S S S ∧ S S ∨ S S ⊕ S ¬S ∨ S S ∧ (S → S ) ≡ (S ∧¬S ) ∨ (S ∧ S ) {b n } ∞ n= b = ,b = b n = b n- - b n- + n + b n n + α n = α n- - α n- (α ̸= ), then divide both equations by α n- , we get α - α + = , Hence C b (α)= α - α + set C b (α)= α - α + = , we get α = α = Hence b n = c ( n )+ cn( n )+ n + now = b = c + + + , so c = . Also = b = ( )+ c ( )( )+ + ,so c = - b n = n - n( n )+ n + = ( n ) - n( n )+ = (n+) - n( n )+ {b n } ∞ n= b = ,b = b n = b n- + b n- b n {b n } ∞ n= b = ,b = b n = b n- + b n- + n - n + b n T F ∃x ∈ R x + = x + = ∃x ∈ R x + = x + = ∃x ∈ N x + = x + = ∃x< x + = x + = ∃x ∈ R x + = - x + x - e x = - ∃x ∈ R x + = - x + √ x + ln( x)+ x =
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Assignment 9: MTH 213, Fall 2017 - ayman-badawi.com MTH 213 Fall 2017 Assignments with... · Assignment 9: MTH 213, Fall 2017 ymanA Badawi QUESTION 1. Given string1, say S1: 0 1 0
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x = -1 and -1 in R and x^2 + 4 = 5, but X + 2 not = 3. Hence conclusion is F. So the whole statement is F. To make it true I should add.. then x + 2 = 3 OR x + 2 = 1