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NATS 101-06 Lecture 11 Air Pressure Air Pressure
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Page 1: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

NATS 101-06Lecture 11

Air PressureAir Pressure

Page 2: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Review

• ELR-Environmental Lapse RateTemp change w/height measured by a thermometer hanging from a balloonDAR and MAR are Temp change w/height for an air parcel (i.e. the air inside balloon)

• Why Do Supercooled Water Droplets Exist?Freezing needs embryo ice crystalFirst one, in pure water, is difficult to make

Page 3: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Review

• Updraft velocity and raindrop sizeModulates time a raindrop suspended in cloud

• Ice Crystal ProcessSVP over ice is less than over SC water droplets

• Accretion-Splintering-AggregationAccretion-supercooled droplets freeze on contact with ice crystalsSplintering-big ice crystals fragment into many smaller onesAggregation-ice crystals adhere on snowflakes, which upon melting, become raindrops!

Page 4: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Warm Cloud Precipitation

As cloud droplet ascends, it grows larger by collision-coalescence

Cloud droplet reaches the height where the updraft speed equals terminal fall speed

As drop falls, it grows by collision-coalescence to size of a large raindrop

Ahrens, Fig. 5.16

Updraft (5 m/s)

Terminal Fall Speed

(5 m/s)

Page 5: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Ice Crystal Process

Since SVP for a water droplet is higher than for ice crystal, vapor next to droplet will diffuse towards ice

Ice crystals grow at the expense of water drops, which freeze on contact

As the ice crystals grow, they begin to fall

Ahrens, Fig. 5.19

Effect maximized around -15oC

Page 6: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Accretion-Aggregation Process

Accretion (Riming)

Aggregation

Supercooled water droplets will freeze on contact with ice

ice crystalice crystal

Small ice particles will adhere to ice

crystals

snowflakesnowflake

Splintering

Ahrens, Fig. 5.17

Also known as the Bergeron Process after the meteorologist who first recognized the importance of ice in the precipitation process

Page 7: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Recoil Force

What is Air Pressure?

Pressure = Force/Area

What is a Force? It’s like a push/shove

In an air filled container, pressure is due to molecules pushing the sides outward by recoiling off them

Page 8: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Air Pressure

Concept applies to an “air parcel” surrounded by more air parcels, but molecules create pressure through rebounding off air molecules in other neighboring parcels

Recoil Force

Page 9: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Air Pressure

At any point, pressure is the same in all directions

But pressure can vary from one point to another point

Recoil Force

Page 10: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Higher density at the same temperature creates higher pressure by more collisions among molecules of average same speed

Higher temperatures at the same density creates higher pressure by collisions amongst faster moving molecules

Page 11: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Ideal Gas Law

• Relation between pressure, temperature and density is quantified by the Ideal Gas Law

P(mb) = constant (kg/m3) T(K)

• Where P is pressure in millibars

• Where is density in kilograms/(meter)3

• Where T is temperature in Kelvin

Page 12: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Ideal Gas Law

• Ideal Gas Law describes relation between 3 variables: temperature, density and pressureP(mb) = constant (kg/m3) T(K)P(mb) = 2.87 (kg/m3) T(K)

• If you change one variable, the other two will change. It is easiest to understand the concept if one variable is held constant while varying the other two

Page 13: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Ideal Gas Law

P = constant T (constant)

With T constant, Ideal Gas Law reduces to

P varies with Denser air has a higher pressure than less

dense air at the same temperature

Why? You give the physical reason!

Page 14: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Ideal Gas Law

P = constant (constant) TWith constant, Ideal Gas Law reduces to

P varies with T Warmer air has a higher pressure than

colder air at the same densityWhy? You should be able to answer the

underlying physics!

Page 15: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Ideal Gas Law

P (constant) = constant TWith P constant, Ideal Gas Law reduces to

T varies with 1/ Colder air is more dense ( big, 1/ small)

than warmer air at the same pressure

Why? Again, you reason the mechanism!

Page 16: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Summary

• Ideal Gas Law Relates

Temperature-Density-Pressure

Page 17: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Pressure-Temperature-Density

9.0

km

300 mb

1000 mb

400 mb

500 mb

600 mb

700 mb

800 mb

900 mb

Minneapolis Houston

9.0

km

Pressure

Decreases with height at same rate in air of same temperature

Isobaric Surfaces

Slopes are horizontal

Page 18: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Pressure-Temperature-Density

Pressure (vertical scale highly distorted)

Decreases more rapidly with height in cold air than in warm air

Isobaric surfaces will slope downward toward cold air

Slope increases with height to tropopause, near 300 mb in winter

8.5

km 9.5

km

300 mb

1000 mb

400 mb

500 mb

600 mb

700 mb

800 mb

900 mb

Minneapolis Houston

COLD

WARM

Page 19: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Pressure-Temperature-Density8.

5 km 9.

5 km

300 mb

1000 mb

400 mb

500 mb

600 mb

700 mb

800 mb

900 mb

Minneapolis Houston

HHLL

LLHH

PressureHigher along horizontal

red line in warm air than in cold air

Pressure difference is a non-zero force

Pressure Gradient Force Pressure Gradient Force or PGF (red arrow)or PGF (red arrow)

Air will accelerate from column 2 towards 1

Pressure falls at bottom of column 2, rises at 1

AnimationSFC pressure rises SFC pressure falls

PGF

PGF

COLD

WARM

Page 20: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Summary

• Ideal Gas Law Implies

Pressure decreases more rapidly with height in cold air than in warm air.

• Consequently…..

Horizontal temperature differences lead to horizontal pressure differences!

And horizontal pressure differences lead to air motion…or the wind!

Page 21: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Review: Pressure-HeightRemember• Pressure falls very

rapidly with height near sea-level 3,000 m 701 mb2,500 m 747 mb2,000 m 795 mb1,500 m 846 mb1,000 m 899 mb500 m 955 mb0 m 1013 mb

1 mb per 10 m height

Consequently………. Vertical pressure changes from differences in station elevation dominate horizontal changes

Page 22: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Station Pressure

Pressure is recorded at stations with different altitudes

Station pressure differences reflect altitude differences

Wind is forced by horizontal pressure differences

Horizontal pressure variations are 1 mb per 100 km

Adjust station pressures to one standard level:Mean Sea Level

Ahrens, Fig. 6.7

Page 23: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Reduction to Sea-Level-Pressure

Station pressures are adjusted to Sea Level PressureSea Level Pressure Make altitude correction of 1 mb per 10 m elevation

Ahrens, Fig. 6.7

Page 24: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Correction for TucsonElevation of Tucson AZ is ~800 m

Station pressure at Tucson runs ~930 mb

So SLP for Tucson would be

SLP = 930 mb + (1 mb / 10 m) 800 m

SLP = 930 mb + 80 mb = 1010 mb

Page 25: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Correction for DenverElevation of Denver CO is ~1600 m

Station pressure at Denver runs ~850 mb

So SLP for Denver would be

SLP = 850 mb + (1 mb / 10 m) 1600 m

SLP = 850 mb + 160 mb = 1010 mb

Actual pressure corrections take into account temperature and pressure-height variations, but 1 mb / 10 m is a good approximation

Page 26: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

You Try at Home for PhoenixElevation of Phoenix AZ is ~340 m

Assume the station pressure at Phoenix was ~977 mb at 3pm yesterday

So SLP for Phoenix would be?

Page 27: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Sea Level Pressure Values

Ahrens, Fig. 6.3

882 mb Hurricane Wilma October 2005

Page 28: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Summary

• Because horizontal pressure differences are the force that drives the wind

Station pressures are adjusted to one standard level…Mean Sea Level…to remove the dominating impact of different elevations on pressure change

Page 29: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Ahrens, Fig. 6.7

PGF

Page 30: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Key Points for Today

• Air Pressure

Force / Area (Recorded with Barometer)• Ideal Gas Law

Relates Temperature, Density and Pressure• Pressure Changes with Height

Decreases more rapidly in cold air than warm • Station Pressure

Reduced to Sea Level Pressure

Page 31: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Isobaric Maps

• Weather maps at upper levels are analyzed on isobaric (constant pressure) surfaces.(Isobaric surfaces are used for mathematical reasons

that are too complex to explain in this course!)

• Isobaric maps provide the same information as constant height maps, such as:

Low heights on isobaric surfaces correspond to low pressures on constant height surfaces!

Cold temps on isobaric surfaces correspond to cold temperatures on constant height surfaces!

Page 32: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Isobaric Maps

Ahrens, Fig. 2, p141

504 mb504 mb

496 mb496 mb

PGF

Downhill(Constant height)

Some generalities:

1) High/Low heights on an isobar surface correspond to High/Low pressures on a constant height surface

2) Warm/Cold temps on an isobaric surface correspond to Warm/Cold temps on a constant height surface

3) The PGF on an isobaric surface corresponds to the downhill direction

Page 33: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Contour Maps

Display undulations of 3D surface on 2D map

A familiar example is a USGS Topographic Map

It’s a useful way to display atmospheric quantities such as temperatures, dew points, pressures, wind speeds, etc.

Gedlezman, p15

Page 34: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Rules of Contouring(Gedzelman, p15-16)

“Every point on a given contour line has the same value of height above sea level.”

“Every contour line separates regions with greater values than on the line itself from regions with smaller values than on the line itself.”

“The closer the contour lines, the steeper the slope or larger the gradient.”

“The shape of the contours indicates the shape of the map features.”

Page 35: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Contour Maps “To successfully isopleth the 50-degree isotherm, imagine that you're a competitor in a roller-blading contest and that you're wearing number "50". You can win the contest only if you roller-blade through gates marked by a flag numbered slightly less than than 50 and a flag numbered slightly greater than 50.”

https://www.e-education.psu.edu/gened/meteo101/Examples/Section2p02.html

Click “interactive exercise”

https://www.e-education.psu.edu/gened/meteo101/Examples/Section2p03.html

https://www.e-education.psu.edu/gened/meteo101/Examples/Section2p04.html

Click “interactive isotherm map”

From

Page 36: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

570 dam contour570 dam contour

Page 37: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

576 dam contour576 dam contour

Page 38: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

570 and 576 dam contours570 and 576 dam contours

Page 39: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

All contours at All contours at 6 dam spacing6 dam spacing

Page 40: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

All contours at All contours at 6 dam spacing6 dam spacing

Page 41: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

-20 C and –15 C -20 C and –15 C Temp contoursTemp contours

Page 42: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

-20 C, –15 C, -10 C -20 C, –15 C, -10 C Temp contoursTemp contours

Page 43: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

All contours at All contours at 55oo C spacing C spacing

Page 44: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Height contours Height contours Temp shadingTemp shading

Page 45: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

PGFWind

Page 46: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Key Concepts for Today • Station Pressure and Surface Analyses

Reduced to Mean Sea Level Pressure (SLP) PGF Corresponds to Pressure Differences

• Upper-Air Maps

On Isobaric (Constant Pressure) Surfaces PGF Corresponds to Height Sloping Downhill

• Contour Analysis

Surface Maps-Analyze Isobars of SLP Upper Air Maps-Analyze Height Contours

Page 47: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Key Concepts for Today

• Wind Direction and PGF

Winds more than 1 to 2 km above the ground are perpendicular to PGF!

Analogous a marble rolling not downhill, but at a constant elevation with lower altitudes to the left of the marble’s direction

Page 48: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Assignment

• Reading - Ahrens pg 148-149

include Focus on Special Topic: Isobaric Maps• Problems - 6.9, 6.10

Page 49: Air Pressure NATS 101-06 Lecture 11 Air Pressure.

Assignment

Topic – Newton’s Laws

Reading - Ahrens pg 150-157

Problems - 6.12, 6.13, 6.17, 6.19, 6.22