f(x) = x2
f ‘(x) = 𝑑
𝑑𝑥f(x) = 2x
Let, we've taken a 60*60 paper Then, measure what do the volume can be…….
x
60 – 2x
60 – 2x
x
This is the time we
need
Derivative helps us to find the maximum Volume ……
60 cm
30
cm
30
cm
30 cm 30 cm
So, x = 10 cm
10 cm
10 cm
(60 – 2*10)cm = 40 cm
Now, The maximum volume = ( 10 * 40 * 40 ) cm3
= 16000 cm3
Let‘s justify the answer
𝑑2𝑣
𝑑𝑥2= −480 + 24𝑥
𝑑2𝑣
𝑑𝑥2 𝑥=10
= −480 + 24(10)
𝑑2𝑣
𝑑𝑥2 𝑥=10
= −240 < 0
Therefore producing the maximum.
ظهللا الحاف