ELEN3441–FundamentalsofPowerEngineeringLab#10Spring2008Page1Lab 10: Split-phase induction motor. Objective:to examine the construction of the split-phase motor; to learn its wiring connections; to observe its starting and running operations; to measure its starting and operating characteristics under load and no-load conditions. Equipment:Power Supply, DAI, Split-phase/Capacitor start motor (8251), Electrodynamometer (8960), timing belt. Theory: Some means must be provided for getting two phases from the standard single-phase power sup- plied to homes if we need to start and run an AC motor. The process of deriving two phases from one is known as phase-splitting and is usually built into the stator circuit of the AC motor. 2-phase power creates the rotating magnetic field. One method is a special auxiliary winding built into the stator called the start (auxiliary) winding to differentiate it from the actual run (main) winding of the stator. In split-phase AC motors, the start winding is used only for starting the motor and has a high resistance and low inductive reac- tance. The run winding has low resistance and high reactance. When power is first applied, both windings are energized. Because of their different inductive reactances, the run winding current lags the start winding current, creating a phase difference between the two. Ideally, the phase difference should be 90 degrees; but in practical motors, it is much less. Nevertheless, the windings develop fields that are out of phase, which creates a rotating magnetic field in the stator. This applies torque to the rotor, starting the motor. When the motor gets up to operating speed, the rotor is able to follow the alternations of the magnetic field created by the run winding without the field of the start winding. The start winding is then switched out of the circuit by a mechanical device called a centrifugal switch, because it is operated by the centrifugal force created by the rotor revolutions. The direction of a split-phase rotating field can be reversed by reversing the connections to the start winding. This changes the direction of the initial phase shift, creating a -magnetic field rotating in the opposite direction. The motor speed depends essentially upon the AC power line frequency and the number of poles on the stator. When power is applied to a split-phase induction motor, both the running (main) and the starting (auxiliary) windings draw about 4- 5 times their normal full load current. This means that the heat loss in these windings is from 16 to 25 times higher than normal. As a result, the starting period must be kept short to prevent overheating of the windings . The high starting currents also produce a proportionally high current in the squirrel-cage rotor, so that the entire motor heats up very quickly during start-u p. The smaller diameter wire employed in the auxiliary winding of split-phase motors is particularly susceptible to overheating and will burn out if it is not disconnected from the power line within 4
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ELEN 3441 – Fundamentals of Power Engineering Lab # 10 Spring 2008
Page 1
Lab 10: Split-phase induction motor.
Objective: to examine the construction of the split-phase motor; to learn its wiring connections;
to observe its starting and running operations; to measure its starting and operating
characteristics under load and no-load conditions.
Equipment: Power Supply, DAI, Split-phase/Capacitor start motor (8251), Electrodynamometer
(8960), timing belt.
Theory:
Some means must be provided for getting two phases from the standard single-phase power sup-
plied to homes if we need to start and run an AC motor. The process of deriving two phases
from one is known as phase-splitting and is usually built into the stator circuit of the AC motor.2-phase power creates the rotating magnetic field.
One method is a special auxiliary winding built into the stator called the start (auxiliary) windingto differentiate it from the actual run (main) winding of the stator. In split-phase AC motors, thestart winding is used only for starting the motor and has a high resistance and low inductive reac-
tance. The run winding has low resistance and high reactance. When power is first applied, both
windings are energized. Because of their different inductive reactances, the run winding currentlags the start winding current, creating a phase difference between the two. Ideally, the phase
difference should be 90 degrees; but in practical motors, it is much less. Nevertheless, the
windings develop fields that are out of phase, which creates a rotating magnetic field in thestator. This applies torque to the rotor, starting the motor.
When the motor gets up to operating speed, the rotor is able to follow the alternations of the
magnetic field created by the run winding without the field of the start winding. The startwinding is then switched out of the circuit by a mechanical device called a centrifugal switch,
because it is operated by the centrifugal force created by the rotor revolutions. The direction of asplit-phase rotating field can be reversed by reversing the connections to the start winding. This
changes the direction of the initial phase shift, creating a -magnetic field rotating in the opposite
direction.
The motor speed depends essentially upon the AC power line frequency and the number of poles
on the stator.
When power is applied to a split-phase induction motor, both the running (main) and the
starting (auxiliary) windings draw about 4-5 times their normal full load current. This means
that the heat loss in these windings is from 16 to 25 times higher than normal. As a result, thestarting period must be kept short to prevent overheating of the windings.
The high starting currents also produce a proportionally high current in the squirrel-cage rotor,so that the entire motor heats up very quickly during start-up.
The smaller diameter wire employed in the auxiliary winding of split-phase motors is particularly
susceptible to overheating and will burn out if it is not disconnected from the power line within 4
ELEN 3441 – Fundamentals of Power Engineering Lab # 10 Spring 2008
Page 2
to 6 seconds.
The starting current of a split-phase motor is usually 4-5 times normal full-load current. This produces two effects: 1) the motor heats very rapidly during start up; and 2) the high starting
current can cause a large line voltage drop so that the starting torque may be seriously reduced.
The no-load current is usually 60% to 80% of the full-load current, which is high compared tothree-phase motors. Most of the no-load current is used to produce the magnetic field in themotor, and only a small portion is used to overcome the mechanical friction and the copper
and iron losses. Because of the large magnetizing current, the power factor of these motors is
rarely more than 60%, even at full-load.
The split-phase motor, like all single-phase induction motors, vibrates mechanically at twice the
power line frequency. Split-phase motors tend to be much noisier than their 3-phase
counterparts, because of the inherent 120 Hz mechanical vibration. This vibration can be reduced
by using resilient rubber mounting supports.
The power output (in horsepower) of the motor delivered to the load is defined as follows:
,
1.4
10 000
rpm Nm
out hp
T P
ω ⋅ ⋅
=
(10-1)
where ω rpm is the motor speed in revolutions per minute, T Nm is its torque in Newton-meters.
Keep in mind that one horsepower equals approximately to 746 W. The reactive power [var]
can be computed as:
2 2Q S P= − (10-2)
where S is the apparent power [VA], P is the real power [W] consumed by the motor. The
efficiency of the motor is:
,100%
out W Pefficiency
P= ⋅ (10-3)
where Pout,W is the output power delivered to the load in Watts. The motor losses, therefore, are
estimated as:
,out W Losses P P= − (10-4)
Experiment:
1) Examine the construction of the Split-phase/Capacitor start motor module (Figure 10-1).
Identify the main stator winding that is composed of many turns of larger diameter wire.
Identify the auxiliary stator winding – wound inside the main stator winding – that is
composed of fewer turns of smaller diameter wire. Note that there are four main stator
poles and four auxiliary poles. Observe the centrifugal switch mechanism mounted on the
ELEN 3441 – Fundamentals of Power Engineering Lab # 10 Spring 2008
Page 5
5) Connect the motor’s main winding (terminals 1 and 2) to the pre-adjusted 100 V AC
output of the PS (terminals 4 and N ). Turn ON the PS for no longer than 3 seconds. Did
the motor growl? Did the motor turn?
6) Disconnect the main winding (terminals 1 and 2) from the PS. Connect the auxiliary
winding (terminals 3 and 4) to the pre-adjusted 100 V AC output of the PS (terminals 4 and N ). Turn ON the PS for no longer than 3 seconds. Did the motor growl? Did the
motor turn?
7) Connect the main winding (terminals 1 and 2) in parallel to the auxiliary winding
(terminals 3 and 4) and to the pre-adjusted 100 V AC output of the PS (terminals 4 and
N ). Turn ON the PS for no longer than 3 seconds. Did the motor start? Was the motor
noisy? What was the direction of rotation?
8) Interchange the leads connecting two windings in parallel. Turn ON the PS for no longer
than 3 seconds. What was the direction of rotation this time?
9) Connect the circuit as shown in Figure 10-4. Observe that the centrifugal switch is
connected in series with the auxiliary winding and both windings are connected in
parallel to the 100 V AC.
Figure 10-4
Turn ON the PS. The voltmeter should read approximately 100 V. Did the motor start?
Did the centrifugal switch operate (you may judge from a clicking sound coming from
the motor)? Record the motor speed as measured by the tachometer. Reduce the voltage
to approximately 80 V as indicated by the voltmeter. Record the motor speed asmeasured by the tachometer. Increase the voltage to approximately 120 V as indicated by
the voltmeter. Record the motor speed as measured by the tachometer. Return the voltage
to 100 V and turn OFF the PS.
10) Connect the circuit as shown in Figure 10-5. Observe that both windings are connected in
parallel to the 100 V AC and the centrifugal switch is connected in series with both
ELEN 3441 – Fundamentals of Power Engineering Lab # 10 Spring 2008
Page 7
1.0, 1.2, and 1.4 Nm. Note: perform measurements for the torque of 1.2 and 1.4 Nm as
quickly as possible.
14) For the no-load applied to your motor, decrease the input voltage to approximately 50 V.
Start the Oscilloscope and observe both the input voltage and the line current applied to
the motor. Save the oscilloscope data in a txt-file. Turn OFF the PS and disassemble yourcircuit.
In your report:
1) Report and compare the resistances of the main and auxiliary windings you have
measured in Parts 2 and 3. What can you conclude based on these values and on your
observations of these windings wound by wires of different diameter?
2) From your observations in Parts 5, 6, and 7, what do you conclude about the purpose of
the main and the auxiliary windings?
3) From your observations in Parts 7 and 8, what do you conclude about reversing the
direction of a split-phase motor?
4) From your observations in Part 9, would you conclude that the speed of the split-phase
induction motor depends on the voltage? Support your conclusion by your results.
5) From your observations in Part 10, at what speed the centrifugal switch operates? Explain
in details the behavior of the motor as seen in Part 10.
6) Using Matlab and the data recorded in Part 12, plot the dependence of the real power
consumed by the motor on the voltage input to the motor. On separate axes, plot themotor speed as a function of the input voltage under the no-load conditions. Does this
graph support your previous conclusion? On separate axes, plot the power factor as a
function of the input voltage for the split-phase induction motor.
7) Using Matlab and the data recorded in Part 13, plot the dependence of the real power on
the load torque. On separate axes, plot the motor speed and power factor as functions of
the motor load.
8) For the data collected in Part 13 for the full-load operation (1.0 Nm), compute and report
the power delivered by the motor, its efficiency, and the motor losses. Compare theefficiency of the split-phase induction motor to the efficiency of the synchronous motor.
9) Load the oscilloscope data you have collected in Part 14 to Matlab. Plot on the same axes
both the line voltage and the line current as functions of time (the way the oscilloscope
shows signals). Judging from your graphs, would you conclude that the line current
passing through motor windings is sinusoidal? Hint: you may decide to scale one of the