TIME 1 hour 30 minutes. INSTRUCTIONS TO CANDIDATES Write your Centre Number and Candidate Number in the spaces provided at the top of this page. Answer all sixteen questions. Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering. Answer all six questions in Section B. Write your answers in the spaces provided in this question paper. INFORMATION FOR CANDIDATES The total mark for this paper is 100. Quality of written communication will be assessed in question 14(d)(iii). In Section A all questions carry equal marks, i.e. two marks for each question. In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question. A Periodic Table of Elements (including some data) is provided. ADVANCED SUBSIDIARY (AS) General Certificate of Education 2006 Chemistry Assessment Unit AS 1 assessing Module 1: General Chemistry WEDNESDAY 7 JUNE, MORNING BP 2 – 2.3.06EA AS1 Chemistry Papers: 2006 - 2014 & Mark Schemes 2006-09: Old-Old Spec June 2009-14: Old Spec 395 Pages in total.
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TIME
1 hour 30 minutes.
INSTRUCTIONS TO CANDIDATES
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all sixteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all six questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in question 14(d)(iii).In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements (including some data) is provided.
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2006
Chemistry
Assessment Unit AS 1assessing
Module 1: General Chemistry
WEDNESDAY 7 JUNE, MORNING
BP
2
– 2
.3.0
6EA
AS1 Chemistry Papers: 2006 - 2014& Mark Schemes2006-09: Old-Old SpecJune 2009-14: Old Spec
For each of the questions only one of the lettered responses (A – D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
1 20 cm3 of 0.3 mol dm–3 potassium hydroxide solution is exactly neutralised by
A 10 cm3 of 0.3 mol dm–3 sulphuric acid B 10 cm3 of 0.6 mol dm–3 sulphuric acid C 20 cm3 of 0.3 mol dm–3 sulphuric acid D 20 cm3 of 0.6 mol dm–3 sulphuric acid
2 Which one of the following electron configurations has two unpaired electrons?
A 1s2 2s1
B 1s2 2s2 2p3
C 1s2 2s2 2p4
D 1s2 2s2 2p6 3s2 3p5
3 Which one of the following shows the trend in electronegativity values of the elements in the Periodic Table?
4 Which one of the following sodium compounds produces a gas when treated with dilute sulphuric acid?
A sodium carbonate B sodium chloride C sodium fluoride D sodium iodide
5 If the price of one tonne (1000 kg) of sulphur is £160, what is the cost (to the nearest pound) of the sulphur needed to make one tonne of sulphuric acid (H2SO4)?
A £52 B £98 C £160 D £490
6 A positively charged particle with the electron configuration 2.8 is
A an aluminium ion. B a fluoride ion. C an oxide ion. D a potassium ion.
7 The orbitals of a nitrogen atom may be represented as shown.
Which one of the following diagrams represents the arrangement of electrons in the ground state of the nitrogen atom?
8 Which one of the following chloro-compounds is non-polar?
A HCl B CCl4 C CH3Cl D CHCl3
9 Which one of the following contains a coordinate bond?
A N2 B NH3 C NH2
–
D NH+ 4
10 The enthalpy of neutralisation when an acid reacts with an alkali is, by definition, the number of kilojoules released by
A the formation of one mole of water. B the formation of one mole of salt. C the neutralisation of one mole of acid. D the neutralisation of one mole of alkali.
(b) The bond enthalpy of hydrogen fluoride is 566 kJ mol–1 whereas that of hydrogen iodide is 299 kJ mol–1. State what would be observed when hydrogen fluoride and hydrogen iodide are heated.
13 Calcium fluoride, CaF2, occurs naturally as fluorite or fluorspar. Impurities give a blue variety known as Blue John. Fluorspar is the major source of hydrogen fluoride and fluorine. It can be prepared in the laboratory by precipitation or direct combination of the elements.
(f) The natural presence of fluoride ions in domestic water supplies is regarded as beneficial by some, but the deliberate addition of fluoride ions is controversial.
(i) State a benefit of fluoride ions in drinking water.
(c) A major use of sodium metal is in sodium street lamps. The lamp contains mercury vapour which conducts electricity at high voltages. Sodium within the lamp vaporises and the electrical energy causes yellow (orange) light to be given out.
(i) Explain, in terms of energy levels, how the yellow light is generated.
(ii) The value of the first ionisation energy for sodium is 500 kJ mol–1. The second ionisation energy has a value of 4513 kJ mol–1. Explain why this is a much higher value.
16 In the laboratory, ammonia can be prepared by heating a mixture of ammonium chloride and calcium hydroxide, as shown in the diagram below.
The equation for the reaction is:
2NH4Cl + Ca(OH)2 → 2NH3 + CaCl2 + 2H2O
(a) The ammonia gas is collected upwards. Calculate the relative molecular masses of ammonia, oxygen and nitrogen and use them to explain why ammonia is collected in this way.
(b) Calculate the volume of ammonia produced, at 20 °C and one atmosphere pressure, if 1.07 g of ammonium chloride are heated with excess calcium hydroxide.
(ii) Freedom of choice/against mass medication [1] 14
14 (a) (i) Electrons = 11 Protons = 11 Neutrons = 12 [–1] for each error [2] (ii) Same number of protons [1] different number of neutrons/different mass [1] [2]
(c) (i) Electrons raised to a higher (energy) level (by electrical energy) [1] accept any value for C as not given in the question paper Electrons fall down to lower/original (energy) level [1] Light given out/energy given out as light [1] [3]
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all sixteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all six questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in question 13(d).In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements (including some data) is provided.
ADVANCED SUBSIDIARY (AS)General Certificate of Education
(b) The isotopes cannot be chemically distinguished. They both react with sodium and phosphorus in the same way to form sodium bromide and phosphorus tribromide respectively.
(i) Explain why the isotopes react in the same way.
(c) Both sodium bromide and phosphorus tribromide can be used to prepare hydrogen bromide. Hydrolysis of phosphorus tribromide yields pure hydrogen bromide gas. The reaction of sodium bromide with concentrated sulphuric acid yields an impure gas.
PBr3 + 3H2O → 3HBr + H3PO3
(i) Calculate the volume of hydrogen bromide produced, at 20 °C and one atmosphere pressure, when 9.0 g of phosphorus tribromide are completely hydrolysed.
(b) The equation for the reaction of silver with nitric acid is:
3Ag + 4HNO3 → 3AgNO3 + 2H2O + NO
(i) Determine the oxidation numbers of the underlined elements in the following species from the equation and use them to explain the redox reaction taking place.
(c) A coin containing silver can be dissolved in nitric acid and silver chloride, AgCl, precipitated using sodium chloride solution. After drying and weighing the mass of the precipitate is used to determine the amount of silver present in the coin.
(i) Write an equation for the reaction of silver ions with chloride ions.
15 Ammonia does not burn in air but it will burn in oxygen.
(a) The equation for the combustion of ammonia in oxygen is:
4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(g)
(i) If 20 cm3 of ammonia are reacted with the required amount of oxygen, what is the total volume of gases produced at the same temperature and pressure?
(ii) Heat/enthalpy produced [1] measured under standard conditions/or stated [1]
when one mole of water formed [1] in the reaction of an acid with an alkali [3]
(b) (i) If a given change can be brought about in more than one way the overall enthalpy change is the same for each way [2]
(ii) ∆H2 + ∆H3 = ∆H1 [1]
(c) HCl(aq) [1]
(d) Calorimeter/polystyrene cup [1] known volume of known M hydrochloric acid [1] measure temperature at start and end [1] stir [1] [4] Quality of written communication [2] 14
(ii) Malleability [1] lustrous [1] ductility [1] [2] 12
15 (a) (i) KOH + HCl → KCl + H2O [1]
(ii) Measure initial and fi nal temperatures of solution/change in temperature [1] Add excess HCl(aq) to a known quantity of KOH [1] Error – lack of insulation [1] Safety – protect eyes [1] [4]
Quality of written communication [2]
(iii) Enthalpy of neutralisation is the enthalpy change [1] when 1 mole of water is produced by reaction between acid and alkali [1] [2]
(c) The colours observed during the fl ame test are due to the excitement of the electrons caused by absorption of energy. The electrons “jump” from their ground state to a higher energy level. As they return to n = 2 they emit visible light . . .
[3] 16
16 (a) (i) Silicon giant covalent [1] aluminium metallic [1] [2] (ii) Sulphur S8 large molecular/strong van der Waals forces [1] argon, weak van der Waals forces [1] [2]
(b) Nuclear charge increases [1] electrons in same shell drawn closer to nucleus [1] [2]
(c) (i) Increased repulsion due to added electron in bromide ion [1]
(ii) Increases from F to I, electrons are going into shells further and further from nucleus therefore less nuclear attraction [2]
(d) (i) Electronegativity is a measure of the tendency of an atom to attract a bonding [1] pair of electrons [1] [2]
(ii) HF is polar as F has a higher/different electronegativity than H [1]
(iii) The (trigonal symmetrical planar) structure [1] of BF3 is such that the dipole (moments) cancel out [1] [2] 14
(b) Electron (excited) to higher energy level [1] Electron falls back to lower energy level [1] Diagram
(Energy) emitted (as a quantum of) light [1] [3] 5
12 (a) Only 4 electrons around the central beryllium atom [1] instead of 8 Atom gain/lose share electrons to obtain 8 electrons in the outer shell [1] [2]
(b) (i) Both electrons in a (covalent) bond come from the same atom [1]
(ii)
H
H
H
HN
X•
X•
••X
•
[–1] for each mistake [2] 5
13 (a) (i) Starch [1]
(ii) A solution the concentration of which is known (accurately) [1]
(iii) Any four: Pipette known volume of the iodine solution into a (conical) flask [1] Titrate with the thiosulphate [1] until the colour of the solution is pale yellow then add starch [1] Continue adding the thiosulphate until the solution goes from blue/black to colourless [1] [4]
Quality of written communication [2]
(b) (i) 2Na2S2O3 + I2 → Na2S4O6 + 2NaI accept ionic equation ([–1] for each mistake) [2]
1.125 × 10–3 1.125 × 10–3 × 10 = 0.01125 0.01125 × 34 = 0.3825 (0.3825/25) × 1000 = 15.3 (g dm–3). (Award full marks directly for the correct answer. Carry any errors through, [–1] for each mistake) [4] 14
14 (a) (i) C12H26 + 1812O2 → 12CO2 + 13H2O
([–1] for each mistake) [2]
(ii) y-axis labelled enthalpy [1] reactants and products correctly shown [1] [2]
(iii) Enthalpy of the reactants is greater than the enthalpy of the products [1]. (Difference) given out as heat [1]. (Or correct explanation in terms of breaking and making bonds.) [2]
(b) (i) Enthalpy of combustion: Enthalpy change on the complete combustion in oxygen [1] of 1 mole [1] (under standard conditions) [2]
(ii) Hess’s Law: The overall enthalpy change for a reaction is independent of the number of steps taken [1] provided the conditions remain the same [1] [2]
(iii) 250.0 + ∆H = 8(–393.5) + 9(–286.0) ∆H = –5472 (kJ mol–1) ([–1] for each mistake) [3]
(c) (i) The energy required to break (1 mole of) bonds in the gaseous state to form the gaseous atoms [1]
(ii) Malleable: Layers can slide over one another (and the bonds reform without breaking) [1] [1]
Conducts electricity: Delocalised (valence) electrons [1] are free to move [1] [2]
(b) (i) 2Na(s) + F2(g) → 2NaF(s) [2]
(ii)
x x
xxx
x
x x
xx
+ –
Na F
x x
Na
x x
F
([–1] for each mistake) [3]
(iii) To help reduce tooth decay [1]
(iv) Lack of freedom of choice (or suitable alternative) [1]
(c) (i) Shielding remains constant/electrons add to same shell [1] Nuclear charge increases giving a greater attraction for the outer electrons [1] [2]
(ii) 12 to 13: The outer electron is being added to the p-subshell which is slightly further from the nucleus making it easier to remove the electron/stability of shell [1]
15 to 16: The outer electron is forming the first pair in the p-subshell and it is slightly easier to separate a pair of electrons/ stability of shell [1] [2]
16 (a) The ability of an atom in a covalent bond to attract the electrons [1]
(b) (i) H2 + F2 → 2HF [1]
(ii) [1]
(iii) Thermal stability decreases down the Group [1] as strength of the HHal bond decreases down the Group [1] [2]
(iv) HAt > HI > HBr > HCl > HF [1]
(c) (i) * Make a solution of the solid [1] Add silver nitrate White precipitate for chloride [1] Giving a cream ppt for bromide [1] White ppt soluble in dilute ammonia solution [1] Cream ppt insoluble in ammonia solution [1]
either
(maximum of [4]) [4]
(ii) NaBr + H2SO4 → NaHSO4 + HBr [2]
(iii) Steamy fumes/purple vapour/smell of rotten eggs/heat produced/ (yellow) solid formed (any two, [1] each) [2]
(d) (i) Cl2: 0 [1] NaCl: –1 [1] NaOCl: +1 [1] [3]
(ii) (ON of Cl changes from) 0 to –1 = Reduction [1] (ON of Cl changes from) 0 to +1 = Oxidation [1] [2]
(b) Moles of ethene = 120 ÷ 24 000 = 0.005 moles 1:1 ratio Moles of bromine (Br2) = 0.005 moles Mass of bromine (Br2) = 0.005 × 160 = 0.8 g Volume of pure liquid bromine Volume (cm3) = mass (g) ÷ density (0.8 ÷ 3.2) = 0.25 cm3 [4] 9
15 (a) (i) White flame/white solid [1]
(ii) 2Mg + O2 → 2MgO [2]
(b) Moles of HCl = 2 × 0.05 = 0.1 moles 2:1 ratio Moles of H2 = 0.05 moles Volume of H2 = 0.05 × 24 = 1.2 dm3 or 1200 cm3 [3]
(c) (i) White [1] precipitate [1] [2]
(ii) Mg2+(aq) + CO32–(aq) → MgCO3(s) [2]
(d) (i) Decreases down the group [1] Use of lattice enthalpy (X) [1] Use of hydration enthalpy (Y) [1] Variation in Y is greater than variation in X down the group [1] [4]
Butan-2-ol [1] [6] (b) (i) Molecules which have the same molecular formula but different structural formula [2]
(ii) An alcohol which has 3 carbons directly attached to the same carbon as the hydroxyl group [2]
(iii) Heat each alcohol (separately) [1] with acidified (potassium) dichromate (APD)/acidified (potassium) manganate VII [1] with butan-1-ol APD orange to green/purple to colourless [1] with 2-methylpropan-2-ol APD remains orange/remains purple [1] Maximum [3] [3]
Quality of written communication [2]
(c) (i) methyl group and a hydrogen attached to the same carbon as the hydroxy group [1]
(c) in sodium electron further from nucleus/in chlorine closer or Cl radius smaller than Na [1] conditional on comment on size less attraction/more attraction (of nucleus for electrons) [1] [2]
(d) (i) [1]
(ii) or or [1] 9
12 (a) (i) three (bonding/shared) pairs of electrons between the nitrogens [2] [2]
(ii) a lot of energy needed to break the bonds [1] [1]
(ii) iodine in flask and thiosulphate in burette [1] add thiosulphate until straw yellow [1] add starch [1] add thiosulphate until the blue/blue-black colour [1] disappears/colourless [1]
Quality of written communication [2] 21
16 (a) two [1] carboxylic acid groups [1]
(b) [2]
(c) alkali: pink/red [1] acid: colourless [1]
(d) concentrated [1] ammonia solution [1] white fumes [1]
(ii) nichrome wire cleaned with concentrated hydrochloric acid [1] placed in blue Bunsen flame [1] yellow [1] dissolve in water [1] add silver nitrate solution [1] to produce a white precipitate [1] to a maximum of [4] NaCl + AgNO3 → NaNO3 + AgCl [1] [5]
(d) (i) Na(g) → Na+(g) + e– [2]
(ii) (more energy is needed to) remove an electron from a full shell [1] the electron(s) are nearer to the nucleus [1]
from a positive ion [1] Any 2 from 3 [2]
(e) sodium metal has delocalised electrons [1] which move and thus a current flows [1] sodium chloride consists of ions [1] in fixed positions which cannot move [1] can move in solution or when molten [1]
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all seventeen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all seven questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in question 16(a)(i).In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in the brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements (including some data) is provided.
For each of the following questions only one of the lettered responses (A – D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet
1 How many electrons are present in a potassium ion, K+?
A 18 B 19 C 20 D 39
2 Which one of the following represents the first five ionisation energies in kJ mol–1 of an s-block element?
1st 2nd 3rd 4th 5th
A 580 1800 2700 11 600 14 800 B 740 1500 7700 10 500 13 600 C 1000 2300 3400 4600 7000 D 14 800 11 600 2700 1800 580
3 A sample of 4.64 g of hydrated sodium carbonate, Na2CO3.xH2O, was dissolved in 1 dm3 of water. 25.0 cm3 of this solution required 20.0 cm3 of 0.05 mol dm–3 hydrochloric acid for neutralisation. Which one of the following is the value of x?
A 0.5 B 5 C 7 D 13
4 Which one of the following contains a coordinate bond?
A Ammonium, NH4+
B Boron trifluoride, BF3 C Sulphur hexafluoride, SF6 D Water, H2O
8 Using the half-equations below, which one of the following is the balanced ionic equation for the reaction between acidified manganate(VII) ions and ethanedioate ions?
Acidified manganate(VII) ions:
MnO4– + 8H+ + 5e– → Mn2+ + 4H2O
Ethanedioate ions:
C2O42– → 2CO2 + 2e–
A 2MnO4– + 16H+ + C2O4
2– → 2Mn2+ + 8H2O + 2CO2
B MnO4– + 8H+ + 5C2O4
2– → Mn2+ + 4H2O + 10CO2
C 2MnO4– + 16H+ + 5C2O4
2– → 2Mn2+ + 8H2O + 10CO2
D 5MnO4– + 40H+ + 2C2O4
2– → 5Mn2+ + 20H2O + 4CO2
9 Which one of the following molecules is non-polar?
A Ammonia, NH3 B Carbon dioxide, CO2 C Hydrogen fluoride, HF D Water, H2O
10 The extraction and purification of uranium from its ore involves the following reaction between uranium(IV) fluoride and magnesium.
2Mg + UF4 → U + 2MgF2
What mass of uranium can be extracted from 500 tonnes of uranium(IV) fluoride and 50 tonnes of magnesium?
A 192 tonnes B 246 tonnes C 379 tonnes D 495 tonnes
13 The percentage of calcium carbonate present in egg shells can be found by back titration using excess hydrochloric acid and standard sodium hydroxide solution.
(a) Write an equation for the reaction between calcium carbonate and hydrochloric acid.
(c) 1.12 g of an egg shell was reacted with 20.0 cm3 of 2M hydrochloric acid and the solution formed made up to 250 cm3 in a volumetric flask. 25.0 cm3 of this solution completely reacted with 18.6 cm3 of 0.1 M sodium hydroxide.
Calculate the percentage of calcium carbonate in the egg shell using the headings below.
15 (a) (i) Pair(s) of electrons shared between (two) atoms [1]
(ii) Diamond: Carbon atoms joined to 4 others [1] tetrahedrally [1] Graphite: hexagonal rings of carbon atoms [1] in layers [1] [4]
(iii) Free electrons [1] are able to move [1] around the layers [2]
(iv) Strong (covalent) bonds [1] throughout the giant (tetrahedral) structure [1]
(b) (i)
[–1] for each mistake [1]
[–1] for each mistake [1]
(ii) Octet rule: eight electrons in the outer shell (when bonded) [1] Be (has less than 8) in beryllium chloride/has only 4 electrons in its outer shell [1] [2] 12
16 (a) (i) Sodium: nichrome wire [1]/(conc HCl) blue flame [1]/yellow [1] Chloride: (make a solution) silver nitrate [1] white precipitate [1] or dissolve in HNO3 [1] (solution) [5]
Quality of written communication [2]
(ii) [4]
(b) (i) In the solution the ions are free to move, (they cannot move in the solid) [1]
(ii) Chlorine atoms are both oxidised (0 to +1) [1] and reduced (0 to –1) [1] this is disproportionation [1] [3]
The total mark for this paper is 100.Quality of written communication will be assessed in question 13(c).In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements (including some data) is provided.
INSTRUCTIONS TO CANDIDATES
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all fifteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all five questions in Section B. Write your answers in the spaces provided in this question paper.
For each of the following questions only one of the lettered responses (A–D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots
as illustrated on the answer sheet.
1 2.65 g of anhydrous sodium carbonate, Na2CO3, was dissolved in water and the solution made up to 250 cm3 in a volumetric flask. The concentration of the solution was
A 0.025 mol dm–3
B 0.050 mol dm–3
C 0.100 mol dm–3
D 0.200 mol dm–3
2 In which one of the following molecules does the central atom obey the octet rule?
A BeCl2 B BF3 C CF4 D SF6
3 Which one of the following statements about iodine is not correct?
A It has a molecular covalent structure. B It contains non-polar molecules. C It exists as a grey-black shiny solid. D It is more soluble in water than hexane.
4 Elements Q and R have ground state electron structures 1s22s22p63s2 and 1s22s22p5 respectively. Q and R combine to produce a compound with the formula
8 When burned in a plentiful supply of oxygen, propane (C3H8) produces carbon dioxide and water.
C3H8 + 5O2 → 3CO2 + 4H2O
What is the number of molecules of carbon dioxide produced when 4.4 g of propane are burned?
A 6.02 × 1022
B 1.81 × 1023
C 6.02 × 1023
D 1.81 × 1024
9 A compound produces a lilac colour in a flame test. When chlorine is bubbled into an aqueous solution of the compound, the solution changes from colourless to yellow-orange. The compound is
A potassium bromide B potassium iodide C sodium bromide D sodium iodide
10 Iron(III) oxide can be reduced by carbon to form iron.
2Fe2O3 + 3C → 4Fe + 3CO2
What is the maximum mass of iron which can be produced when 3.20 kg of iron(III) oxide is heated with 0.72 kg of carbon?
(a) Atoms of the 74Ge isotope contain 32 protons, 32 electrons and 42 neutrons. Complete the following table which shows the properties of each of these particles.
Particle Relative mass Relative charge
Proton
Electron
Neutron
[3]
(b) State, in terms of protons and neutrons, the meanings of the following terms:
Mass number ________________________________________________
12 Phosphorus and nitrogen are in Group V of the Periodic Table. Nitrogen forms a hydride called ammonia and the hydride of phosphorus is called phosphine, PH3.
(a) (i) Draw a dot and cross diagram to show the bonding in phosphine.
[2]
(ii) Draw and name the shape of a phosphine molecule.
(b) There is a general increase in the first ionisation energies across Period 3. The graph below shows the variation of the first ionisation energies of some of the elements in Period 3.
(i) Use crosses to mark the relative positions of the first ionisation energies for the elements Mg, Al and P. Complete the graph by joining the crosses. [2]
(ii) Explain the general increase in first ionisation energy across the period.
(c) The first four ionisation energies of aluminium are 578, 1817, 2745 and 11 578 kJ mol–1.
(i) Label the subshells in the following diagram for an aluminium atom and use the electrons-in-boxes notation to show how the electrons are arranged in the Al2+ ion.
[2]
(ii) Write the equation, including state symbols, for the fourth ionisation energy of aluminium.
(c) When sodium bromide is dissolved in water, the presence of bromide ions can be established by using aqueous silver nitrate followed by concentrated ammonia solution.
(i) What is observed when aqueous silver nitrate is added to sodium bromide solution?
(ii) 21.4 and 21.3 into table [1] Average titre = 21.35 cm3 [1]
(iii) 0.1 × (21.35/1000) = 2.135 × 10−3 [1]
(iv) (2.135 × 10−3) ÷ (0.025) = 0.0854 [1]
(v) 0.854 [1]
(c) Rinsing the pipette (2-3 times) with undiluted vinegar Use of pipette filler Meniscus on mark Mixing/inverting solution in volumetric flask Rinsing the pipette (2-3 times) with diluted vinegar Max = 4 [4]
INFORMATION FOR CANDIDATESThe total mark for this paper is 100.Quality of written communication will be assessed in question 13(d).In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.
INSTRUCTIONS TO CANDIDATESWrite your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all fifteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all five questions in Section B. Write your answers in the spaces provided in this question paper.
ADVANCED SUBSIDIARY (AS)General Certificate of Education
4 Which one of the following gives the correct flame colour for the named compound?
A barium chloride red B copper(II) chloride blue-green C potassium chloride yellow/orange D sodium chloride lilac
5 An element was analysed using a mass spectrometer. The spectrum showed that there were four isotopes. The relative isotopic masses and relative abundances are given below.
Relative isotopic mass Relative abundance
50 2
52 35
53 4
54 1
The relative atomic mass of this element is
A 52.00. B 52.05. C 52.25. D 52.50.
6 Which one of the following is produced when concentrated sulphuric acid reacts with solid sodium chloride?
A chlorine B hydrogen chloride C hydrogen sulphide D sulphur dioxide
7 Titanium is extracted in a two-stage process. The first stage involves the conversion of titanium(IV) oxide to titanium(IV) chloride. In the second stage, the titanium(IV) chloride is reduced using magnesium.
TiO2 + C + 2Cl2 → TiCl4 + CO2
TiCl4 + 2Mg → Ti + 2MgCl2
What is the maximum mass of titanium which can be obtained when 8.0 kg of titanium(IV) oxide is converted to titanium(IV) chloride and then reduced using 7.2 kg of magnesium?
A 2.4 kg B 4.8 kg C 9.6 kg D 14.4 kg
8 Which one of the following electron transitions is responsible for the lowest frequency line in the visible region of the emission spectrum of atomic hydrogen?
12 Fluorine is the most reactive non-metallic element. It combines with both metals and non-metals.
(a) (i) Using dot and cross diagrams, explain how strontium atoms combine with fluorine atoms to form strontium fluoride. Show the outer electrons only.
[4]
(ii) Compare the electrical conductivity of solid strontium metal with that of solid strontium fluoride. Explain your answer.
(d) At room temperature and pressure, iodine exists as a grey-black shiny solid. Describe the bonding in, and explain the structure of iodine crystals. Explain the relative solubilities of iodine in water and hexane.
14 Chlorine is produced by the electrolysis of concentrated sodium chloride solution (brine). It is then used by other industries to produce a variety of useful products.
(a) The reaction between chlorine and cold dilute sodium hydroxide is used in the manufacture of bleach.
(c) 3.57 g of a second sample of sodium carbonate was dissolved in water and the resulting solution was made up to 250 cm3 in a volumetric flask. A 25.0 cm3 sample of this solution required 28.5 cm3
of 0.1 mol dm–3 hydrochloric acid to reach the end point.
(i) Give the colour change which would be obtained at the end point, using the indicator given in (b)(iii).
From _____________________ to _____________________ [2]
(ii) Calculate the number of moles of hydrochloric acid used in the titration.
Sr atom [1] F atom [1] 1 : 2 ratio [1] correct electron transfer + charges [1]
(ii) solid strontium – good electrical conductor [1] solid strontium fluoride – poor electrical conductor solid strontium – delocalised electrons [1] solid strontium fluoride – ions are not free to move [1]
(b) (i) The ability/power of an atom to attract bonding electrons in a covalent bond [2]
(ii)
[1]
(iii)
[2]
(iv) does not apply to sulphur (12 electrons in outer shell) [1] does apply to fluorine (8 electrons in outer shell)/octet rule – has 8 e– in outer shell [1]
(ii) both shared electrons come from nitrogen/lone pair of electrons on nitrogen shared (donated) [1] 22
13 (a) (i) loss of electrons [1]
(ii) decrease in oxidation state/number [1]
(b) (i) +5 [1]
(ii) +2 [1]
(c) (i) 2I− → I2 + 2e− [1]
(ii) 2HNO3 + 6H+ + 6I− → 2NO + 4H2O + 3I2 [2]
(d) reference to covalent bonding/crystalline molecular covalent structure/diatomic/I2 van der Waals’ attractions between molecules 1 mark for each two bold points mentioned – Max [3] marks more soluble in hexane than water [1] since iodine and hexane are non-polar [1] and water is polar [1] like dissolves like [1] Max [4] marks Max [5] marks
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all sixteen questions. Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all six questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in question 14(d).
In Section A all questions carry equal marks, i.e. two marks for each
ADVANCED SUBSIDIARY (AS)General Certificate of Education
For each of the following questions only one of the lettered responses (A–D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
1 An atom in which the number of protons is greater than the number of neutrons is
A 2H. B 3He. C 10B. D 39K.
2 Which one of the following is a correct description of electronic transitions in a given series in the atomic emission spectrum of hydrogen?
A They all start from the ground state. B They all end at the ground state. C They all start from one particular energy level. D They all end at one particular energy level.
3 Which one of the following lists the first ionisation energies (in kJ mol–1) of the elements magnesium, aluminium, silicon, phosphorus and sulfur in this order?
A 496 736 577 786 1060 B 577 786 1060 1000 1260 C 736 577 786 1060 1000 D 786 1060 1000 1260 1520
7 Arsine, AsH3, is a molecular hydride of arsenic which is found in Group V of the Periodic Table. Which one of the following is the structure of arsine in the vapour state?
H
Bond angles 120º
As
HA
H
Bond angles greater than 109.5º
B
D
Bond angles less than 109.5º
C
H
Bond angles 109.5º
As
HH
H
As
HH
H
As
HH
8 50 cm3 of 0.20 mol dm–3 sulphuric acid is exactly neutralised by
A 100 cm3 of 0.40 mol dm–3 potassium hydroxide solution. B 25 cm3 of 0.20 mol dm–3 potassium hydroxide solution. C 50 cm3 of 0.20 mol dm–3 potassium hydroxide solution. D 100 cm3 of 0.20 mol dm–3 potassium hydroxide solution.
9 Which one of the following is the number of electrons which have approximately the same mass as that of a proton?
A 20 B 200 C 2000 D 20000
10 Which one of the following oxides is not polar?
(b) The metal beryllium is obtained either by the electrolysis of a fused mixture of beryllium and potassium chlorides at 350 ºC or by the reduction of beryllium fluoride with magnesium.
(i) Write an equation for the formation of beryllium from beryllium ions.
(c) The first element in a Group often has more distinctive properties than the elements in the rest of the Group. This is often as a result of the difference in electronegativities. The electronegativity values of the Group II elements are shown below.
electronegativityvalue
atomic number
Ba
Be
Mg
CaSr
(i) Explain the meaning of the term electronegativity.
(ii) Draw a dot and cross diagram to show the formation of beryllium chloride from beryllium and chlorine atoms. Use only the outer electrons of each atom.
(ii) Calculatetheoxidationnumberofchlorineinthereactantandintheproductsofthisreactionandusethemtoconfirmthatthereactionisadisproportionationreaction.
14 An experiment was set up to investigate the displacement reactions of the halogens.
Solutions of sodium halides were prepared and reacted with other halogens. The results table is shown below.
sodium iodide (aq)
sodium bromide (aq)
sodium chloride (aq)
iodine solution
X X
bromine solution ✓
chlorine solution
✓ means that a reaction took place X means that no reaction took place
(a) Complete the three remaining places in the table. [2]
(b) (i) Both bromine and iodine solutions are coloured. Describe the observations which would indicate that a reaction took place when aqueous sodium iodide is added to a bromine solution.
(d) If you had poured solutions of sodium iodide, bromide and chloride into beakers A, B and C and forgotten to label them, describe how, using aqueous silver nitrate and both dilute and concentrated ammonia solutions, you would determine which sodium salt was in which beaker. Each beaker must be tested.
(c) Although water is capable of forming hydrogen bonds it does not form long chains of “polywater” at room temperature. However, in the liquid state, molecules such as hydrogen fluoride do form very short chains.
Suggest why water does not form chains and liquid hydrogen fluoride does.
(iii) Calculate the formula of hydrated lithium sulphate if 3.76 g of the hydrated lithium salt produces 3.23 g of anhydrous lithium sulphate on heating.
(b) (i) atom raises and lowers its oxidation number during a chemical reaction [1]
(ii) ClO2 14 HClO3 15 HCl –1
[2]
{ 14 15 oxidation 14 –1 reduction
[1] [3]
(c) (i) Cl2 5 2 3 35.5 5 71
0.8 g 5 0.871 5 0.01127 mol
{ 0.113 M [2]
(ii) e.g. hexane [1]
14 (a) [2] (Note that the marking of the colour changes in this question will
be subject to the application of the “colour changes” scheme.)
(b) (i) compare colours with original solutionsit should go darker
colour of iodine is darker than bromine [2]
(ii) Br2 1 2I– 2Br – 1 I2 [1] no state symbols required
(c) (i) colourless solution [1] orange/yellow/brown colour produced [1] [2]
(ii) Cl2 1 2NaBr 2NaCl1 Br2 [1] no state symbols required
(d) iodide: yellow ppt insoluble in (both dilute and conc.) ammonia solution [2] bromide: cream ppt soluble in conc NH3 [2] chloride: white ppt soluble in dil NH3 [2] [6]
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all sixteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all six questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in question 15(f).
In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand
question.A Periodic Table of Elements (including some data) is provided.
ADVANCED SUBSIDIARY (AS)General Certificate of Education
5 Which one of the following is the shape of the ammonia molecule?
HA B
C D
N HH
N
H
N
HH
H107°HH
N
H120°HH
6 If 30 g of water were completely converted into hydrogen and oxygen which one of the following would be the total mass of gases produced?
A 10 g B 30 g C 45 g D 90 g
7 Which one of the following can not be used to obtain hydrogen chloride in the laboratory?
A burning hydrogen in chlorine B heating concentrated hydrochloric acid C the reaction of chlorine with methane D bubbling chlorine through hexane at room temperature
8 The element europium reacts with hydrogen to form europium hydride. Atoms of europium have their outer electrons in levels 5 and 6 i.e. 5s2 5p6 6s2. Which one of the following formulae resembles europium hydride?
12 Barium chloride crystallises from water to form a hydrate with the formula BaCl2.xH2O. On heating, the hydrate loses water to form anhydrous barium chloride. A solution of barium chloride is colourless.
(a) Barium chloride solution reacts with aqueous silver nitrate to form silver chloride.
(b) 3.05 g of BaCl2.xH2O were dissolved in water to make 250 cm3 of solution in a graduated flask. 20 cm3 of this solution were titrated with 0.1 M silver nitrate solution. It was found that 20.0 cm3 were required.
(i) How many moles of silver ions were added during the titration?
13 Astatine, the last element of the halogen group, was synthesised in 1940. Since then it has been stated that it is the rarest naturally occurring element on Earth with an estimated 30 g of astatine existing at any one time. It was named from the Greek word for “unstable”.
(a) The longest living isotope of astatine is astatine-210, 210At. However, half of this isotope disappears after about 8 hours.
(e) Astatine was first made by bombarding bismuth with alpha particles. Explain how you would show, using mass spectrometry, that astatine had actually been formed.
(c) The first ionisation energy of the Group I elements may be determined using spectroscopic methods.
(i) If the frequency of the radiation needed to remove the outermost electron from a sodium atom is 1.25 1015 s–1 calculate the first ionisation energy of sodium in kJ per mole.
(e) All of the Group I metals react with halogens to form ionic metal halides. Using outer electrons only draw diagrams to explain the formation of caesium chloride from caesium atoms and chlorine atoms.
[3]
(f) All of the Group I elements produce characteristic flame colours in a Bunsen burner flame which can be used to identify them.
(i) Describe how you would carry out a flame test.
16 Carbon dioxide is the most frequently found oxide of carbon in nature. It is a colourless gas with a faint taste and smell. The structure of the molecule can be readily deduced by the application of the octet rule. Even though carbon and oxygen have different electronegativities the molecule does not have a permanent dipole.
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all fifteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all five questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in question 11.
In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements (including some data) is provided.
ADVANCED SUBSIDIARY (AS)General Certificate of Education
A crystalline solid melts sharply at 95 °C. It does not conduct electricity in the solid and liquid states. It dissolves in hexane.
Which one of the following is the structure of the crystal?
A giant molecular B ionic C metallic D molecular covalent
9 The diagram below shows a liquid escaping from a burette and passing a charged glass rod.
+++
Which one of the following liquids will be attracted to the glass rod?
A CCl4 B CHCl3 C CS2 D C5H12
10 The species Ar, K and Ca2 have the same number of electrons. Starting with the smallest, which one of the following is the order in which their radii increase?
(d) The reaction of oxidising agents with potassium iodide can be used to prepare iodine in the laboratory. When heated with manganese dioxide and concentrated sulfuric acid, potassium iodide liberates iodine.
2KI MnO2 3H2SO4 2KHSO4 MnSO4 2H2O I2
(i) Using oxidation numbers, explain this redox reaction.
[3]
(ii) What observation would confirm that iodine had been produced?
13 Phosphorus, P, reacts with bromine at room temperature to form phosphorus tribromide, PBr3, which is a liquid with boiling point 173 °C. It reacts with water immediately forming hydrogen bromide and phosphoric(III) acid, H3PO3. The reaction is used as a method of preparing hydrogen bromide in the laboratory.
(a) Write the equation for the reaction of bromine with phosphorus.
[1]
(b) Calculate the maximum mass of phosphorus tribromide which can be formed when 6.2 g of phosphorus, which is an excess, reacts with 8.0 cm3 of bromine, Br2. The density of liquid bromine is 3.1 g cm3.
mass of bromine, Br2, in grams
[1]
moles of bromine, Br2
[1]
moles of phosphorus, P, in 6.2 g
[1]
moles of bromine, Br2 reacting
[1]
moles of phosphorus tribromide formed
[1]
mass of phosphorus tribromide formed
[1]
(c) Write the equation for the reaction of phosphorus tribromide with water.
(d) The apparatus shown below was used to prepare hydrogen bromide in the laboratory. Bromine is slowly added to a paste of phosphorus and water. Phosphorus tribromide is first formed and is immediately decomposed by the water present. The gases produced are passed through a U-tube containing glass beads coated in phosphorus.
bromine
cardboarddisc
P andwater
moist Pand glassbeads
(i) Suggest why the bromine is not added all at once.
[1]
(ii) An excess of water is not used in the experiment. What is the property of hydrogen bromide which is the reason for not using an excess?
[1]
(iii) Why is the hydrogen bromide collected as shown and not with the delivery tube pointing upwards?
[1]
(e) Hydrogen bromide is a colourless gas but produces fumes in moist air. Why does it fume in moist air?
14 Only 0.08% of the Earth’s crust consists of carbon yet this element is an essential part of living organisms. It occurs naturally as the isotopes carbon-12 and carbon-13 although there is a radioactive isotope carbon-14. Carbon occurs in nature as two structures known as diamond and graphite.
(a) Naturally occurring carbon contains 98.89% of carbon-12 and 1.11% carbon-13. Calculate the relative atomic mass of carbon to three decimal places.
[3]
(b) Carbon-14 is not used in the calculation of the relative atomic mass because virtually none of it exists. It decomposes when a neutron in its nucleus changes into an electron and a proton forming a new element.
(i) What are the numbers of electrons, protons and neutrons in the new element?
[2]
(ii) Name the element produced when carbon-14 decomposes.
[1]
(c) Mass spectrometry uses carbon-12 as the international standard.
(i) What is the purpose of mass spectrometry?
[2]
(ii) Explain the meaning of the term carbon-12 standard.
[2]
(d) Explain why carbon-12 and carbon-14 are isotopes.
(e) Carbon may be produced in the laboratory in many ways. One is to heat cane sugar, C12H22O11, with concentrated sulfuric acid. Steam and carbon are produced together with diluted sulfuric acid.
(i) Write the equation for the reaction. Do not include sulfuric acid in the equation.
[1]
(ii) Explain the meaning of the terms hydrated and water of crystallisation.
[2]
(iii) Explain whether the cane sugar is hydrated.
[1]
(f) Diamond is oxidised when it burns in oxygen at about 700 °C.
(i) Name the product formed from the complete oxidation of diamond.
[1]
(ii) Name the product formed from the incomplete oxidation of diamond.
[1]
(iii) Explain whether graphite will form the same products when it is burned.
(g) Draw dot and cross diagrams, using outer electrons only, to show the formation of a carbon dioxide molecule from a carbon atom and an oxygen molecule.
15 Anhydrous copper(II) chloride, CuCl2, may be prepared by heating copper in chlorine gas. When prepared by dissolving copper(II) oxide in hydrochloric acid, copper(II) chloride crystallises with two molecules of water of crystallisation.
(a) Write the equation for the reaction of copper with chlorine.
[1]
(b) Write the equation for the reaction of copper(II) oxide with hydrochloric acid.
[1]
(c) Write the formula for hydrated copper(II) chloride.
[1]
(d) The purity of the copper(II) oxide may be determined by the process of back titration. Explain, without calculations, how this process would be carried out.
(e) The presence of copper in copper(II) chloride can be shown using a flame test.
(i) The diagram below shows the equipment needed for the test. Identify the acid W, the metal wire X, the colour Y of the flame before the test and the colour Z during the test.
WX
YZ
W [1]
X [1]
Y [1]
Z [1]
(ii) State two reasons for using W.
[2]
(iii) Explain the origin of the flame colour produced by copper(II) chloride.
11 Depending on the response of candidates it is likely that two marking points will be needed for each mark awarded.
shapes H–Cl C S N angles 180 109 105 107 dot and cross •
×H Cl •H
HC
HH
ו
× ×•× ×
•× ×
HS× H
× •× × ×
HN
HHוו ו
diagram
apply the following to each compound lone pair v lone pair > lone pair v bond pair > bond pair v bond pair
the electron pairs repel to be as far apart as possible [6]
4 marking points per compound, i.e. shape, electron structure, angle, explanation, i.e. 16 marking points – count number of errors. Apply following: Even number of errors ÷ 2, subtract this from 6 (Odd number of errors –1) ÷ 2, subtract this from 6
Quality of written communication [2] 8
12 (a) (i) 2I– → I2 + 2e oxidation because electrons are lost [1]
(ii) O2 → 2H2O reduction because electrons are gained [1]
(b) 4I– + 4H+ + O2 → 2I2 + 2H2O (electrons left in [–1]) [2]
(c) chlorine [1] iron(III) ions [1] [2]
(d) (i) I– = –1 MnO2 = +4 I2 = 0 MnSO4 = +2 [2]
iodide/iodine is oxidised and manganese is reduced [1] [3]
(ii) violet/purple vapour or grey/black solid at top of test tube [1] 10
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all fifteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all five questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in question 14(b)(i).
In Section A all questions carry equal marks, i.e. two marks for each
ADVANCED SUBSIDIARY (AS)General Certificate of Education
7 Which one of the following molecules contains the smallest bond angle?
A BeCl2 B BF3
C CH4
D SF6
8 5.30 g of anhydrous sodium carbonate was dissolved in water and made up to 250 cm3 in a volumetric flask. Which one of the following is the concentration of sodium ions in mol dm23?
A 0.05 B 0.10 C 0.20 D 0.40
9 Which block in the Periodic Table contains silver?
A d block B f block C p block D s block
10 Which one of the following is involved in metallic bonding?
A electron delocalisation B electron transitions C gaining electrons to form ions D sharing electron pairs
13 Calcium carbonate is present in eggshells. The percentage of calcium carbonate may be determined by a back titration method. The eggshells are crushed, weighed and then treated with excess dilute hydrochloric acid.
CaCO3 1 2HCl → CaCl2 1 H2O 1 CO2
The unreacted acid is then titrated with standard sodium hydroxide solution.
HCl 1 NaOH → NaCl 1 H2O
(a) (i) Explain the term standard solution.
[1]
(ii) Name a suitable indicator for the titration and state the colour change occurring at the end point.
indicator [1]
from
to [2]
(b) A student weighed out 10.0 g of the crushed eggshells and added 100.0 cm3 of 2.0 mol dm23 hydrochloric acid. The resultant solution was transferred to a 250 cm3 volumetric flask and made up to the mark with distilled water. 25.0 cm3 portions of the solution were titrated with 0.10 mol dm23 sodium hydroxide solution. The average titre was found to be 18.0 cm3.
(i) Calculate the number of moles of sodium hydroxide used in the titration.
[1]
(ii) Calculate the number of moles of hydrochloric acid present in the 25.0 cm3 portion.
[1]
(iii) Calculate the number of moles of hydrochloric acid present in the 250 cm3 volumetric flask.
14 The halogens are reactive non-metals which often react by gaining electrons to form halide ions.
(a) Complete the table to show the colours and physical states of chlorine, bromine and iodine at room temperature and pressure.
Halogen Colour Physical State
Chlorine
Bromine
Iodine
[3]
(b) Solutions of silver nitrate and ammonia can be used to test for the presence of aqueous halide ions.
(i) Describe how you would use these reagents to distinguish between solutions of sodium chloride, sodium bromide and sodium iodide. State the expected result for each solution.
[6]
Quality of written communication [2]
(ii) Give an ionic equation, including state symbols, for the reaction of aqueous sodium iodide with silver nitrate solution.
11 (a) (i) number of protons [1] (ii) number of protons + number of neutrons [1]
(iii) atoms with the same number of protons but a different number of neutrons [1]
(b) (i) 12 12 10 17 18 18 error [–1] [2]
(ii)1s 2s 2p 3s 3p
24Mg2+ [1]
35CI– [1]
(iii)
Mg••
•Cl••
••
••Cl
_
••
••Mg 2+ ••
Cl _
••••
•••Cl••
•• ו
ו
×× [4] [–1] each error
(c) (i) The energy required to convert one mole of gaseous ions with a single positive charge into (gaseous) ions with a double positive charge [2]
(ii) Mg+(g) → Mg2+(g) + e– [2]
(iii) electron closer to nucleus [1] less shielded [1] full shell [1] [3]
(d) electrons promoted from ground state/lower energy level to excited state/ higher energy level [1] as the electron drops back down [1] energy given out as (red) light [1] [3] 21
12 (a) number of atoms [1] present in 12.000 g of carbon-12 [1] [2]
(b) (i) moles of X = 0.05 [1] molar mass = 46 g [1] [2]
(ii) NO2 [1]
(c) 3N2O4 + 2H2O → 4HNO3 + 2NO [1]
(d) (i) moles of Mg = 0.25 moles of nitric acid = 0.50 volume of nitric acid = 250 cm3 each error [–1] [3]
(ii) moles of magnesium nitrate formed 0.25 molar mass = 148 mass (g) = 0.25 × 148 = 37g each error [–1] [2] 11
(ii) e.g. phenolphthalein/methyl orange/colourless [1] to pink [1] or red/pink [1] to yellow/orange [1] [3]
(b) (i) 0.0018/1.8 × 10–3 [1]
(ii) 0.0018/1.8 × 10–3 [1]
(iii) 0.018/1.8 × 10–2 [1]
(iv) 0.2 [1]
(v) 0.2 – 0.018 = 0.182 [1]
(vi) 0.091 [1]
(vii) 9.1 g [1]
(viii) 91% [1] 12
14 (a) green/green-yellow/yellow-green gas red-brown liquid grey-black/black solid [3] [–1] for each error
(b) (i) white precipitate for solution of NaCl [1] dissolves in dilute ammonia [1] cream precipitate for solution of NaBr [1] dissolves in concentrated ammonia [1] yellow precipitate for solution of NaI [1] does not dissolve in concentrated ammonia [1] [6]
(vi) the outer electrons in the iodide ions are further from the nucleus/ more shielded [1] iodide ions lose electrons more easily (than chloride ions) [1] [2]
(ii) V-shaped/angular/bent [1] repulsion [1] between lone (electron) pairs and bond pairs [1] [3]
(iii) no lone pairs in methane/only bond pairs in methane [1] [1]
(c) water molecules held together by hydrogen bonding [1] which is stronger than the intermolecular/polar forces between hydrogen sulfide molecules [1] [2] 9
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all sixteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all six questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in question 11(b).
In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements (including some data) is provided.
ADVANCED SUBSIDIARY (AS)General Certificate of Education
For each of the following questions only one of the lettered responses (A–D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
1 Which one of the following is the electronic configuration for the Fe21 ion?
A 1s22s22p63s23p63d44s2
B 1s22s22p63s23p63d54s1
C 1s22s22p63s23p63d64s0
D 1s22s22p63s23p63d64s2
2 Which one of the following lists the first four ionisation energies of a Group II element?
A 584, 1823, 2751, 11584
B 744, 1457, 7739, 10547
C 793, 1583, 3238, 4362
D 1018, 1909, 2918, 4963
3 Which one of the following is the mass of zinc chloride produced when 8.1 g of zinc oxide, ZnO, is added to 150.0 cm3 of 1.0 mol dm23 hydrochloric acid?
A 10.2 g
B 13.6 g
C 20.4 g
D 40.8 g
4 Which one of the following substances has coordinate bonding in its structure?
5 Which one of the following, in the liquid state, has van der Waals’ forces and permanent dipole attractions but not hydrogen bonds between the molecules?
A CH4
B CO
C H2O
D O2
6 Chlorine does not undergo disproportionation when reacted with
A cold dilute sodium hydroxide solution.
B hot concentrated sodium hydroxide solution.
C potassium bromide solution.
D water.
7 Which one of the following solids will react with concentrated sulfuric acid to give hydrogen sulfide?
A Calcium bromide
B Magnesium iodide
C Potassium chloride
D Sodium fluoride
8 For which one of the following titrations would phenolphthalein be a suitable indicator?
12 Caesium is a very reactive metal that has sky blue lines in the visible region of its emission spectrum (from the Latin caesius meaning “sky blue”).
(a) (i) How are the lines in the emission spectrum of caesium formed?
[3]
(ii) Why do the lines in the emission spectrum of caesium converge?
[1]
(b) Caesium has one of the lowest first ionisation energies of all the elements in the Periodic Table.
(i) Write an equation, including state symbols, for the first ionisation of caesium.
[2]
(ii) The frequency at the convergence limit of caesium is 9.41 3 1014 Hz. Calculate the first ionisation energy of caesium in kJ mol21.
[3]
(iii) Give two reasons why the first ionisation energy of caesium is low.
(c) Caesium is so reactive that it will react with gold to form caesium auride, CsAu. The gold can be obtained from caesium auride by reacting it with water. Caesium hydroxide and hydrogen are the other products. Write an equation for the reaction of caesium auride with water.
13 Fluorine is the most electronegative element in the Periodic Table. Although the element is extremely reactive, fluoride ions can be safely added to water supplies and toothpastes.
(a) What is the meaning of the term electronegativity?
[2]
(b) Fluorine reacts with boron to form boron trifluoride.
(i) Draw a dot and cross diagram, using outer shell electrons only, to show the bonding in boron trifluoride.
[2]
(ii) State and explain the shape of a boron trifluoride molecule.
Shape:
Explanation:
[3]
(iii) State the octet rule.
[2]
(iv) Explain whether or not the elements in boron trifluoride obey the octet rule.
(c) Sodium fluoride is added to toothpaste to strengthen tooth enamel.
(i) The data on a 50 g tube of toothpaste states that it contains “1450 ppm fluoride”; ppm means “parts per million” i.e. there would be 1450 g of fluoride ions in 106 (1,000,000) g of toothpaste. Use the following headings to work out the concentration of sodium fluoride in the toothpaste. The density of the toothpaste is 1.6 g cm–3.
Mass of fluoride ions in the 50 g tube
Number of moles of fluoride ions in the 50 g tube
Number of moles of sodium fluoride in the 50 g tube
Volume of toothpaste in the 50 g tube
Concentration of sodium fluoride in the toothpaste with units
[6]
(ii) Sodium fluoride is also added to some public water supplies. Why might some people be opposed to this?
[1]
(iii) Giving practical details, describe how you could prove that a sample of solid sodium fluoride contains sodium ions.
14 Halide ions can be displaced from aqueous solutions of their salts using a more reactive halogen.
(a) A student bubbled excess chlorine into sodium bromide solution and the following reaction took place.
Cl2(g) 1 2NaBr(aq) 2NaCl(aq) 1 Br2(aq)
(i) What change would be observed in the solution?
[2]
(ii) With reference to oxidation numbers explain why this is a redox reaction.
[3]
(iii) Describe how you could prove that there were no bromide ions remaining.
[4]
(b) Hydrogen halides are gases which are very soluble in water forming acidic solutions.
(i) State and suggest an explanation for the strength of hydrofluoric acid relative to the other hydrogen halides.
[2]
(ii) Silicon dioxide is used to make glass. Hydrofluoric acid has to be stored in plastic containers as it reacts with the “silicon dioxide” in glass to produce silicon tetrafluoride and water. Write the equation for this reaction.
15 Magnesium is an s-block metal which exists as the three isotopes, 24Mg, 25Mg and 26Mg in a ratio of 8:1:1. It reacts with oxygen to form magnesium oxide which has a wide variety of uses including cement manufacture and heartburn medication.
(a) (i) Why is magnesium in the s-block of the Periodic Table?
[1]
(ii) Explain the meaning of the term isotope.
[2]
(iii) Calculate the relative atomic mass of magnesium to one decimal place.
[3]
(b) Magnesium oxide can be formed by the combustion of magnesium metal in oxygen.
(i) Draw a dot and cross diagram, using outer shell electrons only, to show how magnesium oxide is formed from a magnesium atom and an oxygen atom.
[3]
(ii) What type of bonding exists in magnesium oxide?
[1]
(iii) State two physical properties of magnesium oxide.
(c) The amount of magnesium oxide in heartburn tablets can be determined by adding a known excess of hydrochloric acid to the tablets.
2HCl(aq) 1 MgO(s) MgCl2(aq) 1 H2O(l)
The amount of unreacted hydrochloric acid is determined by titrating it against sodium hydroxide.
NaOH(aq) 1 HCl(aq) NaCl(aq) 1 H2O(l)
(i) What is this method of titration called?
[1]
(ii) A student added 80 cm3 of 2.0 mol dm23 hydrochloric acid to five crushed heartburn tablets which contained magnesium oxide. The unreacted acid required 25 cm3 of 2.0 mol dm23 sodium hydroxide for complete neutralisation. Use the headings below to calculate the mass, in milligrams, of magnesium oxide in each tablet.
Number of moles of hydrochloric acid added to the tablets
Number of moles of unreacted hydrochloric acid
Number of moles of hydrochloric acid which reacted with the magnesium oxide
Number of moles of magnesium oxide present in five tablets
(b) (i) X: proton to electron ratio increasing or effective nuclear charge increasing [1]; as each electron is removed the remaining electrons are held more tightly [1] [2]
(ii) Y: electron being removed from a full shell [1] closer to nucleus or less/no shielding represents the change in ionisation energy [1] [2]
Quality of written communication [2] 7
12 (a) (i) Electrons in high energy level [1] drop back down [1] emit energy/light [1] [3]
(ii) Energy levels converge [1] (b) (i) Cs(g) → Cs+(g) + e– [2]
(ii) E = (6.63 × 10–34)(9.41 × 1014) = 6.239 × 10–19
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all sixteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all six questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in Question 16(b)(iii).In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of the Elements, containing some data, is included in this question paper.
ADVANCED SUBSIDIARY (AS)General Certificate of Education
12 The emission spectrum for atomic hydrogen has been used to provide evidence for discrete electron energy levels in atoms.
(a) Complete the diagram to show the electron transitions associated with the first two lines of the hydrogen emission spectrum in the visible region.
n 5 5
n 5 4
n 5 3
n 5 2
n 5 1 [2]
(b) The convergence limit of the hydrogen spectrum in the ultraviolet region is at 3.28 3 1015 Hz. Calculate the ionisation energy of hydrogen in kJ mol21.
[3]
(c) The emission spectra of elements give rise to characteristic flame colours. Complete the table below.
13 Wood vinegar, which contains ethanoic acid, is formed when wood is heated. The percentage by mass of ethanoic acid in wood vinegar can be found by titration with standard sodium hydroxide solution.
(a) (i) What is meant by the term standard solution?
[1]
(ii) Write the equation for the reaction between ethanoic acid and sodium hydroxide.
[1]
(b) 25.0 cm3 of wood vinegar were diluted to 250 cm3 in a volumetric flask. 25.0 cm3 of the diluted wood vinegar required 30.3 cm3 of 0.1 mol dm23 sodium hydroxide solution for neutralisation.
(i) How many moles of sodium hydroxide were required?
[1]
(ii) How many moles of ethanoic acid were present in the 25.0 cm3 of diluted wood vinegar?
[1]
(iii) How many moles of ethanoic acid were present in 25.0 cm3 of undiluted wood vinegar?
[1]
(iv) What was the mass of ethanoic acid in the 25.0 cm3 of undiluted wood vinegar?
[1]
(v) What was the percentage of ethanoic acid by mass in the wood vinegar? Assume that the density of wood vinegar is 1.02 g cm23.
(v) Write an equation, including state symbols, for the first ionisation energy of fluorine.
[2]
(vi) Explain the trend in the first ionisation energy of the halogens.
[2]
(b) Chlorine is used to sterilise water.
(i) Write an equation for the reaction of chlorine with water.
[1]
(ii) Using changes in oxidation number explain why this is considered to be a disproportionation reaction.
[3]
(iii) Ultraviolet light does not react with water and is equally effective as chlorine at sterilising water. Suggest the advantages and disadvantages of storing and using chlorine to sterilise water.
IntroductionMark schemes are published to assist teachers and students in their preparation for examinations. Through the mark schemes teachers and students will be able to see what examiners are looking for in response to questions and exactly where the marks have been awarded. The publishing of the mark schemes may help to show that examiners are not concerned about fi nding out what a student does not know but rather with rewarding students for what they do know.
The Purpose of Mark SchemesExamination papers are set and revised by teams of examiners and revisers appointed by the Council. The teams of examiners and revisers include experienced teachers who are familiar with the level and stan-dards expected of students in schools and colleges.
The job of the examiners is to set the questions and the mark schemes; and the job of the revisers is to review the questions and mark schemes commenting on a large range of issues about which they must be satisfi ed before the question papers and mark schemes are fi nalised.
The questions and the mark schemes are developed in association with each other so that the issues of differentiation and positive achievement can be addressed right from the start. Mark schemes, therefore, are regarded as part of an integral process which begins with the setting of questions and ends with the marking of the examination.
The main purpose of the mark scheme is to provide a uniform basis for the marking process so that all the markers are following exactly the same instructions and making the same judgements in so far as this is possible. Before marking begins a standardising meeting is held where all the markers are briefed using the mark scheme and samples of the students’ work in the form of scripts. Consideration is also given at this stage to any comments on the operational papers received from teachers and their organisations. Dur-ing this meeting, and up to and including the end of the marking, there is provision for amendments to be made to the mark scheme. What is published represents this fi nal form of the mark scheme.
It is important to recognise that in some cases there may well be other correct responses which are equally acceptable to those published: the mark scheme can only cover those responses which emerged in the ex-amination. There may also be instances where certain judgements may have to be left to the experience of the examiner, for example, where there is no absolute correct response – all teachers will be familiar with making such judgements.
13 (a) (i) A solution of (accurately) known concentration [1] (ii) CH3COOH + NaOH → CH3COONa + H2
(b) (i) (0.1 × 30.3)/1000 = 3.03 × 10–3 [1]
(ii) 3.03 × 10–3 [1]
(iii) 3.03 × 10–2 [1]
(iv) (3.03 × 10–2) × 60 = 1.82 g units needed [1]
(v) 1.8225 × 1.02 × 100 = 7.14(%) [1]
(c) Phenolphthalein [1] From colourless [1] to pink/red [1] [3] 10
14 (a) p(-block) [1] Outer electrons in the p-orbital [1] [2]
(b) (i) Increasing number of valence/outer/free electrons [1] Greater attraction between these and the (fixed) cations [1] [2]
(ii) Strong covalent bonds [1] throughout a giant structure [1] (reference to ionic bonding [0]) [2]
(iii) S8 → P4 – More atoms/greater mass/more electrons [1] Greater van der Waals forces (between the molecules) [1] [2]
(c) Atomic radius decreases across the Period/from sodium to argon [1] (Outer) electrons are in the same energy level/shielding remains the same [1] Nuclear charge increases causing greater attraction between the nucleus and the (outer) electrons [1] [3] 11
(ii) Cl2 = 0 HOCl = +1 4 oxidation numbers [2] HCl = –1 Cl is both oxidised, 0 → +1 and reduced, 0 → –1 [1] [3]
(iii) Disadvantages: Storing large quantities of chlorine causes problems/ Chlorine poisonous/toxic/ Freedom of choice
Advantages: Chlorine remains in the water after it leaves the treatment plant/ Chlorine gas can be compressed/chlorine is relatively cheap To a maximum of [3] [3]
Write your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all sixteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all six questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATES
The total mark for this paper is 100.Quality of written communication will be assessed in Question 12(d)(iv).
In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements, containing some data, is included in this question paper.
ADVANCED SUBSIDIARY (AS)General Certificate of Education
For each of the following questions only one of the lettered responses (A–D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
1 An element in the Periodic Table has the following successive ionisation energies (kJ mol–1).
590 1145 4912 6474 8144 10496 12320
In which one of the following groups is this element found?
A Group I
B Group II
C Group III
D Group IV
2 Which one of the following is the oxidation number of hafnium in Hf F732?
A 23
B 13
C 24
D 14
3 Boron consists of the isotopes 105B and 11
5B. The relative atomic mass of the element is 10.80. Which one of the following is the approximate ratio of the number of lighter atoms to heavier atoms?
4 Which one of the following equations shows hydrogen peroxide, H2O2, behaving as a reducing agent?
A 2Fe21 1 H2O2 1 2H1 → 2Fe31 1 2H2O
B 2I2 1 H2O2 1 2H1 → I2 1 2H2O
C MnO2 1 2H1 1 H2O2 → Mn21 1 2H2O 1 O2
D PbS 1 4H2O2 → PbSO4 1 4H2O
5 The electronegativity values, not in order, for caesium, cobalt, fluorine and nitrogen are listed below. Which one of the following is the value for the cobalt atom?
A 0.70
B 1.80
C 3.00
D 4.00
6 Which one of the following molecules is linear?
A CH3CH3
B CO2
C H2O2
D H2Te
7 Which one of the following is the reason why water boils at 100 C while the hydrides of the other Group VI elements boil below 0 C?
8 The first ionisation energy is shown against increasing atomic number.
h
g
f
ed
c
b
a
ij
firstionisationenergy
atomic number
Which one of the following shows a Group I element together with a Group VII element?
Group I Group VII
A b f
B b g
C h f
D h g
9 Which one of the following properties is a characteristic of astatine?
A It has an electronegativity value greater than that of iodine.
B It is a solid at room temperature and pressure.
C It oxidises bromide ions to bromine.
D Its hydride exhibits more hydrogen bonding than hydrogen iodide.
10 3.12 g of MCl 2 were dissolved in water and made up to one litre of solution. 25.0 cm3 of this solution reacts with 7.5 cm3 of 0.100 M silver nitrate solution.
12 The creation of the friction match took many years and involved a variety of chemicals based on phosphorus.
The modern match is shown below. The head is a mixture of potassium chlorate, sulfur and phosphorus trisulfide held together by glue. The wood is soaked in ammonium phosphate which acts as a fire retardant.
wood
soaked in ammonium phosphate
potassium chloratesulfurphosphorus trisulfide
(a) Potassium chlorate reacts with the sulfur to form potassium chloride and sulfur dioxide as shown by the following equation.
2KClO3 1 3S → 2KCl 1 3SO2
(i) Deduce the oxidation number for each element in the reactants.
[1]
(ii) Deduce the oxidation number for each element in the products.
[1]
(iii) Explain, using these oxidation numbers, why this is a redox reaction.
[1]
(b) Potassium chlorate, KClO3, is manufactured using the reaction between chlorine and potassium hydroxide.
(i) Write the equation for the reaction.
[2]
(ii) State the conditions under which the reaction is carried out.
13 Francium is found in Group I of the Periodic Table and was discovered by Marguerite Perey in 1939 in the Curie Laboratory in France. It was isolated from uranium ore. Since then it has been synthesised by the nuclear reaction of oxygen atoms with gold atoms. It exists as 34 isotopes.
In the Periodic Table it has an atomic number of 87 and is given a relative atomic mass of 223.
(a) Francium is found in period 7 of the Periodic Table and is regarded as an s-block element.
Suggest the subshell occupied by the outermost electron in a francium atom.
[1]
(b) Francium was first synthesised according to the following equation.
197Au 1 18O → 210Fr 1 5n
The symbol n represents a neutron.
(i) What is the relative mass of a neutron?
[1]
(ii) Using the relative mass of the neutron from part (i) show, by calculation, that the equation is balanced according to mass.
[2]
(iii) Why are electrons not used when balancing the equation according to mass?
(c) Francium is one of the least electronegative elements in the Periodic Table.
(i) Explain the meaning of the term electronegativity.
[2]
(ii) State how electronegativity values change on going across a period.
[1]
(d) Francium has a melting point of 27 C and would melt in the hand just as caesium does. It has the highest electrical conductivity of the alkali metals.
(i) Explain, in terms of metallic bonding, why francium has a low melting point.
[2]
(ii) Explain, in terms of metallic bonding, why francium has the highest electrical conductivity.
15 Iron reacts with dilute hydrochloric acid to form iron(II) chloride, FeCl2, and hydrogen. The solution deposits crystals of hydrated iron(II) chloride.
(a) Write the ionic equation, with state symbols, for the reaction of iron with hydrochloric acid.
[2]
(b) A solution of iron(II) ions is oxidised by chlorine water to form iron(III) ions.
(i) Write the ionic equation for the reaction.
[1]
(ii) Describe the colour of the solution after the reaction has taken place.
[1]
(iii) Explain whether iron(II) ions would react with bromine water.
[1]
(c) Iron(II) chloride is extremely soluble in water. 69 g of the anhydrous solid dissolve in 100 cm3 of water at 20 C. Assuming there is no volume change calculate the molarity of the resulting solution.
Sulfur hexafluoride is the best known and can be used as a safe electrical insulator. The other fluorides are toxic.
(a) Draw the dot and cross diagrams showing the outer electrons only for each of the fluorides.
[3]
(b) (i) State the octet rule.
[2]
(ii) Explain whether sulfur is obeying the octet rule in each fluoride.
[2]
(c) Sulfur difluoride has the same shape as a water molecule but the bond angle is 6 smaller. Draw and name the shape of sulfur difluoride, stating its bond angle.
AgCl white ionic yes yes AgBr cream ionic no yes Agl yellow ionic no no [4] 4
12 (a) (i) K = +1; Cl = +5; O = –2; S = 0 [1]
(ii) K = +1; Cl = –1; O = –2; S = +4 [1]
(iii) Cl oxidation number goes down and S oxidation number goes up [1]
(b) (i) 6KOH + 3Cl2 → KClO3 + 5KCl + 3H2O [2]
(ii) hot and concentrated (potassium hydroxide solution) [1]
(c) (i) P2S3 [1]
(ii) covalent as both elements are non-metals/covalent as small difference in electronegativity between P and S [1]
(iii) phosphorus trioxide or pentoxide/phosphorus oxide [1] sulfur oxide or sulfur dioxide [1] [2]
(d) (i) NH4+ [1]
(ii) tetrahedral [1] 109º/109.5° [1]
H
N
HH H
[1] [3]
(iii) (NH4)3PO4/PO4(NH4)3 [1]
(iv) melting point which is high because of attraction between ions [1] boiling point which is high because of attraction between ions [1] electrical conductivity which is high in solution or molten because ions can move [1] solubility, ions are surrounded by H2O molecules [1] 3 from 4 [3]
INSTRUCTIONS TO CANDIDATESWrite your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all fifteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all five questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATESThe total mark for this paper is 100.Quality of written communication will be assessed in Question 12(b).In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of the Elements, containing some data, is included in this question paper.
ADVANCED SUBSIDIARY (AS)General Certificate of Education
For each of the following questions only one of the lettered responses (A–D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
1 Which one of the following is not a redox reaction?
A 2Ca(NO 3)2 → 2CaO 4NO2 O2
B Cl2 2I− → I2 2Cl−
C Fe Cu2 → Fe2 Cu
D H2SO4 2NaOH → Na2SO4 2H2O
2 The graph of first ionisation energy against atomic number for a series of ten consecutive elements in the Periodic Table is shown below. Which one of the following indicates a Group II metal and a halogen?
3 Which one of the following is the strongest reducing agent?
A F−
B F2
C I−
D I2
4 4.35 g of potassium sulfate is dissolved in water and made up to 50.0 cm3. Which one of the following is the concentration of potassium ions in this solution?
A 0.025 mol dm–3
B 0.500 mol dm–3
C 0.644 mol dm–3
D 1.000 mol dm–3
5 Which one of the following describes the trend in bond energies of the halogen molecules down Group VII?
A Decreases
B Decreases to bromine then increases
C Increases
D Increases to chlorine then decreases
6 When 0.28 g of a basic oxide, MO, is reacted with 250 cm3 of 0.05 mol dm–3 hydrochloric acid the excess acid required 50 cm3 of 0.05 mol dm–3 sodium hydroxide solution for neutralisation. Which one of the following is the relative atomic mass of M?
7 Which one of the following diagrams represents the distribution of electrons in the 3d and 4s subshells in the ground state of an iron(III) ion?
A 1
1
1
1
1
B 1 1 1 1 1
C 1
1
1 1
1
D 1 1 1 1
1
8 Which one of the following describes the reaction between solid sodium chloride and concentrated sulfuric acid?
A Disproportionation
B Exothermic
C Neutralisation
D Redox
9 Chlorine was bubbled through a pale green solution causing the solution to turn yellow/orange. Which one of the following ions was in the original solution?
12 Phosphorus is a non-metal with a low melting point. It reacts explosively with liquid bromine and more gently with bromine vapour. In each case phosphorus tribromide is formed.
(a) (i) Write an equation for the reaction of phosphorus, P4, with bromine.
[2]
(ii) State the octet rule and explain whether or not phosphorus obeys the octet rule in phosphorus tribromide.
[3]
(b) The melting points of silicon, phosphorus and sulfur are given in the table below.
element Si P4 S8
melting point/°C 1410 44 113
With reference to the structures of silicon and sulfur explain why each has a higher melting point than phosphorus.
13 Sodium is a reactive, soft, silvery metal. Chlorine is a poisonous gas. The two react together to form sodium chloride that is essential to our diet.
(a) (i) Using a labelled diagram explain the bonding in sodium metal.
[3]
(ii) Metals are good conductors of electricity. Explain why the electrical conductivity of aluminium is greater than that of sodium.
[2]
(b) What type of structure is present in the element chlorine?
[1]
(c) (i) Draw dot and cross diagrams to show how sodium bonds with chlorine gas. Only outer shell electrons should be shown.
14 Bromine tablets are used as a disinfectant in hot tubs and some swimming pools because of bromine’s ability to act as an oxidising agent.
(a) Bromine reacts with water in a similar way to chlorine.
(i) Suggest the equation for the reaction of bromine with water.
[1]
(ii) Using oxidation numbers explain why this reaction is an example of disproportionation.
[3]
(b) Manufacturers recommend maintaining the bromine concentration in swimming pools at 4 mg per litre. Calculate the molarity of bromine, Br2, in the water at this concentration.
[2]
(c) Occasionally a ‘shock treatment’ with chlorine is required to further disinfect the water.
(i) Suggest, in chemical terms, why chlorine is used for this purpose.
[1]
(ii) The compound used to provide the chlorine for the shock treatment is “sodium dichlor”, NaCl2C3N3O3. Calculate the percentage of chlorine in “sodium dichlor” to one decimal place.
(d) Bromine is produced from the reaction of sodium bromide with concentrated sulfuric acid. Name four other products formed when sodium bromide reacts with concentrated sulfuric acid.
(ii) Describe how the movement of an electron within an atom gives rise to a line in an emission spectrum.
[3]
(iii) What flame colour is observed when calcium burns?
[1]
(iv) Using the following headings and the first ionisation energy of calcium, 590 kJ mol–1, calculate the frequency of the convergence limit of a calcium atom and state its units.
Energy, in joules, required to ionise one calcium atom
[2]
Frequency of the convergence limit of a calcium atom
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2015
ChemistryAssessment Unit AS 1
assessingBasic Concepts in Physical
and Inorganic Chemistry
[AC112]
WEDNESDAY 10 JUNE, AFTERNOON
9453.01 F 2 [Turn over
General Marking Instructions
IntroductionMark schemes are published to assist teachers and students in their preparation for examinations. Through the mark schemes teachers and students will be able to see what the examiners are looking for in response to questions and exactly where the marks have been awarded. The publishing of the mark schemes may help to show that examiners are not concerned about fi nding out what a student does not know but rather with rewarding students for what they do know.
The purpose of mark schemesExamination papers are set and revised by teams of examiners and revisers appointed by the Council. The teams of examiners and revisers include experienced teachers who are familiar with the level and standards expected of students in schools and colleges.
The job of the examiners is to set the questions and the mark schemes; and the job of the revisers is to review the questions and mark schemes commenting on a large range of issues about which they must be satisfi ed before the question papers and mark schemes are fi nalised.
The questions and the mark schemes are developed in association with each other so that the issues of differentiation and positive achievement can be addressed right from the start. Mark schemes, therefore, are regarded as part of an integral process which begins with the setting of questions and ends with the marking of the examination.
The main purpose of the mark scheme is to provide a uniform basis for the marking process so that all the markers are following exactly the same instructions and making the same judgements in so far as this is possible. Before marking begins a standardising meeting is held where all the markers are briefed using the mark scheme and samples of the students’ work in the form of scripts. Consideration is also given at this stage to any comments on the operational papers received from teachers and their organisations. During this meeting, and up to and including the end of the marking, there is provision for amendments to be made to the mark scheme. What is published represents the fi nal form of the mark scheme.
It is important to recognise that in some cases there may well be other correct responses which are equally acceptable to those published: the mark scheme can only cover those responses which emerged in the examination. There may also be instances where certain judgements may have to be left to the experience of the examiner, for example where there is no absolute correct response – all teachers will be familiar with making such judgements.
9453.01 F 3
AVAILABLEMARKS
Section A
1 B
2 B
3 C
4 A
5 D
6 C
7 C
8 D
9 A
10 C [2] for each correct answer [20] 20
Section A 20
9453.01 F 4 [Turn over
AVAILABLEMARKS
Section B
11 (a) 2K + BeCl2 → 2KCl + Be [1]
(b) Be + Cl2 → BeCl2 [1] Be + 2HCl → BeCl2 + H2 [1]
(c) (i) the electrons in the bonds [1] repel equally [1] linear [1] [3] (ii) BeCl2: red, pH 0–2/strongly acidic. NaCl: green, pH 7/neutral solution. [4]
Quality of written communication [2] (d) (i) no, there are 6 electrons [1] (ii) yes, there are 8 electrons [1] (iii) electron pair donated by one atom to form a bond [2]
(iv) covalent or dipole-dipole bonds need to be broken [1] Needs energy to break bonds [1] 18
(v) ammonia – 1 lone pair amide ion – 2 lone pairs4 both needed for [1] lone pair–lone pair repulsion on amide [1] > lone pair–bond pair repulsion on ammonia/pushes bond pairs closer/reduces bond angles [1] [3] 14
N
HH
• • • •
9453.01 F 6 [Turn over
AVAILABLEMARKS
AVAILABLEMARKS14 (a) (i) 234 × 103
58.5 = 4 × 103
NaCl : NaHCO3 1 : 1 Moles of NaHCO3 = 4 × 103 [–1] for each error [2]
(ii) NaHCO3 : Na2CO3 2 : 1 Moles of Na2CO3 = 2 × 103
Mass of Na2CO3 = 2 × 103 × 106 = 212 kg [–1] for each error [2]
(b) (i) 24.31000 × 0.2 = 4.86 × 10–3 [1]
(ii) moles of Na2CO3 = 4.86 × 10–3 [1]
(iii) moles of Na2CO3 in 250 cm3 = 4.86 × 10–2 [1] (iv)
4.86 ×106.00
2- = 123.50 [1]
(v) 106 [1]
(vi) 106 + 18x = 123.50 x = 1 [1]
δ+ δ– δ– δ+
(c) (i) C═O O─H
[1] for each [2]
(ii) dipoles cancel out/molecule is symmetrical [1]
(iii) Sufficient energy at 100°C [1] to break the hydrogen bonds [1]. [2] 15
9453.01 F 7
AVAILABLEMARKS
15 (a) (i) The extent to which an atom attracts the bonding electrons in a covalent bond. [2] (ii) As Group is descended the atomic radius increases Therefore (force of) attraction from nucleus to bonding electrons decreases [2]
(iii) Moving from HCl to HI the molecules increase in RFM/mass/no. of electrons Increased strength of van der Waals forces [2]
(iv) Between molecules of HF there are (van der Waals forces and) H-bonds H-bonds (are much stronger and) require (a lot) more energy to break 2nd mark dependent on first [2]
(v) HF < HCl < HBr < HI, H–I lowest bond energy – both needed [1]
(b) (i) yellow/orange/brown to colourless
(ii) Disproportionation is the simultaneous oxidation and reduction of the same species [2] Oxidation of Br2 to BrO–, 0 → +1 Reduction of Br2 to Br–, 0 → –1 (Both required for second mark) [2]
(iii) 3Br2 + 6OH– → 5Br– + BrO3– + 3H2O [2]
(c) (i) N is potassium iodide [1]
(ii) O is potassium bromide [1] P is bromine gas [1] Q and R are sulfur dioxide and hydrogen bromide [2] 22
Section B 80
Total 100
TIME1 hour 30 minutes.
INSTRUCTIONS TO CANDIDATESWrite your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all fifteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all five questions in Section B. Write your answers in the spaces provided in this question paper.
INFORMATION FOR CANDIDATESThe total mark for this paper is 100.Quality of written communication will be assessed in Question 11(c)(ii).In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements, containing some data, is included in this question paper.9453.05R
For Examiner’suse only
Question Number Marks
Section A 1–10
Section B1112131415
TotalMarks
*ac112*
AC
112
Centre Number
Candidate Number
Chemistry
Assessment Unit AS 1assessing
Basic Concepts in Physicaland Inorganic Chemistry
[AC112]WEDNESDAY 10 JUNE, AFTERNOON
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2015
9453.05R 2
Section A
For each of the following questions only one of the lettered responses (A–D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
1 Potassium dichromate has the formula K2Cr2O7. Which one of the following lists the oxidation numbers of potassium and chromium in potassium dichromate?
potassium chromiumA 11 13
B 11 16
C 12 13
D 12 16
2 There are three bonding pairs and one lone pair of electrons around the central phosphorus atom in phosphine (PH3). Which one of the following describes the shape of the phosphine molecule?
A Bent
B Pyramidal
C Tetrahedral
D Trigonal planar
3 Which one of the following statements represents how the visible emission line spectrum of atomic hydrogen arises?
A Energy is given out when hydrogen atoms lose electrons to form ions
B Energy is given out when electrons move from higher energy levels to the n51 energy level
C Energy is given out when electrons move from higher energy levels to the n52 energy level
D Energy is given out when electrons move from the n51 energy level to higher energy levels
9453.05R 3 [Turn over
4 The table below shows the first six successive ionisation energies for a Period 2 element.
first second third fourth fifth sixth
Ionisation Energy/ kJ mol21
1090 2350 4610 6220 37800 47000
Which one of the following elements has these ionisation energies?
A Carbon
B Fluorine
C Nitrogen
D Oxygen
5 Which one of the following elements forms an ion with a double negative charge that has the same electronic configuration as argon?
A Calcium
B Chlorine
C Selenium
D Sulfur
6 Boron trichloride reacts with water to form a strongly acidic solution as shown below.
BCl3 1 3H2O → H3BO3 1 3HCl
When 21.6 g of BCl3 is dissolved in 250 cm3 of water the concentration of the hydrochloric acid in this solution is
A 0.55 mol dm23.
B 0.74 mol dm23.
C 2.21 mol dm23.
D 2.94 mol dm23.
9453.05R 4
7 The chlorate(V) ion, ClO32, may be reduced to chlorine.
2ClO32(aq) 1 xH+(aq) 1 ye2 → Cl2(aq) 1 zH2O(l)
Which one of the following represents the correct values of x, y and z?
x y z
A 6 6 3
B 6 4 3
C 12 10 6
D 12 12 6
8 Which one of the following is the most powerful reducing agent?
A Bromine atom
B Chlorine atom
C Fluoride ion
D Iodide ion
9 Which one of the following elements would be expected to form the smallest ion with a noble gas configuration?
A Aluminium
B Chlorine
C Sodium
D Sulfur
9453.05R 5 [Turn over
10 Which one of the following equations represents the first ionisation energy of fluorine?
A F2(g) 1 2e2 → 2F2(g)
B F(g) 1 e2 → F2(g)
C F(g) → F1(g) + e2
D F2(g) → 2F1(g) 1 2e2
Examiner OnlyMarks Remark
9453.05R 6
Section B
Answer all five questions in this section.
11 Beryllium is a hard silver-white metal which was first isolated by Wöhler in 1828 by the reaction of potassium with beryllium chloride. Potassium being more reactive than beryllium gave a metallic solid in a strongly exothermic process.
(a) Write the equation for the reaction of potassium with beryllium chloride.
[1]
(b) Beryllium chloride can be prepared by the reaction of beryllium with chlorine or hydrogen chloride. Write equations for both of these reactions.
[2]
(c) Beryllium chloride is a covalent molecule with a melting point of 400 °C. Its electronic structure is shown below.
Be Cl•X
X X
X X
XXCl •
X
X X
X X
XX
It reacts vigorously with water.
BeCI2 + 2H2O → Be(OH)2 + 2HCI
(i) Name and explain the shape of the beryllium chloride molecule.
[3]
Examiner OnlyMarks Remark
9453.05R 7 [Turn over
(ii) Beryllium chloride and sodium chloride are separately added to water. Describe and explain what is observed when Universal Indicator is added to each solution.
[4]
Quality of written communication [2]
(d) The high melting point of beryllium chloride is explained by its polymeric structure. Part of the polymeric structure is shown below:
CIX X
XX
XX
CIX X
X •
XX
XX
BeX •
CIX X
X •
XX
XX
BeX •
CIX X
XX
XX
(i) Explain whether beryllium, in the polymeric structure, obeys the octet rule.
[1]
(ii) Explain whether chlorine, in the polymeric structure, obeys the octet rule.
[1]
Examiner OnlyMarks Remark
9453.05R 8
(iii) Some of the chlorine atoms in the polymeric structure are forming coordinate bonds. Explain this term.
[2]
(iv) Explain why the polymeric structure has a high melting point.
[2]
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(Questions continue overleaf)
9453.05R 9 [Turn over
Examiner OnlyMarks Remark
9453.05R 10
12 A sample of iron from a meteorite was found to contain the following isotopes: 54Fe, 56Fe and 57Fe.
(a) (i) Complete the table to show the number of protons, neutrons and electrons that are present in each of the isotopes.
isotope protons neutrons electrons54Fe56Fe57Fe
[3]
(ii) From the mass spectrum the relative abundances of the isotopes in this sample of iron were found to be as follows:
m/z ratio 54 56 57
% abundance 5.8 91.6 2.6
Calculate the relative atomic mass of iron to one decimal place.
[2]
(iii) Explain the difference, if any, in the chemical properties of the isotopes of iron.
[1]
(b) (i) Write the electronic configuration of an Fe21 ion.
[1]
(ii) When chlorine gas is bubbled through a solution of Fe21 ions, oxidation to Fe31 ions occurs. Write an equation for this reaction.
[2]
Examiner OnlyMarks Remark
9453.05R 11 [Turn over
(iii) With reference to s,p,d notation explain the stability of the Fe31 ion relative to the Fe21 ion.
[2]
Examiner OnlyMarks Remark
9453.05R 12
13 The combustion of Group I metals forms their oxides. Depending on the reaction conditions sodium can form the peroxide, Na2O2.
(a) (i) Write an equation for the reaction of sodium with oxygen to form
the peroxide.
[1]
(ii) At higher temperatures and pressures a different oxide Y is formed. One mole of Y contains the Avogadro number of O2- ions and 1.2 3 1024 Na1 ions. Deduce the formula of Y.
[1]
(b) If a large amount of energy is supplied to sodium vapour it ionises. The 1st ionisation energy for sodium is 500 kJ mol21. Calculate the
wavelength of energy absorbed in nm by the sodium vapour.
(1 nm = 1 3 1029 m c 5 3.0 3 108 m s21)
[4]
(c) When strongly heated sodium reacts with ammonia to form sodium amide, NaNH2, and hydrogen.
(i) Write the equation for the reaction between sodium and ammonia.
[1]
Examiner OnlyMarks Remark
9453.05R 13 [Turn over
(ii) Use the boxes below to give the electronic configuration of the N atom and the N2 ion.
1s 2s 2p
N
N-
[2]
(iii) Draw the shape of an amide ion, NH22, showing any lone pairs of
electrons.
[1]
(iv) Name the shape of the amide ion.
[1] (v) Explain, in terms of electron pair repulsion, why the bond angle in
an amide ion is smaller than the bond angle in an ammonia molecule.
[3]
Examiner OnlyMarks Remark
9453.05R 14
14 Sodium carbonate is manufactured by the Solvay process. This is a two stage process.
STAGE 1 Sodium hydrogencarbonate is formed.
NaCl 1 NH3 1 CO2 1 H2O → NaHCO3 1 NH4Cl
STAGE 2 Sodium hydrogencarbonate is then thermally decomposed.
2NaHCO3 → Na2CO3 1 H2O 1 CO2
(a) (i) Calculate the number of moles of sodium hydrogencarbonate formed from 234 kg of sodium chloride.
[2]
(ii) Calculate the maximum mass of sodium carbonate formed in kg.
[2]
(b) Sodium carbonate can form a number of hydrates of formula Na2CO3.xH2O. A 6.0 g sample of hydrated sodium carbonate was dissolved in water and the solution made up to 250 cm3. A 25.0 cm3 portion of this solution required 24.3 cm3 of 0.2 mol dm23 sulfuric acid for complete reaction.
Na2CO3 1 H2SO4 → Na2SO4 1 H2O 1 CO2
(i) Calculate the number of moles of sulfuric acid required for complete reaction.
[1]
(ii) Deduce the number of moles of sodium carbonate in 25.0 cm3 of the solution.
[1]
Examiner OnlyMarks Remark
9453.05R 15 [Turn over
(iii) Calculate the number of moles of sodium carbonate in 250 cm3 of solution.
[1]
(iv) Calculate the relative formula mass of the hydrated sodium carbonate.
[1]
(v) Calculate the relative formula mass of anhydrous sodium carbonate.
[1]
(vi) Calculate the value of x.
[1]
(c) Water and carbon dioxide both contain polar bonds.
(i) Show the polarity of the carbon2oxygen bond and the oxygen2hydrogen bond on the bonds drawn below.
C O O H
[2]
(ii) Suggest why the carbon dioxide molecule is non-polar.
[1]
(iii) Explain why water changes to a gas at 100 °C.
[2]
Examiner OnlyMarks Remark
9453.05R 16
15 The table below shows some data about the halogens, Group VII.
element electronegativity boiling point of hydrogen halide/K
bond energy of hydrogen halide/kJ mol21
fluorine 4.0 293 568
chlorine 3.0 188 431
bromine 2.8 206 366
iodine 2.5 238 299
(a) (i) Define the term electronegativity.
[2]
(ii) Explain the trend in electronegativity as the group is descended.
[2]
(iii) Explain the trend in boiling point from hydrogen chloride to hydrogen iodide.
[2]
(iv) Explain why hydrogen fluoride does not follow this trend.
[2]
(v) State and explain the order of increasing acid strength of equimolar solutions of the hydrogen halides.
[1]
Examiner OnlyMarks Remark
9453.05R 17
(b) Bromine water reacts with cold, dilute alkali as shown below:
Br2(aq) 1 2OH2(aq) → Br2(aq) 1 BrO2(aq) 1 H2O(l)
(i) State the colour change observed during this reaction.
[2]
(ii) State the oxidation states of bromine in the reaction and use them to explain why this reaction is an example of disproportionation.
[4]
(iii) Write the ionic equation for the reaction of bromine with hydroxide ions to produce bromate(V), BrO3
2, ions.
[2]
(c) Use the information below to identify N, O, P, Q and R.
(i) When silver nitrate solution is added to a solution of a potassium halide, N, a yellow solid is formed.
N is [1]
(ii) When concentrated sulfuric acid is added to a solid potassium halide O, a red-brown gas P and two colourless gases Q and R are formed.
O is
P is
Q is
R is [4]
THIS IS THE END OF THE QUESTION PAPER
182761
Permission to reproduce all copyright material has been applied for.In some cases, efforts to contact copyright holders may have been unsuccessful and CCEAwill be happy to rectify any omissions of acknowledgement in future if notified.
MARKSCHEME
9453.01 F
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2015
ChemistryAssessment Unit AS 1
assessingBasic Concepts in Physical
and Inorganic Chemistry
[AC112]
WEDNESDAY 10 JUNE, AFTERNOON
9453.01 F 2 [Turn over
General Marking Instructions
IntroductionMark schemes are published to assist teachers and students in their preparation for examinations. Through the mark schemes teachers and students will be able to see what the examiners are looking for in response to questions and exactly where the marks have been awarded. The publishing of the mark schemes may help to show that examiners are not concerned about fi nding out what a student does not know but rather with rewarding students for what they do know.
The purpose of mark schemesExamination papers are set and revised by teams of examiners and revisers appointed by the Council. The teams of examiners and revisers include experienced teachers who are familiar with the level and standards expected of students in schools and colleges.
The job of the examiners is to set the questions and the mark schemes; and the job of the revisers is to review the questions and mark schemes commenting on a large range of issues about which they must be satisfi ed before the question papers and mark schemes are fi nalised.
The questions and the mark schemes are developed in association with each other so that the issues of differentiation and positive achievement can be addressed right from the start. Mark schemes, therefore, are regarded as part of an integral process which begins with the setting of questions and ends with the marking of the examination.
The main purpose of the mark scheme is to provide a uniform basis for the marking process so that all the markers are following exactly the same instructions and making the same judgements in so far as this is possible. Before marking begins a standardising meeting is held where all the markers are briefed using the mark scheme and samples of the students’ work in the form of scripts. Consideration is also given at this stage to any comments on the operational papers received from teachers and their organisations. During this meeting, and up to and including the end of the marking, there is provision for amendments to be made to the mark scheme. What is published represents the fi nal form of the mark scheme.
It is important to recognise that in some cases there may well be other correct responses which are equally acceptable to those published: the mark scheme can only cover those responses which emerged in the examination. There may also be instances where certain judgements may have to be left to the experience of the examiner, for example where there is no absolute correct response – all teachers will be familiar with making such judgements.
9453.01 F 3
AVAILABLEMARKS
Section A
1 B
2 B
3 C
4 A
5 D
6 C
7 C
8 D
9 A
10 C [2] for each correct answer [20] 20
Section A 20
9453.01 F 4 [Turn over
AVAILABLEMARKS
Section B
11 (a) 2K + BeCl2 → 2KCl + Be [1]
(b) Be + Cl2 → BeCl2 [1] Be + 2HCl → BeCl2 + H2 [1]
(c) (i) the electrons in the bonds [1] repel equally [1] linear [1] [3] (ii) BeCl2: red, pH 0–2/strongly acidic. NaCl: green, pH 7/neutral solution. [4]
Quality of written communication [2] (d) (i) no, there are 6 electrons [1] (ii) yes, there are 8 electrons [1] (iii) electron pair donated by one atom to form a bond [2]
(iv) covalent or dipole-dipole bonds need to be broken [1] Needs energy to break bonds [1] 18
(v) ammonia – 1 lone pair amide ion – 2 lone pairs4 both needed for [1] lone pair–lone pair repulsion on amide [1] > lone pair–bond pair repulsion on ammonia/pushes bond pairs closer/reduces bond angles [1] [3] 14
N
HH
• • • •
9453.01 F 6 [Turn over
AVAILABLEMARKS
AVAILABLEMARKS14 (a) (i) 234 × 103
58.5 = 4 × 103
NaCl : NaHCO3 1 : 1 Moles of NaHCO3 = 4 × 103 [–1] for each error [2]
(ii) NaHCO3 : Na2CO3 2 : 1 Moles of Na2CO3 = 2 × 103
Mass of Na2CO3 = 2 × 103 × 106 = 212 kg [–1] for each error [2]
(b) (i) 24.31000 × 0.2 = 4.86 × 10–3 [1]
(ii) moles of Na2CO3 = 4.86 × 10–3 [1]
(iii) moles of Na2CO3 in 250 cm3 = 4.86 × 10–2 [1] (iv)
4.86 ×106.00
2- = 123.50 [1]
(v) 106 [1]
(vi) 106 + 18x = 123.50 x = 1 [1]
δ+ δ– δ– δ+
(c) (i) C═O O─H
[1] for each [2]
(ii) dipoles cancel out/molecule is symmetrical [1]
(iii) Sufficient energy at 100°C [1] to break the hydrogen bonds [1]. [2] 15
9453.01 F 7
AVAILABLEMARKS
15 (a) (i) The extent to which an atom attracts the bonding electrons in a covalent bond. [2] (ii) As Group is descended the atomic radius increases Therefore (force of) attraction from nucleus to bonding electrons decreases [2]
(iii) Moving from HCl to HI the molecules increase in RFM/mass/no. of electrons Increased strength of van der Waals forces [2]
(iv) Between molecules of HF there are (van der Waals forces and) H-bonds H-bonds (are much stronger and) require (a lot) more energy to break 2nd mark dependent on first [2]
(v) HF < HCl < HBr < HI, H–I lowest bond energy – both needed [1]
(b) (i) yellow/orange/brown to colourless
(ii) Disproportionation is the simultaneous oxidation and reduction of the same species [2] Oxidation of Br2 to BrO–, 0 → +1 Reduction of Br2 to Br–, 0 → –1 (Both required for second mark) [2]
(iii) 3Br2 + 6OH– → 5Br– + BrO3– + 3H2O [2]
(c) (i) N is potassium iodide [1]
(ii) O is potassium bromide [1] P is bromine gas [1] Q and R are sulfur dioxide and hydrogen bromide [2] 22
Section B 80
Total 100
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2016
ChemistryAssessment Unit AS 1assessingBasic Concepts in Physicaland Inorganic Chemistry
[AC112]TUESDAY 14 JUNE, AFTERNOON
TIME1 hour 30 minutes.
INSTRUCTIONS TO CANDIDATESWrite your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all eighteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all eight questions in Section B. You must answer the questions in the spaces provided.Do not write outside the boxed area on each page or on blank pages.Complete in blue or black ink only. Do not write with a gel pen.
INFORMATION FOR CANDIDATESThe total mark for this paper is 100.Quality of written communication will be assessed in Question 12(a).In Section A all questions carry equal marks, i.e. two marks for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements, containing some data, is included in this question paper.
*24AC11201*
*24AC11201*
Centre Number
Candidate Number
10120
*AC112*
*AC112*
10120 AC112 XXX 2016.indd 1 29/04/2016 10:45:12
*24AC11202*
*24AC11202*
10120
Section A
For each of the following questions only one of the lettered responses (A–D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
1 Which one of the following shows how many electron pairs can be accommodated in the third energy level, n = 3, of an atom?
A 3
B 6
C 9
D 18
2 Which one of the following molecules contains a total of six bonding electrons?
A C2H4
B CO2
C NH3
D SF6
3 Which one of the following molecules is not polar?
A CHCl3
B CH3OCH3
C CO2
D SO2
10120 AC112 XXX 2016.indd 2 29/04/2016 10:45:13
*24AC11203*
*24AC11203*
10120[Turn over
4 An element X has the following ionisation energies:
1st 2nd 3rd 4th 5th 6th
ionisation energy/kJ mol21
738 1451 7733 10543 13630 18020
Which one of the following is the formula of the chloride of X?
A XCl
B XCl2
C XCl3
D XCl4
5 A salt gives a pink flame in a flame test when observed through cobalt glass. A solution of the salt gives a cream precipitate when added to acidified silver nitrate solution. Which one of the following is the salt?
A Potassium bromide
B Potassium chloride
C Sodium bromide
D Sodium chloride
6 Which one of the following indicators is not suitable for the acid-base titration shown?
0.1 M acid 0.2 M base indicator
A ethanoic acid ammonia solution phenolphthalein
B ethanoic acid sodium hydroxide solution phenolphthalein
C hydrochloric acid ammonia solution methyl orange
D hydrochloric acid sodium hydroxide solution methyl orange
10120 AC112 XXX 2016.indd 3 29/04/2016 10:45:13
*24AC11204*
*24AC11204*
10120
7 Iron can be extracted from iron(III) oxide using carbon according to the following equation:
2Fe2O3 1 3C → 4Fe 1 3CO2
Which one of the following is the maximum mass of iron that can be extracted from a mixture of 150.0 tonnes of iron(III) oxide and 15.0 tonnes of carbon?
A 26.3 tonnes
B 52.6 tonnes
C 93.3 tonnes
D 105.3 tonnes
8 The atomic emission spectrum of hydrogen for the visible region is shown below:
X
frequency
Which one of the labelled transitions is responsible for line X in the spectrum?
A B C D
n 5 6n 5 5
n 5 4
n 5 3
n 5 2
n 5 1
10120 AC112 XXX 2016.indd 4 29/04/2016 10:45:14
*24AC11205*
*24AC11205*
10120[Turn over
9 A sample of hydrated sodium sulfate contains 56%, by mass, of water. What is the formula of the hydrated sodium sulfate?
A Na2SO4.H2O
B Na2SO4.6H2O
C Na2SO4.10H2O
D Na2SO4.12H2O
10 A cup of coffee contains 500 mg of caffeine which has the chemical formula C8H10N4O2. Which one of the following is the number of nitrogen atoms present in this amount of caffeine?
A 1.55 3 1021
B 6.21 3 1021
C 1.55 3 1024
D 6.21 3 1024
10120 AC112 XXX 2016.indd 5 29/04/2016 10:45:14
*24AC11206*
*24AC11206*
10120
Section B
Answer all eight questions in this section.
11 Complete the following table for the ions of three elements, A, B and C.
ion atomic number electronic structure of ion
A31 5
B2 1s22s22p63s23p63d104s24p6
C22 16
[3]
12 The 2010 Nobel Prize for Physics was awarded for the discovery of a new material called graphene. It consists of a single layer of carbon atoms obtained from graphite.
(a) Describe the structure and bonding of graphite. Include an explanation why graphite can conduct electricity.
[4]
Quality of written communication [2]
10120 AC112 XXX 2016.indd 6 29/04/2016 10:45:15
*24AC11207*
*24AC11207*
10120[Turn over
(b) Explain why graphene, like graphite, has a high melting point.
[2]
10120 AC112 XXX 2016.indd 7 29/04/2016 10:45:16
*24AC11208*
*24AC11208*
10120
13 In 1937 the American scientists Taylor and Crist investigated the decomposition of gaseous hydrogen iodide. The hydrogen iodide was heated in a sealed quartz tube.
2HI(g) ? H2(g) 1 I2(g)
(a) Taylor and Crist were able to measure the progress of the decomposition by measuring colour intensity.
(i) State the colour of iodine gas.
[1]
(ii) Suggest what would be observed if this experiment was to be repeated with samples of hydrogen chloride and hydrogen bromide.
[2]
(iii) Explain the difference in observations between hydrogen chloride and hydrogen bromide.
[1]
(b) Hydrogen iodide dissolves in water to form hydriodic acid which is a strong acid.
(i) Explain whether hydriodic acid is a stronger or weaker acid than hydrochloric acid.
[2]
(ii) Suggest an equation for the reaction between sodium carbonate and hydriodic acid.
[2]
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*24AC11209*
*24AC11209*
10120[Turn over
(c) The boiling points of the hydrogen halides at atmospheric pressure are shown below:
hydrogen halide boiling point/°C
HF 19.9
HCl 285.0
HBr 266.7
HI 235.4
Explain why hydrogen iodide has a higher boiling point than hydrogen chloride.
[2]
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*24AC11210*
*24AC11210*
10120
14 The hydrogen atom contains one electron and is difficult to place in a particular group in the Periodic Table. It could be in either Group I or Group VII.
(a) Suggest reasons, with reference to electron structure, why hydrogen could be placed in Group I or Group VII.
(i) Group I
[1]
(ii) Group VII
[1]
(b) Hydrogen, like the halogens, exists as diatomic molecules. However, it is much less reactive because it has a stronger covalent bond than any of the halogens.
(i) State the trend in bond energy of the halogen molecules.
[2]
(ii) Suggest why hydrogen has a higher bond energy than any of the halogen molecules.
[1]
10120 AC112 XXX 2016.indd 10 29/04/2016 10:45:17
*24AC11211*
*24AC11211*
10120[Turn over
(c) Hydrogen reacts with sodium to form sodium hydride. Ions are formed in a similar manner to sodium and chloride ions.
(i) Complete the following diagram to show how the ions are arranged in a sodium chloride lattice.
Sodium chloride
Na1
[1]
(ii) Draw a dot and cross diagram, using outer electrons only, to show the reaction between sodium and hydrogen atoms to form sodium hydride.
[3]
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*24AC11212*
*24AC11212*
10120
(iii) Sodium hydride is a powerful reducing agent and will react with water to form sodium hydroxide and hydrogen. Write an equation for this reaction.
[1]
(iv) 0.44 g of sodium hydride is reacted with 75 cm3 of water.
Calculate the number of moles of sodium hydride.
Calculate the number of moles of sodium hydroxide formed.
Calculate the molarity of the sodium hydroxide solution.
[3]
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*24AC11213*
*24AC11213*
10120
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DO NOT WRITE ON THIS PAGE
(Questions continue overleaf)
[Turn over
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*24AC11214*
10120
15 Chlorine has many industrial uses, particularly as a bleaching agent. It is used to bleach wood pulp in paper manufacture and to remove ink from paper which is to be recycled.
(a) Chlorine has two stable isotopes 35Cl and 37Cl present in nature in the following proportions.
isotope abundance35Cl 75.78 %37Cl 24.22 %
Calculate the relative atomic mass of chlorine to two decimal places.
[2]
(b) Household bleach contains sodium chlorate(I) rather than molecular chlorine. Sodium chlorate(I) can be made by reacting sodium hydroxide with chlorine gas in a disproportionation reaction.
(i) Explain what is meant by a disproportionation reaction.
[1]
(ii) Write an equation for the reaction between chlorine and sodium hydroxide to form sodium chlorate(I) and state the conditions for the formation of sodium chlorate(I).
equation [2]
conditions [1]
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(iii) Explain, in terms of bonding, why sodium chlorate(I) has a higher boiling point than chlorine.
[2]
(c) Chlorine can form a number of chlorine oxides. Complete the table below giving the oxidation number of chlorine in each chlorine oxide.
formula of chlorine oxide oxidation number of chlorine
Cl2O
ClO2
Cl2O7
[3]
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16 Strontium carbonate is commonly used in fireworks and flares as it gives a red flame colour. It contains strontium ions which are isoelectronic with krypton atoms.
(a) (i) Suggest the formula and electronic configuration for the strontium ion.
[2]
(ii) Suggest the meaning of the term isoelectronic.
[1]
(b) The red light emitted by one mole of strontium ions has an energy of 171.09 kJ.
(i) Calculate the energy, in joules, emitted by one ion of strontium.
[2]
(ii) Calculate the frequency of this light.
[1]
(iii) Explain, using electronic transitions, why strontium ions give a red colour in fireworks.
[3]
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(c) 60 cm3 of 2.0 mol dm23 hydrochloric acid was added to 2.56 g of a sample from the firework. The resultant solution was filtered and made up to 500 cm3 with deionised water. 25.0 cm3 of this solution was titrated against 0.2 mol dm23 sodium hydroxide. The following results were obtained:
initial burette reading/cm3
final burette reading/cm3
titre/cm3
rough 0.0 24.9 24.9
1st accurate 24.9 49.5 24.6
2nd accurate 0.0 24.5 24.5
The reactions which occur are:
SrCO3 1 2HCl → SrCl2 1 CO2 1 H2O
NaOH 1 HCl → NaCl 1 H2O
(i) Calculate the total number of moles of hydrochloric acid added.
(ii) Calculate the number of moles of sodium hydroxide reacted.
(iii) How many moles of hydrochloric acid are there in 500 cm3 of the solution?
(iv) Calculate the number of moles of hydrochloric acid that reacted with the strontium carbonate.
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(v) Calculate the mass of strontium carbonate in the sample.
(vi) Calculate the percentage by mass of strontium carbonate in the sample.
[6]
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(Questions continue overleaf)
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17 A typical “lithium ion battery” consists of a lithium cobalt oxide (LiCoO2) electrode and a graphite electrode separated by lithium fluorophosphate (LiPF6).
(a) (i) The dot and cross diagram for the fluorophosphate ion is shown below. State the octet rule and explain whether or not the atoms in the ion obey this rule.
• •• •
X •F• •• •
• •
X
•
F• •
• •• X
F • •
• •• • FP
• •
• •
• •FX •
• • • •
• •X • F
• •
• •
• •
X • F
2
[3]
(ii) Draw and name the shape of the PF62 ion.
[2]
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(iii) Explain why PF62 has the shape selected.
[2]
(b) Redox reactions will occur in a working battery.
(i) Define a redox reaction.
[1]
(ii) What is the oxidation state of cobalt in LiCoO2?
[1]
(iii) The lead–acid battery, common in many motor vehicles, relies on the following redox processes.
Balance the half-equations shown below.
PbO2 1 SO422 1 H1 → PbSO4 1 H2O
Pb 1 HSO42 → PbSO4 1 H1
[2]
(iv) Combine the half-equations into an equation showing the overall reaction.
[1]
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18 Electronic cigarettes have been developed as an alternative to tobacco smoking. They are controversial as some studies have suggested that they release very small amounts of metal ions, such as silver, into the air.
(a) Suggest how the vapour produced by an electronic cigarette could be tested for silver ions. Indicate the result that would be expected if silver ions were present.
[3]
(b) Silver ions can be used to sterilise water, 0.001 g of silver ions being required for 1000 dm3 of water.
(i) What is the concentration of silver ions in mol dm23?
[2]
(ii) What mass of silver ions is required to sterilise an Olympic sized swimming pool which contains 2.5 3 106 dm3 of water?
[1]
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(c) Silver has also been used to dispose of chemical weapons such as mustard gas (C4H8SCl2), which will react with silver(II) ions. The silver(II) ion is a powerful oxidising agent.
(i) Write the formula of a silver(II) ion.
[1]
(ii) An alternative method of disposing of mustard gas is through reaction with sodium hydroxide, which produces C4H8S(OH)2 and sodium chloride. Write an equation for this reaction.
[1]
THIS IS THE END OF THE QUESTION PAPER
10120 AC112 XXX 2016.indd 23 29/04/2016 10:45:28
208717
Permission to reproduce all copyright material has been applied for.In some cases, efforts to contact copyright holders may have been unsuccessful and CCEAwill be happy to rectify any omissions of acknowledgement in future if notified.
DO NOT WRITE ON THIS PAGE
*24AC11224*
*24AC11224*
For Examiner’suse only
QuestionNumber Marks
Section A 1–10
Section B1112131415161718
TotalMarks
10120 AC112 XXX 2016.indd 24 29/04/2016 10:45:28
Periodic Table of the ElementsFor the use of candidates taking
Advanced Subsidiary and Advanced Level Chemistry Examinations
Copies must be free from notes or additions of any kind. No other type of data booklet or information
sheet is authorised for use in the examinations.
gce A/AS examinations
chemistry(advanced)
227
89
139
57
256
101
223
87
226
88
140
58
141
59
144
60
147
61
150
62
152
63
157
64
159
65
162
66
165
67
167
68
169
69
173
70
175
71232
90
231
91
238
92
237
93
242
94
243
95
247
96
245
97
251
98
254
99
253
100
254
102
257
103
133
55
137
56
178
72
181
73
184
74
186
75
190
76
192
77
195
78
197
79
201
80
89
39
91
40
103
45
85
37
88
38
93
41
96
42
99
43
101
44
106
46
108
47
112
48
131
54222
86
210
85
210
84
209
83
207
82
204
81
84
36
79
34
73
32
40
20
39
19
45
21
48
22
51
23
52
24
55
25
56
26
59
27
59
28
64
29
65
30
11
5
12
6
14
7
16
8
19
9
20
10
4
2
40
18
35.5
17
32
16
31
15
28
14
27
1370
31
75
33
80
35115
49
119
50
122
51
128
52
127
53
23
11
24
12
7
3
9
4
1
1
* 58–71 Lanthanum series† 90–103 Actinium series
a = relative atomic mass (approx.)x = atomic symbolb = atomic number
THE PERIODIC TABLE OF ELEMENTSGroup
ab x
0VIIVIVIVIIIIII
*
†
One mole of any gas at 20 °C and a pressure of 1 atmosphere (105 Pa) occupies a volume of 24 dm3.Planck Constant = 6.63 × 10–34 J sGas Constant = 8.31 J mol–1 K–1
Avogadro Constant = 6.02 × 1023 mol–1
MARKSCHEME
10120.01 F
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2016
ChemistryAssessment Unit AS 1
assessingBasic Concepts in Physical
and Inorganic Chemistry
[AC112]
TUESDAY 14 JUNE, AFTERNOON
10120.01 F 2 [Turn over
General Marking Instructions
IntroductionMark schemes are published to assist teachers and students in their preparation for examinations. Through the mark schemes teachers and students will be able to see what the examiners are looking for in response to questions and exactly where the marks have been awarded. The publishing of the mark schemes may help to show that examiners are not concerned about fi nding out what a student does not know but rather with rewarding students for what they do know.
The purpose of mark schemesExamination papers are set and revised by teams of examiners and revisers appointed by the Council. The teams of examiners and revisers include experienced teachers who are familiar with the level and standards expected of students in schools and colleges.
The job of the examiners is to set the questions and the mark schemes; and the job of the revisers is to review the questions and mark schemes commenting on a large range of issues about which they must be satisfi ed before the question papers and mark schemes are fi nalised.
The questions and the mark schemes are developed in association with each other so that the issues of differentiation and positive achievement can be addressed right from the start. Mark schemes, therefore, are regarded as part of an integral process which begins with the setting of questions and ends with the marking of the examination.
The main purpose of the mark scheme is to provide a uniform basis for the marking process so that all the markers are following exactly the same instructions and making the same judgements in so far as this is possible. Before marking begins a standardising meeting is held where all the markers are briefed using the mark scheme and samples of the students’ work in the form of scripts. Consideration is also given at this stage to any comments on the operational papers received from teachers and their organisations. During this meeting, and up to and including the end of the marking, there is provision for amendments to be made to the mark scheme. What is published represents the fi nal form of the mark scheme.
It is important to recognise that in some cases there may well be other correct responses which are equally acceptable to those published: the mark scheme can only cover those responses which emerged in the examination. There may also be instances where certain judgements may have to be left to the experience of the examiner, for example where there is no absolute correct response – all teachers will be familiar with making such judgements.
10120.01 F 3
AVAILABLEMARKS
Section A
1 C
2 C
3 C
4 B
5 A
6 A
7 C
8 D
9 C
10 B [2] for each correct answer [20] 20
Section A 20
10120.01 F 4 [Turn over
AVAILABLEMARKS
Section B
11 Ion Atomic number Electronic structureA3+ 5 1s2
B– 35 1s22s22p63s23p63d104s24p6
C2– 16 1s22s22p63s23p6
[3] 3
12 (a) Each carbon covalently bonded to three others Hexagonal layers with weak forces between them Each carbon has a delocalised electron Electron moves and carries charge [4]
Quality of written communication [2]
(b) Many strong covalent bonds which take a lot of energy to break [2] 8
13 (a) (i) violet/purple [1]
(ii) no change with HCl [1] red-brown gas forms with HBr [1] [2] (iii) HCl has higher bond enthalpy than HBr [1]
(b) (i) Hydriodic is stronger Hydrogen iodide has a weaker covalent bond [2] (ii) Na2CO3 + 2HI → 2NaI + CO2 + H2O [2]
(c) HI higher Mr /more electrons [1] Stronger/more van der Waals [1] 10
10120.01 F 5
AVAILABLEMARKS
14 (a) (i) contains 1 electron in outer subshell [1]
(ii) needs one more electron to fill shell/subshell [1]
(b) (i) bond energy increases from fluorine to chlorine [1] it then decreases down the group [1]
(ii) bond is shorter, (shorter) bonds are stronger [1]
(iii) Electrons excited to higher energy levels. Electrons fall to lower levels. Energy emitted as red light [3]
(c) (i) 0.12 (ii) 0.0049 (iii) 0.098
(iv) 0.022
(v) 1.63 g
(vi) 63.7% [6] 15
17 (a) (i) (When forming a compound,) an atom (tends to) gain, lose or share electrons to achieve eight in its outer shell. [1] Phosphorus does not as it has 12 electrons in the outer shell [1] fluorine does [1] [3] (ii)
F
P
F FF
F F
Octahedral [2]
(iii) six bonding pairs [1] repel equally to maximise separation [1] [2]
(b) (i) oxidation and reduction occur in the same reaction [1]
(ii) +3 [1]
(iii) PbO2 + SO42– + 4H+ + 2e– → PbSO4 + 2H2O [1]
Pb + HSO4– → PbSO4 + H+ + 2e– [1]
(iv) PbO2 + Pb + SO42– + HSO4
– + 3H+ → 2PbSO4 + 2H2O [1] 12
10120.01 F 7
AVAILABLEMARKS
18 (a) Bubble vapour through A solution of sodium chloride or hydrochloric acid White precipitate formed [3]
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2017
ChemistryAssessment Unit AS 1assessingBasic Concepts in Physicaland Inorganic Chemistry
[SCH12]FRIDAY 26 MAY, MORNING
TIME1 hour 30 minutes.
INSTRUCTIONS TO CANDIDATESWrite your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all fifteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all five questions in Section B. You must answer the questions in the spaces provided.Do not write outside the boxed area on each page or on blank pages.Complete in black ink only. Do not write with a gel pen.
INFORMATION FOR CANDIDATESThe total mark for this paper is 90.Quality of written communication will be assessed in Question 13(c).In Section A all questions carry equal marks, i.e. one mark for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements, containing some data, is included with this question paper.
Centre Number
Candidate Number
10675
*SCH12*
*SCH12*
*20SCH1201*
*20SCH1201*
New
Specif
icatio
n
*20SCH1202*
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10675
Section A – Multiple Choice
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
Each multiple choice question is worth 1 mark.
1 Bromine is formed in the reaction below.
Cl2 + 2NaBr → 2NaCl + Br2
Which statement about the reaction is correct?
A Bromide ions lose electrons
B Bromine is reduced by chlorine
C Chloride ions are reduced
D Chlorine is a weaker oxidising agent than bromide
2 Which trend in the Periodic Table is correct?
A Boiling point decreases from fluorine to bromine
B First ionisation energy decreases from lithium to caesium
C First ionisation energy increases from nitrogen to oxygen
D Melting point decreases from sodium to silicon
3 Which of the following is the structure of 55Mn2+ ?
protons neutrons electrons
A 25 30 23
B 25 30 27
C 27 30 25
D 30 25 28
*20SCH1203*
*20SCH1203*
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4 Potassium iodide is formed when potassium is warmed in iodine vapour. Which of the following shows the bonding in the three species?
potassium iodine potassium iodide
A ionic covalent ionic
B metallic ionic covalent
C covalent covalent ionic
D metallic covalent ionic
5 The element astatine lies below iodine in the Periodic Table and is likely to
A be black.
B be a volatile liquid at room temperature and pressure.
C form an astatide ion, At2-.
D oxidise iodide ions to iodine.
6 Which molecule is non-polar?
A H2S
B NH3
C PF3
D SF6
*20SCH1204*
*20SCH1204*
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7 The element boron has a relative atomic mass of 10.8. In this sample, boron exists as two isotopes, 10B and 11B. The percentage abundance of 10B in this sample of boron is
A 10.8%.
B 20.0%.
C 80.0%.
D 89.2%.
8 When burned in oxygen magnesium forms magnesium oxide.
2Mg + O2 → 2MgO
What is the number of molecules of oxygen required for the complete oxidation of 1.2 g of magnesium?
A 1.5 × 1022
B 3.0 × 1022
C 3.0 × 1023
D 6.0 × 1023
9 Which statement describes the trends in electronegativity values in the Periodic Table?
A Decrease across a Period and increase down a Group
B Decrease across a Period and decrease down a Group
C Increase across a Period and increase down a Group
D Increase across a Period and decrease down a Group
*20SCH1205*
*20SCH1205*
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10 Which of the following would exactly neutralise 10.0 cm3 of 1.00 mol dm-3 NaOH(aq)?
A 2.50 cm3 of 1.00 mol dm-3 CH3COOH
B 5.00 cm3 of 1.00 mol dm-3 HCl
C 5.00 cm3 of 1.00 mol dm-3 H2SO4
D 3.00 cm3 of 1.00 mol dm-3 H3PO4
*20SCH1206*
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Section B
Answer all five questions in the spaces provided.
11 Sulfate, hydrogensulfate and thiosulfate ions are formed when sulfuric and thiosulfuric acids ionise.
(a) (i) Write the equation for the complete ionisation of thiosulfuric acid.
[2]
(ii) Write the formula for the hydrogensulfate ion.
[1]
(b) (i) Write the formula for ammonium sulfate.
[1]
(ii) Describe the bonding in ammonium sulfate.
[2]
(c) Describe how you could use chemical tests on an aqueous solution of ammonium sulfate to prove that it contains ammonium ions and sulfate ions.
[4]
*20SCH1207*
*20SCH1207*
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12 Some properties of the metals sodium and aluminium are shown in the table below.
metal charge on metal ion electronic structure of the atom
melting point /°C
sodium 1+ 1s2 2s2 2p6 3s1 98
aluminium 3+ 1s2 2s2 2p6 3s2 3p1 660
(a) Describe, without using a diagram, the bonding in sodium metal.
[2]
(b) Explain why aluminium has a higher melting point than sodium.
[2]
(c) (i) Write the equation, including state symbols, for the first ionisation energy of sodium.
[2]
(ii) The first six ionisation energies, in kJ mol-1, of sodium are 496, 4563, 6913, 9544, 13352 and 16611. Explain which of these values can be used to identify sodium as belonging to Group I of the Periodic Table.
[2]
*20SCH1208*
*20SCH1208*
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(iii) The outer electron in the sodium atom is located in the 3s orbital. Explain what is meant by the term orbital.
[2]
(d) Aluminium forms covalent bonds with chlorine.
(i) Explain what is meant by the term covalent bond.
[2]
(ii) Write the equation for the reaction of aluminium with chlorine to form aluminium chloride, AlCl3.
[1]
(iii) State the octet rule and explain whether the atoms in aluminium chloride obey the rule.
[3]
*20SCH1209*
*20SCH1209*
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13 (a) Zinc reacts with chlorine to form the ionic compound zinc chloride. Draw a dot and cross diagram, using outer electrons only, to show how zinc chloride, ZnCl2, is formed from zinc and chlorine atoms.
[2]
(b) Zinc is an essential trace element. People who have a zinc deficiency can take hydrated zinc sulfate, ZnSO4.xH2O, as a dietary supplement.
The value of x can be determined by heating hydrated zinc sulfate to constant mass.
A student heated 5.65 g of hydrated zinc sulfate and obtained 3.85 g of anhydrous zinc sulfate.
(i) Calculate the number of moles of anhydrous zinc sulfate obtained.
[1]
(ii) Calculate the mass of water present in the hydrated zinc sulfate.
[1]
(iii) Calculate the number of moles of water present in the hydrated zinc sulfate.
[1]
(iv) Calculate the value of x in ZnSO4.xH2O
[1]
*20SCH1210*
*20SCH1210*
10675
(c) Describe how you would prepare 250.0 cm3 of a 28.7 g dm-3 zinc sulfate solution from the anhydrous solid.
In this question you will be assessed on using your written communication skills including the use of specialist scientific terms.
[6]
*20SCH1211*
*20SCH1211*
10675[Turn over
14 Nitrogen and phosphorus are Group V elements. They form the toxic hydrides ammonia and phosphine.
(a) Ammonia is formed by the reversible reaction of nitrogen with hydrogen. Write the equation for this reaction.
[2]
(b) Phosphine is formed by the reaction of phosphorus with aqueous sodium hydroxide.
(i) Balance the equation for the formation of phosphine.
P4 + NaOH + H2O → NaH2PO2 + PH3 [1]
(ii) Deduce the oxidation number of phosphorus in:
P4
NaH2PO2
PH3 [3]
(iii) Explain, using the oxidation numbers of phosphorus, why the reaction is described as disproportionation.
[3]
*20SCH1212*
*20SCH1212*
10675
(c) The boiling point of ammonia is -33 °C while that of phosphine is -88 °C. Explain why the boiling point of ammonia is higher than that of phosphine.
[3]
(d) Both ammonia and phosphine molecules react with H+ ions.
PH3 + H+ → PH4+
(i) Name the type of bond formed between a phosphine molecule and the H+ ion.
[1]
(ii) Draw and name the shapes of the molecule PH3 and the ion PH4+.
PH3
Shape _________________
PH4+
Shape _________________
[4]
(iii) Explain why the bond angle in PH3 is different from the bond angle in PH4+.
[3]
*20SCH1213*
*20SCH1213*
10675[Turn over
(e) Ammonia is very soluble in water. Draw diagrams to show the two ways in which a molecule of ammonia can be attracted to a molecule of water. Include all partial charges and lone pairs in your diagram.
[4]
*20SCH1214*
*20SCH1214*
10675
15 Ammonia is used to make nitric acid by the Ostwald Process outlined below.
Reaction 1: 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)
Reaction 2: 2NO(g) + O2(g) → 2NO2(g)
Reaction 3: 3NO2(g) + H2O(l) → 2HNO3(aq) + NO(g)
(a) (i) Calculate the number of moles of oxygen needed to react with 6.8 kg of ammonia.
[3]
(ii) Calculate the number of moles of nitrogen(IV) oxide which can be obtained from 6.8 kg of ammonia.
[2]
(iii) Calculate the concentration of nitric acid, in g dm-3, produced on reacting the nitrogen(IV) oxide obtained in part (ii) with 50 dm3 of water.
[3]
*20SCH1215*
*20SCH1215*
10675[Turn over
(b) Ammonia reacts with nitric acid according to the equation below.
NH3 + HNO3 → NH4NO3
The following results were obtained by diluting 25.0 cm3 of a concentrated ammonia solution to 250.0 cm3 in a volumetric flask and then titrating 25.0 cm3 portions of the diluted ammonia solution using 0.100 mol dm-3 nitric acid.
titration initial burette reading /cm3
final burette reading /cm3 titre /cm3
rough 0.00 22.00 22.00
first accurate 0.10 21.40 21.30
second accurate 0.20 21.60 21.40
(i) Name a suitable indicator for the titration and state the colour change at the end point.
[3]
(ii) Calculate the mean titre.
[1]
*20SCH1216*
*20SCH1216*
10675
(iii) A burette has an uncertainty of ±0.05 cm3. Calculate the uncertainty when two burette readings are used to calculate a titre value.
[1]
(iv) Calculate the concentration of the concentrated ammonia solution in mol dm-3.
[5]
*20SCH1217*
*20SCH1217*
10675
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DO NOT WRITE ON THIS PAGE
THIS IS THE END OF THE QUESTION PAPER
*20SCH1218*
*20SCH1218*
10675
BLANK PAGE
DO NOT WRITE ON THIS PAGE
*20SCH1219*
*20SCH1219*
10675
BLANK PAGE
DO NOT WRITE ON THIS PAGE
*20SCH1220*
*20SCH1220*
Permission to reproduce all copyright material has been applied for.In some cases, efforts to contact copyright holders may have been unsuccessful and CCEAwill be happy to rectify any omissions of acknowledgement in future if notified.
221023
For Examiner’suse only
QuestionNumber Marks
Section A1–10
Section B1112131415
TotalMarks
DO NOT WRITE ON THIS PAGE
CHEMISTRY DATA SHEETGCE A/AS EXAMINATIONS CHEMISTRY
Including the Periodic Table of the Elements
For the use of candidates takingAdvanced Subsidiary and Advanced LevelChemistry Examinations
Copies must be free from notes or additions of any kind.
No other type of data booklet or information sheet is
authorised for use in the examinations.
For first teaching from September 2016For first award of AS Level in Summer 2017For first award of A Level in Summer 2018Subject Code: 1110
GCE
NewSpe
cifi ca
tionGeneral Information
1 tonne = 106 g1 metre = 109 nmOne mole of any gas at 293 K and a pressure of 1 atmosphere (105 Pa) occupies a volume of 24 dm3
Avogadro Constant = 6.02 1023 mol–1
Planck Constant = 6.63 10–34 J sSpecifi c Heat Capacity of water = 4.2 J g–1 K–1
Speed of Light = 3 108 m s–1
Characteristic absorptions in IR spectroscopy
Wavenumber/cm–1 Bond Compound550–850 C–X (X = Cl, Br, I) Haloalkanes750–1100 C–C Alkanes, alkyl groups1000–1300 C–O Alcohols, esters, carboxylic acids 1450–1650 C ̿ C Arenes1600–1700 C ̿ C Alkenes1650–1800 C ̿ O Carboxylic acids, esters, aldehydes, ketones, amides, acyl chlorides2200–2300 C N Nitriles2500–3200 O–H Carboxylic acids2750–2850 C–H Aldehydes2850–3000 C–H Alkanes, alkyl groups, alkenes, arenes3200–3600 O–H Alcohols3300–3500 N–H Amines, amides
Proton Chemical Shifts in Nuclear Magnetic Resonance Spectroscopy (relative to TMS)
Chemical Shi Structure
0.5–2.0 –CH Saturated alkanes0.5–5.5 –OH Alcohols1.0–3.0 –NH Amines2.0–3.0 –CO–CH Ketones –N–CH Amines C6H5–CH Arene (alipha c on ring)2.0–4.0 X–CH X = Cl or Br (3.0–4.0) X = I (2.0–3.0)4.5–6.0 –C ̿ CH Alkenes5.5–8.5 RCONH Amides6.0–8.0 –C6H5 Arenes (on ring)9.0–10.0 –CHO Aldehydes10.0–12.0 –COOH Carboxylic acids
These chemical shi s are concentra on and temperature dependent and may be outside the ranges indicated above.
227
89
139
57
256
101
223
87
226
88
261
104
262
105
266
106
264
107
277
108
268
109
271
110
272
111
140
58
141
59
144
60
145
61
150
62
152
63
157
64
159
65
162
66
165
67
167
68
169
69
173
70
175
71232
90
231
91
238
92
237
93
242
94
243
95
247
96
245
97
251
98
254
99
253
100
254
102
257
103
133
55
137
56
178
72
181
73
184
74
186
75
190
76
192
77
195
78
197
79
201
80
89
39
91
40
103
45
85
37
88
38
93
41
96
42
98
43
101
44
106
46
108
47
112
48
131
54222
86
210
85
210
84
209
83
207
82
204
81
84
36
79
34
73
32
40
20
39
19
45
21
48
22
51
23
52
24
55
25
56
26
59
27
59
28
64
29
65
30
11
5
12
6
14
7
16
8
19
9
20
10
4
2
40
18
35.5
17
32
16
31
15
28
14
27
1370
31
75
33
80
35115
49
119
50
122
51
128
52
127
53
23
11
24
12
7
3
9
4
* 58–71 Lanthanum series† 90–103 Actinium series
a = relative atomic mass (approx)x = atomic symbolb = atomic number
THE PERIODIC TABLE OF ELEMENTSGroup
ab
x
*
†
1
1
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
III III IV VI VII 0V
285
112Copernicium
MARKSCHEME
10675.01 F
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2017
ChemistryAssessment Unit AS 1
assessing
Basic Concepts in Physicaland Inorganic Chemistry
[SCH12]
FRIDAY 26 MAY, MORNING
New
Specifi
catio
n
10675.01 F 2 [Turn over
General Marking Instructions
IntroductionMark schemes are published to assist teachers and students in their preparation for examinations. Through the mark schemes teachers and students will be able to see what the examiners are looking for in response to questions and exactly where the marks have been awarded. The publishing of the mark schemes may help to show that examiners are not concerned about fi nding out what a student does not know but rather with rewarding students for what they do know.
The purpose of mark schemesExamination papers are set and revised by teams of examiners and revisers appointed by the Council. The teams of examiners and revisers include experienced teachers who are familiar with the level and standards expected of students in schools and colleges.
The job of the examiners is to set the questions and the mark schemes; and the job of the revisers is to review the questions and mark schemes commenting on a large range of issues about which they must be satisfi ed before the question papers and mark schemes are fi nalised.
The questions and the mark schemes are developed in association with each other so that the issues of differentiation and positive achievement can be addressed right from the start. Mark schemes, therefore, are regarded as part of an integral process which begins with the setting of questions and ends with the marking of the examination.
The main purpose of the mark scheme is to provide a uniform basis for the marking process so that all the markers are following exactly the same instructions and making the same judgements in so far as this is possible. Before marking begins a standardising meeting is held where all the markers are briefed using the mark scheme and samples of the students’ work in the form of scripts. Consideration is also given at this stage to any comments on the operational papers received from teachers and their organisations. During this meeting, and up to and including the end of the marking, there is provision for amendments to be made to the mark scheme. What is published represents the fi nal form of the mark scheme.
It is important to recognise that in some cases there may well be other correct responses which are equally acceptable to those published: the mark scheme can only cover those responses which emerged in the examination. There may also be instances where certain judgements may have to be left to the experience of the examiner, for example where there is no absolute correct response – all teachers will be familiar with making such judgements.
10675.01 F 3
AVAILABLEMARKS
Section A
1 A
2 B
3 A
4 D
5 A
6 D
7 B
8 A
9 D
10 C [1] for each correct answer [10] 10
Section A 10
10675.01 F 4 [Turn over
AVAILABLEMARKS
Section B
11 (a) (i) H2S2O3 + 2H2O → 2H3O+ + S2O32–
or
H2S2O3 → 2H+ + S2O32– [2]
(ii) HSO4
– [1] (b) (i) (NH4)2SO4 [1] (ii) oppositely charged ions are held together by electrostatic forces of attraction error [–1] [2]
(c) NH4+: warm with (dilute) sodium hydroxide solution [1]
(the gas produced) gives white fumes with (a glass rod dipped in) concentrated HCl [1] SO4
2–: add a solution of barium chloride [1] a white precipitate forms [1] [4] 10
12 (a) (attraction) between positive sodium ions [1] and delocalised electrons [1] [2]
(b) increase in charge of metal ion/aluminium ion has 3+ compared to 1+ in sodium [1] increase in the number of electrons in delocalised cloud/sea [1] [2]
(c) (i) Na(g) → Na+(g) + e– [2]
(ii) 1st and 2nd values [1] large gap between [1] [2] (iii) A region within an atom that can hold up to two electrons [1] with opposite spin [1]. [2]
(d) (i) (Electrostatic) attraction between a shared pair of electrons and the nuclei of bonded atoms. [2]
(ii) 2Al + 3Cl2 → 2AlCl3 [1] (iii) When forming a compound, an atom tends to gain, lose or share electrons [1] to achieve eight in its outer shell. [1] Aluminium has six electrons in the outer shell [1]
(c) Indicative content • (Weigh out) 7.18g of zinc sulfate * • in a beaker/suitable container • Dissolve the solid in a small amount (50–100cm3) of distilled/deionised water • Transfer the solution/with washings • to the 250.0 cm3 volumetric flask * • and make up to the mark • Stopper and invert the flask
* essential for [6] in Band A If either * missing max [5]
Band Response Mark
A
Candidates must use appropriate specialist terms to fully explain the preparation of the standard solution using 6 points of indicative content. They must use good spelling, punctuation and grammar and the form and style are of an excellent standard.
[5]–[6]
B
Candidates must use appropriate specialist terms to explain the preparation of the standard solution using a minimum of 4 points of indicative content. They must use satisfactory spelling, punctuation and grammar and the form and style are of a good standard.
[3]–[4]
C
Candidates must partially explain the preparation of the standard solution using a minimum of 2 points of indicative content. They use limited correct spelling, punctuation and grammar and the form and style are of a basic standard.
(iii) 0 to +1 is oxidation; 0 to –3 is reduction [1] oxidation and reduction of the same element [1] in the same reaction [1] [3]
(c) Between molecules of NH3 there are van der Waals’ forces and H-bonds [1] Between molecules of PH3 there are only van der Waals’ forces [1] Hydrogen bonds are stronger and require more energy to break. [1] [3]
(d) (i) dative covalent/co-ordinate bond [1]
(ii) H
P
HH H
+
P
HH H
••
[2]
pyramidal tetrahedral [2]
(iii) PH3 has one lone pair/3 bond pairs [1] greater repulsion between lone pair–bond pair [1] pushes bond pairs closer together/reduces bond angle [1] [3] (e)
NH3 : HNO3 1 : 1 moles of diluted ammonia in 25 cm3 = 0.002135 moles of diluted ammonia in 250 cm3 = 0.02135 concentration of diluted ammonia = 0.02135 ÷ 0.25 = 0.0854 concentration of undiluted ammonia = 0.0854 × 10 = 0.854 mol dm–3
([–1] each error) [5] 18
Section B 80
Total 90
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2018
ChemistryAssessment Unit AS 1assessingBasic Concepts in Physicaland Inorganic Chemistry
[SCH12]TUESDAY 22 MAY, MORNING
TIME1 hour 30 minutes.
INSTRUCTIONS TO CANDIDATESWrite your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all fourteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all four questions in Section B. You must answer the questions in the spaces provided.Do not write outside the boxed area on each page or on blank pages.Complete in black ink only. Do not write with a gel pen.
INFORMATION FOR CANDIDATESThe total mark for this paper is 90.Quality of written communication will be assessed in Question 13(a).In Section A all questions carry equal marks, i.e. one mark for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements, containing some data, is included with this question paper.
*SCH12*
*SCH12*
*20SCH1201*
*20SCH1201*
Centre Number
Candidate Number
11282
*20SCH1202*
*20SCH1202*
11282
Section A
For each of the following questions only one of the lettered responses (A–D) is correct.
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
1 A solution of barium chloride was added to sodium sulfate solution.
heat
P Q R S
Which combination of methods should be used to obtain the precipitate and the other product as a solid?
A P + Q
B P + R
C Q + S
D R + S
2 Which species has the same electronic arrangement as a lithium ion, Li+?
A Be−
B B2+
C H+
D He
*20SCH1203*
*20SCH1203*
11282[Turn over
3 Sodium azide decomposes, in an airbag, to form sodium and nitrogen.
2NaN3 → 2Na + 3N2
The sodium then reacts with potassium nitrate to form more nitrogen gas.
10Na + 2KNO3 → 5Na2O + N2 + K2O
0.50 mol of sodium azide produces
A 0.50 mol of nitrogen.
B 0.75 mol of nitrogen.
C 0.80 mol of nitrogen.
D 2.00 mol of nitrogen.
4 Chlorine has two isotopes. How many peaks are there in the mass spectrum of chlorine?
A 2
B 3
C 4
D 5
5 Which molecule is not planar?
A BF3
B BeCl2
C HCHO
D NCI3
*20SCH1204*
*20SCH1204*
11282
6 The curves shown below are for 25 cm3 of acids HX and HY when they are reacted with 0.1 M sodium hydroxide solution.
pH
20
HX
HY
30
volume of 0.1 M NaOH added/cm3
3
1
Compared to acid HY, the acid HX is
A more concentrated and stronger.
B more concentrated and weaker.
C less concentrated and stronger.
D less concentrated and weaker.
7 The largest mass of silver chloride precipitated is when excess silver ions are added to
A 25.0 cm3 of 0.80 M hydrochloric acid. B 30.0 cm3 of 0.30 M iron(III) chloride solution.
C 50.0 cm3 of 0.20 M magnesium chloride solution. D 50.0 cm3 of 0.50 M sodium chloride solution.
*20SCH1205*
*20SCH1205*
11282[Turn over
8 On melting, covalent bonds are broken in
A bromine.
B diamond.
C sodium chloride.
D sulfur(IV) oxide.
9 Which of the following equations represents a redox reaction?
A CaCO3 + SiO2 → CaSiO3 + CO2
B 3Cl2 + 6OH− → 5Cl− + ClO3− + 3H2O
C 2CrO42− + 2H+ → Cr2O7
2− + H2O
D HNO3 + 2H2SO4 → NO2+ + H3O+ + 2HSO4
−
10 Which halide has the most covalent character?
A AIBr3
B AIF3
C MgBr2
D MgF2
*20SCH1206*
*20SCH1206*
11282
Section B
Answer all four questions in this section
11 Chlorine monoxide is a brown-yellow gas with a boiling point of 4 °C while chlorine has a boiling point of −34 °C. The monoxide is formed when excess chlorine is passed over mercury(II) oxide.
2Cl2(g) + HgO(s) → HgCl2(s) + Cl2O(g)
Cl2
HgO
The escaping gases are passed through a U-tube which is cooled to −30 °C. The chlorine monoxide condenses in the U-tube.
(a) (i) How could you test to show that chlorine is passing into the reaction tube?
[2]
(ii) What is the colour of chlorine?
[1]
(iii) Why is it important to limit the temperature of the U-tube to −30 °C and not to have it lower than this temperature?
[1]
*20SCH1207*
*20SCH1207*
11282[Turn over
(iv) How could you show that it is a chloride which remains in the reaction tube?
[3]
(v) Mercury(ll) oxide decomposes when heated to form oxygen and mercury. How could you show that there was no mercury(ll) oxide left in the reaction tube at the end of the experiment?
[3]
(vi) Chlorine monoxide cannot be collected over water as it is very soluble in water, with a solubility of 143 g in 100 cm3 at room temperature and pressure. Explain how you could show that chlorine monoxide is very soluble in water.
[4]
*20SCH1208*
*20SCH1208*
11282
(b) Chlorine monoxide slowly reacts with water to form hypochlorous acid
Cl2O + H2O → 2HOCI
(i) Hypochlorous acid has a systematic name based on chloric acid. State the systematic name for hypochlorous acid.
[1]
(ii) Hypochlorous acid is a weak acid. Explain what is meant by the term weak acid.
[2]
(iii) Hypochlorous acid decomposes to give hydrochloric acid and oxygen. Write the equation for this reaction.
[2]
(c) Chlorine monoxide obeys the octet rule.
(i) State the octet rule.
[2]
(ii) Draw the electronic structure of chlorine monoxide showing the outer electrons only.
[2]
*20SCH1209*
*20SCH1209*
11282[Turn over
(d) Chlorine monoxide has the following shape.
O
Cl Cl
(i) Name the shape.
[1]
(ii) How many lone pairs are there in a chlorine monoxide molecule?
[1]
(iii) Explain why chlorine monoxide forms this shape.
[2]
(e) Fluorine also forms an oxide but this oxide is known as oxygen fluoride because fluorine has a greater electronegativity than oxygen. State how electronegativity changes across a Period and down a Group.
[2]
(f) It has been suggested that chlorine monoxide is the active ingredient in the treatment of water for drinking purposes. Name two substances that are used to treat water for drinking.
[2]
*20SCH1210*
*20SCH1210*
11282
12 Ammonium dichromate is used in the “volcano” experiment. When heated, it decomposes to produce a vast amount of green chromium oxide and gases which push out the green “ash” to form a pile of “lava”.
(NH4)2Cr2O7 → Cr2O3 + N2 + 4H2O
The water forms steam because of the heat of the reaction.
(a) Write the equation for the reaction, with state symbols, for the reactants and products.
[1]
(b) Ammonium dichromate is very soluble in water. At room temperature 10.0 g of ammonium dichromate dissolve in 25.0 cm3 of water. The orange solution can be tested for the presence of ammonium ions.
(i) Calculate the solubility of the ammonium dichromate in g dm−3 to 3 significant figures.
[1]
(ii) Calculate the solubility of the ammonium dichromate in mol dm−3 to 3 significant figures.
[1]
(iii) Explain how you would show that the orange solution contains ammonium ions.
[3]
*20SCH1211*
*20SCH1211*
11282[Turn over
(c) The nitrogen given off in the reaction consists of two isotopes, nitrogen-14 and nitrogen-15. The percentage abundance of nitrogen-14 is 99.632%.
(i) Explain what is meant by the term isotopes.
[2]
(ii) Calculate the percentage abundance of nitrogen-15 given off.
[1]
(iii) Calculate the relative atomic mass of nitrogen to three decimal places.
[2]
(iv) Explain why there is a difference between the calculated relative atomic mass and the one provided in the data sheet.
[1]
.
*20SCH1212*
*20SCH1212*
11282
(d) The dichromate ion is a very strong oxidising agent. The half-equation which shows its oxidising ability is:
Cr2O72− + 14H+ + 6e− → 2Cr3+ + 7H2O
(i) Use this equation to explain, in terms of oxidation numbers, why the dichromate ion is an oxidising agent.
[2]
(ii) Use this equation to explain, in terms of electrons, why the dichromate ion is an oxidising agent.
[1]
(e) Dichromates react with chlorides in the presence of concentrated sulfuric acid to produce chromyl chloride, CrO2Cl2, which is a deep red liquid with a boiling point of 117 °C. Using this information, explain whether chromyl chloride is ionic or covalent.
[2]
*20SCH1214*
*20SCH1214*
11282
13 (a) There are several types of structure which apply to chemical formulae. The species present may be atoms, molecules or ions. In each of the following examples describe which type of structure it is and which type of species is present.
sodium chloride
diamond
bromine
In this question you will be assessed on using your written communication skills including the use of specialist scientific terms.
[6]
(b) The different types of structure have different physical properties. State four physical properties that depend upon structure.
[3]
*20SCH1215*
*20SCH1215*
11282[Turn over
(c) The structure of sodium is shown below.
+ + +
+ + +
+ + +
(i) Attach words to the labels shown. [2]
(ii) Use this diagram to explain whether magnesium has a greater or lower conductivity than sodium.
[2]
(iii) Explain, using a labelled diagram, how you could compare the electrical conductivities of sodium and magnesium in the laboratory.
[3]
*20SCH1216*
*20SCH1216*
11282
14 Ethene is a gas at room temperature and has a boiling point of −104 °C at atmospheric pressure. It has a relative molecular mass of 28 which is approximately the same as the average relative molecular mass of air. It is a planar molecule which has the following structure:
H H C C
H H
(a) The ethene molecule contains single bonds and a double bond which are formed from s- and p-orbitals.
(i) Draw the shape of an s-orbital.
[1]
(ii) Draw the shape of a p-orbital.
[1]
(iii) Explain what is meant by the term orbital.
[2]
*20SCH1217*
*20SCH1217*
11282[Turn over
(b) Ethene is a non-polar molecule. There are two reasons why ethene can be considered to be non-polar. One is based on electronegativity and the other is based on shape.
(i) What is meant by the term electronegativity?
[2]
(ii) Explain why ethene is considered non-polar based on electronegativity.
[1]
(iii) Explain why ethene is considered non-polar based on shape.
[1]
(c) Ethene contains a double bond. Other molecules can contain triple bonds.
(i) Draw the structure of the hydrocarbon ethyne which contains two carbon atoms and a triple bond.
[1]
(ii) Name an element which contains a triple bond.
[1]
*20SCH1218*
*20SCH1218*
11282
(d) When ethene burns, carbon dioxide and water are produced. Describe how you would carry out a test for carbon dioxide and the result expected for a positive test.
[2]
(e) Gases can be collected by two different methods A or B depending on their relative molecular masses compared to air.
gas lighter than air gas heavier than air
A B
(i) Explain which method could be used to collect methane, CH4.
[1]
(ii) Explain which method could be used to collect chlorine.
[1]
*20SCH1219*
*20SCH1219*
11282
(f) The boiling point of methane is −161 °C. Explain why the boiling point of methane is lower than that of ethene.
[2]
THIS IS THE END OF THE QUESTION PAPER
MARKSCHEME
11282.01 F
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2018
ChemistryAssessment Unit AS 1
assessingBasic Concepts in Physical
and Inorganic Chemistry
[SCH12]
TUESDAY 22 MAY, MORNING
11282.01 F 2 [Turn over
General Marking Instructions
IntroductionMark schemes are published to assist teachers and students in their preparation for examinations. Through the mark schemes teachers and students will be able to see what the examiners are looking for in response to questions and exactly where the marks have been awarded. The publishing of the mark schemes may help to show that examiners are not concerned about fi nding out what a student does not know but rather with rewarding students for what they do know.
The purpose of mark schemesExamination papers are set and revised by teams of examiners and revisers appointed by the Council. The teams of examiners and revisers include experienced teachers who are familiar with the level and standards expected of students in schools and colleges.
The job of the examiners is to set the questions and the mark schemes; and the job of the revisers is to review the questions and mark schemes commenting on a large range of issues about which they must be satisfi ed before the question papers and mark schemes are fi nalised.
The questions and the mark schemes are developed in association with each other so that the issues of differentiation and positive achievement can be addressed right from the start. Mark schemes, therefore, are regarded as part of an integral process which begins with the setting of questions and ends with the marking of the examination.
The main purpose of the mark scheme is to provide a uniform basis for the marking process so that all the markers are following exactly the same instructions and making the same judgements in so far as this is possible. Before marking begins a standardising meeting is held where all the markers are briefed using the mark scheme and samples of the students’ work in the form of scripts. Consideration is also given at this stage to any comments on the operational papers received from teachers and their organisations. During this meeting, and up to and including the end of the marking, there is provision for amendments to be made to the mark scheme. What is published represents the fi nal form of the mark scheme.
It is important to recognise that in some cases there may well be other correct responses which are equally acceptable to those published: the mark scheme can only cover those responses which emerged in the examination. There may also be instances where certain judgements may have to be left to the experience of the examiner, for example where there is no absolute correct response – all teachers will be familiar with making such judgements.
(ii) Chlorine is green/green-yellow/yellow-green [1] [1]
(iii) Chlorine would condense [1]
(iv) Dissolve the chloride in water [1] add silver nitrate solution [1] white precipitate formed [1] [3]
(v) Heat the solid left in the tube in a test tube [1] test with a glowing splint [1] it does not relight [1] [3]
(vi) Either Fill a test tube with chlorine monoxide [1] seal the end of the test tube [1] invert in a beaker of water [1] open the test tube to see how far the water rises [1]
Or Bubble through H2O [1] stated volume of H2O/until bubbles appear [1] measured using a physical property, e.g. colour, pH, density, mass, volume, forming precipitate with AgNO3(aq) [2] [4]
(b) (i) Chloric(I) acid [1]
(ii) Partial dissociation in solution (to form hydrogen ions) [2]
(iii) 2HOCI → 2HCI + O2 [2]
(c) (i) When reacting an atom tends to gain, lose or share electrons to achieve 8 in its outer shell [2]
(ii) ×CI ×O××
××CI
[2]
(d) (i) Bent [1]
(ii) 8 [1]
(iii) The lone pairs repel the bonded pairs more [2]
(e) Electronegativity increases across a period [1]
Electronegativity decreases down a group [1] [2]
(f) Chlorine [1] ozone [1] [2] 31
11282.01 F 5
AVAILABLEMARKS
12 (a) (s) (s) (g) (g) [1]
(b) (i) 10.0 g in 25.0 cm3; 40 × 10.0 g = 400 g in 1 dm3 [1]
(ii) (NH4)2Cr2O7 = 2 × 18 + 2 × 52 + 7 × 16 =
36 + 104 + 112 = 252 400.0/252 = 1.59 [1]
(iii) Heat with sodium hydroxide solution [1] moist indicator paper/litmus/red litmus/UI paper [1] turns blue [1] [3]
(c) (i) Atoms which have the same atomic number but a different mass number or contain the same number of protons but a different number of neutrons [2]
(iv) The RAMs in the table are listed as whole numbers (exception of chlorine) [1]
(d) (i) Oxidation number in dichromate is +6; oxidation number in Cr3+ is +3; the oxidation number goes down when an oxidant reacts [2]
(ii) Oxidising agents gain electrons (which are supplied by the reducing agent) [1]
(e) Low boiling point hence covalent [1]; liquid at room temperature hence covalent [1] [2] 17
11282.01 F 6 [Turn over
AVAILABLEMARKS
AVAILABLEMARKS
13 (a) Sodium chloride has ions, it has a giant ionic lattice structure [2] Diamond has atoms, it has a giant covalent structure [2] Bromine has molecules in it, it has a molecular covalent structure [2] [6]
Band Response Mark
A Candidates use 5 or more indicative points above. They use appropriate specialist terms and the spelling, punctuation and grammar and form and style are of a good standard.
[5]–[6]
B Candidates use 3–4 indicative points above. They use appropriate specialist terms and the spelling, punctuation and grammar and form and style are of a satisfactory standard.
[3]–[4]
C Candidates make reference to 1–2 indicative points above using limited spelling, punctuation and grammar and the form and style are of limited standard and they have made no use of specialist terms.
(ii) Magnesium has a greater conductivity [1]; there are more delocalised electrons [1] or magnesium produces 2 delocalised electrons compared to 1 with sodium [2]
(iii) A
cell
metal
ammeter (or light bulb)
Labels [2] Compare reading on ammeter (brightness of light bulb) [1] [3] 16
11282.01 F 7
AVAILABLEMARKS
14 (a) (i) [1]
(ii) [1]
(iii) A region within an atom that can hold up to two electrons with opposite spins [2]
(b) (i) The extent to which an atom attracts the bonding electrons in a covalent bond [2]
(ii) There is little difference in the electronegativities of carbon and hydrogen [1]
(iii) The molecule is symmetrical and the polarities cancel out [1] (c) (i) H C C H [1]
(ii) nitrogen [1]
(d) Bubble into limewater [1] goes milky [1] [2]
(e) (i) A CH4 = 16 hence lighter than air [1]
(ii) B Cl2 = 71 hence heavier than air [1]
(f) Lower mass [1] less/weaker van der Waals’ forces [1] [2] 16
Section B 80
Total 90
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2019
ChemistryAssessment Unit AS 1assessingBasic Concepts in Physicaland Inorganic Chemistry
[SCH12]MONDAY 20 MAY, MORNING
TIME1 hour 30 minutes.
INSTRUCTIONS TO CANDIDATESWrite your Centre Number and Candidate Number in the spaces provided at the top of this page.Answer all sixteen questions.Answer all ten questions in Section A. Record your answers by marking the appropriate letter on the answer sheet provided. Use only the spaces numbered 1 to 10. Keep in sequence when answering.Answer all six questions in Section B. You must answer the questions in the spaces provided.Do not write outside the boxed area on each page or on blank pages.Complete in black ink only. Do not write with a gel pen.
INFORMATION FOR CANDIDATESThe total mark for this paper is 90.Quality of written communication will be assessed in Question 15(c).In Section A all questions carry equal marks, i.e. one mark for each question.In Section B the figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question.A Periodic Table of Elements, containing some data, is included with this question paper.
Centre Number
Candidate Number
11852
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Section A – Multiple Choice
Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.
Each multiple choice question is worth 1 mark.
1 In which of the following does chromium not have an oxidation state of +6?
A CrO3
B CrO42−
C Cr2O72−
D Cr2O3
2 Which bonding type is described as intermolecular?
A Covalent
B Ionic
C Metallic
D van der Waals’ forces
3 Which of the following is the formula of the nitrite ion?
A N3−
B NH4+
C NO2−
D NO3−
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4 25.0 cm3 of 0.10 M sodium hydroxide solution is exactly neutralised by
A 12.5 cm3 of 0.05 M sulfuric acid.
B 25.0 cm3 of 0.05 M sulfuric acid.
C 12.5 cm3 of 0.20 M sulfuric acid.
D 25.0 cm3 of 0.10 M sulfuric acid.
5 The electronic configuration of a Group III element is
A 1s2 2s2 2p6 3s2 3p6 3d3 4s2.
B 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p1.
C 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p2.
D 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3.
6 The bond angle in ammonia is
A 104.5°.
B 107°.
C 109.5°.
D 120°.
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7 The sulfate(VI) ion can be reduced to sulfur dioxide.
SO42− + xH+ + ye− → SO2 + zH2O
Which of the following represents the correct values of x, y and z?
x y z
A 2 2 4
B 2 4 2
C 4 2 2
D 4 4 2
8 Which type of titration can use phenolphthalein as a suitable indicator?
A Strong acid/strong base only
B Strong acid/strong base and weak acid/strong base
C Strong acid/strong base and strong acid/weak base
D Strong acid/weak base and weak acid/strong base
9 In which of the following molecules does the central atom obey the octet rule?
A BF3
B BeCl2
C ClF3
D PH3
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10 Which species is the most powerful oxidising agent?
A Bromide
B Bromine
C Chloride
D Chlorine
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Section B
Answer all six questions in the spaces provided.
11 Water can act as an acid or as a base. It can either lose or gain hydrogen ions.
(a) State and explain the shape of a water molecule.
[3]
(b) Water can react with hydrogen ions forming hydroxonium ions, H3O+.
(i) Draw a dot and cross diagram to show the bonding in a hydroxonium ion, showing all the outer shell electrons.
[2]
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(ii) Suggest why the bond angle in the hydroxonium ion is greater than the bond angle in water.
[2]
(iii) Suggest why the hydroxonium ion does not react with a hydrogen ion to form H4O2+.
[1]
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12 Four new elements have recently been added to the Periodic Table. The four elements are given below, along with their atomic numbers and the mass numbers of their most common isotope.
element atomic number mass number
nihonium 113 286
moscovium 115 289
tennessine 117 294
oganesson 118 294
(a) What is the meaning of the following terms?
(i) Atomic number
[1]
(ii) Mass number
[1]
(iii) Isotopes
[1]
(b) State and explain which element has the most neutrons.
[2]
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(c) Suggest why tennessine is placed in Group VII of the Periodic Table.
[1]
(d) Erbium is a soft, silvery solid that tarnishes slowly in air. It is used in fibre optic cables. There are six known isotopes of erbium and its relative atomic mass is 167.26.
(i) Define the term relative isotopic mass.
[2]
(ii) The table below gives the percentage abundances of six isotopes in the mass spectrum of erbium.
relative isotopic mass 161.93 163.93 165.93 167.93 169.94
% abundance 0.14 1.60 33.50 22.87 26.98 14.91
Calculate the missing relative isotopic mass.
[3]
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13 Chloroauric acid, HAuCl4, is an orange solid that is used widely in gold refining. During World War II, the Hungarian chemist George de Hevesy dissolved two gold Nobel Prize medals in a mixture of concentrated nitric and hydrochloric acids to prevent the Germans from confiscating them. Later the medals were reconstructed from the dissolved chloroauric acid and returned.
(a) The reaction between gold, concentrated hydrochloric acid and concentrated nitric acid produces chloroauric acid, nitrogen(IV) oxide and water. Write the equation for this reaction.
[2]
(b) Gold is extracted from recycled electronic materials by reaction with chlorine and hydrochloric acid, forming chloroauric acid. Elemental gold is recovered by electrolysis of chloroauric acid.
2Au + 3Cl2 + 2HCl → 2HAuCl4
(i) Deduce the oxidation state of gold in chloroauric acid.
[1]
(ii) With reference to oxidation numbers, explain why this is a redox reaction.
[3]
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(c) When heated, chloroauric acid forms gold(III) chloride and hydrogen chloride gas. The bonding in gold(III) chloride is considered to be covalent.
(i) Suggest, in terms of electronegativity, why the bonding in gold(III) chloride is covalent.
[1]
(ii) Describe the chemical test for hydrogen chloride gas.
[2]
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14 The recommended daily allowance for salt, sodium chloride, is 6.0 g. Eating too much salt can lead to high blood pressure, potentially causing heart disease and strokes.
(a) State the electronic configuration of a sodium atom and use it to explain why sodium is regarded as an s-block element.
[2]
(b) (i) Define the term Avogadro’s constant.
[1]
(ii) Calculate the number of sodium ions in the recommended daily allowance of sodium chloride.
[2]
(c) A solid sample of salt was analysed to confirm the identity of the ions present. A flame test was first conducted on the sample using nichrome wire and concentrated hydrochloric acid to identify sodium ions. The presence of chloride ions was subsequently confirmed.
(i) State two reasons why nichrome wire was used.
[2]
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(ii) State two reasons why concentrated hydrochloric acid was used.
[2]
(iii) State the colour observed in the flame test.
[1]
(d) Describe how the presence of chloride ions could be confirmed in the solid salt.
[4]
(e) A second salt sample was thought to be contaminated with sodium carbonate. Describe a chemical test to confirm the presence of carbonate ions.
[3]
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(f) The salt sample, of mass 6.0 g, contaminated with sodium carbonate was dissolved in water. A solution of magnesium chloride was added, forming a precipitate of magnesium carbonate. The precipitate was filtered off and dried to give 1.4 g of magnesium carbonate.
(i) Draw a dot and cross diagram to show the bonding in magnesium chloride showing all the outer electrons.
[2]
(ii) Write the equation for the reaction between sodium carbonate and magnesium chloride.
[2]
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(iii) Use the following headings to calculate the percentage of sodium carbonate in the salt sample.
Relative formula mass of magnesium carbonate
Number of moles of magnesium carbonate
Number of moles of sodium carbonate
Relative formula mass of sodium carbonate
Mass of sodium carbonate in the sample
Percentage of sodium carbonate in the sample
[6]
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15 The third Period in the Periodic Table from sodium to argon displays a number of periodic trends.
(a) State and explain the general trend in first ionisation energy across Period three.
[3]
(b) (i) Write an equation, including state symbols, for the first ionisation energy of phosphorus.
[2]
(ii) Explain why the first ionisation energy of phosphorus is higher than that of sulfur.
[2]
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(c) The graph below shows the melting points of the elements in the third Period.
Na Mg Al Si P S Cl Ar
1800
1600
1400
1200
1000
800
600
400
200
0
melting point/K
With reference to the structure and bonding of the elements, explain the change in melting point from silicon to argon.
In this question you will be assessed on your written communication skills including the use of specialist scientific terms.
[6]
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16 Lead(II) iodide is yellow and was once used as a pigment in paint until concerns over its toxicity led to its use being discontinued. It has a low solubility in water.
(a) Lead(II) iodide can be prepared by reaction between solutions of potassium iodide and lead(II) nitrate. Write the equation for this reaction.
[2]
(b) 75.6 mg of lead(II) iodide dissolve in 100 cm3 of water at 20°C. Calculate the molarity of iodide ions in a saturated solution of lead(II) iodide at 20°C.
[4]
(c) Chlorine water was added to potassium iodide solution in a test tube.
(i) State the colour observed.
[1]
(ii) A solution of starch was then added to the test tube. State the colour observed.
[1]
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(d) (i) State three observations made when concentrated sulfuric acid is added to solid potassium iodide.
[3]
(ii) Explain why concentrated phosphoric acid does not give iodine when added to solid potassium iodide.
[1]
THIS IS THE END OF THE QUESTION PAPER
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Permission to reproduce all copyright material has been applied for.In some cases, efforts to contact copyright holders may have been unsuccessful and CCEAwill be happy to rectify any omissions of acknowledgement in future if notified.
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MARKSCHEME
11852.01
ADVANCED SUBSIDIARY (AS)General Certificate of Education
2019
ChemistryAssessment Unit AS 1
assessingBasic Concepts in Physical
and Inorganic Chemistry
[SCH12]
MONDAY 20 MAY, MORNING
Standardising Meeting Version
Not to be circulated beyond the Examining Team
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General Marking Instructions
IntroductionMark schemes are published to assist teachers and students in their preparation for examinations. Through the mark schemes teachers and students will be able to see what the examiners are looking for in response to questions and exactly where the marks have been awarded. The publishing of the mark schemes may help to show that examiners are not concerned about finding out what a student does not know but rather with rewarding students for what they do know.
The purpose of mark schemesExamination papers are set and revised by teams of examiners and revisers appointed by the Council. The teams of examiners and revisers include experienced teachers who are familiar with the level and standards expected of students in schools and colleges.
The job of the examiners is to set the questions and the mark schemes; and the job of the revisers is to review the questions and mark schemes commenting on a large range of issues about which they must be satisfied before the question papers and mark schemes are finalised.
The questions and the mark schemes are developed in association with each other so that the issues of differentiation and positive achievement can be addressed right from the start. Mark schemes, therefore, are regarded as part of an integral process which begins with the setting of questions and ends with the marking of the examination.
The main purpose of the mark scheme is to provide a uniform basis for the marking process so that all the markers are following exactly the same instructions and making the same judgements in so far as this is possible. Before marking begins a standardising meeting is held where all the markers are briefed using the mark scheme and samples of the students’ work in the form of scripts. Consideration is also given at this stage to any comments on the operational papers received from teachers and their organisations. During this meeting, and up to and including the end of the marking, there is provision for amendments to be made to the mark scheme. What is published represents the final form of the mark scheme.
It is important to recognise that in some cases there may well be other correct responses which are equally acceptable to those published: the mark scheme can only cover those responses which emerged in the examination. There may also be instances where certain judgements may have to be left to the experience of the examiner, for example where there is no absolute correct response – all teachers will be familiar with making such judgements.
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AVAILABLEMARKS
Section A
1 D
2 D
3 C
4 B
5 B
6 B
7 C
8 B
9 D
10 D [1] for each correct answer [10] 10
Section A 10
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Section B
11 (a) Bent [1]
Two lone pairs and two bonding pairs [1]
Increased repulsion [1] [3] (b) (i)
× H
××O××
×H
H
+
[2]
(ii) As there is only one lone pair [1]
Greater repulsion between bonded pairs of electrons [1] [2]
(iii) Repulsion between positively charged ions [1] 8
12 (a) (i) The number of protons in (the nucleus of) an atom [1]
(ii) The total number of protons and neutrons in (the nucleus of) an atom [1]
(iii) Atoms which have the same atomic number but a different mass number (contain the same number of protons but a different number
of neutrons) [1]
(b) Tennessine [1]
177 neutrons [1] [2] (c) Seven electrons in the outer energy level [1]
(d) (i) The mass of an atom of an isotope of an element relative to one-twelfth of the mass of an atom of carbon-12 [2]
13 (a) Au + 3HNO3 + 4HCl → HAuCl4 + 3NO2 + 3H2O [2] (b) (i) +3 [1] (ii) Au 0 → +3 [1]
Cl 0 → –1 [1]
0 to +3 oxidation and 0 to –1 reduction [1] [3] (c) (i) Small difference/similar in electronegativity [1]
(ii) white fumes/smoke/solid with stopper from bottle of concentrated ammonia solution/glass rod dipped in concentrated ammonia solution [2] 9
14 (a) 1s22s22p63s1 [1]
Outer electron in an s orbital/sub-shell [1] [2] (b) (i) Number of atoms in 12.000 g of carbon-12 [1] (ii) 6/58.5 = 0.103 0.103 × (6.02 × 1023) = 6.20 × 1022 [2] (c) (i) High melting point [1]
Unreactive [1] [2] (ii) Cleans the wire [1]
Helps the solid stick to the wire [1] Forms (volatile) chlorides [1] to a maximum of [2] [2] (iii) Yellow/orange [1] (d) Dissolve the solid in water/dilute nitric acid [1]
Add silver nitrate solution [1]
White [1] precipitate [1] [4] (e) Add solid to a named dilute acid [1]
Effervescence [1]
Gas turns limewater milky [1] [3]
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AVAILABLEMARKS
AVAILABLEMARKS
(f) (I)
Cl
Cl
–
–Mg
2+
[2]
(ii) Na2CO3 + MgCl2 → 2NaCl + MgCO3 [2] (iii) Relative formula mass of magnesium carbonate = 84
Number of moles of magnesium carbonate = 1.4/84 = 0.017
Number of moles of sodium carbonate = 0.017
Relative formula mass of sodium carbonate = 106 Mass of sodium carbonate in the sample = 0.017 × 106 = 1.8 g
Outer electron in same shell more strongly attracted to the nucleus [1] [3]
(b) (i) P(g) → P+(g) + e– [2]
(ii) P has half-filled p sub-shell [1]
Half-filled p sub-shells have stability increased [1] [2]
(c) Indicative Content – comments related to melting points
• Silicon – giant covalent • Many strong covalent bonds to be broken • P, S, Cl (Ar) molecular • Comment on van der Waals • van der Waals depend on RMM • S8 versus P4
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Response Mark
Candidates must use appropriate specialist terms to describe fully the trend in melting point from silicon to argon (using a minimum of 6 points of indicative content including reference to all three distinct parts of the trend). They use good spelling, punctuation and grammar and the form and style are of a high standard.
[5]–[6]
Candidates must use appropriate specialist terms to describe the trend in melting point from silicon to argon (using a minimum of 4 points of indicative content). They use satisfactory spelling, punctuation and grammar and the form and style are of a satisfactory standard.
[3]–[4]
Candidates briefly and partially describe the trend in melting point from silicon to argon (using a minimum of 2 points of indicative content). They use limited spelling, punctuation and grammar and they have made little use of specialist terms. The form and style are of a limited standard.
[1]–[2]
[6] 13
16 (a) Pb(NO3)2 + 2KI → PbI2 + 2KNO3 [2]
(b) 75.6 mg = 0.0756 g
Moles lead iodide in 100 cm3 = 0.0756/461 = 1.64 × 10–4
Moles of iodide ions in 100 cm3 = 3.28 × 10–4
Molarity of iodide ions = 3.28 × 10–4/0.1 = 3.28 × 10–3 M [4]
(c) (i) yellow/brown [1] (ii) blue-black [1] (d) (i) Any three from: steamy/misty fumes violet/purple vapour smell of rotten eggs yellow solid grey-black solid (on the sides of the test-tube) [3]
(ii) Phosphoric acid is not an oxidising agent [1] 12