.0009'0'1
HCl 2.1223033E*020
CH3Cl 1.4661'0E*010
H2O 629.'13'4
NERACA ENER>#loss komponen inp-( K>,/am)
ss
CH3OH *10'.340'496
m 10) HCl *.'11164
CH3Cl *42431.963'4
H2O *40.'1226191
< reboiling 306'6.'1022
< kon%ensasi
< loss
- 10 C m (able D*2 2'1010.3169306
7/24/2019 basis mol
97/380
komponen ? B C
CH3OH 21.1 9.0E*02 2.E*0 *2.'E*0'
HCl 30.69 *9.20E*03 1.2E*0 *3.0E*0
CH3Cl 13.'' 1.01E*01 *3.'E*0 2.9E*0
H2O 32.24 1.2E*03 1.06E*0 *3.60E*0
komponen C4 C2 C3 C1 C8
CH3OH 10'00 *362.23 0.39 0 0
HCl 49300 0 0 0 0
CH3Cl 610 *209. 0.3946 0.0004'' 0
H2O 296390 *200.1 '.12 *0.014116 .39E*006
enta)p* ,e.u/
C 7re = 2 C 7 = 30.163' C
K 2'.1 K 303.3136 K
n kmol) H komponen Kg,/am n kmol)
0.2441'99 4121.2 132.66'3 CH3OH 0.00006 0.00016
Cp %7
7/24/2019 basis mol
98/380
0.040032963 24439.3 12.02923 HCl 0.00113 3.12E*00
10.034' 4964'.6 2290.9 CH3Cl 3.3'161 0.0669'
3.'909'192 1366 419.416 H2O 0.044466 0.00246'
9'32.'6
C 7re = 2 CK 2'.1 K
n kmol) H
2.40164E*00 904'23 0.1926
.02'1E*022 3'00936 2.24E*01'
2.64'E*012 6940236 2.00E*00'
34.'390396' 1''039 33'9.6
33'9.'
o-(p-( K/,/am)
%is(ila( bo((om
132.66'302 0.1926
12.029233609 2.24E*01'
2290.913' 2.00E*00'
419.4191 33'9.6
221639
13433
9'32.'62613 2231992'1010.31693063
Cp %7
7/24/2019 basis mol
99/380
7re = 2 C
2'.1K
H
4121.2 0.0'4
Cp %7
7/24/2019 basis mol
100/380
24439.3 0.00966
4964'.6 33.33196
1366 3.441
36.'9''
7/24/2019 basis mol
101/380
7ipe (angki silin%er (egak %engan %asar %a(ar %an a(asn!a b
%asar pemili$an 5m-mn!a %ig-nakan -n(-k li-i% pa%a (ekanan a(mos
8er$i(-ngan :
MEN>H#%"N> DEN$#%A$ CAM6"RAN:
komponen mol kmol,/am massa Kg,/am) Q Kg,m3) ol-me m
CH3OH 0. 122.0'11 32.40944920 9'3. .00936
H2O 0.001 0.122630'2 2.2014243 0.00222
329.616636' .0096
ensi(as #amp-ran = 9'3.3' Kg,m3
4'.44919'lb,(3
%iren#anakan pen!impanan -n(-k 10 $ari %engan 3 b-a$ (angki mem-%a$kan
se$ingga ol-me masing*masing:
pen!impanan = 10 $ari
/-mla$ (angki = 6 b-a$
keb-(-$an me(anol = 329.61664 Kg,/am selama 1 $ari
42629.4 Kg selama 10 $ari
259449 lb
Bo)ume metano) pa'a tan-k*:
ol-me (angki = 424'.4669 (3
ol-me me(anol %alam 1 (angki = 9096.41112266 (3
as-msi ba$an isi '0 ol-me (angki ak(or keamanan)
se$ingga ol-me (angki = '41.6334949 (3
'41.6334949(3
MENEN%"AN D#MEN$# %AN>#
rasio H, = 3,'
= iame(er Brownel,1
H = 7inggi 7angki
R = 3.1413
H = 11.4'''3 (
3.04'm
= 30.6636'' (
.34622 m
HDvo!me ...4
1 2
=
7/24/2019 basis mol
102/380
%ig-nakan %iame(er 3 ( %an (inggi 16 ( &maka
MENEN%"AN !"MLAH 6LA%E DAN %E&AL $HELL
"Browne and $o!ng% pers &'()%(*++ , -./
( = (ebal s$ell S in
8 = (ekanan in(ernal S psi
% = insi%e %iame(er S in
C = ak(or korosi S in 1,' in)
E = ak(or pengelasan& %ig-nakan %o-ble el%
= s(ress alloable& ba$an kons(r-ksi Carbon
ra%e C& maka = 1260 psi
8 = (ekanan in(ernal S 8si = %ensi(as air pa%a s-$- 30 Cel#i-s =H = (inggi #o-rseS (
Cou,e 4
H = 16 (
(1 = 0.214' in
%ipili$ (ebal s$ell s(an%ar = 0.2' in BronellS
meng$i(-ng pan/ang pla(e%iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al
/arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (
L = pan/ang (iap pla(e S (
% =%iame(er %alam (ang
n = /-mla$ pla(e
el% leng($ = n alloable el%e% /oin(
L1 = 10.'''4 in
/a%i = pan/ang pla(e = 10.'''3'3'in
lebar pla(e = ' (
(ebal pla(e = 0.2'
Cou,e 2
H = 16 ( * ' (
(2 = 0.124431
%ipili$ (ebal s$ell s(an%ar = 0.1 in
%iren#anakan akan mengg-nakan s$ell pla(e %engan 6 in ' () butt-weldes cou
C0f
dP
t += ..2.
144-1* = HP
n
engt1weddL
12
.. =
7/24/2019 basis mol
103/380
meng$i(-ng pan/ang pla(e
%iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al
/arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (
L = pan/ang (iap pla(e S (
% =%iame(er %alam (ang
n = /-mla$ pla(e
el% leng($ = n alloable el%e% /oin(
L1 = 10.'92' in
/a%i = pan/ang pla(e = 10.'929644in
lebar pla(e = ' (
(ebal pla(e = 0.1
MENEN%"AN %O6 AN>LE "N%" CON#CAL ROOF
bila %ig-nakan 10 pla(e (iap angle& maka pan/ang (iap angle :
L = 10.093 (
"MENEN%"AN %E&AL DAN %#N>># HEAD %AN>#
"Browne and $o!ng% Pers')'(.-% (*++ , ((2/
(ekanan pen!impanan = 1 a(m = 14.9 psi
%an %iambil ak(or keamanan 10 maka:
8 = 16.19 8si #os 30 = 0.'66
($ = 0.36001 in
7op angle -n(-k (angki #oni#al %engan %iame(er an(ara 3 ( $ingga 60 ( a%ala$
n
engt1weddL
12
.. =
-6.0.*o.2.
P0fDPt1
=
7/24/2019 basis mol
104/380
-%-( a%ala$ s-%-( #one roo (er$a%ap garis $oriTon(al.
"Browne and $o!ng% Pers'-')% (*++ , )-/
= %iame(er (angki s(an
($ = #one s$ell ($i#knessS i
0.2230004
= 12.'' %era/a(
Men-h*tun- t*n--* hea' (h
$ = 3.02064 ( 1.1'4'321 m
MENEN%"AN D#AME%ER 6#6A 6EN>#$#AN DAN 6EN>EL"ARAN
= I-i% Io ra(e S (3 ,sQ = I-i% %ensi(! S lb,(3
i = %iame(er op(im-m S in#$
%iren#anakan ak(- pengisian selama ' /am.
7/24/2019 basis mol
105/380
erben(-k ker-#-(
$erik
ONVER$#
1Kg,m3 = 0.06243lbm,(3 3,/am) 1 Kg 2.2046 lb
1 $ari 24 /am
1 ( 12 in#$
0.304'm
roses pengisian %an pengosongan)
77:41-43
7/24/2019 basis mol
106/380
l = 2940 bbl = 133.' (3
43.033m3
e% & E = '
(eel ?*2'3
.6 Kg,m3
62.1'43 lb,(3
al 34'
el%e% /oin(
i + (ebal s$ellSin
ses.
7/24/2019 basis mol
107/380
el%e% /oin(
i + (ebal s$ellSin
21,2 21,
2 ,
16
7/24/2019 basis mol
108/380
arS (
n
%(**( , &)./
7/24/2019 basis mol
109/380
7ipe (angki silin%er (egak %engan %asar %a(ar %an a(asn!a b
%asar pemili$an 5m-mn!a %ig-nakan -n(-k li-i% pa%a (ekanan a(mos
8er$i(-ngan :
MEN>H#%"N> DEN$#%A$ CAM6"RAN:
komponen mol kmol,/am massa Kg,/am) Q Kg,m3) ol-me m
HCl 31 140.''441 136.9'6'1139'1 113 4.30993
H2O 6 313.'144 64.16'103244 .699'
109'.6621902 .'333
ensi(as #amp-ran = 10'0.366 Kg,m3
69.44163lb,(3
%iren#anakan pen!impanan -n(-k 9 $ari %engan b-a$ (angki mem-%a$kan pr
se$ingga ol-me masing*masing:
pen!impanan = 9 $ari
/-mla$ (angki = 9 b-a$
keb-(-$an HCl = 109'.66 Kg,/am selama 1 $ari
1'12040.91 Kg selama 9 $ari
3771928 lb
Bo)ume metano) pa'a tan-k*:
ol-me (angki = 229.1'3 (3
ol-me HCl %alam 1 (angkki = '461.02'32'3'2(3
as-msi ba$an isi '0 ol-me (angki ak(or keamanan)
se$ingga ol-me (angki = 1013.2334069 (3
1013.2334069(3
MENEN%"AN D#MEN$# %AN>#
rasio H, = 3,'
= iame(er Brownel,1
H = 7inggi 7angki
R = 3.1413
H = 12.20466 (
3.91'03m
= 32.496 (
.1496m
HDvo!me ...4
1 2
=
7/24/2019 basis mol
110/380
%ig-nakan %iame(er 3 ( %an (inggi 16 ( &maka
MENEN%"AN !"MLAH 6LA%E DAN %E&AL $HELL
"Browne and $o!ng% pers &'()%(*++ , -./
( = (ebal s$ell S in
8 = (ekanan in(ernal S psi
% = insi%e %iame(er S in
C = ak(or korosi S in 1,' in)
E = ak(or pengelasan& %ig-nakan %o-ble el%
=s(ress alloable& ba$an kons(r-ksi Lo all
ra%e B& maka = 1'90 psi
8 = (ekanan in(ernal S 8si = %ensi(as air pa%a s-$- 30 Cel#i-s =H = (inggi #o-rseS (
Cou,e 4
H = 16 (
(1 = 0.21031 in
%ipili$ (ebal s$ell s(an%ar = 0.2' in BronellS
meng$i(-ng pan/ang pla(e%iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al
/arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (
L = pan/ang (iap pla(e S (
% =%iame(er %alam (ang
n = /-mla$ pla(e
el% leng($ = n alloable el%e% /oin(
L1 = 10.'''4 in
/a%i = pan/ang pla(e = 10.'''3'3'in
lebar pla(e = ' (
(ebal pla(e = 0.2'
Cou,e 2
H = 16 ( * ' (
(2 = 0.164'13
%ipili$ (ebal s$ell s(an%ar = 0.1 in
%iren#anakan akan mengg-nakan s$ell pla(e %engan 6 in ' () butt-weldes cou
C0f
dP
t += ..2.
144-1* = HP
n
engt1weddL
12
.. =
7/24/2019 basis mol
111/380
meng$i(-ng pan/ang pla(e
%iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al
/arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (
L = pan/ang (iap pla(e S (
% =%iame(er %alam (ang
n = /-mla$ pla(e
el% leng($ = n alloable el%e% /oin(
L1 = 10.'92' in
/a%i = pan/ang pla(e = 10.'929644in
lebar pla(e = ' (
(ebal pla(e = 0.1
MENEN%"AN %O6 AN>LE "N%" CON#CAL ROOF
bila %ig-nakan 10 pla(e (iap angle& maka pan/ang (iap angle :
L = 10.093 (
"MENEN%"AN %E&AL DAN %#N>># HEAD %AN>#
"Browne and $o!ng% Pers')'(.-% (*++ , ((2/
(ekanan pen!impanan = 1 a(m = 14.9 psi
%an %iambil ak(or keamanan 10 maka:
8 = 16.19 8si #os 30 = 0.'66
($ = 0.2461'19 in
7op angle -n(-k (angki #oni#al %engan %iame(er an(ara 3 ( $ingga 60 ( a%ala$
n
engt1weddL
12
.. =
-6.0.*o.2.
P0fDPt1
=
7/24/2019 basis mol
112/380
-%-( a%ala$ s-%-( #one roo (er$a%ap garis $oriTon(al.
"Browne and $o!ng% Pers'-')% (*++ , )-/
= %iame(er (angki s(an
($ = #one s$ell ($i#knessS i
0.3306313
= 1.26' %era/a(
Men-h*tun- t*n--* hea' (h
$ = .9'6049 ( 1.963'91133 m
MENEN%"AN D#AME%ER 6#6A 6EN>#$#AN DAN 6EN>EL"ARAN
= I-i% Io ra(e S (3 ,sQ = I-i% %ensi(! S lb,(3
i = %iame(er op(im-m S in#$
%iren#anakan ak(- pengisian selama ' /am.
7/24/2019 basis mol
113/380
erben(-k ker-#-(
$erik
ONVER$#
1Kg,m3 = 0.06243lbm,(3 3,/am) 1 Kg 2.2046 lb
1 $ari 24 /am
1 ( 12 in#$
0.304'm
oses pengisian %an pengosongan)
77:41-43
7/24/2019 basis mol
114/380
l = 3'0 bbl = 133.' (3
43.033m3
e% & E = '
! (eel ?*22
.6 Kg,m3
62.1'43 lb,(3
al 34'
el%e% /oin(
i + (ebal s$ellSin
ses.
7/24/2019 basis mol
115/380
el%e% /oin(
i + (ebal s$ellSin
21,2 21,
2 ,
16
7/24/2019 basis mol
116/380
arS (
n
%(**( , &)./
7/24/2019 basis mol
117/380
pompa 1
D-ngsi : Mengalirkan me(anol %ari (angki me(anol
7-/-an 8eran#angan :
1. Menen(-kan (ipe pompa
2. menen(-kan %imensi pipa
a. Meng$i(-ng kapasi(as %ebi() pemompaan
b. Meng$i(-ng %iame(er op(imal pipa
#. Menen(-kan pemili$an /enis pipa
3. Meng$i(-ng ke$ilangan energi akiba( gesekan
a. Meng$i(-ng ke#epa(an linier I-i%
b. Meng$i(-ng bilangan e!nol%
#. meng$i(-ng pan/ang ek-ialen pipa
%. Meng$i(-ng risi %alam pemipaan
4. Meng$i(-ng (enaga pompa
a. Meng$i(-ng pres-re $ea%
b. Meng$i(-ng po(ensial $ea%
#. Meng$i(-ng elo#i(! $ea%
%. Meng$i(-ng poer pompa
Langka$ 8eran#angan :
1. Menen(-kan (ipe pompa
alam peran#angan ini %ipili$ pompa #en(ri-gal %engan per(imbanga
a. kons(r-ksi se%er$ana
b. Ke#epa(an p-(aran s(abil
#. Dl-i%a %ialirkan pa%a (ekanan !ang -niorm
%. 7i%ak memel-kan areal !ang l-as
e. Bia!a peraa(ann!a paling m-ra$ %iban%ingkan (ipe pompa lain.
4 Menentukan kapa*ta pemompaan (6e,an
7/24/2019 basis mol
118/380
Komponen Q kg,m3) Q . @ M kg,/am)
CH3OH 0.43923 9'3. 9'3.4094234 32.409446
H2O 0.00062499 0.664691 2.201424
>-mla$ 9'4.01'93'06' 329.61664
La/- alir ee%
7/24/2019 basis mol
119/380
0.0009119lb,(.s
U #amp = 0.000344 lb,(.s Kern, fg 14, 1965 : 823
46.434
(Peters,198,
5n(-k komersial s(eel :
46.434
1.3 in 0.040661' m
e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#
e, = 0.0003'
*"nn'ng *r'ct'on *"ctor (* # + 0.03 ($e"n%o&l's '
1 Men-h*tun- tena-a pompa
")enentu%"n &ressure !e"d
a(a :
g = 32.2
g# = 32.194
1 a(m 2116.1
1.1 a(m 2329.91
211.61
4.320196322(.lb,lbm
b) enentu%"n &otens'"l !e"d
%iren#anakan :
1 m 3.2' (
3 m .'4 (
V = 2 m 6.6 (
Potens'"l e"d + 6.63012 (.lb,lbm
c) enentu%"n .eloc't/ !e"d
;e
=
;e
W 2100 berar(i aliran !ang mas-k men-/- (angki pro%-k a%ala$ alira
;e
=
in =
5n(-k e, s ;e
)& maka :
Kons(an(a ke#epa(an grai(asi (,s2
Dak(or konersi& lb (,lbs2
81 =8 #airan %lm (angki
82= 8 mas-k aporiTer
V1 =
V2 =
vD
N
=%&
cg
g5eadpotensiaH =
2
=
P
7/24/2019 basis mol
120/380
Karena ke#epa(an linear #airan (i(ik 1 %an (i(ik 2 rela(i sama& maka :
1 = 2
.eloc't/ e"d + 0 (.lb,lbm
d) r'ct'on e"d (0#
5n(-k komersial s(eel :
&46.4
1.3 in 0.040661' m
e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#e, = 0.0003'
*"nn'ng *r'ct'on *"ctor (* # + 0.03 ($e"n%o&l's '
Menen(-kan 8an/ang ek-ialen :
Komponen L, >-mla$ 8an/ang Le)
8ipa l-r-s 1 12
3 2 11.26
a(e ale& -ll! open 13 1 2.021'1
C$e#k ale& -ll! open 13 1 21.9264$arp e%ge en(ran#e 2' 1 4.06236
k = 0&
$arp e%ge ei( k=1&0) ' 1 .334346
pipa l-r-s er(ikal 1 '.
7o(al 8an/ang ekialen Le) 1'2.424'4'
Ke$ilangan energi karena riksi
($e"n%o&l's s)2)1-6 &)89#
14.69369' (.lb,lbm
e. Menen(-kan 8oer Hea% *A)
*A) = 2.'2'40'(.lb,lbm
Kapasi(as
7/24/2019 basis mol
121/380
iskosi(as kinema(ik = 9.14E*006 (2,s = 0.662'42
ari Dig.14*36 pe(ers p.20& -n(-k kapasi(as 24.2 gallon,mn( %iperole$
20
B$p = Bro%e orse&ower + 0.61322H8
ari Yg 14*3' 8e(ers p.21& -n(-k B$p = 1.3 %iperole$
eZsiensi mo(or = '1
8oer mo(or = 0.96619
ipakai poer mo(or = 4
Reume :
Ko%e : 8*01
D-ngsi : Mengalirkan me(anol %ari (angki me(anol
7ipe : #en(ri-gal
>-mla$ : 1
Kapasi(as : 24.243613gallon,meni(
7enaga 8ompa : 0.61326 H8
Ba$an Kon(r-ksi : oerc'"l 0teel
8ipa : 2 in
O = 2.3' in
= 1.3 in
#$ = '0
X pompa=
nominal
=
motor
B1pPowermotor
=
=550
-* fQWfB1p
7/24/2019 basis mol
122/380
1 kg = 2.2046 lb
1 gr = 0.001 kg
3.31469
0.0000011 /am = 3600 %(k
1 #-( = 9.4'01 gallon
Ba$an bak- :
Me(anol
Kem-rnian .0
0.10
:
(&eters, &)521#
*u-a)
1 m3 = in2
1 #m3
= m3
H2O
7/24/2019 basis mol
123/380
100
#-(,%(k
gallon,mn(
0.194
0.16039 (
0.0204'4'
(,%(k
(2
7/24/2019 basis mol
124/380
"l 496#
)2)1-3 &)88#
7-rb-len
(,s2
lb (,lbs2
lb,(2
lb,(2
7/24/2019 basis mol
125/380
0.16039 (
)2)1-3 &)88#
()
gallon,mn(
f+
7/24/2019 basis mol
126/380
Cs
eisiensi X)
H8
7/24/2019 basis mol
127/380
1 meni( = 60 se#on%
0.00644
1 m = 3.2' (
1 a(m = 2116.11 in = 0.0'3 (
1 Kg,m.s = 0.6919lb,(.s
1 in2= (2
lb,(2
7/24/2019 basis mol
128/380
7/24/2019 basis mol
129/380
7/24/2019 basis mol
130/380
7/24/2019 basis mol
131/380
7/24/2019 basis mol
132/380
pompa 2
D-ngsi : Mengalirkan HCl %ari (angki HCl
7-/-an 8eran#angan :
1. Menen(-kan (ipe pompa
2. menen(-kan %imensi pipa
a. Meng$i(-ng kapasi(as %ebi() pemompaan
b. Meng$i(-ng %iame(er op(imal pipa
#. Menen(-kan pemili$an /enis pipa
3. Meng$i(-ng ke$ilangan energi akiba( gesekan
a. Meng$i(-ng ke#epa(an linier I-i%
b. Meng$i(-ng bilangan e!nol%
#. meng$i(-ng pan/ang ek-ialen pipa
%. Meng$i(-ng risi %alam pemipaan
4. Meng$i(-ng (enaga pompa
a. Meng$i(-ng pres-re $ea%
b. Meng$i(-ng po(ensial $ea%
#. Meng$i(-ng elo#i(! $ea%
%. Meng$i(-ng poer pompa
Langka$ 8eran#angan :
1. Menen(-kan (ipe pompa
alam peran#angan ini %ipili$ pompa #en(ri-gal %engan per(imbanga
a. kons(r-ksi se%er$ana
b. Ke#epa(an p-(aran s(abil
#. Dl-i%a %ialirkan pa%a (ekanan !ang -niorm
%. 7i%ak memel-kan areal !ang l-as
e. Bia!a peraa(ann!a paling m-ra$ %iban%ingkan (ipe pompa lain.
4 Menentukan kapa*ta pemompaan (6e,an
7/24/2019 basis mol
133/380
Komponen Q Q . @ M kg,/am)
HCl 0.49624969 113 6'.1634'144 136.9'6'11
H2O 0.2392321 21.133''01 64.16'1
>-mla$ 10'.29040246 109'.662
La/- alir ee%
7/24/2019 basis mol
134/380
7/24/2019 basis mol
135/380
Karena ke#epa(an linear #airan (i(ik 1 %an (i(ik 2 rela(i sama& maka :
1 = 2
.eloc't/ e"d + 0 (.lb,lbm
d) r'ct'on e"d (0#
5n(-k komersial s(eel :
6120'.321
2.323 in 0.0'9'32319 m
e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#e, = 0.0009'3
*"nn'ng *r'ct'on *"ctor (* # + 0.04 ($e"n%o&l's '
Menen(-kan 8an/ang ek-ialen :
Komponen L, >-mla$ 8an/ang Le)
8ipa l-r-s 1 12
3 2 13.4663
a(e ale& -ll! open 13 1 2.0619
C$e#k ale& -ll! open 13 1 26.0221$arp e%ge en(ran#e 2' 1 .3'62
k = 0&
$arp e%ge ei( k=1&0) ' 1 11.1'222
pipa l-r-s er(ikal 1 '.
7o(al 8an/ang ekialen Le) 12.11336
Ke$ilangan energi karena riksi
($e"n%o&l's s)2)1-6 &)89#
32.93130'9 (.lb,lbm
e. Menen(-kan 8oer Hea% *A)
*A) = 42.406129'3(.lb,lbm
Kapasi(as
7/24/2019 basis mol
136/380
iskosi(as kinema(ik = 1.14E*00 (2,s = 1.0636149
ari Dig.14*36 pe(ers p.20& -n(-k kapasi(as 4.4 gallon,mn( %iperole$
39
B$p = Bro%e orse&ower + 1.140219H8
ari Yg 14*3' 8e(ers p.21& -n(-k B$p = 1. %iperole$
eZsiensi mo(or = '3
8oer mo(or = 1.'241699
ipakai poer mo(or = 4
Reume :
Ko%e : 8*02
D-ngsi : Mengalirkan HCl %ari (angki HCl
7ipe : #en(ri-gal
>-mla$ : 1
Kapasi(as : 49.1'22gallon,meni(
7enaga 8ompa : 1.1402 H8
Ba$an Kon(r-ksi : oerc'"l 0teel
8ipa : 2 1,2 in
O = 2.'' in
= 2.323 in
#$ = '0
X pompa=
nominal
=
motor
B1pPowermotor
=
=550
-* fQWfB1p
7/24/2019 basis mol
137/380
1 kg = 2.2046 lb
1 gr = 0.001 kg
3.31469
0.0000011 /am = 3600 %(k
1 #-( = 9.4'01 gallon
Ba$an bak- :
HCl
Kem-rnian 31.00
6.00
:
(&eters, &)521#
*u-a)
1 m3 = in2
1 #m3
= m3
H2O
7/24/2019 basis mol
138/380
100
#-(,%(k
gallon,mn(
0.2304 (
0.12'0 (
0.023931
(,%(k
(2
7/24/2019 basis mol
139/380
"l 496#
)2)1-3 &)88#
7-rb-len
(,s2
lb (,lbs2
lb,(2
lb,(2
7/24/2019 basis mol
140/380
0.12'0 (
)2)1-3 &)88#
()
gallon,mn(
f+
7/24/2019 basis mol
141/380
Cs
isiensi X)
H8
7/24/2019 basis mol
142/380
1 meni( = 60 se#on%
0.00644
1 m = 3.2' (
1 a(m = 2116.11 in = 0.0'3 (
1 Kg,m.s = 0.6919lb,(.s
1 in2= (2
lb,(2
7/24/2019 basis mol
143/380
7/24/2019 basis mol
144/380
7/24/2019 basis mol
145/380
7/24/2019 basis mol
146/380
7/24/2019 basis mol
147/380
'o!&! *01-
#)g M&)g#'k') m&(')ol "'! '! m&)'" #'
:& Do!be pipe 0xc1anger:##')
*;-
Ko)" O&!' l#"' P')' : *oC- : *K- : *o-:'o!&! ?! 1667626.386 K/'m
1580604.805 B(#/'m;m') m'#k 'o!&! 3927.62 kg/'m
8658.823644 lb/'mK&b#(#
7/24/2019 basis mol
148/380
:enent!;an Temprat!r ;aori;
572 "pers' .'
7/24/2019 basis mol
149/380
N( 688= D
7/24/2019 basis mol
150/380
%& 46.15014496H 16 -Fig&'" ern! hal "#$.
0.105
d. Menghitung ho
7/24/2019 basis mol
151/380
7/24/2019 basis mol
152/380
7/24/2019 basis mol
153/380
0.006809379
774.7118273
k. Menentukan Pressure Drop ditube
"'! Ag.29
7/24/2019 basis mol
154/380
2.94825E005 P
9APORI:ING
Bl')g') !&)ol" *%&- 1847.980136"'! Ag 29 k&!) ""''(A 0.0016 A(2/)2D 0.79 3ern% tabe ) 1a 2
=umlah 8rosses dan ba!!le
L> 9.523714233 A(
#ml'< !o&N , 1 N + L>/B 3.847965347
#ml'< b'AAl&
N 2.847965347= 0.00498 A(
2.41633E007 P
2.97241E005 P
menentukan ?Ps
PP
menentukan P dishell (Ps)
menentukan ?Ps
PP
Menentukan ?Ps total
PP (o('l
3
10
2
-=&.3.*522.10
1-.=3.*NA.G3OP3
+=
3
10
2
-=&.3.*522.10
1-.=3.*NA.G3OP3
+=
7/24/2019 basis mol
155/380
1 kg
1 g!
1 'm 1 #A(
a'2*/
1 m
3
ficient 1 m3
7/24/2019 basis mol
156/380
a' *.4*)/
A(A(
28.2690092 )2
m'll 100
7/24/2019 basis mol
157/380
2*
21.2031188
! %ig&'"
5 K&!)
lb*n+&%+'
7/24/2019 basis mol
158/380
3ern%fig () 1a 2
7/24/2019 basis mol
159/380
ern.
! %ig&'"
5 K&!)
7/24/2019 basis mol
160/380
3ern%fig () 1a 2
7/24/2019 basis mol
161/380
7/24/2019 basis mol
162/380
=2
7/24/2019 basis mol
163/380
2.2046 lb 1 m&)( 60 &o)" 1
0.001 kg 0.006944
35.31467 1 m 3.28 A(0.000001 1 '(m 2116.1
3600 "(k 1 ) 0.083 A(7.480519 g'llo) 1 kk'l 3.968321 B(#
1 KF 0.9478171 B(#
1 )2 A(2
)
2
m3 lbA/A(2
7/24/2019 basis mol
164/380
k&!) .103
(o 200 A(2 o! l&.
7/24/2019 basis mol
165/380
7/24/2019 basis mol
166/380
7/24/2019 basis mol
167/380
7/24/2019 basis mol
168/380
7/24/2019 basis mol
169/380
7/24/2019 basis mol
170/380
7/24/2019 basis mol
171/380
2.42 lb/A(.'m
7/24/2019 basis mol
172/380
7/24/2019 basis mol
173/380
7/24/2019 basis mol
174/380
7/24/2019 basis mol
175/380
7/24/2019 basis mol
176/380
7/24/2019 basis mol
177/380
7/24/2019 basis mol
178/380
7/24/2019 basis mol
179/380
'o!&! *02-
#)g M&)g#'k') HCl "'! '! m&)'" #'
:& Do!be pipe 0xc1anger:##')
*;-
Ko)" O&!' l#"' P')' : *oC- : *K- : *o-:'o!&! ?! 6468516.383 K/'m
6130970.44 B(#/'m;m') m'#k 'o!&! 10785.96 kg/'m
23778.71997 lb/'mK&b#(#
7/24/2019 basis mol
180/380
:enent!;an Temprat!r ;aori;
572 "pers' .'
7/24/2019 basis mol
181/380
N( 1024= D
7/24/2019 basis mol
182/380
%& 31.45671719H 11 -Fig&'" ern! hal "#$.
0.16 3ern%fig () 1a 2& >ol'(l(' (' komo)&)
')' #)(#k &)g#') 1 mol #m') H> HH> H
L
+=
1mx
i
iDi
=
i
i9ixq1
( )( )
( )( )
+
+
=+
5.0
m) 1
U117.211
4.541
11
0XPN
NN
7/24/2019 basis mol
293/380
Komo)&) A *kmol/'m- + PCH3OH 0.245 0.0017 9.5469HCl 0.049 0.0003 12301.0388CH3Cl 105.035 0.7292 1036.0150H2O 38.708 0.2687 1.1609:o('l 144.037 1.000
Komo)&) k kU+ 'lA'CH3OH 0.0126 0.000021 8.2234365137HCl 16.1856 0.005507 10595.7797387032CH3Cl 1.3632 0.994062 892.3950727796H2O 0.0015 0.000411 1
:o('l 1.000
Penen+uan Te*pera+ur de6+ila+
:&m&!'(#! "&(l'( "'! "&)g') (!'l "& o)( (&m&!'(#!. :&k')') o&!'"')gg' ko)(') '"' ko)" 1 '(m:&k')') 1 '(m 101.325:&m&!'(#! :!'l 30.1635975201 C 303.3136Komo)&) Akmol/'m PCH3OH 0.2449918797 0.0022 165.1879
HCl 0.0490032763 0.0004 38930.6785CH3Cl 105.035459983 0.9619 4988.1414H2O 3.870781752 0.0354 31.9521:o('l 109.200 1.000
Komo)&) k +/k 'lA'CH3OH 0.2174 0.0103 5.16985HCl 51.2246 0.0000 1218.40596CH3Cl 6.5633 0.1466 156.11290H2O 0.0420 0.8431 1.00000
:o('l 1.000
Penen+uan Te*pera+ur 4o++o* De6+ila6i
:&m&!'(#! bo((om "&(l' m&!#'k') (&m&!'(#! b#bbl& o)( "'! #)(#km&)&)(#k') (&m&!'(#! o&!' !&bol&! *!&bol&! '!'l-:&k')') 1 '(m 101.325:&m&!'(#! :!'l 100.0020555086 C 373.1520555086Komo)&) Akmol/'m + PCH3OH 2.450163813569E005 7.03321059416E007 2658.0751643188
HCl 5.902890849928E022 0 123619.564695223CH3Cl 2.964984906363E012 0 23332.2912520951H2O 34 8370357679 0 9999992967 759 9987597097
7/24/2019 basis mol
294/380
:o('l 34.8371 1.000
Komo)&) k kU+ 'lA'CH3OH 3.4974673215 2.45984242181E006 3.4974730292HCl 162.6573219674 0 162.6575874182CH3Cl 30.7003832264 0 30.7004333283H2O 0.999998368 0.9999976647 1:o('l 1.000
Menghi+ung Bu*lah Pla+e Mini*u* Pada To+al Re%lu
;)(#k m&)g!
L=
Log
WLog
= LB
HB
HD X
X
X
Nm
WLDLAverageL x ... =
7/24/2019 basis mol
295/380
%m) , 1 0.9043%m) 0.0957
Menen+uan Bu*lah Pla+e Teori+i6 (N +eori+i6)
Nm) 8% m) 0.0957
=&)g') &!'m'')
% T + %m)Y *% %m)-/*%,1-W *N Nm)-/*N,1-
N *Nm) , W-/ *1 W-
T % Y W1.05 0.1005131758 0.00434919 0.80250765661.1 0.1052995175 0.00866071 0.7286357419
1.15 0.1100858592 0.01293506 0.6931379242
1.2 0.1148722009 0.01717270 0.67201555791.25 0.1196585426 0.02137411 0.65766706741.3 0.1244448843 0.02553976 0.6469563344
1.35 0.129231226 0.02967009 0.63837652911.4 0.1340175677 0.03376556 0.6311273522
1.45 0.1388039094 0.03782660 0.6247522951.5 0.1435902511 0.04185364 0.618976578
='mbl T 1.25%&Al#k 0.1244448843
F#ml'< Pl'(& :&o!( 24.94 25
Menen+uan Bu*lah Pla+e a+ual
M&)gg#)'k') OJCo))&llJ o!!&l'(o) Eo 51325 log *'.Z'- *o#lo) >ol.6g '"' #
7/24/2019 basis mol
296/380
CH3OH 2.2'' 2.6E*01 .13E+02
HCl 3.342 0.292 324.6CH3Cl 1.'19 2.E*01 416.2
Aa(er 5.459 3.05@01 647.13
: (o 303.3136 K komo)&) (o kmol/'m +" CH3OH 0.245 0.002 3.95E,00HCl 0.049 0.000 7.6784121084CH3Cl 105.035 0.962 3.3605984571H2O 3.871 0.035 9.9792504193
#ml'< 109.200 1.000
: bo((om 373.1520555086 K komo)&) bo((om kmol/'m +b CH3OH 2.450163813569E005 7.03321059416E007 0.03HCl 5.902890849928E022 0 0.75CH3Cl 2.964984906363E012 0 0.1H2O 34.8370357679 0.9999992967 0.2838
#ml'< 34.8370602695 1
Bu*lah Pla+e a+ual
'>g 1.0105648667 1.0105648667
Eo 50.8517 [
N '(#'l N (&o!( 1 !&bol&! EAA
47.0781057744 ('g& \ 47
Menen+uan Loa6i ;*pan Ma6u
P&!
7/24/2019 basis mol
297/380
Log N!/N 3.112010322N!/N 22.4661632551N'( 1 N! , NN 2.0062123178
F'" #m') m'#k '"' l'(& "'! 12 "''! m&)'!'.
-M2T2: M2D:
1. iame(er 8-n#ak Menara
= eI-k a(io
, = ? 1.6'00'433 kmol,/am
= Lo + 122.9'6 kmol,/am
B&!'( mol&k#l ;' =&(l'(
Komo)&) X Bm X. BmCH3OH 0.0022 32.0420 0.0718865639
HCl 0.0004 36.4610 0.0163617636CH3Cl 0.9619 50.4880 48.5624432199H2O 0.0354 18.0150 0.6385712636
:o('l 1.0000 4.2'262'111
49.2892628111 kg/kmolP 1.2 '(m 121.59 k': 294.000000 K M'k' "&)(' #' "&(l'(
2.0432411242
Menen+uan Den6i+a6
7/24/2019 basis mol
298/380
;)(#k m&)g
7/24/2019 basis mol
299/380
#m :!' ')g ')g "g#)'k') 18='! g. 16.6 P&(&! ] :mm&!ol#m& '!')
0.0106884
'& Dia*e+er olo* 4a@ah
M&)&)(#k') =&)(' ;' C'm#!') Bo((om=&)(' #' 'm#!') "
7/24/2019 basis mol
300/380
B&!'( mol&k#l ;' bo((om
Komo)&) X Bm X. BmCH3OH 0.0000025 32.0420 7.881827088E005HCl 0.0000000 36.4610 0CH3Cl 0.0000000 50.4880 0H2O 1.0000 18.0150 18.0149579299:o('l 1.0000 137.0060 18.0150367482
18.0150367482 kg/kmolP 1 '(m 101.325 k'
: 100.00 373.15
M'k' "&)(' #' bo((om
0.5883881842
Menen+uan Den6i+a6
7/24/2019 basis mol
301/380
="''( "&)(' lI#" 'm#!') 99.49999
=&)(' lI#" bo((om
1792.4932141449
#m :!' ')g ')g "g#)'k') 18='! g. 16.6 P&(&! ] :mm&!ol#m& #' m'km#m
#m 418.083 kmol/'m + 31.131 kg/kmol 1.3774690356
L'# l! >ol#m& '!') 305.091 kmol/'m + 28.8696kg/kmol 0.0000500
='! &!
#'Bm+)+4
"='m&(&!
=
=
v
vL3v6m
-* =
7/24/2019 basis mol
302/380
:o 2.3555085796
Bo((om 0.1485754537
F'" )&( '!&' ')g "&!ol&< &k('! 1.2520420166
;)(#k "'&!'< "o)om&! "'mbl 20[ l#' k&&l#!#
7/24/2019 basis mol
303/380
2.1146373 m
Menghi+ung Pre66uree Drop
Dr7 Pate Pres!re Drop 13.24453574830.76790482497.0062202866m/
2
K.H "'! Ag 16.12 P&(&! ]
7/24/2019 basis mol
304/380
1.2 + 14.7 17.64
15.644264998 0.002760 P'
P P" , P< 17.64 , 0.0026 17.642760 P='m&(&! kolom 1.0836 m 41.633 )llo'bl& (!& D 13750 PFo)( &AA&) E 0.8Co!oo) A'(o! C 0.125 )/10 ('
7/24/2019 basis mol
305/380
21.5190257663)2 2
18.2690257663
BC ! ! 603.625 50.75
47.3477053039)
=&
7/24/2019 basis mol
306/380
7/24/2019 basis mol
307/380
7/24/2019 basis mol
308/380
P'K
P'K
7/24/2019 basis mol
309/380
OC
7/24/2019 basis mol
310/380
N43.969430260231.7276636413
27.941726144
26.077864133624.94292665424.155863220123.559020295823.076380333322.667348376122.3085885292
l'(&
7/24/2019 basis mol
311/380
2.4E*01
3.22E*01
'.10E*02
8.10@02
.+"8.85E033.45E033.23E,003.54E013.60E,00
.+b2.11E08 g&') kol Ag .34 .3
0.00E,00 g&') kol Ag .34 .40.00E,00 g&') kol Ag .34 .52.84E01 g&') kol ('bl& .24 .22.84E01
mN/mR2
('g&
=3''.
7/24/2019 basis mol
312/380
7/24/2019 basis mol
313/380
K
mmHg
ol
7/24/2019 basis mol
314/380
)A(.
7/24/2019 basis mol
315/380
K
Q. @i
.133339'E*00
0
0.430016
4'12
7/24/2019 basis mol
316/380
)
m/
mol
m3/
m3/
7/24/2019 basis mol
317/380
m2m2
mm
mm
kg/
m2
m2
m2
m2
m2
m2
m2
7/24/2019 basis mol
318/380
m
mm
L#b')g
7/24/2019 basis mol
319/380
42.6630515327)
Xo#)g
42.6630515327)
] Xo#)g-
Xo#)g
7/24/2019 basis mol
320/380
)
)
))
7/24/2019 basis mol
321/380
7# = 30 C
7i= 32. 7o=30 C
CA
7#o = 4 C
%ari nera#a massa %an nera#a panas %iperole$ :
ba$an = 3'2.31914'6
panas !g %ib-(-$kan&
7/24/2019 basis mol
322/380
Menghitung density campuran
Fluida panas
Komponen BM Massa Massa
(kmol) (kg)
CH3OH 32.042 0.24 9.
HCl 36.461 0.04 1.'CH3Cl 50.488 10.03 &303.0
18.015 3.'91 6.9
Total !09." 53#".$
P! P/PJ 0.0022152319:! :/:J 0.1601936129T 1
D&
7/24/2019 basis mol
323/380
Total
Mengitung konduktiitas te+mal *ampu+an
7?BLE 2*31 7$ermal Con%-#(ii(! o norgani# an% Organi# Li-i%s A,mK)_
Fluida /anas
Komponen k i i.k
1(m.K) 1(m.K)
CH3OH !.09203 0.00!5 !.59206
HCl ".9$20$ 0.0003 9.%520#
CH3Cl $.5"20$ 0.9#53 $.$520$
3.9#20$ 0.0!30 5.!5206
Total !.00000 $.5020$
Fluida -ingin
Komponen k k i
1(m.K) 1(m.K)
2E+02 1.0E+02 1
Total !
Menentukan 4-
Dari Tabel 8 Kern, Ud 50-125
Ud = !"5
Menghitung Luas Permukaan
2++E50"
Menentukan spesifikasi dan layout tube
-s-nan Triangular
8ass $ell 1
8ass 7-be 2
O-(si%e iame(er = 3/4 in#$ = 0.062
8i(#$ 0.9375 in#$ = 0.09'12BA ;o. 16
nsi%e iame(er = 0.62 in#$ = 0.016666669
Dlo area per (-be = 0.302 0.002092222
Outside sura!e / lin t = 0.163 2'.2692
"nside sura!e / lin t = 0.1623 23.3912
8an/ang = "5 (
H"O
H"O (B)
#tu/ja$.t2.`%
& = '/(Ud)PT* t2
in2 =
(2=
(2=
7/24/2019 basis mol
324/380
Menentukan jumlah tube
+t = &/(,.a-* @rr>502
ari (abel Kern& maka /-mla$ (-be %ib-la(kan men/a%i
;( = #"" (-be
Menentukan diameter shell
ari (abel Kern& /-mla$ (-be %ia(as& %i%apa(kan %iame(er s$ell
s = 3! in#$ ".5#33333333
Koreksi luas permukaan dan Ud
? = ;(.L.a = $033.965
5% =
7/24/2019 basis mol
325/380
7/24/2019 basis mol
326/380
at = +t ? at / n = 0.#6"0
Mengitung ke*epatan massa (8a)
!3%66.369#6!!! l/r.t2
et = .t/ = "6%0.!!353%960#
Mengitung koeisien pe+pindaan panas
H 92 -Fig&'" ern! hal "#$.
0.07 3ern%fig () 1a 2
7/24/2019 basis mol
327/380
N'm' l'( CON=ENDO%Ko"& l'( C01F#ml'< 1 B#'am.(2.0D
B(-,>am.(2.
DDlo area :
aT (2
DMass elo#i(! :
T Kg,/am (2
lb,/am (2
De!nol% ;-mber :
aoLNA t UU=
TmA
Q>D
=U
n
taNa TT
U144
JU=
ta
WT
J=
T
t
DU%& =
7/24/2019 basis mol
352/380
/e+itungan sell side E
ell side Cold luid (Cai+an medium o+ganik)
?s-msi $o = 300
Kern& ')
7 = 2'.6666669
P7 =
ari Yg 1&11 kern& maka %ig-nakan $o = 129
D Fengitung lean O;erall ei!ient
Kern&106)
5# = 119.0'66626
d = 0.0117
d $ini$u$ = 0.001
/+essu+e -+op tue
Kern&14')
ari Yg 2& kern %i%apa( :
Dak(or rik = 0.001'
Bt = 3.2615252895 sia
B(-,>am.(2.0D
D7empera(-r %in%ing (-be
0D
0D
B(-,>am.(2.0D
B(-,/am (20D
Dir( Da#(or
Aa$ t20%/#tu
Aa$ t20%/#tu
(2,in2
( )cccW tT1o1io
1otT
++=
-*
-.*
1o1io
1o1io>c
+
=
DC
DCD>>>>B
U=
s
t
De
LnfPt
10
2
10U22.5=
7/24/2019 basis mol
353/380
pesiYk ol-me s(ea = 0.64
g s(eam = 0.024446142
Kern&14')
P8r = 1.49262 8sia
Kern&14')
BT = 4.7341502895 sia
8ress-re rop s(an%a = 10 8sia
(3,lb
gs
n6
2
4P!
2
=
rT PPPT +=
7/24/2019 basis mol
354/380
= 302
= 302
= 20
= 20
0D0D0D0D
7/24/2019 basis mol
355/380
7/24/2019 basis mol
356/380
kern& 91).0D
7/24/2019 basis mol
357/380
7/24/2019 basis mol
358/380
7/24/2019 basis mol
359/380
pompa 4
D-ngsi : Mengalirkan me(il klori%a ke (angki pro%-k
7-/-an 8eran#angan :
1. Menen(-kan (ipe pompa
2. menen(-kan %imensi pipa
a. Meng$i(-ng kapasi(as %ebi() pemompaan
b. Meng$i(-ng %iame(er op(imal pipa
#. Menen(-kan pemili$an /enis pipa
3. Meng$i(-ng ke$ilangan energi akiba( gesekan
a. Meng$i(-ng ke#epa(an linier I-i%
b. Meng$i(-ng bilangan e!nol%
#. meng$i(-ng pan/ang ek-ialen pipa
%. Meng$i(-ng risi %alam pemipaan
4. Meng$i(-ng (enaga pompa
a. Meng$i(-ng pres-re $ea%
b. Meng$i(-ng po(ensial $ea%
#. Meng$i(-ng elo#i(! $ea%
%. Meng$i(-ng poer pompa
Langka$ 8eran#angan :
1. Menen(-kan (ipe pompa
alam peran#angan ini %ipili$ pompa #en(ri-gal %engan per(imbanga
a. kons(r-ksi se%er$ana
b. Ke#epa(an p-(aran s(abil
#. Dl-i%a %ialirkan pa%a (ekanan !ang -niorm
%. 7i%ak memel-kan areal !ang l-as
e. Bia!a peraa(ann!a paling m-ra$ %iban%ingkan (ipe pompa lain.
4 Menentukan kapa*ta pemompaan (6e,an
7/24/2019 basis mol
360/380
Komponen Q Q . M kg,/am)
CH3OH 0.0014'463 9'3. 1.1432'111 9.'002'1
HCl 0.0003314 113 0.36021019 1.9'690'46
CH3Cl 0.'23' 1 01.09409940 303.030304
H2O 0.012'6 12.'0'09694' 6.93213326
>-mla$ 1.39242 3'2.319
La/- alir ee%
7/24/2019 basis mol
361/380
0.0003 lb,(.s 0.001009
U air = 0.' Kg,m.s U me(il klori%= 0.1'
0.0009119 lb,(.s 0.000120
U #amp = 0.00012941 lb,(.s Kern, fg 14, 1965 : 823
22362.909
(Peters,198,
5n(-k komersial s(eel :
22362.909
1.3 in 0.040661' m
e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#
e, = 0.0003'
*"nn'ng *r'ct'on *"ctor (* # + 0.01 ($e"n%o&l's '
1 Men-h*tun- tena-a pompa
")enentu%"n &ressure !e"d
a(a :
g = 32.2
g# = 32.194
1 a(m 2116.1
1 a(m 2116.1
0 (.lb,lbm
b) enentu%"n &otens'"l !e"d
%iren#anakan :
1 m 3.2' (
2 m 6.6 (
V = 1 m 3.2' (
Potens'"l e"d + 3.2'2606 (.lb,lbm
;e
=
;e
W 2100 berar(i aliran !ang mas-k men-/- (angki pro%-k a%ala$ alira
;e
=
in =
5n(-k e, s ;e
)& maka :
Kons(an(a ke#epa(an grai(asi (,s2
Dak(or konersi& lb (,lbs2
81=8 #airan %lm (angki
82= 8 mas-k (angki
V1 =
V2 =
vDN
=%&
cg
g5eadpotensiaH =
=
P
7/24/2019 basis mol
362/380
c) enentu%"n .eloc't/ !e"d
Karena ke#epa(an linear #airan (i(ik 1 %an (i(ik 2 rela(i sama& maka :
1 = 2
.eloc't/ e"d + 0 (.lb,lbm
d) r'ct'on e"d (0#
5n(-k komersial s(eel :
223&62.9
1.3 in 0.040661' m
e = 0.000046 m ($e"n%o&l's 'g)2)1-3 &)88#
e, = 0.0003'
*"nn'ng *r'ct'on *"ctor (* # + 0.01 ($e"n%o&l's '
Menen(-kan 8an/ang ek-ialen :
Komponen L, >-mla$ 8an/ang Le)
8ipa l-r-s 1 12
3 1 .6329a(e ale& -ll! open 13 1 2.021'1
C$e#k ale& -ll! open 13 1 21.9264
$arp e%ge en(ran#e 2' 1 4.06236
k = 0&
$arp e%ge ei( k=1&0) ' 1 .334346
pipa l-r-s er(ikal 1 '.
7o(al 8an/ang ekialen Le) 196.9203
Ke$ilangan energi karena riksi
($e"n%o&l's s)2)1-6 &)89#
6.32'9''1 (.lb,lbm
e. Menen(-kan 8oer Hea% *A)
;e
=
in =
Elbo 0o
* =
=cg
6ad6eocit7He
2
2
cg
v
D
Lff
24
2
=
adveocit71eeadpotensia1adpress!re1eWf ++=
7/24/2019 basis mol
363/380
*A) = .'163'46(.lb,lbm
Kapasi(as -mla$ : 1
Kapasi(as : 2'.43'393gallon,meni(
7enaga 8ompa : 0.2'1331 H8
Ba$an Kon(r-ksi : oerc'"l 0teel
8ipa : 2 in
O = 2.3' in
= 1.3 in
#$ = '0
X pompa=
nominal
=
motor
B1pPowermotor
=
=550
-* fQWfB1p
7/24/2019 basis mol
364/380
1 kg = 2.2046 lb
1 gr = 0.001 kg
3.31469
0.0000011 /am = 3600 %(k
1 #-( = 9.4'01 gallon
Ba$an bak- :
Me(anol
Kem-rnian .0
0.10
:
(&eters, &)521#
*u-a)
1 m3 = in2
1 #m3
= m3
H2O
7/24/2019 basis mol
365/380
100
#-(,%(k
gallon,mn(
0.194 (
0.16039 (
0.0204'4'
(,%(k
Kg,m.s
(2
7/24/2019 basis mol
366/380
lb,(.s
Kg,m.s
lb,(.s
"l 496#
)2)1-3 &)94#
7-rb-len
(,s2
lb (,lbs2
lb,(2
lb,(2
7/24/2019 basis mol
367/380
0.16039 (
)2)1-3 &)94#
()
f+
7/24/2019 basis mol
368/380
gallon,mn(
Cs
isiensi X)
H8
7/24/2019 basis mol
369/380
1 meni( = 60 se#on%
0.00644
1 m = 3.2' (
1 a(m = 2116.11 in = 0.0'3 (
1 Kg,m.s = 0.6919lb,(.s
1 in2= (2
lb,(2
7/24/2019 basis mol
370/380
7/24/2019 basis mol
371/380
7/24/2019 basis mol
372/380
7/24/2019 basis mol
373/380
7/24/2019 basis mol
374/380
7ipe (angki silin%er (egak %engan %asar %a(ar %an a(asn!a berbe
%asar pemili$an 5m-mn!a %ig-nakan -n(-k li-i% pa%a (ekanan a(mosp$eri
8er$i(-ngan :
MEN>H#%"N> DEN$#%A$ CAM6"RAN:
komponen kmol,/am massa Kg,/am) Q Kg,m3) ol-me m3,/am)
CH3OH 0.2441 9.'002'1 9'3. 0.010014
HCl 0.040033 1.9'690'461 113 0.0014'
CH3Cl 10.0346 303.03030362 1 .9662
H2O 3.'909'1' 6.932133262 0.0900'3
10.20024 3'2.31914 .'9926
ensi(as #amp-ran = 1.'01412''6 Kg,m3
9.1934'2206lb,(3
%iren#anakan pen!impanan -n(-k 9 $ari %engan b-a$ (angki mem-%a$kan proses p
se$ingga ol-me masing*masing:
pen!impanan = 9 $ari
/-mla$ (angki = b-a$
keb-(-$an HCl = 3'2.31914 Kg,/am selama 1 $ari
04243.06142 Kg selama 9 $ari
477317128322 lb
Bo)ume metano) pa'a tan-k*:
ol-me (angki = 34'69.46261193 (3
as-msi ba$an isi '0 ol-me (angki ak(or keamanan)
se$ingga ol-me (angki = 41'40.134091' (3
'36'.11026'144(3
MENEN%"AN D#MEN$# %AN>#
rasio H, = 3,'
= iame(er Brownel,1
H = 7inggi 7angki
R = 3.1413
H = 11.442'64 (
3.4'99'm
HDvo!me ...4
1 2=
7/24/2019 basis mol
375/380
= 30.1430 (
.3009601m
%ig-nakan %iame(er 3 ( %an (inggi 16 ( &maka
MENEN%"AN !"MLAH 6LA%E DAN %E&AL $HELL
"Browne and $o!ng% pers &'()%(*++ , -./
( = (ebal s$ell S in
8 = (ekanan in(ernal S psi
% = insi%e %iame(er S in
C = ak(or korosi S in 1,' in)
E = ak(or pengelasan& %ig-nakan %o-ble el%
= s(ress alloable& ba$an kons(r-ksi Carbon
ra%e C& maka = 1260 psi
8 = (ekanan in(ernal S 8si
= %ensi(as air pa%a s-$- 30 Cel#i-s =H =(inggi #o-rseS (
Cou,e 4
H = 16 (
(1 = 0.214' in
%ipili$ (ebal s$ell s(an%ar = 0.2' in BronellS
meng$i(-ng pan/ang pla(e
%iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al el%e
/arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (
L = pan/ang (iap pla(e S (
% =%iame(er %alam (ang
n = /-mla$ pla(e
el% leng($ = n alloable el%e% /oin(
L1 = 10.'''4 in
/a%i = pan/ang pla(e = 10.'''3'3' in
lebar pla(e = ' (
(ebal pla(e = 0.2'
Cou,e 2
H = 24 ( * ' (
(2 = 0.1'40129
%iren#anakan akan mengg-nakan s$ell pla(e %engan 6 in ' () butt-weldes courses.
C0f
dPt +=
..2
.
144
-1* =
HP
n
engt1weddL
12
.. =
7/24/2019 basis mol
376/380
%ipili$ (ebal s$ell s(an%ar = 0.1 in
meng$i(-ng pan/ang pla(e
%iren#anakan mengg-nakan 10 pla(e -n(-k (iap #o-rse& alloan#e -n(-k er(i#al el%e
/arak samb-ng an(ar pla(e) = ,32 in %an lebar = ' (
L = pan/ang (iap pla(e S (
% =%iame(er %alam (angn = /-mla$ pla(e
el% leng($ = n alloable el%e% /oin(
L1 = 10.'92' in
/a%i = pan/ang pla(e = 10.'929644in
lebar pla(e = ' (
(ebal pla(e = 0.1
MENEN%"AN %O6 AN>LE "N%" CON#CAL ROOF
bila %ig-nakan 10 pla(e (iap angle& maka pan/ang (iap angle :
L = 10.093 (
"MENEN%"AN %E&AL DAN %#N>># HEAD %AN>#
"Browne and $o!ng% Pers')'(.-% (*++ , ((2/
(ekanan pen!impanan = 1 a(m = 14.9 psi
%an %iambil ak(or keamanan 10 maka:
8 = 16.19 8si #os 30 = 0.'66
7op angle -n(-k (angki #oni#al %engan %iame(er an(ara 3 ( $ingga 60 ( a%ala$ 21,2
n
engt1wedd
L 12
.. =
-6.0.*o.2
.
P0f
DPt1
=
7/24/2019 basis mol
377/380
($ = 0.36001 in
-%-( a%ala$ s-%-( #one roo (er$a%ap garis $oriTon(al.
"Browne and $o!ng% Pers'-')% (*++ , )-/
= %iame(er (angki s(an
($ = #one s$ell ($i#knessS i
0.2230004
= 12.'' %era/a(
Men-h*tun- t*n--* hea' (h
$ = 3.02064 (
MENEN%"AN D#AME%ER 6#6A 6EN>#$#AN DAN 6EN>EL"ARAN
= I-i% Io ra(e S (3 ,s
Q = I-i% %ensi(! S lb,(3
i = %iame(er op(im-m S in#$
%iren#anakan ak(- pengisian selama ' /am.
7/24/2019 basis mol
378/380
(-k ker-#-(
ONVER$#
1Kg,m3 = 0.06243lbm,(31 Kg 2.2046 lb
1 $ari 24 /am
1 ( 12 in#$
0.304'm
engisian %an pengosongan)
77:41-43
7/24/2019 basis mol
379/380
l = 2940 bbl = 133.' (3
43.033m3
e% & E = '
(eel ?*2'3
.6 Kg,m3
62.1'43 lb,(3
al 34'
% /oin(
i + (ebal s$ellSin
7/24/2019 basis mol
380/380
% /oin(
i + (ebal s$ellSin
21,2 ,
16