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PSYCHROMETRY AND CALCULATIONS FOR AIR CONDITIONING
DESIGN
INTRODUCTION
Comfort air conditioning is the process of keeping a giving space within specified conditions
of temperature, relative humidity, etc. Maintaining these specified conditions become
necessary as a result of the unpleasantly high temperatures from solar heat gains and heat
gains from lighting and other equipment in the confined space. The process is quite a complex
one requiring an understanding of the properties of air in its different conditions as it passes
through the process. Air primarily is a mixture of two major component gases (oxygen and
nitrogen), traces of a number of other gases and water vapour. The water vapour in the air is
condensable (under right conditions of temperature and pressure) and where all vapour in
the air is condensed out, the air is referred to as Dry air. The typical percentage proportionof the various components of dry air is given below:
Gas Proportion (%)
Nitrogen 78.048
Oxygen 20.9476
Carbon dioxide 0.0314
Hydrogen 0.00005
Argon 0.9347
It should be noted that the composition varies slightly at different geographic locations and
from time to time.
The natural means of introducing water vapour into air is through evapo-transpiration (from
plants) and evaporation (from humans in form of sweat or from water bodies). As the
conditions of temperature, pressure vary, water molecules drop out or are added to the
surrounding air. The rate at which these occur is dependent on temperature, pressure and
wind velocity. Also the water vapour holding capacity of the air is temperature and pressure
dependent. It is therefore vital for any one studying air conditioning to understand that the
air under study is a mixture of two different gaseous substances. One of these is the dry air
with composition as outlined above and the other, water vapour. The amount of water
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vapour contained in moist air within the temperature range of -18 0C to 37 0C varies from 0.05
to 3% by mass. This variation has a critical influence on the characteristics of moist air.
BASIC AIR-CONDITIONING TERMINOLOGIES
Dry bulb temperature, DB ( 0C or 0F): this is the ambient air temperature as measured by a
standard temperature measuring device.
Wet bulb temperature, WB ( 0C or 0F): this is the temperature recorded by a thermometer that
has its bulb wrapped in moist cloth and rotated rapidly in the air to cause evaporation of its
moisture. A fast evaporation from the cloth indicates low moisture content of the
surrounding air while a slow evaporation indicates that the surrounding air is already
moisture-laden. In dry air, moisture rapidly evaporates from the cloth drawing heat from thethermometer and producing a lower temperature reading usually called the wet-bulb
depression (the difference between the DB and WB temperatures)
Relative humidity, RH (%): As mentioned earlier, the moisture (water vapour) holding
capacity of air varies with temperature. This therefore means that for any given temperature,
there is an amount of moisture that will bring the air to saturation (i.e. to 100% of its water
vapour holding capacity). This water vapour contained in the air exerts its own pressure
(termed vapour pressure ). Relative humidity is the ratio of the vapour pressure of the moist
air (the air being considered) to the vapour pressure of the same air if it were to be at 100%saturation at the same temperature.
Dew point temperature, T dew (0C or 0F): this is the temperature of saturated air which has the
same vapour pressure as the air under consideration. Note that saturated air has the same
WB and DB temperatures. Because the air has reached saturation, condensation begins at
this temperature and will continue if lowered further.
Sensible heat Q S : addition or extraction of heat from a substance results in changes in the
temperature of the substance. The sensible heat is a measure of the thermal energy
associated with a change in the temperature of a substance. It is termed sensible because,
this form of heat can be felt by the sense of touch.
Latent heat Q L: this is a measure of the thermal energy associated with a change of state or
phase of a substance. Take as an example the heating of a kettle of water. As heat of added,
the temperature of the water is felt to rise (sensible heat). At a point, say about 100 0C, the
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temperature stays the same even as more heat is added. The additional heat is used up in
changing the state of the water from the liquid state to the vapour state. This added heat
used up is the latent heat.
Enthalpy: this is the measure of the total heat (sensible and latent heat) in a substance and isa measure of its internal energy and capacity to do work
PSYCHROMETRY
Water vapour, air, temperature and pressure interact with each other with consequences
which can be exploited for heating processes or cooling processes. For example, as air
temperature rises, its capacity to hold water vapour rises also and the warmer air becomes
less dense. Psychrometry is the study of the behavior of air and water vapour and a soundknowledge of Psychrometrics is necessary to carry out air-conditioning calculations. The
terminologies discussed above are particularly relevant in Psychrometry. The psychrometric
chart is a graphical representation of the thermodynamic properties of moist air and various
air-conditioning processes and cycles. The figure below shows the variables shown in a
typical psychrometric chart for any given point.
The chart helps the designer to calculate and analyze the work and energy transfer during
various air-conditioning processes and cycles. Typical arrangement of the coordinates on the
chart is shown below: It should be noted that psychrometric charts in use today have two
kinds of basic coordinates. Those published by the American Society of Heating Refrigeration
and Air-conditioning Engineers (ASHRAE) and the Charted Institution of Building Services
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Engineering (CIBSE) use the h-w coordinates, where enthalpy h and humidity ration w are the
coordinates. Charts published by Carrier Corporation and the Trane Company use the T-
w coordinates. An abridged ASHRAE psychrometric chart is shown below.
To understand the use of the chart above, lets assume an air -conditioned room at sea level
has an indoor design temperature of 75 0F and a relative humidity of 50% and we want to
determine the humidity ratio, enthalpy h, dew point T dew of the indoor air. To do this, we
shall follow these steps
1. Establish the room condition of T = 75 0F and a relative humidity of 50% on the chart (point
r). This is the point where the temperature line at 75 0F meets the 50% -line.
2. Draw a horizontal line toward the humidity ratio scale w-line , w lb/lb. This line cuts the
humidity ratio scale at w r = 0.0093 lb/lb.
3. To get the enthalpy, draw a line through point r parallel to the enthalpy h-line . This gives the
enthalpy of the room air as h r = 28.1 Btu/lb.
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4. Draw a horizontal line left ward from point r to meet the saturation curve. This cuts the curve
at 55 0F. This is the dew point temperature, T dew .
By using the chart, we can also determine the specific volume and the wet bulb temperature
of the room air by simply drawing lines parallel to these coordinates from the room statepoint, r. To determine these two values draw a line from the room point r, parallel to the
specific volume line ( v-line) to get the specific volume and another line parallel to the wet
bulb temperature line ( T *-line) . These give the room air specific volume and wet bulb
temperatures as v r = 13.67 ft 3/lb and T * = 62.5 0F respectively.
With our room air considered as state 1, now let us assume that a quantity of air of different
temperature and relative humidity (in state 2) is brought into the room. What happens? Both
streams of air will mix to form a third state point (state 3). From the principles of
conservation of mass and conservation of energy (both well dealt with in manythermodynamics textbooks), the three state points lie on a straight line in a mass-energy
coordinate system as in psychrometric charts published by the CIBSE and ASHRAE. It shows
clearly that when two air streams mix adiabatically, the mixture state (state 3) lies on the
straight line which joins state point 1 and state point 2. Also the position of state point 3 is
such that the line is divided inversely as the ratio of the masses of dry air in the constituent
airstreams. This is shown below.
Since air conditioning is the treatment or conditioning of air to alter its temperature and
moisture content to suit specific requirements, the psychrometric chart is vital in tracing,
analyzing and predicting the changes occurring in the air as it is subjected to cooling, heating,
humidification, dehumidification etc. Using the chart we can determine the amount of heat
to be removed from (or added to) a space or the amount of moisture to be removed from (or
added) to change the condition of the air in the room.
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AIR-CONDITIONING LOADS
The main purpose of the air conditioning system is to provide suitable thermal conditions of
comfort to the occupants or to provide suitable conditions for process or manufacturingapplications. It is therefore vital to carry out cooling (or heating) load calculations to ensure
that the cooling (or heating) equipment designed or selected serves the intended purpose of
maintaining the required conditions in the conditioned space. For human comfort, it is
required to keep the dry bulb temperature, the relative humidity and air velocity within
control limits.
Principal sources of heat transfer to a conditioned space are:
Direct or indirect transmission of solar radiation from the sun. This accounts for a major partof the building heat gain. By proper design and orientation of the building, selection of
suitable materials and landscaping, the overall energy cost (initial and operational) can be
reduced.
Conduction through building elements (roofs, walls, windows etc.)
Infiltration of air into conditioned space through cracks
Heat emission by building occupants
Ventilation. This normally quoted in terms of volume is the quantity of outside air required
to dilute contamination from all sources to an acceptable level. This is different from the
conditioned air being supplied to the room. The later is usually quoted in terms of mass of air
required to absorb any surplus heat or moisture within the conditioned space or conversely,
to supply heat or moisture to keep the space within specified conditions.
Electrical load due to lighting
Load due to office equipment and or process machinery.
Design challenges
I choose to discuss the design challenges now before I go any further so as to give the reader
an understanding of the shortcomings being encountered in the design of air conditioningsystems for a location as mine, Nigeria. Some of these challenges are:
First, in the design of the space to be air-conditioned most architects do not take into
consideration solar geometry for the location being considered as an energy consideration for
the buildings orientation. This accounts for hi gh energy requirements of the air conditioning
equipment.
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Second, we do not have proper documentation and standards for the properties of the
materials used in our building construction industry. This is vital as the mechanism of heat
transfer is a function of the thermal transmittance coefficient ( U) and the temperature
difference across the material under consideration.
Third, for any given location the variations in temperature, humidity and wind integrate to
provide the climate experience. A study of these interrelationships, their hourly and daily
variations, the seasonal changes in climatic conditions give rise to design guides for each
geographical location. These design guides as published in developed countries such as USA,
Canada, UK etc. provide valuable data for calculating air conditioning loads. They provide
information such as design outdoor and indoor conditions for various locations and building
use. They also provide peak solar gain times, peak solar cooling load in watt per building area
exposed to sunlight etc.
With these challenges, variations will surely exist in our air conditioning load calculation and
therefore a lot of experience is needed in applying data from imported standards and guides.
CALCULATIONS FOR AIR CONDITIONING DESIGN
Having outlined the various sources of heat gain above, it should be borne in mind that when
designing air conditioning systems, the principal concern is directed towards heat gains,
especially during the summer months. The reason for this approach is because heat gainspresent more searching demands than heat losses. The heat gain in any air conditioning
process can be considered in two main parts sensible heat gains and latent heat gains.
Sensible heat gains: as discussed earlier, this refers to that part of the heat which changes the
temperature of the conditioned space. The quantity of air required to combat this heat gain is
directly proportional to the difference in temperature between the supply air and the air in
the conditioned space. This temperature difference is usually limited to a maximum of 20 0 in
order to avoid draft within the space. The sensible heat gain is calculated using:
H = M *c *T
Where H = sensible heat gain (kW)
M = mass of supply air (kg/s)
C = specific heat capacity of air (kJ/kg K)
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T = design temperature rise (K)
Latent heat gain: these do not cause any increase in temperature but affect the moisture
content of the air in the conditioned space. If the air in the room is not saturated, then it hasthe capacity to absorb water vapour from the room thereby causing the moisture content to
rise. As we know, it is necessary to provide heat for any form of evapora
tion to take place. It is therefore customary to
consider the addition of moisture to the air in the room in terms of kW of latent heat ratherthan kg/s of water evaporated.
From the above, the conditioned air supplied to the room has dual function: it is cool enough
initially to suffer a temperature rise up to the room dry-bulb temperature in order to offset
the sensible heat gains, and its initial moisture content is low enough to permit a rise to the
value of the room moisture content as latent heat gains are offset. This is shown below
where S is the supply state point and R is the return state point.
Heat Gain Equations
Having determined design outdoor and indoor conditions from necessary design guides, the
formulae given below are employed for single space heat load considerations.
S/N Quantity Formula Contributes to
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1. Heat gain for roof Q r = Ur * Ar * CLTDr Sensible Heat
2. Heat gain for walls Q w = Uw * Aw * CLTDw Sensible Heat
3. Heat gain for glass(unshaded)
Q g = Ug * Ag * CLTDg Sensible Heat
4. Heat gain for glass(Shaded)
Q gs = Ags * SC * SHGF* CLF Sensible Heat
5. Heat gain forpartitions (walls,
ceilings, floors)
Q p = Up * Ap * TDp Sensible Heat
6. Heat gain due tointernal lights
Q SL = (3.41 * W *CLF*zone% *P)/100 Sensible Heat
7. Sensible Heat gain
from occupants
Q sp = NP *SHP * CLFP * P Sensible Heat
8. Latent Heat gain fromoccupants
Q LP = NP * LHP * P Latent Heat
9. Sensible Heat gainfrom equipment
Q SEQ = 3.41 * W EQ * CLFEQ * P Sensible Heat
10. Latent Heat gain fromequipment
Q LEQ = Lat.Equip Latent Heat
11. Sensible heat due to
outside air (ventilationor infiltration)
Q SOA = 1.1 * CFM * TD OA * AF Sensible Heat
12. Latent Heat gain dueto outside air
(ventilation or
infiltration)
Q LOA = 0.68 * CFM * g * AF Latent Heat
Q = Heat gain, Btuh
U = Design coefficient of thermal transmission, Btuh/ft 2-F
A = Net area, ft 2
CLTD = Cooling load temperature difference, F
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SC = Shading coefficient
SHGF = Maximum solar heat gain factor for north facing glass, Btuh/ft 2
CLF = Cooling load factor for north facing glass, dimensionless
TD = Design temperature difference across the partition, floor, or ceiling, F
W = Total wattage of lighting fixtures including ballast effects for fluorescent lights, Watts
Zone % = Percentage of lighting load to zone (100% if no plenum)
P = Profile i.e. the internal operating loads profile at given hour, fraction
SHP = Sensible heat gain per person, Btuh/person
NP = Number of people in space considered
CLFP = Cooling load factor to account for cooling system running 24 hours/day (equals to 1
since cooling system does not run 24 hours/day)
P = Internal operating profile percent at given hour, fraction
WEQ = Recommended rate of heat gain, Btuh/ft 2 * ft 2 or Watts
CLFEQ = Cooling load factor to account for hours of operation of equipment
Lat.Equip = Latent heat gain per piece of equipment, Btuh
CFM = Infiltration or ventilation rate, CFM
TDOA = Inside outside temperature difference at peak time, F
AF = Altitude factor, dimensionless
g = Inside outside humidity ratio difference at peak time, grains of moisture.
In considering the cooling load for a whole building, the load from the single spaces obtained
from the above formulae are summed up and further calculations are done to determine the
following:
Supply fan power, Q SF
Supply duct heat load, Q SD
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Return air load (recirculation fan power and heat gain through extract ventilated luminaires),
Q RA
Reheat load, Q RH
In that case, the design refrigeration load will be given by:
Q R =(Q + Q SF + Q SD + Q RA + Q RH) * f P
Where Q R = design refrigeration load and
f P = factor to cover chilled water pump power and heat gain to pipes.
APPLICATION OF PSYCHROMETRICS TO AIR CONDITIONING DESIGN
Let us now look at a practical application of the psychrometric chart in the design of an air
conditioning system. As the figure below shows, the design conditions are as follows:
Room is to be maintained at 24 0C (75.2 0F) and a relative humidity of 50% RH
Outdoor condition is 34 0C (93.2 0F) and 40% RH
Total room sensible heat Q SR = 135 kW
Total room latent heat Q LR= 30 kW
Ventilation requirement is 1outdoor air to 3 re-circulated air (by mass)
Outside fresh air first flows over coil 1 where it is cooled to 10 0C DBT and 85% RH.
The air is now mixed with the re-circulated air and through the fan, passed through coil 2 and
sensibly cooled to 12 0C DBT to be delivered to the room.
We want to find the mass flow rates of the supply air at the grill and the outside air required
for ventilation. Also, we would like to find the dry bulb temperature and enthalpy of the air
handled by the fan, and the required cooling capacity of the cooling unit.
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Mass flow rate of supply air.
From the room conditions, using the chart below, locate the point at which the dry bulb
temperature of 24 0C meets the 50% RH curve. For clarity, you can copy the chart and print it
out in A3 sized paper. From the point located follow the horizontal line rightward to hit thehumidity ratio axis. This cuts the axis at w i = 0.0093 kg/kg. This is the humidity ratio of the
room air.
Assuming a difference of 12 0 between temperature of air supplied to the room and that to be
maintained in the room, then the supply air temperature would then be 12 0C.
The mass flow rate of air supplied is obtained from sensible energy balance,
mSA = Q SR / (c *T)
= 135 / (1.021 * 12)
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= 11 kg/s
The moisture content of the supply air can be obtained from latent energy balance,
wS = w i (Q LR /( m SA * h fg))
where h fg = latent heat of vaporization of water, 2501 J/kg. Therefore,
wS = 0.0093 (30 / (11 * 2501) = 0.0089 kg/kg
Back to the chart, taking a horizontal line from the humidity ratio axis at 0.0089 kg/kg to cut
the 12 0C DBT line, gives the supply air RH to be 100%.
Ventilation
As noted earlier, ventilation is required to dilute contamination from all sources to an
acceptable level. The volume of this air is usually related to the type of activity with the space
and the number of persons in the space. Since 25% of the supply air is fresh air,
Mass flow rate of fresh air, m o = 0.25 * 11 = 2.75 kg/s
Mass flow rate of re-circulated air, m rc = 0.75 * 11 = 8.25 kg/s
Condition of mixed air (handled by fan)
Using the sensible energy balance equation, the conditions of the mixed air can be found as
follows:
Temperature of mixed air:
t m = (mo* t o + m rc * t i) / (m o + m rc)
= (2.75 * 34 + 8.25 * 24) / (2.75 + 8.25)
= 26.5 0C
Humidity ratio of mixed air:
w m = (mo * wo + m rc * w i) / (m o + m rc)
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= (2.75 * 0.0134 + 8.25 * 0.0093) / (2.75 + 8.25)
= 0.0103 kg/kg
Enthalpy of mixed air:
hm = (mo * ho + m rc * h i) / (m o + m rc)
= (2.75 * 68 + 8.25 * 48) / (2.75 + 8.25)
= 53 kJ/kg
Required cooling capacity of coil
From the psychrometric chart, the enthalpy of air at the exit of the coil, h c = 34 kJ/kg
Therefore required coil capacity, Q c = mS * (hm hc)
= 11 * (53 34)
= 209 kW
If you have not yet printed a large copy of the psychrometric chart above do so now. Then on
the chart, try locating the state points discussed in this example. You should be able to locate
the following state points on the chart.
Inside design condition (t i = 24 0C, 50% RH, and w i = 0.0093 kg/kg). What is the enthalpy of
this state point from the chart?
Outdoor design condition (t o = 340C, 40% RH). Find w o and h o
Condition of the mixed outdoor and re-circulated air streams (t m = 26.5 0C, wm= 0.0103 kg/kg)
Supply air condition (t s = 12 0C, ws = 0.0089 kg/kg). Can you find the enthalpy of this state
point?
Plotting these points on the chart will help you visualize the processes involved in air
conditioning design.
It is not possible to cover completely all the necessary issues of psychrometrics and air
conditioning design in any one post. Feel free to contact me should the need arise for clarity
on any item discussed in this post or if you need assistance on your design.