Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017 May 10, 2017 Aim : SWBAT the coordinate plane and graph a linear equations using a T-chart. Do Now : Read the notes on Page 1 and do #'s 1 - 6 at the bottom of the page. Homework : Pages 5 (bottom), 6 & 7 in the Unit 6A Packet Unit 6A Quiz is Tuesday (Pages 1 - 17)
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Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
May 10, 2017
Aim: SWBAT the coordinate plane and graph a linear equations using a T-chart.
Do Now: Read the notes on Page 1 and do #'s 1 - 6 at the bottom of the page.
Homework: Pages 5 (bottom), 6 & 7 in the Unit 6A Packet
Unit 6A Quiz is Tuesday(Pages 1 - 17)
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
6A
6A
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
A
V
BC
DE
F
yaxis
V
QuadrantQuadrant
QuadrantQuadrant
xaxisx y
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
There are an infinite number of solutions to the equation.
x y
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
There are an infinite number of solutions to the equation.
-2-10
21
-2 + 1-1 + 10 + 11 + 12 + 1
2
01
-1
3
(-2, -1)(-1, 0)(0, 1)
(2, 3)(1, 2)
y = x + 1
x y
4 = -5 + 14 ≠ -4
Nox 2x - 3 y (x, y)
-2-10
21
2(-2) - 3
2(-1) - 32(0) - 3
2(1) - 3
2(2) - 3
-7-5-3-11
(-1, -5)(-2, -7)
(0, -3)
(2, 1)
(1, -1)
37 = 2(20) - 337 = 40 - 337 = 37
x y
Yes
These ordered pairs are your solutions
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
2B
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
x + y = 5- x - x
y = -x + 5
y + 2x = 10- 2x - 2x
y = -2x + 10
2y + 4x = 12- 4x - 4x
2y = -4x + 122 2 y = -2x + 6
3y = x + 123 3
y = + 4x3
** Choose multiples of 3 for x to avoid fraction/ decimal values for y.
-6-30
63
+ 4
5
34
2
6
(-6, 2)(-3, 3)(0, 4)
(6, 6)(3, 5)
x + 4 y (x, y)x3-63
+ 4 + 4
+ 4+ 4
3y = x + 1
2
-33
03
336
3
2B
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
x
y
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
They form a straight line
y = x - 1 rt = 24a2 + b2 = c23p + 5q = 16
-2-10
21
-3(-2) - 1 5
-1-4
2
-7
(-2, 5)(-1, 2)(0, -1)
(2, -7)(1, -4)
x -3x - 1 y (x, y)
-3(-1) - 1-3(0) - 1
-3(1) - 1
-3(2) - 1 y = -3x - 1
x
y
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
-4-20
42
(-4) + 5
54
7
3
6
(-4, 7)(-2, 6)(0, 5)
(4, 3)(2, 4)
x x + 5 y (x, y)12
-12
(-2) + 5-12
(0) + 5-12
(2) + 5-12
(4) + 5-12
y = x + 512
x
y
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
-4-20
42
(-4) + 5
54
7
3
6
(-4, 3)(-2, 4)(0, 5)
(4, 7)(2, 6)
x x + 5 y (x, y)1212
(-2) + 512
(0) + 512
(2) + 512
(4) + 512
y = x + 512
-2-10
21
-2 - 6 -8
-6
-4-5
-7(-2, -8)(-1, -7)(0, -6)
(2, -4)(1, -5)
-1 - 60 - 61 - 62 - 6
y = x - 6
x
y
x
y
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
-2-10
21
2(-2) - 3
-5
-1-3
1
-7 (-2, -7)(-1, -5)(0, -3)
(2, 1)(1, -1)
x 2x - 3 y (x, y)
2(-1) - 3
2(0) - 3
2(1) - 3
2(2) - 3 y = 2x - 3
x
y
-6-3
0
6
3
-1
-2
1
-3
0
(-6, -3)
(-3, -2)
(0, -1)
(6, 1)
(3, 0)
x - 1 y (x, y)x3
y = - 1x3
x
y
- 1-63- 1-3
3- 10
3- 13
3- 16
3
Day 01 Graphing Linear Equations Using a TChart.notebook May 10, 2017
-2-10
21
-3(-2) + 2 8
2-1
5
-4
(-2, 8)(-1, 5)(0, 2)
(2, -4)(1, -1)
x -3x + 2 y (x, y)
-3(-1) + 2-3(0) + 2
-3(1) + 2
-3(2) + 2
y + 3x = 2x
y
y + 3x = 2- 3x - 3x
y = -3x + 2
y + 3x = 2
2 + 3(-3) = 2-7 ≠ 2
The point (-3, 2) is NOT a solutions to this equation. When I substituted the x and y values into the equation, I did not get a true statement.
x y
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