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Course 1 2-5 Addition Equations Course 1 2-5 Addition Equations Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day
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Page 1: Addition equations

Course 1

2-5 Addition Equations

Course 1

2-5 Addition Equations

Course 1

Warm UpWarm Up

Lesson PresentationLesson Presentation

Problem of the DayProblem of the Day

Page 2: Addition equations

Course 1

2-5 Addition Equations

Warm UpDetermine whether each value is a solution.

1. 86 + x = 102 for x = 16

2. 18 + x = 26 for x = 4

3. x + 46 = 214 for x = 168

4. 9 + x = 35 for x = 26

yes

no

yes

yes

Page 3: Addition equations

Course 1

2-5 Addition Equations

Problem of the Day

After Renee used 40 m of string for her kite and gave 5 m to her sister for her wagon, she had 8 m of string left. How much string did she have to start with?53 m

Page 4: Addition equations

Course 1

2-5 Addition Equations

Learn to solve whole-number addition equations.

Page 5: Addition equations

Course 1

2-5 Addition Equations

The equation h + 14 = 82 can be represented as a balanced scale.

h + 14 82

To find the value of h, you need h by itself on one side of the scale.

h ?

To get h by itself, first take away 14 from the left side of the scale. Now the scale is unbalanced.

h 68To rebalance the scale, take away 14 from the other side.

h + 14 82

Page 6: Addition equations

Course 1

2-5 Addition Equations

Taking away 14 from both sides of the scale is the same as subtracting 14 from both sides of the equation.

h + 14 = 82–14 –14h = 68

Subtraction is the inverse, or opposite, of addition. If an equation contains addition, solve it by subtracting from both sides to “undo” the addition.

Page 7: Addition equations

Course 1

2-5 Addition Equations

Solve the equation. Check your answer.

Additional Example 1A: Solving Addition Equations

x + 87 = 152

Check x + 87 = 152

x + 87 = 152 87 is added to x.

x = 65

– 87 – 87 Subtract 87 from both sides to undo the addition.

65 + 87 = 152?

152 = 152?

Substitute 65 for x in the equation.

65 is the solution.

Page 8: Addition equations

Course 1

2-5 Addition Equations

Solve the equation. Check your answer.

Additional Example 1B: Solving Addition Equations

72 = 18 + y

Check 72 = 18 + y

72 = 18 + y 18 is added to y.

54 = y

–18 –18 Subtract 18 from both sides to undo the addition.

72 = 18 + 54?

72 = 72?

Substitute 54 for y in the equation.

54 is the solution.

Page 9: Addition equations

Course 1

2-5 Addition Equations

Solve the equation. Check your answer.

Check It Out: Example 1A

u + 43 = 78

Check u + 43 = 78

u + 43 = 78 43 is added to u.

u = 35

– 43 – 43 Subtract 43 from both sides to undo the addition.

35 + 43 = 78?

78 = 78?

Substitute 35 for u in the equation.

35 is the solution.

Page 10: Addition equations

Course 1

2-5 Addition Equations

Solve the equation. Check your answer.

Check It Out: Example 1B

68 = 24 + g

Check 68 = 24 + g

68 = 24 + g 24 is added to g.

44 = g

–24 –24 Subtract 24 from both sides to undo the addition.

68 = 24 + 44?

68 = 68?

Substitute 44 for g in the equation.

44 is the solution.

Page 11: Addition equations

Course 1

2-5 Addition Equations

Johnstown, Cooperstown, and Springfield are located in that order in a straight line along a highway. It is 12 miles from Johnstown to Cooperstown and 95 miles from Johnstown to Springfield. Find the distance d between Cooperstown and Springfield.

Additional Example 2: Social Studies Application

It is 83 miles from Cooperstown to Springfield.

95 = 12 + d

distance between Johnstown and Springfield

distance between Johnstown and Cooperstown

distance between Cooperstown and Springfield

= +

95 = 12 + d

–12 –12

83 = d

12 is added to d.

Subtract 12 from both sides to undo the addition.

Page 12: Addition equations

Course 1

2-5 Addition Equations

Patterson, Jacobsville, and East Valley are located in that order in a straight line along a highway. It is 17 miles from Patterson to Jacobsville and 35 miles from Patterson to East Valley. Find the distance d between Jacobsville and East Valley.

Check It Out: Example 2

It is 18 miles from Jacobsville to East Valley.

35 = 17 + d

distance between Patterson and East Valley

distance between Patterson and Jacobsville

distance between Jacobsville and East Valley

= +

35 = 17 + d

–17 –17

18 = d

17 is added to d.

Subtract 17 from both sides to undo the addition.

Page 13: Addition equations

Course 1

2-5 Addition Equations

Solve each equation.

1. x + 15 = 72

2. 81 = x + 24

3. x + 22 = 67

4. 93 = x + 14

Lesson Quiz

x = 57

x = 57

x = 45

x = 79

56 inches

5. Kaitlin is 2 inches taller than Reba. Reba is 54 inches tall. How tall is Kaitlin?