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Algebra 1-2 Flexbook Q1 Solutions – Chapter 2 Chapter 2: Linear Functions 2.1 Write a Function in Slope-Intercept Form 1. (βˆ’3) = 3; (0) = βˆ’3; (5) = βˆ’13 2. (βˆ’9) = 4; (0) = 10;(9) = 16 3. () = 5 βˆ’ 3 4. () = βˆ’2 + 5 5. () = βˆ’7 + 13 6. () = 1 3 +1 7. () = 4.2 + 19.7 8. () = βˆ’2 + 5 4 9. () = βˆ’2 10. () = βˆ’ 11. sample answer: 4 times the sum of a number and 2 is 400 12. βˆ’98.8875 13. 1 2 3 ℃ 14. 40/ 15. 121% 16. 62.52%increase 17. β‰ˆ 6834.78 2.2 Graph a Line in Standard Form 1. = 2 + 5
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Algebra 1-2 Flexbook Q1 Solutions Chapter 2 1-2 Flexbook Q1 Solutions – Chapter 2 Chapter 2: Linear Functions ... 16. sample answer: (-4, -2); Quadrant III is (-x,-y) 17. =0 18.

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Page 1: Algebra 1-2 Flexbook Q1 Solutions Chapter 2 1-2 Flexbook Q1 Solutions – Chapter 2 Chapter 2: Linear Functions ... 16. sample answer: (-4, -2); Quadrant III is (-x,-y) 17. =0 18.

Algebra 1-2 Flexbook Q1 Solutions – Chapter 2

Chapter 2: Linear Functions

2.1 Write a Function in Slope-Intercept Form

1. 𝑓(βˆ’3) = 3; 𝑓(0) = βˆ’3; 𝑓(5) = βˆ’13

2. 𝑓(βˆ’9) = 4; 𝑓(0) = 10; 𝑓(9) = 16

3. 𝑓(π‘₯) = 5π‘₯ βˆ’ 3

4. 𝑓(π‘₯) = βˆ’2π‘₯ + 5

5. 𝑓(π‘₯) = βˆ’7π‘₯ + 13

6. 𝑓(π‘₯) =1

3π‘₯ + 1

7. 𝑓(π‘₯) = 4.2π‘₯ + 19.7

8. 𝑓(π‘₯) = βˆ’2π‘₯ +5

4

9. 𝑓(π‘₯) = βˆ’2π‘₯

10. 𝑓(π‘₯) = βˆ’π‘₯

11. sample answer: 4 times the sum of a number and 2 is 400

12. βˆ’98.8875

13. 12

3℃

14. 40π‘š/π‘šπ‘–π‘›

15. 121%

16. 62.52%increase

17. 𝑀 β‰ˆ 6834.78

2.2 Graph a Line in Standard Form

1. 𝑦 = 2π‘₯ + 5

Page 2: Algebra 1-2 Flexbook Q1 Solutions Chapter 2 1-2 Flexbook Q1 Solutions – Chapter 2 Chapter 2: Linear Functions ... 16. sample answer: (-4, -2); Quadrant III is (-x,-y) 17. =0 18.

2. 𝑦 = βˆ’3

8π‘₯ + 2

3. 𝑦 = 2π‘₯ βˆ’ 5

Page 3: Algebra 1-2 Flexbook Q1 Solutions Chapter 2 1-2 Flexbook Q1 Solutions – Chapter 2 Chapter 2: Linear Functions ... 16. sample answer: (-4, -2); Quadrant III is (-x,-y) 17. =0 18.

4. 𝑦 = βˆ’6

5π‘₯ βˆ’ 4

5. 𝑦 = βˆ’3

2π‘₯ βˆ’ 4

Page 4: Algebra 1-2 Flexbook Q1 Solutions Chapter 2 1-2 Flexbook Q1 Solutions – Chapter 2 Chapter 2: Linear Functions ... 16. sample answer: (-4, -2); Quadrant III is (-x,-y) 17. =0 18.

6. 𝑦 = βˆ’1

4π‘₯ βˆ’ 3

7. x-intercept: (6, 0) y-intercept: (0, 4)

Page 5: Algebra 1-2 Flexbook Q1 Solutions Chapter 2 1-2 Flexbook Q1 Solutions – Chapter 2 Chapter 2: Linear Functions ... 16. sample answer: (-4, -2); Quadrant III is (-x,-y) 17. =0 18.

8. x-intercept: (βˆ’15

2, 0) y-intercept: (0, 6)

9. x-intercept: (8, 0) y-intercept: (0, βˆ’4)

Page 6: Algebra 1-2 Flexbook Q1 Solutions Chapter 2 1-2 Flexbook Q1 Solutions – Chapter 2 Chapter 2: Linear Functions ... 16. sample answer: (-4, -2); Quadrant III is (-x,-y) 17. =0 18.

10. x-intercept: (βˆ’1, 0) y-intercept: (0, βˆ’7)

11. x-intercept: (5

2, 0) y-intercept: (0,

3

2)

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12. x-intercept: (βˆ’7, 0) y-intercept: (0,7

2)

13. x-intercept: π‘›π‘œπ‘›π‘’ y-intercept: (0, 3)

14. sample answer: I think converting to slope intercept form is easier because there are less steps.

15. sample answer: I would graph a vertical line at π‘₯ = βˆ’5. There is not y-intercept and the slope is

undefined.

2.3 Horizontal and Vertical Line Graphs

1. 𝑦 = 0

2. π‘₯ = 0

3. E: π‘₯ = 6

4. B: 𝑦 = βˆ’2

5. C: 𝑦 = βˆ’7

6. A: 𝑦 = 5

7. D: π‘₯ = βˆ’4

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8.

9.

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10.

2.4 Linear Equations in Point-Slope Form

1. 𝑦 βˆ’ 2 = βˆ’1

10(π‘₯ βˆ’ 10)

2. 𝑦 βˆ’ 125 = βˆ’75π‘₯

3. 𝑦 + 2 = 10(π‘₯ + 8)

4. 𝑦 βˆ’ 3 = βˆ’5(π‘₯ + 2)

5. 𝑦 βˆ’ 12 = βˆ’13

5(π‘₯ βˆ’ 10)

6. 𝑦 βˆ’ 3 = 0

7. 𝑦 + 3 =3

5π‘₯

8. 𝑦 βˆ’ 0.5 = βˆ’6π‘₯

9. 𝑦 βˆ’ 7 = βˆ’1

5π‘₯

10. 𝑦 βˆ’ 5 = βˆ’12(π‘₯ + 2)

11. 𝑦 βˆ’ 5 = βˆ’9

10(π‘₯ + 7) OR 𝑦 + 4 = βˆ’

9

10(π‘₯ βˆ’ 3)

12. 𝑦 βˆ’ 6 = βˆ’π‘₯ OR 𝑦 = βˆ’1(π‘₯ βˆ’ 6)

13. 𝑦 + 9 = 3(π‘₯ + 2)

14. 𝑦 βˆ’ 32 = βˆ’9

5π‘₯

15. 𝑦 βˆ’ 20 =1

40(π‘₯ βˆ’ 100) OR 𝑦 βˆ’ 25 =

1

40(π‘₯ βˆ’ 300) The length of the spring before it is stretched is

17.5 cm.

16. 𝑦 βˆ’ 400 = βˆ’35

2π‘₯ OR 𝑦 βˆ’ 50 = βˆ’

35

2(π‘₯ βˆ’ 20) The depth of the submarine five minutes after it

started surfacing would be 312.5 ft.

2.5 Writing and Comparing Functions

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1.

2.

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3.

4.

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5.

6.

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7.

8.

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9.

10.

11. 𝑑(𝑑) = 1100 βˆ’ 30𝑑 OR 𝑑(𝑑) = βˆ’30𝑑 + 1100

12. π‘š = βˆ’30

13. 𝑑(𝑑) = 2000 βˆ’ 20𝑑 OR 𝑑(𝑑) = βˆ’20𝑑 + 2000

14. slope: (#11) π‘š = βˆ’30 (#12) π‘š = βˆ’20; The distanced traveled each day is larger for the migrating

monarch so it flies at a faster rate.

y-intercepts: (#11) (0, 1100) (#12) (0, 2000); The y-intercept in this scenario represents the total

distance the butterfly must travel, or the amount of miles left to travel on day zero.

x-intercepts: (#11) (362

3, 0) (#12) (100, 0); The x-intercept in this scenario represents the amount of

time it takes to travel the total migrating distance.

Domain: (#11) 0 ≀ 𝑑 ≀ 362

3 (#12) 0 ≀ 𝑑 ≀ 100

Range: (#11) 0 ≀ 𝑑(𝑑) ≀ 1100 (#12) 0 ≀ 𝑑(𝑑) ≀ 2000

15. 𝑓(π‘₯) = 1.5 + 3000

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16. π‘š = 1.5

17. The writer needs to sell 4667 books.

2.6 Applications of Linear Models

1. 𝑦 = 350π‘₯ + 1500; x= #of months y=amount paid

Constraints: The number of months (x) would include integers greater than or equal to zero until the car

is paid off. The amount paid would start at $1500 then add an amount of $350 per month until the car

is paid off.

Domain: {0, 1, 2, 3, … } until paid off

Range: {1500, 1850, 2150, … } until paid off

2. 𝑦 =1

2π‘₯ +

17

2; x=# of weeks; y= height of the plant (in)

Constraints: The number of weeks could be 0 weeks or greater, including a fraction of a week. The

height could be greater than or equal to 8.5 inches.

Domain: π‘₯ β‰₯ 0

Range: 𝑦 β‰₯ 8.5

The height of the rose was 8.5 inches when Anne planted it.

3. 𝑦 =1

40π‘₯ + 1; x=weight (lbs.) y=length of spring (m)

Constraints: The weight could be 0 lbs. or greater, including fractions of a pound; the length could be

greater than or equal to 1 m since that is the length of the spring with no weight attached. There would

be a limit to both when the weight would cause the spring to hit the ground.

Domain: π‘₯ β‰₯ 0

Range: 𝑦 β‰₯ 1

The spring would be 4.5 meters long when Amardeep hangs from it.

4. 𝑦 =1

2π‘₯ + 215; x=weight (lbs.) y=distance stretched (ft.)

Constraints: The weight could be 0 lbs. or greater, including fractions of a pound; the length would be

greater than or equal to 215 ft. which is the length of the cord before it is stretched (within the values

that represent a linear function).

Domain: π‘₯ β‰₯ 0

Range: 𝑦 β‰₯ 215

The expected length of the cord would be 290 ft. for a weight of 150 lbs.

5. 𝑦 βˆ’ 20 =1

40(π‘₯ βˆ’ 100); x=weight (g) y=length (cm)

Constraints: The weight could be 0 g or greater, including fractions of a gram; the length would be

greater than or equal to 17.5 cm which is the length of the cord before it is stretched.

Domain: π‘₯ β‰₯ 0

Range: 𝑦 β‰₯ 17.5

6. 𝑦 βˆ’ 400 = βˆ’35

2π‘₯; x=time (mins) y=depth (ft)

Constraints: The time would be between 0 and 22.86 minutes (the time it takes to surface) and the

depth would be any measure between 400 and 0 feet.

Domain: [0, 22.86]

Range: [0, 400]

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7. 𝑦 βˆ’ 2500 = 6(π‘₯ βˆ’ 200); x= # of shades sold y=amount $$ made

Constraints: It would be possible to sell zero shades and any whole number greater than zero so the

positive integers are appropriate; the amount made each month would be a minimum of $1300 plus $6

for each shade thereafter.

Domain: positive integers greater than or equal to zero

Range: {1300, 1306, 1312, … }

8. You can only buy one pound of corn.

9. 165 baked fish dinners were sold.

10. Andrew needs to work 36 hours at his $6/hour job to make $366.

11. She needs to invest $2142.86 or less in the account with 7% interest.

12. 𝑦 = 6π‘₯ βˆ’ 16

13. 𝑝 = βˆ’19

14. The graph of π‘₯ = 1.5 is a vertical line at π‘₯ = 1.5 where the value of x is always 1.5 for any value of y.

15. No it is not a solution.

16. sample answer: (-4, -2); Quadrant III is (-x,-y)

17. π‘š = 0

18.

2.7 Rates of Change

1. Slope is the rate of change when considering a linear equation or function because the rate of change

is constant.

2. traffic light = B; mending tire = E; hills in order of most steep to least steep: A, F, C, D

3. 512

3/β„Žπ‘Ÿ OR 155π‘šπ‘–/3β„Žπ‘Ÿπ‘ 

4. $24/π‘€π‘’π‘’π‘˜

5. sample answer: An elevator moves at 10 ft/sec.

6. x-intercept: (10

3, 0); y-intercept: (0, βˆ’2)

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7.

8. sample answer:

9. Although this can be graphed as a linear function, keep in mind the constraints of dimes and quarters.

You can’t have a negative amount of either and you can’t have a portion of either (i.e. 37.5 dimes). In

reality, the graph should be a set of discrete points rather than a continuous linear function.

Page 18: Algebra 1-2 Flexbook Q1 Solutions Chapter 2 1-2 Flexbook Q1 Solutions – Chapter 2 Chapter 2: Linear Functions ... 16. sample answer: (-4, -2); Quadrant III is (-x,-y) 17. =0 18.

10. domain: {βˆ’2, βˆ’1, 0, 1, 2}; range: {2, 1, 0, 1, 2}

11. 𝑦 = 6.75

12. 3π‘₯ + 1 = 2π‘₯ βˆ’ 35

βˆ’1 βˆ’ 1 subtraction property of equality

3π‘₯ = 2π‘₯ βˆ’ 36 substitution property of equality (simplify)

βˆ’2π‘₯ βˆ’ 2π‘₯ subtraction property of equality

π‘₯ = βˆ’36 substitution property of equality (simplify)

13. π‘Ž = 3

Quick Quiz

1. x-intercept: (25

3, 0); y-intercept: (0,

35

36)

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2. π‘š = βˆ’1

13

3.

4.

5. sample answer: Membership has been steadily increasing over the last 10 years. The increase in

membership was the same from year to year for the first two years.

2.8 Linear and Non-Linear Function Distinction

1. non-linear

2. linear

3. linear

4. linear

5. non-linear

6. linear

7. linear

8. non-linear

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9. linear

10. non-linear

11.

12.

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13.

14.

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15.

16.

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17.

18.

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19.

20.

2.9 Comparing Function Models

2.29 linear

2.30 non-linear

2.31 linear

2.32 not quadratic

2.33 quadratic

2.34 not quadratic

2.35 not exponential

2.36 exponential

2.37 exponential

2.38 exponential

2.39 linear

2.40 quadratic