Top Banner
11

ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =

Sep 06, 2019

Download

Documents

dariahiddleston
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Page 1: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 2: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 3: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 4: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 5: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 6: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 7: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 8: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 9: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 10: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =
Page 11: ecoledz.weebly.comecoledz.weebly.com/uploads/3/1/0/6/31060631/... · arg(z — 3 + 2i) = arg(z — 1) + E Iz—3+2il— Z—3+2i z A—ZL za—ZJ z.2 = —cosÐ + i sine = 10 z3 =