Aims: • To be able to use the Mid-ordinate rule to calculate an estimate for the area. • To be able to check your estimated answer with the acurate one using your calculator. Numerical Methods Lesson 3
Jan 18, 2016
Aims:
• To be able to use the Mid-ordinate rule to calculate an
estimate for the area.
• To be able to check your estimated answer with the acurate
one using your calculator.
Numerical Methods Lesson 3
Intro
The Mid-ordinate Rule
y
x
The Mid-ordinate Rule is similar to the Trapezium Rule. It uses a series of rectangles of equal width to estimate the area under a graph between two points a and b. The height of each rectangle is determined by the height of the curve at the m_________________ of the interval.
b
aydx hy1 + hy2 + hy3 +. . . + hyn-1
+ hyn
a b
Area h(y1 + y2 + y3 +. . . + yn-
1 + yn)
h h h hO
yny1 y2 y3
The Mid-ordinate RuleArea h(y1 + y2 + y3 +. . . + yn-1 + yn)
x 5.5 6.5 7.5
y = f(x) 12.25 30.25 42.25 56.2520.25
Approximate using the mid-ordinate rule with 5 strips.
Example Question 1
dxx8
3
2 We tabulate as below. dxx
8
3
2
x
y = f(x)
2 4 6 80 1 3 5 7
A 1(12.25 + 20.25 + 30.25 + 42.25 + 56.25) = 161.25
3.5 4.5
b aheight h
n
The Mid-ordinate RuleArea h(y1 + y2 + y3 +. . . + yn-1 + yn)
x
y = f(x)
x 1.75 2.25 2.75
y =f(x) 0.9412 0.3902 0.2462 0.1649 0.1168
Approximate using the mid-ordinate rule with 6 strips. 3
0 1
1dx
x2
Example Question 2
We tabulate as below. 3
0 1
1dx
x2
A ½(0.9412 + 0.64 + 0.3902 + 0.2462 + 0.1649 + 0.1168) = 1.25 (2 dp)
0.64
0.5 1 1.5 2 2.5 3
0.25 0.75 1.25
b ah
n
The Mid-ordinate RuleArea h(y1 + y2 + y3 +. . . + yn-1 + yn)
x
y = f(x) 3.375 42.875 91.125
Approximate using the mid-ordinate rule with 4 strips. 5
1dxx3
Example Question 3
15.625
We tabulate as below. 5
1dxx3
A 1(3.375 + 15.625 + 42.875 + 91.125) = 153
1.5 2.5 3.5 4.5
Check ans approximately correct with your calculator: Run ModeOPTN, F4 (calc), F4 (intergrate) enter X^3,1,5) press EXE 156
b ah
n
The Mid-ordinate RuleArea h(y1 + y2 + y3 +. . . + yn-1 + yn)
x
y = f(x) 0.25 0.25
Example Question 4
1
A /3(0.25 + 1 + 0.25) = 1.57 (2 dp)
Approximate using the mid-ordinate rule with 3 strips.
0
2 dxxsin
We tabulate as below.
0
2 dxxsin
/30 2/3
5/6/6 /2
b ah
n
The Mid-ordinate Rule
Question 1: Approximate using the mid-ordinate rule with 4 strips. dxx4
0
2 21dxx
4
0
2Question 2: Approximate using the mid-ordinate rule with 5 strips. dx
x
12
1
dxx
12
1 0.6919
Question 3: Approximate using the mid-ordinate rule with 4 strips.
dx Sinx3
2
0
1.736
Question 4: Approximate using the mid-ordinate rule with 4 strips. dx Sinx3
2
0
dx1)(2x1
0
dx1)(2x1
0 1.40
Homework, do exercise C page 139
Exercises
0
2sin dxx
2
021
1dx
xusing the mid-ordinate
rule with 4 strips, giving your answer to 3 d.p. How can your answer be improved?
1. Estimate
rule with 3 strips. Give your answer to 3 s.f.
2. Estimate using the mid-ordinate
N.B. Radians !
Solutions
)( 4321 yyyyhA
246203902064094120 y
751251750250 x
,4n
50h
The answer can be improved by using more strips.
2
021
1dx
x1.
) p. d. 3( 1091)(50 4321 yyyyA
1x
)( 321 yyyhA
25.01250y6
5
26
x
,3n
3
h
) f. s. 3( 571
Solutions
0
2sin dxx
1x
The red shaded areas should be included but are not.
The blue shaded areas are not under the curve but are included in the rectangle.
The following sketches show sample rectangles where the mid-ordinate rule under- and over-estimates the area.
Under-estimates( concave upwards )
Over-estimates( concave downwards )
Past Exam Question
Questions about the integral ∫02 √(1+x3)dx. The value of this integral, correct to
four decimal places, is 3.2413.
The percentage error in the use of the mid-ordinate rule in question 5 is (a) -0.65% (b) -0.66% (c) 1.30% (d) 1.28%
Integration on GDC
Multi guess worksheet
Three minutes to answer 3 out of
these 10 questions on your white
boards.
Discuss in pairs your comments – 2 minutes
Share with class
What I liked most about this lesson was…
I was surprised by…
After this lesson I feel…
I might have learned more if…
Today I learned…
One thing I’m not sure about is…
I was interested in…
The most useful thing was…
One thing I want to find out more about is…
What still puzzles me is…Here’s a ‘fun’ picture of the mid-ordinate rule
Worksheet
Question 1: Approximate using the mid-ordinate rule with 4 strips.
dxx4
0
2Question 2: Approximate using the mid-ordinate rule with 5 strips.
dxx
12
1
Question 4: Approximate using the mid-ordinate rule with 4 strips.
dx Sinx3
2
0
Question 3: Approximate using the mid-ordinate rule with 4 strips.
dx1)(2x1
0
Question 1: Approximate using the mid-ordinate rule with 4 strips.
dxx4
0
2Question 2: Approximate using the mid-ordinate rule with 5 strips.
dxx
12
1
Question 4: Approximate using the mid-ordinate rule with 4 strips.
dx Sinx3
2
0
Question 3: Approximate using the mid-ordinate rule with 4 strips.
dx1)(2x1
0