UNIVERSITI TEKNOLOGI MARAFAKULTI KEJURUTERAAN KIMIAPROCESS
ENGINEERING LABORATORY II(CPE554)
Name: NURUL AIN BINTI ZULKIFLEEstudent id: 2013452866Group :
4Experiment: Shell and tube heat exchangerdate performed: 11TH
march 2015SEMESTER: 4programme / code: eh2214a / CPE554submit to :
ms habsah alwi
No.TitleAllocated Marks (%)Marks
1Abstract/Summary5
2Introduction5
3Aims5
4Theory5
5Apparatus5
6Methodology/Procedure10
7Results10
8Calculations10
9Discussion 20
10Conclusion10
11Recommendations5
12Reference5
13Appendix5
TOTAL MARKS100
Remarks:
70
Checked by:
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Date:
Rechecked by:
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ABSTRACTThe objective of this experiment is to evaluate and
study the function as well as the performance of shell and tube
heat exchanger at various operating conditions. The conditions
are:1) Heat Load and Heat Balance, LMTD, Overall Heat Transfer
Coefficient (U)2) Turbulent/Laminar Flow, Reynolds Number Shell
Side, Reynolds Number Tube Side3) Heat Transfer Coefficients 4)
Pressure Drop, Shell Side, Tube Side
[EDIT]From the data collected, the configuration of Shell and
Tube heat exchanger in counter current flow has a higher
effectiveness than the co-current flow.
INTRODUCTIONA heat exchanger is equipment built for
efficientheat transferthat takes place between two fluids that
enter and exit at different temperatures. The media may be
separated by a solid wall to prevent mixing or they may be in
direct contact. The main function of heat exchanger is to either
remove heat from a hot fluid or to add heat to the cold fluid. They
are widely used in space heating, refrigeration, air-conditioning,
power plants, chemical plants, petrochemical plants, petroleum
refineries, natural gas processing, and sewage treatment. The
classic example of a heat exchanger is found in an internal
combustion engine in which a circulating fluid known as engine
coolant flows through radiator coils and air flows past the coils,
which cools the coolant and heats the incoming air.
The direction of fluid motion inside the heat exchanger can
normally categorised as parallel flow, counter flow and cross flow.
In this experiment, only parallel flow and counter flow is
highlighted. For parallel flow, also known as co-current flow, both
the hot and cold fluids flow in the same direction. Both the fluids
enter and exit the heat exchanger on the same ends. For counter
flow, both the hot and cold fluids flow in the opposite direction.
Both the fluids enter and exit the heat exchanger on the opposite
ends. In this experiment, shell and tube heat exchanger is focused
on.
AIMSTo evaluate and study the performance of the Shell and Tube
Heat Exchanger at various operating conditions. The conditions are
1) Heat Load and Heat Balance, LMTD, Overall Heat Transfer
Coefficient (U)2) Turbulent/Laminar Flow, Reynolds Number Shell
Side, Reynolds Number Tube Side3) Heat Transfer Coefficients 4)
Pressure Drop, Shell Side, Tube Side
THEORYHeat exchangers are devices designed to transfer heat from
one fluid to another without the fluids coming into contact.
Shell-and-tube heat exchanger is the most common type of heat
exchanger in industrial applications. They contain a large number
of tubes packed in a shell with their axes parallel to that of the
shell. Heat transfer takes place as one fluid flows inside the
tubes while the other fluid flows outside the tubes through the
shell.
Figure 1: a) Co-current Flow and b) Counter Current Flow
a) Co-current (Parallel) flowThe flow of the hot and the cold
fluid is taking place in the same direction in this case. As the
graph shown in Figure 1a, the temperature difference between the
hot and the cold fluid keeps on decreasing from one end to the
other.
b) Counter current flowThe hot fluid enters from one end of the
exchanger and the cold from the opposite end. This results in
nearly constant temperature difference between the hot and the cold
fluid. This is a significant aspect and makes counter current
exchangers preferable over co-current exchangers.
Shell and Tube Heat Exchangers Construction
Figure 2: Construction of Shell and Tube Heat Exchanger
a) TubesThe tubes provide the heat transfer area in a shell and
tube heat exchanger. The tubes in a shell and tube heat exchanger
are arranged in various arrangements. They are enclosed by a shell
around them. They are available in various sizes and shapes
according to B.W.G (Birmingham wire gauge) system. The selection of
wall thickness of tube depends on maximum operating pressure and
corrosion characteristics.
b) Tube PitchVarious aspects have to be kept in mind while
designing a shell and heat tube exchanger. The tubes cannot be made
very close to each other as that would then leave very less amount
of metal between the drilled tubes holes in tube sheets attached at
the ends of the exchanger. And if the space between the tubes is
very high, it would result in less surface area which in turn,
would affect the efficiency of the exchanger. Hence, an optimum
distance should be maintained. The shortest distance between
centers of two adjacent tubes is called the tube pitch, should not
be less than 1.25 times the tube diameter.
c) Shell As shown in the Figure 2, the shell is the outer casing
of the heat exchanger. One fluid flows between the outer wall of
the heat exchanger and inner wall of the shell while the other
flows inside the tube. Shell has a circular cross section and
selection of material of the shell depends upon the corrosiveness
of the fluid and the working temperature and pressure. Carbon steel
is a common material for the shell under moderate working
conditions.
d) BafflesThese are panels responsible for obstructing and
redirecting the flow of fluid in the shell side of an exchanger.
They are situated normal to the walls of the shell and force the
liquid to flow at right angles to the axis of the tubes. This
increases turbulence resulting in greater heat transfer. Also, the
baffles help in keeping the tubes from sagging and increase the
strength of the tubes by preventing their vibration.
Heat BalanceFor a parallel-flow shell and tube heat exchanger
with one tube pass and one shell pass shown in Figure 1a, the heat
balance is given as: Similarly, for the counterflow shell and tube
heat exchanger with one tube pass and one shell pass, the heat
balance is given as: where,= mass flowrate of cold fluid in the
tube= mass flowrate of hot fluid in the shell= specific heat of
cold fluid in the tube= specific heat of hot fluid in the shell=
temperature of cold fluid entering/leaving the tube= temperature of
hot fluid entering/leaving the shell= heat exchange rate between
fluid
Heat TransferThe general equation for heat transfer across the
tube surface in a shell and tube heat exchanger is given by:
where,= outside area of the tube= inside area of the tube= mean
temperature difference= overall heat transfer coefficient based on
the outside area of the tube= overall heat transfer coefficient
based on the inside area of the tube
The coefficients and are given by:
and
where,= outside fluid film coefficient= inside fluid film
coefficient = outside dirt coefficient (fouling factor)= inside
dirt coefficient= thermal conductivity of the tube wall material=
tube outside diameter= tube inside diameter
The mean temperature difference for both parallel and
counterflow shell and tube heat exchanger with single shell pass
and single tube pass is normally expressed in terms of log-mean
temperature difference (LMTD)
Figure 3: Temperature profile for a 1:2 heat exchanger
For a more complex heat exchanger, such as 1:2 heat exchanger in
Figure 3, an estimate of the true temperature difference is given
by:
where is the temperature correction factor as a function of two
dimensionless temperature ratios R and S:
Having calculated R and S, then is determined from the standard
correction factor figures in Figure 6.
Tube-side Heat-transfer Coefficient, For turbulent flow,
Sieder-Tate equation can be used:
where,= Reynolds Number = = = Nusselt Number = = Prandtl Number
= = equivalent (or hydraulic) diameter (m)= 4 (cross-sectional area
of flow)/wetted perimeter= mass velocity, mass flow per unit area=
fluid viscosity of bulk fluid temperature = fluid viscosity at the
wall= fluid density = fluid velocity in tube = fluid specific heat,
heat capacity= 0.023 for non-viscous liquids= 0.027 for viscous
liquids=Fluid thermal conductivity
For laminar flow (Re < 2000), the following correlation is
used:
where,L = the tube length (m)
Tube-side Pressure Drop, The tube-side pressure drop is given
by:
where,= tube-side pressure drop= number of tube-side passes=
tube dimensionless friction factor in Figure 8= length of one tube,
(m)= tube-side velocity= 0.25 for laminar, Re < 2100= 0.14 for
turbulent, Re > 2100
Shell-side Heat-transfer Coefficient, (Kerns Method)In order to
determine the heat transfer coefficient for fluid film in shell,
first calculate the cross-sectional area of flow for hypothetical
row of tubes of the shell as follows:
where,= tube outside diameter (m)= tube pitch (m)= shell inside
diameter (m)= distance between baffle (m)
Then, the shell-side mass velocity, and linear velocity, are
calculated as follows:
where,= Fluid flowrate on the shell-side = shell-side fluid
density
The shell equivalent diameter, is given by:= = (For square pitch
arrangement)
= = (For equilateral triangular pitch arrangement)
Thus, Reynolds number in shell is given by:= =
Baffle cut, , is used to specify the dimensions of a segmental
baffle. It is the height of the segment removed to form the baffle,
expressed as a percentage of the baffle disc diameter.
Using this Reynolds number and given value, the heat transfer
factor, value is determined from Figure 9. Then, the heat transfer
coefficient for fluid film in shell is calculated from:
Shell-side Pressure Drop, (Kerns Method)The shell-side pressure
drop is given by:
where,= shell pressure drop= shell dimensionless friction factor
in Figure 10= distance between baffle (m)= shell-side velocity
Shell-side Heat-transfer Coefficient, (Bells Method)The
shell-side heat transfer coefficient is given by:
where,= heat transfer coefficient calculated for cross-flow over
an ideal tube bank, no leakage or by-passing= correction factor to
allow for the effect of the number of vertical tube rows= window
effect correction factor= by-pass stream correction factor= leakage
correction factor
The ideal cross-flow heat transfer coefficient is given by:
where,= =
Heat-transfer coefficient for an ideal cross-flow tube banks can
be calculated using the heat transfer factors, from Figure 11.
The correction factor is determined as follows:a. For Re >
2000, turbulent, take from Figure 12b. For Re > 100 to 2000,
transition region, take c. For Re < 100, laminar region,
where, numbers of rows crossed in series from end to end of the
shell.
The window correction factor is plotted against , in Figure 13
where is the ratio of the numbers of tubes in the window zones to
the total number in the bundle.
The by-pass correction factor is for /2
where,= 1.5 for laminar flow, Re < 100= 1.35 for transitional
and turbulent flow Re > 100= clearance area between the bundle
and the shell= maximum area for cross-flow= number of sealing
strips encountered by the by-pass streamin the cross-flow zone= the
number of constrictions, tube rows, encountered in thecross-flow
section
If there is no sealing strips used, is obtained from Figure
14.The leakage correction factor is,
where,= a factor obtained from Figure 15= tube-to-baffle
clearance area, per baffle= shell-to-baffle clearance area, per
baffle= total leakage area,
Shell-side Pressure Drop, (Bells Method)The total shell-side
pressure drop is the sum of pressure drop in cross-flow and window
zones, determined separately. The pressure drop in the cross-flow
zones between the baffle tips is calculated from the correlations
for ideal tube banks, and corrected for leakage and bypassing.
where,= pressure drop calculated for an equivalent ideal tube
bank= number of tube rows crossed (in the cross-flow region)=
shell-side velocity, based on the clearance area at the bundle
equator= friction factor from Figure 16 for Re calculated with us=
by-pass correction factor= leakage correction factor
Calculate with for laminar region, Re < 100 and for
transition and turbulent region, Re > 100. If no sealing strips
used, take from Figure 17
Calculate from Equation 22 taking from Figure 18
The window-zone pressure drop is,
where,= geometric mean velocity = = velocity in the window zone
= = shell-side fluid mass flow= number of restrictions for
cross-flow in window zone, approximately equal to the number of
tube rows
The end-zone pressure drop is,
Thus, the total shell-side pressure drop is the sum of pressure
drops over all the zones in series from inlet to outlet:= 2(end
zones) + ()(crossflow zones) + (window zones)=
where,
Shell and Bundle GeometryThe shell and bundle geometry described
below shall be used for calculating the correction factors
above.
Where,= baffle cut height= , where is the baffle cut as a
fraction= height from the baffle chord to the top of the tube
bundle= bundle cut = = angle subtended by the baffle chord (rads)=
bundle diameter
Subsequently,= = =
where,= vertical tube pitch= for square pitch= 0.87 for
equilateral triangular pitch
The number of tubes in a window zone is given by:
where can be obtained from Figure 20, for the appropriate bundle
cut, .
The number of tubes in a cross-flow zone Nc is given by:
and
where is obtained from Figure 20 for the appropriate baffle cut,
.
where is the diametrical tube-to-baffle clearance, typically 0.8
mm.
where is the baffle-to-shell clearance and can be obtained from
Figure 20 for the appropriate baffle cut, Bc.
where is the baffle spacing.
APPARATUS1) Shell and Tube Heat Exchanger2) Stopwatch
Figure 4: Heat Exchanger Training Apparatus (Model: HE158C)
Figure 5: Schematic Diagram for Heat Exchanger Training
Apparatus
PROCEDUREGeneral Start-up 1) A quick inspection is performed to
make sure that the equipment is in a proper working condition.2)
All valves are ensured to be initially closed, except V1 and V12.3)
Hot water tank is filled up via a water supply hose connected to
valve V27. The valve is closed once the tank is full.4) The
cold-water tank is filled up by opening valve V28 and the opened
valve is left for continues water supply.5) A drain hose is
connected to the cold water drain point.6) The main power is
switched on. The heater is switched on for the hot water tank and
the temperature controller is set to 50C.7) The water temperature
is allowed in the hot water tank to reach the set-point.8) The
equipment is now ready to be run.
General Shut-down 1) Heater is switched off. Wait until the hot
water temperature drops below 40C.2) Pump P1 and pump P2 are
switched off.3) Main power switched off.4) All water in the process
lines is drained off. Water in the hot and cold water tanks are
retained for next laboratory session.5) All valves are closed.
Experiment A: Counter-Current Shell & Tube Heat Exchanger1)
General start-up procedures is performed.2) The valves are switched
to counter-current Shell & Tube Heat Exchanger arrangement.3)
Pumps P1 and P2 are switched on.4) Valves V3 and V14 are opened and
adjusted to obtain the desired flowrates for hot water and cold
water streams, respectively.5) The system is allowed to reach
steady state for 10 minutes.6) FT1, FT2, TT1, TT2, TT3 and TT4 is
recorded.7) The pressure drop measurements are recorded for
shell-side and tube-side for pressure drop studies.8) Steps 4 to 7
is repeated for different combinations of flowrate FT1 and FT2 as
in the results sheet.9) Pumps P1 and P2 are switched off after the
completion of experiment.10) The next experiment is proceeded.
Experiment B: Co-Current Shell & Tube Heat Exchanger1) The
valves are switched to co-current Shell & Tube Heat Exchanger
arrangement2) Pumps P1 and P2 are switched on.3) The valves are
switched to counter-current and the air is bled with high water
flowrate if there is air trap in the shell-side. Then the valves
are switched position back to co-current position.4) Valves V3 and
V14 are opened and adjusted to obtain the desired flowrates for hot
water and cold water streams, respectively.5) The system is allowed
to reach steady state for 10 minutes.6) FT1, FT2, TT1, TT2, TT3 and
TT4 is recorded.7) The pressure drop measurements are recorded for
shell-side and tube-side for pressure drop studies.8) Steps 5 to 8
are repeated for different combinations of flowrate FT1 and FT2 as
in the results sheet.9) Pumps P1 and P2 are switched off after the
completion of experiment.10) Shut-down the equipment is
proceeded.
RESULTSExperiment A: Counter-Current Shell & Tube Heat
ExchangerFI 1 (LPM)FI 2 (LPM)TT1 (C)TT2 (C)TT3 (C)TT4 (C)DPT1
(mmH2O)DPT1 (mmH2O)
21030.829.238.149.3193-5
41031.529.243.148.8195-5
61032.229.344.049.2191-5
81033.329.744.849.5192-5
101034.029.845.148.7191-5
FI 1 (LPM)FI 2 (LPM)TT1 (C)TT2 (C)TT3 (C)TT4 (C)DPT1 (mmH2O)DPT1
(mmH2O)
10241.429.947.549.16.0-5
10437.930.246.649.169.0-5
10635.429.245.649.0126-5
10834.028.944.948.9214-5
101033.228.944.648.9377-5
HOT FLUID (TUBE)TEST12345
VOLUMETRIC FLOWRATE (LPM)1010101010
MASS FLOW RATE(kg/s)0.16470.16470.16470.16470.1647
HEAT TRANSFER RATE(J/s)3162.991925.01100.17825.13618.85
COLD FLUID (SHELL)TEST12345
VOLUMETRIC FLOWRATE(LPM)2.004.006.008.0010.00
MASS FLOWRATE(kg/s)0.033190.06640.09960.13280.1659
HEAT TRANSFER RATE(J/s)111.06222.13416.49499.79832.97
TEST12345
T LOG MEAN, )17.9419.5819.5019.8519.15
HEAT LOSS(W)3051.931702.87683.68325.34235252
EFFICIENCY(%)3.5111.5437.8660.57134.60
OVERALL HEAT TRANSFER COEFFICIENTTEST12345
Total exchange area(0.050.050.050.050.05
Overall heat transfer coefficient
3526.191966.291128.38831.36646.32
TUBE SIDETEST12345
CROSS SECTION AREA(0.0005570.0005570.0005570.0005570.000557
MASS VELOCITY
295.69295.69295.69295.69295.69
LINEAR VELOCITY(m/s)0.29920.29920.29920.29920.2992
REYNOLDS NUMBER14337.7914337.7914337.7914337.7914337.79
PRANDTL NUMBER3.563.563.563.563.56
NUSELT NUMBER73.9473.9473.9473.9473.94
TYPE OF FLOWturbulentturbulentturbulentturbulentturbulent
STANTON NUMBER0.001450.001450.001450.001450.00145
HEAT TRANSFER FACTOR, 0.003390.003390.003390.003390.00339
TUBE COEFFICIENT,
1786.331786.331786.331786.331786.33
SHELL SIDETEST12345
CROSS FLOW AREA(0.00480.00480.00480.00480.0048
MASS VELOCITY
6.9213.8320.7527.6734.56
LINEAR VELOCITY(m/s)0.006950.013890.020840.02780.03471
EQUIVALENT DIAMETER(m)0.05160.05160.05160.05160.0516
REYNOLDS NUMBER445.76891.261337.201783.152227.17
PRANDTL NUMBER5.445.445.445.445.44
NUSELT NUMBER5.299.2112.7516.0519.17
TYPE OF FLOWlaminarlaminarlaminarlaminarLaminar
STANTON NUMBER0.002180.001900.0017520.001650.00158
HEAT TRANSFER FACTOR, 0.006790.005910.0054510.0051330.00492
SHELL COEFFICIENT,
63.14427.62609.79855.541068.58
Experiment B: Co-Current Shell & Tube Heat ExchangerFI 1
(LPM)FI 2 (LPM)TT1 (C)TT2 (C)TT3 (C)TT4 (C)DPT1 (mmH2O)DPT1
(mmH2O)
21029.931.438.649.5679604
41029.931.843.248.8678601
61030.032.744.349.2675583
81030.133.745.450.0678530
101030.234.045.449.4676527
FI 1 (LPM)FI 2 (LPM)TT1 (C)TT2 (C)TT3 (C)TT4 (C)DPT1 (mmH2O)DPT1
(mmH2O)
10230.338.147.248.723526
10430.436.046.648.97524
10630.334.446.048.9653524
10830.134.045.648.7670523
101030.033.745.249.0712530
HOT FLUID (TUBE)TEST12345
VOLUMETRIC FLOWRATE (LPM)1010101010
MASS FLOW RATE(kg/s)0.16470.16470.16470.16470.1647
HEAT TRANSFER RATE(J/s)3162.991925.01100.17825.13618.85
COLD FLUID (SHELL)TEST12345
VOLUMETRIC FLOWRATE(LPM)2.004.006.008.0010.00
MASS FLOWRATE(kg/s)0.033190.06640.09960.13280.1659
HEAT TRANSFER RATE(J/s)111.06222.13416.49499.79832.97
TEST12345
T LOG MEAN, )17.9419.5819.5019.8519.15
HEAT LOSS(W)3051.931702.87683.68325.34235252
EFFICIENCY(%)3.5111.5437.8660.57134.60
OVERALL HEAT TRANSFER COEFFICIENTTEST12345
Total exchange area(0.050.050.050.050.05
Overall heat transfer coefficient
3526.191966.291128.38831.36646.32
TUBE SIDETEST12345
CROSS SECTION AREA(0.0005570.0005570.0005570.0005570.000557
MASS VELOCITY
295.69295.69295.69295.69295.69
LINEAR VELOCITY(m/s)0.29920.29920.29920.29920.2992
REYNOLDS NUMBER14337.7914337.7914337.7914337.7914337.79
PRANDTL NUMBER3.563.563.563.563.56
NUSELT NUMBER73.9473.9473.9473.9473.94
TYPE OF FLOWturbulentturbulentturbulentturbulentturbulent
STANTON NUMBER0.001450.001450.001450.001450.00145
HEAT TRANSFER FACTOR, 0.003390.003390.003390.003390.00339
TUBE COEFFICIENT,
1786.331786.331786.331786.331786.33
SHELL SIDETEST12345
CROSS FLOW AREA(0.00480.00480.00480.00480.0048
MASS VELOCITY
6.9213.8320.7527.6734.56
LINEAR VELOCITY(m/s)0.006950.013890.020840.02780.03471
EQUIVALENT DIAMETER(m)0.05160.05160.05160.05160.0516
REYNOLDS NUMBER445.76891.261337.201783.152227.17
PRANDTL NUMBER5.445.445.445.445.44
NUSELT NUMBER5.299.2112.7516.0519.17
TYPE OF FLOWlaminarlaminarlaminarlaminarLaminar
STANTON NUMBER0.002180.001900.0017520.001650.00158
HEAT TRANSFER FACTOR, 0.006790.005910.0054510.0051330.00492
SHELL COEFFICIENT,
63.14427.62609.79855.541068.58
Temperature Profile for counter-current Shell and Tube Heat
ExchangerHeat transfer Coefficient Study
CALCULATIONSThe specific results for this experiment allow us to
determine the heat transfers, heat losses, heat transfer
coefficient and LMTD values.Tube O.D. : 9.53 mmTube I.D. : 7.75
mmTube Length : 500 mmTube Count : 10 (single pass)Tube Pitch : 18
mmTube arrangement: TriangleShell O.D.: 100 mmShell I.D. : 85
mmBaffle Count: 8Baffle Cut : 20 %Baffle Distance : 50 mmMaterial
of Construction: 316 L Stainless Steel/Borosilicate Glass
Hot waterCold water
Density: 988.18 kg/m3Density: 995.67 kg/m3
Heat capacity: 4175.00 J/kg.KHeat capacity: 4183.00 J/kg.K
Thermal cond: 0.6436 W/m.KThermal cond: 0.6155 W/m.K
Viscosity: 0.0005494 Pa.sViscosity:0.0008007 Pa.s
Experiment A: Counter-Current Shell & Tube Heat
Exchanger
[Fixed Cold Water Flow Rate 10 LPM]1) Calculations of heat
transfer and heat lostThe heat transfers of both hot and cold water
are both calculated using the heat balance equation.
Heat transfer rate for hot water i) = 220.03 W
ii) 632.60 W
iii) = 1196.44 W
iv) = 1980.31 W
v) = 2887.96 W
Heat transfer rate for cold water i) = 7774.46 W
ii) = 3956.64 W
iii) = 3609.57 W
iv) = 3262.50 W
v) = 2498.93 W
Heat Lost Rate = i) ii) iii) iv) v)
Efficiency = i) ii) iii) iv) v)
2) Calculations of Log Mean Temperature Differencei) = = =
ii) = =
iii) = =
iv) = =
v) = =
3) Calculation of the tube and shell heat transfer coefficients
by Kerns methodFor 1-shell pass; 1-tube pass,
Heat transfer coefficient at Tube side:Cross Flow Area, A= =
=
Total cross Flow Area, = 0.0000472 number of tubes= 0.0000472
10= 0.000472 m2
Mass velocity, = = =
Linear Velocity, = = =
Reynolds No, Re= = = (Turbulent Flow)
Prandtl No, Pr= = = 5.44
Tube Side Coefficient, hi= = =
Heat transfer coefficient at Shell side:Cross Flow Area, A= =
=
Mass velocity, = = =
Linear Velocity, = = =
Equivalent Diameter, = = =
Reynolds No, Re= = = (Laminar Flow)
Prandtl No, Pr= = = 5.44Shell Side Coefficient, hi= = =
Overall heat transfer coefficientCross Flow Area, A= = =
Overall heat transfer coefficient, U= = = -111.80 4) Calculation
of Pressure Drop across Tube and Shell= = = 338.8 Pa
= = = 3.3 Pa
[Fixed Hot Water Flow Rate 10 LPM]1) Calculations of heat
transfer and heat lostThe heat transfers of both hot and cold water
are both calculated using the heat balance equation.
Heat transfer rate for hot water i) = 7907.50 W
ii) = 5294.59 W
iii) = 4263.17 W
iv) = 3506.80 W
v) = 2956.72 W
Heat transfer rate for cold water i) = 222.13 W
ii) = 694.15 W
iii) = 1416.06 W
iv) = 2221.27 W
v) = 2984.84 W
Heat Lost Rate = i) ii) iii) iv) v)
Efficiency = i) ii) iii) iv) v)
2) Calculations of Log Mean Temperature Differencei) = = =
ii) = =
iii) = =
iv) = =
v) = = undefined
3) Calculation of the tube and shell heat transfer coefficients
by Kerns methodFor 1-shell pass; 1-tube pass,
Heat transfer coefficient at Tube side:Cross Flow Area, A= =
=
Total cross Flow Area, = 0.0000472 number of tubes= 0.0000472
10= 0.000472 m2
Mass velocity, = = =
Linear Velocity, = = =
Reynolds No, Re= = = (Turbulent Flow)
Prandtl No, Pr= = = 3.56
Tube Side Coefficient, hi= = =
Heat transfer coefficient at Shell side:Cross Flow Area, A= =
=
Mass velocity, = = =
Linear Velocity, = = =
Equivalent Diameter, = = =
Reynolds No, Re= = = (Laminar Flow)
Prandtl No, Pr= = = 5.44Shell Side Coefficient, hi= = =
Overall heat transfer coefficientCross Flow Area, A= = =
Overall heat transfer coefficient, U= = = -111.80 4) Calculation
of Pressure Drop across Tube and Shell= = = 338.8 Pa
= = = 3.3 Pa
DISCUSSIONIn this experiment, there are a few objectives that
are need to be achieved which are, to demonstrate the working
principles of concentric flow heat exchanger under counter-current
and co-current flow conditions, to observe the effect of the heat
water inlet temperature variation on the performance characteristic
of a concentric tube heat exchanger, to show the effect of flow
rate variation on the performance of a concentric heat exchanger
and the major part of the objectives is to determine the most
efficient flow of concentric tube heat exchanger whether it is the
counter-flow or co-current flow.
In addition, double pipe concentric heat exchanger is used to
archive these objectives. It is combined with thermometers and the
flow rates meter. Moreover, the control of the hot fluids
temperature and both hot and cold fluid flow rates were made much
easier.
Furthermore, notice that for both experiment 3a and 3b, the
counter-flow produce greater efficiency that co-current flow. This
result obey the theoretical conclusion where the counter-flow heat
exchanger is more efficient that co-current flow.
Moreover, there are a lot of mistakes and error that might have
affected the results obtained. The most common error occurred
during the experiment is parallax error. The eye position is not
perpendicular to the scale when recording the temperatures of the
fluids. Besides that, the flow rates always change easily during
the experiments and the reading of in from the typical laboratory
thermometer is merely different from the reading on the digital
thermometer.
Based on the calculation that had been done, it was found out
that the values of LMTD for co-current flow is higher than the
counter-current flow. But, the overall heat transfer coefficient
for counter-current flow is higher than the co-current flow. This
mean that counter current flow heat exchanger has a higher
effectiveness.
CONCLUSIONThis experiment shows that the shell and tube heat
exchanger follows the basic law of thermodynamics. In parallel
(co-current) flow configuration, the exit temperature of the hot
fluid is always higher than the exit temperature of the cold fluid.
In counter-current flow configuration, the exit temperature of the
hot fluid is also higher than the exit temperature of the cold
fluid. However, in counter current flow configuration, the exit
temperature of the cold fluid is higher than the exit temperature
of the cold fluid in co-current configuration. Hence, it is clear
that for heat exchanger, counter current flow configuration has a
higher effectiveness than the co-current flow configuration. The
experiment shows that when the flow rate of one of the stream
increases, the rate of heat transfer will also increases. The
amount of heat loss form the hot water is not equal to the heat
gain by the cold water due to the heat loss to the surrounding.
From the calculations done, the LMTD (log mean temperature
difference) for co-current flow is higher than the counter-current
flow. However, the overall heat transfer coefficient for
counter-current flow is higher than the co-current flow. As a
conclusion, counter current flow configuration of heat exchanger is
more preferred for practical application. One of the applications
of heat exchanger is oil cooler.
RECOMMENDATIONSThere are few recommendations that are needed to
be considered when conducting this experiment so that the result
obtained can be more accurate and precise. First, the eye position
should be perpendicular to the meniscus and the scale. This can
prevent parallax error from occurring. Next, the experiment should
be repeated at least 3 times in order to get an accurate data which
will be more convincing.Furthermore, the flow rates and the
temperature must be monitored regularly during the experiment to
ensure that they remain constant. This can reduced the possibility
for error to occur and achieved the main objective of the
experiment. In addition, the equipment must be check first in order
to avoid any error such as leakage. Always check and rectify any
leak and make sure that the heater is fully immersed in the water.
It must assure to run properly. Other than that, be extremely
careful when handling liquid at high temperature. Do not touch the
hot components of the unit as it may cause a serious injury.The
amount of cold water must be continuous in order to avoid the
reducing of hot water because if the hot water reduced into
critical level it might cause an explosion. Lastly, always switch
off the heater and allow the liquid to cool down before draining it
out.
REFERENCES1. Chopey, N.P. Handbook of Chemical Engineering
Calculations (2nd Edition), McGraw-Hill, 1994.2. Coulson, J.M. and
Richardson, J.F. Chemical Engineering, Volume 1 (3rd Edition),
Pergamon Press, 1977.3. Coulson, J.M. and Richardson, J.F. Chemical
Engineering, Volume 6 (Revised 3rd Edition), Butterworth-Heinemann,
1996.4. Kern, D.Q. Process Heat Transfer (Intl Edition),
McGraw-Hill, 1965.5. Perry, R.H., Green, D.W. and Maloney, J.O.
Perrys Chemical Engineering Handbook (6th Edition), McGraw-Hill,
1984.
APPENDICES
Figure 6: Temperature correction factor: one shell pass; two or
more even tube passes
Figure 7: Tube side heat transfer factors
Figure 8: Tube side friction factors
Figure 9: Shell side heat transfer factors, segmental
baffles
Figure 10: Shell side friction factors, segmental baffles
Figure 11: Heat transfer factors for cross-flow tube banks
Figure 12: Tube row correction factor,
Figure 13: Window correction factor,
Figure 14: Bypass correction factor,
Figure 15: Coefficient for , heat transfer
Figure 16: Friction factors for cross-flow tube banks
Figure 17: Bypass factor for pressure drop,
Figure 18: Coefficient for , pressure drop.
Figure 19: Baffle and tube geometryFigure 20: Baffle geometrical
factors
Experiment B: Co-Current Shell & Tube Heat Exchanger
[Fixed Cold Water Flow Rate 10 LPM]1) Calculations of heat
transfer and heat lostThe heat transfers of both hot and cold water
are both calculated using the heat balance equation.
Heat transfer rate for hot water i) = 206.28 W
ii) = 522.58 W
iii) = 1113.93 W
iv) = 1980.31 W
v) = 2612.91 W
Heat transfer rate for cold water i) = 7566.21 W
ii) = 3887.23 W
iii) = 3401.32 W
iv) = 3193.08 W
v) = 2776.59 W
Heat Lost Rate = i) ii) iii) iv) v)
Efficiency = i) ii) iii) iv) v)
2) Calculations of Log Mean Temperature Differencei) = = =
ii) = =
iii) = =
iv) = =
v) = =
3) Calculation of the tube and shell heat transfer coefficients
by Kerns methodFor 1-shell pass; 1-tube pass,
Heat transfer coefficient at Tube side:Cross Flow Area, A= =
=
Total cross Flow Area, = 0.0000472 number of tubes= 0.0000472
10= 0.000472 m2
Mass velocity, = = =
Linear Velocity, = = =
Reynolds No, Re= = = (Turbulent Flow)
Prandtl No, Pr= = = 3.56
Tube Side Coefficient, hi= = =
Heat transfer coefficient at Shell side:Cross Flow Area, A= =
=
Mass velocity, = = =
Linear Velocity, = = =
Equivalent Diameter, = = =
Reynolds No, Re= = = (Laminar Flow)
Prandtl No, Pr= = = 5.44Shell Side Coefficient, hi= = =
Overall heat transfer coefficientCross Flow Area, A= = =
Overall heat transfer coefficient, U= = = -111.80 4) Calculation
of Pressure Drop across Tube and Shell= = = 338.8 Pa
= = = 3.3 Pa
[Fixed Hot Water Flow Rate 10 LPM]1) Calculations of heat
transfer and heat lostThe heat transfers of both hot and cold water
are both calculated using the heat balance equation.
Heat transfer rate for hot water i) = 5363.35 W
ii) = 3850.61 W
iii) = 2819.20 W
iv) = 2681.67 W
v) = 2544.15 W
Heat transfer rate for cold water i) = 208.24 W
ii) = 638.62 W
iii) = 1207.82 W
iv) = 1721.49 W
v) = 2637.76 W
Heat Lost Rate = i) ii) iii) iv) v)
Efficiency = i) ii) iii) iv) v)
2) Calculations of Log Mean Temperature Differencei) = = =
ii) = =
iii) = =
iv) = =
v) = =
3) Calculation of the tube and shell heat transfer coefficients
by Kerns methodFor 1-shell pass; 1-tube pass,
Heat transfer coefficient at Tube side:Cross Flow Area, A= =
=
Total cross Flow Area, = 0.0000472 number of tubes= 0.0000472
10= 0.000472 m2
Mass velocity, = = =
Linear Velocity, = = =
Reynolds No, Re= = = (Turbulent Flow)
Prandtl No, Pr= = = 3.56
Tube Side Coefficient, hi= = =
Heat transfer coefficient at Shell side:Cross Flow Area, A= =
=
Mass velocity, = = =
Linear Velocity, = = =
Equivalent Diameter, = = =
Reynolds No, Re= = = (Laminar Flow)
Prandtl No, Pr= = = 5.44Shell Side Coefficient, hi= = =
Overall heat transfer coefficientCross Flow Area, A= = =
Overall heat transfer coefficient, U= = = -111.80 4) Calculation
of Pressure Drop across Tube and Shell= = = 338.8 Pa
= = = 3.3 Pa