Top Banner
Section 7-2 (and 7-3) Properties of Powers (and Negative Integer Exponents)
62

AA Section 7-2/7-3

Apr 22, 2015

Download

Education

Jimbo Lamb

Properties of Powers
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Page 1: AA Section 7-2/7-3

Section 7-2 (and 7-3)Properties of Powers (and Negative Integer Exponents)

Page 2: AA Section 7-2/7-3

Warm-upA multiple choice quiz has two questions. For each

question, there are three choices: A, B, and C. List all possible ways for a student to complete the quiz.

Is the possible number of ways 23 or 32?

Page 3: AA Section 7-2/7-3

Warm-upA multiple choice quiz has two questions. For each

question, there are three choices: A, B, and C. List all possible ways for a student to complete the quiz.

Is the possible number of ways 23 or 32?

(1A, 2A), (1A, 2B), (1A, 2C), (1B, 2A), (1B, 2B), (1B, 2C), (1C, 2A), (1C, 2B), (1C, 2C)

Page 4: AA Section 7-2/7-3

Warm-upA multiple choice quiz has two questions. For each

question, there are three choices: A, B, and C. List all possible ways for a student to complete the quiz.

Is the possible number of ways 23 or 32?

(1A, 2A), (1A, 2B), (1A, 2C), (1B, 2A), (1B, 2B), (1B, 2C), (1C, 2A), (1C, 2B), (1C, 2C)

32

Page 5: AA Section 7-2/7-3

Example 1

32i34

Page 6: AA Section 7-2/7-3

Example 1

32i34

= (3i3)(3i3i3i3)

Page 7: AA Section 7-2/7-3

Example 1

32i34

= (3i3)(3i3i3i3) = 36

Page 8: AA Section 7-2/7-3

Example 1

32i34

= (3i3)(3i3i3i3) = 36

32i34

Page 9: AA Section 7-2/7-3

Example 1

32i34

= (3i3)(3i3i3i3) = 36

32i34

= 32+4

Page 10: AA Section 7-2/7-3

Example 1

32i34

= (3i3)(3i3i3i3) = 36

32i34

= 32+4 = 36

Page 11: AA Section 7-2/7-3

Product of Powers Postulate

bmibn = bm+n

Page 12: AA Section 7-2/7-3

Example 2

(32 )4

Page 13: AA Section 7-2/7-3

Example 2

(32 )4 = (32 )(32 )(32 )(32 )

Page 14: AA Section 7-2/7-3

Example 2

(32 )4 = (32 )(32 )(32 )(32 ) = 38

Page 15: AA Section 7-2/7-3

Example 2

(32 )4 = (32 )(32 )(32 )(32 ) = 38

(32 )4

Page 16: AA Section 7-2/7-3

Example 2

(32 )4 = (32 )(32 )(32 )(32 ) = 38

(32 )4 = 32i4

Page 17: AA Section 7-2/7-3

Example 2

(32 )4 = (32 )(32 )(32 )(32 ) = 38

(32 )4 = 32i4

= 38

Page 18: AA Section 7-2/7-3

Power of a Power Postulate

(bm )n = bmn

Page 19: AA Section 7-2/7-3

Example 3

(x2 y )3

Page 20: AA Section 7-2/7-3

Example 3

(x2 y )3 = (x2 y )(x2 y )(x2 y )

Page 21: AA Section 7-2/7-3

Example 3

(x2 y )3 = (x2 y )(x2 y )(x2 y ) = x6 y3

Page 22: AA Section 7-2/7-3

Example 3

(x2 y )3 = (x2 y )(x2 y )(x2 y ) = x6 y3

(x2 y )3

Page 23: AA Section 7-2/7-3

Example 3

(x2 y )3 = (x2 y )(x2 y )(x2 y ) = x6 y3

(x2 y )3 = (x2 )3 y3

Page 24: AA Section 7-2/7-3

Example 3

(x2 y )3 = (x2 y )(x2 y )(x2 y ) = x6 y3

(x2 y )3 = (x2 )3 y3

= x6 y3

Page 25: AA Section 7-2/7-3

Power of a Product Postulate

(ab)m = ambm

Page 26: AA Section 7-2/7-3

Example 4

(3x2 y3 )4

Page 27: AA Section 7-2/7-3

Example 4

(3x2 y3 )4 = 34(x2 )4 (y3 )4

Page 28: AA Section 7-2/7-3

Example 4

(3x2 y3 )4 = 34(x2 )4 (y3 )4 = 81x8 y12

Page 29: AA Section 7-2/7-3

Example 5

1011

108

Page 30: AA Section 7-2/7-3

Example 5

1011

108 =

(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)

Page 31: AA Section 7-2/7-3

Example 5

1011

108 =

(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)

Page 32: AA Section 7-2/7-3

Example 5

1011

108 =

(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)

= 103

Page 33: AA Section 7-2/7-3

Example 5

1011

108 =

(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)

= 103

1011

108

Page 34: AA Section 7-2/7-3

Example 5

1011

108 =

(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)

= 103

1011

108 = 1011−8

Page 35: AA Section 7-2/7-3

Example 5

1011

108 =

(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)(10)

= 103

1011

108 = 1011−8 = 103

Page 36: AA Section 7-2/7-3

Quotient of Powers Postulate

bm

bn= bm−n

Page 37: AA Section 7-2/7-3

Example 6

x

y

⎝⎜⎞

⎠⎟

6

Page 38: AA Section 7-2/7-3

Example 6

x

y

⎝⎜⎞

⎠⎟

6

=

x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟

Page 39: AA Section 7-2/7-3

Example 6

x

y

⎝⎜⎞

⎠⎟

6

=

x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟x

y

⎝⎜⎞

⎠⎟ =

x6

y6

Page 40: AA Section 7-2/7-3

Power of a Quotient Postulate

a

b

⎝⎜⎞

⎠⎟

m

=am

bm

Page 41: AA Section 7-2/7-3

Example 7

x3

x3

Page 42: AA Section 7-2/7-3

Example 7

x3

x3 = x3−3

Page 43: AA Section 7-2/7-3

Example 7

x3

x3 = x3−3 = x0

Page 44: AA Section 7-2/7-3

Example 7

x3

x3 = x3−3 = x0

x3

x3

Page 45: AA Section 7-2/7-3

Example 7

x3

x3 = x3−3 = x0

x3

x3 = 1

Page 46: AA Section 7-2/7-3

Example 7

x3

x3 = x3−3 = x0

x3

x3 = 1

x0 = 1

Page 47: AA Section 7-2/7-3

Zero Exponent Theorem

b0 = 1, b ≠ 0

Page 48: AA Section 7-2/7-3

7-3: Negative Integer Exponents

Page 49: AA Section 7-2/7-3

Example 1

x7

x10

Page 50: AA Section 7-2/7-3

Example 1

x7

x10 = x7−10

Page 51: AA Section 7-2/7-3

Example 1

x7

x10 = x7−10 = x−3

Page 52: AA Section 7-2/7-3

Example 1

x7

x10 = x7−10 = x−3

x7

x10

Page 53: AA Section 7-2/7-3

Example 1

x7

x10 = x7−10 = x−3

x7

x10 =

(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )

Page 54: AA Section 7-2/7-3

Example 1

x7

x10 = x7−10 = x−3

x7

x10 =

(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )

=

1(x )(x )(x )

Page 55: AA Section 7-2/7-3

Example 1

x7

x10 = x7−10 = x−3

x7

x10 =

(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )(x )

=

1(x )(x )(x )

=1

x3

Page 56: AA Section 7-2/7-3

Negative Exponent Theorem

b−n =

1

bn

Page 57: AA Section 7-2/7-3

Example 2

(5b)3 (4b)−5

Page 58: AA Section 7-2/7-3

Example 2

(5b)3 (4b)−5

=

(5b)3

(4b)5

Page 59: AA Section 7-2/7-3

Example 2

(5b)3 (4b)−5

=

(5b)3

(4b)5 =

125b3

1024b5

Page 60: AA Section 7-2/7-3

Example 2

(5b)3 (4b)−5

=

(5b)3

(4b)5 =

125b3

1024b5

=

125

1024b2

Page 61: AA Section 7-2/7-3

Homework

Page 62: AA Section 7-2/7-3

Homework

p. 430 #14-30p. 435 #9-21, 25